M4maths Previous Puzzles

02 Jan 2014 Solve

An army contingent of 1232 members is to march behind an army band of 64 members in a parade. The two group are to march in the same number of columns. What is the maximum number of columns in which they can march.

OPtion

1) 4
2) 8
3) 10
4) 12
5) 14
6) 16
7) 18
8) 22
9) 24
10)None of these

Solution

To find the maximum number of columns, we find H.C.F. (1232, 64)
By using Euclid,s algorithm to find their H.C.F.
the maximum number of columns in which they can march in 16

Correct Option: 6 Best Solution (29)

mahima srivastava   11 years AGO

we have to divide 1232 and 64 member into equal number of columns
so,
let x be the number of columns
let y and z be the number of rows of 64 member group and 1232 members group respectively.
so,
x*y=64
x*z=1232
when we simplify 1232/64 then we get 77/4
therefore, y=4 and z=77
so now solving above equation for x we get,
x=16
hence option 6

Like? Yes (6) | No (2)  

R.RAVIKUMAR   11 years AGO

The H.C.F of 1232 and 64 is 16...
so, they can march in the 16 no.of columns...

Like? Yes (5) | No (3)  

Dr.Dipin Singh   11 years AGO

64=4*16
1232= 77*16
so 16 is common factor .

Like? Yes (2) | No (1)  

stutisahoo   11 years AGO

16*4=64
16*77=1232

Like? Yes (3) | No (2)  

A.Sivapriya   11 years AGO

H.C.F of 1232 and 64 is 16...

Like? Yes (3) | No (2)  

Naveen Pandey   11 years AGO

take the hcf of 1232 and 64..it will be 16

Like? Yes (1) | No (1)  

TAREK HAYDER SK   11 years AGO

h.c.f of 1232 and 64 is 16

Like? Yes (3) | No (3)  

D.Mamatha   11 years AGO

H.C.F of 1232 and 64 gets 16..

Like? Yes (2) | No (2)  

Sukanya   11 years AGO

the GCD of 64 and 1232 is 16.

Like? Yes (2) | No (2)  

KRISHNAN   11 years AGO

The Highest common multiple between 1232 and 64 is 16 hence the maximum number of coloum can be 16

Like? Yes (2) | No (2)  

Leelanand Kumar Yalla   11 years AGO

H.C.F OF 1232,64= 16.....

Like? Yes (1) | No (1)  

Grishma Shah   11 years AGO

Maximum column = the reminder dividing the no. of army band to the no. of column should be equal to 0.

64%16=1232%16=0
Hence,maximum no. of column = 16

Like? Yes (2) | No (2)  

Gurmeet Singh   11 years AGO

Gcd of 64 and 1232= 16 is the required ans

Like? Yes (1) | No (1)  

SHIKHA SUMAN   11 years AGO

hcf of 1232 and 64=16

Like? Yes (1) | No (1)  

babita   11 years AGO

as we have to take the maximum no. of members in a column we have to find the HCF of 1232 and 64 ie 16

Like? Yes (1) | No (1)  

vishnupriya   11 years AGO

gcd(64,1232)=16

Like? Yes (1) | No (1)  

Siba Kumar Sahu   11 years AGO

because h c f of 1232 and 64 is 16

Like? Yes (1) | No (2)  

P Niranjan   11 years AGO

we can form 64 members by

2×32,4×16,8×8,16×4, 32×2

similarly for 1232 members

616×2,308×4,154×8,77×16

so from the arrangements 16 columns is maximum

so answer is 16

Like? Yes (2) | No (3)  

Surya Narayana K   11 years AGO

The maximum of columns in which they can march is H.C.F of 1232 and 64.

H.C.F of 1232 and 64 is 16.

So,maximum of columns in which they can march is 16.

Like? Yes (1) | No (2)  

vinoth kumar   11 years AGO

1232 and 64 can be divided by 16

Like? Yes (1) | No (2)  

Er. SIBA KUMAR   11 years AGO

the highest common factor of 1232 and 64 is 16

Like? Yes (1) | No (2)  

v.srujan kumar   11 years AGO

4*16=24, i.e;16 is suitable.............

Like? Yes (1) | No (2)  

sravani   11 years AGO

16 is the maximum no that can divide boith of them

Like? Yes (1) | No (2)  

Doddi Venkata Rao   11 years AGO

because HCF of both 1232 and 64 is 16.hence the max possible columns are 16.

Like? Yes (1) | No (2)  

Krishna Chaitanya   11 years AGO

Given 1232 members should march behind 64 members so that we need to find maximum columns,Suppose 64 mem form 4*16 columns then 1232 mem form 77*16 members
Therefore maximum number of columns in which they march=16

Like? Yes (1) | No (2)  

vaibhav singh   11 years AGO

both the numbers are divisible by maximum value that is 16.
that's why
means hcf of 1232 and 64.

Like? Yes (1) | No (2)  

Sivanjali   11 years AGO

The G.C.D of 1232 and 64 is 16.

Like? Yes (1) | No (2)  

mohini gupta   11 years AGO

64/16=4 rows
1232/16=77 rows

Like? Yes (1) | No (2)  

Srinivasa Vamsi Krishna Dodda   11 years AGO

1232 must be distributed in same Coloumn ..
So Divide it with 64 .. Ans is Not Interger So , no Same distribution
Divide with 32 (2 rows of Band men) ., Not Integer

Divide with 16 (4 Rows of band men) ., We Got an integer 77..

So, 16 is answer

Like? Yes (1) | No (2)  

01 Jan 2014 Probability

There are 4 men A, B, C, D and 4 women a, b, c, d. If B's wife is not a and A's wife is not c then probability that C's wife is either b or d is

OPtion

1) 1/2
2) 4/7
3) 1/7
4) 1/4
5) 1/3
6) 3/7
7) 1/12
8) 3/4
9) 15/16
10) 3/5

Solution

Total no. of combinations are 4*3*2*1=24
There are 6 ways for making a pair of B-a, similarly 6 ways are possible for the pair A-c in these ways 2 ways are common hence total no. of rejected ways
=6+6-2=10
Similarly 6-6 ways are possible for the combination of C-b and C-d, in these ways 3-3 ways are affiliated with pair A-c and B-a hence only 3-3 ways are acceptable
A representation for the pair C-b is
C-b A-a B-c D-d (selected)
C-b A-a B-d D-c (selected
C-b A-c B-a D-d (rejected)
C-b A-c B-d D-a (rejected)
C-b A-d B-a D-c (rejected)
C-b A-d B-c D-a (selected)

Hence probability is 6/14=3/7

Correct Option: 6 Best Solution (2)

ROHIT UPADHYAY   11 years AGO

probability is 6/14=3/7

Like? Yes (4) | No (3)  

Keshav Kishlay   11 years AGO

here total sample space=14
for C's wife is either b or d=6
so, probability=6/14=3/7

Like? Yes (1) | No (2)  

31 Dec 2013 Solve

The rank of the word ABDUL in the dictionary of all the words formed by the letters of the word ABDUL is?

OPtion

1) 1
2) 12
3) 120
4) 37
5) 24
6) 2
7) 28
8) 49
9) 29
10) None of these

Solution

A, B, D are in the correct sequence in the given word, but U and L are in reverse positions, hence rank is 2.

Correct Option: 6 Best Solution (29)

YUVAN SATHAIAH   11 years AGO

Write the alphabetical order of the letters of the given word \'ABDUL\' as ,A,B,D,L,U.

now strike of the first letter A

A,B,D,L,U

then count the no.of letters before M, and it\'s equal to 0, which is the coefficient of 4!.
0(4!)

similarly B,D,U,L
0(3!), 0(2!), 1(1)

Finally add 1 to the above values to get the rank of the word ABDUL:

0(4!)+0(3!)+0(2!)+1(1!)+1=1+1
=2
option is 6)2

Like? Yes (3) | No   

Siba Kumar Sahu   11 years AGO

Ans:2
because the words formed from the letters of the word ABDUL are
ABDLU
ABDUL
ABLDU
ABLUL
and simillarly many more word
In the list the word ABDUL comes 2. so the rank of the word ABDUL is 2.

Like? Yes (2) | No   

P Niranjan   11 years AGO

ABDUL
give the alphabetical sequence number for the word
i.e, 1 2 3 5 4
after applying order ABD there are two possibilities that are ABDLU(1) and ABDUL(2)

So the rank is 2

Like? Yes (2) | No   

Keshav Kishlay   11 years AGO

rank will depend only "U" and "L".
in dictionary first L will come.
hence the position of ABDUL is second

Like? Yes (3) | No (1)  

Sajib Ghosh   11 years AGO

all the alphabet of the word abdul is in proper form except the last two alphabet i.e 'u' and 'l'.. since u>l ,,so the position will be second.

Like? Yes (1) | No   

babita   11 years AGO

to arrange ABDUL it will be first arranged as per dictionary as ABDLU and then the 2nd rank ABDUL

Like? Yes (1) | No   

Rahul gulati   11 years AGO

ABDLU - 1
ABDUL - 2

Like? Yes (1) | No   

PRADEEP REDDY INTURI   11 years AGO

1)abdlu
2)abdul

Like? Yes (1) | No   

sujata patiyal   11 years AGO

according to dictionary abdul will be 2 wprd

Like? Yes (1) | No   

Mayuri Rangari   11 years AGO

Total no of words formed from the letters of word ABDUL = 120
1st letter using dictionary is = ABDLU
n hence 2nd letter will b = ABDUL
hence ans is 2.

Like? Yes (1) | No   

Code Breaker   11 years AGO

Considering no repetition,
ABDLU be the first word & ABDUL should be second

Like? Yes (1) | No   

pankaj chandra joshi   11 years AGO

strt by abd=2! 2
one is abdlu and other is abdul
At 2nd abdul will come
so option 6

Like? Yes (1) | No   

rajansingh   11 years AGO

in dict.
the sequence format will appear as like
abcdefgh...
so
ABDLU
ABDUL

Like? Yes (1) | No   

Sivanjali   11 years AGO

The first word is ABDLU then the second word is ABDUL

Like? Yes (1) | No   

prakash kumar   11 years AGO

in dictionary all letters are alphabetically,
in ABDUL - ABD are self arranged,by alphabetical L come before U ,
then LU arranged 2 ways.

Like? Yes (1) | No   

Anand Sanmani   11 years AGO

AB is the 2nd phase

Like? Yes (1) | No   

Krishna Chaitanya   11 years AGO

Given ABDUL given no condition so no repetition
1 2 3 5 4
A B D U L
0 0 0 1 0
4! 3! 2! 1! 0!
answer=(0*4!)+(0*3!)+(0*2!)+(1*1!)+(0*0!)+1=1+1=2
Write alphabetical order of numbers above each letter and check numbers

Like? Yes (1) | No   

Vijay Chauhan   11 years AGO

there are only one word before ABDUL is
ABDLU...out of 120 combinations...

Like? Yes (1) | No   

ASHOK KUMAR KUNCHALA   11 years AGO

ABDLU is the first word, ABDUL is the second

Like? Yes (1) | No   

Vinay Sipani    11 years AGO

Arranging the letters alphabetically

=> 1st word will be ABDLU
=> 2nd word will be ABDUL

so rank = 2
=> Option 6

Like? Yes (1) | No (1)  

Ann Mary Jolly   11 years AGO

In alphabetical order,
1st word will be ABDLU
2nd word will be ABDUL

Like? Yes (1) | No (1)  

mahima srivastava   11 years AGO

first word abdlu and second abdul

Like? Yes (1) | No (1)  

R.RAVIKUMAR   11 years AGO

From the word ABDUL..
In dictionary it follows the sequence of letters as
A,B,C,D,...
so, here from given letters possibilities are
ABDLU -- rank 1
ABDUL -- rank 2

Like? Yes (1) | No (1)  

stutisahoo   11 years AGO

ABDLU will be rank 1

Like? Yes (2) | No (2)  

Surya Narayana K   11 years AGO

ABD.. Remaining two letters are 2 ways.
Those are
ABDLU
ABDUL
so, ABDUL rank is 2.

Like? Yes (1) | No (1)  

sudipta sadhukhan   11 years AGO

after A B D L U comes then A B D U L
so rank 2

Like? Yes (1) | No (1)  

g.soujanya   11 years AGO

1 2 3 5 4
A B D U L
0/0! 0/0! 0/0! 1/1! 0/1!

