Given that one root of the equation ax^2+bx+c=0 is three times the other, Then 3b^2 = ?
OPtion
1) ac
2) 8ac
3) 9ac
4) 5a^2.c^2
5) 14ac
6) 16a^2.c
7) 16ac
8) 8ac^2
9) 12ac
10)None of these
Solution
Let one root be x, then other root will be 3x
x+3x=-b/a ---- 4x=-b/a (i)
x*3x=c/a ---- 3x^2=c/a (ii)
Substituting x form (i) into (ii)
solve
3b^2=16ac
option 7)
Seven times a given two digit number is equal to four times the number obtained by inter changing the digit and the difference of the digit is 3. find the number.
By the given condition
7(10x+y)=4(10y+x)
y=2x (i)
Also given x-y=3 (ii)
solve we get x=3 and y=6
10x+y = 30+6 = 36
check 36*7 = 63*4
252 = 252
option 6
1. 12/04/1996 is one-two/zero-four/one-nine-nine-six
This word representation contains 6 / 8 / 14 letters hence code is 6814.
2. 11/05/2003 is one-one/zero-five/two-zero-zero-three
This word representation contains 6 / 8 / 16 letters hence code is 6816.
3. 21/09/2009 is two-one/zero-nine/two-zero-zero-nine
This word representation contains 6 / 8 / 15 letters hence code is 6815.
Similarly
18/09/2013 is one-eight/zero-nine/two-zero-one-three
So this word representation contains 8 / 8 / 15 letter hence code is 8815.
option 5
Let r, R be radii of smaller and larger circles respectively.
Distance between centres = R+r=17 (i)
Sum of areas = (Pi*R^2)+(Pi*r^2) = 149*Pi
R^2 + r^2 = 149 (ii)
Using (R+r)^2 + (R-r)^2 = 2(R^2+r^2)
solve (i) and (ii)
R-r=3 (iii)
solve (i) and (iii)
R=10, r=7
Ratio of areas = (Pi*r^2)/(Pi*R^2) = 49:100