M4maths Previous Puzzles

07 Nov 2013 Difference

What will be the difference of the amounts in the two types of saving given below
1) 20 rupee per day upto 100 days
2) 25 paisa then 50 paisa then 75 paisa then so on upto 100 days

OPtion

1) 300.00
2) 850.50
3) 737.50
4) 1520.50
5) 377.50
6) 675.50
7) 575.50
8) 975.50
9) 1262.50
10) None of these

Solution

Reason. In first saving total amount = 20*100 = 2000 rupee
In second, savings of 50th and 51st days are 12.50 and 12.75 rupee
(These two are middle terms) (or by solving AP method)
Total saving in second case = 100*{(12.50 + 12.75)/2} = 1262.50 rupee
Difference is 2000-1262.50 = 737.50 rupee
option 3)

Correct Option: 3 Best Solution (49)

Rahul Gupta   11 years AGO

20*100=2000
sum of AP = n/2(2a+(n-1)d)
here, a=25, n=100, d=25
sum=126250
this is in paisa now we have convert in rupee. i.e. sum/100.
126250/100=1262.50
Difference = 2000 - 1262.50 = 737.50
3)737.5 Right Answer

Like? Yes (10) | No (1)  

Md.Sultan Khichi   11 years AGO

20 rupee per day upto 100 days
so amount=20*100=rs.2000.
In second case the money are in AP
so 25+50+75.....
100/2(2*25+(100-1)25)
=126250
RS=126250/100=1262.50
different=2000-63125
=737.5
Ans:3

Like? Yes (3) | No   

hitesh kumar gupta   11 years AGO

first saving upto hundred days will be = 2000 rupees
now next statement contains series
25+50+75+...................upto 100 terms

now 100th terms will be
2500
so sum of this is =1262.5 rupee
the difference is = 737.5
which is 3rd option in given options.

Like? Yes (2) | No   

Lavankumar Reddy   11 years AGO

20 rupee per day 100 days total saving = 2000
25 paisa then 50 paisa then 75 paisa then so on upto 100 days total saving = n(a1 + n(a1))/2= 100(0.25+100(0.25))/2= 2525/2= 1262.5
Then Difference = 2000-1262.5 = 737.5

Like? Yes (2) | No   

dev kumar   11 years AGO

20*100-25*(1+2+.....+100)/100

Like? Yes (2) | No   

a.k.gayathridevi   11 years AGO

1)20*100=2000.00
2).25+.50+.75+1.00+1.25+.... =0.25(1+2+3+4+....+100)
=.25(5050)=1262.50
diff=2000.00-1262.50=737.50

Like? Yes (2) | No   

Saket chhitij   11 years AGO

for First case total=20*100=2000

for 2nd case , terms are in arithmetic progression , therefore sum of n terms in a.p. =n/2*(2a+(n-1)*d)..
which gives the value 1262.5 ... the difference of this 2 value = 737.50

Like? Yes (2) | No   

Rats   11 years AGO

(1)Rs20 for 100days = Rs2000
(2)0.25+0.50+0.75+......upto 100days
Sum=(100/2)(0.50+99*0.25)
=1262.50
Difference=2000-1262.50=737.50.....Ans

Like? Yes (1) | No   

Manish Kumar   11 years AGO

1st saving, 20*100= Rs2000
2nd saving, 100/2[2*25+(100-1)*25]= 126250 paisa =Rs1262.50
so, the difference of the amounts in the two types of saving are Rs(2000-1262.5)= Rs737.50

so option 3 is correct

Like? Yes (1) | No   

SHAIK SADDAM HUSSAIN   11 years AGO

(20*100)-(25+50+75+........+2500)/100=737.50

Like? Yes (1) | No   

Harjit kaur   11 years AGO

1) 20*100=2000
2)series is 25+50+75+...............
N=100
Sn=n/2(2a+(n-1)d)
Here a=25,d=25,n=100
By solving
We get saving =1262.50
So diff is2000-1262.50=737.50

Like? Yes (1) | No   

ArunKumar   11 years AGO

1) 20 *100 = 2000
2) 25 + 50 + 75 + . . . (100 days)
25 ( 1+2+3+ .... ) 100 days
25 * 100 * (100+1)/2
1262.50
diff = 2000-1262.50 = 737.50

Like? Yes (1) | No   

Rajeswar guin   11 years AGO

20*100=2000=a
100/2[2*25+99*.25]=1262.5=b
a-b=737.5

Like? Yes (1) | No   

KD   11 years AGO

Case 1:
20+20+....100th=20*100=2000 rs.

Case 2:
25+50+75+....+100 th term
a=25
d=25
n=100
so nth term is=25+99*25=2500
sum=100/2(25+2500)=2525*50 paise
i.e 1262.5 rs
so difference is 737.50

Like? Yes (1) | No   

kakali sarkar   11 years AGO

in 1st case the no total savings of 100 days will be (100*20)=2000.
in 2nd case total savings will be using A.P
=((100/2)*(2*25+(100-1)*25))=1262.5
so the diff will be=2000-1262.5=737.5

Like? Yes (1) | No   

achyuth   11 years AGO

1) 20 rupee per day upto 100 days the amount will be=20*100=2000
2) 25,50,75,...it is in arithmetic progression so
sum=n/2(2a+(n-1)d)
s=126250 paisa
convert into rupee
s=126250/100
s=1262.5
difference=2000-1262.5
diff=737.50

Like? Yes (1) | No   

ChinnaChowdaiah   11 years AGO

20 per day upto 100 days so total amount will be 2000.

25,50,75.......up to 100th day
will be arithmetic progression
so it will be
100/2(2*25 + (100-1) *25)
126250 paise
now convert this into rupees.
1262.50/-
so difference is 2000-1262.50 will be 737.50.

Like? Yes (1) | No   

GAYATHRI   11 years AGO

20+20+.....= 2000(for 100 days)
.25+.5+.75+.....= 1262.5
2000-1262.5 = 737.5

Like? Yes (1) | No   

sravani   11 years AGO

20*100=2000rs
25ps(1+2+...+100)=100*101/2 * 25ps=(100*101)/8rs=1262.5.
diff=737.50rs..

Like? Yes (1) | No   

Rajan   11 years AGO

Ans 3. in first case the saving will be 20*100=2000 and as the second case is in arithmetic progression the saving will be n(a1+an)/2 i.e 100(.25+25)/2=1262.5. so the difference is 737.50

Like? Yes (1) | No   

Rituraj Singh   11 years AGO

amount of first case= 20*100=2000
and in second case, its a A.P.
So last term will be= F.T.+ D(n-1)=> 25 + 25(100-1)=2500
Sum of A.P. is =n/2(F.T.+L.T.)=100/2(25+2500)=126250 i.e. 1262.50 rupees
So difference is =2000-1262.50=737.50

Like? Yes (1) | No   

sanjay   11 years AGO

if we save 20 Rs per day, we save 2000 rs for 100 days and if we save .25 ps per day for 100 days it would be 1262.5.

Like? Yes (1) | No   

PINKY   11 years AGO

first saving ->20*100= rs 2000
second saving -> 25p,50p,75p...upto 100 terms
sum upto 100 terms= 100/2(2*25+(100-1)25)=126250p
RS 126250/100

dif is 737.50

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

Amount after 100 days @20/day=20*100=2000
Amount with increase of 25 paise or 0.25 Rs/day upto 100 days=100/2[2*0.25+ 99*0.25]=1262.5
So difference=2000-1262.5=737.50 Rs.

Like? Yes (1) | No   

b.s.venkatesh   11 years AGO

1)100*20=2000
2)sn=n/2(a+l)
100/2(2525)
=2000-1262.50
=737.50

Like? Yes (1) | No   

Deepak Bharadwaj   11 years AGO

1st case saving = 20x100= rs 2000
second case total saving can be calculated by
25p+50p+75p+....upto 100 terms, which is an A.P
sum= n/2(2a+(n-1)d)=100/2(2x50+(100-1)x25)
=126250p = Rs.1262.50
difference= 2000-1262.50= Rs. 737.50 (3rd option)

Like? Yes (1) | No   

Ann Mary Jolly   11 years AGO

ANS: 3)737.50
An= 20
total amt saved in 1st case = 20*100 = 2000 ....(1)
Bn = 25n (in paisa)
total amt saved in 2nd case = B1+B2+....B100 (in paisa)
= (25*1)+(25*2)+...(25*100)
= 25*(1+2+3+.....100)
= 25*(100*101/2)
= 25*5050
= 126250
= 126250/100 Rs
= 1262.5 ....(2)
(2) - (1) gives, 2000-1262.50 = 737.50 Rs

Like? Yes (1) | No   

VISHAKHA BHATTACHARJEE   11 years AGO

20*100=2000 saving upto 100 days
next will be an AP series with d=25 and 1st term 25 and we go on increasing to 100 terms. sum of an ap series=(2a+(n-1)d)n/2=1262.50
hence diff=737.50

Like? Yes (1) | No   

prem singh   11 years AGO

20 rupees per day upto 100 day
=20*100=2000
25,50,75,..n
sum of AP =n/2[2a+(n-1)d)
so here n=100, a=25,d=25
sum of 100 terms=100/2[2*25+99*25)
=12625
now in rupees=12625/100=1262.50
difference=2000-1262.50
=737.50

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

total savings by 1=20*100=2000
total savings by 2
=100/2[2*0.25+0.25*99]=1262.5........(by A.P)
difference=737.50

Like? Yes (1) | No   

sreetej   11 years AGO

in case1 the savings are 20*100=2000
in case2 the savings are 0.25+0.5+0.75+1+......
it is in a.p with difference 0.25 .
therefore the sum of 100 terms = 1262.5
so answer is 2000-1262.50=737.50

Like? Yes (1) | No   

Jyothi   11 years AGO

20*100=2000
s=n/2(2a+(n-1)d)
a=0.25
d=0.25
n=100
s=1262.5
difference=2000-1262.5=737.5

Like? Yes (1) | No   

Saurabh Keshri   11 years AGO

case 1- saving= rs 20*100

case 2- saving =25+50+75+100....100 terms
=25(1+2+3+....+100)
=25*100*101/2
=126250 p = rs 1262.5
difference= 2000-1262.5= 737.5

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

20*100-1262.50

Like? Yes (1) | No   

ALISHA AHAMAD   11 years AGO

20*100=2000
.25+(.25+.25)+(.25+2*.25)+.....+(.25+99*.25).
sum = 100/2(2*.25+99(.25))=1262.50
2000-1262.50= 737.50

Like? Yes (1) | No   

mirtunjay verma   11 years AGO

20Rs per day then for 100 day it will
20*100=2000
and 25,50,75,...till 100 term we use sum of n number formula,so for that we take 25 common out this series so it will convert in new series
25(1+2+3.....+100)
so sum will
25*50*101=126250 paise..we convert it into Rs.then it will 1262.50Rs
so therefore diff is 2000.00-1262.50=737.50 Rs.
:)

Like? Yes (1) | No   

batsal   11 years AGO

1. 20*100=2000
2. it is based on AP
S= n/2(2a+(n-1)d)
here n=100 d=0.25 a=0.25
so, S= 1262.5
difference is 2000-1262.5=737.5

Like? Yes (1) | No   

NIDHI   11 years AGO

1. 20*100=2000
2. it is based on AP
S= n/2(2a=(n-1)d)
here n=100 d=0.25 a=0.25
so, S= 1262.5
difference is 2000-1262.5=737.5
S= n/2(2a+(n-1)d)

Like? Yes (1) | No   

HARI om kashyap   11 years AGO

20*100=2000
next saving is in arithmetic progression where first term is 25
common difference 25
number of terms is 100
then Sn= 100/2[2*25+(100-1)*25]
=1262.5
so differenc is 2000-1262.5=737.5

Like? Yes (1) | No   

moumita majee   11 years AGO

20*100=2000
next saving is in arithmetic progression where first term is 25
common difference 25
number of terms is 100
then Sn= 100/2[2*25+(100-1)*25]
=1262.5
so differenc is 2000-1262.5=737.5

Like? Yes (1) | No   

neeru   11 years AGO

first is a direct multiplication while second is an ap..

