M4maths Previous Puzzles

24 Oct 2013 Quadratic Equation

If the root of the quadratic equation x^2-4x-log a(base3)=0 are real, then find the least value of a.

OPtion

1) 1/16
2) 1/8
3) 1/2
4) 1/9
5) 1/36
6) 1/27
7) 1/64
8) 1/72
9) 1/81
10)None of these

Solution

Since the root of the given equation are real
Discriminant >= 0
16 + 4 log a(base3)>=0
log a(base3)>= -4
a >= 3^-4
a >= 1/81
option 9

Correct Option: 9 Best Solution (31)

ArunKumar   11 years AGO

x^2-4x-log a(base3)=0
for real, b^2-4ac=0
4^2-4*( -log a(base3)= 0
16+4*log a(base3)= 0
4*log a(base3)= -16
log a^4(base3)= -16
a^4= 3^-16
a^4= (3^-4)^4
a^4= (1/3^4)^4
a = 1/3^4
a= 1/81

Like? Yes (16) | No (4)  

ABHISHEK KUMAR MISHRA   11 years AGO

For real root (-4)^2 - -4*1*(-log a(base3))>=0
or, 16+log a(base3)>=0
16>=-log a(base3)...(1)
so here least value of a according to the option 1/81 which satisfied (1)
so option is 9)

Like? Yes (9) | No (4)  

Grishma Shah   11 years AGO

If roots of the equation are real then b^2 -4ac >=0
Here a=1 , b=-4 ,c =-loga(base 3)
b^2-4ac =16 + 4 loga
for real roots 16 + 4log a>=0
thus loga >= -4
for base 3, to satify above condition a=1/81 ,1/9,1/3
thus for minimum value of a ,answer is 1/81

Like? Yes (5) | No   

Ashfaque Hussain   11 years AGO

D=0, roots are real
16 + 4*1*log a(base3)=0
log a(base3)= -4
a = 3^-4
a=1/3^4
a=1/81

Like? Yes (6) | No (1)  

md shoaib alam   11 years AGO

a=(1/3)^4

after computing roots of equation

Like? Yes (7) | No (2)  

Rituparna Bhattacharyya   11 years AGO

ans. 9) 1/81

x^2 -4x - log a(base3)=0
=>log a(base3) = x^2 -4x
=> a = 3^(x^2-4x)
for x = 2
we have
a = 3^(-4)
thus
a = 1/81

Like? Yes (4) | No (1)  

Rats   11 years AGO

given equation :
x^2-4x-log a(base3)=0
here a=1, b=-4, c=-log a(base3)
for roots to be real
b^2-4ac=0
(-4^2)-4*1*(-log a(base3)) = 0
16+4log a(base3)=0
log a(base3)=-4
a=3^-4
a=1/81........Ans

Like? Yes (5) | No (2)  

Mayuresh Srivastava   11 years AGO

for real roots D>=0
i.e. b^2-4ac>=0
16+4log a(base3)>=0
a>=1/3^4
so least value=1/81.

Like? Yes (4) | No (2)  

kumar sundram   11 years AGO

for real root, b^2-4*a*c greater than equal to zero.
i.e, (-4)^2-4*{1*[-log a(base3)]}=0
or, 16+4*log a(base3)=0
or, 16=-4*log a(base3)
or, -4=log a(base3)
or, a=(3)^(-4)=1/81

Like? Yes (3) | No (1)  

Md Shahnawaz Shahab   11 years AGO

ans: option 9 : 1/81

x^2 -4x - log a(base3)=0
=>log a(base3) = x^2 -4x
=> a = 3^(x^2-4x)
substituting the value of 1/81 as 'a' we get
real solutions and its the least the given option
thus,
a = 1/81

Like? Yes (3) | No (2)  

Dharmendra Kumar Rajak   11 years AGO

Given equation is x^2-4x-log a(base3)=0,
is real
So for real root
a>0 and D>=0;
D=b^2-4ac
=(-4)^2-(4*1*-log a)
i.e. => 16+4 log a(base3)>=0
=> 4 log a(base3)>=-16
=> log a(base3)>=-4
=> a>=3^-4
=> a>=1/3^4
=> a>=1/81
So least value of a =1/81
So option (9) is correct

Like? Yes (1) | No   

Sriparna Boote   11 years AGO

As it is given the roots are real so D(discriminate) must be >=0.
D=b^2-4ac>=0
16-4loga(base 3)>=0
Solving we get a>=1/81
so Minimum value of a is 1/81

Like? Yes (1) | No   

ak   11 years AGO

x^2-4x-loga(base3)=0
roots are,x=-b(+-)root(b^2-4ac)/2a
x=2(+-)root(4+log3a)
if roots are real,
4-log3a>=0
a>=3^-4
a>=1/81
a=1/81

Like? Yes (1) | No   

raghuram dharmavarpu   11 years AGO

the value 81 will be the least value for above expression a=1/81
because it can be written as log a(base3)=-4
sub in above expression we get (x-2)^2 expression

Like? Yes (1) | No   

Rahul Gupta   11 years AGO

x^2-4x-log(base3)=0
x=4+-Sqrroot(16+4loga(base3))
x=2+-sqrroot(4+loga(base3))
now calculate loga(base3) you find 1/81 is less value for a.

Like? Yes (2) | No (1)  

akash   11 years AGO

For least value of a,discriminant=0
4^2+4loga(base 3)=0
solving this,value of a=3^(-4)=1/81

Like? Yes (1) | No   

jagdish sharma   11 years AGO

when roots are real then
b*b-4ac>=0
4^2-4*log(base3)a>=0
a>=1/81

Like? Yes (1) | No   

lakshay bansal   11 years AGO

x^2-4x-loga(base3)=0
b^2-4ac=0
16+4loga(base 3)=0
log a(base 3)=-4
a=3^(-4)
a=1/81

Like? Yes (1) | No   

Anantharaman   11 years AGO

Minimum value for a,

Using elimination method

Starting from minimum value for a

a = 1/81 => x^2-4x+4 = 0 => x= 2

1/81 (Option 9)

Like? Yes (2) | No (1)  

Prakash kumar   11 years AGO

For roots to be real
D = b^2 -4ac =0
16-4*1*-loga(base3)=0
16+4/loga(base3)= 0
loga(base3) = -4
a = 3^-4
a = 1/81

Like? Yes (1) | No   

Jyothi   11 years AGO

(b^2)-4ac=0
c=4 so loga(base3)=4
a=1/81

Like? Yes (1) | No   

prakash kumar   11 years AGO

for real roots
16+4loga(base3)>=0
loga(base3)>=-4
3^-4=a
a=1/81

Like? Yes (2) | No (1)  

Bharat Bhushan Jha   11 years AGO

a=1/27 and 1/81
both satisfy the given equation
but least value of a=1/81

Like? Yes (2) | No (1)  

Shrikant kumar   11 years AGO

D=B^2-4ac=0

Like? Yes (1) | No   

Saurabh Mishra   11 years AGO

4*4-4*1*(-loga(base 3))>=0
on solving this equation we get value
of a>=1/81

Like? Yes (1) | No   

sandipan patra   11 years AGO

as roots are real,
4^2-4*1*(-loga(base3))>=0
=> log a(base 3)>=-4
=> a>=1/81
least value of a=1/81

Like? Yes (1) | No (1)  

HARI om kashyap   11 years AGO

we need to find b^2-4ac>=0
4ac= 4*1*-log a base3
applying 1/81 since 81 is 4th power of 3
-log 1/81 base 3= -log 1 base 3 + log 81 base 3
=0+4
=4
d= 4^2 - 4*1*4
d=0
hence real roots

Like? Yes (1) | No (1)  

rohit kumar   11 years AGO

given,
x^2 - 4x - loga(base 3) = 0
the discriminant will be,
d = (-4)^2 - 4(1)(-log(a))
d = 16 + 4*log(a)
For the roots to be real, the discriminant must be non-negative(i.e >0),
16 + 4*log(a) >= 0
4*log(a) >= -16
log(a) >= -16/4
log(a) >= -4
a >= 3^(-4)
a >= 1/81
The minimum value of a is 1/81

Like? Yes (3) | No (3)  

ravi singh   11 years AGO

answer is 1/81
for least real value b^2-4ac=0

by putting the value og a,b,c we get
4^2+4*loga(base3)=0
therefore,1/a=3^4
hence a=1/81

Like? Yes (1) | No (1)  

Rashmi bharti   11 years AGO

b^2-4ac greater than or equal to 0
16+4log a(base 3)greater than equal to 0
a=1/81

Like? Yes (1) | No (1)  

Manish Kumar   11 years AGO

For x^2-4x-log a(base3)=0 to be real,
b^2-4ac >= 0, i.e, 16-4c >= 0
so, c

Like? Yes (2) | No (4)  

23 Oct 2013 Code For JAY

In coded language
RAM = 234
SUN = 5586
ANU = 294
Then
JAY = ?

OPtion

1) 170
2) 2560
3) 1680
4) 454
5) 625
6) 1225
7) 845
8) 250
9) 275
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
In coded language
RAM = 18*1*13 = 234 (Multiply)
SUN = 19*21*14 = 5586
ANU = 1*14*21 = 294
Then
JAY = 10*1*25 = 250
option 8

Correct Option: 8 Best Solution (65)

Manish Kumar   11 years AGO

RAM-18*1*13 =234
SUN-19*21*14=5586
ANU-1*14*21=294
Similarly
JAY-10*1*25=250, OPTION 8 IS CORRECT.

Like? Yes (7) | No (1)  

Rats   11 years AGO

code for alphabet is respective position in alphabet series i.e. A=1, B=2, C=3,......, Z=26
after getting numbers multiply it.

RAM=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
Hence, for JAY
JAY=10*1*25=250......Ans

Like? Yes (5) | No (2)  

ABHISHEK KUMAR MISHRA   11 years AGO

Multiply the each position of letter in the given word:
RAM=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
so JAY=10*1**25=250
i.e option 8)

Like? Yes (4) | No (2)  

ashish   11 years AGO

position of R--->18
position of A--->1
position of M--->13
so multiply 18*1*13=234
so in same fashion
position of J--->10
position of A--->1
position of Y--->25
10*1*25=250

Like? Yes (2) | No   

Laltu banerjee   11 years AGO

Number the alphabets as they are.
then r=18
a=1
m=13
then multiply 18*1*13=234
similarly
for jay =10*1*25=250
option 8 is the right answer

Like? Yes (3) | No (1)  

Bholanath    11 years AGO

CORRESPONDING CODES FOR ALPHABETS
A B C D E F G H I J K L M N O P Q R S T
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
U V W X Y Z
21 22 23 24 25 26

NOW,
RAM=18*1*13 =234
SUN=19*21*14=5586
ANU=1*14*21=294
SO,
JAY=10*1*25=250 ANS.

Like? Yes (2) | No   

FRANKLIN VIJAY   11 years AGO

j=10
a=1
y=25
=>10*1*25=250

Like? Yes (2) | No (1)  

Vikram Saini   11 years AGO

position of j is 10
position of a is 1
nd position of y is 25
so, multiply alll position we get 250
option 8 is correct answer.

Like? Yes (2) | No (1)  

rohit kumar   11 years AGO

multiply all the alphabetical values,
RAM=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
so for,
JAY=10*1*25=250.....ANS

Like? Yes (3) | No (2)  

Dharmendra Singh   11 years AGO

Ans 8) 250
Explanation: find the positions of alphabet and multiply with them.
so, J(15)*A(1)*Y(25)=250

Like? Yes (2) | No (1)  

neha selokar   11 years AGO

RAM = R * A * M = 18 * 1 * 13 = 234
similarly
JAY = J * A * Y = 10 * 1 * 25 = 250

Like? Yes (2) | No (1)  

abhishek   11 years AGO

Simply fint the numerical value of the alphabet and multiply all of them to get tje desired result
10*1*25 =250

Like? Yes (2) | No (1)  

Md Shahnawaz Shahab   11 years AGO

JAY = 10*1*25 = 250

Like? Yes (2) | No (1)  

Dharmendra Kumar Rajak   11 years AGO

According to Position of letters
(R=18)*(A=1)*(M=13)=234;
(S=19)*(U=21)*(N=14)=5586;
(A=1)*(N=14)*(U=21)=294;
Then
(J=10)*(A=1)*(Y=25)=250;
So option (8) is correct;

Like? Yes (2) | No (1)  

Grishma Shah   11 years AGO

the multiplication of digit.
J=10, A=1, Y= 25
10x1x25 = 250 Ans

Like? Yes (1) | No   

Bingumalla Abinay   11 years AGO

j=10
a=1
y=25
10*1*25=250

Like? Yes (1) | No   

Rituparna Bhattacharyya   11 years AGO

ans. 8)250
Jay = 10 x 1 x 25 = 250

Like? Yes (2) | No (1)  

jagdish sharma   11 years AGO

RAM=234
R=18,A=1,M=13
then RAM=18*1*13=234
SUN=19*21*14=5586
Similarly
JAY=10*1*25=250

Like? Yes (1) | No   

Neha Jha   11 years AGO

as by giving numbers..as1,2,3 to alphabets
we have R=18,A=1,M=13 RAM=234=18*1*13
similarly for SUN=19*21*14=5586
and for ANU=1*14*21=294
therefore, JAY= 10*1*25=250
hence answer is 250

Like? Yes (2) | No (1)  

Dinesh thatti   11 years AGO

R=18 A=1 M=13 R*A*M=234
S=19 U=21 N=14 S*U*N=5586
A=1 N=14 U=21 A*N*U=294
J=10 A=1 Y=25 J*A*Y=250

Like? Yes (1) | No   

Kumar Ankit   11 years AGO

A=1
B=2
C=3
......
Z=26
NOW,
RAM=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
JAY=10*1*25=250

Like? Yes (2) | No (1)  

Jyothi   11 years AGO

r=18,a=1,m=13:18*1*13=234
j=10.a=1.y=25:10*1*25=250

Like? Yes (1) | No   

soumya ranjan mishra   11 years AGO

because correspomding number of digits are mulitiplied as A=1,B=2, ...z=26.

