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13 years ago
Dear sandeep,
question is
x + y^2 = 17
17 > y + x^2 > 14
here x and y are real numbers greater than 1
then y-x will be
Check a case in which x=3.31 and y=3.7
so x + y^2 = 17
and y + x^2 = 3.7 + (3.31)^2 = 14.6561
similarly many other cases
Dear SANDEEP, DIPIN and INDER
in this question x and y are real numbers not integers, so 17 > y + x^2 > 14 is possible for any real set.
and INDER you wrote in your comment that
In today's puzzle,
one condition is
17 > y + x^2 > 14
it means
17>14
which is not correct.
Why 17 is not greater than 14. As far as we know 17 is greater than 14
Please check the admin's answer once again
Thanks
Congratulation DIPIN for such an excellent performance in solving the questions. You provided a nice 100. Please send your mailing address at m4maths.com@gmail.com