M4maths Previous Puzzles

12 Aug 2015 Time and work

A tank can be filled by one tap 20 minute and by another 25 minute. Both the taps are kept open for 5 minute and then second is turned off. In how many minute more is the tank completely filled.

OPtion

1) 6
2) 45/2
3) 25/2
4) 7
5) 9
6) 35/2
7) 10
8) 11
9) 12
10)None of these

Solution

Work done by both in 5 minute = (1/20 + 1/25) = 9/20
Remaining part = (1 - 9/20) = 11/20
Now, 1/20 part is filled in 1 minute. So, 11/20 part will be filled in 11 minute.
Hence, the tank will be full in 11 min more
Option 8)

Correct Option: 8 Best Solution (40)

aman aditya   9 years AGO

let tank be of 100 liter(taking L.C.M of 20 and 25)
now first tank fill it in 20 min. it fill 5 lit/min
second tank fill it in 25 min . it fill 4 lit/min .
if both are open for 5 min=(5+4)*5=45 liter is filled.
so 100-45=55 liter is left
55/5=11 min.

Like? Yes (19) | No (2)  

sanjeev kumar   9 years AGO

1st and 2nd tap filled in first min=1/20+1/25=9/100
in 5 min=(9/100)*5=9/20
remaining space=1-9/20=11/20
11/20 filled by first tap=(11/20)*20=11 min.

Like? Yes (14) | No (3)  

Narendra Gopi   9 years AGO

work done by A in one day= 1/20
work done by B in one day=1/25
Both together work in a day is 1/20+1/25=9/100
5 days work is=5*9/100=45/100
remaining work=1-45/100=55/100
B is turn off A can complete the remaining work in 55/100*20=11days

Like? Yes (9) | No (2)  

santosh kumar patel   9 years AGO

Part filled in 5 minut = 5*(1/20+1/25)
= 9/20
Remaining part = 1-9/20 = 11/20

so, now 1/20 : 11/20 = 1 : X
X = 11

Like? Yes (7) | No (3)  

Dinni   9 years AGO

Both taps open =5 ( 1/20 +1/25 ) =9/20
Remaining =1-9/20 = 11/20.
Second tap is turned off.
First tap will fill 1/20 in 1 min
So 11/20 in 11min.

Like? Yes (3) | No   

satyam kumar   9 years AGO

5(A+B)+XA=1
A=1/20;
B=1/25;
A+B=9/100;
5*9/100+x*1/20=1;
SOLVING WE GET X=11;
so 11 hours more....total hours is 11+5=16.

Like? Yes (3) | No   

Altaf Hussain   9 years AGO

Let the capacity of the tank be 100.
Time taken by 1st tap is 20min, Rate=5
Time taken by 2nd tap is 25min, Rate=4
They are kept open for 5min i.e., 9*5=45, remaining 100-45=55 is filled by 1st tap in 55/5=11min

Like? Yes (3) | No (1)  

vinusha   9 years AGO

5 (1/20 + 1/25) =9/20 for 5min
Remaining 11/20 in 11 min

Like? Yes (2) | No   

Akansha   9 years AGO

Both taps are opened for 5min = 5 (1/20+1/25)=9/20
And second tap is turned off
Remaining portion= 1-9/20 =11/20
First tap will fill remaining in 11min.

Like? Yes (2) | No   

AK Garg   9 years AGO

let us assume work is 100 units
then tap 1 do 5 unit work and tap 2 do 4 unit work
so in first 5 mints they did 45 unit work
then remaing work is 55 unit so it is done by tap 1 in more 11 mins

Like? Yes (1) | No   

Soma Naresh   9 years AGO

1 min work of two pipes are 1/20, 1/25
5 min work by both pipes
=(5/20)+(5/25)=9/20
after 5 min second tap is closed
so first tap has to work to complete the work
so remaining work=1-(9/20)=11/20
tap one takes 11 mins to fill the tank

Like? Yes (1) | No   

avanthika   9 years AGO

Both taps open = 5 (1/20 + 1/25) =9/20
Remaining = 11/20 and second tap turned off
First tap fill 11/20th part in 11 minutes.

Like? Yes (2) | No (1)  

sagar kumar mishra   9 years AGO

1/20+1/25=9/100
total time taken to complete =100/9m
in 5 minute 45/100 part of wrk will be completed
therefore remaining part 55/100 will be completed by 1st tap =(55/100)*20=11m

Like? Yes (1) | No   

ramya   9 years AGO

Let 2 taps be A and B.
In 5 min A&B fill = 5(1/20 + 1/25) = 9/20 tank
Tap B is turned off. So,
The remaining time taken to fill the tank by tap A will be 1 - 9/20 = 11/20 tank
Therefore, The time taken by tap A to fill the remaining tank is: 11minutes

Like? Yes (1) | No   

Ashu Kumar   9 years AGO

LET EXTRA TIME TO FILL THE TANK IS X.
SO ( X+5/20)+5/25=1
SO X=11 MINUTE
SO CORRECT OPTION IS 8

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

1 min work of two pipes are 1/20, 1/25
5 min work by both pipes
=(5/20)+(5/25)=9/20
after 5 min second tap is closed
so first tap has to work to complete the work
so remaining work=1-(9/20)=11/20
tap one takes 11 mins to fill the tank

Like? Yes (1) | No   

NITESH KUMAR SINGH   9 years AGO

when both the tank is open then time taken to fill the tank is 100/9.
so when both the tank is open for 5 minutes they can fill only 9/20 part of the tank so 11 /20 part of the tank is filled with after 11 minutes

Like? Yes (1) | No   

Ajay Kumar Gupta   9 years AGO

in one min both tank can fill tank (1/20+1/25)=9/100
in 5 min-tank will be 9/100*5=9/20 part
then 2nd is off.
by 1st tap-1/20 work in a minute.
so 11/20 lewft work in 11 min
so 11/20+9/20=1
so tank will full in 11 minutes.

Like? Yes (1) | No   

nishi   9 years AGO

1 min work of both taps =1/20 + 1/25 = 9/100
5 min work of both =9/100 * 5 =9/20
remaining work = 11/20
now 1/20 * x = 11/20
x=11

Like? Yes (1) | No   

vibha   9 years AGO

(1/20+1/25)*5 +(1/20)*x=1
solving x=11
as 1st tap work for x more min so he does x/20 more than 2nd

Like? Yes (1) | No   

S R Y Farhan   9 years AGO

1 work mean 100 percent work complete ----------------------------------------------eq 1
tap 1 => 1 min ----- 120 work complete
tap 2 => 1 min ----- 125 work complate
on doing 5 min together work ----> work completed = 5 *(120 + 125 ) = 920 .
work left to complete = 1 - 920 = 11/20.
now tap 1 requires 1120 work to complete in ______ time .
by using eq 1
time needed to complete laft work is = 1120 * 20 = 11 min.

Like? Yes (1) | No   

Harmeet kaur gurudatta   9 years AGO

1st tap fill in 20 min
2nd tap fill in 25 min
total capacity of tank=100
ie;1st fill 5 unit/min
2nd fill 4unit/min
if both open for 9 min they fill 45 unit (9*5)
remaining unit=100-45=55
now 2nd tap closes.1st tap fill in 11 min(55/5)
and=11 min

Like? Yes (1) | No   

velmala gangadhar   9 years AGO

let tank containing K lts of liquid
A tank capacity(pressure) is K/20 lts/min
B tank capacity(pressure) is K/25 lts/min
First A,B taps are kept open for 5 min then tank filled by
(K/20+k/25)*5 ==9K/20 part of tank
to fill remaining 11K/20 part of tank ,A tap will take 11 min...

Like? Yes (1) | No   

V.NIVETHA   9 years AGO

in five hours 9/20 of the tank will be filled so remaining 20/11 of the tank will be filled by tap a alone in 11 min

Like? Yes (1) | No   

vimal tiwari   9 years AGO

total time both will take to fill = 9/100
after 5 min = 45/100 = 9/20

remaing 11/20
first will fill it in 11 min

Like? Yes (1) | No   

pratik avinash   9 years AGO

1/20 + 1/25 = 9/100
work done by both in 5 min. = 5 * 9/100 = 9/20
r.w = 11/20
therefore remaining work done by A is 11 min.

Like? Yes (1) | No   

sarfarosh khan   9 years AGO

work done by A+B=45/100
remaining work is 55/100
first alone can do the work in 20 min
55/100 work done by firs is 55/100*20=8

Like? Yes (1) | No   

Ankit Kumar   9 years AGO

Let tank is of 100 L
Then speed of !st tap= 100/20 L/min=5 L/min
and speed of 2nd tap=100/25=4 l/min
Now both the tap are kept open for 5 min,then
total amount fill by both the tap =5*5 L+ 4*5 L=45 L
remaining =55 L which is to be filled by only 1st tap
hence time required to fill 55 L by 1st tap =55 L/5 L/min
=11 min

Like? Yes (1) | No   

vivek   9 years AGO

in 5 minutes work done by both pipes together is ((9/100)*5)=9/20
so required work will be 1-9/20= 11/20
work done by 1st pipe in 1 min= 1 unit(to fill a 20 unit tank)
then, time taken to fill 11 unit = 11 min.

Like? Yes (1) | No   

yamini shrivastava   9 years AGO

let the volume of the tank=v
tap 1 takes 20 mins to fill it and tap2 takes 25 mints to fill it up.
so the vol filled by tap1 in 1 min=v/20
tap2=v/25
togather the vol filled by them in 1 min =v/20+v/25=9v/100
so in 5 min the vol filled by both=9v/20
remaining vol =v-9v/20=11v/20.
v vol ifs filled by tap1 in 20 mins
11v/20 will be filled by tap1=11mins

Like? Yes (1) | No   

Kuheli   9 years AGO

1st tap
in 20 mint tank can filled 100 percent
in 5 mint tank can filled 25 percent
2nd tap
25 mints take to fill 100 percent
5 mints takes to fill 20 percent
so total in 5 mints tank can be filled 25 + 20 = 45 percent
remaining 55 percent can be filled by (100/20)*55
= 11minutes .

Like? Yes (1) | No   

Abhishek Anand   9 years AGO

As A takes 20 min to fill up so it is 100/20 = 5% efficient in doing work.
similarly for B 100/25 = 4%
Both works for 5 min so (5x5 + 4x5)= 45 % work is done
Rest 55% of work is to be done by tap A
so tap A will take 55/5=11 minutes more !

Like? Yes (1) | No   

GAUTAM CHAURASIA   9 years AGO

In 1 min part of tank filled = (1/20 + 1/25 ) = 9/100
In 5 Min = 9/20
Part of tank left unfilled = 1-9/20 = 11/20.
Time taken by Tap 1 to fill it = 11/20 * 20/1 = 11 min
Hence 11 More min will be requried

Like? Yes (1) | No   

Nizamuddin S   9 years AGO

When both taps are opened, in 1 minute the tank will be filled (1/20)+(1/25) part of tank that is 9/100 of the tank will be filled in 1 min .For 5 minutes 45/100 part of the tank will be filled and now second tap is turned off then the remaining 55/100 part of the tank will be filled in 11 minutes.So answer is 11.

Like? Yes (1) | No   

KajriSingh   9 years AGO

tank fill by two taps= 5(1/20+1/25)
remaining tank is 11/20
a fill a tank in=11/20*20/1=11

Like? Yes (1) | No   

Tarun Gupta   9 years AGO

Tank Filled by tap A in 1 min = 1/20
Tank Filled by tap B in 1 min = 1/25
Part filled in 5 min = 5(1/20 + 1/25) = 9/20
Remaining part = 1-9/20 = 11/20
Since Tap B is turn off
Then,
1/20:11/20 :: 1:x
x = 11/20 * 20 * 1
=> x = 11 min

Like? Yes (1) | No   

Archie   9 years AGO

1st tap in 20mins
2nd tap in 25mins
Let capacity of tank =LCM(20,25)=100 unit
1st tap's 1min work=5unit
2nd tap's 1min work=4unit
(1st+2nd tap's 1min work)=9unit
-----> Together they can fill 45unit in 5mins
Unit of tank left to be filled=55units
55units can be filled by 1st tap in 55units/(5unit/min)
=11mins
Hence 11mins more will be required to completely fill the tank .