Like? Yes (1) | No   

Bharat Bhushan Jha   11 years AGO

J=10
A=1
Y=25
SO JAY=10*1*25=250

Like? Yes (1) | No   

Sriparna Boote   11 years AGO

Taking A=1 B=2......Z=26
RAM
R=18 A=1 M=13
RAM=18*1*13=234
SUN
S=19 U=21 N=14
SUN=19*21*14=5586
Similarly ANU= 1*14*21=294
Now
JAY
J=10 A=1 Y=25
JAY=10*1*25=250
250 is the required answer

Like? Yes (1) | No   

sivaraman   11 years AGO

In coded language you give A for 1 and upto Z to 26
so RAM= 18*1*13=234
so
JAY= 10*1*25=250

Like? Yes (1) | No   

sunil saini   11 years AGO

ram = (r=18)*(a=1)*(m=13)=234 (using alphabets serial no.)

similarly jay=10*1*25=250

Like? Yes (1) | No   

Dr.Dipin Singh   11 years AGO

RAM = 234...... 18*1*13
similarly
SUN = 5586
ANU = 294
Then
JAY = 10*1*25=250

Like? Yes (1) | No   

ArunKumar   11 years AGO

as in alphabets
R= 18 A=1 M=13
18*1*13 =234

S= 19 U=21 N=14
19*21*14= 5586

J=10 A=1 Y=25
JAy = 10*1*25 =250

Like? Yes (1) | No   

prakash kumar   11 years AGO

multiply numerical value of alphabet
RAM = 18*1*13 = 234
SUN = 19*21*14 = 5586
ANU = 1*14*21 = 294
JAY = 10*1*25 = 250

Like? Yes (1) | No   

deepak kumar   11 years AGO

j=10, a=1, y=25
jay= 10*1*25=250

Like? Yes (1) | No   

MOHIT BHARDWAJ   11 years AGO

18*1*13=234
anu=1*14*21=294
so
jay=10*1*25=250

Like? Yes (1) | No   

Avinash Aryan   11 years AGO

J=10th letter
A=1st letter
Y=25th Letter
now JAY=10*1*25=250

So 8th Option.

Like? Yes (1) | No   

Saurabh Shekhar Singh   11 years AGO

R=18,A=1,M=13, 18*1*13=234
S=19,U=21,N=14, 19*21*14=5586
A=1,N=14,U=21, 1*14*21=294
so, J=10,A=1,Y=25, 10*1*25=250(option 8)

Like? Yes (1) | No   

a.k.gayathridevi   11 years AGO

a=1,b=2,.....z=26
ram=18*1*13=234
sun=19*21*14=5586
anu=1*14*21=294
so
jay=10*1*25=250

Like? Yes (1) | No   

Amresh kumar   11 years AGO

JAY=10*1*25=250

Like? Yes (1) | No   

jaya prakash reddy   11 years AGO

r=18
a=1
m=13
18*1*13=234;sun= 19*21*14=5586,......
jay=10*1*25= 250

Like? Yes (1) | No   

akshansh shrivastav   11 years AGO

J=10,a=1,y=25

Like? Yes (1) | No   

Amar Deep Singh   11 years AGO

write the corresponding numeric position of the english alphabet and then multiplied it as given below:-
RAM=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
JAY=10*1*25=250

Like? Yes (1) | No   

nivetha m   11 years AGO

give value to alphabets like a=1 b=2 ... z=26
so ram= 18*1*13 =234
like jay = 10*1*25 = 250

Like? Yes (1) | No   

harjeet   11 years AGO

Start indexing alphabets from A=1,B=2...Z=26
then,
R=18,A=1,M=13 RAM=18*1*13=234
similarly
J=10,A=1,Y=25 JAY=10*1*25=250

Like? Yes (1) | No   

raghuram dharmavarpu   11 years AGO

numbering the alphabets&then multiply it
A=1,B=2,C=3,.....Y=25,Z=26
J=10,A=1,Y=25
So that JAY=10*1*25=250

Like? Yes (1) | No   

Anantharaman   11 years AGO

Multiply the alphabet position to get the result

RAM = 18*1*13 = 234
SUN = 19*21*14 = 5586
ANU = 1*14*21 = 294

JAY = 10*1*25 = 250

Option 8

Like? Yes (1) | No   

sandipan patra   11 years AGO

R is 18th letter
A ... 1ST ....
M ... 13th ....
RAM=18*1*13=234
like this JAY=10*1*25=250

Like? Yes (1) | No   

Manish Singh   11 years AGO

position of R--->18
position of A--->1
position of M--->13
so multiply 18*1*13=234
so in same fashion
position of J--->10
position of A--->1
position of Y--->25
10*1*25=250

Like? Yes (1) | No   

ravi singh   11 years AGO

answer is 250
coding is come from multiplication of alphabet in number form
like
RAM=18*1*13=234
similarly,
JAY=10*1*25=250
hence option 8

Like? Yes (1) | No   

arnab pandey   11 years AGO

R=18,A=1,M=13 SO 18*1*13=234
S=19,U=21,N=14 SO SUN=19*21*14=5586
A=1,N=14,U=21 SO ANU=1*14*21=294
THUS JAY=10*1*25=250

Like? Yes (1) | No   

jatin patware   11 years AGO

ram=r*a*m=18*1*13=234
sun=s*u*n=19*21*24=5586
anu=a*n*u=1*14*21=294
similarly=>jay=j*a*y=10*1*25=250
so option 8 is correct

Like? Yes (1) | No   

abhinav paul   11 years AGO

code the alphabets serially in terms of numbers i.e. A=1, b=2, and so on.
R=18 A=1 M=13, 18*1*13=234
A=1 N=14 U=21, 1*14*21=294
so,
J=10 A=1 Y=25 gives 10*1*25=250
is the answer

Like? Yes (1) | No   

chaitanya   11 years AGO

all the numbers init are multiplied by their respective count

Like? Yes (1) | No   

VIKASH KUMAR SHARMA   11 years AGO

RAM= 18*1*13(ACC TO NUMERIC POSITION OF ALPABT)=234
SUN= 19*21*14= 5586
ANU= 1*14*21= 294
THRFOR JAY= 10*1*25= 250 ans

Like? Yes (1) | No   

Garima   11 years AGO

RAM = 18*1*13 = 234
sun = 19*21*14 = 5586
ANU = 1*14*12 = 294
JAY = 10*1*25 = 250

Like? Yes (1) | No   

sa   11 years AGO

ram=13*1*18=234
sun=19*21*14=5586
jay=10*1*25=250

Like? Yes (1) | No   

Bhargav S   11 years AGO

Corresponding position in alphabets multiplied.
RAM=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
Therefore, JAY=10*1*25=250

Like? Yes (1) | No   

mohan lal garg   11 years AGO

ram= 18*1*13=234
same as
jay =10*1*25=250

Like? Yes (1) | No   

richa ahuja   11 years AGO

jay=10*1*25=250

Like? Yes (1) | No   

Saurabh Mishra   11 years AGO

a=1,b=2,c=3,d=4............similarly z=26
now in RAM R=18,A=1,M=13 SO RAM=18*1*13=234
SUN S=19,U=21,N=14 SO SUN=19*21*14=5586
ANU A=1,N=14,U=21 SO ANU=1*14*21=294

SO JAY=10*1*25

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=250
code=>(multiplication of letter's resp. position no in alphabetic series)
RAM=> 18,01,13 => 18*1*13 = 234
SUN=> 19,21,14 => 19*21*14= 5586
ANU=> 01,14,21 => 1*14*21 = 294
similarly,
JAY=> 10,01,25 => 10*1*25 =250

Like? Yes (1) | No   

ravi shankar rai   11 years AGO

ram according to position no. we writeand multiply all of them
ram=18*1*13=234
anu=1*14*21=294
similarly,
jay=10*1*25=250

Like? Yes (1) | No   

Chithra   11 years AGO

J=10, A=1,Y=25
JAY=10*1*25=250

Like? Yes (1) | No   

md shoaib alam   11 years AGO

JUST PLACE THE NUMERIC VALUE OF LETTER LIKE A=1,B=2,C=3,....J=10,,,,Y=25
NOW \"JAY\"
PUTING VALUE AND MULTIPLY 10*1*25=250

Like? Yes (2) | No (1)  

satyam nagariya   11 years AGO

if a=1,b=2,c=3.....z=26
RAM=R*A*M=18*1*13=234
SUN=19*21*14=5586
ANU=1*14*21=294
SO..
JAY=10*1*25=250

Like? Yes (1) | No   

D venkatesh babu   11 years AGO

A=1,B=2,-------Z=26
RAM=18*1*13=234
SUM=19*21*14=5586
ANU=1*14*21=294
SIMILARLY
JAY=10*1*25=250.

Like? Yes (2) | No (1)  

susmit   11 years AGO

Replacing letters by numbers, according to their rank in alphabetical order and then multiplying.
Ram = 18*1*13 = 234.
Sun = 19*21*14 = 5586.
Anu = 1 *14*21 = 294.
So Jay = 10*1*25 = 250.
Hence option no . (8)

Like? Yes (1) | No (1)  

NITISH KUMAR   11 years AGO

ram
ram =234;
according to position of later in alphabet
here 18*1*13= 234;
same as for sun
19*21*14=5586;
same as for anu;
1*14*21= 294
so, for jay
10*1*25=250 is ans

Like? Yes (1) | No (1)  

22 Oct 2013 Probability

Using the digit 2, 4 and 6, two digit number is formed, each digit being used only once. Find the probability that the number so formed is greater than 46.

OPtion

1) 1/2
2) 1/9
3) 2/5
4) 2/3
5) 1/3
6) 5/6
7) 4/5
8) 1/5
9) 1/4
10)None of these

Solution

Sample space = (26,24,42,46,62,64)
Total possible cases = 6
Total favorable cases = 2
then probability (greater then 46) = 2/6 = 1/3
option 5

Correct Option: 5 Best Solution (61)

ABHISHEK KUMAR MISHRA   11 years AGO

Total no of sample space=3C2*2!=6
total no which is greater than 46=1*2=2
so probability=2/6=1/3
i.e option 5)

Like? Yes (8) | No (2)  

Saurav Mandholiwal   11 years AGO

no.of sample space=6(24,26,42,46,62,64)
no.of possible events=2(64,62)
probability=2/6=1/3

Like? Yes (4) | No   

Bharat Bhushan Jha   11 years AGO

total no of way=3!
no greater then 46 will be
1.62
2.64
so total probability=2/3!=1/3 ANS

Like? Yes (3) | No   

mohini gupta   11 years AGO

out of 24,42,26,62,46,64...only 62 n 64 are greater

Like? Yes (4) | No (1)  

ArunKumar   11 years AGO

the number of digit formed is 6 (24,26,42,46,64,62)

out of which greater than 46 is 2 ( 64,62)

Like? Yes (4) | No (2)  

Md Shahnawaz Shahab   11 years AGO

total no of two digit nos formed by 2,4,6 = 6
nos above 46 are 62 and 64 = 2 no.s
therefore probability = 1/3

Like? Yes (3) | No (1)  

ravi singh   11 years AGO

answer is 1/3
total=(24,26,42,46,62,64)
and greater than 46 is 64 and 62
hence=2/6=1/3

Like? Yes (2) | No   

LAKSHMI ROJA   11 years AGO

Fix the 6 in tens digit place and the units place can be fillled in 2 way so the probability is 2/3c2=2/6=1/3

Like? Yes (2) | No   

VIKASH KUMAR SHARMA   11 years AGO

no. of total ways = 3*2
thn 64 and 62 can v formed which is grtr thn 46
thrfor probability= 2/6= 1/3 ans

Like? Yes (2) | No   

sandy   11 years AGO

2 digits num formed using 2,4,6 are 24,26,42,46,62,64
numbers greater than 62,64
so probability of getting a num greater than 46 is 2/6=1/3

Like? Yes (4) | No (2)  

deepak kumar   11 years AGO

62 and 64 are 2 event.
24,26,42,46,62,64 are 6 possible event
Probability=2/6=1/3

Like? Yes (3) | No (2)  

Harsh Poddar   11 years AGO

two digit numbers formed by 2,4,6 without repeating the digits are 24,26,42,46,62,64
total numbers=6
numbers greater than 46=2
probability of getting more than 46=2/6=1/3
option 5

Like? Yes (2) | No (1)  

Anantharaman   11 years AGO

No# of ways to form a number >46 = 2

Total no# of outcomes = 6


Probability of forming a number > 46 = 2/6

=> 1/3

Option 5

Like? Yes (2) | No (1)  

Ashfaque Hussain   11 years AGO

Two Digit Number can be formed: 3c2 = 3
Greater than 46 is only one 64
so probability = 1/3

Like? Yes (4) | No (3)  

chaitanya   11 years AGO

total possible combinations 24 42 26 62 46 64
6 in total
of which only two are greater than 46

so 2/6=1/3

Like? Yes (3) | No (2)  

xyz   11 years AGO

total condition=6
favorable conditions=2(64 and 62)
so probability=2/6
1/3

Like? Yes (1) | No   

Anand   11 years AGO

numbers are -- 24,26,42,46,62,64
no more than 46 is-- 62 and 64

so probability is= 2/6= 1/3

Like? Yes (3) | No (2)  

Laltu banerjee   11 years AGO

n(e)=2 because only 62 and 64 is greater than 46.
n(s)=6 number we can formed using each digit only once.
hense n(e)/n(s)=2/6=1/3

Like? Yes (1) | No   

Amresh kumar   11 years AGO

according to question we can have 24,42,26,62,46 and 64
from these six numbers problty for numbers greater than 46 is 2/6=1/3.

