M4maths Previous Puzzles

10 Aug 2016 Profit

If a commission of 10% is given on the list price, the gain is 20%. Find the gain percent, if the commission is increased to 20%.

OPtion

1) 15/2 %
2) 13/2 %
3) 20/3 %
4) 5/2 %
5) 23/3 %
6) 10/3 %
7) 20/7 %
8) 14/3 %
9) 11/4 %
10)None of these

Solution

Let list price = Rs.100. Commission = 10%
=> S.P. = Rs.90, Gain = 20%
=> C.P. Rs. (100/120*90) = Rs.75
New S.P. = Rs.80
New gain % = 5/75*100 = 6 2/3 = 20/3 %

Option 3)

Correct Option: 3 Best Solution (33)

DEVANSH SUBNANI   8 years AGO

CP=100,First SP=120
Now S.P=120,Commission=10%
MP=(100/90)*120=Rs.400/3
MP=400/3 ,Commission=20%
SP=(80/100)*(400/3)=Rss.320/3
Gain%=(320/3)-100=(20/3)%
Option 3)

Like? Yes (9) | No (2)  

madanpal vishwakarma    8 years AGO

let assume that the price shown is rs 100

then after 10 % commission = 100-10 =90

given that after 10 % commission gain is 20 %

if original price is x then

x + 20 % of x =90

x=75 rs

if commission is 20% on showing price then the price is = 100 -20 =80 rs

so gain is rs 5 and original price is rs 75

so 5 = 20/3 % of 75

so option 3 is correct .

Like? Yes (9) | No (2)  

SURAJ BALANI   8 years AGO

Let the marked price MP be X, CP be 100rs thus SP will be 120 since 20% gain...
For 10% commission the MP will be:
SP=X-10%X=>133.33
For 20% commission the profit will be:
133.33-20% of 133.33=106.664
thus profit is 6.664 which is (20/3)approx.

Like? Yes (8) | No (2)  

Rajat Garg   8 years AGO

let Sp = 100 than after commission Sp be (100-10%*100)=90. Let CP =x, Gain 20%
so X+20%of X=90 which is = 75
if commission is 20% than SP (100-20)=80
gain %= (80-75)*100/75
=20/3

Like? Yes (5) | No   

Dr.Dipin Singh   8 years AGO

If CP is Rs 100, In first case , SP= Rs 120,
Listed price= 120*100/90 = Rs 400/3
In 2nd case, SP= 400/3 - 80/3 = Rs. 320/3
Profit = Rs 20/3
so % age profit = 20/3 %

Like? Yes (7) | No (3)  

Guruprasad G   8 years AGO

let retail price =100
s.p=100-10=90
c.p=[100/(100+gain)]*s.p=75
new s.p=100-20=80
gain=s.p-c.p=80-75=5
gain(%)=(gain/c.p)*100=20/3%

Like? Yes (3) | No   

Mukund Manohar   8 years AGO

Let CP = Rs 100.First SP = Rs 120
Now SP = Rs 120 and Commission = 10%
Then,Marked Price = {(100/90)*120} = Rs 400/3
Now,Marked Price = Rs 400/3 and Commission = 20%
So,SP = 80% of 400/3 = Rs 320/3
Gain% = {(320/3)-100} = 20/3 %

Like? Yes (6) | No (4)  

prasad reddy   8 years AGO

Let listed price be x. CP be y.
in first case:
(90/100)x = (120/100)y
Y = 0.75x
In case 2:
Profit % = (sp-cp)/cp × 100
= (80x/100 - y) ×100/y
By putting y = 0.75x in above eq. We get
Profit % = 20/3%

Like? Yes (2) | No   

aligi santoshi   8 years AGO

Let MP=100
After given 10% commission SP=90
Let CP=X
Gain=20%
now
x+20%of x=90;X=75
20%on sp=80
gain=sp-cp=5
%gain=5*100/75=20/3

Like? Yes (1) | No (1)  

Naga   8 years AGO

Let
x= list price
y = cost price
commission = 10x/100
final price = x-10x/100

y+20y/100 = x-10x/100
120yy/100 = 90x/100
12y = 9x
4/3 = x/y
y/x = 3/4 (cost to selling price ratio)
so for example
cost price = 75
sell price = 100
sell price after 20% discount = 80
profit = 5
profit percentage = 5/75*100
=(5*4)/3

Like? Yes (1) | No (1)  

Nitish kesarwani   8 years AGO

Since cp is calculated from above statement CP=75 now p=80-75=5 apply formula p%=p/CP*100 hence 5/75*100=20/3

Like? Yes | No   

saurabh chatterjee   8 years AGO

let list price = 100 so now 100*.90=90 which is the sp
90=1.2*cp so cp equals 75.for the new commission sp is 80 and gain is 80-75=5 so gain percent is 5*100/75=20/3%

Like? Yes | No   

Vidhya Lakshmi   8 years AGO

Let SP be 100 After Commissionof 10% it become 90
SP=CP+Gain% of CP
90=CP=(20% of CP)
90=120CP/100
CP=75
So if commission is 20% then SP=80
Then Gain = SP-CP
Gain = 80-75
Gain is 5
Gain% = gain*100/CP
Gain% = 5*100/75
Gain% is 20/3

Like? Yes | No   

Priyaj   8 years AGO

Suppose mp=100
sp after comm.=90
let cp=x
profit=20%
now,
x+x*20%=90
x=75=cp
20% comm sp=80
profit= (80-75/75)*100%
=20/3%

Like? Yes | No   

Shiv Pandey   8 years AGO

Let the list price be 100. Commision =10, So Selling price = 90. If gain =20% then, Cost Price = 75.
Now, Commision =20%. So, Selling = 80 .
gain % = ( ( 80 - 75 ) / 75 ) * 100 = 20/3%

Like? Yes | No   

yerra anitha   8 years AGO

Ans:3
CP-cost price, MP-market price SP-selling price
let CP=100 and MP=x.
SP=100+20% of 100=120.
10% commision given was given on SP.
SP=X-10% OF X
120=X-10X/100
120=9X/10
9X=1200
X=1200/9
MP=1200/9
IF 20% Commision was given, then
SP=(1200/9)-20% of 1200/9
SP=(1200/9)(1-(20/100))
SP=(1200/9)(80/100)
SP=320/3
Gain=(320/3)-100
=(320-300)/3
=20/3%

Like? Yes | No   

G.S.Kantharao   8 years AGO

Let C.P = Rs.100 and M.P= X
Gain = 20% and Commmisin =10% on M.P
Then S.P= 100 + 20% of 100
S.P = Rs.120 = X - 10% of X
(9X)/10 = Rs.120
X = 1200/9 = 400/3
If commission is 20% then S.P is= X - 20% of X
= (400/3) - (400*20)/(3*100)=(400-80)/3 = 320/3
Gain is = (320/3) -100
= (320 - 300)/3
= 20/3
Hence the right choice is 3.

Like? Yes (2) | No (2)  

sandeep kumar   8 years AGO

Let lp=100 discount=10% cp=x
100×90/100=12x/10
Cp=75
100×80/100=(300+3p)/4
P=20/3

Like? Yes | No   

Jasmine   8 years AGO

List price be 100,then SP=LP-Commission=90,
given gain%=20,so CP= SP*(100/(100+Gain%))=900/12.
Further when commission increased to 20%, new SP=LP-commission=80. Hence the gain=SP- CP=80-900/12=60/12.
Hence gain%=gain/CP*100=20/3.

Like? Yes | No   

Rips Andy   8 years AGO

Let List Price be 100
Then SP = (100-10)/100*100= 90
CP = (100/120)*90=75.
Now, the commission increased to 20%
Therefore, New SPP= (100-20)100*100 = 80
Profit =SPP - CP = 5
Profit % = 5/75*100 = 20/3%. (OPTION 3)

Like? Yes | No   

Aditi Paul   8 years AGO

Let list price= Rs. 100
then commission rs. 90
(sp-cp)/cp*100=20
cp= rs. 75
sp remaning 100, commission =20, remaining price =rs. 80
new gain=5/75*100= 20/3%

Like? Yes | No   

Akshat Mokashi   8 years AGO

let mp=100
sp after giving 10% commission=100-10% of 100=90
let cp=x
gain=20%
now x+20%of x=90
120x/100=90
x=75
if 20% commission is given then sp=80
gain=80-75=5
%gain=5*100/75=20/3%

Like? Yes | No   

Rucha   8 years AGO

cp 100 sp 120
commission 10 % on sp
9x=120000
x=133.33
20% commission on 133.33
we get 106.67
106.67-100
6.67%

Like? Yes | No   

bhaskar   8 years AGO

0.9x-cp=0.2cp --> x=1.2/0.9cp
(0.8*(4/3)-1)*100=20/3

Like? Yes (1) | No (2)  

SANDEEP KUMAR MAHATO   8 years AGO

Let the list price=Rs 100
commission=Rs 10
then S.P.=(100-10)=Rs 90
gain=20%
C.P.=(100/120)*90= Rs 75

new commission=Rs 20
new S.P.=Rs (100-20)=Rs 80
gain=(S.P.-C.P.)=(80-75)=Rs 5

%gain=(5/75)*100 = (20/3) %

Option 3)

Like? Yes | No (1)  

Sandip Das   8 years AGO

let list price is 100 rupee an cost price is x rupee
10% commission on list price (100*90)/100=90
then gain is 20% means (x*120)/100=90
=>x=75
if the commission increased to 20%
then (100*80)/100=80
so the gain percentage is ((80-75)*100)/75
=20/3 (option 3)

Like? Yes | No (1)  

himabindu   8 years AGO

let cost price is 100 and list price is x. gain is 20%
the selling price is 100+20=120.
120=x-10% of x
12000=90x
x=400/3
if commison is increased to 20% then
sp = 400/3-20% of 400/3
sp=400/3-80/3
sp=320/3
gain=320/3-100=20/3

%gain=(20/300 )*100=20/3%

Like? Yes (1) | No (2)  

Sachin Tuli    8 years AGO

MP=100 Dis= 10 Sp=90 20%gain cp=75. Now disc. = 20 % sp = 80 gain is calculated on cp. Which will be 20/3 %

Like? Yes | No (1)  

Dhaval Vekariya   8 years AGO

cp=100 sp=120 now commission 10%
so 120=x-10%x
so 20% commision now.
gain=133.33-20%of 133.33-100
gain=6.666
=20/3