Like? Yes (1) | No   

SHIVANI PRAKASH   11 years AGO

20*100- [100/2(2*0.25+99*0.25)]
=737.50

Like? Yes (1) | No   

Preetika Karnal   11 years AGO

1) Rs 20*100 =Rs 2000
2) Rs 100/2*(25 + 25+(100-1)*25)/100 =Rs 1262.50

1) - 2) =737.50

Like? Yes (1) | No   

Grishma Shah   11 years AGO

In case-1:
20 rupee for 100 days = 2000 rs at 100th day.
In case-2:
25 paisa increment every day forms a.p.
Here, a=0.25; d=0.25; n=100
Sn= n/2(2a + (n-1)d)
at 100th day sum= 50*25.25=1262.5

Hence, diffence of case 1 and case 2 is 737.5/- rupee

Like? Yes (1) | No   

pranayee karmakar   11 years AGO

as 20*10=2000-[1/100{100/2(2*50+99*25)}]=737.5

Like? Yes (1) | No   

Praveen   11 years AGO

let x denotes 25 paisa
then,
case i: 20 rupee= 0.25 x 4 x 20= 80x
in case ii:

x+2x+3x...100x ==>Arithmetic Progression==>5050x
==>5050 x 0.25
==>1262.5
diffenece = 2000-1262.5
==>737.5

Like? Yes (1) | No   

vikash kumar   11 years AGO

tn=25+25(100-1)=2500paisa

100*(25+2500)
---------------=2525*50=1262.50Rs
2

Rs 2000-1262.50

Like? Yes (1) | No   

Abhideep Saha   11 years AGO

20*100=2000. 25*!00(100+1)/2=126250 paise. 1262.50 rs. 2000.00-1262.50=737.50 rs.

Like? Yes (1) | No   

ankita   11 years AGO

1. 20*100=2000
2. a=25,n=100,d=50-25
(n/2)(2a+(n-1)d)=1262.5
ans=737.5

Like? Yes (1) | No   

06 Nov 2013 Different Word

Which of the following word is different?

OPtion

1) FIRE
2) FIRST
3) FIRM
4) FROG
5) FIGURE
6) FOG
7) FISH
8) FONT
9) FOOD
10)FIELD

Solution

O is repeated in the word FOOD.

Correct Option: 9 Best Solution (3)

Vijil Gupta   11 years AGO

in the word FOOD O is being repeated and in no other word any letter is being repeated

Like? Yes (11) | No (9)  

pawan kumar   11 years AGO

All letters are not distinct only in this.

Like? Yes (1) | No   

Amresh kumar   11 years AGO

it caontains letter O twice

Like? Yes (3) | No (5)  

05 Nov 2013 Leap Year Interest

What will be the interest of 1 day of 20500 rupee at a rate of 6.25 % yearly in a leap year. (Answer in approx)

OPtion

1) 4.00
2) 2.00
3) 8.60
4) 6.70
5) 3.00
6) 5.40
7) 9.30
8) 1.80
9) 3.50
10)None of these

Solution

Daily interest rate = 6.25/366 %
Hence Interest = {20500*(6.25/366)*1}/100 = 3.50

Correct Option: 9 Best Solution (59)

Rats   11 years AGO

Here P=20,500
R=6.25%
So for 1year Interest,I
I=PR/100
=(20500*6.25)/100
=1281.25
So for 1day,
=1282.25/366 (366 for leap year)
=3.50......Ans

Like? Yes (10) | No (1)  

Mithlesh Prasad   11 years AGO

P=20500 rupee
R=6.25%
T=1/366 since it is a leap year.
therefore, I=(P*R*T)/100
I=(20500*6.25*1)/(366*100)
ON CALCULATING we get,
I=3.5006831
so, I=3.50(approx)

Like? Yes (3) | No   

Muhammad Nadeem Haider Naseem   11 years AGO

interset in leap year=20500*6.25%=1281.25
interset in one day=1281.25/366=3.50 (approx)

Like? Yes (3) | No   

Grishma Shah   11 years AGO

the year interest on 20500/- is 1281.25 at 6.25 interest.
the year is leap year hence 366 days in year.
1281.75/366 = 3.5
hence per interest is 3.5

Like? Yes (3) | No   

VIKASH KUMAR SHARMA   11 years AGO

p=20500 rs, r=6.25%, t=1/366 (for leap year),
simple interest= (p*r*t)/100
= (20500*6.25*1/366)/100 = 3.50 rs (approx) ans

Like? Yes (3) | No   

prabhat kumar   11 years AGO

principle=20500
rate=6.25%
time=1/366(because of leap year)
for 1 year simple interest and compound interest are same
so, simple interest = p*r*t/100
= 20500*6.25*1/100*366
= 3.50068306010929(appx 3.50)

Like? Yes (4) | No (1)  

Suman Saurabh   11 years AGO

interest=20500*6.25*1/100*366=3.50

Like? Yes (3) | No (1)  

Udhaya kumar   11 years AGO

20500*6.25/100=1281.25
per day 1281/366=3.5..........

Like? Yes (2) | No   

dev kumar   11 years AGO

interest = (20500*6.25)/(366*100)

Like? Yes (2) | No   

Manish Kumar   11 years AGO

20500*(1/366)*6.25/100 = 3.50 approx

Like? Yes (2) | No   

ABHISHEK KUMAR MISHRA   11 years AGO

1 day =1/366 year

S.I=p*r*t/100

S.I=(20500*6.25*1)/100*366 = 3.50

Like? Yes (2) | No   

vikash kumar   11 years AGO

6.25*20500*366
-------------------- = 3.51
365*365*100

Like? Yes (2) | No   

abhi   11 years AGO

s.I= p*r*t/100
it is leap year =366
t= 1/366
p=20500
r=6.25
si=(20500*6.25*1)/(100*366)=3.50

Like? Yes (2) | No   

HARI om kashyap   11 years AGO

20500*6.25/100=1281.25
per day interest will be
1281.25/366=3.5

Like? Yes (2) | No   

praneeth   11 years AGO

interest=P*T*R/100;
T=1/366(since it is being a leap year);
substituting in the interest formula we get
i=(20500*1*6.25)/(366*100)=128125/36600=3.50

Like? Yes (2) | No   

Shrikant kumar   11 years AGO

p=20500,r=6.25%,t=1/366(since in a leap year there are 366 days,hence for 1 days t=1/366)
s.i=(p*r*t)/100
si=(20500*6.25*1)/100*366=3.50

Like? Yes (1) | No   

ishita gorai   11 years AGO

20500*6.25/100=1281.25
per day interest will be
1281.25/366=3.5

Like? Yes (1) | No   

Rajan   11 years AGO

on calculating the 6.25% interest on 20,500 will be 1281.25 on dividing that with 366 days(leap year) it will 3.500683 so app 3.5

Like? Yes (1) | No   

moumita majee   11 years AGO

20500*6.25/100=1281.25
per day interest will be
1281.25/366=3.5

Like? Yes (1) | No   

Md.Sultan Khichi   11 years AGO

as we know SI=p*r*t/100
so SI= 20500*6.25*1/100=1281.25
so one day interest=1281.25/366=3.50
Ans:9

Like? Yes (1) | No   

Lavankumar Reddy   11 years AGO

20500*6.25%=1281.25
=1281.25/366(leap year)
=3.50

Like? Yes (1) | No   

Abhishek Kumar   11 years AGO

interest for 1 year(366 days) / 366

Like? Yes (1) | No   

SHAIK SADDAM HUSSAIN   11 years AGO

(20500*6.25)/36600

Like? Yes (1) | No   

Jyothi   11 years AGO

for year interest=0.0625*20500=1281.25
for day=1281.25/366=3.5

Like? Yes (1) | No   

ArunKumar   11 years AGO

Inetrest for a year = 20500 * 6.25 /100 *1 = 1281.5
for a day = 1281.5/366 = 3.50

Like? Yes (1) | No   

PINKY   11 years AGO

SI = (20500*6.25*1)/(100*366)
= 3.50 APPROX

Like? Yes (1) | No   

prem singh   11 years AGO

leap yaer=366 days
r=6.25
p=20500
1 day interest =(p*r/100)/leap year days
=20500*6.25/366*100
=128125/36600
=3.50

Like? Yes (1) | No   

Yapadinne Raju   11 years AGO

we have 366 days in a leap year.
1 day convert into years=1/366 years
interest=(20500*6.25*1)/(100*366)
=(205*625)/36600
=3.50(approx)

Like? Yes (1) | No   

kakali sarkar   11 years AGO

it will be= (6.25/366*100)*20500

Like? Yes (1) | No   

ALOK KUMAR NAYAK   11 years AGO

interest = (20500*6.25*366)/(100*365)
interest = 1284.76057
interest/day = 3.50 (approx)

Like? Yes (1) | No   

Prakash kumar   11 years AGO

si = (20500*6.25)/(100*366)
= 3.50 approx

Like? Yes (1) | No   

prasanth_ponnaluri   11 years AGO

one year interest for a leap year = (20500*1*6.25)/100 = 1281.25 this is per 366 days
so for one day it is 1281.25 / 366 = 3.500

Like? Yes (1) | No   

Abhinav Kumar   11 years AGO

interest = (20500*625*1)/(366*100*100)
here time = 1/366 in yr.

Like? Yes (1) | No   

GAYATHRI   11 years AGO

yearly interest=6.25%
interest for the amount of 20500 for 366 days(1 leap year)=20500*6.25/100=1282.275
interest for the amount of 20500 for 1 day=1282.275/366=3.50348

Like? Yes (1) | No   

Mithun Kumar Kesari   11 years AGO

interest= principal*time(in year)*rate
=20500*(1/366)*(6.25/100)=3.50

Like? Yes (1) | No   

Chithra   11 years AGO

20500*(6.25/100)=1281.25
1281.25/366=3.5

Like? Yes (1) | No   

Rashmi bharti   11 years AGO

Interest for 1 day = (20500*0.0625)/366
Interest for 1 day = 3.5006
Ans= 3.5

Like? Yes (1) | No   

Laltu banerjee   11 years AGO

20500*6.25%=1281.25
1281.25/366=3.50

Like? Yes (1) | No   

TANMOY DUTTA GUPTA   11 years AGO

6.25%/366*20500*1/100=3.50

Like? Yes (1) | No   

Saket chhitij   11 years AGO

intrest per year=20,500*6.25/100=1281.25

intrest per day =1281.25/365=3.51

Like? Yes (1) | No   

R.RAVIKUMAR   11 years AGO

(20500*6.25*(1/366))/100=3.5

Like? Yes (1) | No   

prakash kumar   11 years AGO

in a leap year=366 days, in one leap year 6.25% interest of 20500 rupee=(20500*6.25)/100 =1281.25, in 1 year interest=1281.25, then in one day=1281.25/366= 3.500683,nearest option is 9 .