Like? Yes (1) | No   

akash   11 years AGO

2/6.64 and 62 out of 6 numbers formed.

Like? Yes (1) | No   

Manas Aggarwal   11 years AGO

total no of ways=3!=6
putting 6 at the tens place no. formed are 62,64 wich r only no.s greater than 46
2/6=1/3

Like? Yes (1) | No   

prakash kumar   11 years AGO

2 digit no using 2,4,6=24,26,42,46,62,64
no greater than 46=62,64
P=2/6
=1/3

Like? Yes (1) | No   

harjeet   11 years AGO

no. of combinations= 3*3=9
and greater than 46= 3(62,64,66)
p=3/9
=1/3

Like? Yes (1) | No   

Roushan Singh   11 years AGO

Number of 2 digit no. formed (without repetition of digit)=6(24,42,46,64,26,62)
greater than 46 digits are 64 and 62
so probablity of getting no formed greater than 46=
2/6 which results in 1/3

Like? Yes (2) | No (1)  

Saurabh Mishra   11 years AGO

total no of two digit no from 2,4,6=6
total no of digit from 2,4,6 which is grater than 46=2
so probability=2/6= 1/3

Like? Yes (1) | No   

sravan   11 years AGO

total possible ways are- 24,26,42,46,62,64.
condition is - number> 46
probability is 2/6= 1/3

Like? Yes (1) | No   

teena sirwani   11 years AGO

possible 2 digit no. is 6
no. greater than 46 is 2 so
p= 2/6=1/3

Like? Yes (1) | No   

Dr.Dipin Singh   11 years AGO

only 2 numbers (62,64) are greater than 46 among 6 numbers (24,26,42,46,62,64) formed with given conditions.
so prob. = 2/6=1/3

Like? Yes (1) | No   

Rituraj Singh   11 years AGO

for no. greater than 46 first digit should be 6 and two no. are possible 62,64 i.e. 2 no.
total no. possible are = 3*2=6
So, probability can be given as = 2/6=1/3

Like? Yes (1) | No   

Deb Das   11 years AGO

total numbers formed 3*2=6.
as decimal digit can formed in 3 ways and unit digit in 2 ways. Now number greater than 46 formed is 62,64. So the probability is 2(/6)=1/3

Like? Yes (1) | No   

jatin patware   11 years AGO

possible number=24,42,46,64,62,26
favourable=62,64
so ans is 2/6 i.e 1/3 so option 5 is correct

Like? Yes (1) | No   

Anandapaul   11 years AGO

combinations are,
24
26
46
64
62
42
so 2 numbers are greater than 46
so probability is=(1/3)

Like? Yes (1) | No   

KALIDASS   11 years AGO

Possible numbers are 6
possible number greater than 46 is 64 & 62
probability 1/3

Like? Yes (1) | No   

Pritam Sahu   11 years AGO

1/3c2=1/3

Like? Yes (1) | No   

sivaramakrishna   11 years AGO

we can not place 2 or 4 in tens place.
we must place 6.
then 62,64.
totla outcomes=>24,26,42,46,62,64=>>6
hence 2/6=>1/3.

Like? Yes (1) | No   

Udhaya kumar   11 years AGO

total possibilities 3*2*1=6
>46 are only 62&64
so 2/6=1/3

Like? Yes (1) | No   

Nitin Jain   11 years AGO

total numbers are 6 - 24 26 42 46 62 64 and favourable only 2 - 64 62

prob. = fav /total

Like? Yes (1) | No   

susmit   11 years AGO

Following 6 two digit numbers can be formed using each digit only once, from the digits 2, 4, 6.
24, 26, 42, 46, 62, 64.
Out of this only 62 & 64 i.e. two numbers are greater than 46.
So probability is 2/6 = 1/3.
Hence option no.(5).

Like? Yes (1) | No (1)  

Rats   11 years AGO

total combination = 3! = 6
which are
24, 26, 42, 46, 62, 64
there are only two numbers greater than 46
which are 62 and 64
So, probability for number greater than 46
=2/6=1/3...........Ans

Like? Yes (4) | No (4)  

rohit kumar   11 years AGO

total two digits numbers formed by using 2,4 & 6 (w/o repitittion)=6
numbers greater than 46 is 62 & 64=2
so,
probability=2/6=1/3

Like? Yes (4) | No (4)  

sanjeev kumar   11 years AGO

grater than 46 no form

62,64
total no formed
246,264,426,462,624,642.

probability 2/6 =1/3

Like? Yes (1) | No (1)  

kumar sundram   11 years AGO

two digit nos. using 2, 4 and 6 are 24, 26, 42, 46, 62 and 64.
so, no. of nos. of two digit using 2, 4 and 6 only once is 6.
the nos. which is greater than 46 are 62 and 66.
so, no. of nos. greater than 46 is 2.
thus, probability that the no. is greater than 46 is 2/6=1/3.

Like? Yes (1) | No (1)  

Dharmendra Singh   11 years AGO

Ans 5) 2/6
Explanation : we can choose two digit number from 3-different number by 6 ways
for first place 3 ways 2nd place 2 ways total=3*2=6 ways
so total sample's event=6
and only two no. 62, 64 are favorable. so probability =2/6=1/3

Like? Yes (2) | No (2)  

Grishma Shah   11 years AGO

the no. formed is 24,26,42,46,62,64.
total = 6
the no. greater then 46 is 62,64 =2
the probability = 2/6 = 1/3

Like? Yes (1) | No (1)  

jagdish sharma   11 years AGO

two digit numbers r formd by 2,4,6 is
24,42,26,62,46,64
Only 62 and 64 greater then 46
Probability=2/6=1/3

Like? Yes (1) | No (1)  

Triloki Shaw   11 years AGO

total two digit no. formed by 2,4,6 is 3P2=6
two digit no greater than 46 is 6 at tens place and unit place being formed in 2! ways=2
therefore probability= 2/6
i.e., 1/3 ans.

Like? Yes (3) | No (3)  

Rituparna Bhattacharyya   11 years AGO

total no of two digit nos formed b 2,4,6 = 6
nos above 46 are 62 and 64
therefore prob = 2/6 = 1/3

Like? Yes (1) | No (1)  

Jyothi   11 years AGO

total possibility 3!
possibility for the number greater than 46 is 2!
probability=2!/3!=1/3

Like? Yes (1) | No (1)  

Dharmendra Kumar Rajak   11 years AGO

Given digits are 2,4,6
we have to make two digits numbers using given numbers
now,
[___] [___]
3ways 2ways
So,
total number of permutation =3*2=6
i.e. [24,26,46,42,62,64]
out of which only two are greater than 46 i.e.62,64
So probability of outcome of number which are greater than 46
will be
p=2/6;
p=1/3;
So option (5) is correct.

Like? Yes (1) | No (1)  

Harjit kaur   11 years AGO

Total no of two digit(s)={24,26,42,46,62,64}
let e be the event two digit no greater than 46
e={62,64}
thus n(s)=6
n(e)=2
P(e)=n(e)/n(s)
=2/6
=1/3
thus option is 5

Like? Yes (1) | No (1)  

Suman Saurabh   11 years AGO

The numbers are=24,26,42,46,62,64
so probability=2/6=1/3

Like? Yes (1) | No (1)  

soumya ranjan mishra   11 years AGO

only one digit can be made which is greater than 46

Like? Yes (1) | No (1)  

kunwar prabhakar singh   11 years AGO

greater than 46...62& 64=2ways
and 3*2=6ways
so..p=2/6=1/3

Like? Yes (1) | No (1)  

Nayan Agrawal   11 years AGO

fav outcomes 24,26,42,46,62,64.....
desired outcomes 62,64
hence , desired outcomes/fav outcomes =2/6 =1/3...........ans

Like? Yes (1) | No (1)  

snigdha chakraborty   11 years AGO

2 digit no.s that can be formed using 2,4 and 6 are 62
64
46
42
26
24 i.e. 6 no.s out of which onlt 2 are greater than 46 hence answer will be (2/6) i.e. 1/3

Like? Yes (1) | No (1)  

Nagarjun N   11 years AGO

total no of ways is 6 and possible ways to get above 46 is 2 so 2:6 = 1/3

Like? Yes (1) | No (1)  

ravi shankar rai   11 years AGO

total no. of sample space 3!=6
no of possibility greater than 46 is 2 i.e 62 &64
probability=(2/6)=1/3...ans

Like? Yes (1) | No (1)  

Vikram Saini   11 years AGO

total no. of event is 6
nd favourabl no. of event is 2
so prob is 2/6
so it is 1/3

Like? Yes (1) | No (1)  

Neha Jha   11 years AGO

as the chances for no. greater than 46 are only if it is 62 or 64 ie.2 ways
total no of eays for two digit no. with digits 2,4,6 =3*2=6
hence
P=2/6=1/3

Like? Yes (1) | No (1)  

GAYATHRI   11 years AGO

nos formed using 2,4,6 are 24,42,46,64,62,26.
nos greater than than 46 are 64,62
the probability is 2/6=1/3

Like? Yes (1) | No (1)  

Arun sauhu   11 years AGO

only two number can be formed

62 64 but not 66 x
as per question digit should not repeated

then only 2 numbers can be form
the total numbers can be form 3!
hence probablity is
2/6=1/3

Like? Yes (1) | No (1)  

21 Oct 2013 Sequence

What is the next number of the following sequence
32,101,234,404,638,.....

OPtion

1) 808
2) 865
3) 898
4) 909
5) 966
6) 988
7) 1001
8) 1099
9) 990
10)None of these

Solution

5^2 = 25 = 25+(5+2) = 32 (Add sum of digit)
10^2 = 100 = 100+(1+0+0) = 101
15^2 = 225 = 225+(2+2+5) = 234
20^2 = 400 = 400+(4+0+0) = 404
25^2 = 625 = 625+(6+2+5) = 638
Similarly
30^2 = 900 = 900+(9+0+0) = 909

option 4

Correct Option: 4 Best Solution (4)

susmit   11 years AGO

5^2=25, 25+5+2=32
10^2=100, 100+1+0=101
15^2=225,225+2+2+5=234
20^2=400, 400+4+0+0=404
similarly 30^2=900 and 900+9+0+0=909
option no.4

Like? Yes (14) | No (2)  

Devendra Marghade   11 years AGO

Square of 5n added to its digit's sum
5^2=25, 25+(2+5)=32
10^2=100, 100+(1+0+0)=101
15^2=225, 225+(2+2+5)=234
20^2=400, 400+(4+0+0)=404
25^2=626, 625+(6+2+5)=638
30^2=900, 900+(9+0+0)=909

Like? Yes (5) | No (2)  

ravi shankar rai   11 years AGO

same number in tail n head end then middle 0
means 1-1=0(101),4-4=0(404)
and diif number give middle one 3
so ans is 909.