1/1! + 1 = 2

Like? Yes (1) | No (1)  

ROHIT UPADHYAY   11 years AGO

abdlu and then abdul

Like? Yes (1) | No (1)  

Grishma Shah   11 years AGO

Dictionary is formed by words A, B, D, U, L
1. ABDLU
2. ABDUL
Hence 2nd place

Like? Yes (1) | No (1)  

30 Dec 2013 Sequence

What is the next number of the following sequence
3,9,19,33,.......

OPtion

1) 48
2) 56
3) 51
4) 64
5) 68
6) 72
7) 81
8) 88
9) 96
10)None of these

Solution

(2*1^2)+1 = (2*1)+1 = 2+1 = 3
(2*2^2)+1 = (2*4)+1 = 8+1 = 9
(2*3^3)+1 = (2*9)+1 = 18+1 = 19
(2*4^2)+1 = (2*16)+1 = 32+1 = 33
Similarly
(2*5^2)+1 = (2*25)+1 = 50+1 = 51
option 3)

Correct Option: 3 Best Solution (85)

Akanksha Mishra   11 years AGO

Look upon the series Carefully
3,9,19,33...

9 - 3 = 6
19 - 9 = 10
33 - 19 = 14

look at difference of ans is 4
6,10,14,...
so next difference of 5th and 4th number will be 18

4th number + 18 = 5th number
33 + 18 = 51
so answer will be 51(option 3)

Like? Yes (17) | No (5)  

A.Sivapriya   11 years AGO

sequence is 1+2*(n^2)
so, from the sequence next number is 5
this gives 1+2*25=51

Like? Yes (6) | No (3)  

LOGAN WOLVERINE   11 years AGO

3+6=9;
9+10=19;(6+4=10)
19+14=33;(10+4=14)
next difference number is 14+4=18;
so 33+18=51
option 3

Like? Yes (3) | No   

Sajib Ghosh   11 years AGO

51
x(n)=1+2*(n^2)
x(1)=3;x(2)=9;x(3)=19;x(5)=51

Like? Yes (2) | No   

Rahul gulati   11 years AGO

3 9 19 33 ...
difference is-
6 10 14 ...
difference is-
4 4 4 ...
so it should be :
3 9 19 33 (51)
difference is-
6 10 14 (18)
difference is-
4 4 4 (4)

Like? Yes (2) | No   

Shubham Saxena   11 years AGO

3
9
19
33
51
Difference b/w 9 & 3 is 6
Difference b/w 19 & 9 is 10
Difference b/w 33 & 19 is 14
Difference b/w 51 & 33 is 18
so the difference is 4
Answer is 51

Like? Yes (5) | No (3)  

Gurmeet Singh   11 years AGO

9-3=6
19-9=10
33-19=14
51-33=18

Like? Yes (2) | No   

Arpit Jain   11 years AGO

9-3=6
19-9=10
33-19=14
difference is 4
so 33+18=51
answer (3)

Like? Yes (2) | No   

babita   11 years AGO

common differeces btw each no. are having a common difference of 4.

Like? Yes (2) | No   

Naveen Pandey   11 years AGO

the diff between consecutive numbers are 6,10,14..hence the next increase will be of 18...so the answer will be 33+18=51

Like? Yes (2) | No   

suvradeb kundu   11 years AGO

9-3=6 19-9=10 33-19=14 51-33=18

Like? Yes (2) | No   

Mahak   11 years AGO

there is difference of 4 in dirrerence b/w every successive no.

Like? Yes (2) | No   

prakash kumar   11 years AGO

difference between 3 & 9 = 6
difference between 9 & 19 = 10
difference between 6 & 10 = 4
next no.=10+4+19=33
similarly,14-10=4
4+14+33=51

Like? Yes (2) | No   

adnan   11 years AGO

3+6=9
9+10=19
19+14=33
33+18=51

Like? Yes (2) | No   

P.SWETHA   11 years AGO

9-3=6
19-9=10
33-19=14
and
6+4=10,10+4=14,so 14+4=18
means x-33=18,x=51

Like? Yes (2) | No   

thota anil kumar   11 years AGO

difference+4 is the increment

Like? Yes (2) | No   

upendra singh chahar   11 years AGO

9-3=6
19-9=10
33-19=14
51-33=18
each time difference get increased by 4.

Like? Yes (1) | No   

Payal Prajapati   11 years AGO

+6, +10, +14, +18 = 51

Like? Yes (2) | No (1)  

Shivaraj Karrolla   11 years AGO

bcoz difference in the form of 4,10,14,18,,,,

Like? Yes (1) | No   

R.RAVIKUMAR   11 years AGO

The sequence follows as 1+2*(n^2)
1+2*1=3
1+2*4=9
1+2*9=19
1+2*16=33
1+2*25=51

Like? Yes (2) | No (2)  

ROHIT UPADHYAY   11 years AGO

2*25 + 1

Like? Yes (2) | No (2)  

D.Mamatha   11 years AGO

the given sequence follows that 1+2*(n^2)
where n=1,2,3,4,5...
so, from the sequence next number is 5
this gives
1+2*(5^2)=1+2*25=51

Like? Yes (3) | No (3)  

Aditya Verma   11 years AGO

series 3,9,19,33,...
difference b/w two terms
9-3=6
19-9=10
33-19=14
x-33=18
x=51
next number is 51
option 3

Like? Yes (2) | No (2)  

Balakumaran N.A   11 years AGO

increases by 6,10,14,18,... etc.
33+18 = 51.

Like? Yes (2) | No (2)  

Sunku Mounika   11 years AGO

By the terms itself
3+6=9
9+10=19
19+14=33
So, we can say 33+18=51.
Ans is option 3.

Like? Yes (2) | No (2)  

akhilesh kumar   11 years AGO

in this qstn
9-3=6
19-9=10
33-19=14
51-33=18
so here difference between two number is in order of 4 so the next number is 51
so ans=(3)51

Like? Yes (3) | No (3)  

stutisahoo   11 years AGO

9-3=6
19-9=10
33-19=14
51-33=18
4 difference

Like? Yes (2) | No (2)  

Sneghapriya Ravindran   11 years AGO

Ans: 51
3+6=9
9+10=19
19+14=33
33+18=51

Like? Yes (1) | No (1)  

T.Aravinth kumar   11 years AGO

Given 3, 9, 19, 33..
Take difference between adjacent number s
6, 10, 14,...
Take difference between adjacent numbers
4, 4,...
Then answer=4+14=18.
18+33=51...

Like? Yes (2) | No (2)  

RAKESH ROSHAN   11 years AGO

3 9 19 33
9 - 3 = 6
19 - 9 = 10
33 - 19 = 14
51 - 33 = 18

Like? Yes (2) | No (2)  

Arati Sethi   11 years AGO

the difference of consecutive nos are 6,10,14 so the difference between 4th and 5th no will be 18 so the 5th no is 33+18=51
so Ans:51

Like? Yes (2) | No (2)  

Hemalatha   11 years AGO

3+6=9
9+10=19
19+14=33
33+18=51 so ans 51..

Like? Yes (2) | No (2)  

Narendra Kumar   11 years AGO

3+6=9
9+10=19
19+14=33
33+18=51

Like? Yes (2) | No (2)  

Prabhat Yadav   11 years AGO

+1=51

Like? Yes (2) | No (2)  

Dr.Dipin Singh   11 years AGO

nth term ,Tn is given by 2*n^2 + 1.
T1= 2*1+1=3
T2= 2*2^2+1= 2*4+1=9
..
..
T5= 2*5^2+1= 2*25 +1 =50+1=51 .. option 3.

Like? Yes (4) | No (4)  

sharan kumar    11 years AGO

3,9,19,33,.........
The difference between two consecutive numbers 6,10,14,....
2*3,2*5,2*7,.... so next should be 2*9
that means 33+18=51

Like? Yes (2) | No (2)  

Ankit Goyal   11 years AGO

3
3 + 6
9 + 10
19 + 14
33 + 18 = 51

Like? Yes (2) | No (2)  

haritha   11 years AGO

taking the difference of the consecutive numbers
and again taking the difference between the result we get same number 4.
9-3=6,19-9=10,33-19=14
now
10-6=4,14-10=4
so to get equal difference we add 14+4=18
now add 33+18=51(result)

Like? Yes (2) | No (2)  

THULASIARAVINDH   11 years AGO

1+2(1^2),1+2(2^2),1+2(3^2),....1+2(n^2)

Like? Yes (2) | No (2)  

jagadish   11 years AGO

increase +4
33+14=51

Like? Yes (2) | No (2)  

saranyamanoharan   11 years AGO

each series is added

Like? Yes (2) | No (2)  

Krishna Chaitanya   11 years AGO

Given number series 3,9,19,33 Here difference of their numbers is in AP with common difference=4
9-3=6
19-9=10
33-19=14
so next term in this series is 18 so 18 should be added to 33 to get next term which is 51

Like? Yes (2) | No (2)  

OM PRAKASH JHA   11 years AGO

From the series,
9-3=6
19-9=10
33-19=14
Here the difference between the two consecutive number is in order 6,10,14. thus next will be 18.
hence next number in sequence will be 33+18=51.

Like? Yes (2) | No (2)  

OM PRAKASH JHA   11 years AGO

From the above series,the difference between the two consecutive number is in order 6,10,14.
9-3=6
19-9=10
33-19=14
Thus next difference will be 18 i.e. 51-33=18
Hence next number in sequence will be 33+18=51.

Like? Yes (2) | No (2)  

sandy   11 years AGO

3+6=9
9+10=19
19+14=33
33+18=51

Like? Yes (2) | No (2)  

Keshav Kishlay   11 years AGO

9-3=6
19-9=10
33-19=14
and 10-6=4,14-10=4
so, 14+4=18+33=51

Like? Yes (2) | No (2)  

Priya Dharshini   11 years AGO

the difference between 3and 9 is 6;
the difference between 9 and 19 is 10;
the difference between 19 and 33 is 14;
now see all the diffences are increased by 4;
so 14+4=18;
33+18=51;

Like? Yes (2) | No (2)  

Ganesh Hembram   11 years AGO

ans is \"51\" difference btw 3 and 9 is 6 and the difference btw 19 and 9 is 10 but in every difference we add 4 in differences like 6+4=10 then the nxt value after 9 is 19 and the difference btw 19 and 33 is 14 i.e 10+4=14 likewise add 4 in nxt difference i.e 14+4=18 and the nxt value is \"51\" and the difference btw 33 and 51 is 18.

Like? Yes (2) | No (2)  

Sweta Rahangdale   11 years AGO

there is a diffrence of 4

Like? Yes (2) | No (2)  

Jhansi   11 years AGO

9-3 is 6
19-9 is 10
33-19 is 14

Now 6,10,14

where we can observe as 6,6➕4,6➕4➕4

And 33➕6➕4➕4➕4 is 51

Like? Yes (2) | No (2)  

susmit   11 years AGO

f(x) = 2x^2+1
When x = 1, f(x) = 3
When x = 2, f(x) = 9
When x = 3, f(x) = 19
When x = 4, f(x) = 33
So,
When x = 5, f(x) = 51
Hence,
The next number will be 51
option no.(3)

Like? Yes (1) | No (2)  

Rajasekhar Reddy   11 years AGO

the sequence follows as
1+2*n^2
where n = 1,2,3,4,5,.......
for n = 5
it is 51

Like? Yes (2) | No (3)  

Jigyasa Kumar   11 years AGO

the rule followed is :
3 [+6] 9 [+10] 19 [+14] 33 [+18] 51 [+22] 73
and so on

Like? Yes (1) | No (2)  

siddhanta kumar Behera   11 years AGO

the sequence is 3,9,19,33,....
let the 5th no. be x
now,
9-3=6=3^2
19-9=10=5^2
33-19=14=7^2
so the nextresult must be 9^2=18
x-33=18
=>x=33+18=51...........ANS
so,option 3 is correct

Like? Yes (1) | No (2)  

Aarush Singh   11 years AGO

3 [+6] 9 [+10] 19 [+14] 33 [+18] 51 [+22] 73
and so on

Like? Yes (2) | No (3)  

siddagalla bhaskar   11 years AGO

1+2(n^2)
where n=1,2,3,4,5,...