Like? Yes (1) | No   

lovkesh goyal   11 years AGO

because everybody know a Leap year have 366 days so in the ques given a 1 day so we have convert 1 day into a year so
366 days have 1 year
so 1 day have 1/366 year

so according to formula
s.i=(p*t*r)/100
so (20500*1*6.25)/(366*100)~=3.50

Like? Yes (1) | No   

Pratyush Praveen   11 years AGO

first we find out the si for one year
si= (p*R*T)/100=(20500*6.25*1)/100=1281
so this is the interest for one year and interest for one day is 1281/366=3.50

Like? Yes (1) | No   

pavan   11 years AGO

SI=(PTR/100)
(20500*6.25)/(100*366)=3.50

Like? Yes (1) | No   

Sourav Maity   11 years AGO

we know,simple interest=(p*r*t)/100=(20500*6.25*1)/100=1281.25 in a year.In leap year there are 366 days. so,interest for 1 day =1281.25/366=3.50(approx)

Like? Yes (1) | No   

ChinnaChowdaiah   11 years AGO

I=PTR/100
P=20500
T=1year
R=6.25%
I=1281.25 for year.
so for 1 day in leap year the interest becomes
1281.25/366
~ 3.50

Like? Yes (1) | No   

SWATI MISHRA   11 years AGO

because 1 day is 1/366 part of an year.

Like? Yes (1) | No   

mssurya   11 years AGO

it's a basic simple interest question by that we can answer

Like? Yes (1) | No   

AMIT   11 years AGO

Rate for 365 days=6.25%
Rate for 366 days=6.25/365*366=6.26
time=1/366 year
So,
S.I.=(20500*6.26*1)/(100*366)=3.50

Like? Yes (1) | No   

Alok kumar   11 years AGO

SI=(20500*625*1)/(100*366*100)
=3.50

Like? Yes (1) | No   

surbhi   11 years AGO

interest= P*R*T/100
P=20500
R=6.25
T=1/366

Like? Yes (1) | No   

Gudivada sunitha   11 years AGO

interest=prt/100, t=1/366, i= (20500*6.25*1)/(366*100)=3.50

Like? Yes (1) | No   

Mahesh   11 years AGO

for 365 day interest comes up to 1281.25
(6.25/100 * 20500)
for 1 day it will 1281.25/365= 3.50 (approx)

Like? Yes (1) | No   

dishant   11 years AGO

p=20500,r=6.25%,time=1/365yr
si=prt/100
si=(20500*6.25*1)/(100*365)
si=3.51

Like? Yes (1) | No   

Kishan Kumar Singh   11 years AGO

since Interest = (P*R*T)/100
therefore, I=(20500*6.25*1)/100 =1281.25
and since it is for 366 days therefore for 1 day it will be equal to 1281.25/366 = Rs. 3.50 Ans

Like? Yes (1) | No   

satya   11 years AGO

actual answer is 3.50

Like? Yes (1) | No   

mirtunjay verma   11 years AGO

for leap year 1 interest=1/366 so solution will

(20500*6.25*1)/(100*366)

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

20500*1*6.25/100*366=3.50

Like? Yes (1) | No   

04 Nov 2013 Sequence

What is the next number of the following sequence
74,101,306,416,794,981.....

OPtion

1) 1075
2) 1183
3) 1195
4) 1275
5) 1325
6) 1375
7) 1455
8) 1475
9) 1595
10) None of these

Solution

5^2+(2+5)^2 = 25+49 = 74
10^2+(1+0+0)^2 = 100+1 = 101
15^2+(2+2+5)^2 = 225+81 = 306
20^2+(4+0+0)^2 = 400+16 = 416
25^2+(6+2+5)^2 = 625+169 = 794
30^2+(9+0+0)^2 = 900+81 = 981
Similarly
35^2+(1+2+2+5)^2 = 1225+100 = 1325
option 5)

Correct Option: 5 Best Solution (6)

Mahesh   11 years AGO

First number is 5^2 = 25 + (2+5)^2=49 =74
Second number is 10^2= 100 +(1+0+0)^2=1 total is 101
Third number is 15^2 = 225 +(2+2+5)^2 = 81 total is 306

Similarly next number is 35^2 = 1225 + (1+2+2+5)^2 = 100, total is 1325

Like? Yes (10) | No   

praneeth   11 years AGO

5*5=25+49=74;
10*10=100+1=101;
15*15=225+81=306;
20*20=400+16=416;
25*25=625+169=794;
30*30=900+81=981;
35*35=1225+100=1325

Like? Yes (5) | No   

priya   11 years AGO

1325.
1)7+4=11;1+1=2;
2)1+0+1=2;
3)3+0+6=9
4)4+1+6=11;1+1=2;
5)7+9+4=20;2+0=2;
6)9+8+1=18;1+8=9;
7)1+3+2+5=11;1+1=2

Like? Yes (4) | No   

asha   11 years AGO

7+4=11 1+1=2
1+0+1=2
3+0+6=9
4+1+6=11 1+1=2
7+9+4=20 2+0=2
9+8+1=18 1+8=9
1+3+2+5=11 1+1=2

Like? Yes (3) | No   

swastik   11 years AGO

in this series 306 and 981 are divisible by 3
but all the term expect these 2 is giving a remainder of 2
so we will get a term after 981 which will give a remainder 2
checking the option u will get ans as 1325

Like? Yes (1) | No   

Harjit kaur   11 years AGO

74=5^2+7^2
101=10^2+1^2
306=15^2+9^2
416=20^2+4^2
794=25^2+13^2
981=30^2+9^2
next no is
35^2+10^2=1325

Like? Yes (1) | No   

01 Nov 2013 Coded Language

In a coded Language
MANGO = 3/5
ORANGE = 2/6
APPLE = 1/5
Then
POTATO = ?

OPtion

1) 1/6
2) 3/5
3) 1/5
4) 5/6
5) 1/4
6) 1/3
7) 1/2
8) 2/3
9) 4/5
10)None of these

Solution

In MANGO 3 letters M,A,O out of 5 letters have suprimeposable mirror images, hence code is 3/5

In ORANGE 2 letters O,A out of 6 letters have suprimeposable mirror images, hence code is 2/6

In APPLE 1 letter A out of 5 letters have suprimeposable mirror image, hence code 1/5

Similarly in POTATO 5 letters O,T,A,T,O out of 6 letters have suprimeposable mirror image, hence code is 5/6.

option 4)

Correct Option: 4 Best Solution (2)

neel roy   11 years AGO

the no of words in the denominator is 6...so the ans reduces to either 1 or 4.and comparing the place of A in the given 3 words the ans will be 4.

Like? Yes (1) | No   

Ayodhya prasad   11 years AGO

remainder is position of A
denominator is sum of alphabats.

Like? Yes (10) | No (11)  

31 Oct 2013 birds

40 % of birds in a tree went to other place and half of the remaining died. On multiplying the number of remaining birds to 30, It became a perfect square number. What will be the least possible number of birds

OPtion

1) 4
2) 16
3) 36
4) 64
5) 100
6) 144
7) 196
8) 256
9) 324
10) 400

Solution

let no of birds be x
then 60 % of the birds = 0.6x
half of this = 0.3x
so if we multiply remaining to 30 we get 30*0.3x = 9x
it will be an integer only if x is integer
so we have to select x in such a way that x, 0.6x and 0.3x would be integers
and the least possible value for this will be 100

Correct Option: 5 Best Solution (24)

Suman Saurabh   11 years AGO

Let number of birds=100
40%of birds went to other tree and 30% of birds are dead.
so remaining birds are 30%.
if we multiply it by 30=30*30=900 which is a perfect square.
so number of birds=100

Like? Yes (4) | No (1)  

Sourangsu Bandyopadhyay   11 years AGO

The question here gives the answer itself!
The solution can be derived as:
Since 40% of the birds flew away.
Then let the total number of birds be 'x'.
So,
(40/100)*x=(2/5)*x=(some whole number,say k)
Now judging by the options,100 is the least number which gives k,a whole number)!!
Hence, Answer=100. [Ans]
You, don't even require to go beyond this step..

But however let's do it for formality!
Suppose,x=100
40% of 100 is 40.
No. of remaining birds=100-40=60.
Half of them flew away,so no of remaining birds=30
Then, multiplying by 30,we get
30*30=900.[Which is indeed a perfect square!!]

Like? Yes (5) | No (3)  

SHAIK SADDAM HUSSAIN   11 years AGO

only 30% of the total birds will be left on the tree so for total of 100 birds 30% will be 30 birds so if we multiply with 30, 30*30=900 which is a perfect square.. which is not possible for any in given less than 100

Like? Yes (2) | No   

Ann Mary Jolly   11 years AGO

Ans : 5)100
30*n=x^2
lowest no. x = 30, 30*n = 30^2
=> n = 30
remaining birds on tree after half died = 30
Therefore, initially there must have been 60 birds.
Since 40% birds flew away from total,60% remained.
60%(total) = 60 => total no. of birds = 100

Like? Yes (2) | No   

Divya Srivastava   11 years AGO

let the number be 'x'
0.6x did not fly away.
0.3x * 30 = 9x
for the 9x should be perfect square the least possible value of x should be 4.
But it is given that 40% of them fly away, now 40% of 4 = 1.6 which is not possible,
therefore it should be divisible by 10 or 100.
hence correct option is 5). 100.

Like? Yes (2) | No   

VIKASH KUMAR SHARMA   11 years AGO

let the no. of birds are 100.
then 40% of birds went to other place and in the remaining 60% birds. thn 50% of the remaing were died , thrfor 30*30= 900 , which is a perfect square.
thrfor the total no. of birds = 100 (ans)

Like? Yes (1) | No   

Sujeet Kumar   11 years AGO

30% of the birds remain on tree
and 30% multiplied by 30 is perfect square
which is 30= 2*3*5
so at least 2*3*5 should be there to make it perfect sqaure.
so ans is 100,so that (30/100)*100*30= prefect square.

Like? Yes (1) | No   

anil   11 years AGO

40*X/100;
REMAIN*30=900
SO REMAIN=30;
60+40=100;

Like? Yes (1) | No   

vikash kumar   11 years AGO

100*.6=60
60/2=30
or
100*.3=30birds
30*30=900perfect sq

Like? Yes (2) | No (1)  

Md Shahnawaz Shahab   11 years AGO

let the number of birds be x
therefore .4x birds fly away, and .6x birds remain. Now half of .6x birds die. Now total remaining birds = .3x
Now according to the problem 0.3x * 30 = a perfect square...
subtituting x = 100 we get 0.3x = 30 which makes it a perfet square....we didnt consider the other options as e cannot use a fraction of any bird.... 0.5 or 0.3 bird can NOT remain.