Like? Yes (1) | No   

jayaram   9 years AGO

part filled in 5 minutes=5{(1/20)+(1/25)}=9/20
part remained=11/20;
time taken to fill remain part=(11/20)*20*1
time taken to fill the tank=11minutes

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

5 min. filling by both the taps=5*[(1/20)+(1/25)]=9/20
Remaining tank=11/20, so time taken by first tank to fill remaining=(11/20)/(1/20)=11 min.
Option 8)

Like? Yes (1) | No (1)  

sidhu   9 years AGO

if tank size is100l 1st tank fillid in 20m. its 1minut to fill 5li.
2nd tank filled in 25min.its 1minut time to fill 4li,
both are open 5min then if fill 5*5+5*4=45; 100-45=55
then aftr 5m second is trnde of then complity filled time 55/5=11
ans=11

Like? Yes (1) | No (1)  

11 Aug 2015 Time and Distance

Shweta rides at the rate of 10 km per hour but stops for 10 minutes to take rest at the end of every 15 km. How many hours will she take to cover 100 km?

OPtion

1) 9
2) 10
3) 11
4) 12
5) 25/2
6) 67/6
7) 34/3
8) 14
9) 15
10)None of these

Solution

Time taken to cover 100 km = 100/10 hr = 10 hr
During a journey of 100 km, she stops 6 times for
10 min each time, i.e. she stops for 1 hour
Therefore time taken = 11 hours

Option 3)

Correct Option: 3 Best Solution (18)

Megha Goel   9 years AGO

Time taken to cover 100 km= 100/10 hr
i.e. 10 hr
but she takes 10 min after every 15km hence it will take 1 hr for 6 time rest of 10 min.
hence 10+1 hr =11hr
option 3)

Like? Yes (4) | No   

Shiva Sharma   9 years AGO

she takes 10 min rest after 15 km
so there is 6 laps
and effectively she completes each lap in 100 min
and after 6th lap remaining distance is 10 km
which she completes in 60 min
so total time = 100*6 + 60 min
660 min = 11 hrs.

Like? Yes (3) | No   

umesh   9 years AGO

she is covering 15km in every 100m
so 90km in 600m i.e 10h
next 10km in 1h so total time is 10+1=11h

Like? Yes (2) | No   

Pritam Das   9 years AGO

she has 6 stops before completing her journey. thus 60 extra mins, thus 10+1=11 hrs

Like? Yes (2) | No   

AK Garg   9 years AGO

15*6 = 90
and take 60 mins rest for 90 km and 9 hour
then at last 10 km she takes 1 hour so
60 min + 1 hour + 9 hours = 11 hour

Like? Yes (1) | No   

sneha sri   9 years AGO

for 90 km she will take 10 hrs
for 15 km she will take 1 hr 40 mns
for last 10 km she will take 1 hr
so total 11 hrs

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

Time taken for every 15 Km=Time to cover 15 Km.+10 min. stop=(15/10) +(1/6)=5/3 Hr.
So for 90 Km. time taken=6*5/3=10 Hr.
and for remaining 10 Km. time taken=1 Hr.
So total time taken=10+1=11 hours
Option 3)

Like? Yes (1) | No   

SOURADIP MISTRY   9 years AGO

she will take (9*10+6*1/6)=10 hr to cover 90 km.. another 1 hr for last 10 km. therefore total time taken= 11hrs ..
therefore the correct option is 3)

Like? Yes (1) | No   

Altaf Hussain   9 years AGO

15 km are covered in 1hr 40min(including the rest time)
To cover 100 km time taken is 11hrs

Like? Yes (1) | No   

Narendra Gopi   9 years AGO

with the rate 10km/hr it will take 10 hrs to complete the task
And the rest between every 15 km is 10min
so he takes rest 6 times in his journey so 60min=1hr
total journey is 10hr+1hr=11hrs

Like? Yes (1) | No   

prashant   9 years AGO

SHE TAKES 100MIN FOR 15KM SO SHE WILL TAKE 600MIN FOR 90KM
+60MIN FOR THE REST 10KM.
TOTAL 660MIN=11HOURS

Like? Yes (1) | No   

Juhi Gupta   9 years AGO

coz in 1hr she covers 10km.
in 3/2 hr she cover 15 km take 10 min break so 11 hr.

Like? Yes (1) | No   

KUMAR ROHIT   9 years AGO

100%6 i.e, 6 times she takes rest for 10min each that means 6*10=60min=1hr
and she takes 10hr for 100km with the speed of 10km/hr.
Result:10hr+1hr=11hr

Like? Yes (1) | No   

aditya   9 years AGO

1 1/2 hr --> 15 km
1hr stop
it takes 10 hr to reach and 10+1

Like? Yes (1) | No   

Rishabh Pandey   9 years AGO

time=distance/speed
t=100/10
=10 hr
but as she stops every 15 km so
100/15 =6.**
so that means she stops six times so 6*10 ie the 10 min she stops
60 min =1 hr
so total time 11 hr

Like? Yes (1) | No   

ramya   9 years AGO

Number of Breaks between 100 kms is 6 times
Therefore 6*10mins=1hrs
Without break shweta can reach the destination in 10hrs
Time=Distance/Speed
Time=100/10
Total time=Break time+Time
Total time=1+10=11hrs

Like? Yes (1) | No   

kondapuram tirumalreddy   9 years AGO

after every 90 minutes she will take 10 minutes rest
so she will take rest after every 15km
to cover 90km she will take 10 hours and extra 1 hour to cover remaining 10 km
finally she will take 11 hours to cover 100 km

Like? Yes (1) | No   

SURAJ KUMAR   9 years AGO

for first 15 km time =1.5+0.16666
=1.66666 hours
for 90 km time will be =6 x 1.6666
=10 hours
for next 10 km time will be =1 hour
overall to cover 100 km time taken will be =10+1 =11 hours

Like? Yes (1) | No (1)  

10 Aug 2015 Percentage

The length and breadth of a square are increased by 30% and 20% respectively. The area of the rectangle so formed exceeds the area of the square by

OPtion

1) 20%
2) 30%
3) 36%
4) 38%
5) 46%
6) 48%
7) 50%
8) 52%
9) 54%
10)56%

Solution

Let the area of original square = 100
Then, side = 10
New length = 130% of 10 = 13, New breadth = 120% of 10 = 12
New area = 13*12 = 156
Therefore
Increase is area = 56%

Option 10)

Correct Option: 10 Best Solution (102)

Ankush Surana   9 years AGO

100*100=10000
130*120=15600
% increase= (15600-10000)/ 10000*100=56%

Like? Yes (9) | No (3)  

Sushmita Ghanty   9 years AGO

let length and breadth of the square is 100 m
the area of square is= 100*100= 10000 m^2
new length of the rectangle is=130 m
new breadth of the rectangle is=120 m
area if the rectangle is 130*120=15600 m^2
therefore, The area of the rectangle so formed exceeds the area of the square by (15600-10000)/10000*100=56%

Like? Yes (5) | No (1)  

sudiptaa   9 years AGO

let side of square = 100
len of rect = 130
bre of rect = 120
area of rect= 130 * 120 = 15600
area of square = 10000
too much = 5600
in % = (5600 *100)/10000
= 56 %

Like? Yes (7) | No (3)  

Devendra Marghade   9 years AGO

If original length & breadth are 'x' & 'y' respectively, then Area=x*y
If increased length=x*130/100=1.3x and
increased breadth=y*(120/100)=1.2y then
New Area=(1.3x)*(1.2y)=1.56xy
% increase in Area=100*(1.56xy-xy)/xy=56
Option 10)

Like? Yes (2) | No   

Deepak kumar kumawat   9 years AGO

let length and breadth are 10x
now increased length and breadth 13x and 12x
so (13x)*(12x)-100x=56x
required %= 56x/100x=0.56*100=56%

Like? Yes (2) | No   

Tarang gupta   9 years AGO

let the length be 'L' & breadth be 'B'....so area is L*B
now the length is increased by 30%of the original length
so new length =1.3L
similarly breadth=1.2B
new area =1.3L*1.2B=1.56LB
area increased=.56
%=(.56/100)*1=56%

Like? Yes (2) | No   

Aamir Beriwala   9 years AGO

first the area of square is lxb
then area of rectangular is 1.3l x 1.2b
so ans. is 1.56 lxl which is 56% of square

Like? Yes (2) | No   

Dubey Nandini M   9 years AGO

Say Len of Square=2 and Breath of square=2
area=(side)2=4

len of rectangle incre by 30%
terefore, 2+2*30/100= 13/5

Breath of rectangle incre by 20%
terefore, 2+2*20/100= 12/5

area=l*b=156/5

let ap=exceeds % of area
so,
4+4*ap/100=156/25
solving above equation we get
ap=56%

Like? Yes (2) | No   

sainath somisetty   9 years AGO

consider length and breadth of rectangle as 100 and 100 then area=10000
as the length increases by 30% hence length is 130
as the breadth of rectangle is increased by 20% then breadth is 120 then area=15600.
difference in area=5600
percentage increase in area=(5600/10000)*100=56%

Like? Yes (2) | No   

Manish Kumar Rana   9 years AGO

initially
area of rectangle = l*b = lb
after increment in length and breadth
length = 1.3l
breadth = 1.2 b
area= 1.3l*1.2b= 1.56lb
% increment= (1.56lb-lb)*100 = 56 %

Like? Yes (2) | No   

KajriSingh   9 years AGO

assume the side of square =x
length of rectangle=130x/100
breadth of 120x/100
area of square=x^2
area of rectangle=130x/100*120x/100=(39x^2/25)-x^2

i.e. 14x^2/25

increased percentage of area of rectangle is (14x^2/25)*100=56%

Like? Yes (2) | No   

Priya Dharshini   9 years AGO

for eg :
let us take length as 100m;
and Breadth as 100m;
so the area of the square is 10,000sq.m;


now....length is increased by 30% & breadth is increased by 20%

so,length=130;
breadth=120
Area of Rectangle=L*B
which is 130*120=15,600;


to find the exceeded percentage
(5600/10000)*100=56%

Like? Yes (2) | No   

Altaf Hussain   9 years AGO

If the sides of square are increased by 30% and 20% then the sides will be 1.3 and 1.2 times. On calculating area of the rectangle 1.3*1.2=1.56. Hence the area is increased by 56%.

Like? Yes (1) | No   

shashank verma   9 years AGO

Area 1+X%=area2
10000+X%=15600
x=56
56% is answer

Like? Yes (1) | No   

gopiraju   9 years AGO

100*200=20000
(100+30)*(200+40)=31200
change is=(31200-20000)/20000=0.56
now %=0.56*100=56%

Like? Yes (1) | No   

SOUVIK   9 years AGO

suppose previously length was x and breath was y.so area xy.now after increasing it became 13x/10 and 12y/10 respectively.so area is 156xy/100 .so increament is 56%

Like? Yes (1) | No   

Kethineni Vinodh   9 years AGO

side of square=x
then length=1.3x
breadth=1.2x
area of rectangle=1.3x*1.2x=1.56x^2
area of square=x^2
so 56%

Like? Yes (1) | No   

Nishith HM   9 years AGO

let l=10 b=10 area now is 100(l*b)
after increasing l=12 n b=13 area is 156 total increase is 56%

Like? Yes (1) | No   

Naveen Tiwari   9 years AGO

The lenght and breadth are incresed by 30% and 20% , hence square become rectangle...
Area of rectangle i=L*B
after increasing
the new area=1.3*1.2=1.56
hence changes in area is 56% increase..