Like? Yes (6) | No (4)  

Rats   11 years AGO

(5^2)+7=32
(10^2)+1=101
(15^2)+9=234
(20^2)+4=404
(25^2)+8=633
So only 909 fulfils requirement as
(30^2)+9=909.....Ans

Like? Yes (3) | No (4)  

18 Oct 2013 Rank

What will be the rank of word COMPANY in the words of dictionary formed by letters of the word COMPANY

OPtion

1) 1430
2) 3428
3) 4370
4) 1247
5) 1117
6) 1976
7) 2934
8) 4484
9) 934
10) 1029

Solution

total no of words formed by letters of word COMPANY = 5040
ordered sequence A, C, M, N, O, P, Y
so rank
= (5040/7)*1+(720/6)*3+(120/5)*1+(24/4)*2+(6/3)*0+(2/2)*0+1
= 720+360+24+12+1
= 1117

Correct Option: 5 Best Solution (40)

Dharmendra Singh   11 years AGO

ans 5) 1117
fix A remaining words form 6!=720
fix C A remaining words form 5!=120
fix C M remaining words form 5!=120
fix C N remaining words form 5!=120
fix C O A remaining words form 4!=24
fix C O M A remaining words form 3!=6
fix C O M N remaining words form 3!=6
fix C O M P A N Y THESE THREE remaining words ARE ARRANGED AS IN DICTIONARY =1
now add all(720+3*120+24+2*6+1)=1117

Like? Yes (29) | No (4)  

Rats   11 years AGO

word COMPANY in ascending letters
ACMNOPY
So for COMPANY
C(6!)+O(3*5!)+M(4!)+P(2*3!)+A(1)+N(1!)+Y(1!)
=720+360+24+12+1+0+0
=1117......Ans

Like? Yes (11) | No (3)  

Dharmendra Kumar Rajak   11 years AGO

Given word is COMPANY
[A,_ _ _ _ _ _]
1*!6 =720,

[C,A,_ _ _ _ _]
1*1*!5=120,

[C,M,_ _ _ _ _]
1*1*!5=120,

[C,N,_ _ _ _ _]
1*1*!5=120,

[C,O,A,_ _ _ _]
1*1*1*!4=24,

[C,O,M,A,_ _ _]
1*1*1*1*!3=6,

[C,O,M,N,_ _ _]
1*1*1*1*!3=6,

[C,O,M,P,A,_ _] i.e.[COMPA,N,Y]and[COMPA,Y,N]
rank of COMPANY will be just one less than
the word COMPAYN
So totol number of permutation will be
720+120+120+120+24+6+6+(2-1)=1117 Ans
So the correct option is (5)

Like? Yes (7) | No (1)  

Triloki Shaw   11 years AGO

First arrange the letters of COMPANY as per dictionary like A C M N O P Y
Now make words starting from A: 6!=720
Next comes C which is our requirement so place C then A it becomes CA which is not our req. so words from CA: 5!=120
likewise CM: 5!=120
CN: 5!=120
Now CO is matching then place A so COA: 4!=24
likewise COMA 3!=6
COMN 3!=6
COMP is our req. place A i.e., COMPA is true then COMPAN is also true then COMPANY is perfectly matched i.e., COMPANY =1
THEREFORE 1117

Like? Yes (6) | No (2)  

rohit kumar   11 years AGO

arrange the letters in alphabetical values order
i.e ACMNOPY
=>A _ _ _ _ _ _=6!=720
=>CA _ _ _ _ _=5!=120
=>CM _ _ _ _ _=5!=120
=>CN _ _ _ _ _=5!=120
=>COA _ _ _ _=4!=24
=>COM _ _ _ _=4!=24
COMPANY should be in 1104 to 1128
=>COMA _ _ _=3!=6
=>COMN _ _ _=3!=6
total=720+120+120+120+24+6+6=1116
so, next word will be COMPANY i.e 1117th position

Like? Yes (5) | No (1)  

Dipak Shaw   11 years AGO

FIRST ARRANGE THE WORD IN ACCENDING ORDER
2 5 3 6 1 4 7
C O M P A N Y

NOW TAKE C, IT COMES AT 2 AND LOOK ITS LEFT SIDE HOW MANY LETTER POSITION SMALLER THAN THE LETTER C.
THERE IS ONLY ONE A(1)
SO,MULTIPLIED BY 1 FOR C.
WE REPEAT SAME PROCESS FOR REST OF THE LETTER,
WE WILL GET
FOR 0 - MULTIPLIED BY 3
FOR M - MULTIPLIED BY 1
FOR P - MULTIPLIED BY 2
FOR A,N,Y-MULTIPLIED BY 0

SO,FINAL RANK WILL BE FIND OUT BY ADDING 1 -> 1*6!+3*5!+1*4!+2*3!+0*2!+0*1!+0*0! + 1
= 1117

Like? Yes (6) | No (2)  

ABHISHEK KUMAR MISHRA   11 years AGO

ans 5) 1117 fix A remaining words form 6!=720 fix C A remaining words form 5!=120 fix C M remaining words form 5!=120 fix C N remaining words form 5!=120 fix C O A remaining words form 4!=24 fix C O M A remaining words form 3!=6 fix C O M N remaining words form 3!=6 fix C O M P A N Y THESE THREE remaining words ARE ARRANGED AS IN DICTIONARY =1 now add all(720+3*120+24+2*6+1)=1117

Like? Yes (4) | No (2)  

Ann Mary Jolly   11 years AGO

Ans : 5)1117
No. of words starting with A = 6!
No. of words starting with CA = 5!
No. of words starting with CM = 5!
No. of words starting with CN = 5!
No. of words starting with COA = 4!
No. of words starting with COMA = 3!
No. of words starting with COMN = 3!
The next word in alphabetical order is COMPANY.
Therefore,the rank of the word company is
6! + 3*5! +4! + 2*3! + 1 = 1117.

Like? Yes (3) | No (1)  

prakash kumar   11 years AGO

there r 7 letters and all r different.
In dictionary, words starting from A will come b4 word COMPANY.
so, total no of words starting from A=6!=720
now, first word starting with letter C will come.
so, no of words starting with CA=5!=120
no of words starting with CM=5!=120
no of words starting with CN=5!=120
now, first word starting with letter CO will come.
so, no of words starting with COA=4!=24
now, first word starting with letter COM will come.
so, no of words starting with COMA=3!=6
no of words starting with COMN=3!=6
then after words starting from COMP will come and first word will be COMPANY
so, total no of words b4 COMPANY=720+120*3+24+6*2
=1116
so, rank of COMPANY in a dictionary=1117

Like? Yes (3) | No (1)  

Divya Srivastava   11 years AGO

2 5 3 6 1 4 7 (Ranks acc. to alphabetical order)
C O M P A N Y
1 3 1 2 0 0 0 (No. of Ranks smaller than the respective rank)
6!5!4!3!2!1!0! (No. of ways of arranging each alphabet)
the Rank of Company is given by :
6!*1 + 5!*3 + 4!*1 + 3!*2 + 2!*0 + 1!*0 + 0!*0 + 1
= 720+360+24+12+0+0+0+1
= 1117

Like? Yes (2) | No   

Parveen Soni   11 years AGO

1*6! +3*5! +4! +2*3! +1=1117
use rank finding shortcut techniques

Like? Yes (2) | No (1)  

mithun Abhimanyu   11 years AGO

2 5 3 6 1 4 7
c o m p a n y
1 3 1 2 0 0 0
6! 5! 4! 3! 2! 1! 0!
1*6!+3*5!+1*4!+2*3!+0*2!+0*1!+0*0!+1=1117

Like? Yes (1) | No   

xyz   11 years AGO

words started from A=9*5!
FROM COA----=4!
STARTED FROM COMA---=3!
STARTED FROM COMN---=3!
the last word company=1
total=1080+24+12+1=1117

Like? Yes (2) | No (1)  

Laltu banerjee   11 years AGO

staring with c->6!
ca->5!
cm->5!
cn->5!
co
coa->4!
com->4!
coma->3!
comn->3!
company-1
total->1117

Like? Yes (2) | No (1)  

md shoaib alam   11 years AGO

COMPANY can be re write as....." A C M N O P Y"
IN CORRECT ALPHABETIC ORDER NOW
MATCH WITH ORIGINAL WORD "COMPANY"

LIKE FIRSR OF ALL
NO OF WORDS BEFORE C IS =1*6!
NO OF WORDS BEFORE O IS =3*5!
NO OF WORDS BEFORE M IS =1*4!
NO OF WORDS BEFORE P IS =2*3!
NO OF WORDS BEFORE A IS =0*2!
NO OF WORDS BEFORE N IS =0*6!

AND ADD 1 TO SUM OF (720+360+24+12+1)

Like? Yes (1) | No   

Suyash Kunawat    11 years AGO

we will arrange the letters in alphabetical order as ACMNOPY
then taking A as 1st letter we have 6! words i.e. 720
then CA we have 120
then CM we have 120
then CN we have 120
then COA we have 24
then COMA we have 6
then COMN we have 6
the very next word will be COMPANY
so total rank is 720+120+120+120+24+6+6+1=1117

Like? Yes (1) | No   

harshu   11 years AGO

word start with
A: 6!=720
CA: 5!=120
CM: 5! =120
CN: 5!=120
COA: 4!=24
COMA: 3!=6
COMN: 3!=6
company: 1
now sum all no
720+120+120+120+24+6+6+1
1117 Ans.

Like? Yes (1) | No   

Sindu   11 years AGO

In alphabetical order Company is written as
A C M N O P Y
A------=6!=720
CA-----=5!=120
CM-----=5!=120
CN-----=5!=120
COA----=4!=24
COMA---=3!=6
COMN---=3!=6
COMPANY=1
So 720+120+120+120+24+6+6+1=1117.

Like? Yes (2) | No (1)  

vivek jain   11 years AGO

720(6!) words would start with A.
afterwards first letter would be C.
then, 360 ( 5!+5!+5!) are needed for coming to the letter O as second word.
then , 24(4!) needed for M to come up at third place.
then, we all needed that p would at come at fourth place for this we have to skip 13(4!+1) rank.
the +1 is done for the position of next word.
therefore the answer is 1117

Like? Yes (1) | No   

Dinesh thatti   11 years AGO

in company first c will come as for dictionary
remainig 6 letters will be arranged in 6!=720 ways
if we take 2 letters without repitition we get
ca 5!=120
cm 5!=120
cn 5!=120

if we take 3 letters without repitition we get
coa 4!=24

if we take 4 letters without repitition we get
coma 3!=6
comn 3!=6

if we take 5 letters without repitition we get
company 1!=1


finally we get 720+360+24+12+1=1117

Like? Yes (2) | No (1)  

sandy   11 years AGO

COMPANY
ARRANGE IN ALPHABETICAL ORDER
ACMNOPY
1*6!+3*5!+1*4!+2*3!+0*2!+0*1!+1=1117

Like? Yes (2) | No (2)  

Vinay Sipani    11 years AGO

Arranging alphabetically => ACMNOPY

=> Rank = 1×6! + 3×5! + 1×4! + 2×3! + 1
=> Rank = 1117
=> option 5

Like? Yes (1) | No (1)  

jagdish sharma   11 years AGO

when A is first position then total words =720
CA_ _ _ _ _ =120
CM_ _ _ _ _=120
CN_ _ _ _ _=120
COA_ _ _ _=24
COMA_ _ _=6
COMN_ _ _=6
COMPANY=1
Total=1117

Like? Yes (1) | No (1)  

deepak kumar   11 years AGO

company just arrange in alphabetical manner acmnopy after that c is in 2nd place after arrangement
before c only one char is there ie a. and remaining char is 6 except c. 1x6! + 3x5! + 3x4! + 0x3! + 0x2! + 1 = 1117

Like? Yes (1) | No (1)  

Bholanath    11 years AGO

COMPANY in increasing order
ACMNOPY
A[6!]
CA[5!]
CM[5!]
CN[5!]
COA[4!]
COMA[3!]
COMN[3!]
COMPANY[1]
so, rank of company is =6!+3x5!+4!+2x3!+1=1117

Like? Yes (1) | No (1)  

Manish Kumar   11 years AGO

COMPANY
ACMNOPY - WRITING IN ALPHABETICAL ORDER FIRST

a-720
ca-120
cm-120
cn-120
coa-24
coma-6
comn-6
company-1
total=720+120+120+120+24+6+6+1=1117

Like? Yes (1) | No (1)  

Nagarjun N   11 years AGO

if taken in alphabetical order first a comes.. then there will be 6! ways then 721st word starts from c. we do the same thing with 2, 3 4 th words and add them to get the answer 1117

Like? Yes (1) | No (1)  

Md Shahnawaz Shahab   11 years AGO

the first word formed by the word COMPANY will be ACMNOPY
therefore rank of the word COMPANY will be 6!+3*5!+4!+2*3!+1! = 1117

Like? Yes (1) | No (1)  

js manikanta   11 years AGO

i think it is 1117 .... as in a dictionary
acmnopy
then 6!+5!+5!+4!+3!+3!+1=1117

Like? Yes (1) | No (1)  

Prateek Nanhorya   11 years AGO

A->6!
CA->5!
CM->5!
CN->5!
COA->4!
COMA->3!
COMM->3!/2!
COMP->3!
COMPAA->2!/2!
COMPAM->2!
COMPANY->4
ADDITION WILL BE 1117

Like? Yes (1) | No (1)  

manisha mehta   11 years AGO

720+5*120+24+2*6+1=1117

Like? Yes (1) | No (1)  