Like? Yes (2) | No (1)  

swastik   11 years AGO

ans is 100
let there is 100 birds.40 birds went to other tree. so there is only 60 bird left. out of that half died.so 30 bird left.
means only 30% bird left
now go with the option
0.4*0.3=1.2 cant be birds number
16*0.3=4.8 cant be birds number
36*0.3=10.8 cant be birds number
64*0.3=19.2 cant be birds number
100*0.3=30 it can be birds number

now check the 2nd condition
30*30=900
it is a perfect square
so 100 is the least possible ans

Like? Yes (1) | No   

prakash kumar   11 years AGO

since 40% of birds went to other place so no of birds must be a multiple of 5
there are only two options of multiple of 5
if we check for 100
if 40% went then remaining birds are 60
since half of remaining died
now remaining birds are 30
after multiplying with 30 it will be a perfect square
100 is satisfying all conditions ang is least no
den no of birds=100

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=100
remaining %=100-40-60/2=30
30x*30=perfect square=> min=>x=1
=>900
=>remaining min birds=30
=>total birds=30*2+40=100

Like? Yes (1) | No   

Yapadinne Raju   11 years AGO

let total birds=x,
40% of birds went means= 40x/100=2x/5
remaining birds=3x/5
in which half of the remaining birds died..=3x/(5*2)=3x/10
on multiplying the number of remaining birds to 30.....>3x/10=30
x=100

Like? Yes (1) | No   

Ranjit Somisetty   11 years AGO

.3*x*30=9x is perfect square when x is 100

Like? Yes (1) | No   

ravi singh   11 years AGO

answer is 100

40% of 100=40
remaining is =60
and 50% of 60=30

remaining is 30

30*30=300
hence option 5

Like? Yes (1) | No   

Raviranjan Pandey   11 years AGO

bcoz if u multiply with 30*30=900 ITS PERFECT SQUARE
LET 100BIRDS

Like? Yes (1) | No   

Grishma Shah   11 years AGO

given is the remaining no. of birds multiplying gives a perfect square.
Hence,
30*30=900 is a perfect square.
30 birds are remaining
Half died, results 30*2= 60
40 % flied = 60+40=100
hence 100 is the least possible birds

Like? Yes (2) | No (1)  

samiul islam   11 years AGO

We can get 40% bird by selecting two options 100 or 400..but doing other calculations it is clear that 100 will give us right ans

Like? Yes (1) | No   

moumita majee   11 years AGO

given that 40 % brds left the treee.. and remaining 30% are died..
remaining are 30%... i.e.
according to question
let X be the total num of birds
then 30% of X * 30 = perfect square
so the x will be 100
since if you find 40% of other optn then result came in fraction
but in case of 100 all condition satisfied

Like? Yes (1) | No   

HARI om kashyap   11 years AGO

given that 40 % brds left the treee.. and remaining 30% are died..
remaining are 30%... i.e.
according to question
let X be the total num of birds
then 30% of X * 30 = perfect square
so the x will be 100
since if you find 40% of other optn then result came in fraction
but in case of 100 all condition satisfied

Like? Yes (1) | No   

ishita gorai   11 years AGO

given that 40 % brds left the treee.. and remaining 30% are died..
remaining are 30%... i.e.
according to question
let X be the total num of birds
then 30% of X * 30 = perfect square
so the x will be 100
since if you find 40% of other optn then result came in fraction
but in case of 100 all condition satisfied

Like? Yes (1) | No   

Uddhav Ghodake   11 years AGO

becoz 40% of total birds means number shuld be integer so by taking 100 only least number comes as 40... and perfect square number is 900.

Like? Yes (1) | No   

b.s.venkatesh   11 years AGO

LET NUMBER OF BIRDS ARE 100.
40% BIRDS WENT TO ANOTHER PLACE SO REMAINING 60
HALF DIED-REMAINING 30
MULTYPLY WITH 30 WHICH IS 900 IS A PERFECT SQUARE.

Like? Yes (1) | No   

30 Oct 2013 Find the number of toys

A man bought a certain number of toys for Rs.180, he kept one for his own use and sold the rest for one rupees each more than he gave for them. Besides getting his own toy for nothing he made a profit of Rs.10. Find the number of toys.

OPtion

1) 9
2) 15
3) 20
4) 24
5) 30
6) 36
7) 40
8) 48
9) 50
10)None of these

Solution

Let the number of toys = x
Cost of each toy = 180/x Rs.
Now no. of toys sold = x-1 and selling price of each = (180/x)+1
He sold the toys for (x-1){(180/x)+1)Rs.
His profit is 10 Rs.
(x-1){(180/x)+1}-180 = 10
solve
x= 20 and -9
rejecting -9
20 toys were bought
option 3)

Correct Option: 3 Best Solution (39)

Abhishek Kumar   11 years AGO

let no. of toys=n
cost of 1 toy=180/n
now, (n-1)*(180/n + 1)=180+10; as 1 toy cost nothing,
it gives (n-20)(n+9)=0;
which gives n=20 toys

Like? Yes (16) | No (3)  

Sourangsu Bandyopadhyay   11 years AGO

The question is a bit Tricky...But let's explain it..
The solution can be derived as
Let the number of toys the man brought be 'x'
Then, Cost Price of each toy=180/x
(Trick: The cost price is just the average cost price used here.As per our question it might be confusing from the language of the question that each of the toy was brought for a different cost price.)
Since he paid Rs.1 extra for each of the toy he brought and sold(except the one he kept for himself!!)
He made a profit of Rs.10 on the whole bargain.
Thus,k we could claim that on an he gained Rs.1 on his average cost price.(Completely rejecting the fact that he might have brought each of the toy for different cost price)
Total selling price=Rs.(180+10)=Rs.190
Then,our equation becomes quite simple:
(190/(x-1))-(180/x)=1
Solving, we get x=20 or -9.
Since quantity cannot be negative.
Thus, x=20 [Answer]

Like? Yes (10) | No (5)  

prakash kumar   11 years AGO

let a man bought x toys
buying cost of each toy=180/x
a/q,
((180/x)+1)(x-1)-180=10
(180+x)(x-1)-180x=10x
180x-180+x^2-x-180x=10x
-180+x^2-x=10x
x^2-11x-180=0
x^2-20x+9x-180=0
x(x-20)+9(x-20)=0
(x-20)(x+9)=0
x cant be -ve
so,x=20

Like? Yes (7) | No (2)  

Raisul Alam   11 years AGO

Suppose the no of toys=x
So the cost price for each toys is=180/x
He kept 1 toy for his own.
So now (x-1) no of toys are remaining.
And the selling price of (x-1) no of toys are (x-1)*(180/x+1)(given in the qstn)
now (x-1)*(180/x+1)-180=10
=>x^-11x-180=0
by middle term factor we get (x-20)(x+9)=0
So the value of x will be either 20 or -9.But the no of toys can't be negative . So the no of toys are=20

Like? Yes (5) | No (1)  

HARI om kashyap   11 years AGO

let X be price of toys and Y be number of toys
then acc to question
XY=180
and (X+1)(Y-1)=190 since 10 rs is profit
solving both eq we get y-x=11
and XY=180.
then X=9
Y=20

Like? Yes (4) | No (1)  

ishita gorai   11 years AGO

let X be price of toys and Y be number of toys
then acc to question
XY=180
and (X+1)(Y-1)=190 since 10 rs is profit
solving both eq we get y-x=11
and XY=180.
then X=9
Y=20

Like? Yes (6) | No (3)  

ChinnaChowdaiah   11 years AGO

Let man bought x toys
Then, cost of one toy = Rs 180/x
He kept one toy for his own,
According to question

After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs (180/x)+1

so
(x-1)(180/x +1)=180+10
(x-1)(180/x)+(x-1)=190
180- 180/x +x -1=190
x- 180/x -11=0
x^2-11x-180=0
x^2-20x+9x-180=0
x(x-20)+9(x-20)=0
x=20 (or)-9
so the no of toys are 20

Like? Yes (3) | No (1)  

Ashik Kuppili   11 years AGO

Let man bought x toys
Then, cost of one toy = Rs
He kept one toy for his own,
According to question
After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs
so

Like? Yes (3) | No (2)  

Kumar Ankit   11 years AGO

Let man bought x toys

Then, cost of one toy = Rs

He kept one toy for his own,

According to question

After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs

so

since the number of toys can never be negative

Hence the man has bought 20 toys

Like? Yes (4) | No (3)  

Chandni Maurya   11 years AGO

ans=20
let n be the no of toys and x be the cost,
then,
n*x=180----(1)
(n-1)(x+1)=180+10=190---(2)
put n*x=180 in 2,
n-x=11----(3),
180=2*2*3*3*5= 20*9(satisfies the condition 3)
=>n=20

Like? Yes (2) | No (1)  

ravi singh   11 years AGO

answer is 20

let toys is x then cost of one toy is 180/x

now according to the question
(x-1)*( 180/x +1) = 190

=>x^2 - 11x -180 = 0
by solving this we get,
x=20, -9
since no. of toys is not negative hence answer is 20

Like? Yes (1) | No   

Md.Sultan Khichi   11 years AGO

Let the no. of toys are x..
So price of single toy is 180/x.
New price of one toy is (180/x +1)..
So according to the ques
(x-1)*(180/x+1)=190.
after solving we get x=20,-9.
So the no. of toys are 20.
Ans:3.

Like? Yes (1) | No   

Dinesh thatti   11 years AGO

Let man bought x toys
Then, cost of one toy = Rs
He kept one toy for his own,
According to question
After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs
so


since the number of toys can never be negative
Hence the man has bought 20 toys

Like? Yes (1) | No   

Nigam Agrawal   11 years AGO

let x is the no. of toys...
then /toys price=180/x
we get one toys and sold rest of them
so (180/x+1)(x-1)=190
for solving this
we get x=20,-9 so 3 option is correct

Like? Yes (1) | No   

Jagadeesh   11 years AGO

toys bought for 20*9=180.
after using one toy and price increased by 1 rupee 19*10=190.
Profit achieved 190-180=10.
Therefore number of toys is 20.

Like? Yes (1) | No   

Paranthamakannan   11 years AGO

XY=180,
(X-1)(Y+1)=190....
solve tihs ...
X=20

Like? Yes (1) | No (1)  

VIKASH KUMAR SHARMA   11 years AGO

let the no. of toys are x.
if he sell the rest toys beside his toy, he is getting 10 rs profit, thrfor it is clear that after taking out his toy he is selling his toys 1 rs more as of the cost price , thrfor if the no. of toys are 20 thn after taking out a single toy, the cost of 20 toy is 180 rs, again for 19 toys the sellipng price = 19*10=190
thrfor the total no. of toys are 20 (ans)

Like? Yes (2) | No (2)  

Devendra Marghade   11 years AGO

If number of toys=x
cost of each toy=180/x
Given (x-1)[(180/x)+1]=190
x^2-11x-180=0
(x-20)(x+9)=0
x=20

Like? Yes (2) | No (2)  

moumita majee   11 years AGO

let X be price of toys and Y be number of toys
then acc to question
XY=180
and (X+1)(Y-1)=190 since 10 rs is profit
solving both eq we get y-x=11
and XY=180.
then X=9
Y=20

Like? Yes (2) | No (2)  

Rituparna Bhattacharyya   11 years AGO

ans. 3)20

let no. of toys be x and price of toys be y
&
AT LAST he is left with one of his toy which he didn't sell and Rs. 10

therefore
x*y = 180
&
(x-1)*(y+1) = 190
on solving for x we'll get x=20 and y =9.

Like? Yes (1) | No (1)  

Md Shahnawaz Shahab   11 years AGO

let no. of toys be x and price of toys be y
therefore x*y = 180
and (x-1)*(y+1) = 190
on solving for x we'll get x=20 and y =9.