Like? Yes (1) | No   

jaya   9 years AGO

area of rectangle exceed area of square by=
area rectangle -area of square
area of rectangle = (130b/100)(120b/100)
area of square=b*b
=(156(b*b)/100) - (b*b)
=56% (b*b)
i.e. 56% of area of square

Like? Yes (1) | No   

sneha sri   9 years AGO

let x be the side of a square
then dimensions of rectangle are 1.3x and 1.2x
area exceeded by 56%

Like? Yes (1) | No   

mithilesh kumar   9 years AGO

a1=l*b
a2=(130/100*l)*(120/100*b)
=156/100*l*b
=156/100*a1
So 56% increase

Like? Yes (1) | No   

kartik dolas   9 years AGO

let l-length,b-bredth.initialy area be a=l*b
now acording to conditn let new area be A=(l+30l/100)(b+20b/100)=13*12/100lb=1.56lb=1.56a...(as a=lb)
now,%change=(A-a)/a*100=56%

Like? Yes (1) | No   

jasbir kaur   9 years AGO

with 30% increase the area becomes 130, further 20% increase makes it 156, so (156-100)/100=56%

Like? Yes (1) | No   

karan minocha   9 years AGO

let
length=x
breadth=x(as it is a square)
new length= 1.3x (as it is increased by 30%)'
new breadth=1.2x (as it is increased by 20%)'
therefore area of rectangle exceeds = 1.3*1.2=1.56 (56%)

Like? Yes (1) | No   

chinna madhu   9 years AGO

let the squre be 10*10=100 after changes 13*12=156
so the percentage change is 56%

Like? Yes (1) | No   

phani krishna   9 years AGO

l1=b1=y,a1=(y*y).....l2=1.3y,b2=1.2y,a2=(1.3y)*1.2y=(1.56*y*y).%increase=((1.56-1)*y*y)*100/(y*y)=56

Like? Yes (1) | No   

Madhurima Bhattacharyya   9 years AGO

let 100 be the length and breadth of square.then length and breadth of rectangle be 130 and 120 resp.area of sq=10000 and that of rect=15600.inc in area is 5600.then percentage inc in area is 56%

Like? Yes (1) | No   

anubhav kumar gupta   9 years AGO

actual area of rectangle=l*b
after transformation area=1.3l*1.2b=1.56
difference in area=1.56lb-1lb=0.56lb
% increase=(difference/actual area)*100=56%

Like? Yes (1) | No   

nikita gupta   9 years AGO

initial length = l units
initial breath = b units
initial area = l*b sq units
increased length = 13/10 units
increased breadth = 6/5 units
new area= 39/25 l*b sq units
so, increased area = 56%

Like? Yes (1) | No   

RAGNI RUPAM   9 years AGO

let side of square,s=100
area= 10000
new length, l=130
new breadth, b=120
area of rectangle= 15600
diff= 5600
%diff = (5600*100)/10000

Like? Yes (1) | No   

Kuheli   9 years AGO

increased area =( 130X * 120Y)/100*100
so (156/100 - 1 )XY = 56XY/100
so percent is 56 percent

Like? Yes (1) | No   

vamsi   9 years AGO

Assume l=10 and b=10
when l is increased by 30% and b is increased by 20%,then the l becomes 10+3=13 and b becomes 10+2=12
Hence area of rectangle is 13*12=156 i.e 56% more than area of square i.e 100

Like? Yes (1) | No   

M Nikhil kumar   9 years AGO

Assume the initial values of square as 100,100
Increased values are 130,120 and hence the final area is 15600
it is increased by 56%

Like? Yes (1) | No   

poojasaisri   9 years AGO

length increased by 1.3
breadth increased by 1.2
area will increase by 1.3*1.2=1.56
=56%

Like? Yes (1) | No   

lokesh kumar   9 years AGO

let 100 be the side of square.
old area=100*100=10000
new area formed = 130*120=15600
%age area=(15600-10000)/10000 *100= 56%

Like? Yes (1) | No   

pankaj kumar   9 years AGO

let length is 1 and breadth is 1 then increment in both is
as follow .3 & .2 then area after increment will be 56%

Like? Yes (1) | No   

Sanjeeb Chatterjee   9 years AGO

let length of sq be x unit.
therefore area of sq is x^2 unit.
now length and breadth exceeds by 30% and 20% then
length becomes 13x/10 unit and breadth 12x/10 unit.
area becomes 156x^(2)/100 unit.
area increases by {(156x^2)/100 - x^2}*1/x^2*100=56%

Like? Yes (1) | No   

Avik Das   9 years AGO

Previous area 10000. After change it becomes 15600. So, percentage increase by 56. option 10 is correct.

Like? Yes (1) | No   

Gyanranjan   9 years AGO

let the sides of the square be 100 units
so length and breadth of the rectangle will be 130 & 120 units
so area of rectangle =15600 units^2 and area of the old square =10000 units^2
%increase=((15600-10000)/10000)*100%=56%

Like? Yes (1) | No   

Priyanjay Kumar   9 years AGO

net increase =
a+b+(a*b)/100
where a is % increase in first quantity and b is % increase in second quantity .

Like? Yes (1) | No   

momin ashraf ahamed   9 years AGO

assume side of square as 10,
30% increase in side=13
20% increase in side =12
area of original square =10*10=100
area of increased square=12*13=156
therefore increase in area =156/100*100=156
therefore increase in %=156-100=56%

Like? Yes (1) | No   

Karthick Raja   9 years AGO

assume the side of the square is 100 units
so area is 10000
Length increase by 30% & width increase by 20%
so Length is 130 width is 120
area=130*120=15600

area increased =
(15600-10000)*100/10000
=56%.

Like? Yes (1) | No   

Prabakaran   9 years AGO

consider 100m be side of square
so area is 10000
length is 130m (30% increase)
breadth is 120m(20% increase)
area is 15600
area of rectangle exceeds by square is (5600/100)%=56%

Like? Yes (1) | No   

Juhi Gupta   9 years AGO

let the length & breadth of rectangle be x & y.
original area=xy m2
new length=130x/100
new breadth=120y/100
new area=156xy/100
156xy/100-xy/100=56xy/100
increase%=([56xy/100]*[1/xy]*100)
56%

Like? Yes (1) | No   

deepak kumar   9 years AGO

area after increment is 1.2*1.3=1.56of previous area
hence increment in % is=56%

Like? Yes (1) | No   

Akarsh Kumar   9 years AGO

increasing the sides by 30% and 20 % gets your length and breadth as 1.3s and 1.2s , assuming side of the square to be s.
1.2s*1.3s=1.56s^2 increasing the area to 56%

Like? Yes (1) | No   

Subhodeep Ghosh   9 years AGO

If length is suppose a and breadth is suppose b then Formula is: (a+b+((a*b)/100))=(30+20+(600/100))=56

Like? Yes (1) | No   

manasa   9 years AGO

new length=a+(30/100)a=(13/10)a
new breadth=b+(20/100)b=(6/5)b
rectangle area=(13/10)a*(6/5)b=(78/50)ab=(ab+(28/50)ab)
=>ab+(56/100)ab
=>ans=56%

Like? Yes (1) | No   

satyam kumar   9 years AGO

let area be 100 .den increase in 30 % is 130 and then increase of 20 % of 130 is 156 ..so 56% is d %change..

Like? Yes (1) | No   

Rupa Kumari   9 years AGO

Let, length=x, bredth=x,
original Area of square =x*x;
New area=(x+0.3x)*(x+0.2x) =(1.56 x^2)m^2;
Area increment=[ (1.56 x^2- x^2)/x^2] *100= 56%

Like? Yes (1) | No   

AASTHA MITTAL   9 years AGO

new area=(l+.03l)*(b+0.2b)
=1.56lb
%age increase=(1.56-1)/1
=0.56
i.e. 56 %

Like? Yes (1) | No   

kumaravel   9 years AGO

assume lenth of a side of square be 100,so it's area is 10000(area of square=a^2)..if length is increased by 30%,then lenth becomes 130,breadth is increased by 20% it becomes 120.so the area of rectangle is 15600(arae of (rectangle =l*b) ,so difference ia area is (15600-10000=5600)..(therefore (5600/10000)*100=56%)

Like? Yes (1) | No   

Naveen Chaudhary   9 years AGO

% increase in area=[a+b+(a*b)/100] %
=[30 +20+(30*20)/100]%
=[50+600/100]%
= (50+6)= 56 %

Like? Yes (1) | No   

pratik avinash   9 years AGO

New L=13/10l
new B=6/5b
therfore area incresed = 156/100
therefore 56%

Like? Yes (1) | No   

Kajal Manohar Roshni Rangwani   9 years AGO

Area of square= l*l
Area of rectangle=(l+30/100*l)*(l+20/100*l)=156l^2/100
%increase= %(area of rectangle-area of square)

Like? Yes (1) | No   

anushka bansal   9 years AGO

length = L
breadth = B
area = LB
new length = 1.30L
new breadth = 1.20B
new area = (1.30L)*(1.20B)
= 1.56LB
therefore 56% increase

Like? Yes (1) | No   

Prabhat Burnwal   9 years AGO

x'=x(1+20/100)
y'=y(1+30/100)
new area=x'*y'
%age increase=(new area-old area)/old area*100

Like? Yes (1) | No   

Mugesh sivagnanam Krishnapillai   9 years AGO

Let the sides of square be 1 unit .
then Area =1 sq.unit.
After increase,the length and breadth would be 1.3 & 1.2
so area=1.56 sq.unit
Hence increase in area =( (1.56-1)/1)*100=56%.

Like? Yes (1) | No   

jomon v j   9 years AGO

let length=100
breadth =100
then area =10000
now the length is increased by 30% ,then length =130

breadth =120

area =15600

change in area =5600

% in increase = (5600/10000)*100=56

Like? Yes (1) | No   

abhishek kumar singh   9 years AGO

let us consider the previous length will be x nd breath also x means area=x^2
new lenght =1.3x
new breath=1.2x
area=1.3x*1.2x=1.56x^2
56% increased

Like? Yes (1) | No   

srikanth   9 years AGO

it will increase area by .56 times the original so answer will be 56%

Like? Yes (1) | No   

rimjhim gupta   9 years AGO

suppose initially l and be are 100
after increase l and b will be 130 and 120
so change in area will be 5600
and percent change will be 56.

Like? Yes (1) | No   

shivjee yadav   9 years AGO

let length=10,
width=10,
area=100
after increase length=13,
width=12
area=156 that meanst increase 56%

Like? Yes (1) | No   

Shweta Sharma   9 years AGO

let dimensions be l and b
new dimension=130/100l=1.3l and 120/100b=1.2b
increase=(1.3lX1.2b)-lXb
=1.56lb-lb
=.56lb
increase percent=(0.56lb/lb)X100
=56%

Like? Yes (1) | No (1)  

Pritam Das   9 years AGO

Suppose a is the length and b is the breadth. New length (a 0.3a) and new breadth (b 0.2b) and multiplying them we get 1.56ab. Thus, area is 56%more

Like? Yes (1) | No (1)  

SUNIDHI   9 years AGO

let intial area be 10000
new area =15600
inrease 5600 or 56%

Like? Yes (1) | No (1)  

Narendra Gopi   9 years AGO

area of a square is x^2
so rectagle length is :130x,breadth is 120x
rectagle area is 1.30x*1.20x=1.56x^2
so the are of rectangle exceeds is (1.56x^2-x^2)=0.56
percentage increase is 0.56*100=56%

Like? Yes (1) | No (1)  

aman aditya   9 years AGO

Let l=20m
b=10m
so area=20*10=200m*m

now after 20% increment.
l=26
b=12
new area=26*12=312 m*m

so new area exceed old by 56%

Like? Yes (1) | No (1)  

Bairi Sowjanya Reddy   9 years AGO

new length= s+(30 s/100) =13 s/10
new breadth= s+(20 s/100) =12 s/10
area=13 s/10 *12 s/10= ( 156 s*s )/100
% increase={(156 s*s)/100 - (s*s)}/(s*s) *100 = 56%

Like? Yes (2) | No (2)  

jayaram   9 years AGO

let a be the side of square then
Here the increase in area when length is extended to 30% and breadth is extended to 20 % then the area of rectangle will be 56%+area of square

Like? Yes (1) | No (1)  

velmala gangadhar   9 years AGO

n% of value=(getting/need)*100
from that 30% length(l) means getting=0.3l
breadth(b)means getting=0.2b
actual area of square=l*b
area of rectangle=(l+0.3l)(b+0.2b)
=1.3l*1.2b
=1.56lb
=(1+0.56)lb
actual area is lb and exceeding area is 0.56 times
It means exceeding area is 56%......

Like? Yes (1) | No (1)  

SURAJ KUMAR   9 years AGO

let x,y be the length and breadth of square
area of square= xy
length increased by 30%= x+0.3x
breadth increased by 20%=y+0.2y
then area of rectangle so formed is
=(x+0.3x)(y+0.2y)
=xy+0.2xy+0.3xy+0.06xy
=0.56xy
then area of rectangle is increased by 56%.