Neha Rani   11 years AGO

fix A remaining words form 6!=720
fix C A remaining words form 5!=120
fix C M remaining words form 5!=120
fix C N remaining words form 5!=120
fix C O A remaining words form 4!=24
fix C O M A remaining words form 3!=6
fix C O M N remaining words form 3!=6
fix C O M P A N Y THESE THREE remaining words ARE ARRANGED AS IN DICTIONARY =1
now add all(720+3*120+24+2*6+1)=1117

Like? Yes (2) | No (2)  

Devendra Marghade   11 years AGO

Arranging the letters of the word COMPANY, in order A,C,M,N,O,P,Y
rank of the word =1(6!)+3(5!)+1(4!)+2(3!)+0(2!)+0(1!)+1
=720+360+24+12+1
=1117

Like? Yes (1) | No (1)  

ravi shankar rai   11 years AGO

company should be written in alphabetically
a c m n o p y
now by seeing the alphabet before we ge
=1(6!)+3(5!)+1(4!)+2(3!)+0(2!)+0(1!)+1
=1117

Like? Yes (1) | No (1)  

raghuram dharmavarpu   11 years AGO

word COMPANY can be arranged in the alphabetical order so that ACMNOPY
A------ it can be arranged in 6! ways
CA----- it can be arranged in 5! ways
CM----- it can be arranged in 5! ways
CN----- it can be arranged in 5! ways
COA---- it can be arranged in 4! ways
COMA--- it can be arranged in 3! ways
COMN--- it can be arranged in 3! ways
COMPANY can be arranged in one way
so that rank of COMPANY is 6!+3(5!)+4!+2(3!)+1=1117

Like? Yes (1) | No (1)  

poonam   11 years AGO

1(6!) + 3(5!) + 1(4!) + 2(3!) +1
720+360+24+12+1
=>
ANSWER = 1117

Like? Yes (1) | No (1)  

Rahul Rajak   11 years AGO

use permutation and combination

Like? Yes (1) | No (1)  

Neha Jha   11 years AGO

letters in alphabetical order are a,c,m,n,o,p,y
words starting with a are 6!=720
words starting with c are 6!=720
among these 720,words starting with ca are 5!=120
similarly, with cm = 5!=120
with cn= 120
with co=120
among these 120 words with coa starting =4!=24
with com =4!=24
among these 24 words words starting with coma=3!=6
with comn=6
with comp=6
among these 6 words words starting with compa =2!=2
the first one among these two words would be company
therefore rank of company=720+120+120+120+24+6+6+1=1117

Like? Yes (1) | No (1)  

Ravishankar Karn   11 years AGO

word before company===
form A=6!
from CA=5!
from CM=5!
from CN=5!
from COA=4!
from COMA=3!
from COMN=3!
next word is COMPANY.
6!+5!+5!+5!+4!+3!+3!=1116
so the rank of COMPANY is 1117.

Like? Yes (1) | No (1)  

Chandni Maurya   11 years AGO

ans=1117
arranging in alphabetic order, A,C,M,N,O,P,Y
words starting with A=6!
words starting with CA=5!
words starting with CM=5!
words starting with CN=5!
words starting with COA=4!
words starting with COMA=3!
words starting with COMN=3!
then next will be COMPANY
total=6!+5!+5!+5!+4!+3!+3!+1=1117

Like? Yes (1) | No (1)  

17 Oct 2013 Coded Language

If
MAHESH = NZSVHS
SOHAN = HLSZM
GAURAV = TZFIZE
Then
HEMANT = ?

OPtion

1) SGMZVN
2) SZMGVN
3) SNZMGV
4) NSZMGV
5) ZMGVNS
6) SZGMVN
7) SMZVNG
8) VNGSMZ
9) SVNZMG
10)None of these

Solution

Rules for making these codes are
Letters are changed according to the sequence given below
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Z Y X W V U T S R Q P O N M L K J I H G F E D C B A
MAHESH = NZSVHS
SOHAN = HLSZM
GAURAV = TZFIZE
then
HEMANT = SVNZMG

OPTION 9)

Correct Option: 9 Best Solution (79)

Rats   11 years AGO

code for respective alphabet is the position in alphabet series. eg A=1, B=2, C=3,......,Z=26
for a paricular alphabet code is 27-position=code
MAHESH=27-M(13)=14=N
27-A(1)=26=Z
27-H(8)=19=S
27-E(5)=22=V
27-S(19)=8=H
So for MAHESH=NZSVHS
Similarly for rest of the names
and for HEMANT
27-H(8)=19=S
27-E(5)=22=V
27-M(13)=14=N
27-A(1)=26=Z
27-N(14)=13=M
27-T(20)=7=G
Hence
HEMANT=SVNZMG........Ans

Like? Yes (13) | No (5)  

prabhat kumar   11 years AGO

If
MAHESH=NZSVHS
SOHAN=HLSZM
GAURAV=TZFIZE
Then
HEMANT=SVNZMG
because here reverse albhabetical series are used
H=S
E=V
M=N
A=Z
N=M
T=G
JUST OPPOSITE IN REVERSE ALPHABETICAL SERIES.like
A=Z
B=Y
C=X
D=W
E=V
F=U
G=T
H=S
I=R
J=Q
K=P
L=O
M=N
N=M
O=L
P=K
Q=J
R=I
S=H
T=G
U=F
V=E
W=D
X=C
Y=B
Z=A

Like? Yes (4) | No (1)  

k n v v subbarao   11 years AGO

A=Z, B=Y, C=X, D=W,...., M=N, N=M,....., Y=B, Z=A

So HEMANT = SVNZMG

Like? Yes (3) | No (1)  

Anantharaman   11 years AGO

MAHESH = NZSVHS
SOHAN = HLSZM
GAURAV = TZFIZE

Alphabets are mappined in reversed order
ABCDEFGHIJKLMNOPQRSTUVWXYZ
ZYXWVUTSRQPONMLKJIHGFEDCBA

which brings

HEMANT = SVNZMG (Option 9)

Like? Yes (2) | No   

kumar sundram   11 years AGO

here,
M(13)=N(26-13+1=14),
A(1)=Z(26-1+1=26),
H(8)=S(26-8+1=19),
E(5)=V(26-5+1=22),
O(15)=L(26-15+1=12),
N(14)=M(26-14+1=13),
G(7)=T(26-7+1=20),
Thus, HEMANT=SVNZMG.

Like? Yes (1) | No   

Mayuresh Srivastava   11 years AGO

from left side
H(8)E(5)M(13)A(1)N(14)T(20)
=S(8)V(5)N(13)Z(1)M(14)G(20) from right side.

Like? Yes (1) | No   

LAKSHMI ROJA   11 years AGO

when we write the alphabets in the order
A B C D E F G H I J K L M
Z Y X W V U T S R Q P O N
MAHESH can be written as NZSVHS i.e., written as opposite words
similarly SOHAN=HLSZM
GAURAV=TZFIZE
therfore HEMANT can be written as SVNZMG so answer is SVNZMG i.e., option 9

Like? Yes (1) | No   

ABHISHEK KUMAR MISHRA   11 years AGO

According to question:
H=S
E=V
M=N
A=Z
N=M
SO appropriate answer of HEMANT=SVNZMG

Like? Yes (1) | No   

Manish Kumar   11 years AGO

MAHESH(13,1,8,5,19,8)=NZSVHS(14,26,19,22,8,19)
Just reversing the position of alphabet.
So..
HEMANT(8,5,13,1,14,20)= SVNZMG(19,22,14,26,13,7)

Like? Yes (1) | No   

Dharmendra Singh   11 years AGO

Ans. (9) very simple,
reverse the alphabet positions and get desired code.

Like? Yes (1) | No   

Kumar Ankit   11 years AGO

MAHESH
M stands at 13th position from Forward counting=N stands at 13th position from backward counting
Similarly
A stands at 1st position from Forward counting=Z stands at 1st position from Backward counting
H=S
E=V
S=H
H=S
Similarly
HEMANT = SVNZMG

Like? Yes (1) | No   

Dinesh thatti   11 years AGO

H=s
E=V
M=N
A=Z
N=M
T=G

Like? Yes (1) | No   

Rashmi bharti   11 years AGO

In MAHESH,SOHAN and GAURAV,we have
MN AZ HS EV GT
so, HEMANT=SVNZMG

Like? Yes (1) | No   

Harsh Poddar   11 years AGO

MAHESH=NZSVHS
M=N
A=Z
H=S
E=V
SOHAN=HLSZM
S=H
O=L
A=Z
N=M
GAURAV=TZFIZE
G=T
A=Z
U=F
R=I
A=Z
V=E
Then HEMANT
H=S
E=V
M=N
A=Z
N=M
T=G
HEMANT=SVNZMG
option 9

Like? Yes (1) | No   

venkata bavani g   11 years AGO

they have given the substitute for each leeter so taking tht in basis v hv to substitute for getting ans and for letter g it can also b taken as g as given

Like? Yes (1) | No   

prateek jain   11 years AGO

h=s;
e=v;
m=n;
a=z;
n=m;
t=g;

Like? Yes (1) | No   

Md Shahnawaz Shahab   11 years AGO

If
Since, MAHESH = NZSVHS , here we get H=S, E=V, M=N, A=Z
Now taking the above values into account only option 9) SVNZMG satisfies.



Then
HEMANT = ?

Like? Yes (1) | No   

harjeet   11 years AGO

H=S,E=V,M=V,A=Z,N=M,T=G all are given.

Like? Yes (1) | No   

KARUPPASAMY C   11 years AGO

H=s
E=v
M=n
A=z
N=m
T=g
so ans is=SVNZMG option (9)

Like? Yes (1) | No   

Vikram Saini   11 years AGO

reverse order A=Z,B=Y
similarly
HEMANT=SVNZMG

Like? Yes (1) | No   

Triloki Shaw   11 years AGO

in MAHESH M=N; A=Z;H=S;E=V;S=H; H=S;
IN SOHAN S=H;O=L;H=S;A=Z;N=M;
THEREFORE IN HEMANT H=S;E=V;M=N;A=Z;N=M;T=G
OPTION 9.

Like? Yes (1) | No   

Grishma Shah   11 years AGO

the Logic behind is :
A=Z; B=Y; C=X; D=W; E=V; F=U; G=T; H=S; I=R; J=Q; K=P; L=O; M=N;
Hence, HEMANT = SVNZMG

Like? Yes (1) | No   

jagdish sharma   11 years AGO

reverse order A=Z,B=Y
similarly
HEMANT=SVNZMG

Like? Yes (1) | No   

neha selokar   11 years AGO

Reverse the place values of number
like a=1 b=2.....z=26
start backwards
i.e z=1 y=2...a=26
so in this fashion,
HEMANT = SVNZMG

Like? Yes (1) | No   

AMIT SINHA   11 years AGO

H-S, E-V, M-N, A-Z, N-M, T-G

Like? Yes (1) | No   

Ashfaque Hussain   11 years AGO

HS
EV
MN
A->Z
NM
TG

Like? Yes (1) | No   

Priya   11 years AGO

Substitute the coded word for corresponding word
that means h-s,e- v,m- n ,a - z ,n- m, t -g

Like? Yes (1) | No   

krishnapriya   11 years AGO

from given we can understand that
M=N; A=Z; H=S; E=V; O=L; G=T; U=F; R=I
So, HEMANT=SVNZMG
option 9

Like? Yes (1) | No   

sivaraman   11 years AGO

In this sum coded language used below us:
H for S
E for V
M for N
A for Z
T for G

so you get SVNZMG

Like? Yes (1) | No   

N RAJU   11 years AGO

M=N
S=H
H=S
A=Z
E=V

AND SO ON...

Like? Yes (1) | No   

ashish   11 years AGO

Closely observe that
H represents --->S
E represents --->V
M represents --->N
A represents --->Z
N represents --->M
T represents --->G (See in "G"aurav ->"T"ZFIZE)
so ans 9) i.e. SVNZMG would be the answer

Like? Yes (2) | No (1)  

niraj kimar   11 years AGO

h=s,E=V,M=N,A=Z,N=M,T=G

Like? Yes (1) | No   

nivetha m   11 years AGO

a to z has the number 1 to 26 and then it reverse order vice calculate the given word the find the answer "svnzmg"

Like? Yes (1) | No   

lucky raj   11 years AGO

H=S; E=V; M=N; A=Z; N=M; T=G;
Thus, HEMANT=SVNZMG.

Like? Yes (1) | No   

Neha Jha   11 years AGO

replace each alphabet with the corresponding alphabet from right ie.
MAHESH - NZSVHS
HEMANT - SVNZMG
as(H=S from right and so...on....T=G from right)

Like? Yes (1) | No   

Anandapaul   11 years AGO

here,
above 3 words we conclued,
H=S
E=V
M=N
A=Z
N=M
T=G
SO TNE ANS IS: SVNZMG

Like? Yes (1) | No   

Radhika   11 years AGO

ANS:SVNZMG
Alphatic of reverse order Eg:
A,B,C,D,E,F,......etc
Tha alphabets of reverse order is:z,y,x,w,v,...etc.
so HEMANT=SVNZMG.