Like? Yes (1) | No (1)  

deepak kumar   11 years AGO

Let man bought x toys

Then, cost of one toy = Rs

He kept one toy for his own,

According to question

After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs

so

(x-1)(180/x + 1) = 180+10
(x-1)*180/x + (x-1) = 190
180-180/x + x-1 = 190
x^2 -11x - 180=0
(x-20)(x+9)=0
x=20

Like? Yes (1) | No (1)  

vishal chandra pathak   11 years AGO

simple....1 toy cost 180/x....and profit loss equation...thats all
(180/x +1)(x-1)-180=10
=>(180+x)(x-1)-180x=10x
=>x^2-11x-180=0
so x=20.
thanks

Like? Yes (1) | No (1)  

Bholanath    11 years AGO

let total no. of toys =x
so, cost of one toy=180/x
as kept one toy for own use,
so, remaining toys =x-1
and the man increase the price of each toys by
1 Rs.
so total sold price=(x-1)(180/x +1)
and this must be equal to 190 because profit =10
so,(x-1)(180/x +1)=190
on solving, x=20

Like? Yes (2) | No (2)  

Harjit kaur   11 years AGO

Let no of toys =x
Cp of x toys=180
Cp of 1toy=180/x
SP of 1toy= 180/x+1
SP of x-1 toys=(180/x+1)(x-1)
Now SP-CP=10
(180/x+1)(x-1)-180=10
by solving we get
X^2-11x-180=0
solving this quadratic equation
X=20
thus no of toys =20
Opt is 3

Like? Yes (1) | No (1)  

chandu   11 years AGO

consider we have 90 toys each toy consist 2rps so he sold only 179 toys for 1 rupee he got profit of 10rps of toy that he had so 2*10=20

Like? Yes (1) | No (1)  

Prakash kumar   11 years AGO

let x be no of toys of 180 toys.
so cost of 1 toy = 180/x.
so x-1 toys sold at 180/x + 1

therefore a/c
(x-1) * [(180/x) + 1] = 190
x^2 - 11x - 180 = 0

x =20 (neglect x = -9)

Like? Yes (1) | No (1)  

prabhat kumar   11 years AGO

let no. of toys = x
each toys price = y
according to question,
180/x=y & xy=180-------------(1)
180+10/x+1=y-1
190/x+1=y-1
190=xy-x+y-1
putting euation value in above
190=180-x+y-1
y-x=11
y=10+x---------------(2)
now from first equation
180/x=11+x
x^2-11x-180=0
x=20

Like? Yes (3) | No (3)  

IFFAT IRAM   11 years AGO

let the number of toys be x
c.p. of x toys =180
no. of toys sold=x-1
s.p. of 1 toy=180/x + 1
= (180+x)/x
s.p. of x toys=(180+x)(x-1)/x
(180+x)(x-1)/x - 180 = 10
x^2-11x-180=0
x=20

Like? Yes (1) | No (1)  

Rituraj Singh   11 years AGO

sp-cp=profit

let no. of toys be x
[(x-1)(180/x +1)]-180=10
==>x^2 - 11x - 180 =0
on solving we get

x= -9 and x=20
therefore x=20

Like? Yes (1) | No (1)  

Srinivas    11 years AGO

number of toys =n,cp=180/n
sold n-1,sp=(180/n)+1
sp-cp=profit=10
gives n=20

Like? Yes (1) | No (1)  

susmit   11 years AGO

Let x be number of toys.
Let y be cost per toy.
So, x*y = 180...........(1)
Given :
He sold x-1 toys at the price of y+1.
So, S.P. = (x-1)*(y+1) = xy+x-y-1...........(2)
But x*y = 180 & S.P. = 180+10 = 190.
So 180+x-y-1 = 190
So x-y = 11.................................(3)
Solving (1) & (3) x = 20 & y = 9.
So, number of toys = 20.
Hence option no. (3)

Like? Yes (1) | No (2)  

Dharmendra Singh   11 years AGO

abs 3) 20
equation: x= no of toys;
(180/x +1)(x - 1)=10 put the value and get the result otherwise solve you will get x=20,-9

Like? Yes (1) | No (2)  

anil   11 years AGO

Let man bought x toys
Then, cost of one toy = Rs
He kept one toy for his own,
According to question
After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs
so


since the number of toys can never be negative
Hence the man has bought 20 toys

Like? Yes (1) | No (2)  

achyuth   11 years AGO

Let man bought x toys

Then, cost of one toy = Rs 180/x

He kept one toy for his own,

According to question

After selling (x – 1) toys, he made a profit of Rs 10 by selling each toy for Rs 180/x +1

so
(x-1)(180/x +1)=180+10
x.180/x +x -180/x -1=190
180-180/x +x-1=190
x^2 -11x -180=0
(x-20)(x+9)=0
x=20 or -9

Like? Yes (1) | No (2)  

anurag   11 years AGO

let x toys=rs.180
=> 1 toy cost=rs.180/x
sold x-1 toys each rs.1 extra
=>(x-1)((180/x)+1)=180+10=190
=> x^2-11x-180=0
=> x=20 =>ans=20 toys

Like? Yes (1) | No (2)  

PINKY   11 years AGO

let no of toys be x and their cost be y
then, x*y= Rs 180 (equation 1)
again A/q
(x-1)(y+1)= Rs 190
xy+x-y-1=190
180+x-y=191
x-y=11
x-180/x=11 (from above eqn 1)
by solving above quadratic eqn we will have
x=-9
x=20
so, the no. of toys are 20.

Like? Yes (1) | No (2)  

chaitanya   11 years AGO

Let the number toys be x and cost price of each toy is y,
so xy = 180
and after removing one item, and increasing cost price by 1 rupee
Total cost is (x-1)(y+1) = 180 + 10 ( this 10 is profit)
xy-y+x-1=190
180-y+x=191
x-y=11 [since xy=180, y= 180/x)
x-180/x=11
x^2-180=11x
x^2-11x-180=0
x^2-20x+9x-180=0
x(x-20)+9(x-20)=0
(x-20)(x+9)=0

so x=20, because the number of toys will never be negative.

Like? Yes (1) | No (2)  

lakshay bansal   11 years AGO

let he buys x toys
so cp of 1 toy=180/x
sp of 1 toy = (180/x)+1
sp of x-1 toys = ((180/x)+1)(x-1)=190
so x=20,-9
but -9 not possible so ans is 20

Like? Yes (1) | No (2)  

29 Oct 2013 Coded Language

If in coded language
7321 = 6
5342 = 3
8645 = 15
Then
9312 = ?

OPtion

1) 8
2) 12
3) 5
4) 4
5) 14
6) 2
7) 16
8) 9
9) 7
10)None of these

Solution

7321 = 7*3*2*1 = 42 = 4+2 = 6
5342 = 5*3*4*2 = 120 = 1+2+0 = 3
8645 = 960 = 9+6+0 = 15
Then
9312 = 9*3*1*2 = 54 = 5+4 = 9

Correct Option: 8 Best Solution (45)

susmit   11 years AGO

7321 : 7 * 3 * 2 * 1 = 42, 4 + 2 = 6.
5342 : 5 * 3 * 4 * 2 = 120, 1 + 2 + 0 = 3.
8645 : 8 * 6 * 4 * 5 = 960, 9 + 6 + 0 = 15.
Hence, 9312 : 9 * 3 * 1 * 2 = 54, 5 + 4 = 9.
Hence option no. (8)

Like? Yes (12) | No (2)  

Rituparna Bhattacharyya   11 years AGO

ans. 8
oo....the ans is already there... ;p

logic behind 7321 = 7*3*2*1 = 42 = 6
thus 9321 = 9*3*1*2 = 54 = 9

Like? Yes (4) | No   

Raisul Alam   11 years AGO

7321=7*3*2*1=42=4+2=6
5342=5*3*4*2=120=1+2+0=3
8645=8*6*4*5=960=9+6=15
Similiarly,
9312=9*3*1*2=54=5+4=9

Like? Yes (3) | No   

Ashfaque Hussain   11 years AGO

7321 => 7*3*2*1 = 42 => 4+2 =6
5342 => 5*3*4*2 = 120 => 1+2+0 =3
8645 => 8*6*4*5 = 960 => 9+6+0 =15
Then
9312 => 9*3*1*2 = 54 => 5+4 =9
Final Answer =9

Like? Yes (3) | No   

Gudivada sunitha   11 years AGO

7*3*2*1=42,4+2=6; 5*3*4*2=120,1+2+0=3; likewise 9*3*1*2=54, 5+4=9

Like? Yes (3) | No   

Grishma Shah   11 years AGO

The crack of this coded language is its the sum of the result of multiplication of the digits

7x3x2x1=42==4+2=6
9x3x1x2=54==5+4=9

Like? Yes (2) | No   

Dinesh thatti   11 years AGO

7*3*2*1=42 4+2=6
5*3*4*2=120=1+2+0=3

8*6*4*5=960=9+6+0=15

9*3*1*2=54=5+4=9

Like? Yes (2) | No   

ishita gorai   11 years AGO

7*3*2*1=42 => 4+2=6
5*4*3*2=120 =>1+2+0=3
9*3*1*2=54 => 5+4=9

Like? Yes (2) | No   

moumita majee   11 years AGO

7*3*2*1=42 => 4+2=6
5*4*3*2=120 =>1+2+0=3
9*3*1*2=54 => 5+4=9

Like? Yes (2) | No   

HARI om kashyap   11 years AGO

7*3*2*1=42 => 4+2=6
5*4*3*2=120 =>1+2+0=3
9*3*1*2=54 => 5+4=9

Like? Yes (2) | No   

Niraj   11 years AGO

Multiply all digits of given number and then add the digits of product.

Like? Yes (2) | No   

rohit kumar   11 years AGO

multiply all the digit and after that multiply it,
7321=7*3*2*1=42 i.e 4+2=6
5342=5*4*3*2=120 i.e 1+2+0=3
8645=8*6*4*5=960 i.e 9+6+0=15
so for,
9312=9*3*1*2=54 i.e 5+4=9....ANS

Like? Yes (2) | No   

Md Shahnawaz Shahab   11 years AGO

7321 = 7*3*2*1 = 42 = 4+2 = 6
thus 9321 = 9*3*1*2 = 54 = 5+4= 9

Like? Yes (2) | No   

Md.Sultan Khichi   11 years AGO

Ans has already been given in the question...