Like? Yes | No (1)  

JAYA TRIPATHI   8 years AGO

let cp = 100 and mp = x gain = 20%
SP=120
commission is 10% on sp
sp = x-10x/100=9x/100
x = 1200/9
if commission incrased to 20%
sp= 1200/9-1200*20/9*100=1200/9-240/9
sp = 960/9
now gain = 960/9-100 = 60/9 = 20/3
gain% = 20/3%

Like? Yes (2) | No (3)  

madhulikadoggala   8 years AGO

As we know that
Gain%={(SP-CP)*100}/CP ---(1)
Where SP=selling price
CP= cost price
==>For first condition i.e 10% commission is subtracted
from SP then we get from eq(1)

==> 20={(SP-10%SP-CP)*100}/CP
==>SP=4/3*CP ----(2)
==>For second condition i.e 20% commission is subtracted
from SP then we get from eq(1)

==>Gain%={(SP-20%SP-CP)*100}/CP
==>Gain%={(4/5*SP-CP)*100}/CP ----(3)
Substituting eq(2) in eq(3) we get

Gain%=20/3%

Like? Yes | No (1)  

Machireddygari Murali mohan reddy   8 years AGO

suppose rs 100 is the prize on the list then 10% commission = rs 10, then the product is sold for rs 90 ( but the seller is still getting a gain of 20% i.e 90 rs =120%, 20%=15 rs, 100% = rs 75(actual cost of the product) ) now if the commission is raised to 20% then the product is sold for rs 80 but still a gain of rs 5 which is 20/3%

Like? Yes | No (2)  

Saumyadipta Sarkar   8 years AGO

actual purchase =100
to gain 20% SP = 120
now 120/- is the 10 % commission price of the list price ,
if list price =x
then x * (1- (10/100)) =120
x= 400/3
now commission is 20%
SP =400/3 *(1-(20/100))
SP = 320/3
profit is = 20/3
percentage gain = 20/3 % ( actual price was 100 taken )

Like? Yes | No (3)  

09 Aug 2016 Bride And Groom

There are 5 eligible Gujarati grooms of which 2 know Bengali and 5 eligible Bengali grooms of which 3 know Gujarati. There are 5 eligible Gujarati and 5 eligible Bengali brides. An eligible bride is agreeable to marry a boy of his community or a boy who knows her language. Grooms have no choice. In how many different ways 10 couples can be formed.

OPtion

1) 16550
2) 14400
3) 12000
4) 120
5) 256920
6) 435680
7) 37200
8) 16340
9) 144000
10)12800

Solution

In 5 eligible Gujarati grooms, 2 know Bengali, remaining 3 should make their pair with Gujarati girls.
No. of methods to make such couple = 5.4.3 = 60
Similarly in 5 eligible Bengali grooms, 3 know Gujarati, remaining 2 should make their pair with Bengali girls.
No. of methods to make such couple = 5.4 = 20
No. of methods to make remaining 5 couple = 5.4.3.2.1 = 120
Hence total no. of methods = 60*20*120 = 144000

Option 9)

Correct Option: 9 Best Solution (11)

G.S.Kantharao   8 years AGO

There are 3 chances
1. 5 brides marry 5grooms
Then the total ways are5!*5!*=120*120=14400
2. 5 Bengali brides can marry 4 Bengalii grooms and 1 Gujarathi groom. Then the number of ways is= 3c1*2c1*5!*5! = 6*14400
3. 5Bengali brides can marry 3Bengali grooms and 2 Gujarathi grooms.
Then the ways are 3c2*2c2*5!*5!= 3*14400
Then the total number of ways= 14400+6*14400+3*14400
=10*14400=144000
Hence the right choice is 9

Like? Yes (5) | No   

SANDEEP KUMAR MAHATO   8 years AGO

There are only 3 cases possible

CASE-1) 5 punjabi brides marry to 5 punjabi grooms and
5 bengali brides marry to 5 bengali grooms

so total cases = 5!*5! = 14400

CASE-2) 5 punjabi brides marry to 4 punjabi & 1 bengali groom

so total cases = 3C1*2C1*5!*5! = 86400

CASE-3) 5 punjabi brides marry to 3 punjabi & 2 bengali grooms

so total cases = 3C2*2C2*5!*5! = 43200

now adding all these 3 cases for formation of 10 couples

14400 + 86400 + 43200 = 144000

option 9)

Like? Yes (1) | No   

KUMARA S K   8 years AGO

5 grooms - 2 knows bengali = 5!/2! = 60
5 grooms bengali - 3 knows gujarati = 5!/3! = 20
all couples = 5! = 120
couples formed = 60*20*120 = 144000

Like? Yes (1) | No   

Shiv Pandey   8 years AGO

3 gujrati groom can make couple only with gujrati brides
So, ways=5*4*3=60
2 bengali groom can make couple only with bengali brides
So, ways=5*4=20
remaining 5 (i.e 2 gujrati and 3 bengali) will make couple in 5*4*3*2*1 ways= 120 ways
So, different ways = 60*20*120 = 144000 ways

Like? Yes (1) | No   

prashant kumar   8 years AGO

first of all we hav 5 groom who are eligible for all the brides so we are left with 3 gujrati who can mary only gujrati bride and 2 bengali who can mary only bengali bride so selection and arrangement fr then will be (5p3)*(5p2) and then other 5 couple arranged among themselves so factorial of 5 so final equation will be (5p3)*(5p2)*fact5=144000

Like? Yes (1) | No   

himabindu   8 years AGO

there are three possible ways

Like? Yes | No   

yerra anitha   8 years AGO

in 5 eligible gujarathi grooms 2know bengali,remaining 3 should make thie r pair with gujarathi girls.
no of methods to make such couple in 5.4.3 ways ie..60 and in same way for Bengali grooms can be arranged in 5p2 ways remaining can be done in 5p5 ways finally 10 couple scan be arranged in =5p3.5p2.5p5=144000

Like? Yes | No   

Rips Andy   8 years AGO

In the Gujrati Grooms knows bengali= 2
Therefore, Gujrati pair= 5*4*3=60
Similarly, in Bengali Grooms knows gujrati = 3
Therefore, Bengali pair= 5*4= 20
No of couples formed= 120
total 10 couples are= 120*20*60= 144000

Like? Yes | No   

sandeep kumar   8 years AGO

In 5 eligible Gujarati grooms, 2 know Bengali, remaining 3 should make their pair with Gujarati girls.
No. of methods to make such couple = 5.4.3 = 60
Similarly in 5 eligible Bengali grooms, 3 know Gujarati, remaining 2 should make their pair with Bengali girls.
No. of methods to make such couple = 5.4 = 20
No. of methods to make remaining 5 couple = 5.4.3.2.1 = 120
Hence total no. of methods = 60*20*120 = 144000

Like? Yes | No   

Mukund Manohar   8 years AGO

In 5 eligible Gujarati grooms,2 know bengali,remaining 3 should make their pair with Gujarati girls
No. of methods to make such couple = 5*4*3 = 60
Similarly in 5 eligible Bengali grooms,3 know gujarati,remaining 2 should make their pair with Bengali girls
No. of methods to make such couple = 5*4 = 20
No. of methods to make remaining 5 couple
= 5*4*3*2*1
=120
Total number of methods = 60*20*120 = 144000

Like? Yes | No (1)  

Vaishali   8 years AGO

By using permutations and combinations
(5c5*5c5)+(5c......

Like? Yes | No (3)  

08 Aug 2016 Sequence

What is ?
46, 58, 74, 26, 18, 41, 53, 69, 21, ?

OPtion

1) 36
2) 63
3) 48
4) 81
5) 60
6) 13
7) 31
8) 64
9) 16
10)None of these

Solution

46, 58, 74, 26, 18, 41, 53, 69, 21, ?
(46, 58, 74, 26, 18) (41, 53, 69, 21, 13)

2nd group is 5 less than 1st so x = 18-5 = 13

Option 6)

Correct Option: 6 Best Solution (70)

G.S.Kantharao   8 years AGO

46,58,74,26,18, (46-5),(58-5),(74-5),(26-5),(18-5)
Hence the answer is 13.
Right option is 6.

Like? Yes (2) | No   

SANDEEP KUMAR MAHATO   8 years AGO

by subtracting each numbers in succession from its predecessor in the given number series from left to right

58-46 = 12

74-58 = 16

26-74 = -48

18-26= -8

41-18 = 23

53-41 = 12

69-53 = 16

21-69 = -48

so the next term 'x' in the series will be

x-21 = -8

or x = 13

hence option(6) will be the answer

Like? Yes | No   

Vaishali   8 years AGO

observe the series
The difference is as follows
12,16,-48,-8,-23,12,16
Similarly 21-8=13 hence option 6is correct

Like? Yes | No   

Jaikumar Bhatia   8 years AGO

There are two sets of 5 numbers,
[46,58,74,26,18] & [41,53,69,21,?]
In 1st set
46+12=58
58+16=74
74-48=26
26-08=18
so in same pattern
2nd set
41+12=53
53+16=69
69-48=21
21-08=13
so ans is 13
option is (6)

Like? Yes | No   

Anup Sahay   8 years AGO

the difference between numbers repeats after 41,follow that and get the answer

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Vishnu Prakash   8 years AGO

The consecutive increase or decrease in first five numbers is repeated.So, as 26-18=8, 21-8=13

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Chitrala Venkatesh Babu   8 years AGO

58-46= 12 53-41= 12
74-58= 16 69-53= 16
26-74= -48 21-69= -48
18-26= -8 ?-21= -8
?=13

Like? Yes | No   

atchaya bala   8 years AGO

Because the difference between 26 and 18 was 8,in the above series 21 and x claims the same variation as my thought

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MINAKSHI DUBEY   8 years AGO

46+12=58
58+16=74
26-8=18
41+12=53
53+16=69
21-8=13

Like? Yes | No   

himabindu   8 years AGO

46+12=58
58+16=74
26-8=18
41+12=53
53+16=69
21-8=13

Like? Yes | No   

gurpreet singh   8 years AGO

Consecutive difference is making a series.
12
16
48
8
23
12
16
48

Like? Yes | No   

JAGAN MOHAN   8 years AGO

46+12=58
58+16=74
26-8=18
41+12=53
53+16=69
21-8=13

Like? Yes | No   

ASHISH BAGHEL   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21
18-5=13

Like? Yes | No   

JAYA TRIPATHI   8 years AGO

58-46=12
74-58=16
26-74=48(-ve)
18-26=8(-ve)
41-18=23
53-41=12difference repeating again as above)
69-53=16
69-21=48
13-21=8(-ve)
therefore the ans is option (6) 13.