Like? Yes (1) | No (1)  

Rishikesh Ranjan   9 years AGO

area of square=L*L,
NOW the length of rectangle= L+L*30/100=(13/10)L
and breadth= L+L*20/100=(6/5)L
so area of rectangle= (39/25)L*L
so % increase in area= [39/25 L^2 - L^2]*100 = 56% of L^2

Like? Yes (1) | No (1)  

Ashu Kumar   9 years AGO

LET SIDE OF SQUARE IS 100 UNIT
SO AREA EQUALL TO=10000UNIT^2
NOW NEW LENGTH=130, BREADTH=120
SO AREA OF RECTANGUL=130*120=15600
SO AREA OF SQUARE EXCEED BY
15600-10000=5600=56%
SO 56% OPTION 10

Like? Yes (1) | No (1)  

Soma Naresh   9 years AGO

length of rectangle=l+(30×l/100)
breadth of rectangle=b+(20×b/100)
area of rectangle=(130l/100)(120b/100)
= 15600lb/10000=lb+(56lb/100)
area of rectangle=area of square+(56% ) area of square

Like? Yes (1) | No (1)  

ramya   9 years AGO

Let length =a and breadth=b.
Let area =ab .
new length: a+30a/100
= 13a/10
Similarly new breadth : b+20b/100
=120b/100 =>6b/5

New Area= (13a/10 * 6b/5)+ab
=>(78ab/100) = 50ab/50 +28ab/50
= ab + 56ab/100


New area is increased by 56%

Like? Yes (1) | No (1)  

deepak singh   9 years AGO

new length =1.3x
new breadth=1.2x
new area=1.56x
change in area =1.56x^2-x^2=.56

Like? Yes (1) | No (1)  

A M ANKIT KALLURAYA   9 years AGO

A=lb
A'=1.3*1.2lb
A'=1.56A
so there is an increase of 56%

Like? Yes (1) | No (1)  

santosh kumar patel   9 years AGO

Let a be the length of rectangle
and b be the breadth of rectangle
the old area = ab units
Length increased by 30% and Breadth increased by 20%
Therefore new length = a+(30a/100)=13a/10
and new breadth = b+(20b/100)=6b/5
New area of rectangle = 13a/10*6b/5
=78ab/50
=ab+(28ab/50)
=ab+(56ab/100)
=56%

Like? Yes (1) | No (1)  

Sneha Kurapati   9 years AGO

length of rectangle= a+ (30 a /100)= 13 a/10
breadth of rectangle = a+ (20 a/100) = 12 a/10
area of rectangle = 13 a/10 * 12a/10 = 156 a*a /100
% increase = {(156 a*a /100 - a*a )/(a*a) }*100=56%

Like? Yes (1) | No (1)  

siddhi datri   9 years AGO

new length=130/100
new breadth=120/100
new area=((130*120/10000)-1)*100=56%

Like? Yes (1) | No (1)  

SOMA NARESH   9 years AGO

length of rectangle=l+(30×l/100)
breadth of rectangle=b+(20×b/100)
area of rectangle=(130l/100)(120b/100)
= 15600lb/10000=lb+(56lb/100)
area of rectangle=area of square+(56% ) area of square

Like? Yes (1) | No (1)  

Danda Sindhura   9 years AGO

Suppose let the side of square be 100...(130/100)*(120/100)=156..
so rectangle increased by 156-100=56

Like? Yes (1) | No (1)  

Sriparna Boote   9 years AGO

At first lenght=breadht=x
Area is x^2

Now lenght =1.3x and breadth =1.2x
Area is 1.56x^2

Difference of area is 1.56x^2-x^2=0.56x^2 that is 56%

Like? Yes (1) | No (1)  

sushma   9 years AGO

if suppose side of square is 4cm. the increased length n breadth will be 26/5,24/5. now area of rectangle will be 624/25. area of square is 16. increase in are is 224*100/25*16=56%

Like? Yes (1) | No (1)  

ruby   9 years AGO

difference b/n area of rectangle and square is 5600.
percentage is 56%

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

Let side = 100 so area = 10000
new length = 130, new width = 120
new area = 15600

%age increment = 5600*100/10000 = 56%

Like? Yes (1) | No (1)  

manohar   9 years AGO

Side of squre be a,
Then length and bredth of rectangle =a+30/100,a+20/100

a*a(1.56-1)=.566

Like? Yes (1) | No (1)  

pandali   9 years AGO

Lets say square initial area :10*10=100;
after inc it 30% and 20% it will become =13*12=area of rectangle =156;
rectangle area is 156
square area is =100
rectangle exceeds square by 56%

Like? Yes (1) | No (1)  

Rudra   9 years AGO

l becomes=1.3 times & b become =1.2 time
so area will be=l*b
=1.3*1.2
=1.56
means increasd by 56%

Like? Yes (1) | No (1)  

rahul shaw   9 years AGO

area of square=l^2
area of rect=( l*B*120*130)/10000=1.56l*B
subtracting both we get
.56=56?
option 10

Like? Yes (1) | No (1)  

NITESH KUMAR SINGH   9 years AGO

let area of sq be x then l of rect=1.3x nd bnreadth=1.2x area of rec=1.56x y=(0.56x/x)*100

Like? Yes (1) | No (1)  

karthiga   9 years AGO

Let side of the square is x;
Area is x^2;
Side increased by 30% &20%..
Area of rectangle is 130x*120x/(100*100)
= 156/100 x^2;
Increased % = 56x/100/(x^2)*100
= 56%.

Like? Yes (1) | No (1)  

Lavanya Rajendran   9 years AGO

130/100*l(*)120/100*b=1.56lb
1.56lb-lb=0.56
=56%

Like? Yes (1) | No (1)  

Tinku   9 years AGO

Since side1 * side2= area.
: Net % change in area
= (x + y + xy /100) %
= ( 30 + 20 + 30*20/100) % ( x = 30, y = 20)
= 56%.
Therefore, the area of rectangle so formed exceeds the area of square by 56%.

Like? Yes (1) | No (1)  

Deepanshu gupta   9 years AGO

Difference comes out to be 28/50 x^2..which is 56%.
Hopefully correct

Like? Yes (1) | No (1)  

Archie   9 years AGO

let original length b l and b be the breadth
New length=13l/10
new breadth=6b/5
Area of square=lb
Area if rectangle =78lb/50
%increase in area=
(((78lb/50)-(lb))/lb)*100=56%

Like? Yes (1) | No (1)  

vimal tiwari   9 years AGO

let 100 be side of square

initial area =10000

after inc sides

new sides 130 and 120

new area =15600

% change = 15600-10000=5600/10000=.56*100=56%

Like? Yes (1) | No (1)  

hemant jain   9 years AGO

old area=X^2
new area=156x^2/100
increase in area=56/100
i.e 56 %

Like? Yes (1) | No (1)  

ArmyKIRI   9 years AGO

length(1+(30/100))*breadth(1+(20/100))=area(1+(ans/100))
ans=56%

Like? Yes (1) | No (1)  

Gaurab Kumar Jha   9 years AGO

Let side of the Square be L
Area Before : L^2
Area After :1.3l * 1.2 l = 1.56L^2
Change in Area = (1.56-1)L^2
Therefore, area increase by : ((0.56*L^2)/L^2 )* 100 = 56 %

Like? Yes (1) | No (1)  

07 Aug 2015 Area

A circular road runs round a circular ground. If the difference between the circumferences of the outer circle and the inner circle is 66 metres, the width of the road is

OPtion

1) 21 m
2) 10.5 m
3) 7 m
4) 5.25 m
5) 6 m
6) 6.5 m
7) 8 m
8) 8.2 m
9) 9 m
10)None of these

Solution

2 Pi R - 2 Pi r = 66
2 Pi (R-r) = 66
Therefore
R - r = (66/2 * 7/22) = 10.5 m

Option 2)

Correct Option: 2 Best Solution (75)

RAKESH   9 years AGO

2*22/7 *(r1-r2) = 66
=> r1-r2 = 10.5

Like? Yes (7) | No (1)  

KSuresh   9 years AGO

let the circumference of the inner circle be 2*pi*r1,
and that of the outer be 2*pi*r2.
given difference i.e., 2*pi*r2 - 2*pi*r1=66
therefore r2-r1=66/2*3.14=10.509

Like? Yes (6) | No (1)  

Kajal Manohar Roshni Rangwani   9 years AGO

2(pi) [(R-r)]=66
therefore difference between the two radii will be the width of the road

Like? Yes (5) | No   

RAHUL DEB BARMAN   9 years AGO

let radius of road and ground be r1 metre, r metre respectively
2*pi*r1-2*pi*r=66
there for , r1-r=(66*7)/(2*22)=42/4=10.5 metre

Like? Yes (4) | No   

Gaurav Kumar   9 years AGO

let the outer radius be R and inner radius is r.
A/q
2?R-2?r=66
(R-r)=21/2=10.5

Like? Yes (4) | No   

mithilesh kumar   9 years AGO

Ans:2*pi*R-2*pi*r=66
so R-r=66*7/2*22 where pi=22/7
=21/2
=10.5m which is width of the road

Like? Yes (4) | No   

suraj bhatt   9 years AGO

2*pi(R1-R2)=66
R1-R2 is the width of the road

Like? Yes (4) | No   

Balkrishna Meena   9 years AGO

R= radius of circular road
r= radius of ground

width of road = R-r = (66/2(pi))= 10.5 m

Like? Yes (4) | No   

Jyotsna    9 years AGO

Let the outer radius be R and inner radius be r, now 2*pi*R-2*pi*r=66
therefore, R-r=66/(2*pi)=66/6.28=10.5

Like? Yes (4) | No   

neha gupta   9 years AGO

let the radius of circular ground be r and final radius after a circular road is constructed around it be R
so , 2*pi*R - 2*pi*r = 66
R - r = 10.5

Like? Yes (3) | No   

ABHINAV PUSHPAM   9 years AGO

Ans: 2
2Ï€(R-r)=60 => 2*22/7 * (R-r)=60.
Therefore, (R-r)= (66*7/44)= 10.5m

Like? Yes (3) | No   

A M ANKIT KALLURAYA   9 years AGO

comparing the difference of the circumferences,we will get the width of the road

Like? Yes (3) | No   

sanjeev kumar   9 years AGO

Suppose r1=radius of ground and r2=redius of road
(2pi)r1-(2pi)r2=66
width of road =r1-r2=10.5

Like? Yes (3) | No   

Megha Goel   9 years AGO

difference between circumference is 66
i.e. 2*pi*R-2*pi*r=66
(R=outer and r=inner)
R can be written as (r+w)
where w= width of road
hence , 2*pi*w= 66
pi*w=33m
w=33*7/22m
w=21/2m
w=10.5m

Like? Yes (4) | No (1)  

ADITYA SARIPALLI   9 years AGO

Let the outer circle radius be "r2"
Let the inner circle radius be "r1"

difference in the circumferences of the 2 circles = 66 m
Hence we have ...

2(pi)(r2-r1) = 66 {where pi = 22/7}
=> (r2-r1) = 66 / (2 * pi)
= (66 * 7) / (2 * 22)
= 21/2
= 10.5 m

Thus width of the road is 10.5 m

Like? Yes (3) | No   

Surit Datta   9 years AGO

2*pi*R - 2*pi*r = 66
(R - r ) = 21/2 = 10.5 m
so option 2
that's it.

Like? Yes (2) | No   

shivjee yadav   9 years AGO

2Ï€R-2Ï€r=66
2Ï€(R-r)=66
R-r=66/2Ï€=66*7/44=21/2=10.5

Like? Yes (2) | No   

Debabrata Dey   9 years AGO

2*3.14*r1-2*3.14*r2=66
=>r1-r2=10.5 m
so width is 10.5m

Like? Yes (2) | No   

Testing Account   9 years AGO

2*pi*outer-2*pi*inner=66
diff.=width of road=66/6.28
=10.5m

Like? Yes (2) | No   

Piyush Telang   9 years AGO

Let radius of outer circle be R and that of inner circle be r meters.
Then according to given condition
2 x pi x R - 2 x pi x r = 66
=> 2 x 22 x ( R - r ) / 7 = 66
=> ( R - r ) = 10.5 m Width of the road is determined by the difference between the Radii i.e. R - r.
Hence 10.5 m is the width of the road.

Like? Yes (2) | No   

sudhir kumar maurya   9 years AGO

we need to find r2-r1
2 * pi *r2 - 2*pi*r1 =66 ( pi=22/7)
r2-r1=66/2*pi
r2-r1=10.5

Like? Yes (2) | No   

Shweta Sharma   9 years AGO

let r of inner circle be x so radius of outer circle will be x+width
diffrence in circumfrence=66=2X22/7(r+width-r)
width=(66X7)/(2X22)
width=10.5m

Like? Yes (2) | No   

RAVAL   9 years AGO

2*pi*outer-2*pi*inner=66
so.diff= width of road = 66/6.28
=10.5m

Like? Yes (2) | No   

Pihu Mascott   9 years AGO

let radius of road and ground be r1 metre, r metre respectively
2*pi*r1-2*pi*r=66
there for , r1-r=(66*7)/(2*22)=42/4=10.5 metre

Like? Yes (2) | No   

santosh kumar patel   9 years AGO

2*22/7*(R-r)=60
therefore, R-r = 66*7/44 = 10.5

Like? Yes (2) | No   

shreya saklecha   9 years AGO

diffrence in circumference=2*(22/7)[R-r]=66 (given)
where R=radius of outer circle and r=radius of inner circle
[R-r]=66/[2*(22/7)]=10.5m

Like? Yes (3) | No (1)  

pratik avinash   9 years AGO

As given the difference between their circumference is 66.
As all know circumference of a circle is 2(pi)r.
So, if we take radius of outer circle is r1 and radius of inner circle is r2.
A/q
2(pi)r1-2(pi)r2=66
so 2(pi)[r1-r2]=66
after solving this we get r1-r2=10.5
and that is thw width of the road.