Like? Yes (1) | No   

ArunKumar   11 years AGO

H -> S
E -> V
M -> N
A -> Z
N -> M
T -> G

Like? Yes (1) | No   

sagar verma   11 years AGO

as M=N,H=S,E=V,A=Z,G=T,,.......by above given samples......
so v can easily write for HEMANT=SVNZMG

Like? Yes (1) | No   

Amar Deep Singh   11 years AGO

FROM GIVEN CODED NAMES WE HAVE
H=S,E=V,M=N,A=Z,N=M,T=G,O=L,U=F & R=I
therefore HEMANT=SVNZMG

Like? Yes (1) | No   

Heena Jain   11 years AGO

from the content given in the question h=>s,e=>v,m=>n,a=>z,n=>m,t=>g thus we get hemant=svnzmg

Like? Yes (1) | No   

Parveen Soni   11 years AGO

match the corresponding alphabets from given code and try to find code for given question

Like? Yes (2) | No (1)  

Sneha   11 years AGO

a b c d e f g h i j k l m
z y x w v u t s r q p o n
So, HEMANT-SVNZMG

Like? Yes (1) | No   

Prakash kumar   11 years AGO

from three given coded language, it can be justified that
H = S
E = V
M = N
A = Z
N = M
T = G

Like? Yes (1) | No   

FAISAL RIZWAN   11 years AGO

Given
MAHESH = NZSVHS
SOHAN = HLSZM
GAURAV = TZFIZE

A(1)to Z(26)
Now position of 1st letter=position of reversed letter

so option 9 is the correct

Like? Yes (2) | No (1)  

LOGAN WOLVERINE   11 years AGO

h coded as s
a as z
e as v
m as n
t as g
so answer svnzmg

Like? Yes (1) | No   

Gaurav Singh   11 years AGO

h-s and vice versa
e-v , m-n /n-m
m-n
a-z
n-m
t-g

Like? Yes (1) | No   

RAKKUYIL SARATH   11 years AGO

A= Z
B= Y
C= X
....
....
y= B
Z= A
alphabets corresponds to respective alphabets in reverse order
so HEMANT = SVNZMG

Like? Yes (1) | No   

Dipak Shaw   11 years AGO

By comparing
we get,
M=N
A=Z
H=S
E=V
T=G

Therefore,
HEMANT = SVNZMG

Like? Yes (1) | No   

Sagar   11 years AGO

From the first three equations
M=N
S=H
A=Z
E=V
Hence the answer

Like? Yes (1) | No   

Dharmendra Kumar Jain   11 years AGO

the letter in Question counting from starting
the answer letter will be the letter counting form ending word

Like? Yes (1) | No   

deepthi kankula   11 years AGO

from d abve 3,we get code for alphabets wat it actual means
m->n,a->z,h->s,e->v

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

the number at which the letter of LHS appears starting from A, the letters of same but starting from Z are writen.
HEMANT=starting from A
HEMANT=8TH+5TH+13TH+1ST+14TH+20TH......FROM A
SVNZMG=8TH+5TH+13TH+1ST+14TH+20TH......FROM Z
HEMANT=SVNZMG

Like? Yes (1) | No   

Nagarjun N   11 years AGO

a1 b2 c3 d4 e5 f6 g7 h8 i9 j10 k11 l12 m13 n13 012 p11 q10 r9 s8 t7 u6 v5 w4 x3 y2 z1
replace the alphabets with the alphabets having the same no.
example m (m13) will be replaced by n (n13)(both have the same no attached to it)
so h=s,e=v,m=n,a=z,n=m,t=g
ans is svnzmg

Like? Yes (1) | No   

js manikanta   11 years AGO

here m=n a=z e=v h=s
n=m t=G
so HEMANT=SVNZMG

Like? Yes (1) | No   

abhinav paul   11 years AGO

the alphabets used in the names have same code for the same alphabet i.e A is coded as Z, H is coded as S and so on..
so for HEMANT, choose the individual codes,, for lest alphabet T, G will be T. because G is coded as T.

Like? Yes (1) | No   

yvs radhika   11 years AGO

for mahesh-nzsvhs,coding simly...for hemant is svnzmg

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

M=N,E=V,H=S,A=Z,N=M,T=G
SO,HEMANT=SVNZMG

Like? Yes (1) | No   

Manish Singh   11 years AGO

here M=N,A=Z,H=S,E=V,S=H,ANS SO ON
i.e vic-vers
MAHESH = NZSVHS
SOHAN = HLSZM
GAURAV = TZFIZE
Then
HEMANT=SVNZMG ,BECAUSE
H=S,E=V,M=N,A=Z,M=N,T=G AND IT MEY BE vice versa ...

Like? Yes (1) | No   

prakash kumar   11 years AGO

let, A=1, B=2, ......, Z=26
In MAHESH. position of M is 13. now assume Z=1, Y=2, X=3, ......, B=25, A=26
then, at 13th position alphabet is N
similarly,position of A is 1 then in reverse order at 1s position,Z is there
so, MAHESH=NZSVHS
similarly,HEMANT=SVNZMG

Like? Yes (1) | No   

Saurabh Shekhar Singh   11 years AGO

comparing and providing the mathes..

Like? Yes (1) | No   

Gopal gupta   11 years AGO

HS
E V
M N
A Z
G T

therefor HEMANT=SVNZMG

Like? Yes (1) | No   

surbhi rathaur   11 years AGO

the letters are replaced by corresponding letters positioned on the number when counted from last.
HEMANT- H(8)by S(it is at 8th position when counted from last) similarly others.
so ans is SVNZMG

Like? Yes (1) | No   

ravikumar   11 years AGO

m=n, n=m,
e=v, v=e,
h=s, s=h

Like? Yes (1) | No   

rakesh   11 years AGO

Logic here is: 27 - NUMERICAL VALUE of the letter
MAHESH - NZSVHS
SOHAN - HLSZM
GAURAV - TZFIZE

HEMANT -
H=(27-8)S,E=(27-5)V,M=(27-13)N,A=(27-1)Z,N=(27-14)M,T=(27-20)G

HEMANT - SVNZMG

option :- 9

Like? Yes (2) | No (1)  

chaitanya   11 years AGO

as per comparision SVNZMG matches HEMANT

Like? Yes (1) | No   

ravi shankar rai   11 years AGO

h=a,s=h,a=z,m=n,h=s overall we get
the code
svnzmg

Like? Yes (1) | No   

Nipun saini   11 years AGO

H is replaced with S in all words and vice versa
E is replaced with V
and so on....

Like? Yes (1) | No   

Laltu banerjee   11 years AGO

here WE CAN SEE THAT
M->N
A->Z
H->S
E->V
S->H
H->S
O->L
N->M
G->T or T->G
by putting these we can get
HEMANT->SVNZMG
hence option 9

Like? Yes (1) | No   

malarvezhi.m   11 years AGO

From the given question,
MAHESH=NZSVHS.
That is,
M=N
A=Z
H=S
E=V
S=H
H=S.
Like this equate all the given names,then
In HEMANT,
H=S
E=V
M=N
A=Z
N=M
T=G
So the ans is SVNZMG.

Like? Yes (1) | No   

Neha Sharma   11 years AGO

In MAHESH=NZSVHS
M=N
A=Z
H=S
E=V
And IN GAURAV=TZFIZE
G=T
And in SOHAN = HLSZM
N=M
SO HEMANT=SVNZMG

Like? Yes (1) | No (1)  

Roushan Singh   11 years AGO

if we arrange the Alphabets in (A-Z) manner and again we will arrange the Alphabets in (Z-A) manner,we will find that the value which is coming at the same position with the refrence of any sequence(either (A-Z)OR(Z-A)) is chosen.

Like? Yes (1) | No (1)  

sandy   11 years AGO

A=Z
B=Y
C=X
D=W
E=V
F=U
G=T
H=S
I=R
J=Q
K=P
L=O
M=N
N=M
O=L
P=K
Q=J
R=I
S=H
T=G
U=F
V=E
W=D
X=C
Y=B
Z=A
so HEMANT = SVNZMG

Like? Yes (1) | No (1)  

Dharmendra Kumar Rajak   11 years AGO

Given MAHESH=NZSVHS
SOHAN=HLSZM
GAURAV=TZFIZE
From above we gets
H=S,E=V,M=N,A=Z,N=M,Then T=G
Then HEMANT=SVNZMG
So,Option (9) is correct

Like? Yes (1) | No (1)  

manisha mehta   11 years AGO

h comes at 8 position in alphabetical order of English and if we count from last that is in reverse order then s=8 and so on...so hemant=svnzmg

Like? Yes (1) | No (1)  

Udhaya kumar   11 years AGO

A=Z , B=Y....................Z=A
THEN HEMANT=SVNZMG........

Like? Yes (1) | No (1)  

NEELMANI SINDWANI   11 years AGO

A=Z=1;
B=y=2;
c=x=3;.....so on

Like? Yes (1) | No (1)  

ravi singh   11 years AGO

answer is SVNZMG

here,
S=H,
O=L,
A=Z
N=M
G=T
U=F
R=I
V=E
hence HEMANT=SVNZMG

Like? Yes (1) | No (1)  

shamily.k   11 years AGO

MAHESH=NZSVHS.
That is,
M=N
A=Z
H=S
E=V
S=H
H=S.
Like this equate all the given names,then
In HEMANT,
H=S
E=V
M=N
A=Z
N=M
T=G
So the ans is SVNZMG.

Like? Yes (1) | No (1)  

16 Oct 2013 Evaluate

Exact Value of 5.678678678678........ is

OPtion

1) 5672/999
2) 4673/999
3) 5673/333
4) 6753/343
5) 7653/233
6) 1891/999
7) 1891/333
8) 1981/333
9) 8911/999
10)None of these

Solution

let x = 5.678678678678........... (i)
Multiply 1000 both side
1000x = 5678.678678678678........... (ii)
Subtracting (ii) from (i)
999x = 5673
x = 1891/333

option 7

Correct Option: 7 Best Solution (49)

Rats   11 years AGO

5.678678678
.678678678 can be written as 678/999 since its a recurring decimal.
=5(678/999)
=(999*5+678)/999
=5673/999 (divide by 3 num. & den.)
=1891/333.......Ans

Like? Yes (15) | No (4)  

Harsh Poddar   11 years AGO

x=5.678678678......
1000x=5678.678678.....
Subtracting
999x=5673
x=5673/999=1891/333
option 7

Like? Yes (4) | No   

jagdish sharma   11 years AGO

x=5.678678.....
1000x=5678.678678....
1000x-x=5678.678678....-5.678678....
999x=5673
x=1891/333

Like? Yes (2) | No   

Ann Mary Jolly   11 years AGO

Ans : 1891/333
Let x be the rational no., x = 5.6786786786......
Then 10x = 56.786786....
and 10,000x = 56786.786786....
Now Subtracting 10x from 10,000x,since the decimal parts of two no.s are the same they'll be cancelled.
And so, 9,990x = 56786 - 56 = 56730 =>9990x=56730
Therefore, x = 5673/999 = 1891/333.

Like? Yes (2) | No   

Bholanath    11 years AGO

let y=5.678678...
1000y=5678.678678...
subtract both the equations,
999y=5673
y=5673/999
y=1891/333

Like? Yes (2) | No   

Triloki Shaw   11 years AGO

5672/999=5.677
4673/999=4.67
1891/333=5.6786786789

Like? Yes (2) | No   

Parveen Soni   11 years AGO

let a=given no. .............(1)
then 1000*a=given no. *1000.............(2)
(2)-(1) gives
5673/999 i.e 1891/333 option (7)

Like? Yes (2) | No   

Manish Singh   11 years AGO

when we divide 1891/333
we get 5.678678678678..... :)
so as ans gives the question,so option no 7.

Like? Yes (2) | No   

FAISAL RIZWAN   11 years AGO

1891/333=5.678678678678
so option 7 is correct

Like? Yes (2) | No   

Chandra sekhar reddy   11 years AGO

let x=5.678678678........
now 1000x=5678.678678.......
1000x-x= 5673.0
999x=5673
x=5673/999= 1891/333

Answer is 1891/333
Option is 7

Like? Yes (2) | No   

Manish Kumar   11 years AGO

1891/333 = 5.678678678678
option 7 is correct.

Like? Yes (1) | No   

Dharmendra Singh   11 years AGO

Ans. 7) is closest.
There is no other options that match up to three-four decimal places so need not to match all digits after decimal.
1891/333=5.6786.... only this option carry four digits of given question.
Note: you can also discard some option because they are not matching even single characteristics value.