Like? Yes | No   

Jagdeep   8 years AGO

it is alternating series
1st term-5 = 6th term
2nd term-5 = 7th term.
Similarly
18-5 = 13

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Avdhesh Singh Rana   8 years AGO

first five numbers having difference with each other like -12,-16,48,8. In the same way last five having difference
41-53=-12
53-69=-16
69-21=48
21-x=8
where x should be 13 .

Like? Yes | No   

saiprakash   8 years AGO

The difference between the consecutive numbers repeats after 5 numbers. I.e
46-58=41-53
58-74=53-69
74-26=69-21
26-18=21-?
so ?=13

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raghav vij   8 years AGO

calculate the diffrence between each element you will get answer

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venky   8 years AGO

46 58 74 26 18 minus 5 from every number that is 41 53 69 21 13
so answer is 13

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kedasu suresh   8 years AGO

divide the series into four parts then 1st&3rd difference is same and 2nd&4th is same

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Anusha Reddy   8 years AGO

divide the number series into two parts
one part is ----46,58,74,26,18
second part----41,53,69,21
41+5=46
53+5=58
69+5=74
21+5=26
the answer is 13+5=18
option-6

Like? Yes | No   

Naveen Kesharwani   8 years AGO

in this series ans is like this
46+12=58
58+16=74
74-48=28
26-8=18
18+23=41
41+12=53
53+16=69
69-48=21
now according this sequence the next number will be
21-8=13
so 13 is the right answer.

Like? Yes | No   

Mukund Manohar   8 years AGO

Subtract 5 from the first set of 5 numbers to get the next set of 5 numbers
46-5=41
58-5=53
74-5=69
26-5=21
18-5=13

Like? Yes | No   

puneet mahawar   8 years AGO

46-58=-12
58-74=-16
74-26=48
26-18=8
18-41=-23
41-53=-12
53-69=-16
69-21=48
21-x=8
x=13

Like? Yes | No   

vaishali Rathore   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21
so 18-5=13

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sunil   8 years AGO

take first 4 no. and subtract 5 from them and get last 4 no. like this from 18 also subtract 5 and get 13 as ans

Like? Yes | No   

sujit sinha   8 years AGO

last 5 number is 5 less than first 5 numbers...

46-5=41
58-5=53
74-5=69
26-5=21
18-5=13
so 13 will be the next term

Like? Yes | No   

Karthic Jayakumar   8 years AGO

sequence comes as 2,6,48,8,23 and again repeats
so 21-8=13

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Shiv Pandey   8 years AGO

We look at the first 5 numbers of series, 6th onwards are 5 less than the first five.
1st=46 & 6th=41; 2nd=58 & 7th=69; 3rd=74 & 8th=69; 4th=26 & 9th=21.. And 5th=18 So, 10th will be 18-5=13.

Like? Yes | No   

Abhishek kumar   8 years AGO

we need to take first 5 terms and see the difference

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Adesh   8 years AGO

46 - 58 = -12
58 - 74 = -16
74 - 26 = +48
26 - 18 = +8
18 - 41 = -13
41 - 53 = -12
53 - 69 = -16
69 - 21 = +48
21 - ? = +8

So, ? =21-8=13.

Hence 6) is correct.

Like? Yes | No   

Anonymous   8 years AGO

Divided the series into two parts.
46,58,74,26,18,|41,53,69,21,?
Now
46-5=41;
58-5=53;
74-5=69;
26-5=21;
18-5=13.

Like? Yes | No   

DEVANSH SUBNANI   8 years AGO

46+12=58
58+16=74
74-48=26
26-8=18
18+23=41
41+12=53
53+16=69
69-48=21
21-8=13

Option 6)

Like? Yes | No   

Rajat Garg   8 years AGO

46+12=58,58+16=74,74-48=26,26-8=18
41+12=53,53+16=69,69-48=21,21-8=13

Like? Yes | No   

madhu   8 years AGO

the difference between 46 and 41 is 5
similarly the sequence continues and 18-5=13

Like? Yes | No   

ALICEPATRICIA AROQUIANADIN   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21
18-5= 13

Like? Yes | No   

himanshu   8 years AGO

58-46=12
74-58=16
74-26=48
26-18=8
41-18 =23
53-41=12
69-53=16
69-21=48
two successive no. Differ by 12 16 48 8 and 23 continuously so next no. Will be
21-8=13

Like? Yes | No   

Alex   8 years AGO

It is the series of 5 numbers
The first five numbers are 46, 58, 74, 26, 18
The second series is (first series)-5 i.e.,
46 - 5 = 41
58 - 5 = 53
And so on.... then, 18 - 5 = 13

Like? Yes | No   

I. Maria Alex Raj   8 years AGO

6th term=1st term-5,7th term=2nd term, so on finally 10th term=5th term-5

Like? Yes | No   

Nandha kumar   8 years AGO

the second five number are 5 less then first five number

Like? Yes | No   

Shiny Niveditha   8 years AGO

the difference between number is 5 at the intervals of 4
such as 46---41
58---53
74---69
26---21
18---13
so 13 is the answer

Like? Yes | No   

Palak Jain   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21. So, 18-5=13, which is required.

Like? Yes | No   

prasad reddy   8 years AGO

the given sequence contains 2 parts, (46, 58,74,26,18) and (41, 53, 69, 21, ?)....if we observe clearly difference between i th element in first and second sets is 5. so ? = 18-5= 13.

Like? Yes | No   

Pranav Raina   8 years AGO

The series follows the pattern of adding and subtracting numbers (12,16,48,8,23...12,16,48,8,23...).
Tweleve is added to 46,
16 is added to 58.
48 is subtracted from 74.
Again 8 is subtracted from 26
and finally 23 is added to 18.
Following the pattern, 8 must be subtracted from 21 i.e.
(21-8)=13

Like? Yes | No   

Revathi   8 years AGO

for incrasing orde numbers 58-46=12 53-41=12
74-58=16 69-53=16
hence 26-18=8 therefore 21-8=13

Like? Yes | No   

akash kumar   8 years AGO

the first five are in one series and the rest four +? in other series.like 46+12=58
58+16=74
74-48=26
26-8=18 then in the second series also the duffrence will same.like
41+12=53
53+16=69
69-48=21
21-8=13
so 13 will be the right ans.

Like? Yes | No   

saurabh chatterjee   8 years AGO

the difference of digits are repeated after a certain point and following that 13 should come.

Like? Yes | No   

vidyullatha sargu   8 years AGO

46 58 74 26 18 41 53 69 21
the diff b/w each term +12 +16 -48 -8 +23 +12 +16 -48
by observing the differences it is clear that ,,next term will be 21-8
therefore the answer is 13

Like? Yes | No   

Akshat Mokashi   8 years AGO

difference between first five and next five nos is 5 for example
46-41=5
58-53=5 so on

Like? Yes | No   

B Rajitha   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21
18-5=13

Like? Yes | No   

Rahul Das   8 years AGO

46+12=58 41+12=53
58+16=74 53+16=69
74-48=26 69-48=21
26-8=18 21-8=13
18+23=41

Like? Yes | No   

Nishi   8 years AGO

46-5=41
58-5=53
.
.
.
18-5=13

Like? Yes | No   

Akshay Kumar Shaw   8 years AGO

Divide the series into two halves. One from 46 to 18 and the other 41 to ?. Now if we find the difference between every elements in the two series that we get, we can find the answer.
The first half:
46+12=58
58+16=74
74-48=26
26-8=18
Now the second half:
41+12=53
53+16=69
69-48=21
21-8=13
So the answer is Option:6,i.e., 13

Like? Yes | No   

ASHIRBAD GHOSH   8 years AGO

considering 1st 3 nos 46,58,74
58-46=12 and 74-58=16

now from next two nos 26,18
26-18=8

again from next three nos 41,53,69
53-41=12,69-53=16

now it can be concluded that 21-8=13 i.e option 13

Like? Yes | No   

Pranjal Shrivastava   8 years AGO

the differences sequence is 12 16 48 8 23 12 16 48
the next difference should be 8 so the option 6 is correct

Like? Yes | No   

L.Backiyalakshmi   8 years AGO

46-5 = 41
58-5 =53
74-5 =69
26-5 = 21
18-5 =13

Like? Yes | No   

anupama   8 years AGO

we have here 2 series
one is 46,58,74,26,18
second is 41,53,69,21,?(13)
which is reduced by 5

Like? Yes | No   

Aman Kumar Jaiswal   8 years AGO

If we divide the whole sequence into two sequence A and B. Where A contains{46,58,74,26,18} and B contains{41,53,69,21,?}. In A we have 58-46=12 and in B we have 53-41=12.In A we have 74-58=16 and in B we have 69-53=16. In A we have 26-74=-48 and in B we have 21-69=-48. In A we have 18-26=-8, so in B we should have 13-21=-8. Hence answer should be 13

Like? Yes | No   

harish kedas    8 years AGO

41+5=46
53+5=58
69+5=74
21+5=26
13+5=18
and next numbers are 41,53,69,21,13

Like? Yes | No   

RAHUL KUMAR   8 years AGO

difference of 5 finds
46-5=41
58-5=53
74-5=69
25-5=21
18-5=13

Like? Yes | No   

SWATI OMAR   8 years AGO

46-58=12
58-74=16
26-74=-48
18-26=-8
41-18=23

// Series repeated

53-41=12
69-53=16
21-69=-48
So,
x-21=-8
x=-8+21
x=13

Like? Yes | No   

vishnu shekhar singh   8 years AGO

46 - 5 = 41
58 - 5 = 53
74 - 5 = 69
26 - 5 = 21
18 - 5 = 13

Like? Yes | No   

Nitish kesarwani   8 years AGO

since from right of 74-26=48, then decreases by 8 simlaraly
69-21=48,then decrease by 8 21-8=13

Like? Yes | No (1)  

SAMIRAN PATHAK   8 years AGO

46+12=58
58+16=74
74-48=26
26-8=18
18+23=41
41+12=53
53+16=69
69-48=21
so,21-8=13 is the ans.