Like? Yes (3) | No (1)  

velmala gangadhar   9 years AGO

R is the radius of outer circle
r is the radius of inner circle
2Ï€R-2Ï€r=66
width of the road is R-r=(66/2Ï€)=10.5

Like? Yes (2) | No   

SOMA NARESH   9 years AGO

(2*PI*R)-(2*PI*r)=44

2*(22/7)(R-r)=66

R-r=(66*7)/44=10.5

Road width=(R-r)=10.5 meter

Like? Yes (2) | No   

Soma Naresh   9 years AGO

(2*PI*R)-(2*PI*r)=44

2*(22/7)(R-r)=66

R-r=(66*7)/44=10.5

Road width=(R-r)=10.5 meter

Like? Yes (2) | No   

Kuheli   9 years AGO

let R is the radius of the big circle and r is the radius of the small circle
so given that
2*pi*R - 2*pi*r = 66
=> R - r = 33/pi = 10.5

Like? Yes (3) | No (1)  

jayaram   9 years AGO

Because he asked for road width that is the difference between the radius of both circles..
2*3.14(R-r)=64
(R-r)=64/6.28;
=10.5

Like? Yes (2) | No   

Ravi Chauhan   9 years AGO

if outer radius is 2*3.14*R and inner radius is 2*3.14*r and difference is 66m,then R-r=10.5m

Like? Yes (2) | No   

Rishikesh Ranjan   9 years AGO

let r1 is the radius of outer circle, and r2 be the radius of inner circle
2*pi*r1- 2*pi*r2 =66
so r1-r2= 10.5m

Like? Yes (2) | No   

Angeline   9 years AGO

2*pi*R - 2*pi*r = 66
2*pi(R-r) = 66
R-r = 66/(2*pi)
R-r = (66*7)/(2*22)
R-r = 21/2
R-r = 10.5m

Like? Yes (2) | No   

anand vijay   9 years AGO

r=radius of outer circle & r1=radius of inner circle
2pi*r=66+2pi*r1
r-r1=66/2pi=10.5 m (pi=22/7)
option 2)

Like? Yes (2) | No   

laxmikant chhipa   9 years AGO

circumfrences of cirle =2Pir
diff of cir = (2pir1=2pir2) =66
2pi(r1-r2)=66
r1-r2=66/(2x3.14)
r1-r2 =10.5

Like? Yes (2) | No   

rahul shaw   9 years AGO

let inner and outer radius be x and r resp.
thn acc to prblm,
2?(x+r)-2?x=66
r=10.5mt
option 2

Like? Yes (2) | No   

pooja   9 years AGO

(2*r1*pi)-(2*r2*pi)=66
2pi(r2-r1)=66
hence width =10.5m

Like? Yes (2) | No   

Sonu Khandelwal   9 years AGO

outer circle's radius- r1
inner circle's radius- r2
then according question- (2*pi*r1)-(2*pi*r2)= 66
so r1-r2 = 66/2pi= 10.5

Like? Yes (2) | No   

Dipanjan Saha   9 years AGO

2Ï€R-2Ï€r=66;
2Ï€(R-r)=66;
R-r=66/2Ï€
R-r=10.5
Ans. 2)10.5

Like? Yes (2) | No   

ramya   9 years AGO

Inner circle radius =r1
Outer circle radius=r2
Width of the road = r2-r1
So, 2Ï€(r2-r1)=66
r2-r1=10.5

Like? Yes (2) | No   

Rashmi Verma   9 years AGO

2?r2-2?r1=66
2?(r2-r1)=66
r2-r1=66/2?
r2-r1=21/2
r2-r1=10.5

Like? Yes (2) | No   

Anuj Rai   9 years AGO

let the outer radius be r1 and inner radius be r2
as per the question
2*22/7*(r1-r2)=66
where r1-r2= width of the road
r1-r2=10.5

Like? Yes (2) | No   

Ankesh   9 years AGO

given:
difference between the circumferences
of outer and inner circlr is = 66 m
now, we know that circumference = 22/7
to find :
As we have to find width of road between
circle 1 and circle 2 so;
2*(22/7)(R-r) = 66
44/7(R-r) = 66
44(R-r) = 66 * 7 = 462/44 = 10.5
therefore, (R - r) = 10.5

Like? Yes (2) | No   

shubham kumar soni    9 years AGO

Circumference of outer circle =2*pi*r1
Circumference of inner circle =2*pi*r2
Then
2pir1- 2pir2=66
2pi(r1-r2)=66
r1-r2=33/pi
Pi =22/7
So
r1-r2 =10.5

Like? Yes (2) | No   

jaganathan   9 years AGO

It is two circles one around the other.
Let the radius of the inner circle be "r1" and
He radius of the outer circle be " r2" .
We know circumference of a circle is 2*pi*r ( pi=22/7 and r is radius).
Given that:
Difference between circumference of outer and inner circle is "66"
That is.( 2*pi*r2)-(2*pi*r1)=66
r2-r1=66/(2*pi). pi=22/7
( the difference between the radius gives the width of the road )
=(66*7)/(2*22)
=10.5m. Which is the width of the road

Like? Yes (2) | No   

shubhika katarey   9 years AGO

as diffrence b/w circumference of outer and inner circle is 66mts,hence calculating difference 2pie(r+x)-2pie(r)=66, taking r=radius of inner circle and x=width of road,we get x=10.5.

Like? Yes (2) | No   

Shiva Sharma   9 years AGO

2*pi*(R-r) = 66
pi = 22/7
width(R-r) = 21/2
width=10.5

Like? Yes (2) | No   

preksha   9 years AGO

2*pi*(r1-r2)=66
r1-r2=66*7/(2*22)
r1-r2=21/2
10.5

Like? Yes (2) | No   

Narendra Gopi   9 years AGO

Circumference of a circle is 2*pi*r
so difference b/w innner and upper is 2*pi*R-2*pi*r=66
2*pi(R-r)=66
2*22/7(R-r)=66
R-r=66*7/44=10.5

Like? Yes (2) | No   

Ashu Kumar   9 years AGO

LET GROUND & ROAD HAVE RADIUS r &R RESPECTIVELY.
SO 2*22(R-r)/7=66
R-r=10.5
SO CORRECT OPTION IS 2

Like? Yes (2) | No   

AKANSHA SUMAN   9 years AGO

Let the radius of inner circle be r and that of outer circle be R.Now the difference between the radii of these ciercles will give the width of the road i.e.(2*pi*R-2*pi*r)=66.After solving this,we get R-r=66/2*pi = 10.5

Like? Yes (2) | No   

Sushmita Ghanty   9 years AGO

let the radius of the outer circle and inner circle are r1 and r2
so, 2pi(r1-r2)=66
ri-r2=66/2pi=10.5
therefore the width of the road is 10.5m

Like? Yes (2) | No   

Rupa Kumari   9 years AGO

circumference of the circle= 2 Pi * r.
Now, A/c Q, 2 Pi*(R-r) = 66 m
then, width of the road, i.e. (R-r) = 10.5 m

Like? Yes (2) | No   

SOUVIK   9 years AGO

2*22/7(R-r)=66
=>R-r=66*7/44
=>R-r=21/2=10.5 m
[here R is the radius of the circular outer road
r, is the radius of the circular ground
here pi=22/7]

Like? Yes (2) | No   

abhishek kumar   9 years AGO

2*227*R-2*227*r=66 where R is radius of circular road and r bis radius of circular ground. so (R-r)=10.5 width of road

Like? Yes (2) | No   

sai madhuri   9 years AGO

let the radii of ground and road be r,R.
given that 2*pi*(R-r)=66m
from this we can get R-r=10.5m
thus,10.5m is width of road.

Like? Yes (2) | No   

Kshitiz Khandelwal   9 years AGO

let r be inner radius
let x be width of road

then
2*pi(x+r) - 2*pi(r) = 66
on solving
x=10.5

Like? Yes (2) | No   

jaya   9 years AGO

2*22/7(R-r)=66
width of road=R-r=(66*7)/(22*2)
=10.5m
where r and R are radius of outer and inner circle resp.

Like? Yes (2) | No   

Zainab Naseem   9 years AGO

using the formula of circle circumference the value of their differencee comes 10.5m which is not among the given options.

Like? Yes (2) | No   

Subham Mahanta   9 years AGO

Let, the radius of the outer circle is R.
So, the perimeter is 2*pi*R.

Let, thee radius of inner circle is r.
So, the perimeter is 2*pi*r.

Mathematically,
2*pi*R - 2*pi*r = 66
which gives,
(R - r)= 66/ (2*pi)
= 10.5 m
So, option 2 is correct.

Like? Yes (2) | No   

ARJYA HALDER   9 years AGO

Let, the radius of the outer circle is R.
So, the perimeter is 2*pi*R.

Let, thee radius of inner circle is r.
So, the perimeter is 2*pi*r.

Mathematically,
2*pi*R - 2*pi*r = 66
which gives,
(R - r)= 66/ (2*pi)
= 10.5 m
So, option 2 is correct.

Like? Yes (2) | No   

shahida   9 years AGO

let the inner and outer radii be r and R metres..
then 2*22/7(R-r)=66
R-r=66*7/22*2
R-r=10.5

Like? Yes (2) | No   

vimal tiwari   9 years AGO

2* .3.14* r1 - 2*3.14* r2 = 66

r1 -r2 = 10.5m

Like? Yes (2) | No   

Mugesh sivagnanam Krishnapillai   9 years AGO

Let the radius of outer round be R and inner round be r,
2Ï€R-2Ï€r=66
2Ï€(R-r)=66
R-r=10.504.
Thus the width of road is 10.5m.

Like? Yes (2) | No   

Khan   9 years AGO

Circumference of outer circle be 2*pi*R.
Circumference of inner circle be 2*pi*r.
Given difference is 66m.
Hence, 2*pi*R-2*pi*r=66
R-r= 66 / (2 * 3.14)
R-r= 10.5

Like? Yes (2) | No   

Kethineni Vinodh   9 years AGO

2piR-2pir=66
R-r=66/2*pi
Width=R-r=10.5095metres

Like? Yes (2) | No   

Sangeetha G   9 years AGO

diff of circum=2*22/7(r2-r1)=66
so,r2-r1=10.5
ans:10.5

Like? Yes (2) | No   

Nishith HM   9 years AGO

let R be outer radius n r be inner radius given 2piR-2pir=66
solving we will get R-r=10.5m

Like? Yes (2) | No   

Anupam Mukherjee   9 years AGO

2*pi*(outer rad.-inner rad.)= 66 ; therfore, (outer rad.-inner rad.)= 10.5= width of the road

Like? Yes (2) | No   

Archie   9 years AGO

(2*pi*R)-(2*pi*r)=66
R-r=66/(2*pi)
=66/(2*(22/7))
= 10.5 m
where R is radius og road and r i s radius of ground :)

Like? Yes (3) | No (1)  

Prabakaran   9 years AGO

W - width
2*pi(R+W)-2*pi*R=66
2*pi*W=66
W=(66*7)/(2*22)
=10.5

Like? Yes (2) | No   

Devendra Marghade   9 years AGO

If radius of outer circle=R & inner circle=r, then
Width of the road=R-r
Difference between circumference=(2*Pi*R)- (2*Pi*r)=66 , 2*Pi*(R-r)=66, R-r=66/(2*22/7)=10.5
Option 2)

Like? Yes (2) | No (1)  

Kundan Gope   9 years AGO

Let r1 is outer radius and r2 is inner radius
2*3.14*r1-2*3.14*r2=66
r1-r2=10.5 m

Like? Yes (2) | No (1)  

06 Aug 2015 Rank of word

What will be the rank of the word "JAIMATADI" in the dictionary of the words formed by using letter of the word "JAIMATADI". (You have to use all letter in every word)

OPtion

1) 24671
2) 19675
3) 17444
4) 16351
5) 21972
6) 22473
7) 20959
8) 17868
9) 18920
10)21797

Solution

Total number of word formed = 9*8*7*6*5*4*3*2*1/ 3*2*1*2*1
(Denominator is due to repetition of A & I)
= 30240

Now rank of JAIMATADI in dictionary
20160+540+240+18+1 = 20959

Option 7)

Correct Option: 7 Best Solution (16)

Deven Patidar   9 years AGO

AAA D II J M T

A 10080
D 3360
I 6720
J A A 360
J A D 180
J A I A 120
J A I D 60
J A I I 60
J A I M A A 6
J A I M A D 6
J A I M A I 6
J A I M A T A D I 1 = 20959

Like? Yes (1) | No   

Megha Goel   9 years AGO

JAIMATADI contains A-3 D-1 I-2 J-1 M-1 T-1 i.e. 9 letters
words from A _ _ _ _ _ _ _ = 8!/(2!*2!)= 10080
D _ _ _ _ _ _ _ _ = 8!/(3!*2!)=3360
I _ _ _ _ _ _ _ _=8!/(3!)=6720
JAA _ _ _ _ _ _= 6!/2!
JAD _ _ _ _ _ _ =6!/(2!*2!)
JAIA _ _ _ _ _=5!
JAID _ _ _ _ _ =5!/2!
JAII _ _ _ _ _=5!/2!
JAIMAA _ _ _ =3!
JAIMAD _ _ _=3!
JAIMAI _ _ _=3!
next word will be JAIMATADI . Hence adding these numbers we get 20958 and RAnk of word JAIMATADI is 20959.