Like? Yes (2) | No   

Sourangsu Bandyopadhyay   11 years AGO

The Solution can be derived as:
Let say, we write, 7321=7*3*2*1=42
Now 42 can be broken as 4+2=6
Then, 7321->42->6
Similarly,
5342->120->3
8645->960->15
So,
9312->(9*3*1*2)->54->(5+4)->9 [Ans]

Like? Yes (2) | No   

anil   11 years AGO

7*3*2*1=42=6

Like? Yes (2) | No   

Prakash kumar   11 years AGO

multiply the digits given and add the digits obtained after multiplication.
7*3*2*1 =42 then 4+2 = 6
9*3*1*2 =54 then 5+4 =9

Like? Yes (2) | No   

FAISAL RIZWAN   11 years AGO

7321 =7*3*2*1=42 the add 4+2=6
5342 =5*3*4*2=120=1+2+0=3
8645 = 8*6*4*5=960=9+6+0=15
Then
9312 = 9*3*1*2=54=5+4=9

So option 8 is correct

Like? Yes (2) | No   

VIKASH KUMAR SHARMA   11 years AGO

mutiply then digits n add the nos
9*3*1*2 =54 now 5+4 =9

Like? Yes (2) | No   

Balakumaran N.A   11 years AGO

multiply each digit first and then add it.
9*3*1*2 = 54 = 5+4 = 9. answer given already.... :P

Like? Yes (2) | No   

mathanbabu   11 years AGO

multiply to all digit and then add these number

Like? Yes (2) | No   

Pratyush Praveen   11 years AGO

when 7*3*2*1=42 and 4+2=6
5*3*4*2=120 and 1+2+0=3
8*6*4*5=960 and 9+6+0=15
so 9*3*1*2=54 and 5+4=9

Like? Yes (2) | No   

Dr.Dipin Singh   11 years AGO

7321 = 6..... 7*3*2*1= 42.. Sum of digits =4+2=6
5342 = 3
8645 = 15
Then
9312 = 9.....9*3*1*2= 54... sum of digits = 5+4=9

Like? Yes (2) | No   

Rahul Gupta   11 years AGO

7*3*2*1=42 =>4+2=6
5*3*4*2=120 =>1+2+0=3
8*6*4*5=960 =>9+6+0=15
9*3*1*2=54 =>5+4=9

Like? Yes (2) | No   

Rituraj Singh   11 years AGO

7*3*2*1=42 ==> 4+2=6
5*3*4*2=120 ==> 1+2+0=3
8*6*4*5=960 ==> 9+6+0=15
Similarly,
9*3*1*2=36 ==> 3+6=9

Like? Yes (2) | No   

Roushan Singh   11 years AGO

7321 = 7*3*2*1 = 42
4+2=6

5342 = 5*3*4*2 = 120
1+2+0=3

8645 = 8*6*4*5 = 960
9+6+0=15
similarly,
9312 = 9*3*1*2 =54
5+4=9

Like? Yes (2) | No   

kumar sundram   11 years AGO

First multiplying all digit then adding the digits of product.
7321=7*3*2*1=42=4+2=6;
5342=5*3*4*2=120=1+2+0=3;
8645=8*6*4*5=960=9+6+0=15;
so,
9312=9*3*1*2=54=5+4=9.

Like? Yes (2) | No   

Pooja Gupta   11 years AGO

7*3*2*1=42==>6
5*3*4*2=120==>3
similarly
9*3*1*2=54==>9
so option 8 is correct.

Like? Yes (2) | No   

prabhat kumar   11 years AGO

7321=7*3*2*1=42=4+2=6
5342=5*3*4*2=120=1+2+0=3
8645=8*6*4*5=960=9+6+0=15
then
9312=9*3*1*2=54=5+4=9

Like? Yes (2) | No   

Chithra   11 years AGO

7321=(7*3*2*1)=42=4+2=6
5342=5*3*4*2=120=3
8645=8*6*4*5=15
9312=9*3*1*2=9

Like? Yes (2) | No   

Saurav Mandholiwal   11 years AGO

7*3*2*1=42=4+2=6
5*3*4*2=120=1+2+0=3
8*6*4*5=960=9+6+0=15
similarly....
9*3*1*2=54=5+4=9

Like? Yes (2) | No   

Saurabh keshri   11 years AGO

7*3*2*1=42=4+2=6
5*3*4*2=120=1+2+0=3
8*6*4*5=960=9+6+0=15
similarly....
9*3*1*2=54=5+4=9

Like? Yes (2) | No   

prakash kumar   11 years AGO

7321=7*3*2*1=42=4+2=6
5342=5*3*4*2=120=1+2+0=3
8645=8*6*4*5=960=9+6+0=15
9312=9*3*1*2=54=5+4=9

Like? Yes (2) | No   

pavan   11 years AGO

product of each num
and add the result as 9*3*1*2=54
5+4=9

Like? Yes (2) | No   

Chandni Maurya   11 years AGO

ans=54
7321=>7*3*2*1= 42 => 4+2 = 6
5342=>5*3*4*2=120 =>1+2+0= 3
8645=>8*6*4*5=960 =>9+6+0=15
9312=>9*3*1*2= 54 => 5+4 = 9

Like? Yes (2) | No   

sanjay singh   11 years AGO

7321=7*3*2*1=42>4+2=6
5342=5*3*4*2=120>1+2+0=3
8645=8*6*4*5=960>9+6+0=15>1+5=6
9312=9*3*1*2=54>5+4=9

Like? Yes (2) | No   

pardeep   11 years AGO

7*3*2*1=42,4+2=6
5*3*4*2=120,1+2+0=3
8*6*4*5=960,9+6+0=15
9*3*1*2=54,5+4=9

Like? Yes (2) | No   

Aakash Kumar   11 years AGO

9*3*1*2=54
5+4=9

Like? Yes (2) | No   

Udhaya kumar   11 years AGO

9*3*1*2=54;;;5+4=9

Like? Yes (2) | No   

md shoaib alam   11 years AGO

multiply the digit and then add digit of result,,,,,like
7*3*2*1=42 now add 4+2=6
5*3*4*2=120 now add 1+2+0=3
8*6*4*5=960 now add 9+6+0=15

so 9*3*1*2=540 now add 5+4+0=9 hence 9 is correct that is option (8)

Like? Yes (2) | No   

Sindu   11 years AGO

7*3*2*1=42=>4+2=6.
5*3*4*2=120=>1+2=3.
8*6*4*5=960=>9+6=15.
like wise
9*3*1*2=54=>5+4=9
so ans is 9.

Like? Yes (2) | No   

Dipak Shaw   11 years AGO

option 8)

7321: Take 7⋅3⋅2⋅1=42. Then 4+2=6.

5432: Take 5⋅4⋅3⋅2=120. Then 1+2+0=3.

8645: Take 8⋅6⋅4⋅5=960. Then 9+6+0=15

9312: Take 9.3.1.2=54. Then 5+4=9.

Like? Yes (2) | No   

Ramanand Yadav   11 years AGO

7321=7*3*2*1=42=4+2=6
5342=5*4*3*2=120+1+2+0=3
8645=8*6*4*5=9600=9+6+0+0=15
9312=9*3*1*2=54=5+4=9

Like? Yes (1) | No   

PINKY   11 years AGO

multiply the digits of the no and then add the digits
9*3*1*2=54 then 5+4 =9

Like? Yes (1) | No   

NIPUN JAIN   11 years AGO

7321 7*3*2*1=42. 4+2=6.
5432 5*4*3*2=120. 1+2+0=3.
8645 8*6*4*5=960. 9+6+0=15.
9312 9*3*1*2=54. 5+4=9.

Like? Yes (1) | No   

28 Oct 2013 Sequence

What is the next number of the following sequence
6,39,94,171,270,.....

OPtion

1) 531
2) 520
3) 491
4) 462
5) 425
6) 391
7) 375
8) 357
9) 296
10)None of these

Solution

(1^2*11)-5 = 11-5 = 6
(2^2*11)-5 = 44-5 = 39
(3^3*11)-5 = 99-5 = 94
(4^2*11)-5 = 176-5 = 171
(5^2*11)-5 = 275-5 = 270
Then
(6^2*11)-5 = 396-5 = 391
option 6)

Correct Option: 6 Best Solution (70)

Ashfaque Hussain   11 years AGO

39-6 = 33
94-39 = 55
171-94 = 77
270-171 = 99
Difference b/w two terms increasing by 22
So, next difference b/w two no. 99+22=121
Next number = 270+121 = 391

Like? Yes (19) | No (2)  

Rituparna Bhattacharyya   11 years AGO

ans. 391
there is a diff of 22 in between common difference every two nos.

Like? Yes (3) | No   

Grishma Shah   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
Hence the next difference should be 121
Hence, 270+121=391

Like? Yes (2) | No   

VIKASH KUMAR SHARMA   11 years AGO

the diff btn two terms is 33 thn 55 thn 77 thn 99
thrfor the diffrnc btn these two terms= 22
thrfor the next term in the above terms is 99+22=121
thrfore next term in the qstn will be 270+121=391 ans

Like? Yes (2) | No   

Pratyush Praveen   11 years AGO

the difference between them is 33,55,77, and so on so the next no will 391 when 121 is added to 270

Like? Yes (2) | No   

prabhat kumar   11 years AGO

6,39,94,171,270,391 because
39-6=33
94-39=55
171-94=77
270-171=99
391-270=121

Like? Yes (2) | No   

Manish Singh   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
so diff of there differences is 22
so next term will be 270+(99+22)=391 :)

Like? Yes (2) | No   

Rajasekhar   11 years AGO

6+(11*3),39+(11*5),94+(11*7),171+(11*9),270+(11*11)

Like? Yes (2) | No   

Amit Ghosh   11 years AGO

6+33=39
39+55=94
94+77=171
171+99=270
270+121=391

Like? Yes (2) | No   

susmit   11 years AGO

1st order differences are 33, 55, 77, 99.
2nd order differences are 22, 22, 22.
So the fifth 1st order difference is 99 + 22 = 121.
Hence the required number is 270 + 121 = 391.
Hence option no.(6)

Like? Yes (3) | No (2)  

Manish Kumar   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
391-270=121

We add 22 to the differences to get next difference.

Like? Yes (2) | No (1)  

Dharmendra Singh   11 years AGO

ans. 6)391
Explanation:
there's difference in odd multiple of 11
39-6=33=11*3
94-39=55=11*5
171-94=77=11*7
270-171=99=11*9
next will maintain difference 11*11
so 391-270=121=11*11 :)

Like? Yes (3) | No (2)  

Neha Rani   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
391-270=121
ans=391

Like? Yes (1) | No   

HARI om kashyap   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
so 22 is the difference then next is 121 hence
270+121=391

Like? Yes (1) | No   

Dinesh thatti   11 years AGO

6,6+33,39+55,94+77,171+99,270+121=391

Like? Yes (1) | No   

ishita gorai   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
so 22 is the difference then next is 121 hence
270+121=391

Like? Yes (1) | No   

moumita majee   11 years AGO

difference between consecutive numbers
39-6=33
94-39=55
171-94=77
270-171=99
so 22 is the difference then next is 121 hence
270+121=391

Like? Yes (1) | No   

Dharmendra Kumar Rajak   11 years AGO

Given sequence is 6,39,94,171,270,.....
We will expand it as follows
39-6=33 =>6+33=39;
94-39=55 =>39+55=94;
171-94=77 =>94+77=171;
270-171=99 =>171+99=270;
Similarly =>270+121=391;
So option (6) is correct.

Like? Yes (1) | No   

Dipak Shaw   11 years AGO

answer is 6)391
6+33=94
94+55=171
Starting with d addition of 33 in the first no.,then
in next no. addition of 22 more as compare to previous addition. i.e.addition of 33+22=55
And this process will continue
so the series will be
6+33 = 39
39+55 =94
94+77 =171
171+99=270
270+121 =391

Like? Yes (1) | No   

Prakash kumar   11 years AGO

difference between the terms are 33, 55, 77, 99
And the difference between these terms is 22
therefore 99+22= 121
so next term will be 270+121 = 391

Like? Yes (1) | No   

sandipan patra   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
270+121=391

Like? Yes (1) | No   

Md Shahnawaz Shahab   11 years AGO

ans. 391
the common difference are in AP.