Like? Yes | No (1)  

Ramgopal   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21
18-5=13

Like? Yes | No (1)  

pravallika   8 years AGO

difference of numbers sequence is 12,16, -48,-8,23
12,16,-48 so, next difference between numbers is -8.
13-21 = -8.(6 th option).

Like? Yes | No (1)  

Vipul kumar   8 years AGO

First five no ..
46 +12=58
58 +16=74
74 -48=26
26 -8 =18

second four no form same pattern
41 +12=53
53 +16=69
69 -48=21
so the next no will be
21 -8= 13

Like? Yes | No (1)  

MRITUNJAY   8 years AGO

46-5=41
58-5=53
74-5=69
26-5=21
18-5=13
option6

Like? Yes | No (1)  

RAHUL KUMAR   8 years AGO

46-5 = 41
58- 5 = 53
74-5 = 69
26- 5 = 21
18- 5 = 13

option (6)

Like? Yes | No (1)  

bhaskar   8 years AGO

46+12 41+12
58+16 53+16
74-48 69-48
26-8 21-8=13

Like? Yes | No (1)  

05 Aug 2016 Amount receive

Rs.5625 are divided among Mohan, Raju, Chandan so that Mohan may receive one-half as mush as Raju and Chandan together receive and Raju receives one-fourth of what Mohan and Chandan together receive. The share of Mohan is more than that of Raju by.

OPtion

1) Rs.975
2) Rs.950
3) Rs.750
4) Rs.850
5) Rs.1050
6) Rs.1500
7) Rs.1450
8) Rs.1600
9) Rs.1650
10)None of these

Solution

M+R+C = 5625
R = 1/4(M+C)
=> M+C = 4R
=> R+4R = 5625
=> 5R = 5625
=> R = 1125
M+R+C = 5625 & M = 1/2(R+C)
=> R+C = 2M
=> M+2M = 5625
=> 3M = 5625
M = 1875
M-R = 750
Option 3)

Correct Option: 3 Best Solution (67)

G.S.Kantharao   8 years AGO

Let Mohan,Raju and Chandan's shares are = M,R and C respectively.
Given M = ( R + C )/2
2M - R = C Equation 1
and R = ( M + C )/4
4R - M = C Equation 2
From 1 and 2
2M - R = 4R - M
3M = 5R
M : R = 5 : 3
From R = (M + C)/2 substituting M = 5R/3
R = ( 5R + 3C )/12 {After Simplification}
12R = 5R + 3C
7R = 3C
R : C = 3 : 7
M : R : C = 5 : 3 : 7
The difference of Mohan and Raju's Share is =
(5625* 2)/(5+3+7) = 750.
Hence the right choice is 3.

Like? Yes (2) | No (1)  

Prateek khanna   8 years AGO

M+R+C=5625..........(1)
according to question,
M=1/2(R+C) so
R+C=2M
put it in equation 1
3M=5625 ->M=1875
and R=1/4(M+C)
4R=M+C
put it in equation 1
5R=5625
R=1125
so share of mohan is more than raju by 1875-1125=Rs.750

Like? Yes (1) | No   

madhulikadoggala   8 years AGO

consider M,R,C be the shares of mohan,raju and chandhan respectively.
so
M+R+C=5625-----(1)
from the conditions given in question
we get the following equations
M=(R+C)/2-------(2)
R=(M+C)/4--------(3)
solving (1) and (2) we get
M=1875
Substituting 'M' value in equations (2)and (3) we get
R+C=3750-----(4)
4R-C=1875-----(5)
Solving (4) and (5) we get
R=1125
So Share of Mohan more than Raju=1875-1125=750

Like? Yes | No   

Mridula Shaw   8 years AGO

M=1/2(R+C)
R=1/4(M+C)
ATP,
M+R+C=5625
=>1/2(R+C)+R+C=5625
=>(R+C)=3750
Thus,
M=1/2*3750=Rs.1875
Now,
R=1/4(1875+3750-R)
=Rs.1125
Thus,Difference between Mohan's And Raju's Share=Rs.(1875-1125)=Rs.750

Like? Yes (1) | No (1)  

sujit sinha   8 years AGO

M+R+C=5625
and , R+C=2M
therefore, M=1875.
and R+C=3750
also,4R=M+C
so, R=1125

hence,M-R=750

Like? Yes | No   

saiprakash   8 years AGO

m=r+c/2
r=m+c/4
m+r+c=5625
m=1875
r=1125
m-r=750;

Like? Yes | No   

DWARAKA   8 years AGO

M+R+C=5625

M=1/2(R+C) ===> 2M=R+C ===>M=1875

R=1/4(M+C) ===>4R=M+C ===>R=1125

M-R=1875-1125

Like? Yes | No   

upasana bisht   8 years AGO

mohan share = 1/2 [raju + chandan]' share...... (1)

raju share = 1/4[mohan + chandan]' share........(2)

m+r+c = 5625
m= 5625 - r-c..... (3)
putting (1) in (3)
r + c = 3750... ( 4)
similarly
r = 5625 - m -c ... (5)
putting (2) in (5)
m + c = 4500 ...(6)

solving (5) and (6)
m - r = 750
m = 750 + r ans

Like? Yes | No   

AYAN PAUL   8 years AGO

From Equation 1 we get Mohan=.5(Raju+Chandan)
From Equation 2 we get Raju=.25(Mohan+Chandan)
from solving these two equations we get Raju = 3*Chandan/7 and Mohan= 5*Chandan/7
We know Mohan+Chandan+Raju=5625
so 5*Chandan/7+3*Chandan/7+Chandan=5625
We will get the amount of chandan and rest of two from these then.

Like? Yes | No   

dipanwita Bishnu   8 years AGO

M=1/2 (R+C)
R=1/4 (M+C)
M:R:C=5:3:7
M= 1875/-
R =1125/-
M-R =750/-

Like? Yes | No   

MOHAMMAD AAQIB   8 years AGO

2m=r+c eqn1; 4r=+m+c eqn2;
m+r+c=5625 eqn3;

put eqn1 & eqn2 in eqn3,we get
m=1875;
r=1125;
required ans= m-r=1875-1125=750;
option no.3

Like? Yes | No   

Naveen Kesharwani   8 years AGO

1) 1/2M=R+C
2) 1/4R=M+C
After solving these equation mohan=1875,raju=1125,
Chandan=2625
So difference between Raju and mohan share is 750.
So the answer is 750.

Like? Yes | No   

sindhuja   8 years AGO

m+r+c=5625
r=5625-m-c & r=(m+c)/2.eqaute these 2.
also m=(r+c)/2 solve tis with 1st eqn nd ull gt m.sub it in 2nd which will result in c nd find r using 1st eqn.thus ull gt the result

Like? Yes | No   

Siva   8 years AGO

M+R+C=5625,
M=[R+C]/2
2M =[5625-M]
M=1875.
R=[M+C]/4
4R=5625-R
R=1125.
M-R= 750.

Like? Yes | No   

Sangeetha Chinnasamy   8 years AGO

M+R+C=5625
M=1/2(R+C)
R=1/4(M+C)
Find R,M
R is 1125
M is 1875
1875-1125=750
ans is 750

Like? Yes | No   

Jyoti Ranjan   8 years AGO

as m+r+c=5625,2m=r+c,4r=m+c....
so m=1875 and r=1125,therefore m-r=750

Like? Yes | No   

DEVMALLYA BANDYOPADHYAY   8 years AGO

mohan recieves rs 1875 where as raju recieves 1125 so the difference is 750

Like? Yes | No   

jyoti   8 years AGO

let mohan.raju.chandan receive x,y,z money respectively.
then x+y+z=5625
x=y+z/2
y+z=5625-x

x=y+z/2
5625-x/2=x
after solving this we get x =1875

now
y+z= 3750

y=3750-z

3750-z= x+z/4;

x=1875; so put in ek

after solving we get z =2625

so y= 1125

we can check it by

2625+1125/2=1875 whichvis the value of x . similarly we check second condition.

mohan receive money more than raju= 1875-1125=750 ans

Like? Yes | No   

Abhash Kumar   8 years AGO

Answer:

A + B + C = 5625

4B + B = 5625
   B = 1125


Also A + C = 4B = 4 x 1125 =Rs 4500


Also
  B = 2A - C
 2A - C = 1125
Now solving A+C = 4500 and 2A-C = 1125


Then A = 1875 and C = 2625


Therefore., A-B = 1875 - 1125 = Rs. 750

Like? Yes | No   

R.Jayaraman   8 years AGO

let x ,y andz be the share's of mohan ,Raju and chandan respectively.
x=(y+z)/2








2x=y+z

y=(x+z)/2
2y=x+z and
x+y+z=5625
solving
x=1875
y=1125
x-y=750

Like? Yes | No   

bikash baral   8 years AGO

mohan;s share =5625/3=1875
as one part for mohan and rest 2 for raju & chandan

raju 's share = 5625/5=1125
one for raju and rest 4 for mohan and chandan

ans =1875-1125
=750

Like? Yes | No   

Pranjal Shrivastava   8 years AGO

let M R C be shares of mohan raju and chandan resp.
M = (R+C)/2 ; R=(M+C)/4; M+R+C = 5625;
solving these equation M= 1875 ; R= 1125; C= 2625;
M-R=750

Like? Yes | No   

pallabi   8 years AGO

Raju 2x chandan 2y
By first condition mohan will have x+y
Thn second condition gives 2x=1/4 (x+y+2y)
7x -3y=0
x+y+2x+2y=5625
By solving with a trick....add these...10x=5625
2x=1125
We need to find mohan - Raju by the question
So x+y-2x means y-x
Form 7x-3y=0
y=7x/3
Put it in y-x to get ans 4x/3 means 2*1125/3 =750

Like? Yes | No   

surajthite3995@gmail.com   8 years AGO

Let mohan=x,raju=y,chandan=z
Then,eq.1) x=1/2(y+z)
2x=y+z
eq.2) y=1/4(x+z)
4y=x+z
Solving 1 and 2
We get 3x=5y
Hence mohan = 1875
Raju= 1125
Hence mohan get 750 shares more than Raju.