Like? Yes (1) | No (2)  

satyen nabar   11 years AGO

Difference between number increasing by 4. Difference of 6, 10, 14,..
33+18 =51

Like? Yes (1) | No (2)  

TAREK HAYDER SK   11 years AGO

9-3=6=3*2;19-9=10=5*2;33-19=14=7*2
then next difference will be 9*2=18
so next no is 33+18=51

Like? Yes (1) | No (2)  

P Niranjan   11 years AGO

the series added by 6+4*i (i=0,1,...)
3+(6+4*0) = 9

9+(6+4*1) = 19

19+(6+4*2) = 33

33+(6+4*3) = 51

Like? Yes (1) | No (2)  

mahima srivastava   11 years AGO

series is 3, 9 , 19, 33
taking difference of consecutive terms
9-3=6
19-9=10
33-19=14
6,10,14,18 (difference of 4)
so,
33+18=51

Like? Yes (1) | No (2)  

Pratiksha Gupta   11 years AGO

3
9
19
33
51
Difference b/w 9 & 3 is 6
Difference b/w 19 & 9 is 10
Difference b/w 33 & 19 is 14
Difference b/w 51 & 33 is 18
so the difference is 4
Answer is 51

Like? Yes (1) | No (2)  

Shubham Saxena   11 years AGO

3
9
19
33
51
Difference b/w 9 & 3 is 6
Difference b/w 19 & 9 is 10
Difference b/w 33 & 19 is 14
Difference b/w 51 & 33 is 18
so the difference is 4
Answer is 51

Like? Yes (1) | No (2)  

pankaj chandra joshi   11 years AGO

gap is incrsd by 4 so 14+4=18
33+18=51

Like? Yes (1) | No (2)  

vartika mishra   11 years AGO

if we look at the series we get
3+6=9;
6+10=19;
19+14=33;
there is a difference of 4 when we add it;
so next number will be 14+4=18;
thus,next number will be;
33+18=51;
hence 51 is the next number.

Like? Yes (1) | No (2)  

Leelanand Kumar Yalla   11 years AGO

3,9 the difference is 6.
9,19 the difference is 10.
19,33 the difference is 14; here every time +4 is added to first difference. so, now the difference should be 18; that means 51.......

Like? Yes (1) | No (2)  

Praveen kumar   11 years AGO

3 + 6 = 9
9 + 10 = 19 (6+4=10)
19 + 14 = 33 (10+4=14)
33 + 18 = 51 (14+4=18)

Here the difference between the two consecutive number is increasing by 4 so 33+18=51

Like? Yes (1) | No (2)  

Dinesh thatti   11 years AGO

in the above series difference between numbers
are as follows 9-3=6,19-9=10,33-19=14
if we carefully see the results are 6,10,14 so next difference result would be 18 we add 18+33 we get 51

Like? Yes (1) | No (2)  

Hitesh Kulkarni   11 years AGO

3+6=9 9+10=19 19+14=33
Addition of 4 in sequecnce of sum
i.e 3 to 9 (6) 9 to 19 (6+4)
19 to 33(6+4+4) and 33 to 51(6+4+4+4)

Like? Yes (1) | No (2)  

g.soujanya   11 years AGO

3 9 19 33 51
6 10 14 18 //first diff
4 4 4 //second diff

Like? Yes (1) | No (2)  

muthu   11 years AGO

33+18=51

Like? Yes (1) | No (2)  

DHIRENDRA    11 years AGO

given
3,9,19,33,.......
3------------------------3
3+6----------------------9
9+6+4--------------------19
19+6+4+4-----------------33
33+6+4+4+4---------------51

Like? Yes (1) | No (2)  

Nikhil Prathapani   11 years AGO

9-3 = 6
19-9 = 10
33-19 = 14
The difference series is 6,10,14,18
so next number is 33+18 =51.

Like? Yes (1) | No (2)  

thol   11 years AGO

4 is added to every difference

Like? Yes (1) | No (2)  

Surya Narayana K   11 years AGO

Difference between two successive are 6(9-3),10(19-10),14(33-19).
So next number is 33+18 =51

Like? Yes (1) | No (2)  

Mridhula   11 years AGO

the diff btw d consecutive nos is 6,6+4,6+8.hence next term\' diff is 6+12=18.HENCE 33+18=51

Like? Yes (1) | No (2)  

Paras   11 years AGO

3,9,19,33
the difference is 6,10,14,18
add 18+33=51

Like? Yes (2) | No (3)  

Siba Kumar Sahu   11 years AGO

Ans: 51
the difference two consecutive no is increase by 4.
the difference of 1st and 2nd no= 6
the difference of 2nd and 3rd no= 10
the difference of 3rd and 4th no= 14
so the the difference of 4th and 5th no will be 18
there fore the next no will be 33+18=51

Like? Yes (1) | No (2)  

ANSHUL KUMAR   11 years AGO

3 9 19 33 51
6 10 14 18
4 4 4
0 0

Like? Yes (2) | No (3)  

AMIT JAISWAL   11 years AGO

since , 9-3=6
19-9=10
33-19=14

here the difference of the next and previous terms in increasing by 4 each time so next term wiil be 33+18 = 51 answer

Like? Yes (2) | No (3)  

vishal shanker polowalia   11 years AGO

x(n)=1+2(n^2). Here x(1)=3,x(2)=9 and so on

Like? Yes (1) | No (3)  

vishesh thakur singh   11 years AGO

Diff b/w 3 and 9 =6
Diff b/w 9 and 19 =10
Diff b/w 19 and 33 =14
So 33+18=51

Like? Yes (1) | No (3)  

pavithra   11 years AGO

3,9,19,33...
diff between 3&9-->6,9&19-->10,19&33-->14...
their resultant differs by 4.. i.e 6,10,14..
therefore next could be 18 .. if added with 33+18 we get 51 as the answer

Like? Yes (1) | No (3)  

amit bhagat   11 years AGO

since , 9-3=6
19-9=10
33-19=14

here the difference of the next and previous terms in increasing by 4 each time so next term wiil be 33+18 = 51 answer

Like? Yes (1) | No (3)  

julee verma   11 years AGO

since 9-3=6
19-9=10(6+4)
33-19=14(10+4)
so next number will be 33+18=51

Like? Yes (1) | No (3)  

Anucia Mary A   11 years AGO

difference between 3 and 9 is 6
difference between 9 and 19 is 10
difference between 19 and 33 is 14
difference between 6 and 10 is 4
likewise will be others
so
the next number should be 33+18=51

Like? Yes (2) | No (4)  

27 Dec 2013 Coded language

If ten numbers are chased in a coded language by the following numbers given below then what will be next number in that coded language
3,3,5,4,4,3,5,5,4,3,.....

OPtion

1) 2
2) 3
3) 4
4) 5
5) 6
6) 7
7) 8
8) 9
9) 12
10)None of these

Solution

One = 3 (total 3 alphabet)
two = 3
three = 5
four = 4
five = 4
six = 3
seven = 5
eight = 5
nine = 4
ten = 3
Similarly
eleven = 6

option 5)

Correct Option: 5 Best Solution (20)

Akanksha Mishra   11 years AGO

LOOK Upon the series carefully
3,3,5,4,4,3,5,5,4,3,.....

3,3,5...4...4,3,5...5...4,3,--

3+3+5...4...4+3+5...5...4+3+--

11 ...4... 12 ...5...13

4+3+-- = 13
7 +-- = 13
next number in that coded language will be 6(option 5)

Like? Yes (36) | No (9)  

Dr.Dipin Singh   11 years AGO

Number of letters in 'ONE' =3

Number of letters in 'TWO' =3

..
.
Number of letters in 'ELEVEN' =6

Like? Yes (11) | No (1)  

Shubham Saxena   11 years AGO

one=3
two=3
three=5
four=4
five=4
six=3
seven=5
eight=5
nine=4
ten=3
eleven=6
etc

Like? Yes (5) | No (3)  

ROHIT UPADHYAY   11 years AGO

3, 3, 5, 4, 4, 3, 5, 5, 4, 3, 6, 6, 8, 8,

Like? Yes (4) | No (2)  

Siba Kumar Sahu   11 years AGO

one-3 letters
two-3 letters
three-5 letters
so similarly after ten-3
the next term will be eleven=6

Like? Yes (2) | No   

Arati Sethi   11 years AGO

one=3 letter
two=3 letters
three=5 letters so on
ten=3 letters
after that 11 will come
so eleven=6 letters
so ans. is option 5.

Like? Yes (2) | No   

pranitha karnati   11 years AGO

given code: 3,3,5,4,4,3,5,5,4,3
the encoded answer is no. of letters in numbers from 1, i.e, one - 3 letters
two - 3
three - 5
four - 4
five - 4
six - 3
seven - 5
eight - 5
nine - 4
ten - 3
so, next number is : eleven - 6
answer is : 6

Like? Yes (9) | No (8)  

Shubham Saxena   11 years AGO

one=3
two=3
three=5
four=4
five=4
six=3
seven=5
eight=5
nine=4
ten=3
eleven=6
etc

Like? Yes (2) | No (1)  

vinoth kumar   11 years AGO

one-3
two-3
.
.
.
eleven-6

Like? Yes (1) | No   

Subham Mahanta   11 years AGO

The following numbers are,
3,3,5,4,4,3,5,5,4,3,......
Here, one = 3 letters = 3
two = 3 " = 3
three = 5 " = 5
four = 4 " = 4
five = 4 " = 4
six = 3 " = 3
seven = 5 " = 5
eight = 5 " = 5
nine = 4 " = 4
ten = 3 " = 3
so, the next number is = 6
hence, eleven = 6 letters = 6
ANS:- OPTION - (5)

Like? Yes (1) | No   

Aashu   11 years AGO

one = 3
two = 3
three = 5
four = 4
five = 5
six = 3
seven = 5
eight = 5
nine = 4
ten = 3
similarly
eleven = 6 (total no of alphabets)

Like? Yes (1) | No   

T.Aravinth kumar   11 years AGO

One-3
Two-3
.
.
.
Ten-3
Eleven-6.

Like? Yes (2) | No (1)  

Udhaya kumar   11 years AGO

one = 3
two = 3
three = 5
four = 4
.
.
.
.
.
ten = 3
eleven = 6.............

Like? Yes (2) | No (1)  

Devendra Marghade   11 years AGO

Numbers of letters are counted in the spelling of 1,2,3,....
[One=3],[Two=3],[Three=5],[Four=4],[Five=4],[Six=3],
[Seven=5],[Eight=5],[Nine=4],[Ten=3],[Eleven=6]

Like? Yes (2) | No (2)  

Pratiksha Gupta   11 years AGO

one=3
two=3
three=5
four=4
five=4
six=3
seven=5
eight=5
nine=4
ten=3
eleven=6
etc

Like? Yes (2) | No (2)  

SONU GUPTA   11 years AGO

one=3
two=3
three=5
four=4
five=4
six=3
seven=5
eight=5
nine=4
ten=3
so the next number
eleven=6

Like? Yes (1) | No (1)  

SHIVANI PRAKASH   11 years AGO

one=3
two=3
three=5
.
.
.
.
ten=3.
similarly next number 11 =6.

Like? Yes (1) | No (1)  

Er. SIBA KUMAR   11 years AGO

eleven --> 6 letters
so ans is 6

Like? Yes (1) | No (1)  

KRISHNAN   11 years AGO

The number of characters in the spelling of the number.
Like 1 is one so 3
2 is two so 3
,...11 is eleven so 6

Like? Yes (1) | No (2)  

Pradyumna K S   11 years AGO

see above answers

Like? Yes (2) | No (4)  

26 Dec 2013 Solve

How many words (meaningful or meaningless) can be formed by using the letters of the word HOTSPOT taking 4 letters at a time.