Like? Yes (1) | No   

Raisul Alam   11 years AGO

The diffrence between two consequtive numbers are 33(39-6),55(94-39),77(171-94),99(270-171)..So the diffrences are 33(11*3),55(11*5),77(11*7),99(11*9) and the next diffrence will be 11*11 hence 121. So the next number will be 270+121=391

Like? Yes (1) | No   

deepak kumar   11 years AGO

difference b/t the series is 11 multiple with odd number ie 11*3 , 11*5, 11*7, 11*9,11*11
so 270+121=391

Like? Yes (1) | No   

prem singh   11 years AGO

first term is 6 than
33+6=39
55+39=94
77+94=171
99+171=270
121+270=391
so answer is 391

Like? Yes (1) | No   

Jyothi   11 years AGO

6-39=-33
39-94=-55
94-171=-77
171-270=-99
270+121=391

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

39-6=33
94-39=55=33+22
171-94=77=55+22
270-171=99=77+22
x-270=99+22
x=391
hence the last number is 391

Like? Yes (1) | No   

Rashmi bharti   11 years AGO

270+121=391

Like? Yes (1) | No   

MUKESH KUMAR   11 years AGO

11*x^2 − 5

In place of x:-
putting 1 we get = 6,
putting 2 we get = 39,
.
.
.
putting 6 we get = 391.

Like? Yes (2) | No (1)  

Anilkumar   11 years AGO

11*0+6
11*3+6
11*(3+5)+6
11*(3+5+7)+6
11*(3+5+7+9)+6
11*(3+5+7+9+11)+6

Like? Yes (1) | No   

Shubhi Thatere   11 years AGO

The difference between 2 nos. are like 33 55 77 99 so it is d difference of 22 i. e 270 & 121 makes 391

Like? Yes (1) | No   

Chithra   11 years AGO

6 +33=39, 39+55=94,
94+77=171, 171+99=270,
270+121=391

Like? Yes (1) | No   

Sriparna Boote   11 years AGO

in the sequence
39-6 = 33 =11*3
94-39=55=11*5
171-94= 77= 11*7
270-171=99=11*9

so the next term will be 270+(11*11)=270+121=391

391 is the required answer

Like? Yes (1) | No   

Laltu banerjee   11 years AGO

6 39 94 171 270
here difference between number is
33 55 77 99 i.e 11*3 11*5 11*7 11*9
hence the next term in a difference of 11*11
270+121=391

Like? Yes (1) | No   

mahak saha   11 years AGO

6+33=39
39+55=94
94+77=171
171+99=271
270+121=391

Like? Yes (1) | No   

harjeet   11 years AGO

ans=6
here In sequence...
39-6=33
94-39=55
171-94=77
270-171=99
so, the (common difference) of difference b/w successive no's is=22
for next no. 99+22=121

and next no. should be- 270+121=391

Like? Yes (1) | No   

twinkle sahoo   11 years AGO

its a difference series
6 (+33)39(+55) 94(+77) 171(+99) 270(+121)=391

33(+22)55(+22)77(+22)99(+22)=121

Like? Yes (1) | No   

MOHIT BHARDWAJ   11 years AGO

39-6=33,11*3
94-39=55,11*5
171-94=77,11*7 etc so 391-270=121 which is 11*11

Like? Yes (1) | No   

raju kumar sah   11 years AGO

6+33=39
39+55=94
94+77=171
171+99=270
next no is 270+121=391

Like? Yes (1) | No   

ravi kumbhkar   11 years AGO

with every number there is the increase of 22
so, next number 391

Like? Yes (2) | No (1)  

anil   11 years AGO

33/11 55/11 77/11 99/11 121/11
3 5 7 9 11

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=391
difference of this series,
33,55,77,99 which is increased by 22
99+22=121
next no=270+121=391

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

6+(11*3)=39
39+(11*5)=94
94+(11*7)=171
171+(11*9)=270
270+(11*11)=391

Like? Yes (1) | No   

mukesh   11 years AGO

difference between no\'s are 33 55 77 99 so next difference is 121
so no will be 121+270=391

Like? Yes (1) | No   

KARUPPASAMY C   11 years AGO

39-6=33
94-39=55
171-94=77
270-171=99
391-270=121
the ans in 391
so the option (6)

Like? Yes (1) | No   

mohan   11 years AGO

difference is 33,55,77,99,121

Like? Yes (1) | No   

vinod   11 years AGO

add 33,55,77,99 in sequence to get next number
so ans is 270+111=391

Like? Yes (1) | No   

Ramsb   11 years AGO

33-6=33
94-39=55
171-94=77
270-171=99
99+20+171=391

Like? Yes (1) | No   

Roushan Singh   11 years AGO

39-6 = 33
94-39 = 55
171-94 = 77
270-171 = 99
Difference b/w two terms increasing by 22
So, next difference b/w two no. 99+22=121
Next number in the series will be 270+121 = 391

Like? Yes (1) | No   

akash   11 years AGO

differnce between numbers is in a.p.
33,55,77,99,121
270+121=391

Like? Yes (1) | No   

Ramanand Yadav   11 years AGO

6,39,94,171,270.....
that means
39-6=33
94-39=55
171-94=77
270-171=99
we can see that
33+22=55
55+22=77
77+22=99
so next will be 99+22=121
that is 270+121=391

Like? Yes (1) | No   

Saurav Mandholiwal   11 years AGO

39-6=33=11*3
94-39=55=11*5
171-94=77=11*7
270-171=99=11*9
next term=270+11*11=270+121=391

Like? Yes (1) | No   

Sushil Singh   11 years AGO

39-6=33(11*3)
94-39=55(11*5)
171-94=77(11*7)
270-171=99(11*9)
391-270=121(11*11)
391(ans)

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

each term exceeds diffrence of the last two by 22

Like? Yes (1) | No   

lakshay bansal   11 years AGO

differnce=33,55,77,99
so next difference is 121
so 121+270=391

Like? Yes (1) | No   

Nitin rahtor   11 years AGO

6+33=39 39+55=94 94+77=171 171+99=270 270+121=391

Like? Yes (1) | No   

ravi singh   11 years AGO

answer is 391

differenace is 33,55,77,99 hence next is 121
therefore 121+270=391

Like? Yes (1) | No   

SUMIT   11 years AGO

39-6=33(11*3);94-39=55(11*5);171-94=77(11*7)
270-171=(11*9); so,next no.=11*11+270=391

Like? Yes (1) | No   

FRANKLIN VIJAY   11 years AGO

6+(33)=39
39+(55)=94
94+(77)=171
171+(99)=270
270+(121)=391
The Answer is 391

Like? Yes (1) | No   

ChinnaChowdaiah   11 years AGO

the sequence is 6,39,94,171,270...
39-6=33
94-39=55
171-94=77
270-171=99
x-270 will be 121 .
so answer is 391.

Like? Yes (1) | No   

achyuth   11 years AGO

the difference between the two numbers is 22

Like? Yes (1) | No   

immortal   11 years AGO

6
39=6+33
94=39+55
171=94+77
270=171+99
391=270+121

Like? Yes (1) | No   

ANUPAM KUMAR   11 years AGO

6,6+33,39+55,94+77,171+99,270+121,

Like? Yes (1) | No   

dudhanath patel    11 years AGO

39-6=33 =>3*11
94-39=55 =>5*11
171-94=77 =>7*11
270-171=99 =>9*11
So,
x-270=121 =>11*11
Hence x=391.
Option (6) is correct.

Like? Yes (1) | No   

Bholanath    11 years AGO

6,39,94,171,270,...
differences
33,55,77,99
again,
22,22,22
it means difference of differences is 22
so next difference must be 99+22=121
so, next number will be=270+121=391

Like? Yes (1) | No   

Shrikant kumar   11 years AGO

X-270=121
X=391

Like? Yes (1) | No   

prateek jain   11 years AGO

ans-6
6-39 difference of =33
39-94 differrnce of=55
....
.....
270-391 difference of=121
ans=6

Like? Yes (1) | No   

sivaramakrishna   11 years AGO

39-6=33=11*3
94-39=55=11*5
171-94=77=11*7
270-171=99=11*9


391-270=121=11*11

Like? Yes (1) | No   

saurabh agarwal   11 years AGO

diff between 6 and 39 is 33,
diff between 39 and 94 is 55,
diff between 94 and 171 is 77,
so his pattern you get the correct answer.

Like? Yes (1) | No   

Bharat Bhushan Jha   11 years AGO

diff between each next is odd multiple of 11

Like? Yes (1) | No   

25 Oct 2013 Number of student

Student of a class are made to stand in rows. If 4 student are extra in a row, there would be 2 rows less. If 4 student are less in a row, there would be 4 more rows, find the number of student in the class.

OPtion

1) 16
2) 32
3) 48
4) 64
5) 72
6) 88
7) 96
8) 108
9) 120
10)None of these

Solution

Le no of rows = x and no of student in each row y
total no of student x*y
By given condition
(x-2)(y+4)=xy (i)
(x+4)(y-4)=xy (ii)
Solve
x=8, y=12
no of student = 12*8 = 96
option 7

Correct Option: 7 Best Solution (26)

MUKESH KUMAR   11 years AGO

Let x be a number of students in a row and y be a number of students in a column. Then the amount of kids is xy.
(x+4)(y-2)=(x-4)(y+4)=xy
xy+4y-2x-8=xy-4y+4x-16=xy
4y-2x-8= -4y+4x-16=0 add two first equations.
2x-24=0
x=12
4y-24-8=0
4y=32
y=8
xy=12*8=96

Like? Yes (86) | No (20)  

prabhat kumar   11 years AGO

let,
no. of students in a row = y
no. of rows = x
so no. of studenta in class = no. of student in a row*no. of rows = xy
according to question,
(y+4)(x-2)=no. of student=xy
xy-2y+4x-8=xy
4x-2y=8
2x-y=4------------(1)

(y-4)(x+4)=no. of students in class=xy
xy+4y-4x-16=xy
-x+y=4-----------(2)
by solving equation (1) & (2)
x=8
y=12
so number of students in class = xy = 12*8 = 96.

Like? Yes (66) | No (13)  

Grishma Shah   11 years AGO

If no. of student = x
and no of row =y
then from given:
total student = xy
xy = (x+4)(y-2)
xy = (x-4)(y+4)

Solving the above
x=12
y=8
Hence total no. of student = 12x8 = 96
The option seven 7) is answer

Like? Yes (31) | No (10)  

ArunKumar   11 years AGO

let x = number students in a row
let y = number of rows
then No of students = xy
"If four students are extra in a row there would be two rows less."
(x-2)(y+4) = xy
xy + 4x - 2y - 8 = xy
4x - 2y - 8 = 0
2x - y = 4
"If four students are less in a row there would be four more rows."
(x+4)(y-4) = xy
xy - 4x + 4y - 16 = xy
-4x + 4y = 16
-x + y = 4

Adding these two equations eliminates s
2x - y = 4
-x + y = 4
-------------
x = 8 rows
find s:
-8 + y = 4
y = 4 + 8
y = 12 students in a row

the number of students in the class?
8 * 12 = 96 students

Like? Yes (21) | No (5)  

Saurav Mandholiwal   11 years AGO

Let no. of student in each row=x
let no. of rows=y
total no. of student=xy
now,
(x+4)(y-2)=xy (eqn1)
(x-4)(y+4)=xy (eqn2)
solving eqn1 & eqn2
we get,x=12,y=8
hence no. of student=xy=12*8=96

Like? Yes (16) | No (4)  

rohit kumar   11 years AGO

there would be 12 students in each row and it contains 8 rows,
so total no of students=12*8=96
if we increase 4 students in each row i.e 16 and it decreases 2 rows i.e 6 (total=16*6=96)
next,
if we decrease 4 students in each row i.e 8 and it will increases 4 students in each row that will be 12 students in each row(total=8*12=96)
so,
the ans will be 96...ANS

Like? Yes (12) | No (5)  

chaitanya   11 years AGO

let s = number students in a row
let r = number of rows
then
No of students = rs
;
"If four students are extra in a row there would be two rows less."
(r-2)(s+4) = rs
FOIL
rs + 4r - 2s - 8 = rs
rs - rs + 4r - 2s - 8 = 0
4r - 2s = 8
2r - s = 4; simplified, divided by 2
:
"If four students are less in a row there would be four more rows."
(r+4)(s-4) = rs
rs - 4r + 4s - 16 = rs
rs - rs - 4r + 4s = 16
-4r + 4s = 16
-r + s = 4; simplified, divided by 4
:
Adding these two equations eliminates s
2r - s = 4
-r + s = 4
-------------
r = 8 rows
:
find s:
-8 + s = 4
s = 4 + 8
s = 12 students in a row
:
Find the number of students in the class?
8 * 12 = 96 students
:
:
See if that's true
"If four students are extra in a row there would be two rows less."
(12+4)*(8-2) =
16 * 6 = 96
and
"If four students are less in a row there would be four more rows."
(12-4)*(8+4) =
8 * 12 = 96

Like? Yes (9) | No (3)  

kumar sundram   11 years AGO

Let us assume that x is the no. of rows & y is the no. of student per row.
so, total no. of student = xy
a/c to question-
xy=(x-2)(y+4)
or, xy=xy-2y+4x-8
or, 2x-y=4.......(1)
again, a/c to question-
xy=(y-4)(x+4)
or, xy=xy+4y-4x-16
or, 2y-2x=8......(2)
adding eq(1) & eq(2) we have,
y = 12
substituting the value of y in eq(1) we get,
x=(4+12)/2=16/2=8.
thus the no. of students=12*8=96.