Like? Yes | No   

yerra anitha   8 years AGO

given equations are:M=1/2(R+C) AND R=1/4(M+C)
When we solve the equations we wil get 2M=R+C;(1)
4R=M+C;(2)
M=4R-C;
PUT M IN 1 EQUATION THEN
2(4R-C)=R+C;
7R=3C;
R/C=3/7;
NOW PUT R&C VALUES IN 1 EQAUTION WE WILL GET 5=M;
SOO SHARES ARE OF Devied in 5:3:7 =m:r:c then valu MOHAN=1875;
RAJU=1125 DIFF IS 750

Like? Yes | No   

Shiv Pandey   8 years AGO

m=1/2(r+c)
2m=r+c

r=1/4(m+c)
4r=m+c
solving this, m=5/3r
ad put in equation, c=7/3r
r+m+c=5625
r+5/3r+7/3r=5625
r=1125 and m=1875
m-r=750

Like? Yes | No   

Ramneet kaur bhutani   8 years AGO

Mohan has (x+y)/2
Raju has x
Chandan has y
together they had 5625
and also Raju has((x+y)/2+y)/4
solving these equations we get the ans

Like? Yes | No   

Ashok   8 years AGO

M=1/2(R+S)
R = 1/4(M+S)
From Second line 4R= M+S (Substitute M value to get ratio of R & S as =3:7)

Then From the First Line 2M = R+S (Substitute S=7R/3 from the last equation)
Then we will get 5:3
So that M : R : C=5 : 3 :7

15 --->5625
1 ------>375
Diff of M & R = (5-3= 2) 2---->2*375=750


or
---------------------------
4R= M+S
2M=R+S
M+R+S=5625
4R+R = 5625 ==> 5R =5625 =====> R =1125

M+R+S=5625
2M+M =5625 ===> 3M =5625 =====> M=1875

So M-R = 1875-1125=750

Like? Yes | No   

Rucha   8 years AGO

Rajus share is 1125 and chandan is 2625 so we get mohans share as 1875 I e 750 more than raju

Like? Yes | No   

Shagun Chaudhary   8 years AGO

M=1/2(R+C)
R=1/4(M+C)
M+R+C=5625
=>M=1875
=>R=1125
M-R=750₹

Like? Yes | No   

Santosh   8 years AGO

Value of m comes out as 5R/3 and value of ac comes out as 7R/3
Putting it in m+c+r=5625
We get value of m as 1875 and value of r as 1125

Like? Yes | No   

Akshat Mokashi   8 years AGO

let mohan raju and chandan share be m,r and c
so m+r+c=5625 also m=1/2*(r+c)
r=1/4*(m+c) its clear that r+c=2m and m+c=4r
substituting these values we get 3m=5625 and 5r=5625
So share of mohan is more than that of raju by 750

Like? Yes | No   

Datla Lakshmi Bhavani   8 years AGO

mohan:chandan:raju=5:7:3
mohan=5/15*5625=1875
raju=3/15*5625=1125
so 1875-1125
=750

Like? Yes | No   

Aayushi Aggarwal   8 years AGO

Let mohan receives rs. X, raju receives rs. Y,chandan receives rs Z,
Then since all get rs 5625
then, X+Y+Z=5625,
Mohan receives half of raju and chandan
Then X=1/2(Y+Z)
NOW raju receives one fourth of mohan &chandan
Then Y=1/4(X+Z)
Now solving all three eq.
We get X=1875
Y=1125
Z=2625
THEN SHARE WHICHH MOHAN GET MORE BY RAJU IS Rs. (X-Y)
1875-1125=750 RS.

Like? Yes | No   

saurabh chatterjee   8 years AGO

m=(r+c)/2...1
r=(m+c)/4...2
we equate for c and find the ratio of m and r,then also find the value of c by putting the value in any of the equations above. m:r:c=5:3:7

Like? Yes | No   

gayathri   8 years AGO

M+R+C=5625
As per given conditions
M=0.5(R+c)
R=0.25(m+c)
So,by solving
M=1875
R=1125
Sol:1875-1125=750

Like? Yes | No   

Prakash Jha   8 years AGO

x+y+z=5625 .............(1)
x=(1/2)(y+z)............(2)= 2x-y-z=0;
y=(1/4)(x+z)...........(3)=x-4y+z=0;

adding 2 and 3;
3x-5y=0;.... (4)
subtracting 1 & 3;
5y=5625......(5)

therefore, by substituting value of 5 in 4,
3x=5625
x=1875
y=1125;
x-y=750rs

Like? Yes | No   

Rajeev Ranjan   8 years AGO

mohan=1/2(raju+chandan)
raju=1/4(mohan+chandan)
=>raju=3/7(chandan); 5/7(chandan)=mohan
5/7(chandan)+3/7(chandan)+chandan=5625
=> mohan-raju=1875-1125=750

Like? Yes | No   

sanjeet kumar   8 years AGO

From the question we have
Let mohan share be x.
Raju be y and chandan be z.
Then x+y+z = 5625
2x = y + z and 4y = x+z
On solving we get 750 as required answer

Like? Yes | No   

Gokul Krishnan   8 years AGO

a+b+c=5625
b+c=2a
a+c=4b
a-b=Rs.750

Like? Yes | No   

deepa subramanian   8 years AGO

m=(r+c)/2 => 2m=r+c
r=(m+c)/4 => 4r = m+c
r+m+c= 5625
m+2m=5625
m=1875

r+4r=5625
r=1125

m-r = 1875-1125 => 750

Like? Yes | No   

shailendra singh    8 years AGO

as given M=1/2(R+C) , R=1/4(M+C)
R=3/5M , C=7/5 M
M+R+C=5625
M+3/5M+7/5M = 5625
M=1875
HENCE R=1125
1875-1125 =750 = M-R

Like? Yes | No   

NISHA AGARWAL   8 years AGO

From the question,
Mohan:(Raju+Chandan)=1:2
So,Mohan's share is Rs(5625*(1/3))=Rs 1875
and also,
Raju:(Mohan+Chandan)=1:4
So,Raju's share is Rs (5625*(1/5))=Rs 1125
Therefore,
Mohan's share is more than that of Raju's by Rs(1875-1125)=Rs 750.

Like? Yes | No   

JAGARLAMUDI MAYURI   8 years AGO

let amount received by Mohan=m
let amount received by Raju=r
let amount received by Chandan=c
given m=(r+c)/2
=>(r+c)=2m --->equation 1
given r=(m+c)/4
=>(m+c)=4r --->equation 2
given m+c+r=5625--->equation 3
by substituting equation 1 in equation 3 we get
2m+m=5625
3m=5625
m=1875
by substituting equation 2 in equation 3 we get
4r+r=5625
5r=5625
r=1125
m-r=1875-1125=750
so share of mohan is more than that of raju by 750 rupees

Like? Yes | No   

muthukumar   8 years AGO

5625=x+y+z=>z=2625
x=(y+z)/2=(((x+z)/4)+z)/2=(5/7)z=>1875
y=(x+z)/4=(((5/7)z)+z)/4=(3/7)z=>1125
z=z=>2625
x-y=750

Like? Yes | No   

madhavan nair   8 years AGO

total amount in 3 parts and then in 5 parts - difference of these two gives the difference of mohan and raju - which is 5625/3 - 5625/5 = 750

Like? Yes (1) | No (1)  

Rohit Ritesh   8 years AGO

A + B + C = 5625
B=1/4(A+C) = A+C =4B

4B + B = 5625

B = 1125

Also A + C = 4B = 4 x 1125 = 4500

A=1/2(B+C)=B+C= 2A

B = 2A - C

2A - C = 1125

Now solving A+C = 4500 and 2A-C = 1125

Then A = 1875 and C = 2625

A-B = 1875 - 1125 = Rs. 750

Like? Yes | No   

Mukund Manohar   8 years AGO

M+R+C = 5625
R = 1/4(M+C)
=> M+C = 4R
So,4R+R = 5625
R = 1125
M+C = 4R
=>M+C = 4*1125 = 4500
Now,M = 1/2(R+C)
=> R = 2M-C
=> 2M-C = 1125
On Solving,M+C = 4500 AND 2M-C = 1125
We get,M = 1875 and C = 2625
So,M-R = 1875 - 1125 = 750
The share of Mohan is more than that of Raju by Rs 750

Like? Yes | No (1)  

RAHUL KUMAR   8 years AGO

Let Mohan =A
Raju = B and
Chandan = C
A/C to question,
A = (B + C)/2
? B + C = 2 A
? A + B + C = 3A
Thus 3A = 5625
? A = Rs. 1875

Again B = ( A + C )/4
? A + C = 4B
? A + B + C = 5B
? 5B = 5625
? B = Rs. 1125

Thus A's share is more than that of B by Rs. (1875-1125) I.e. Rs. 750.

Option (3)

Like? Yes | No (1)  

ABHINAV PUSHPAM   8 years AGO

Let Mohan =A
Raju = B and
Chandan = C
A/C to question,
A = (B + C)/2
⇒ B + C = 2 A
⇒ A + B + C = 3A
Thus 3A = 5625
⇒ A = Rs. 1875

Again B = ( A + C )/4
⇒ A + C = 4B
⇒ A + B + C = 5B
∴ 5B = 5625
∴ B = Rs. 1125

Thus A's share is more than that of B by Rs. (1875-1125) I.e. Rs. 750.
Option (3)

Like? Yes | No (1)  

DEVANSH SUBNANI   8 years AGO

Let Mohan's share be A
Raju's share be B
Chandan's share be C
A=(B+C)/2
B+C=2A
A+B+C=5625
A+2A=5625
3A=5625
A=Rs1875

B=1/4(A+C)
4B=A+C
A+B+C=5625
B+4B=5625
5B=5625
B=Rs.1125

A-B=1875-1125=Rs.750
Therefore,Mohan's share is more than Raju by Rs.750
Option 3)

Like? Yes | No (1)  

UMANG RASTOGI   8 years AGO

m+r+c=5625.......(1
(r+c)/2=m.............(2
(((m+c)/4)+c/2)=m..............(3
on solving equations 2 and 3,
c=7/5 m
r=3/5 m
putting in equation 1,
m = 1875
from r = 3/5 m
r= 1125
m-r = 750 ans.