Like? Yes (1) | No   

Krishna Chaitanya Boyanapalli   11 years AGO

1000x=5678.678678
x=5.678678
on solving x=5673/999=1891/333

Like? Yes (1) | No   

LAKSHMI ROJA   11 years AGO

by option verifying 1891/333=5.678678678...... so answer 1891/333 i.e.,option 7

Like? Yes (1) | No   

venkata bavani g   11 years AGO

tht is the only no which is divided by 333 which gives such a no as the ans

Like? Yes (1) | No   

Ravishankar Karn   11 years AGO

(5678-5)/999=5673/999=1891/333

Like? Yes (1) | No   

kumar sundram   11 years AGO

5.678678678=(5678-5)/999=5673/999=1891/333

Like? Yes (1) | No   

ravi shankar rai   11 years AGO

=1891/333=5.678678678

Like? Yes (1) | No   

Mayuresh Srivastava   11 years AGO

1891/333=5.6786786786786786786786786786787.

Like? Yes (1) | No   

MUKESH KUMAR   11 years AGO

1891/333= 5.678678678678

Like? Yes (2) | No (1)  

VAGU RAGHAVA ANJANI DIVYAVANI   11 years AGO

1891/333=5.678678678678

Like? Yes (1) | No   

neha selokar   11 years AGO

divide the options to get the answer
1891/333 = 5.6786787...

Like? Yes (1) | No   

Satyendra Singh   11 years AGO

divide and check no other options i think.

Like? Yes (1) | No   

NIDHI   11 years AGO

1891/333= 5.678678678678

Like? Yes (1) | No   

Guru Pranav   11 years AGO

choosing the values from options,
option 7 with 1891/333 satisfies the value of 5.678678678678

Like? Yes (1) | No   

Priya   11 years AGO

While dividing round off the last value

Like? Yes (1) | No   

Nagarjun N   11 years AGO

333*5.678678678678 = 1891

Like? Yes (1) | No   

Grishma Shah   11 years AGO

Multiplying 5.678678678678*333 = 1891

Like? Yes (1) | No   

Anantharaman   11 years AGO

1891/333 = 5.678678678678...

Option 7

Like? Yes (1) | No   

AMIT SINHA   11 years AGO

1891/333=5.678678678679

Like? Yes (1) | No   

Vinay Sipani    11 years AGO

As the decimals are recurring => denominator is a multiple of 3 or 11

From the options below,denominator is either 333 or 999

If denominator is 999 => numerator = 999 * 5.678 = 5673
If denominator is 333 => numerator = 333 * 5.678 = 1891

=> Number is 5673/999 or 1891/333

Hence option 7 is required answer

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

.678678....=678/999=226/333
5.678678678....=(5*333+226)/333=1891/333

Like? Yes (1) | No   

Soham Yadav   11 years AGO

1891/333= 5.678678678678679
it is very near to given value. So ans is 7

Like? Yes (1) | No   

Dilip B Gauswami   11 years AGO

all divide value can be different the
but 7 1891/333=5.678678678678678678......repeat them..

Like? Yes (1) | No   

prateek jain   11 years AGO

1891/333=5.678678678678...

Like? Yes (1) | No   

manoj kumar mayrya   11 years AGO

in this question only two option is possible 1&7.
and 7is right answer

Like? Yes (1) | No   

KARUPPASAMY C   11 years AGO

1891/333=5.678678678678
so option is (7)

Like? Yes (1) | No   

Dipak Shaw   11 years AGO

its a reccuring problem
x=5.678678....
x=5+.678678...
x=5+(678/999)
x=1891/333

Like? Yes (1) | No   

krishnapriya   11 years AGO

1891/333=5.678678678678...

Like? Yes (1) | No   

PRATHAM MEHROTRA   11 years AGO

1891/333=5.678678678678

Like? Yes (1) | No   

Bhargaviinduri   11 years AGO

by verifying options we get ans op-7

Like? Yes (1) | No   

Ashfaque Hussain   11 years AGO

1891/333=5.678678678678
option 7 is correct

Like? Yes (1) | No   

prakash kumar   11 years AGO

5.678678678678.....
=5+0.678678678678.....
=5+678/999
=5673/999
=1891/333

Like? Yes (1) | No   

Shashi Kumar Gupta   11 years AGO

1891/333=5.678678678678

Like? Yes (1) | No   

Dinesh thatti   11 years AGO

1891/333=5.678678678678

Like? Yes (1) | No   

Anjai Baghel   11 years AGO

i am explaining this question by taking other example
like
We have .555.... --------(1)

Multiply both side by 10, we get 10*.5555=5.55...-----(2)

Subtracting (1) from (2) we get

9*0.55...=5

so we right 0.55..=(5/9)ans

Directly from the rule , we also get the same result .555.... has its period 5, so the numerator is 5. And as there is only one digit in the period, the denominator will have one nine. Thus, the vuglur fraction=5/9

of if .454545=45/99

or if 5.454545= 5(45/99)(this technique is used in this question)

Like? Yes (1) | No   

Neha Sharma   11 years AGO

1) 5672/999=5.677677677677678
2) 4673/999=4.677677677677678
3) 5673/333=17.03603603603604
4) 6753/343=19.68804664723032
5) 7653/233=32.84549356223176
6) 1891/999=1.892892892892893
7) 1891/333=5.678678678678679
8) 1981/333=5.948948948948949
9) 8911/999=8.91991991991992
so answer is 1891/333=5.678678678678......

Like? Yes (3) | No (3)  

prabhat kumar   11 years AGO

simply going through all option when 1891 divided by 333 we will get 5.6786787 . so the exact value of 5.678678678678 is 1891/333.

Like? Yes (2) | No (2)  

ashish   11 years AGO

Hit and trial method ........ No reason !

Like? Yes (1) | No (1)  

15 Oct 2013 Solve

Solve
(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1 = ?

OPtion

1) 299.5
2) 448.5025
3) 448.0025
4) 448
5) 448.4975
6) 449
7) 449.5025
8) 449.0025
9) 449.4975
10) None of these

Solution

Simply solve
(150*150/100)+(149.5*149.5/100)-(.5025)+1
225 + 223.5025 - .5025 + 1
opton 6)

Correct Option: 6 Best Solution (55)

Rats   11 years AGO

225+223.5025-0.5025+1
=449......Ans

Like? Yes (12) | No   

Grishma Shah   11 years AGO

150% of 150 is 225
149.5% of 149.5 is 223.5025
150-149.4975=0.5025

hence, 225+223.5025-0.5025+1=449

Like? Yes (7) | No   

rohit kumar   11 years AGO

Given,
(150% of 150)+(149.5% of 149.5)-(150-149.4975)+1
=>((150/100)*150)+((149.5/100)*149.5)-(.05025)+1
=>(1.5*150)+(1.495*149.5)-(0.5025)+1
=>225+223.5025-0.5025+1
=>449.5025-0.5025
=>449......Ans

Like? Yes (4) | No   

ashish   11 years AGO

(150/100)*150 = 225
(149.5/100)149.5= 223.5025
150-149.4975 = .5025
so 225 + 223.5025 - 0.5025 + 1 = 449

Like? Yes (3) | No   

Ann Mary Jolly   11 years AGO

Ans : 449
150^2/100 + 149.5^2/100 -(150-149.4975) + 1
= 150^2/100 + (150-0.5)^2/100 - 150 + 149.4975 + 1
= (150^2 + 150^2 + .5^2 - 150)/100 + .4975
= (150(150*2 - 1)+.25)/100 + .4975
= (300*150 - 150 +.25)/100 + .4975
= (44850.25)/100 + .4975
= 448.5025 + .4975
=449

Like? Yes (3) | No   

FAISAL RIZWAN   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1=
225+448.5025-.5025+1=449
so on solving We are Getting 449

Option 6 is correct

Like? Yes (3) | No   

prabhat kumar   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+1
by solving above equation step by step
((150*150)/100)+((149.5*149.5/100))-0.5025+1
or 225+223.5025+0.4975
or 448.5025+0.4975
= 449
so, the correct option number is (6).

Like? Yes (3) | No (1)  

Sagar Jinachandran   11 years AGO

(150% of 150)= 225
(149.5% of 149.5)= 223.5025
(150-149.4975)= 0.5025
=225+223.5025-0.5025+1= 449
option 6

Like? Yes (1) | No   

LOGAN WOLVERINE   11 years AGO

448.5025-0.5025+1=449

Like? Yes (1) | No   

kumar sundram   11 years AGO

ans is 15^2+{(149.5)^2}/100-(150-149.4975-1)
=225+223.5025+.4975=449

Like? Yes (1) | No   

Pradyumna K S   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1 =
225+223.5025-0.5025+1=225+223+1=449
option 6 is answer

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1
=(150*150/100)+(149.5*149.5/100)-150+149.4975+1
=225+223.5025-150+149.4975+1
=449

Like? Yes (1) | No   

LAKSHMI ROJA   11 years AGO

((150*150)/100)+((149.5*149.5)/100)-0.5025+1
=>(22500+22350.25-50.25+100)/100
=>44900/100=449
therefore answer is 449 i.e., option 6

Like? Yes (1) | No   

Triloki Shaw   11 years AGO

first bracket gives 225, 2nd=223.5025; 3rd=0.5025
summing all dis gives 449

Like? Yes (1) | No   

Harjit kaur   11 years AGO

(150*150)/100+(149.5*149.5)/100-(150-149.4975)+1
(225+223.5025)-(0.5025)+1
448.5025-.5025+1
449

Like? Yes (1) | No   

neha selokar   11 years AGO

150% 150 = 225
149.5% 0F 149.5 =223.5025
SO 225+223.5025-150+149.4975+1=449

Like? Yes (1) | No   

Dinesh thatti   11 years AGO

150/100*150=225
149.5/100 * 149.5=223.5025

150-149.4975=0.5025

225+223.5025-0.5025+1=449

Like? Yes (1) | No   

sivaraman   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1 so answer is mathematical function use you get 449

Like? Yes (1) | No   

Bhargaviinduri   11 years AGO

225+223.5025-0.5025+1=449
so ans is 449

Like? Yes (1) | No   

manasa epuru   11 years AGO

jst by solving we could get the result..

Like? Yes (1) | No   

subhrajit mitra   11 years AGO

(150*150/100)+(149.5*149.5/100)-0.5025+1
=(15^2+14.95^2)+0.4975
=(15-14.95)^2+2*15*14.95+0.4975
=.05^2+30*14.95+0.4975
=.0025+448.5+0.4975
=449

Like? Yes (1) | No   

ravi shankar rai   11 years AGO

(1.5*150)+(1.495*149.5)-(0.5025)+1
=225+223.5025-0.5025+1
=449

Like? Yes (1) | No   

Mayuresh Srivastava   11 years AGO

225+223.5+0.4975
=449.

Like? Yes (1) | No   

krishnapriya   11 years AGO

=225+223.5025-0.5025+1=449

Like? Yes (1) | No   

Anantharaman   11 years AGO

150% of 150 = 225

149.5% of 149.5 = 223.5025

150-149.4975 = 0.5025

225+223.5025-0.5025+1 = 449 (Option 6)

Like? Yes (1) | No   

sandy   11 years AGO

(1.5*150)+(1.495*149.5)-(0.5025)+1
=449

Like? Yes (1) | No   

rakesh   11 years AGO

Following the BEDMAS rule

Evaluate exp's present in brackets then

((150/100)*150)=225
((149.5/100)*149.5)=223.5025
(150-149.4975)=0.5025 NOW

225 + 223.5025 - 0.5025 + 1 (Acc to BEDMAS next opearation to perform is ADDITION)

448.5025-0.5025+1

448.5025+0.4975 = 449

therefore ANSWER IS 449 i.e option 6

Like? Yes (1) | No   

VAGU RAGHAVA ANJANI DIVYAVANI   11 years AGO

((150/100)*150)+((149.5/100)*149.5)-(150-149.4975)+1

=(225)+(223.5025)-(0.50250)+1
=449

Like? Yes (1) | No   

VIKASH KUMAR SHARMA   11 years AGO

150% of 150= 225
149.5% of 149.5=223.5025
-.5025
+1
=449 ans

Like? Yes (1) | No   

Siddhartha   11 years AGO

150% of 150 = 225, 149.5% of 149.5 = 223.5025
150-149.4975 = 0.5025
So, 225+223.5025+1-0.5025=449

Like? Yes (1) | No   

Neha Sharma   11 years AGO

150% of 150=150*150/100 =225
149.5% of 149.5= 149.5*149.5/100=223.5025
150-149.4975=0.5025
so
(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1 = 225+223.5025-0.5025+1= 449

Like? Yes (1) | No   

ravi singh   11 years AGO

answer is 449

its a simple calculation of percentage

Like? Yes (1) | No   

surbhi rathaur   11 years AGO

simply solved.
225+223.5025-0.5025+1= 449

Like? Yes (1) | No   

ashutosh   11 years AGO

225+223.5025-.5025+1=449

Like? Yes (1) | No   

DEEPAK SINGHAL   11 years AGO

solve this question by calculaion becoz 149.25 * 149.25/100 it wil be223.5025 and ans of (150-149.4975)=.5025 so ans will only 4 &6 after calculating 223+225+1=449

Like? Yes (1) | No   

Amar Deep Singh   11 years AGO

(150%of 150)+(149.5% of 149.5)-(150-149.4975)+1=
(225)+(223.5025)-(.5025)+1=
448+1=449

Like? Yes (1) | No   

Guru Pranav   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1 =449

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

=(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1
=(15*15)+(149.5*149.5)+0.4975
=225+223.5025+0.4975
=449

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prakash kumar   11 years AGO

150% of 150=225
149.5% of 149.5=223.5025
150-149.4975=0.5025
now, 225+223.5025-0.5025+1
=449.5025-0.5025
=449

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jatin patware   11 years AGO

225+223.5025-150+149.4975+1=449
so option 6 is correct

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Ankit Pandey   11 years AGO

225+223.5025-.5025+1=449

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

225+223.5025-0.5025+1=449

Like? Yes (1) | No   

Udhaya kumar   11 years AGO

225+223.5025+1-0.5025=449..............