Like? Yes (1) | No   

sudhir kumar maurya   9 years AGO

arrange in order A,A,A,D,I,I,J,M,T
no. of letters starting with A=8!/2!2! (divide becoz A and I repeated twice)
no. of letters with D = 8!/3!2!(divide by 3! and 2! becoz A and I repeated 3 times and 2 times resp. )
no. of letters with I =8!/3!
next letter will be J so fix J
after J it is A so fix JA after this
no. of letters with A = 6!/2!
no. of letters with D = 6!/2!2!
next letter will be I
so fix JAI
no. of letters with A = 5!
no. of letters with D = 5!/2!
no. of letters with I = 5!/2!
fix JAIMA
no. of letters with A = 3!
no. of letters with D = 3!
no. of letters with I = 3!
fix JAIMATADI
add all factorial + 1 =20959

Like? Yes (1) | No   

Abhishek Sneh   9 years AGO

make JAIMATADI in rank wise ....
like =JAIMATADI
J=4,A=1,I=3,M=5,A=1,T=6,A=1,D=2,I=3

first take J and check the number who less than the valu of J like a,i,a,a,d,i =6 so in this there are a many time i many times so we have to write like 6/3!x2! x8! =20160
for I = 3/2!x2!x6!=540
for M=2!x5!=240
for T =3x3!=18
NOTE rest we leave because something multiply in "0" is equal to 0 ,
after adding all the number we get
20160+540+240+18=20958
add 1 for the position of JAIMATADI = 20959

Like? Yes (1) | No   

Debabrata Dey   9 years AGO

8!/2!2!+8!/3!2!+8!/3!+6!/2!+6!/2!2!+5!+5!/2!+5!/2!+3!+3!+3!+1
=20959

Like? Yes (1) | No   

Dinni   9 years AGO

Arranging in alphabetical order to determine rank of the word JAIMATADI
AAADIIJMT
A - 8!/4
D - 8!/12
I - 8!/6
(JA)A - 6!/2
(JA)D - 6!/4
(JAI)A- 5!
(JAI)D- 5!/2
(JAI)I - 5!/2
(JAIMA)A- 3!
(JAIMA)D- 3!
(JAIMA)I - 3!
(JAIMAT) ADI - 1
Adding we get 20959

Like? Yes (1) | No   

vinusha   9 years AGO

A - 8!/4
D - 8!/12
I - 8!/6
(JA)A - 6!/2
(JA)D - 6!/4
(JAI)A- 5!
(JAI)D- 5!/2
(JAI)I - 5!/2
(JAIMA)A- 3!
(JAIMA)D- 3!
(JAIMA)I - 3!
(JAIMAT) ADI - 1
10080+3360+6720+360+240+180+18+1
20959.

Like? Yes (1) | No   

Kundan Gope   9 years AGO

J A I M A T A D I
_____________________________________________________
4 1 3 5 1 6 1 2 3
_____________________________________________________
6 0 3 4 0 3 0 0 0
---- ----- -----
3!2! 2!2! 2!
_____________________________________________________
X X X X X X X X X
8! 7! 6! 5! 4! 3! 2! 1! 0!

=20160+0+540+240+0+18+0+0+0
=20958
The rank of word is= 20958+1= 20959 (Ans)

Like? Yes (1) | No   

Deepak kumar kumawat   9 years AGO

JAIMATADI there is 9 words
arranging words in alphabatic order
AAADIIJMT
WORD START FROM A= 8!/2!*2!=10080
D=8!/(3!*2!)= 3360
I= 8!/3!=6720
WORD START FROM JA
[JA]A=6!/2!= 360
[JA]D= 6!/(2!*2!)= 180
NOW WORD STARTS FROM JAI
[JAI]A=5!=120
[JAI]D=5!/2!=60
[JAI]I=5!/2!=60
WORD START FROM JAIMA
[JAIMA]A=3!=6
[JAIMA]D=3!
[JAIMA]I=3!
JAIMATADI=1
SO rank of jaimatadi is 10080+3360+6720+360+180+120+60+60+18+1=20959

Like? Yes (1) | No   

Narendra Gopi   9 years AGO

A...........8!/2!*2! =10080
D............8!/3!*2! =3360
I............8!/3! = 6720
J
JA
JAA.......6!/2! =360
JAD........6!/2!*2! =180
JAI
JAIA.......5! =120
JAID........5!/2! =60
JAII..........5!/2! =60
JAIM
JAIMA
JAIMAA.........3! =6
JAIMAD.......3!/2! =3
JAIMAI.........3!/2! =3
JAIMAT
JAIMATA
JAIMATAD
JAIMATADI
Total The word JAIMATADI=20959

Like? Yes (1) | No   

aman agrawal   9 years AGO

in word JAIMATADI first of all we give a temporary no to each alphabet according to the priority of alphabet.so "A" will get 1 priority similarly "D"will get 2 priority & so on.
now from the first letter we check how much priorities are smaller than this (so in case of "J" there are 6 letters whose priority is lesser than the j's priority)
(6/3!*2!)*8!+(3/2!*2!)*6!+(4/2!)*5!+(3/0!)*3!+1 will give the rank of the word"JAIMATADI" which is 20959.

Like? Yes (1) | No   

RAKESH   9 years AGO

8!(1/4 +1/12 + 1/6) + 6!(1/2 +1/4) + 5!(1+ 1/2 +1/2) + 3*3! + 1

= 20959

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

give the numbers according to alphabetical order as
A=1, D=2, I=3, J=4, M=5, T=6
now
Order of Letters J=3 A=1 I=3 M=5 A=1 T=6 A=1 D=2 I=3
For J = 4*8!/(3!*2!) = 20160
For A = 0*7!/(3!*2!) = 0
For I = 3*6!/(2!*2!) = 540
For M = 4*5!/(2!) = 240
For A = 0*4!/2! = 0
For T = 3*3! = 18
For A = 0*2! = 0
For D = 0*1! = 0
For I = 0*0! = 0
For the word JAIMATADI = 1
Total sum = 20160 + 540 + 240+ 18 + 1 = 20959

Like? Yes (1) | No   

Soma Naresh   9 years AGO

give the numbers according to alphabetical order as
A=1, D=2, I=3, J=4, M=5, T=6
now
Order of Letters J=3 A=1 I=3 M=5 A=1 T=6 A=1 D=2 I=3
For J = 4*8!/(3!*2!) = 20160
For A = 0*7!/(3!*2!) = 0
For I = 3*6!/(2!*2!) = 540
For M = 4*5!/(2!) = 240
For A = 0*4!/2! = 0
For T = 3*3! = 18
For A = 0*2! = 0
For D = 0*1! = 0
For I = 0*0! = 0
For the word JAIMATADI = 1
Total sum = 20160 + 540 + 240+ 18 + 1 = 20959

Like? Yes (1) | No   

jomon v j   9 years AGO

A -10080
D -3360

I -6720
JAA-360
JAD- 180
JAIA-120
JAID-60
JAII-60
JAIMAA-6
JAIMAD -6
JAIMAI -6
JAIMATADI-1

TOTAL =20959

Like? Yes (1) | No   

Abhishek Anand   9 years AGO

Explanation :
Write Down the WORD JAIMATADI and assign each letter a value

4 1 3 5 1 6 1 2 3
J A I M A T A D I

8! 7! 6! 5! 4! 3! 2! 1! 0!

now look for the smaller value than 4 towards its ryt side
6 no. are there which is lesser than 4
And,also look how many times letters are repeating .

And then write expression in this manner...

6 / 3!x2! 0/3!x2! 3/2!x2!.....so on upto 0/0!

now multiply the above expression corresponding to the factorials written below to that letter and add them !
At last +1 to the resulting sum !
u got the Answer as 20959! Thanks !

Like? Yes (1) | No   

05 Aug 2015 Series

If 1^2 + 2^2 + 3^2 + ................. 100^2 = A
& 1^3 + 2^3 + 3^3 + .................. 100^3 = B
Then
1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101 will be

OPtion

1) A - B
2) A + B
3) A^2 - B^2
4) A^2 + B^2
5) A^2 - B^3
6) A^3 - B^2
7) A + 2B
8) 2A + B
9) A - 2B
10)2A - B

Solution

1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101
= 1^2(1+1) + 2^2(2+1) + 3^2(3+1) + ........... + 100^2(100+1)
= 1^3 + 1^2 + 2^3 + 2^2 + 3^3 + 3^2 + ......... + 100^3 + 100^2
= (1^3 + 2^3 + 3^3)+(1^2 + 2^2 + 3^2 + ....... + 100^2)
= A + B

Option 2)

Correct Option: 2 Best Solution (32)

RAKESH   9 years AGO

1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101

1^2*(1+1) + 2^2*(2+1) + 3^2*(3+1) + 4^2*(4+1) ........ + 100^2*(100+1)

= (1^3 + 2^3 + 3^3 + .................. 100^3) + (1^2 + 2^2 + 3^2 + ................. 100^2) = B+A

Like? Yes (1) | No   

Narendra Gopi   9 years AGO

A=1^2+2^2+3^2+4^2+......100^2
B=1^3+2^3+3^3+4^3+........100^3
A+B=1^2*2+2^2*3+3^2*4+4^2*5+.......100^2*101

Like? Yes (1) | No   

Soma Naresh   9 years AGO

1^2*2+2^2*3+3^2*4+_ _ _ +100^2*101
=1^2*(1+1)+2^2*(2+1)+3^2*(3+1)+_ _ _+100^2*(100+1)
=(1^3+1^2)+(2^3+2^2)+(3^3+3^2)+_ _ _+(100^3+100^2)
=(1^3+2^3+3^3+_ _ _ +100^3)+(1^2+2^2+3^2+_ _ _ +100^2)
=(B+A)

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ANIKET GAURAV   9 years AGO

As 1^2 + 1^3 = 1^2(1+1) = 1^2*2 .. 2^2 + 2^3 = 2^2(1+2) = 2^2*3 ..... andso on upto 100^2 + 100^3 = 100^2 * 101
Hence A+B is right answer

Like? Yes (1) | No   

Apurva Gupta   9 years AGO

a=n^2
b=n^3
c= N^2*(n+1)
=a+b

Like? Yes (1) | No   

Ayush Singhal   9 years AGO

A+B=(1^2+1^3)+(2^2+2^3)+...........(100^2+100^3)
=1^2(1+1)+2^2(1+2)+..........100^2(1+100)
=1^2*2+2^2*3+...............100^2*101
so answer is A+B (2)

Like? Yes (1) | No   

Kundan Gope   9 years AGO

A+B
1^2+1^3=1^2*2
2^2+2^3=2^2*3
3^2+3^3=3^2*4
...
...
100^2+100^3=100^2*101

Like? Yes (1) | No   

SURAJ KUMAR   9 years AGO

Sum of A=100(1+100^2)/2
=500050
Sum of B=100(1+100^3)/2
=50000050
Sum of (A+B)=50500100
Sum of 1^2*2+2^2*3+...+100^2*101=100(2+100^2*101)/2=50500100
Which is equal to A+B

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

1^2*2+2^2*3+3^2*4+_ _ _ +100^2*101
=1^2*(1+1)+2^2*(2+1)+3^2*(3+1)+_ _ _+100^2*(100+1)
=(1^3+1^2)+(2^3+2^2)+(3^3+3^2)+_ _ _+(100^3+100^2)
=(1^3+2^3+3^3+_ _ _ +100^3)+(1^2+2^2+3^2+_ _ _ +100^2)
=(B+A)

Like? Yes (1) | No   

Deepak kumar kumawat   9 years AGO

By adding these terms we will get the answer
Hence A+B is the answer

Like? Yes (1) | No   

Debabrata Dey   9 years AGO

1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101
=1^2(1+1)+2^2(2+1)+3^2(3+1)+4^2(4+1)+........ 100^2(100+1)
=1^3+1^2+2^3+2^2+3^3+2^2+........100^3+100^2
=A+B
so option 2 is correct...