Like? Yes | No (1)  

MRITUNJAY   8 years AGO

Let Mohan =A
Raju = B and
Chandan = C
A/C to question,
A = (B + C)/2
? B + C = 2 A
? A + B + C = 3A
Thus 3A = 5625
? A = Rs. 1875

Again B = ( A + C )/4
? A + C = 4B
? A + B + C = 5B
? 5B = 5625
? B = Rs. 1125

Thus A's share is more than that of B by Rs. (1875-1125) I.e. Rs. 750.
Option (3)

Like? Yes | No (1)  

Jaikumar Bhatia   8 years AGO

Let's
Mohan=A
Raju=B
Chandan=C
Now,
A+B+C=5625

B=1/4(A+C)
A+C=4B
Therfore,
4B+B=5625
B=1125
Also,
A+C=4b=4*1125=4500
also A=1/2(B+C)=>B+C=2A
B=2A-C
2A-C=1125
Now Solving
A+C=4500 and 2A-C=1125
We get A=1875 and C=2625
Therefore,
A-B=1875-1125=750
Ans is Mohan(A) is more than Raju(B) by Rs 750
Option is (3)

Like? Yes | No (1)  

Dinesh kumar sah   8 years AGO

According to the question,
M+R+C=Rs.5625.........(1)
and M=(R+C)/2.........(2)
and R=(M+C)/2.........(3)
if we solve the above equations (1) and (2)
then we get M=Rs.1875 and if we further solve the above equations (2) and (3) and put the value of M then we will get R=Rs.1125.
so the share of Mohan is more than that of Raju by 1875-1125=Rs.750 Ans
hence option (3) is the right answer.

Like? Yes | No (1)  

Vipul kumar   8 years AGO

Let
mohan gets = M
chandan gets = C
Raju gets = R

given that,
M + C + R = 5625....(1)
2M = R + C............ (2)
and 4R=M + C ............ (3)

we hv to find ,
M-R=?

now from (1)+(2)
3M = 5625
M = 1875

from (2) - (3)
3M - 5R = 0
5625 - 5R = 0
5R = 5625
R = 1125

so M - R = 1875-1125
= 750

Like? Yes | No (1)  

PILLI MEGHASAI   8 years AGO

3m=5625;5r=5625;;then
M>R....and is 1875_1125=750.
mohan have more money than raju

Like? Yes | No (1)  

Rahul Das   8 years AGO

m+r+c=5625 & 2m=r+c & 4r=m+c
solve this 3 equation we get m=1875 & r=1125
so,m-r=750

Like? Yes | No (1)  

Vipul Mayank   8 years AGO

let x y and z for the three person

x+y+z=5625 .........eq1
y=1/4(x+z) => 4y=x+z .........eq2
therefore from eq 1
4y+y=5625
=> y=1125

Also x+z=4y from eq2
therefore x+z=4*1125=4500 .....................eq3

Also x=1/2(y+z) => y+z=2x
=> y=2x-z
but y=1125
therefore 2x-z=1125 .............................eq4

from eq3 and eq4
we get x=1875 and z=2625

so x-y=1875-1125= Rs750

Like? Yes | No (1)  

Prabhleen   8 years AGO

1/2(r+c)+ r+c =5625
=>r+c =3750. Eq1
1/4(m+c)+ m +c =5625
=>m+c= 4500. Eq2
Eq2-eq1
=>m-r = 750

Like? Yes | No (1)  

shaik jasmin   8 years AGO

let mohan be m,raju be r,chandhan be c
total amount is 5625
i.e m+r+c=5625----->eq 1
from question m=1/2(r+c)
2m=r+c------>eq 2
and r=1/4(m+c)
4r=m+c------------>eq 3
substitute eq 2 in eq 1
m+r+c=5625
m+2m=5625 (r+c=2m)
3m=5625
m=1875
now substitute eq 3 in eq 1
m+r+c=5625
4r+r=5625 (m+c=4r)
5r=5625
r=1125
now difference between mohan and raju is 1875-1125
=750

Like? Yes | No (1)  

Vishnu Prakash   8 years AGO

m+r+c=5625
m=(r+c)/2
r=(m+c)/4
On solving above equations, we get
m=1875
r=1125
c=2625
Answer=m-r=750

Like? Yes | No (1)  

SANDEEP KUMAR MAHATO   8 years AGO

let Mohan, Raju and Chandan be denoted by M,R and C respectively.

so atq we have 2 equations as

M=1/2(R+C) .............(1)

R=1/2(M+C) .............(2)

by comparing above 2 equations we will get

C=7R/3 and M=5R/3

now, M+R+C=5625

=> (5R/3) + R + (7/3)R = 5625

=> R = 1125

so, M = 5R/3 = 1875

So share of Mohan than by Raju is given by

M-C= 1875-1125 = 750

so option (3) is the answer

Like? Yes | No (1)  

Sandip Das   8 years AGO

let say chandan share is x rs and raju share is y rs
total rs 5625
so mohan share is 5625-(x+y) rs
also from question we get mohon share is (x+y)/2
hence 5625-x-y=(x+y)/2
=>x+y=3750
so mohon share is (5625-3750)
=1875
again from question we get raju share is
(((5625-(x+y))+x)/4
hence
y=(5625-x-y+x)/4
=>y=1125
so the share of more than that of raju by (1875-1125)
=750 (option 3)

Like? Yes | No (1)  

Jagdeep   8 years AGO

let x be Raju and chandan's share and y be Mohan and chandan's share.
According to the given condition x+x/2=5625
it gives x= 1875
and
y+y/4= 5625 which gives y= 1125.

so x/2(mohan's) is 750 more than y/4(raju's)

Like? Yes | No (1)  

puneet mahawar   8 years AGO

R+C=5625-M
M+C=5625-R
M=1/2(R+C)=1/2(5625-M)
M=1875
same as this R=1125
M-R=750

Like? Yes (1) | No (2)  

Ajay Barathula   8 years AGO

Given M+R+C=5625-----(1)

condition's are R+C=2M-----(2) and M+C=4R-----(3)

by substituting (2) in (1) we get M=1875

similarly substituting (3) in (1) we get R=1125

by subtracting R from M we get remaining share of mohan from raju

M-R=1875-1125=750

Like? Yes | No (1)  

04 Aug 2016 Average

If a, b, c, d, e are consecutive odd integers, then what is their average.

OPtion

1) (a+b+c+d+e)/5
2) a+4
3) a+b+4
4) 5*abcde
5) (ab+bc+cd+de)/5
6) 5(a+b+c+d+e)
7) b+4
8) abcde/5
9) ab+4
10)None of these

Solution

Clearly
b=a+2, c=a+4, d=a+6 and e = a+8
=> Average = a+(a+2)+(a+4)+(a+6)+(a+8) / 5
5a + 20 / 5
a+4

Option 2)

Correct Option: 2 Best Solution (53)

Aakash Beniwal   8 years AGO

answer is 1st and 2nd both...
as (a+b+c+d+e)/5 and (a+4) both are correct.
as in 5 consecutive odd integer,3rd term is average and (first+4) is third term only. Multi answer question

Like? Yes (3) | No (1)  

NISHA AGARWAL   8 years AGO

Let b=a+2,c=a+4,d=a+6 and e=a+8.
Therefore, average=(a+a+2+a+4+a+6+a+8)/5=(5a+20)/5=(a+4)

Like? Yes (3) | No (1)  

SANDEEP KUMAR MAHATO   8 years AGO

as mentioned in the question, 5 consecutive odd integers are there. Hence rest 4 consecutive odd integers b,c,d,e can be written as

b=a+2, c=a+4, d=a+6, e=a+8

so average of a,b,c,d,e is given by

(a+b+c+d+e)/5 = (a+(a+2)+(a+4)+(a+6)+(a+8))/5
= (5a+20)/5
=a+4

so option(2) is correct.

Like? Yes (1) | No   

Vipul kumar   8 years AGO

Avg of five consecutive odd number
=(a+b+c+d+e)/5
=(a+(a+2)+(a+4)+(a+6)+(a+8))/5
=(5a+20)/5
=a+4

Note two ans may be current
1. Universally
2. By simplifying 1

Like? Yes (2) | No (1)  

Jaikumar Bhatia   8 years AGO

Five consecutive odd itegers numbers are:
a,a+2,a+4,a+6,a+8
then avg =(5a+20)/5=5(a+4)/5=a+4
ans is a+4
option is (2)

Like? Yes (1) | No   

G.S.Kantharao   8 years AGO

Let the intigers are= a, a+2,a+4,a+6,a+8
Their sum is =5a+20
Average = (5a +20)/5
= a + 4
Hence the right choice is 2.

Like? Yes (2) | No (1)  

Shreya    8 years AGO

Because there are five consecutive integers a,b,c,d,e and their average is the sum of all five integers divided by 5.

Like? Yes | No   

Abhash Kumar   8 years AGO

The numbers are a, b, c, d, e, f
As they are consecutive odd integers they can be expressed as a, a+2, a+4, a+6, a+8. 
Average = sum of the integers / Total Number of integers 
ie, A = (a + a+2 + a+4 + a+6 + a+8)/ 5
A = (5a + 20)/ 5
A = 5(a + 4)/ 5 = a+4 
So option 2 is the correct answer

Like? Yes | No   

puneet mahawar   8 years AGO

ans(1)
(a+s+b+c+d+e)/5
(1+3+5+7+9)/5=25/5=>5
or
a+4
1+4=5

Like? Yes | No   

kondapuram tirumalreddy   8 years AGO

according to question

b=a+2, c=a+4 , d=a+6 , e =a+8
then average =( a+b+c+d+e)/5
==>[a+(a+2)+(a+4)+(a+6)+(a+8)]/5=(5a+20)/5 = a+4.

Like? Yes | No   

Sandip Das   8 years AGO

since a,b,c,d,e are consecutive odd integer
so a is a odd integer
b=a+2
c=a+4
d=a+6
e=a+8
avg=(a+a+2+a+4+a+6+a+8)/5
=(5a+20)/5
=a+4 (option 2)

Like? Yes (1) | No (1)  

Shashank Shekhar   8 years AGO

Taking a=x, we have
b=x+2
c=x+4
d=x+6
e=x+8

Average = (x+x+2+x+4+x+6+x+8)/5
=(5x+20)/5
=x+4
Ans = a+4

Like? Yes | No   

JAYA TRIPATHI   8 years AGO

if a b c d e are 5 odd consecutive odd numberts then it can be written as,
a+a+2+a+4+a+6+a+8
now its average will be,
a+a+2+a+4+a+6+a+8/5 = 5a+20/5 = 5(a+4)/5 = a+4.