Like? Yes (8) | No (3)  

Dipak Shaw   11 years AGO

let no. of stdnts in row x and row is r.
total no. of stdnts = xr
from 1st condition,
xr = (x+4)(r-2)
or, xr = xr-2x+4r-8
or, x = 2r-4 -------------(i)

from 2nd condition,
xr = (x-4)(r+4)
so, x = r+4 ---------------(ii)
by compairing eqn (i) & (ii), we get
r=8
& x=12

so,no.of stdnt in the class = 12*8 = 96

Like? Yes (5) | No (1)  

ABHISHEK KUMAR MISHRA   11 years AGO

Let no of students in the class=x
No. of student in a row=y
so total no of rows=x/y
Now according to question
x/y - 2 = x/(y+4).....(1)
x/y + 4 = x/(y-4)......(2)
solve (1) & (2) then
y=12 and x=96
so our required answer is 96 i.e option 7)

Like? Yes (11) | No (7)  

ShAg   11 years AGO

initially, number or rows = 8
and number of students in each row = 12
total = 8*12=96

Like? Yes (8) | No (4)  

raghuram dharmavarpu   11 years AGO

Let number of students be x, number of students in a row be y and number of rows be n
x=ny-----(1)
x = (n - 2) (y + 4)

ny = ny + 4n - 2y - 8

Or, 4n - 2y - 8 = 0 ----------------- (2)

Or, 2n - y - u = 0

and x = (n + 4) (y - 4)

ny = ny - 4n + 4y - 16

Or, -4n + 4y - 16 = 0

Or, -n + y - u = o -------------------- (3)

Adding (2) & and (3)

From (3) y = n + 4 = 8 + 4 = 12

so that x=ny=96

Like? Yes (6) | No (3)  

Vishwadeep Solpankhi   11 years AGO

Students of a class are made to stand in rows. If four students are extra in a
row there would be two rows less. If four students are less in a row there
would be four more rows. Find the number of students in the class?
:
let s = number students in a row
let r = number of rows
then
No of students = rs
;
\"If four students are extra in a row there would be two rows less.\"
(r-2)(s+4) = rs
FOIL
rs + 4r - 2s - 8 = rs
rs - rs + 4r - 2s - 8 = 0
4r - 2s = 8
2r - s = 4; simplified, divided by 2
:
\"If four students are less in a row there would be four more rows.\"
(r+4)(s-4) = rs
rs - 4r + 4s - 16 = rs
rs - rs - 4r + 4s = 16
-4r + 4s = 16
-r + s = 4; simplified, divided by 4

:
Adding these two equations eliminates s
2r - s = 4
-r + s = 4
-------------
r = 8 rows
:
find s:
-8 + s = 4
s = 4 + 8
s = 12 students in a row
:
Find the number of students in the class?
8 * 12 = 96 students
:
:
See if that\'s true
\"If four students are extra in a row there would be two rows less.\"
(12+4)*(8-2) =
16 * 6 = 96
and
\"If four students are less in a row there would be four more rows.\"
(12-4)*(8+4) =
8 * 12 = 96

Like? Yes (4) | No (2)  

Manish Kumar   11 years AGO

The number of student in the class is 96.

There are 8 rows earlier containing 12 students each, a total of 96 students.
If 4 student are extra in a row, there would be 2 rows less. i.e, in 6 rows of 16 students each = 96 students.

If 4 student are less in a row, there would be 4 more rows, i.e, in 12 rows of 8 students of each = 96 students.

Like? Yes (3) | No (2)  

Garima   11 years AGO

"If four students are extra in a row there would be two rows less."
(12+4)*(8-2) =
16 * 6 = 96
and
"If four students are less in a row there would be four more rows."
(12-4)*(8+4) =
8 * 12 = 96

Like? Yes (3) | No (2)  

BADAM CHAITANYA KUMAR   11 years AGO

let s = number students in a row
let r = number of rows
then
No of students = rs
;
\"If four students are extra in a row there would be two rows less."
(r-2)(s+4) = rs

rs + 4r - 2s - 8 = rs
rs - rs + 4r - 2s - 8 = 0
4r - 2s = 8
2r - s = 4; simplified, divided by 2
:
\"If four students are less in a row there would be four more rows.\"
(r+4)(s-4) = rs
rs - 4r + 4s - 16 = rs
rs - rs - 4r + 4s = 16
-4r + 4s = 16
-r + s = 4; simplified, divided by 4
Adding these two equations eliminates s
2r - s = 4
-r + s = 4
-------------
r = 8 rows
:
find s:
-8 + s = 4
s = 4 + 8
s = 12 students in a row
:
Find the number of students in the class?
8 * 12 = 96 students
:
:
See if that\'s true
\"If four students are extra in a row there would be two rows less.\"
(12+4)*(8-2) =
16 * 6 = 96
and
\"If four students are less in a row there would be four more rows.\"
(12-4)*(8+4) =
8 * 12 = 96

Like? Yes (5) | No (4)  

HARI om kashyap   11 years AGO

let X=number of rows
y=number of student in each row
then total number of student=xy
as stated in question
first case
(x-2)(y+4)=xy
4x-2y-8=0 ----- 1

second case
(x+4)(y-4)=xy
4y-4x-16=0 -------------- 2

solving eq 1 and 2
2y=24
y=12
puting value of y in eq 1 we got x=8
so total num of student=12*8 = 96

Like? Yes (4) | No (4)  

FRANKLIN VIJAY   11 years AGO

Let x be a number of students in a row and y be a number of students in a column. Then the amount of kids is xy.
(x+4)(y-2)=(x-4)(y+4)=xy
xy+4y-2x-8=xy-4y+4x-16=xy
4y-2x-8= -4y+4x-16=0 add two first equations.
2x-24=0
x=12
4y-24-8=0
4y=32
y=8
xy=12*8=96

Like? Yes (2) | No (2)  

krishnapriya   11 years AGO

Let x be the number of rows and y be the number of students
Total no.of students=no. of rows * no of students=xy
In given case 1,xy=(y+4)(x-2)
solving the above we get 4x-2y=8---------(1)

In given case2, xy=(y-4)(x+4)
solving the above we get 4x-4y=-16---------(2)

Solving eqns. (1) and (2) we get,
x=8 and y=12
Total no. of students=8*12=96

Like? Yes (3) | No (3)  

jagdish sharma   11 years AGO

total rows=r
Studnt in one row=s
case 1
if 4 student are extra in a row then two rows are less
Total student=(r-2)(s+4)
Case 2
similarly total students=(s-4)(r+4)
find the value of s and r
then total students=s*r=96

Like? Yes (2) | No (2)  

gurunadh   11 years AGO

let s = number students in a row
let r = number of rows
then
No of students = rs
;
"If four students are extra in a row there would be two rows less."
(r-2)(s+4) = rs
FOIL
rs + 4r - 2s - 8 = rs
rs - rs + 4r - 2s - 8 = 0
4r - 2s = 8
2r - s = 4; simplified, divided by 2
:
"If four students are less in a row there would be four more rows."
(r+4)(s-4) = rs
rs - 4r + 4s - 16 = rs
rs - rs - 4r + 4s = 16
-4r + 4s = 16
-r + s = 4; simplified, divided by 4

:
Adding these two equations eliminates s
2r - s = 4
-r + s = 4
-------------
r = 8 rows
:
find s:
-8 + s = 4
s = 4 + 8
s = 12 students in a row
:
Find the number of students in the class?
8 * 12 = 96 students
:
:
See if that's true
"If four students are extra in a row there would be two rows less."
(12+4)*(8-2) =
16 * 6 = 96
and
"If four students are less in a row there would be four more rows."
(12-4)*(8+4) =
8 * 12 = 96

Like? Yes (2) | No (2)  

poonam   11 years AGO

(x-4)(y+4) = xy = (x+4)(y-2)
solving these equation :
x=12
y=8
so total no of students = 96

Like? Yes (4) | No (4)  

pavan   11 years AGO

let there be x rows and y students in each row
(x-2)(y+4)=Xy
(x+4)(y-4)=xy solving we get 96

Like? Yes (3) | No (3)  

prakash kumar   11 years AGO

let no of rows=x
& no of students in each row=y
a/q, (x-2)(y+4)=xy
4x-2y=8
2x-y=4------(1)
again, (x+4)(y-4)=xy
-4x+4y=16
-x+y=4------(2)
fron 1 & 2,
2x-y=4
-x+y=4
x=8
so y from eqn (2)
y=x+4
=8+4
=12
so, total no of students in a class=xy=8*12=96

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VIMALRAJ V   11 years AGO

Let the number of students in each row be x, and the number of rows be y.
xy = (x + 4)(y – 2)
xy = (x – 4)(y + 4)
From xy = (x + 4)(y – 2):
xy = xy – 2x + 4y – 8
xy – xy = xy – 2x + 4y – 8 – xy
0 = -2x + 4y – 8
0 = x – 2y + 4
x – 2y + 4 – 4 = 0 – 4
x – 2y = -4
From xy = (x – 4)(y + 4):
xy = xy + 4x – 4y – 16
xy – xy = xy + 4x – 4y – 16 – xy
0 = 4x – 4y – 16
0 = x – y – 4
x – y – 4 + y + 4 = 0 + y + 4
x = y + 4
Substitute x = y + 4 into x – 2y = -4:
y + 4 – 2y = -4
-y + 4 = -4
-y + 4 – 4 = -4 – 4
-y = -8
y = 8
Substitute y = 8 into x = y + 4:
x = 8 + 4
x = 12
xy = (12)(8) = 96
therefore answer is 96

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ChinnaChowdaiah   11 years AGO

x=no.students to each row
n=no. of rows
total no.of students=xn
(x+4)(n-2)=xn
(x-4)(n+4)=xn
after solving these two equations
2x-4n=-8
-4x+4n=-16
so..by solving
-2x=-24
x=12
then n=8
at last the total no of students= xn
=12*8
=96

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