OPtion

1) 175
2) 235
3) 5040
4) 120
5) 144
6) 270
7) 72
8) 198
9) 840
10) 210

Solution

Total number of different letters = 5 ( H, O, T, S, P )
Number of Words having all the letters different = 5*4*3*2 = 120
Total number of repeated letters = 2 ( O, T )
If one letter is repeated then number of words = 2*(4*3/2)*(4*3*2*1/2) = 144
If two repeated letters are used then number of words = 6
Total number of words = 120 + 144 + 6 = 270

Correct Option: 6 Best Solution (2)

mahima srivastava   11 years AGO

(5c4*4!)+(2(4c2*4!/2!))+(4!/(2!*2!))=270

Like? Yes (7) | No (5)  

susmit   11 years AGO

there are following possibilities.
no. of o's : 0 0 1 1 1 2 2 2
no. of t's : 1 2 0 1 2 0 1 2
no. of ways: 24 36 24 72 36 36 36 6 : total =270
option no.6

Like? Yes (2) | No (3)  

25 Dec 2013 Find total property

A man divides his property between 3 children in such a way that Mohan gets 50% of the total property. Gaurav gets fifth part of the remaining property. If Hemant gets 1 lacs 50 thousand rupee, then the total property is

OPtion

1) 340000 Rs
2) 288000 Rs
3) 192000 Rs
4) 375000 Rs
5) 168000 Rs
6) 320000 Rs
7) 480000 Rs
8) 400000 Rs
9) 80000 Rs
10)None of these

Solution

Total property = 100 %
Part of Mohan = 50%
Part of Gaurav = 50%/5 = 10%
Part of Hemant = 40%
Given Part of Hemant = 150000
40% = 150000
Then total property = 150000*100/40 = 375000 Rs

option 4)

Correct Option: 4 Best Solution (43)

Suresh   11 years AGO

Mohan = 50%
Gaurav = 10%
Hemant = 40% = 1,50,000

So, total property = 100% = 3,75,000 (option 4)

Like? Yes (10) | No (7)  

Udhaya kumar   11 years AGO

Gaurav gets 150000 / 4 = 37500
Gaurav + Hemant = 150000+37500 = 187500
Total = 187500 * 2 = 375000.....

Like? Yes (6) | No (4)  

Ashutosh Nilesh Ujwala Patkar   11 years AGO

let total property be 'x'
mohan got 50%, and gaurav got 1/5th of remaining
therefore gaurav got 10% .
therefore remaining property is 40% hemant got 150000 ,so 40% =150000 so 100% = 100/40*150000=375000

Like? Yes (1) | No   

vishnupriya   11 years AGO

let total money be 'x'.
mohan got x/2.
gaurav got (x/2)/5.
given that hemanth got 1,50,000
so,by this 4*(x/2)/5=1,50,000.
i.e., 2x/5=1,50,000
x=3,75,000

Like? Yes (1) | No   

Gurmeet Singh   11 years AGO

As per given statement
X/2 + X/10 + 150000=X

Solving this
X=375000

Like? Yes (1) | No   

mahima srivastava   11 years AGO

x=(x/2)+(4x/10)+(x/10)
4x/10=150000
x=375000

Like? Yes (3) | No (2)  

LOGAN WOLVERINE   11 years AGO

total=x;
mohan=50%x;
gauvrav=(x-50%x)1/5;
hemant=150000;
total=mohan+gaurav+hemant;
x=50%x+(x-50%x)1/5+150000;
solve this equation we get x value

x=375000
total property value is 375000 rs.

Like? Yes (1) | No   

ramakrishna   11 years AGO

=>total property=100%
=>mohan gets=50%
=>in remaining 50% ,gaurav gets fifth part i.e 10%
=>so hemant gets 40%
=>40%=150000 =>1%=3750
there fore 100%=375000

Like? Yes (1) | No   

sukhman singh   11 years AGO

hemant get 40%=150000
80%=150000+150000=300000
20%=150000/2=75000
100%=375000

Like? Yes (1) | No   

Mayuri Rangari   11 years AGO

let total property x
amount to Mohan = 50%x = 0.5x
amount to Gaurav = 1/5 * 0.5x = 0.1x
amount to Hemant = 150000
hence we get a/c to info
0.5x + 0.1x + 150000 = x
By solving we get
x = 375000

Like? Yes (1) | No   

Abhishek kumar singh   11 years AGO

Let x be total rupees,then mohan get x/2.
gorav get 1/5(x/2),
hemant get x/2-1/5(x/2)=4x/10.
4x/10=150000
x=375000

Like? Yes (1) | No   

Akanksha Mishra   11 years AGO

Let The Total Property Is x;

Mohan gets 50% of the total property = x/100 * 50
= x/2 part
remaining property = x/2 part

Gaurav gets fifth part of the remaining property
= x/2 * 1/5
= x/10 part

Hemant gets = 1,50,000 Rs

According to the question;

Mohan gets + Gaurav gets + Hemant gets = x
x/2 + x/10 + 1,50,000 = x

5x + x + 15,00000 = 10x
6x + 15,00000 = 10x
4x = 15,00000
x = 15,00000/4
x = 375000 Rs

the total property is 375000 Rs

I hope My solution will easy to understand !!

Like? Yes (4) | No (4)  

amit bhagat   11 years AGO

let the total property be x.
then, according to question mohan gets 50% of x = x/2.
and gaurav gets 1/5 of (x-x/2) = x/10
hemant gets 1,50,000

so on summing up we get = x/2+x/10+ 150000 = x
x = Rs 375000

Like? Yes (4) | No (4)  

pankaj chandra joshi   11 years AGO

totel=z
mohan=z/2=reamaning propty
gaurv=z/10
left=4z/10=150000
z=375000

Like? Yes (2) | No (2)  

vartika mishra   11 years AGO

let the total money be x;
amt that mohan gets=x-x/2;=x/2;
amt that gaurav gets=(1/5)*(x/2);
remaining amount=(x/2)-(x/10);=4x/10;
according to the question, (4x/10)=1,50,000;
therefore x=3,75,000

Like? Yes (2) | No (2)  

AMIT JAISWAL   11 years AGO

since,

x/2 + x/10 + 150000 = x
6x/10 + 150000 = x
x-6x/10 = 150000
4x = 150000 * 10
x = 375000

Like? Yes (2) | No (3)  

Siba Kumar Sahu   11 years AGO

ans: 375000
let the total property=10x
then according to question
mohan gets=5x
gaurav gets=0.2(10x-5x)=0.2(5x)=x
now hemant gets=10x-5x-x=4x=rs 150000
so total property=(150000/4x)*10x=rs 375000
so the ans is 375000 Rs

Like? Yes (2) | No (3)  

T.Aravinth kumar   11 years AGO

hemant-150000.
gaurav-5th part of remaining property=150000/4=37500.
mohan-50%=150000+37500=187500.
total property=187500*2=375000.

Like? Yes (1) | No (2)  

DHIRENDRA    11 years AGO

let total property=x
mohan gets 50% i.e=x/2
mohan gets fifth part of remaining property i.e
=(x/2)*1/5
=x/10
hement gets 1 lacs 50 thousand i.e
x/2-x/10=1,50,000
5x-x/10=1,50,000
4x/10=1,50,000
2x/5=1,50,000
x=1,50,000*5/2
x=3,75,000

Like? Yes (1) | No (2)  

SK FARID   11 years AGO

let x be the total amount among which mohan gets 50%of x i.e;x/2 and with rest 50% amount gaurav gets x/10
so,x=x/2+x/10+150000
solving above we would get x=375000

Like? Yes (1) | No (2)  

satyen nabar   11 years AGO

4/5 th of remaining is 150000. so gaurav gets 37500. half the property is 187500. total value is 375000

Like? Yes (1) | No (2)  

alanbala   11 years AGO

.5x+(0.5x/5)+150000=x

375000

Like? Yes (2) | No (3)  

navneet shankhwar   11 years AGO

the eq of the quetion is
x=x/2+x/10+150000
where x is total property
on solving the eq x=375000

Like? Yes (2) | No (3)  

Jigyasa Kumar   11 years AGO

Answer = 3,75,000
let the total property be x
0.5x+1/5(0.5x)+1,50,000 = x
so, x = 3,75,000

Like? Yes (1) | No (3)  

jayabharathy   11 years AGO

lets take thr total property be X
mohan gets 50% of totat property then remaining 50% of X
gaurav gets fifth part of remaining prop that is 1/5 of 50%X
then the remaining for hemant 4/5 of 50%X=150000
X=150000*100/50*5/4
X=375000 i.e total property 375000

Like? Yes (1) | No (3)  

VENKATESAN A   11 years AGO

Mohan = 50%
goutham = 10 %
hemant = 40% (remaining )
= 1,50,000
if
40% = 1,50,000
then 100% = 3,75,000

Like? Yes (1) | No (3)  

KRISHNAN   11 years AGO

Mohan gets 50% 0f the property
Gourav gets 1/5 of the remaining i.e 10%
so hemants gets 40% of the property which is 1lac 50 thousand
so 100% of the property is 150000/100*40 or 375000

Like? Yes (1) | No (3)  

Parthiban C   11 years AGO

(150000*100)/40=375000

Like? Yes (1) | No (3)  

Yapadinne Raju   11 years AGO

total property=x
mohan=50% of x=x/2
gaurav=(1/5)of x/2=x/10
hemant gets remaining means
remaining property=(x/2)-(x/10)=2x/5
2x/5=1,50,000
x=3,75,000

Like? Yes (1) | No (3)  

thol   11 years AGO

total amount = (1.5*10)/4

Like? Yes (1) | No (3)  

sharath   11 years AGO

if mohan gets 50%
then remaining 50%
remaining 50% gurav gets 1/5 =10%
hemant is 40%=150000
total is 100%=?
(100/40)*150000=375000

Like? Yes (1) | No (3)  

sandy   11 years AGO

4/5(1/2x)=150000
x=375000

Like? Yes (1) | No (3)  

vinoth kumar   11 years AGO

M-50%
REMAINING-50%
G-10% FROM 50%
H-40%(150000)
TOTAL=40%+40%+20%=
150000+150000+75000=375000

Like? Yes (1) | No (3)  

Amit   11 years AGO

x is total property. x/2 to mohan. 1/5 of (x/2)=x/10 to gaurav.and remaining to hemant.
sum of all is x=(x/2)+(x/10)+150000. solving above we get. x=375000.

Like? Yes (1) | No (3)  

susmit   11 years AGO

Mohan gets 50%
So, remaining is 50 %
So, Guarav gets (1/5)*50 = 10%
So, Hemant gets (100-50-10)% = 40%
Now, 40% = 150000
So, total property is 100% = 100*150000/40 = 375000
Hence, option no. (4)

Like? Yes (1) | No (4)  

VIKASH RAY   11 years AGO

Let,the total property be x.
Then,mohan gets (50% of x)=x/2
gaurav gets (1/5)(x-x/2)=x/10
& hemant gets Rs.1,50,000/-
Then,
according to problem,
(x/2)+(x/10)+(1,50,000)=x
or, 4x=1500000
or, x=375000.
hence,option 4 is correct.

Like? Yes (2) | No (5)  

Narendra   11 years AGO

Let x be the total propert
x/2 + (x/2)*1/5 + 150000=x;
x=375000

Like? Yes (1) | No (4)  

TAREK HAYDER SK   11 years AGO

mohan gets=x/2; gaurav gets =x/2*5=x/10;so hemant gets =4x/10=150000;then x=375000

Like? Yes (1) | No (4)  

Aarush Singh   11 years AGO

let the total property be x
0.5x+1/5(0.5x)+1,50,000 = x
so, x = 3,75,000

Like? Yes (1) | No (4)  

piyush   11 years AGO

let x be the total amount.
mohan gets 1/2 of x.
gaurav gets 1/5th of 1/2 of x,which is equal to 1/10 of x.
therefore hemanth gets 1- (1/2 + 1/10)= 4/10 of x.
hemanth gets 150000.
4/10 *x = 150000
x=375000 rs.

Like? Yes (1) | No (4)  

madhu Kiran   11 years AGO

40% of total property is 150000
Then total property is (150000*100)/40=375000

Like? Yes (1) | No (4)  

Math Lovers   11 years AGO

let total property = x
mohan got = x*50/100 = x/2
remaining property = x - x/2 = x/2
Gaurav got = (x/2)*(1/5) = x/10
hemant got = x/2 - x/10 = 4x/10 = 150000
=> x = 375000

Like? Yes (1) | No (4)  

vishal shanker polowalia   11 years AGO

let property be x
mohan has (x/2)
gaurav has (1/5) of x/2
hemant has 4/5 of x/2
(4/5)*(x/2) = 150000
after solving we get x = 375000

Like? Yes (1) | No (4)  

24 Dec 2013 Solve

The thickness of a paper is 0.8 mm. Number of papers in a rim of thickness 29.6 cm. are

OPtion

1) 38
2) 2060
3) 22060
4) 206
5) 380
6) 3800
7) 370
8) 1862
9) 450
10) None of these

Solution

29.6 cm. = 296 mm.