Like? Yes | No   

Abhishek Batra   8 years AGO

average = (sum of all observation)/ total number of observation

Like? Yes | No   

priya karuppuchamy   8 years AGO

average means to add all the values and divide how many numbers is given

Like? Yes | No   

MOHAMMAD AAQIB   8 years AGO

a,b,c,d,e are odd int . b=a+2;c=a+4;d=a+6;e=a+8;
avg=(a+b+c+d+e)/5
avg=(a+a+2+a+4+a+6+a+8)/5
avg=(5a+20)/5
avg=a+4
and is option no. 2;

Like? Yes | No   

Mridula Shaw   8 years AGO

Average=Sum of the integers/Total no of integers
=(a+b+c+d+e)/5

Like? Yes (1) | No (1)  

BHANU KIRAN   8 years AGO

because average means nothing but but the sum of the digits divided by no.of digits we are considering

Like? Yes | No   

Jagdeep   8 years AGO

since it is average so ans 1. But it can be calculated as simple the middle value that is c. Another way for calculating is (a+d)/2

Like? Yes | No   

Heena Pathan   8 years AGO

consecutive means without break..so divide by total no.so option 1

Like? Yes | No   

DEVANSH SUBNANI   8 years AGO

a,a+2,a+4,a+6,a+8
(a+a+2+a+4+a+6+a+8)/5=(5a+20)/5
=a+4
Option 2)

Like? Yes | No   

R.Jayaraman   8 years AGO

we know that average of n numbers is that sum of the numbers and sum is diveded by n

Like? Yes | No   

Vinay Mahobia   8 years AGO

since they are consecutive odd number, they can be represented as a series of AP with a as first term and 2 as comman difference.

Like? Yes | No   

shaik jasmin   8 years AGO

given numbers are a,b,c,d,e
total given numbers are 5
average=(a+b+c+d+e)/5

Like? Yes | No   

Shiv Pandey   8 years AGO

Numbers: a, b, c, d, e
consecutive 5 odd integers: a, a+2, a+4, a+6, a+8
average = sum/5
average = a+a+2+a+4+a+6+a+8/5
= 5a+20/5 = a+4

Like? Yes | No   

madhulikadoggala   8 years AGO

consider five consecutive numbers
a,(a+2),(a+4),(a+6),(a+8)
their average is calculated as ={a+(a+2)+(a+4)+(a+6)+(a+8)}/5
=a+4

Like? Yes | No   

himabindu   8 years AGO

their average is always middle number.that is c.
for example take five consecutive integers 13,15,17,19,21
average is 17.
where a=13
average=17(a+4)

Like? Yes | No   

JAGAN MOHAN   8 years AGO

Their average is always middle number[c]
foe example 1,3,5,7,9
average is 5.
answer is 1+4.=(a+4).for all cases.

Like? Yes | No   

shweta saxena   8 years AGO

consecutive odd number i.e. b=a+2, c=b+2, d=c+2, e=d+2
so...
(a+b+c+d+e)= (a+a+2+a+4+a+6+a+8)
=(5a+20)
avg= (5a+20)/5

avg=a+4

Like? Yes | No   

suthanth   8 years AGO

Sum of all numbers nd divided it by the count will gve da average

Like? Yes | No   

Sangeetha Chinnasamy   8 years AGO

5 consecutive odd integers are a,b,c,d,e
It can also written like this
(a,a+2,a+4,a+6,a+8)/5
=(5a+20)/5
=a+4

Like? Yes | No   

RAVI KUMAR   8 years AGO

Conecutive means one after the other.so the total average is a+b+c+d+e/5

Like? Yes | No   

Palak Jain   8 years AGO

consecutive odd integers can be denoted by a,a+2,a+4,a+6,a+8. their sum=5a+20. on dividing by 5 it is equal to a+4.

Like? Yes | No   

Vishnu Prakash   8 years AGO

Average = Sum of quantities/ Number of quantities=a+b+c+d+e/5

Like? Yes | No   

M Abhishek   8 years AGO

Suppose the consecutive odd numbers is 1,3,5,7 & 9
Then their sum is 25 and average is 5
(1+3+5+7+9)/5 = 5

Like? Yes | No   

himanshu   8 years AGO

Odd no. Next to a is a+2
next no. a+4
Next will be a+6
Next no a+8
Sum of all no= 5a+20= 5 (a+4)
Avg of 5 no. = sum of 5 no. /5= a+4

Like? Yes | No   

sanjeet kumar   8 years AGO

Since number are consecutive. So
a, a+2,a+4,a+6,a+8.
Avg = a+4

Like? Yes | No   

RITESH dassani Jain   8 years AGO

the numbers are a,a+2,a+4,a+6,a+8
sum =5a +20
avg=sum/5=a+4

Like? Yes | No   

Harika   8 years AGO

obviously the average for five consecutive odds will be the third digit and third digit will be first digit plus 4

Like? Yes | No   

Akshat Mokashi   8 years AGO

average of 1+3+5+7+9/5=25/5=5=1+4
3+5+7+9+11/5=35/5=7=3+4
....
So (a+b+c+d+e)/5=a+4

Like? Yes | No   

Gurpreet Kaur   8 years AGO

a+b+c+d+e/5
=[a+(a+2)+(a+4)+(a+6)+(a+8)]/5
=[5a+20]/5
=a+4

Like? Yes | No   

madhavan nair   8 years AGO

the middle number to be average and as cd is 2 first term+4 = a+4

Like? Yes | No   

gouselazam   8 years AGO

clearly,b=a+2,c=a+4,d=a+6,e=a+8.
->average =[a+(a+2)+(a+4)+(a+6)+a+8)]/5
->(5a+20)/5
->(a+4)

Like? Yes | No   

Mukund Manohar   8 years AGO

Here, b = a+2,c=a+4,d=a+6 and e=a+8
Sum = a+(a+2)+(a+4)+(a+6)+(a+8)
= 5a+20
Average = (5a+20)/5 = a+4

Like? Yes | No (1)  

ABHINAV PUSHPAM   8 years AGO

let a, b, c, d, e be 1,3,5,7,9
1+3+5+7+9/5= 25/5 = 5
sp, answer is a+4

Like? Yes | No (1)  

PRABHAT KUMAR   8 years AGO

let a,b,c,d,e be 1,3,5,7,9 respectively
then (1+3+5+7+9)/5
25/5=5
so 5=a+4
option 2
!!!!!!!!!#######!!!!!!!

Like? Yes | No (1)  

Sohini Chakraborty   8 years AGO

a,b,c,d,e being consecutive odd integers have values a,a+2,a+4,a+6,a+8 respectively..
hence average = Sum / 5 = (5a + 20) / 5 = a+4

Like? Yes | No (1)  

Dinesh kumar sah   8 years AGO

simply, average =sum of quantity/no of quantity
then average=(a+b+c+d+e)/5 Ans
hence option (1) is the correct answer...

Like? Yes | No (1)  

Alex   8 years AGO

let the five numbers be 1,3,5,7,9
then average of them is (1+3+5+7+9)/5 = 5
and a+4 = 1+4 = 5

Now let the five numbers be 11,13,15,17,19
then the average is (11+13+15+17+19)/5 = 15
and a+4 = 11+4 = 15

Hence, answer is a+4

Like? Yes | No (1)  

deepti   8 years AGO

a+(a+2)+(a+4)+(a+6)+(a+8)/5 //5 consequetive odd nos...
=5a+20/5
=a+4

Like? Yes | No (1)  

Siva   8 years AGO

There is not important weather the 5 are consecutive or odd or even anything, as they are 5 numbers, the avg is (a+b+c+d+e)/5.

Like? Yes (1) | No (2)  

upasana bisht   8 years AGO

lets consider an example :
3 + 5 + 7+9+11 = 35/7= 7
i.e 3+4 = 7
or
9 + 11 +13 +15+17 = 13
i.e 9+ 4 = 13
hence a+4 = avg of 5 consecutive odd numbers.

Like? Yes | No (1)  

RAHUL KUMAR   8 years AGO

odd consecutive odd integer means
a,b=a+2,c=a+4,d=a+6,e=a+8;
So,avg=sum/num;
avg=(a+a+2+a+4+a+6+a+8)/5
=(5a+20)/5
=5(a+4)/5
=a+4.

Like? Yes | No (1)  

03 Aug 2016 What percent

What percent is
150 ml of 3.5 litres ?

OPtion

1) .05 %
2) 1.5 %
3) 400/3 %
4) 25/4 %
5) 10/3 %
6) 30/7 %
7) 3.5 %
8) 3/2 %
9) 100/3 %
10)None of these

Solution

Required percentage = 150/350 * 100
30/7 %

Option 6)

Correct Option: 6 Best Solution (8)

SANDEEP KUMAR MAHATO   8 years AGO

let x% of 3.5 litres or 3500 ml will be 150 ml

so the equation will be

(x%) of 3500 = 150

=> 3500*(x/100) = 150

=> x = (150*100)/3500

=> x = 150/35

=> x = 30/7

so the final answer is x = 30/7 %

so option (7) is the correct answer

Like? Yes (13) | No (2)  

Alex   8 years AGO

Given x% of 3.5l = 150 ml
i.e., x/100 of 3.5*1000 ml = 150 ml
=> x*35 = 150
=> x=30/7

Like? Yes (9) | No (4)  

JAYA TRIPATHI   8 years AGO

since 1ml = 1000ltr
therefor 150/1000
let it will be x% of 3.5
therefore,
3.5*x/100= 150/1000 = 150/35 = 30/7

Like? Yes (5) | No   

Vinay Mahobia   8 years AGO

3.5L = 3.5*1000ml= 3500ml
so, %age=(150/3500)*100%
=30/7 %

Like? Yes (2) | No (1)  

PRABHAT KUMAR   8 years AGO

we know that 1000ml=1 liter
so,(150*100)/(3.5*1000)
30/7%
option 6
!!!!!!!!!!!#######!!!!!!!!!!