Like? Yes (1) | No   

aditi arora   9 years AGO

taking first three terms of the series:

1^2+2^2+3^2=14=A
1^3+2^3+3^3=36=B
1^2*2+2^2*3+3^2*4=50
A+B=50

Like? Yes (1) | No   

Manuraj Raghuwanshi   9 years AGO

1^2+1^3=1^2(1+1)=1^2*2..

Similarly for any n..

N^2+N^3=N^2(N+1).

Like? Yes (1) | No   

Sriparna Boote   9 years AGO

1^2+2^2+3^2=14
1^3+2^3+3^3=36
14+36=50

and
1^2*2 + 2^2*3 + 3^2*4 =50

So it will be A+B

Like? Yes (1) | No   

shrishti singh   9 years AGO

the given equation gives
Tn=n^2(n+1)
Sn=Summation Tn
=Summation n^3+Summation n^2
=B+A

Like? Yes (1) | No   

SAURABH SINGH   9 years AGO

add the correspomding digits , which are being satisfied by A+B only

Like? Yes (1) | No   

krishnaveni   9 years AGO

because if u verify A+B the result is equal to th e given series result

Like? Yes (1) | No   

Piyush Telang   9 years AGO

Series ( C ) = 2 x 1^2 + 3 x 2^2 + 4 x 3^2 + .................+ 101 x 100^2
- 1^2 + 2^2 + 3^2 + .................+ 100^2
=> C - A = 1 x 1^2 + 2 x 2^2 + 3 x 3^2 +...................+ 100 x 100^2 = B
=> C = A + B

Like? Yes (1) | No   

Nisha Singh   9 years AGO

A is summation of n^2 & B is summation of n^3
the generalised form of the question is the addtion of the summation of A&B


A= summation of N^2 (N=1 to 100)
B=summation of N^3 (N=1 to 100)

A+B = summation N^2(N+1)
=summation (N^3)+summation(N^2)
=A+B

Like? Yes (1) | No   

sai   9 years AGO

we can write B as
1^2*1 + 2^2 *2+ 3^2*3 + ................. 100^2*100
by adding A and B we get the result

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m.lokeswari   9 years AGO

1^2(1+1)+2^2(1+2)+.......+100^2(1+100)
(1^2+2^2+...+100^2)+(1^3+2^3+.......100^3)
A+B

Like? Yes (1) | No   

Rohit Kumar   9 years AGO

1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101
1^2*(1+1) + 2^2*(1+2) + so on-----
(1^2 + 1^3) + (2^2 + 2^3) + so on----
A+B

Like? Yes (1) | No   

Deven Patidar   9 years AGO

1^3 + 2^3 + 3^3 + .................. 100^3 = B
or B= 1^2*1+2^2*2+3^2*3+...........100^2*100
A= 1^2 + 2^2 + 3^2 + ................. 100^2
A+B= 1^2(1+1) + 2^2(1+2) + 3^2(1+3) + ................. 100^2(1+100)
A+B=1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101

Like? Yes (1) | No   

lavanya   9 years AGO

Consider frst two terms
1+4= 5=A
1+8=9=B
A+B= 14= 2+12=14

Like? Yes (1) | No   

Prabhat Burnwal   9 years AGO

1^2*2=1^2(1+1)
similarlily all term can be written in this form

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RAVAL   9 years AGO

1^2+1^3=1^2(1+1)=1^2*2
2^2+2^3=2^2(2+2)=2^2*4
same as .....
A+B

Like? Yes (1) | No   

Subham Mahanta   9 years AGO

here, 1^2 + 2^2 + 3^2 + ................. 100^2 = A
1^3 + 2^3 + 3^3 + .................. 100^3 = B
so, 1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101
= 1^2*(1+1) + 2^2*(2+1) + 3^2*(3+1) + 4^2*(4+1) ........ 99^2*(99+1) + 100^2*(100+1)
=1^2+1^3+2^2+2^3+3^2+3^3+4^2+4^3..........99^2+99^3+100^2+100^3
= (1^2 + 2^2 + 3^2 + ..... 100^2) + (1^3 + 2^3 + 3^3 + ..... 100^3)
= A + B
ans is option (2)

Like? Yes (1) | No   

Sravani   9 years AGO

1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101
=>1^2*(1+1) + 2^2*(2+1) + 3^2*(3+1) + 4^2*(4+1) ........ 99^2*(99+1) + 100^2*(100+1)
=>1^3+1^2+2^3+2^2+.......100^3+100^2
=>(1^2 + 2^2 + 3^2 + ................. 100^2)+(1^3 + 2^3 + 3^3 + .................. 100^3 )
=>A+B

Like? Yes (1) | No   

velmala gangadhar   9 years AGO

1^2 + 2^2 + 3^2 + ................. 100^2 = A
& 1^3 + 2^3 + 3^3 + .................. 100^3 = B
1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*10
can written as..1^2*(1+1)+ 2^2*(2+1) + 3^2*(3+1) + 4^2*(4+1)
then ans..is A+B

Like? Yes (1) | No   

kousik tankala   9 years AGO

3^2*4=(3^2)(3+1)=(3^3)+(1*(3^2)).....separating every term and picking the common terms simplifies it as A+B.

Like? Yes (1) | No   

Prabakaran   9 years AGO

1^2+1^3=1^2*2
2^2+2^3=2^2*3
....
therefore for A+B the given output will be produced

Like? Yes (1) | No   

ashvini kumar   9 years AGO

1^2*2 + 2^2*3 + 3^2*4 + 4^2*5 ........ 99^2*100 + 100^2*101
=E(n^2*(n+1))=E(n^3+n^2)=A+B

Like? Yes (1) | No   

04 Aug 2015 Ratio

If 6 (A's Capital) = 8 (B's Capital) = 10 (C's Capital), then the ratio of their capitals is.

OPtion

1) 1:3:6
2) 4:6:8
3) 6:8:10
4) 10:8:6
5) 3:4:5
6) 20:15:12
7) 12:15:20
8) 2:5:7
9) 15:20:25
10)None of these

Solution

6A = 8B = 10C = k
Then A = k/6, B = k/8, and C = k/10
Therefore
A : B : C = k/6 : k/8 : k/10
20:15:12

Option 6)

Correct Option: 6 Best Solution (61)

Piyush Telang   9 years AGO

6 A = 8 B = 10 C
Taking A and B
=> 6 A = 8 B => A / B = 8 / 6 = 4 / 3
Taking B and C
=> 8 B = 10 C => B / C = 10 / 8 = 5 / 4
Since A / B = 4 / 3 , B / C = 5 / 4
=> A / B = 4 x 5 / 3 x 5 , B / C = 5 x 3 / 4 x 3
=> A / B = 20 / 15 , B / C = 15 / 12
Now Combining A B and C
We get = A : B : C = 20 : 15 : 12

Like? Yes (16) | No (1)  

Altaf Hussain   9 years AGO

LCM of 6, 8 and 10 is 120
on dividing 120 we have
A/B=20/15, B/C=15/12
A:B:C=20:15:12

Like? Yes (10) | No   

saranya   9 years AGO

6A=8B=10C
=> 3A=4B=5C
A:B=4:3
B:C=5:4
A:B:C= 4*5:3*5:3*4
= 20:15:12

Like? Yes (11) | No (3)  

Sushmita Ghanty   9 years AGO

let 6A = 8B = 10C = x.
Then A = x/6, B = x/8 and C = x/10.
Ratio of A: B : C is x/6 : x/8 : x/10
A = 120*x/6=20x, B = 120*x/8=15x, C= 120*x/10 = 12x.
the ratio of their capitals is 20 : 15 : 12.

Like? Yes (5) | No (1)  

Pritam Das   9 years AGO

6*A/(6*8*10)=8*B/(6*8*10)=10*C/(6*8*10)
Simplifying we get,
A/20=B/15=C/12
=>A:B:C=20:15:12

Like? Yes (4) | No (1)  

Yogendra Kumar   9 years AGO

a:b=8:6 or 40:30
b:c=10:8 or30:24
So, a:b:c = 40:30:24 or 20:15:12

Like? Yes (3) | No   

Ayush Singhal   9 years AGO

given
6A=8B=10C=x(suppose)
so A=x/6
B=x/8
C=x/10
ratio is (1/6):(1/8):(1/10)
Lcm is 120
so ratio is 20:15:12
option (6)

Like? Yes (2) | No   

Debabrata Dey   9 years AGO

(6*A)/(6*8*10)=(8*B)/(6*8*10)=(10*C)/(6*8*10)
=>A/80=B/60=C/48
=>A:B:C=20:15:12

Like? Yes (1) | No   

revathi lakkireddy   9 years AGO

let A=1000, then b=6000/8=750,C=6000/10=600,
A:B:C=1000:750:600=20:15:12

Like? Yes (1) | No   

Narendra Gopi   9 years AGO

c's captil=x/10,
B's capital=x/8
A's capital=x/6
ratio of A,B,C=x/6:x/8:x/10
=20:15:12

Like? Yes (1) | No   

Soma Naresh   9 years AGO

6A=8B=100
6A=8B
B= 3A/4
6A=10 C
C=3A/5
Ratio A:B:C= A: (3A/4):(3A/5)
A: B:C= 1:3/4 :3/5
A: B:C=20:15:12

Like? Yes (1) | No   

Kshitij   9 years AGO

6A=8B=10C
So, A:B=4:3 and B:C=5:4
combine these 2 equations and you will get 20:15:12

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

Let 6(A's Capital)=8(B's Capital)=10(C's capital)=K
Then, A's Capital= K/6
B's Capital= K/8
C's Capital= L/10
so, Tatio of Capital of A:B:C = K/6 : K/8 : K/10
= 20 : 15 : 12

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

A=8B=100
6A=8B
B= 3A/4
6A=10 C
C=3A/5
Ratio A:B:C= A: (3A/4):(3A/5)
A: B:C= 1:3/4 :3/5
A: B:C=20:15:12

Like? Yes (1) | No   

Gaurav Verma   9 years AGO

6a=8b=1oc
6a=8b --1
a/b=4/3 --2 (a=4,b=3)

8b=10c => b/c=5/4 (b=5,c=4)

multiplying 5/3in equation 2, we get a=20,b=15, c=12

Like? Yes (1) | No   

kurmapu satya prasad   9 years AGO

let, 6A=8B=10C=k,
so, A=k/6, B=k/8, C=k/10
therefore, A:B:C=k/6:k/8:k/10 = 20:15:12

Like? Yes (1) | No   

sanjeev kumar   9 years AGO

let , 6A=8B=10C=k
A=k/6
B=k/8
C=k/10
A:B:C=(120/6):(120/8):(120/10)=20:15:12

Like? Yes (1) | No   

D.RAVIKIRAN   9 years AGO

Given B's capital =6/8(A's)
Let A's capital= 1000
then B's capital =750
and C's capital =600
ratio is =1000:750:600
=20:15:12

Like? Yes (1) | No   

TINKU MITTAL   9 years AGO

A:B=8:6=4:3 *5
B:C=10:8=5:4 *3
A:B:C=20:15:12

Like? Yes (1) | No   

Vasudha Singh   9 years AGO

Take LCM of all three numbers that is 6,8 and 10 which comes to 120. taking 120 as numerator , divide 120 by three numbers 6,8 and 12 separately. After solving fractions the answer comes to 20:15:12

Like? Yes (1) | No   

pratyush   9 years AGO

A/C to Qun..
6A = 8B = 10C = K (Let) then
A=K/6,B=K/8 AND C=K/10
then take LCM OF 6,8,10 AND THEN MULTIPLY WE GET
20:15:12

Like? Yes (1) | No   

pranay   9 years AGO

Say 6x=8y=10z=k
Therfore x=k/6,y=k/8,z=k/10.
X:y:z=20:15:12

Like? Yes (1) | No   

sai jeevana   9 years AGO

6A=8B=10C=k then A=k/6,B=k/8,C=k/10
A:B:C=k/6:k/8:k/10
=1/6:1/8:1/10
L.C.M of 6,8,10 is 120
=1/6*120:1/8*120:1/10*120
A:B:C=20:15:12
so answer is option (6)