Hence number of pages = 296/.8 = 370

Correct Option: 7 Best Solution (63)

Akanksha Mishra   11 years AGO

1 cm = 10 mm
29.6 cm = 296 mm
The thickness of a paper is 0.8 mm
Number of papers in a rim of thickness 29.6 cm. are
= 296/0.8
= 370 sheets

Like? Yes (9) | No (4)  

VINAYKUMAR MR   11 years AGO

Given data...

Thickness of one paper = 0.8mm = 0.08cm

Thickness of rim = 29.6cm

Number of papers = (1/0.08)*29.6

= 370 papers.

So Option 7 is correct

Like? Yes (4) | No (2)  

Lavankumar Reddy   11 years AGO

1 cm = 10 mm
29.6 cm = 296 mm
then 296/0.8 = 370 papers

Like? Yes (2) | No   

Naeem Ahamad   11 years AGO

29.6*10/.8=370

Like? Yes (2) | No   

Udhaya kumar   11 years AGO

29.6 cm = 296 mm
296 / 0.8 = 370.....

Like? Yes (4) | No (3)  

Ashutosh Nilesh Ujwala Patkar   11 years AGO

mm and cm are different quantities
hence both should be converted into one quantity.
hence 29.6 cm shuld be converted into 296mm as 1cm=10mm
thickness of group of papers/thickness of one paper=number of papers 296/0.8=370
ans is 370

Like? Yes (1) | No   

eeranna   11 years AGO

29.6*10^-2/(.8*10^-3) ===370

Like? Yes (1) | No   

Sneghapriya Ravindran   11 years AGO

Ans: 370

thickness of a paper = 0.8/10 cm=0.08cm
nos of papers=29.6/0.08=370 papers

Like? Yes (1) | No   

mithila gayatri   11 years AGO

0.8 * x=29.6 * 10
1cm=10 mm

x=370

Like? Yes (1) | No   

chalamalasetti   11 years AGO

total thickness 296 mm so 1 paper 0.8.. 296/0.8=370

Like? Yes (1) | No   

Gurmeet Singh   11 years AGO

rim of thickness=29.6 cm= 296 mm
therfore no. of pages= 296/0.8=370

Like? Yes (1) | No   

saravana7989@gmail.com   11 years AGO

370*.8----29.6 cm

Like? Yes (1) | No   

Subham Mahanta   11 years AGO

Let, x is number of paper in a rim of thickness 29.6 cm.
Here, the thickness of a paper is 0.8 mm = 0.08 cm
so, the thickness of x paper is = 0.08x cm
s0, we get the equation is,
0.08x = 29.6
=> x = 29.6/0.08
=> x = 370
So,the number of papers in a rim of thickness 29.6 cm.are 370.

Like? Yes (1) | No   

DHIRENDRA    11 years AGO

1 cm =10 mm
total page=2960/8
=370

Like? Yes (1) | No   

rupireddy bharath kumar   11 years AGO

29.6*10/0.8

Like? Yes (1) | No   

abc   11 years AGO

29.6cm = 296mm
& 296/0.8=370

Like? Yes (1) | No   

achyuth   11 years AGO

1 millimeter=0.1 centimeter
0.8mm=0.8*10^-1
number of papers =(29.6*10)/0.8
ans=370

Like? Yes (1) | No   

T.Aravinth kumar   11 years AGO

Thickness of the rim=29.6cm=296mm.
Thickness of the paper=0.8mm.
No of papers=296/0.8=370.

Like? Yes (2) | No (1)  

Aditya Verma   11 years AGO

total thickness of a rim=29.6cm=296mm
then numbers of papers=296/0.8=370
answer is option 7

Like? Yes (1) | No   

ramakrishna   11 years AGO

1cm=10mm =>o.8mm=0.08cm
1page=o.08cm
?=29.6cm
=>(29.6/0.08)*1=370pages

Like? Yes (1) | No   

babita   11 years AGO

let d no. of papers be x
so, 0.8x/10 = 29.6
hence, x= 29.6*100/8
x= 370

Like? Yes (1) | No   

vishal shanker polowalia   11 years AGO

The thickness of paper is 0.8mm = 0.08cm
the thickness of rim is 29.6cm
Number of paper = 29.6/0.08 =2960/8 = 370

Like? Yes (1) | No   

adnan   11 years AGO

simple 1 paper=.8mm=.08cm
1cm=1/.08=12.5
29.6cm=12.5*29.6=370

Like? Yes (1) | No   

shreya sagar   11 years AGO

29.6cm/0.8mm=296mm/0.8mm=370

Like? Yes (1) | No   

Rachna   11 years AGO

according to the question
thickness of rim=29.6
thickness of a paper=0.8
number of papers=29.6/0.8=370

Like? Yes (1) | No   

mahima srivastava   11 years AGO

(29.6*10)/0.8= 370 papers

Like? Yes (1) | No   

P vannursab   11 years AGO

29.6*10^-2/0.8*10^-3=2960=8=370

Like? Yes (1) | No   

Parthiban C   11 years AGO

2960/8=370

Like? Yes (2) | No (1)  

Sukanya   11 years AGO

29.6cm = 296 mm.
296/0.8=370.
So there are will be 370 papers.

Like? Yes (1) | No   

Priya Dharshini   11 years AGO

first convert 29.6 cm into 296 mm.
then 296/0.8=370 papers.

Like? Yes (1) | No   

Krishna Chaitanya   11 years AGO

1 paper-0.8mm
1cm=10mm
therefore 29.6cm=296mm

1 paper thickness is 0.8mm,296mm requires (296/0.8)=370 papers

Like? Yes (1) | No   

Dhinakaran   11 years AGO

1cm=10mm;
29.6cm=296mm;

1 paper=0.8mm;
296/0.8=370 papers

Like? Yes (2) | No (1)  

mohini gupta   11 years AGO

29.6/.8=37
37*10=370

Like? Yes (3) | No (2)  

Siba Kumar Sahu   11 years AGO

ans: 370
Given,
thickness of a paper=0.8 mm
thickness of papers in the rim = 29.6 cm=296 mm
so, the total nos of paper in the rim = 296/0.8=370

Like? Yes (2) | No (2)  

swastik   11 years AGO

(29.6*10)/0.8=370

Like? Yes (1) | No (1)  

KRISHNAN   11 years AGO

1 mm = .1cm or 0.8mm = 0.08 cm

So the number of papers in a rim of 29.6 cm is
29.6/0.08 or 370

Like? Yes (1) | No (1)  

susmit   11 years AGO

29.6 cm = 296 mm
so ans= 296/0.8= 370
option no. 7

Like? Yes (1) | No (1)  

A.Sivapriya   11 years AGO

Paper thickness = 0.8mm = 0.08 cm

Rim thickness = 29.6 cm

So, no. of papers in a rim = (29.6/0.08) = 370

the option is 7.

Like? Yes (1) | No (1)  

D.Mamatha   11 years AGO

Given data...

Thickness of one paper = 0.8mm = 0.08cm

Thickness of rim = 29.6cm

Number of papers = (1/0.08)*29.6

= 370 papers.

So Option 7 is correct

Like? Yes (2) | No (2)  

VIKASH RAY   11 years AGO

thickness of paper is-0.8 mm
thickness of rim is-29.6cm
so,the number of paper is-(29.6cm)/(0.8mm)
=370.

Like? Yes (1) | No (1)  

R.RAVIKUMAR   11 years AGO

thickness of rim is 29.6cm=296mm
no.of papers need with thickness 0.8mm is
296/0.8=370

Like? Yes (1) | No (1)  

P Niranjan   11 years AGO

Given thickness of the page is 0.8 mm

thickness of total number of papers is 29.6cm

i.e, 296 mm

So the number of pages in the rim is

296/0.8 = 370

So there are 370 pages in the rim.........

Like? Yes (1) | No (1)  

TAREK HAYDER SK   11 years AGO

29.6cm=296mm;296/.8=370

Like? Yes (1) | No (1)  

Abhijeet Kumar   11 years AGO

29.6 cm = 29.6*10 = 296 mm
296/0.8 = 370 number of pages.

Like? Yes (2) | No (2)  

Shubham Saxena   11 years AGO

we know that 29.6 cm =296 mm
Hence 296/0.8
=370 Ans

Like? Yes (1) | No (1)  

Leelanand Kumar Yalla   11 years AGO

Here, Each Paper Thickness is 0.8 Millie meter;
in centimeters it is 0.08;
Rim thickness is 29.6 cm;
Therefore 29.6/0.08=370 papers..
cross check.. 370*0.08 cm= 29.6 cm; This is the answer.......

Like? Yes (1) | No (1)  

Keshav Kishlay   11 years AGO

we know that 1cm=10mm
so,29.6cm=296mm
so,in 296mm rim there is 296/0.8 paper of thickness 0.8 will adjust
so,370 pieces

Like? Yes (1) | No (1)  

Shubham Saxena   11 years AGO

we know that 29.6 cm =296 mm
Hence 296/0.8
=370 Ans

Like? Yes (1) | No (1)  

Ankit Goyal   11 years AGO

(29.6*10)/0.8

= 3700

Like? Yes (1) | No (1)  

Arati Sethi   11 years AGO

thickness of paper=0.8 mm
thickness of the rim = 29.6 cm=296 mm
so, the total nos of paper in the rim = 296/0.8=370

Like? Yes (1) | No (1)  

Dinesh thatti   11 years AGO

to convert cm to mm multiply with 10

29.6*10/0.8=370

Like? Yes (1) | No (1)  

Er. SIBA KUMAR   11 years AGO

ans is 370
we have,
thickness of one paper=0.8 mm=0.0008m
thickness of papers in the rim = 29.6 cm=0.296 m
so, the total nos of paper in the rim = 0.296/0.0008=370

Like? Yes (1) | No (1)  

Narendra   11 years AGO

29.6 cm= 296 mm;
0.8-->1
296-->?
296/0.8=370
Ans is 370(option 7)

Like? Yes (1) | No (1)  

THULASIARAVINDH   11 years AGO

29.6*10=296
296/.8=370

Like? Yes (1) | No (1)  

shubha   11 years AGO

29.6/0.08=370

Like? Yes (1) | No (1)  

satyen nabar   11 years AGO

296/0.8= 370

Like? Yes (1) | No (1)  

Satyendra Singh   11 years AGO

1 paper thickness is 0.8 mm
a rim with n number of papers thickness will be
n * 0.8 mm = 29.6 cm
n = 29.6 * 10 / 0.8 = 370

Like? Yes (1) | No (1)  

AMIT JAISWAL   11 years AGO

since thickness of rim = 29.6 cm
converting it in mm = 296.0 mm
so, no of papers in rim = 296.0/0.8 = 370

Like? Yes (1) | No (1)  

amit bhagat   11 years AGO

since thickness of rim = 29.6 cm
converting it in mm = 296.0 mm
so, no of papers in rim = 296.0/0.8 = 370

Like? Yes (1) | No (1)  

asam srinivasa kumar   11 years AGO

(29.6*10)/0.8=370

Like? Yes (1) | No (1)  

ponprakash   11 years AGO

0.8/10=0.08cm
0.08/29.6cm=370 papers

Like? Yes (1) | No (1)  

Anantharaman   11 years AGO

29.6 cm = 296 mm

296/0.8 = 370

Answer Option 7

Like? Yes (1) | No (1)  

deepak srivastava   11 years AGO

2960/8

Like? Yes (1) | No (1)  

23 Dec 2013 Sequence

What is the next number of the following sequence
122,486,1092,1940,..........