Like? Yes (1) | No (2)  

DEVANSH SUBNANI   8 years AGO

1000 ml=1 litre
150 ml=0.15 litre
(0.15/3.5)*100=4.2857%
30/7=4.2857
option 6)

Like? Yes | No (1)  

Sohini Chakraborty   8 years AGO

3.5 litre means 3500 ml
hence required percentage = 150/3500 * 100
= (15×10)/35 % = 30/7 %

Like? Yes (2) | No (3)  

sruthi pujari   8 years AGO

3.5lt =3500ml
150ml can be given as (150/3500)×100 percent of 3.5lt= 30/7 %

Like? Yes | No (1)  

02 Aug 2016 Find the value

Find the value of
Sqrt [(.036*.049*.25)/(.16*.064*.081)]

OPtion

1) 3/2
2) 25/48
3) 25/81
4) 35/81
5) 7/8
6) 7/9
7) 35/48
8) 5/9
9) 2/3
10)None of these

Solution

Given Exp.
Sqrt [(36*49*25)/(16*64*81)]
= 6*7*5 / 4*8*9
= 35/48

Option 7)

Correct Option: 7 Best Solution (14)

Sandip Das   8 years AGO

=(0.036*0.049*0.25)/(0.16*0.064*0.081)
=(36*49*25)/(16*64*81)
=(49*25)/(4*64*9)
now sqrt[(49*25)/(4*64*9)]
=(7*5)/(2*8*3)
=35/48 (option 7)

Like? Yes (3) | No   

Vipul kumar   8 years AGO

We can eliminate all floating point...
because number after floating point in numerator is equal to the denominator...
now it becomes...

sqrt [(36×25×49)/16×64×81]
[(6×7×5)/(4×8×9)]
35/48

Like? Yes (1) | No   

shraddha   8 years AGO

sqrt(0.36*0.1*0.49*0.1*0.25/0.16*0.64*0.1*0.81*0.1)
5*6*7/4*8*9
=35/48

Like? Yes | No   

Sangeetha Chinnasamy   8 years AGO

(4.41*10^-4)/(8.29*10^-3)=5.31*10^-8
sqrt(5.31*10^-8)=0.729
so ans is 35/48

Like? Yes | No   

suman    8 years AGO

sqrt of(36/1000*49/1000*25/100)/(16/100*64/1000*81/1000)
=(6*7*5)/(4*8*9)
=35/48

Like? Yes | No   

JAYA TRIPATHI   8 years AGO

Sqrt(.0336*.049*.25/.16*.064*.081)

=Sqrt(36*49*25/16*64*81)

=6*7*5/4*8*9 = 35/48

Like? Yes | No   

Amit pandey   8 years AGO

solving the qstn inside the braces we get sqrt(1225/2304)
so.ans is sqrt of (1225/2304)i.e. 35/48

Like? Yes | No   

Akshat Mokashi   8 years AGO

sqrt[(.036*.049*.25)/(.16*.064*.081)]=sqrt[(7^2*5^2)/(8^2*6^2)]=7*5/8*6=35/48

Like? Yes | No   

JAGARLAMUDI MAYURI   8 years AGO

multiply and divide with 100000000
Sqrt [(.036*.049*0.25*100000000)/(.16*.064*.081*100000000)]
=Sqrt[(36*49*25)/(4*8*9)]=[(6*7*5)/(4*8*9)]=35/48

Like? Yes | No   

PRABHAT KUMAR   8 years AGO

sqrt{(36*49*25)/(16*64*81)}
(6*7*5)/(4*8*9)
35/48
option 7
chess

Like? Yes | No (1)  

DEVANSH SUBNANI   8 years AGO

.036*.049*.25=4.41*10^(-4) -(1)
.16*.064=8.2944*10^(-4) -(2)
eqn1/eqn2

0.5316
sqrt(0.5316)=0.729
35/48=0.729
Therefore,option(7) is the correct answer.

Like? Yes (1) | No (2)  

Jaikumar Bhatia   8 years AGO

Sqrt[(.036*.049*.25)/(.16*.064*.081)
=>Sqrt[(36*49*25)/16*64*81)]...........Remove decimals
=>(6*7*5)/4*8*9).................................Sqrt
=>(210/288)
=>35/48
Ans is 35/48
Option is (7)

Like? Yes | No (1)  

Mukund Manohar   8 years AGO

Sqrt[(.036*.049*.25)/(.16*.064*.081)]
= (6*7*5)/(4*8*9)
= 35/48

Like? Yes | No (1)  

Sohini Chakraborty   8 years AGO

0.036 × 0.049 = 0.001764 whose sqrt is 0.042 and sqrt 0.25 is 0.5.. hence the numerator becomes (0.042×0.5) = 0.021
In denominator, sqrt (0.064 × 0.081) is 0.072 and sqrt 0.16 is 0.4 hence (0.072×0.4) = 0.0288...
So basically the answer is 0.021/0.0288 = 210/288 = 35/48

Like? Yes (1) | No (2)  

01 Aug 2016 Sequence

What is the next number of the following sequence
16, 28, 48, 92, 63, 15, 29, 107, 46, 28, 36, .....

OPtion

1) 109
2) 89
3) 94
4) 121
5) 100
6) 96
7) 99
8) 118
9) 110
10)None of these

Solution

(16, 28, 48, 92), (63, 15, 29, 107), (46, 28, 36, .....)

16 + 28 + 48 = 92 (Sum of first three number = fourth number)
63 + 15 + 29 = 107
46 + 28 + 36 = (110)

Option 9)

Correct Option: 9 Best Solution (13)

DEVANSH SUBNANI   8 years AGO

(16,28,48,92),(63,15,29,107),(46,28,36,x)
16+28+48=92
63+15+29=107
46+28+36=110
Therefore,option(9) is the correct answer.

Like? Yes (2) | No   

G.S.Kantharao   8 years AGO

16 + 28 + 48 =92
It means 1st + 2nd + 3rd = 4th
Simlarly 63 + 15 + 29 = 107 (5th +6th + 7th = 8th)
Hence 46 +28 +36 =110
The correct option is 9.

Like? Yes (2) | No   

saravanakumar velsamy   8 years AGO

first three number addition is fourth number.so based on this concept.and is 110

Like? Yes (1) | No   

JAYA TRIPATHI   8 years AGO

sum of 1st 3 = 4th
for example, 16+28+48=92
63+15+29=107
same as, 46+28+36=110.

Like? Yes | No   

puneet mahawar   8 years AGO

Answer is (9)110

(16+28+48)=92
(63+15+29)=107
(46+28+36)=110

Like? Yes | No   

subodh kumar   8 years AGO

this sequence is divide in 3 segment.each segment have 4 digit Numbers.Sum of 1st 3 digit Number will get last digit number.same procedure repeat for next segment and finally we will get missing Number..

Like? Yes | No   

R.Jayaraman   8 years AGO

sum of first 3 numbers is the 4th number
16+28+48=92
63+15+29=107
46+28+36=110

Like? Yes | No   

bhumika bisht   8 years AGO

Because
16+28+48=92
63+15+29=107 SO
46+28+36=110

Like? Yes | No   

ANIRBAN MUKHERJEE   8 years AGO

16+28+48=92
and 63+15+29=107 so the next number will be 46+28+36=110.

Like? Yes | No   

PRABHAT KUMAR   8 years AGO

16+28+48 =92
63+15+29 =107
46+28+36 =110
option 9

Like? Yes | No   

saiprakash   8 years AGO

sum of first three numbers is equal to the fourth one and sum of next three numbers is the following number and so on..

Like? Yes | No   

Prakash Jha   8 years AGO

16+28+48=92
63+15+29=107
46+28+36=110
So, the next term in the sequence is 110

Like? Yes | No (1)  

Jaikumar Bhatia   8 years AGO

(16+28+48)=92
(63+15+29)=107
(46+28+36)=110
Ans is 110
Option is (9)

Like? Yes | No (1)  

29 Jul 2016 Volume of Tower

The height and base diameter of a solid cube are 20 cm and 20 cm. One cube of max. possible size is cut from the cone touching the base, after this second cone is cut above it from the cone of max possible size, the process is repeated infinite times, all cubes are one above the other and seems like a tower having largest cube at bottom and smallest at top. Calculate the volume of tower.

OPtion

1) 1271.42
2) 1285.71
3) 1157.14
4) 1244.58
5) 1286.86
6) 1171.42
7) 1189.65
8) 1142.85
9) 1185.71
10)1215.42

Solution

Let dimensions of largest cube are x cm then by symmetry
20/10 = x/ (10- x/2)
=> 20-x = x
=> x = 10 cm
After cutting this cube, remaining cone has height and diameter as 10 cm, just half of initial so dimensions of second cube will be half of first similarly others so net volume of tower
= 10^3 + (10/2)^3 + (10/4)^3 + ........... infinite
= 1000(1 + 1/8 + 1/8^2 + ................. infinite
= 1000(1/ (1- 1/8))
= 1000*8/7 = 8000/7 cm^3
1142.85 cm^3
Option 8)

Correct Option: 8 Best Solution (2)

G.S.Kantharao   8 years AGO

Measurements of first cone is d = 20cm, r =10cm and h =20cm.
Side of a maximum possible cube is = 10cm
Side of next maximum cube is = 5cm
Next ones are 2.5cm, 1.25cm etc
Sum of their volumes are = 10^3 + 5^3 + (2.5)^3 + (1.25)^3 + .........
=10^3 + (10/2)^3 +(10/4)^3 +..........
=10^3{1 + 1/(2^3) +1/(4^3) +......}
= 10^3{1/(1-1/8)}
= 1000 x 1/(7/8)
= 1000 x 8/7
= 1000 x 1.14285
=1142.85
Hence right choice is 8

Like? Yes (7) | No (1)  

Aakash Beniwal   8 years AGO

size of any cube inside cone with equal diameter and height is = 1/2 of diameter.
hence cube volume= 10^3 cm= 1000
now remaining cone is of diameter 10 cm.
so volume of cube= 5^3 = 125 cm^3
similarly next cone with 5 cm diameter and cube with 2.5 cm side.
hence volume = 2.5 ^ 3 cm ^3 ....
and so on... 1000 + 125 + 15.625 + 1.95 + ... = 1142.8 (8th option)
Or can use
summation of (20/2k)^3 from k=1 to infinity....

Like? Yes (6) | No (1)  

28 Jul 2016 Fruits with different tags

There are 5 mangoes and 6 bananas. In how many different ways can a selection of fruits be made if all fruits of same kind are numbered with different tags.

OPtion

1) 2048
2) 41
3) 1024
4) 2047
5) 30
6) 11
7) 510
8) 1
9) 1023
10)512

Solution

All the fruits are numbered with different tags, thus it can be considered that all fruits are different objects,
For each fruit, we have two choices- Either select the fruit or not
Hence total number of choices are 2*2*2…….11 times – 1 = 2047

Option 4)

Correct Option: 4 Best Solution (0)