Like? Yes (1) | No   

niraj kimar   11 years AGO

150*150/100=225+(149.5*149.5/100)=223.5025+1-0.5025=449

Like? Yes (1) | No   

manikandan   11 years AGO

150% of 150=225 149.5of 149.5=223.5025
225+223.5025-150+149.4975+1=449

Like? Yes (1) | No   

Anilkumar   11 years AGO

150% of 150=225
149.5% of 149.5=223.5025
150-149.4975=0.5025
225+223.5025-0.5025+1=449

Like? Yes (1) | No   

Sindu   11 years AGO

150%of 150=225
149.5%of 149.5=223.5025
S0 225+223.5025-0.5025+1=449

Like? Yes (1) | No   

pratik jitendra malviya   11 years AGO

225+223.5025-0.5025+1=449

Like? Yes (1) | No   

Md Shahnawaz Shahab   11 years AGO

By simplification we get the result...449

Like? Yes (1) | No   

Priya   11 years AGO

According to Bodmas theory first we should solve with in the bracket and then usual solving

Like? Yes (1) | No   

manisha mehta   11 years AGO

225+223.5025-0.5025+1=449

Like? Yes (1) | No   

IFFAT IRAM   11 years AGO

225+223.5025-0.5025+1=449

Like? Yes (1) | No   

TIPPANA LOCHANA   11 years AGO

=((150/100)*150)+((149.5/100)*149.5)-150+149.4975+1
=225+223.5025-150+149.4975+1
=449

Like? Yes (1) | No   

Shashi Kumar Gupta   11 years AGO

225+223.5025-150+149.4975+1=448

Like? Yes (1) | No   

MUKESH KUMAR   11 years AGO

(150% of 150)+(149.5% of 149.5)-(150-149.4975)+ 1 =449

Like? Yes (1) | No (1)  

14 Oct 2013 Sequence

What is the next number of the following sequence
521,523,526,5201,5251,.......

OPtion

1) 5971
2) 5212
3) 5278
4) 5476
5) 5281
6) 5264
7) 8635
8) 6534
9) 5221
10)None of these

Solution

5^2+10^2 = 25+100 = 125 (Reverse the number) = 521
10^2+15^2 = 100+225 = 325 (Reverse the number) = 523
15^2+20^2 = 225+400 = 625 (Reverse the number) = 526
20^2+25^2 = 400+625 = 1025 (Reverse the number) = 5201
25^2+30^2 = 625+900 = 1525 (Reverse the number) = 5251
Similarly Next
30^2+35^2 = 900+1225 = 2125 (Reverse the number) = 5212
option 2)

Correct Option: 2 Best Solution (35)

rohit kumar   11 years AGO

Reverse all the numbers i.e
125,325,625,1025,1525
Now,
325-125=200
625-325=300
1025-625=400
1525-1025=500
So next one will be

2125-1025=600
Now reverse the term i.e 5212

Like? Yes (20) | No (2)  

Dharmendra Singh   11 years AGO

Ans 2) 5212
Explanation:
Reverse the all digits we got a series as
125, 325, 625, 1025, 1525, .. here difference of next no. is 200, 300, 400, 500, so next will be 600 so 1525+600=2125 now we reverse we get 5212 :)

Like? Yes (4) | No (1)  

Pargat Pal Singh   11 years AGO

521,523,526,5201,5251,.......
writing numbers in reverse order

125,325,625,1025,1525
Diff in numbers is 200,300,400,500
next number will be obtained by adding 600.
so next number in reverse order will be 1525+600=2125...
2125 5212
so required number is 5212.

Like? Yes (3) | No   

Harjit kaur   11 years AGO

Writt d seq by reversing digit of every no as
125,325,625,1025, 1525
nw here diff b/w these no is
200,300,400,500 res.
So d next no diff will be 600
so next term is 1525+600=2125
By reversing it's digit we get the ans 5212

by reversing it's digit we get 5212
That's ans.

Like? Yes (2) | No (1)  

vaibhav rajhns   11 years AGO

take reverse order of digits i.e
521 as 125
523 as 325
526 as 625
5201 as 1025
5251 as 1525
then we require 2125 so answer is 5212

Like? Yes (1) | No   

bothra namita   11 years AGO

sequence is given as first two digits(52) are stationary and other digits are the series with consecutive no is add(1, 3=1+2, 6=3+3, 01=reverse of 10(=5+4)..)
thus next no is 5212(12= reverse of 21(=15+6))

Like? Yes (1) | No   

Ann Mary Jolly   11 years AGO

The digits after 52 is given by Tn=Tn-1+n,in reverse order.
So the digits in T6 after 52is T6=T5+6=15+6=21 in reverse order,so 12
Therefore the next term is 5212.

Like? Yes (3) | No (2)  

Kanika   11 years AGO

521, now take last digit of 521 i.e. 1
1+2=3 so 523
3+3=6 so 526
6+4=10 but written as 01 so 5201
10+5=15 but written as 51 so 5251
15+6=21 but written as 12 so 5212

Like? Yes (1) | No   

Manish Singh   11 years AGO

reverse the digit ,i.e 325-125=200
625-325=300
similarly
1525-1025=500 and the next digit should have a diff of 600 ,so 1525+600=2125 an reverse it we have 5212 i.e option no 2 .

Like? Yes (2) | No (1)  

raja babu   11 years AGO

5 2 1 =
5 2 3 = difrence of unit digit is 2
5 2 6 = difrence of unit digit is 3
5 2 0 1= difrence of unit digit is 4
5 2 5 1=difrence of unit digit is 5
so differen unit digit will be 6 and it is added in unit digit and carry is written before unit digit.
so the next no. will be 5212

Like? Yes (1) | No   

sharmila navaladi   11 years AGO

the unit digit is added by 1.

Like? Yes (1) | No   

Bicky kumar   11 years AGO

i incrases by linearly by 2,3,4,ans so on and after every 10,a new number starting from o is started.
523-521=2,526-523=3we can see that it increasing linearly.now for the next number 526+4=530 but it is 5201.for the next number increses by 5 so 525+5=530but it will be 5212.

Like? Yes (1) | No   

Akash Mehta   11 years AGO

1st number fixed=5
2nd number fixed=2
now the difference of third digit is increasing linearly,i.e,means increasing by 1.
1-3=2
3-6=3
6-10(reverse of 01)=4
10-15(reverse of 51)=5
so, 15-21(reverse of 12)=6
hence 5212 is the rite answer.

Like? Yes (1) | No   

Kanchan Nandwani   11 years AGO

as here all the numbers in series have 52 (frst two digit) and521,523,526,5201,5251......
1,3,6,10(inverting last two digits of 5201),15(inverting last two digits of 5251)
and differnces are in AP next term would 21 ie.
12...5212

Like? Yes (2) | No (1)  

Anantharaman   11 years AGO

Reverse the numbers, we get

125 325 625 1025 1525 2125
200 300 400 500 600

2125 => Reversing the digits, we get

5212 (Option 2)

Like? Yes (2) | No (1)  

Rats   11 years AGO

first two digits in each number same. Now look at the remaining digits..
1,3,6,01,51
reverse the last two numbers
1,3(1+2),6(3+3),10(6+4),15(10+5)
so next number is (15+6)21
now reverse it and join with 52
So we get 5212.....Ans

Like? Yes (2) | No (2)  

Udhaya kumar   11 years AGO

It is the sequence of reverse number of 25*(5+2n)
where n = 0,4,10,18,28,40 respectively.......
so next number is 25*(5+2(40))=25*85=2125;;5212......

Like? Yes (1) | No (1)  

Devendra Marghade   11 years AGO

Following result written with digits reversed
25*5=125 = 521
25*(5+8)=325 =523
25*(13+12)=625 =526
25*(25+16)=1025 =5201
25*(41+20)=1525 =5251
25*(61+24)=2125 =5212

Like? Yes (1) | No (1)  

Md Shahnawaz Shahab   11 years AGO

521
52(1+2)=523,
52(3+3)=526,
52(6+4)=5210=5201,
52(10+5)=5215=5251,
52(15+6)=5221=5212

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surbhi rathaur   11 years AGO

521:1+2=3, so next no. is 523
then 3+3=6, next no. is 526
6+4=10 the last digits are reversed in the next no. i.e.5201
then 10+5=15, digits reversed i.e. 5251
hence next no. will be 15+6=21, digits reversed i.e. 5212

Like? Yes (1) | No (1)  

risha anand   11 years AGO

521=1st 2 digits are 52,last digit is 1
523=1st 2 digits are 52,last digit is 3
526=1st 2 digits are 52,last digit is 6
5201=1st 2 digits are 52,last 2 digit is 10 written as 01
5251=1st 2 digits are 52,last 2 digit is 15 written as 51
so, in our ans also 1st 2 digits will be 52 so lat 2 digits will be 21 written as 12
ANS.5212 i.e option no. 2

Like? Yes (1) | No (1)  

jatin patware   11 years AGO

increment by 1 then 2 3 4 5
so increment is 6
51=15
15+6=21
21=12

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harshit   11 years AGO

soln:
the first two digit 52 remain d same...the third digit increases...1,1+2=3,3+3=6,6+4=10(reversed),10+5=15(reversed),15+6=21(reversed)..so 5212

Like? Yes (1) | No (1)  

manisha mehta   11 years AGO

521(52,1), 523(52,3), 526(52,6), 5201(52,10 and the 10 gets reversed i.e. 52,01), 5251(52,15 and the 15 gets reversed i.e. 52,51) and now, according to the series, (1,3,6,10,15 .. ) the next term comes as 21 and it gets reversed as 12 which gives the next term as 5212

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Amar Deep Singh   11 years AGO

the series follows as 521,523,526,5201,5251,5221 keeping 52 as constant and increasing the next term as follows 520+1=521
521+2=523
523+3=526
526+4=5210 but the summmation part after three terms written in reveresed order as=5201.
5210+5=5215 but written as5251.
5215+6=5221 but written as5212.

Like? Yes (1) | No (1)  

prabhat kumar   11 years AGO

first reverse all the digits. so the series becomes 125,325,625,1025,1525. Now we'll see that each successive terms differ by 200,300,400,500 respectively. So the 6th term would differ by 600. so 6th term = 1525+600 = 2125. Reversing this number we get 5212.

Like? Yes (1) | No (1)  

rakesh   11 years AGO

reverse all the given numbers then,
125,325,526,1025,1525,....(on dividing each number by 25)
25*5=125,25*13=325,25*25=625,25*41=1025,25*61=1525..
now consider diff b/w quotients,there pattern is as follows..
8,12,16,20..(diff getting increased by 4,therefor next one should be 24)
hence 61+24=85,25*85=2125.
now reverse this number we get 5212..
therefore answer is 5212

Like? Yes (1) | No (1)  

manasa epuru   11 years AGO

add +2,+3 and so on.. when it crosses 10 reverse last two digits..

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Bhargav Dekivadiya   11 years AGO

see last digit 1,3,6 and distance is 1+2=3, 3+3=6, 6+4=10(rotate it = 01),10+5=15(rotate it = 51) so 15+6=21(after rotating 12)...so ans is 5212

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ANIL CHOUDHARY   11 years AGO

52 is constant...and unit digit of first no. is..
1.second1+2=3,third 3+3=6,fourth there are write in opposite order 6+4=10,fifth 10+5=15,sixth..15+6=21,,there for next term is...5212

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P.Krishnakanth   11 years AGO

521,523,526,5201,5251

here 52 is common
1 3 6 01 51
1 3 6 10 15
difference 2 3 4 5 6
so 21-15=6 then 12 is the next number
answer 5212

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VAGU RAGHAVA ANJANI DIVYAVANI   11 years AGO

52 is common..
01 must be reversed so 10
51 revers 15
so
difference is 3-1=2
1,3,6,10,15,

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pratik namjoshi   11 years AGO

its just +n and reversing the digits in resulting sum where n is 1,2,3,...

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manisha gajanan gawai   11 years AGO

521 add 2 it become 523
then add 3 into 523 it become 526
then add 4 into 526 it become 5210 interchange last digit now new one is 5201
again add 5 into 5210 it become 5215 interchange last digit now it become 5251 same process ans is 5212

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sivaraman   11 years AGO

521 next number is 523. first two digit are same. so we update last two digit add and make it reverse..
so 5251 add 6 5212

Like? Yes (1) | No (2)