OPtion

1) 3025
2) 2936
3) 3096
4) 3030
5) 4050
6) 3265
7) 4356
8) 4362
9) 1189
10)None of these

Solution

1+11^2 = 1+121 = 122
2+22^2 = 2+484 = 486
3+33^2 = 3+1089 = 1092
4+44^2 = 4+1936 = 1940
Similarly
5+55^2 = 5+3025 = 3030

Correct Option: 4 Best Solution (80)

Akanksha Mishra   11 years AGO

look upon the series carefully
122,486,1092,1940.....

First Method :
(11*11*1^2) + 1 = 122
(11*11*2^2) + 2 = 364
(11*11*3^2) + 3 = 1092
(11*11*4^2) + 4 = 1940
So next no. will be;
(11*11*5^2) + 5 = 3030

Another Method:
486 - 122 = 364
1092- 486 = 606
1940-1092 = 848

606-364 = 242, 848 - 606 = 242
therefore
848 + 242 = 1090
1090+ 1940= 3030
so answer will be option (4)

I hope my answer will easy to understand

Like? Yes (24) | No (9)  

Udhaya kumar   11 years AGO

11 * 11 + 1 = 122
22 * 22 + 2 = 486
33 * 33 + 3 = 1092
44 * 44 + 4 = 1940
similarly
55 * 55 + 5 = 3030........

Like? Yes (7) | No (4)  

mayank   11 years AGO

122= (11)2+1
486=(22)2+2
1092=(33)2+3
1940=(44)2+4
next is
3030=(55)2+5

Like? Yes (4) | No (1)  

T.Aravinth kumar   11 years AGO

given
122, 486, 1092, 1940.....
take difference between adjacent numbers
346, 606, 848....----(1)
take difference once more
242, 242, .....---(2)
SO add 242 with 848---> 242+848=1090.
THEN 1090 + 1940=3030.
ans(4).

Like? Yes (3) | No (1)  

Rahul gulati   11 years AGO

122,486,1092,1940,...(3030)
difference:
364,606,848,...(1090)
Difference:
242,242,...,(242)

Like? Yes (2) | No   

Amit kumar   11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1092
44^2+4=1940
55^2+5=3030

Like? Yes (4) | No (2)  

Sajib Ghosh   11 years AGO

486=122*4-2=(122)*(2^2)-(2*1)
1092=122*9-6=(122)*(3^2)-(3*2)
1940=122*16-12=(122)*(4^2)-(4*3)

now the next term will be
(122)*(5^2)-(5*4)=122*25-20=3050-20=3030
so, option 4 is correct

Like? Yes (2) | No (1)  

TAREK HAYDER SK   11 years AGO

difference between two numbers are increasing by 242. e. g. (486-122)=364;(1092-486)=606;[606-364]=242;(1940-1092)=848;[848-606]=242;
so,848+242=1090 then next term is 1940+1090=3030

Like? Yes (3) | No (2)  

M.ANAND   11 years AGO

11^2+1 = 122
22^2+2 = 486
33^2+3 = 1092
44^2+4 = 1940
next
55^2+5 = 3030

Like? Yes (1) | No   

krishna   11 years AGO

given that 122,486,1092,1940,..
==>122*1^2 = 122 - 1*0 = 122
==>122*2^2 = 488 - 2*1 = 486
==>122*3^2 = 1098 - 3*2 = 1092
==>122*4^2 = 1952 - 4*3 = 1940
==>122*5^2 = 3050 - 5*4 = 3030
==>122*6^3 = 4392 - 6*5 = 4362
so series is 122,486,1092,1940,3030,4362 .....

Like? Yes (2) | No (1)  

eeranna   11 years AGO

(11^2)+1=122
(22^2)+2=386
(33^2)+3=1092
(44^2)+4=1940
(55^2)+5=3030

Like? Yes (2) | No (1)  

Amit pandit   11 years AGO

squre root of every number is in the sequense of 11.045,22.045,33.045,44.045 and the option 4 has 55.045

Like? Yes (2) | No (1)  

Roushan Singh   11 years AGO

11*11 = 121+1 = 122
22*22 = 484+2 = 486
33*33 = 1089+3 = 1092
44*44 = 1936+4 = 1940
similarly,
55*55 = 3025+5 = 3030

Hence ans is 4)3030

Like? Yes (3) | No (2)  

Pradyumna K S   11 years AGO

121n^2 + n.
121(1)^2+1=121
121(2)^2+2=486
121(3)^2+3=1092
121(4)^2+4=1940
121(5)^2+5=3030

Like? Yes (2) | No (1)  

muthu   11 years AGO

(122*5^2)-5*4=3030

Like? Yes (1) | No   

swastik   11 years AGO

it is a series of 121*n^2+n
so 121*1^2+1=122
121*2^2+2=486
121*3^2+3=1092
121*4^2+4=1940
121*5^2+5=3030

Like? Yes (1) | No   

Ashfaque Hussain   11 years AGO

11*11+1=122 , 22*22+2=486 , 33*33+3=1092 , 44*44+4=1940 , 55*55+5=3030

Like? Yes (1) | No   

chandana   11 years AGO

The numbers in the series are of the form (121*n^2)+n.
(121*1^2)+1=122(first number)
(121*2^2)+2=486(second number)
(121*3^2)+3=1092(third number)
(121*4^2)+4=1940(fourth number)
(121*5^2)+5=3030(fifth number).
so my answer is 3030(option 4)

Like? Yes (1) | No   

ABHISHEK KUMAR   11 years AGO

122=11*11+1
486=11*44+2 44-11=33
1092=11*99+3 99-44=55
1940=11*176+4 176-99=77
now 176+99=275
therefore
next number=11*275+5=3030

Like? Yes (1) | No   

pratibha Tiwari    11 years AGO

divide all the numbers of series by 2 to simplify the series
on dividing,We will get 61,243,546 and 970
Now 243-61=182
546-243=303
970-546=424 nw if we see the difference between obtained no.s it is equal like 303-182=121&424-303=121
Nw if we add 121 next to 424 we get 424+121=545 nw add 970+545=1515 we got the no. Of series. We mouble the number 1515*2=3030..we got actual no.of series,.

Like? Yes (1) | No   

srivatsan v   11 years AGO

the difference for each number is increased by 242 when you subtract 1940 from 3030 you will get 1090 which is increased by 242 from the previous difference

Like? Yes (1) | No   

pratik jitendra malviya   11 years AGO

11*11+1=122
22*22+2=486
33*33+3=1092
44*44+4=1940
55*55+5=3030

Like? Yes (1) | No   

g.soujanya   11 years AGO

122 486 1092 1940 3030
364 606 848 1090
242 242 242

Like? Yes (1) | No   

sai sirish   11 years AGO

486-122=364
1092-486=606=364+242
1940-1092=848=606+242
next=1940+848+242=3030

Like? Yes (1) | No   

Gunaseelan   11 years AGO

Given 121 = (11*11)+1
486 = (22*22)+2
1092 = (33*33)+3
1940 = (44*44)+4
Thus Answer is 3030 = (55*55)+5

Like? Yes (2) | No (1)  

Priya Dharshini   11 years AGO

first get the difference between 486 and 122,then get difference between 1092 and 486,then similarly for 1940 and 1092.the differences are 364,606,848 again the difference between 364 and 606 is 242.and similarly the difference between 848 and 606 is 242.so obviosly the next number in the sequence we can get by adding 848 and 242 so that we get 1090.finally 1940+1090=3030.

Like? Yes (1) | No   

Aditya Verma   11 years AGO

series 122,486,1092,1940
differences series 364,606,848...
diff of diff series 242,242,....
848+242=1090
next term = 1940+1090= 3030
answer is option 4

Like? Yes (1) | No   

RagunathKC   11 years AGO

(121)(x^2)+x
if x=1 then 121+1=122
if x=2 -> 121*4+2=486
if x=3 -> 121*9+3=1092
if x=4 -> 121*16+4=3030

Like? Yes (1) | No   

sivaraman   11 years AGO

122-486=364, 486-1092=606, 1092-1940=848
so
364,606,848 the common difference of this number is 242
so
add 242+848=1090
1090+1940=3030

Like? Yes (1) | No   

Anilkumar   11 years AGO

121*1+1=122
121*4+2=486
121*9+3=1092
121*16+4=1940
121*25+5=3030

Like? Yes (1) | No   

Prakash kumar   11 years AGO

11^2+1
22^2+2
------
55^2+5 = 3030

Like? Yes (1) | No   

navneet shankhwar   11 years AGO

by the sequence 242 is the difference of the difference of the given number
therefor, 242+848=1090
1090+1940=3030

Like? Yes (1) | No   

kishan kumar   11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1096
44^2+4=1940
55^2+5=3030

Like? Yes (1) | No   

VIKASH RAY   11 years AGO

the general formula of this series is- 121n^2 + n.
we have to find the fifth term in this series, so n=5.
by putting n=5 in the general formula we get 3030.
hence,option 4 is correct.

Like? Yes (1) | No   

SHRISH SHUKLA   11 years AGO

11*11+1 , 22*22+2 , 33*33+3.....so on..
answer
3030

Like? Yes (1) | No   

thol   11 years AGO

the difference btween each difference is 242.,by adding it to the next number we get 3030...

Like? Yes (1) | No   

asam srinivasa kumar   11 years AGO

(121*n^2) + n where n=1,2,3,....
n=5--->(121*5^2)+5=3030

Like? Yes (2) | No (2)  

Narendra   11 years AGO

121n^2 + n.

Like? Yes (1) | No (1)  

vishal shanker polowalia   11 years AGO

The reason is 121(n^2)+n
when n = 1
122

when n = 2
486

when n = 3
1092
when n = 4
1940
when n = 5
3030

Like? Yes (1) | No (1)  

Jigyasa Kumar   11 years AGO

its following the sequence 121 n^2 +n
so the next no. will be 3030

Like? Yes (1) | No (1)  

Leelanand Kumar Yalla   11 years AGO

Here 122= 121*1+1=122;
486=121*4+2=486;
1092=121*9+3=1092;
1940=121*16+4=1940;
similarly.....
Next 121*25+5=3030.....
This is the Answer.....

Like? Yes (2) | No (2)  

Shubham Saxena   11 years AGO

The Given series is 122,486,1092,1940,..........
486-122=364
1092-486=606
1940-1092=848
The difference of 606 & 364 and 848 & 606= 242
So by considering the difference of 242
Next no. will be 3030
as, 3030-1940=1090
which again 1090-848=242
Hence Answer is 3030

Like? Yes (2) | No (2)  

D.Mamatha   11 years AGO

The given sequence is 122,486,1092,1904,....

(121*1^2) + 1 = 122

(121*2^2) + 2 = 486

(121*3^2) + 3 = 1092

(121*4^2) + 4 = 1940

Similarly......

(121*5^2) + 5 = 3030

So the option 4 is correct.

Like? Yes (2) | No (2)  

susmit   11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1092
44^2+4=1940
so answer is 55^2+5=3030
option no.4

Like? Yes (1) | No (1)  

Rajasekhar Reddy   11 years AGO

the sequence is follows as
121*(n^2) + n
where n = 1,2,3,4,5,.......
for n = 5
121*25 + 5 = 3030

Like? Yes (1) | No (1)  

Ankit Goyal   11 years AGO

11^2 + 1 = 122
22^2 + 2 = 486
33^2 + 3 = 1092
44^2 + 4 = 1940
55^2 + 5 = 3030 (Answer)

Like? Yes (1) | No (1)  

Aarush Singh   11 years AGO

121n^2 + n

Like? Yes (1) | No (1)  

Pratiksha Gupta   11 years AGO

The Given series is 122,486,1092,1940,..........
486-122=364
1092-486=606
1940-1092=848
The difference of 606 & 364 and 848 & 606= 242
So by considering the difference of 242
Next no. will be 3030
as, 3030-1940=1090
which again 1090-848=242
Hence Answer is 3030

Like? Yes (2) | No (2)  

R.RAVIKUMAR   11 years AGO

(122*4)-2=486
(122*9)-6=1092
(122*16)-12=1940
(122*25)-20=3030

Like? Yes (2) | No (2)  

kumar sundram   11 years AGO

here,
(11*1)^2+1=121
(11*2)^2+2=486
(11*3)^2+3=1092
(11*4)^2+4=1940
so, next no. is
(11*5)^2+5=3030

Like? Yes (1) | No (1)  

Shubham Saxena   11 years AGO

The Given series is 122,486,1092,1940,..........
486-122=364
1092-486=606
1940-1092=848
The difference of 606 & 364 and 848 & 606= 242
So by considering the difference of 242
Next no. will be 3030
as, 3030-1940=1090
which again 1090-848=242
Hence Answer is 3030

Like? Yes (1) | No (1)  

Siba Kumar Sahu   11 years AGO

ans: 3030
because the terms are in the series as
122
122*2^2-2*1 =486
122*3^2-3*2 =1092
122*4^2-4*3 =1940
so the next term will be
122*5^2-5*4=3030

Like? Yes (1) | No (1)  

satyen nabar   11 years AGO

The difference between numbers is 364, 606, 848. the difference is increasing by 242. Hence 848+242=1090. 1940+1090=3030.

Like? Yes (1) | No (1)  

rupireddy bharath kumar   11 years AGO

(11)^2+1=122
(22)^2+2=486
(33)^2+3=1092
(44)^2+4=1940
(55)^2+5=3030

Like? Yes (1) | No (1)  

KRISHNAN   11 years AGO

The series is formed by 121*n^2+1
so 121+1^2+1 =122
121+2^2+2 =486
121+3^2+3 = 1092
121+4^2+4 = 1940
121+5^2+5 = 3030

Like? Yes (1) | No (1)  

Arati Sethi   11 years AGO

we have the nos 122,486,1092,1940 so looking at the nos we can write the nos as
122
122*4-2*1 =486
122*9-3*2 =1092
122*16-4*3 =1940
so according to the series the next no must be
122*25-5*4=3030

Like? Yes (1) | No (1)  

P Niranjan   11 years AGO

series in the form of
121*n^2+n

n starts with 1
so, 121*5^2+5 = 3030

Like? Yes (1) | No (1)  

Sukanya   11 years AGO

122 486 1092 1940 3030

364 606 848 1090

242 242 242
Hence there is a common difference of 242 for each increase.

Like? Yes (1) | No (1)  

Dinesh thatti   11 years AGO

11^2=121+1=122,
22^2=484+2=486,
33^2=1089+3=1092,
44^2=1936+4=1940,
55^2=3025+5=3030

Like? Yes (1) | No (1)  

YUVAN SATHAIAH   11 years AGO

11*11+1=122
22*22+2=486
33*33+3=1092
44*44+4=1940
then
55*55+5=3030
option is 4)3030

Like? Yes (1) | No (1)  

SONU GUPTA   11 years AGO

122,486,1092,1940,?
so
11*11=121+1=122
22*22=484+2=486
33*33=1089+3=1092
44*44=1936+4=1940
55*55=3025+5=3030
so answer will be 3030

Like? Yes (1) | No (1)  

Harshit Daga   11 years AGO

The difference is
364, 606, 848, y(difference between the next number of the series and 1940)

Assume that next number should be x
means x = 1940+y

now if you see that the difference series gives the difference as 242, 242, 242
which means y = 848+242
y=1090

and therefore,
x=1940+y
x=3030

Like? Yes (1) | No (1)  

JAYANTHI K   11 years AGO

(11^2)+1=122
(22^2)+2=486
(33^2)+3=1092
(44^2)+4=1940
similarly
(55^2)+5=3030

Like? Yes (1) | No (1)  

SanthoshKumar   11 years AGO

(11*11)+1 =122
(22*22)+2 =486
(33*33)+3 =1092
(44*44)+4 =1940
(55*55)+5 =3030(answer)

Like? Yes (1) | No (1)  

jaya prakash reddy   11 years AGO

sequence of n numbers : 121n^2+n

Like? Yes (1) | No (1)  

Dr.Dipin Singh   11 years AGO

nth tgerm is given by
(11n)^2+n
1st term=(11*1)^2+1=122
..
..
5th term = (11*5)^2+5= 55^2+5= 3025+5=3030

Like? Yes (2) | No (2)  

Abhijeet Kumar   11 years AGO

general form :(121*n^2)+n
(121*1^2)+1=(121*1)+1=122
(121*2^2)+2=(121*4)+2=486
(121*3^2)+1=(121*9)+3=1092
(121*4^2)+2=(121*16)+4=1940
(121*5^2)+1=(121*25)+5=3030...Ans

Like? Yes (2) | No (2)  

VINAYKUMAR MR   11 years AGO

(x2 * n) + n
X= 11 n= 1,2,3,4,5,6..........
(121 * 1) + 1 = (121 * 1) + 1 =122
Similarly (11^2 * 5^2)+5
(121 * 25)+5 =3030

Like? Yes (2) | No (2)  

Keshav Kishlay   11 years AGO

486-122=364,
1092-486=606,
1940-1092=848 and
606-364=242,
848-606=242 so,
similarly 848+242=1090 and 1940+1090=3030

Like? Yes (1) | No (1)  

pankaj chandra joshi   11 years AGO

11^2+1,22^2+2...............55^2+5

Like? Yes (1) | No (1)  

achyuth   11 years AGO

11*11+1=122
22*22+2=486
33*33+3=1092
44*44+4=1940
the next number..
55*55+5=3030
ans;3030

Like? Yes (1) | No (1)  

AMIT JAISWAL   11 years AGO

here 486-122=364
1092-486=606 (364+242)
1940-1092=848(606+242)
x-1940=848+242
x=1940+1090
x=3030

Like? Yes (1) | No (1)  

amit bhagat   11 years AGO

here 486-122=364
1092-486=606 (364+242)
1940-1092=848(606+242)
x-1940=848+242
x=1940+1090
x=3030

Like? Yes (1) | No (1)  

Krishna Chaitanya   11 years AGO

The number's difference is in AP with common difference 242,
486-122=364
1092-486=606
1940-1092=848
now the numbers 364,606,848 are in AP with d=242 therefore we need to add 242 to 848 so that we get 1090 now we should add 1090 to 1940 to get next number which is 3030.

Like? Yes (1) | No (1)  

Nivetha   11 years AGO

The series follows the sequence 121n^2+n
121(1^1)+1=122
121(2^2)+2=486
121(3^2)+3=1092
121(4^2)+4=1940
121(5^2)+5=3030

Like? Yes (1) | No (1)  

kiran kumar reddy yanamala   11 years AGO

11*11+1,22*22+2,33*33+3,44*44+4,55*55+5,.....

Like? Yes (1) | No (1)  

julee verma   11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1092
44^2+4=1940
55^2+5=3030

Like? Yes (1) | No (1)  

A.Sivapriya   11 years AGO

Given Sequence is 122,486,1092,1940

122 = (121 X 1^2)+1
486 = (121 X 2^2)+2
1092 = (121 X 3^2)+3
1940 = (121 X 4^2)+4

Like wise the next number is (121 X 5^2)+5 = 3030
So, the option is 4.

Like? Yes (2) | No (3)  

J.Arun kumar   11 years AGO

(11*11)+1=122
(22*22)+2=486
(33*33)+3=1092
(44*44)+4=1940
(55*55)+5=3030

Like? Yes (1) | No (2)  

Meenakshi   11 years AGO

122*4=488-2=486
122*9=1098-6=1092
122*16=1952-12=1940
122*25=3050-20=3030

Like? Yes (1) | No (2)  

20 Dec 2013 Coded Language

If in a coded language
ABHISHEK = -23
HEMANT = -9
NEHA = 10
Then
ASHU = ?

OPtion

1) -8
2) 12
3) -14
4) -18
5) 6
6) 9
7) 16
8) -28
9) 0
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
ABHISHEK = (A+B+H+I)-(S+H+E+K) = (1+2+8+9)-(19+8+5+11) = 20-43 = -23
HEMANT = (H+E+M)-(A+N+T) = (8+5+13)-(1+14+20) = 26-35 = -9
NEHA = (N+E)-(H+A) = (14+5)-(8+1) = 19-9 = 10
Similarly
ASHU = (A+S)-(H+U) = (1+19)-(8+21) = 20-29 = -9

Option 10) None of these

Correct Option: 10 Best Solution (43)

Udhaya kumar   11 years AGO

Let A=1 ,B=2 ,.....Z=26 respectively......
Subtract second half of the word from first word..
ABHISHEK ;; ABHI - SHEK
(1+2+8+9)-(19+8+5+11) = 20-43 = -23
SIMILARLY ;; ASHU : AS - HU
(1+19)-(8+21)= -9 ..
SO Ans is (-9)..........

Like? Yes (28) | No (23)  

Shubham Saxena   11 years AGO

ABHISHEK = -23
HEMANT = -9
NEHA = 10
On taking the difference of first half and second half of the words, we are getting the value.
So here
ASHU=1+19+8+21
1+19=20
8+21=29
hence 20-29=-9 Ans

Like? Yes (4) | No (1)  

Pratiksha Gupta   11 years AGO

ABHISHEK = -23
HEMANT = -9
NEHA = 10
On taking the difference of first half and second half of the words, we are getting the value.
So here
ASHU=1+19+8+21
1+19=20
8+21=29
hence 20-29=-9 Ans

Like? Yes (5) | No (2)  

sujata   11 years AGO

Mark each alpha according to their alphabetical arrangement/order i.e

A=1
B=2
C=3
D=4
E=5 and so on

consider HEMANT
H=8
E=5
M=13
A=1
N=14
T=20

Divide it into 2 parts HEM and ANT
(8+5+13)-(1+14+20)
=26-35
=-9

Similarly for NEHA
NE and HA
(14+5)-(8+1)
=19-9
=10

So ASHU will be
AS and HU
(1+19)-(8+21)
=20-29
-9

Like? Yes (2) | No   

Shubham Saxena   11 years AGO

ABHISHEK = -23
HEMANT = -9
NEHA = 10
On taking the difference of first half and second half of the words, we are getting the value.
So here
ASHU=1+19+8+21
1+19=20
8+21=29
hence 20-29=-9 Ans

Like? Yes (2) | No   

pranitha karnati   11 years AGO

ABHI | SHEK --> (A+B+H+I)-(S+H+E+K)
=> (1+2+8+9)-(19+8+5+11)
=> 20-43= -23
HEM | ANT --> (H+E+M)-(A+N+T)
=> (8+5+13)-(1+14+20)
=> 26-35= -9
NE | HA --> (N+E)-(H+A)
=> (14+5)-(8+1)
=> 19-9 = 10
hence, ASHU=
AS | HU = (A+S)-(H+U)
=> (1+19)-(8+21)
=> 20-29= -9
SO , answer is -9
option : 10) none of these

Like? Yes (9) | No (7)  

Darsana K   11 years AGO

assign the alphabets numbers from 1-26
divide the word in 2 halfs
add the numbers assigned to each half and then find the difference between halfs
ABHISHEK divided into ABHI and SHEK
ABHI - SHEK=(1+2+8+9) -(19+8+5+11)=-23
HEM - ANT =(8+5+13)-(1+14+20)=-9
NE - HA=(14+5)-(8+1)=10
AS - HU=(1+19) - (8+21)=-9
therefore ans is option 10

Like? Yes (2) | No   

YUVAN SATHAIAH   11 years AGO

A(1),B(2),C(3),D(4),E(5),F(6),G(7),H(8),I(9),J(10),K(11),L(12),M(13),N(14),O(15),P(16),Q(17),R(18),S(19),T(20),U(21),V(22),W(23),X(24),Y(25),Z(26)

Every name separated equal after using addition and subtraction,

ABHISHEK=(A+B+H+I)-(S+H+E+K)
=(1+2+8+9)-(19+8+5+11)
=20-43
=-23
HEMANT=(H+E+M)-(A+N+T)
=(8+5+13)-(1+14+20)
=26-35
=-9
NEHA=(N+E)-(H+A)
=(14+5)-(8+1)
=19-9
=10
Then
ASHU=(A+S)-(H+U)
=(1+19)-(8+21)
=20-29
=-9
Answer is:-9
Option 10)none of these

Like? Yes (3) | No (1)  

T.Aravinth kumar   11 years AGO

Ashu=As - hu ...
--->
(1 + 19 )- ( 8 + 21) = -9..

Like? Yes (3) | No (1)  

OM PRAKASH JHA   11 years AGO

WE GROUP THE NAME IN 2 PAIRS AND SOLVE AS DONE HERE....
(A+B+H+I)-(S+H+E+K)=(1+2+8+9)-(19+8+5+11)=-23
(H+E+M)-(A+N+T)=(8+5+13)-(1+14+20)=-9
(N+E)-(H+A)=(14+5)-(8+1)=10
(A+S)-(H+U)=(1+19)-(8+21)=-9
HENCE ANSWER IS 10)NON OF THESE...

Like? Yes (3) | No (1)  

OM PRAKASH JHA   11 years AGO

add the alphabetic order of all letter and solve in groups as done here
(A+B+H+I)-(S+H+E+K)=(1+2+8+9)-(19+8+5+11)=-23
(H+E+M)-(A+N+T)=(8+5+13)-(1+14+20)=-9
(N+E)-(H+A)=(14+5)-(8+1)=10
(A+S)-(H+U)=(1+19)-(8+21)=-9

Like? Yes (2) | No   

Rajasekhar Reddy   11 years AGO

let A-1,B-2,..............Z-26
ABHISHEK = ABHI-SHEK
HEMANT = HEM-ANT
NEHA = (N+E)-(H+A) = 19-9 = 10
similarly,
ASHU = (A+S)-(H+U) = 20-29 = -9

Like? Yes (2) | No (1)  

R.RAVIKUMAR   11 years AGO

the coded language follows that subtraction of first half of the letters from last half of the letter as assigning number to alphabeticals.

so,ASHU gives 1 19 8 21
by coded language (1+19)-(8+21)=-9

Like? Yes (2) | No (1)  

Bupathikavya   11 years AGO

sum of first half-sum of second half is the answer so ashu ==>(a+s)-(h+u)=20-29=-9

Like? Yes (1) | No   

A.Sivapriya   11 years AGO

Given coded language

ABHISHEK = -23

By Subtracting the last half of the letters from the first half of the letters we get the answer.

1.(A+B+H+I)-(S+H+E+K)= (1+2+8+9)-(19+8+5+11)

= 20-43

= -23

ASHU = (A+S)-(H+U) = (1+19)-(8+21) = 20 - 29 = -9

So, the answer is -9

Option is none of the above

Like? Yes (2) | No (1)  

Vinay Sipani    11 years AGO

ABHIHEK => (A + B + H + I) - (S + H + E + K)
=> (1 + 2 + 8 + 9) - (19 + 8 + 5 + 11)
=> -23

HEMANT => (H + E + M) - (A + N + T)
=> (8 + 5 + 13) - (1 + 14 + 20)
=> -9

similarly,
ASHU => (A + S) - (H + U)
=> (1 + 19) - (8 + 21)
=> -9

10)None of these

Like? Yes (1) | No   

LOGAN WOLVERINE   11 years AGO

as value 20
hu value 29
20-29=-9
option 10

Like? Yes (1) | No   

mohan lal garg   11 years AGO

ABHISHEK=1+2+8+9-19-8-5-11=-23
HEMANT=8+5+13-1-14-20=-9
NEHA=14+5-9-1=10
NOW
ASHU=1+19-8-21=-9
-9 NOT IN OPTION ANS IS
(10)NONE OF THESE

Like? Yes (1) | No   

DHIRENDRA    11 years AGO

Decode the all name withh the no and then divide the name into two parts and then subtrat the second half from first half
ASHU= 1+19-8-21=-9

Like? Yes (1) | No   

Abhinav Sharma   11 years AGO

when we put the alphabetically order no for the ABHISHEK ,and HEMANT,or NEHA .Abhiskek can divide in ABHI-SHEK,HEMANT in HEM-ANT and NEHA in NE-HA so similarly ASHU in AS-HU.Now take the alphabetic no mand sum this no respectively and then substrate.so we get ABHI=20,SHEK=43 ,20-43=-23=ABHISKEH,Similarly HEM=26,ANT=35,26-35=-9=HEMANT,so as take this reason we say AS=20,HU=29,20-29=-9=ASHU.

Like? Yes (2) | No (1)  

Dr.Dipin Singh   11 years AGO

ABHISHEK = -23
Take sum of number values of first 4( half of total) letters and subtract sum of number values of first 4( half of total) letters i.e.
(1+2+8+9)-(19+8+5+11)=-23
..
..
similarly
In ASHU,
Take sum of number values of first 2( half of total) letters and subtract sum of number values of first 2( half of total) letters i.e.
(1+19)-(8+21)=20-29=-9.. option 10.. none of these

Like? Yes (2) | No (1)  

K.ARun   11 years AGO

-9,
Because The sum of the first half of the number
Minus
The sum of the other half of the number,
i.e. by replacing each char (A-Z) by (1-26) Number.

Like? Yes (2) | No (1)  

pavani   11 years AGO

first half letters sum of a word is substracted from the second half letters sum of a word.............
1)Given word(ABHISHEK)
ABHI-SHEK
SUM OF ABHI=20
SUM OF SHEK=43
ABHI-SHEK=20-43
=-23
2)HEMANT
SUM OF HEM=26
SUM OF ANT=35
HEM-ANT=26-35
=-9
3)NIHA
SUM OF NI=19
SUM OF HA=9
NI-HA=19-9
=10
4)ASHU
SUM OF AS=20
SUM OF HU=29
AS-HU=20-29
=-9
so,answer is none of these

Like? Yes (1) | No   

shaswata tripathy   11 years AGO

alphabteical position of A-1 B-2 C-3 ...like this
so if we calculate
the first word
1 2 8 9 19 8 5 11..ABHISHEK
now the sum of the 1st four - Last four
= (1+2+8+9)-(19+8+5+11)
=20 - 43= -23

hemant = 8 5 13 1 14 20
(8+5+13) - (1+14+20)
=26 - 35
= -9
neha 14 5 8 1
= (14 + 5 ) - (8+1)
=19 - 9
=10

now ASHU = 1 , 19 , 8 , 21
(1+19) - (8+21) = - 9
ans - 9

Like? Yes (2) | No (1)  

Anurag Agrawal   11 years AGO

A+S=20
H+U=29
20-29= -9

Like? Yes (1) | No   

mounika   11 years AGO

given is ABHISHEK=-23,then a=1,b=2,h=8,i=9,s=19,h=8,e=5,k=11(this will get by giving the numbers from 1 to 26 to the alphabets from begging)
sum of the(a,b,h,i)-sumof(s,h,e,k)will give the -23
(1+2+8+9)-(19+8+5+11)=20-43=-23
like this way only we get hemant=-9((8+5+13)-(1+14+20)=(26-35)=-9)and neha=10((14+5)-(8+1)=(19)-(9)=10)
so the ASHU is -9 because sum of the (a,s)-sum of the(h,u)=(1+19)-(8+21)=20-29=-9

Like? Yes (1) | No   

javed ahmad   11 years AGO

First of all we arrenge all charecter according to there no position
ABHISHEK=-23
A=1, B=2, H=8, I=9, S=19, H=8, E=5, K=11
Now divide total no of charecter into two equal part
Sum of.first part - sum if second part
1+2+8+9-(19+8+5+11)= -23
HEMANT=-9
8+5+13-(1+14+20)= -9
NEHA = 10
14+5-(8+1))= 10
SIMILARLY
ASHU= -9
1+19-(8+21)= -9
Answer is none of these

Like? Yes (1) | No   

~Sandeep~   11 years AGO

- 9 is the answer

Like? Yes (1) | No   

srinivasan ramesh   11 years AGO

Split the letters in two half and subtract using coded no.

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krishna   11 years AGO

ans is -9
because
i.e if we convert the letters into numbers and then
half of the letters sum - other of the letters sum = ans
example:
ABHISHEK = -23
half of the letters sum = A+B+H+I = 20
other half part sum = S+H+E+K = 43
so total ans is 20-23=43
now
given that:
ASHU = (A+S)- (H+U)
= (1+19) - (8+21)
= 20-29
= -9

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Satyendra Singh   11 years AGO

ABHISHEK - 1+2+8+9-19+8+5+11= -23
HEMANT = 8+5+13-1+14+20 = -9
NEHA = 14+5-8+1=10
ASHU= 1+19-8+21 = -9
NONE OF THESE is as given answer

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Yelda Ramesh   11 years AGO

Give the numbering to a=1,b=2 and so on z=26.
sum of the first half of the letters minus second half of the letters.
ABHI=1+2+8+9=20 & SHEK=19+8+5+11=43
then 20-43=-23

Like the above: AS=1+19=20 & HU=8+21=29
then 20-29= -9;
ans is not there so "None of these" is ans.

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sandy   11 years AGO

1+19-8-21=-9

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Mahesh   11 years AGO

A=1
s=19
H=8
U=21
There fore
A+s-H-u = 1+19-8-21 = -9

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piyush   11 years AGO

divide the string into two parts
convert the alphabets to their corresponding numbers(a=1,b=2....z=26)
add all the numbers in the first part, and same for second part also.
subtract second part from first part,resulting number is the code.
a b h i || s h e k
1 2 8 9 19 8 5 11
sum of first part = 20
sum of second part = 43
first part-second part = 20 - 43 = -23
similarly,
a s || h u
1 19 8 21
sum of first part = 20
sum of second part = 29
first - second = -9
since -9 is not their in options none of these is answer

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sharathkumarp   11 years AGO

ans=-9
Abhishek =1+2+8+9-(19+8+5+11)=-23
similarly others
so ASHU=-9

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mirtunjay verma   11 years AGO

pattern is follow first half num add and subtract by
add second half..
so it will.
A=1,S=19,H=8,U=21..
so (1+19)-(8+21)=-9

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Ankit Goyal   11 years AGO

Get the rank of each letter given in the words above

subtract the sum of position of second half of letters from sum of position of letters in first half

e.g. ABHISHEK
A(1)+B(2)+H(8)+I(9) = 20
S(19)H(8) E(5) K(11) = 43

20 - 43 = -23

likewise for ASHU
A(1)+S(19) = 20
H(8)+U(21) = 29

20 - 29 = -9
which doesn't matches any of the options, hence None of the above options is correct

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Leelanand Kumar Yalla   11 years AGO

Here Divide Each number into equal parts;
ABHI= 1+2+8+9=20;
SHEK= 19+8+5+11=43;
20-43=-23;
HEM= 8+5+13=26;
ANT= 1+14+20=35;
26-35=-9;
NE= 14+5=19;
HA=8+1=9;
19-9=10;
THEN
AS= 1+19=20;
HU= 8+21=29;
20-29= -9;
THEREFORE NONE OF THESE IS ANSWER........

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vishal shanker polowalia   11 years AGO

In abhishek
a-k = 1- 11= -10
b-e = 2 - 5 = -3
h-h = 8 - 8 = 0
i-s = 9 - 19 = -10
The sum of digit is -23
similarly
In hemant
h-t = 8 - 20= - 12
e-n = 5 - 14 = -9
m-a = 13 - 1 = 12
The sum of digit is -9
similarly
In neha
n-a = 14 - 1= 13
e-h = 5 - 8 = -3
The sum of digit is 10

similarly
In ashu
a-u = 1 - 21= -20
s-h = 19 - 8 = 11
The sum of digit is -9

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Keshav Kishlay   11 years AGO

ABHISHEK=-23 So, ABHI-SHEK=(1+2+8+9)-(19+8+5+11)=-23,
HEMANT=-9 So, HEM-ANT=(8+5+13)-(1+14+20)=-9,
NEHA=10 So, NE-HA=(14+5)-(8+1)=10
Hence, ASHU=AS-HU=(1+19)-(8+21)=-9

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julee verma   11 years AGO

FIRSTLY DIVIDE THE WORDS INTO TWO PART THEN TAKE SUM OF POSITION VALUE OF WORDS AND SUBRTRACT FIRST PART FROM SECOND PART,SO
ABHISHEK= (A+B+H+I)-(S+H+E+K)=20-43=-23
HEMANT=(H+E+M)-(A+N+T)=26-35=-9
NEHA=(N+E)-(H+A)=19-9=10
HENCE ASHU=(A+S)-(H+U)=20-29=-9
SO ANSWER =-9

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lovely verma   11 years AGO

break it into two parts and and then add value of words and subtract it so we get-
(ABHI)-(SHEK)=20-43=-23
(HEM)-(ANT)=26-35=-9
(NE)-(HA)=19-9=10
(AS)-(HU)=20-29=-9
SO ANSWER=-9

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