Like? Yes (1) | No   

aman aditya   9 years AGO

LCM=120
so
a=120/6=20
b=120/8=15
c=120/10=12
so
20:15:12

Like? Yes (1) | No   

Urvashi Jain   9 years AGO

6A=8B=10C=K(LET)
A=K/6,B=K/8,C=K/10
K/6:K/8:K/10
20:15:12

Like? Yes (1) | No   

Priya   9 years AGO

let 6a=8b=10c=k;
so, a=k/6, b=k/8 , c=k/10
a:b:c= 20:15:12

Like? Yes (1) | No   

anand vijay   9 years AGO

6A=8B=10C=k
A=k/6, B=k/8, C=k/10
therefore ratio=k/6:k/8:k/10
=120*k/6: 120*k/8 : 120*k/10
=20 : 15 : 12
option 6)

Like? Yes (1) | No   

Kuheli   9 years AGO

A/B=8/6=4/3
B/C=10/8=5/4
A/C=10/6=5/3
now we have different value of A so we have to multiply with a certain number with A, as well as with B ,and C
so A=20,B=15,C=12

Like? Yes (1) | No   

Dinni   9 years AGO

6(A’s capital)=8(B’s capital)=10(C’s capital)= 1/x

Then, A’s capital=x/6 , B’s capital=x/8, C’s capital=x/10

Ratio of capitals of A,B,C = x/6 : x/8 :x/10

= 20:15:12

Like? Yes (1) | No   

vinusha   9 years AGO

6(A’s capital)=8(B’s capital)=10(C’s capital)= 1/x

Then, A’s capital=x/6 , B’s capital=x/8, C’s capital=x/10

Ratio of capitals of A,B,C = x/6 : x/8 :x/10

= 20:15:12

Like? Yes (1) | No   

avanthika   9 years AGO

6(A’s capital)=8(B’s capital)=10(C’s capital)= 1/x

Then, A’s capital=x/6 , B’s capital=x/8, C’s capital=x/10

Ratio of capitals of A,B,C = x/6 : x/8 :x/10

= 20:15:12

Like? Yes (1) | No   

rajat gupta   9 years AGO

a/b=4/3 and b/c=5/4 so to make b=3 multiply and divide by 3 then a:b:c becomes 4:3:12/5 which is 20:15:12

Like? Yes (1) | No   

Anupreet Kaur   9 years AGO

let the ratio be x
x/6 = x/8 = x/10
take the LCM of all the denominators
LCM = 60
A= 20x , B= 15x , C=12x
Thus , A:B:C = 20:15:12

Like? Yes (1) | No   

sai   9 years AGO

6A=8B=10C
L.C.M of 6,8,10=120
then divide all by 120
then A:B:C=20:15:12

Like? Yes (1) | No   

Subham Mahanta   9 years AGO

let , 6 (A's Capital) = 8 (B's Capital) = 10 (C's Capital) = k
so, A's Capital = k/6
B's Capital = k/8
C's Capital = k/10
so, the ratio of their capital is = A : B : C = (k/6) : (k/8) : (k/10)
= 20 : 15 : 12
so, the ans. is option (6)

Like? Yes (1) | No   

momin ashraf ahamed   9 years AGO

doing LCM for their reciprocals we get the solution as 20:15:12

Like? Yes (1) | No   

prashanth   9 years AGO

Given that 6 (A's Capital)=8 (B's Capital) = 10 (C's Capital) = k
i.e, k/6 = k/8 = k/10
so the ratio is 1/6 : 1/8 : 1/10
from this we get 20 : 15 : 12

Like? Yes (1) | No   

UDIT GAUTAM   9 years AGO

for 20:15:12

let suppose a's capital =20
for 6(a)=8(b)
6*20=8*b
b=15
and 6(a)=10(c)
6*20=10*c
c=12

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Aniketh nangunoori   9 years AGO

let 3a=4b=5c=60(lcm)
a=20
b=15
c=12

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Deven Patidar   9 years AGO

6*A= 8*B= 10*C
(6*20)/20 A = (8*15)/15 B = (10*12)/12 C
120A/20=120B/15=120C/12
A/20 = B/15 = C/12 => A/B=20/15, B/C=15/12
So A:B:C= 20:15:12

Like? Yes (1) | No   

roshni.s   9 years AGO

6A=8B=10C
--> A:B = 8:6 = 4:3
--> B:C =10:8= 5:4
A:B:C = 20:15:12

Like? Yes (1) | No   

deenbandhu Kumar    9 years AGO

When we divide d ratio of capital by total.i.e-24
Den ratio of a capital=24/6=4
Ratio of B capiral=24/8=3
Ratio of C capital=24/10=2.4
So d ratio=4:3:2.4 so d matching answer it we multiply it by 5 is=20:15:12.so it is d right answer

Like? Yes (1) | No   

V.NIVETHA   9 years AGO

A/B=20/15,B/C=15/12 so A:B:C=20:15:12 since 120 is the LCM of 6;8;10

Like? Yes (1) | No   

RAVAL   9 years AGO

LCM of 6,8,10 is 120
so, 120/6:120/8:120/10
= 20:15:12

Like? Yes (1) | No   

Kundan Gope   9 years AGO

LCM of 6,8,10 is 120
6/120, 8/120 10/120 =1/20, 1/15, 1/12
so ratio is 20:15:12

Like? Yes (1) | No   

TARUN CHAUHAN   9 years AGO

let A ,b,c capital be x,y,z respectively

given 6x=8y
therefore x/y=8/6

simlarly 8y=10z
therefore y/z=10/8

therefore x:y:z can be calculated by making value of y equal in both x/y and y/z this can be done by taking LCM of two different y values .

x:y:z=20:15:12

Like? Yes (1) | No   

Archie   9 years AGO

A's capital:B's=8:6
B's:C's=10:8
A's:B's:C's=(8*10):(6*10):(6*8)
=80:60:48
=20:15:12
Hence option 6 is correct

Like? Yes (1) | No   

Nitheesh Aithu   9 years AGO

The LCM of 6,8,10 is 120.The ratio is 120/6:120/8:120/10 =20:15:12

Like? Yes (1) | No   

Ashish Pathak   9 years AGO

6a=8b=10c=k
a=k/6 , b=k/8 ,c=k/10
therefore, a:b:c = 20:15:12

Like? Yes (1) | No   

kondapuram tirumalreddy   9 years AGO

6A=8B=10C
A:B=8:6
B:C=10:8
Multiply
[A:B]×10. and [B:C]×6
We get A:B:C = 20:15:12 by solving

Like? Yes (1) | No   

lavanya   9 years AGO

a=k/6
b=k/8
c=k/10
a:b:c= 1/6:1/8:1/10 = 20:15:12

Like? Yes (1) | No   

ARYA KRISHNAN G   9 years AGO

Let 6A:8B:10C=K
A=K/6,B=K/8,C=K/10
so A:B:C=1/6 : 1/8 : 1/10
=20 : 15:12

Like? Yes (1) | No   

shivam dubey   9 years AGO

Given 6*A = 8*B = 10*C

A/B = 8/6 = 4/3
B/C = 10/4 = 5/4

A/B = 4*5/5*3 = 20/15
B/C = 5*3/4*3 = 15/12

A:B:C =20:15:12

ans

Like? Yes (1) | No   

NAGENDRA P   9 years AGO

3A=4B=5C
4/3 : 1 : 4/5
20:15:12
SO..OPTION (6)

Like? Yes (1) | No   

Amber Singh   9 years AGO

A=8B/6 and B=10C/8
so A/B=4/3 and B/C=5/4
so A/B=20/15 and B/C=15/12
so A:B:C=20:15:12

Like? Yes (1) | No   

jomon v j   9 years AGO

a:b=4:3=20:15

b:c=5:4=15:12

combining these we get a:b:c=20:15:12

Like? Yes (1) | No   

rahul shaw   9 years AGO

let 6A=8B=10C
then 6a=8b
a/b= 4/3
similarly b/c=5/4
so a:b:c= 4*5:5*3:4*3
=20:15:13
option 6

Like? Yes (1) | No   

prasenjit Malakar   9 years AGO

LCM of 6, 8, 10 =120 .So 120/6=20,120/8=15,120/10=12. so ratio is 20:15:12

Like? Yes (1) | No   

Anuj Rai   9 years AGO

6(A’s capital)=8(B’s capital)=10(C’s capital)=x

Then, A’s capital=x/6 , B’s capital=x/8, C’s capital=x/10

Ratio of capitals of A,B,C = x/6:x/8:x/10

= 20:15:12

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

6A = 8B =10C
Representing in terms of A,
A= 6A/8 = 6A/10 and for proportion, equating to common denominator, 80A: 60A :48A = 20 : 15 : 12
Option 6)

Like? Yes (1) | No (1)  

Prabakaran   9 years AGO

A:B=8:6=4:3
B:C=10:8=5:4
B:C can be changed as 5:4=5*3/5:4*3/5=3:12/5
A:B:C=4:3:12/5
so
20:15:12 is the ans

Like? Yes (1) | No (1)  

03 Aug 2015 Sequence

What is the next number of the following sequence.
84, 76, 69, 63, 57, 52, .....

OPtion

1) 44
2) 43
3) 48
4) 45
5) 46
6) 50
7) 51
8) 47
9) 49
10)None of these

Solution

(8)4
84 - (8) = 76
76 - 7 = 69
69 - 6 = 63
63 - 6 = 57
57 - 5 = 52
Similarly
52 - 5 = 47

Option 8)

Correct Option: 8 Best Solution (41)

RAKESH   9 years AGO

decreasing by Tens digit of pre num

52-5 = 47

Like? Yes (1) | No   

neha gupta   9 years AGO

Next Number = Subtracting the first digit of the number from the previous number
84-8=76
76-7=69
69-6=63
63-6=57
57-5=52
52-5=47

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

Subtract tens place digit from the number to get next number
84- 8=76
76- 7=69
69- 6=63
63- 6=57
57- 5=52
52- 5=47
Option 8)

Like? Yes (1) | No   

vinusha   9 years AGO

Present number-first digit digit is the sequence
So 52-5=47.

Like? Yes (1) | No   

shivani gupta   9 years AGO

84-76=8
69-63=6
57-52=5
52-47=5

Like? Yes (1) | No   

avanthika   9 years AGO

84-8=76, 76-7=69, 69-6=63, 63-6=57, 57-5=52
So 52-5=47

Like? Yes (1) | No   

Pinku Burnwal   9 years AGO

sequence is 87,76,69,63,57,52
1st number=87
2nd number is obtained by subtracting digit at tens place=87-8=76
3rd number=76-7=69
4th number=69-6=63
5th number=63-6=57
6th number=57-5=52
7th number=52-5=47
option 8

Like? Yes (1) | No   

Narendra Gopi   9 years AGO

84,76,69,63,57,52..
The difference b/w numbers is :- 8,7,6,6,5, it is following fibonacci sequence so the next number difference is 5...
52-5=47.

Like? Yes (1) | No   

ANKUR ANAND   9 years AGO

Subtract ten's place digit from the whole number
84-8=76
76-7=69
69-6=63
63-6=57
57-5=52
So,52-5=47

Like? Yes (1) | No   

Sourav Chauhan   9 years AGO

My answer is 47 becz the first digit of the number is subtracting from the succeding number..

Like? Yes (1) | No   

GITANJALI GOSWAMI   9 years AGO

FIRST DIGIT IS DECIDED BY THE DIFFERENCE OF SUBSEQUENT NUMBERS.AS THE FIRST DIGIT IS 5(OF 52) THE NUMBER IS 52-5=47
THE LAST DIGIT IS DECIDED BY THE SUMMATION OF DIGITS OF SUCCESSOR OF A NUMBER.SO FOR 52,THE NUMBER IS 47 AS 4+7=1+1=2 i.e,THE LAST DIGIT OF 52..

Like? Yes (1) | No   

RAHUL DEB BARMAN   9 years AGO

the next no in the series is obtained by subtracting the tenth place digit of a no from that no

Like? Yes (1) | No   

santu ghosh   9 years AGO

84-8=76
76-7=69
69-6=63
63-6=57
57-5=52
52-5=47

Like? Yes (1) | No   

rahul shaw   9 years AGO

84-76=8,which is the tenth place digit
similarly for all...
57-52=5
so 52-5=47
option 9

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Piyush Telang   9 years AGO

84 - 8 = 76
76 - 7 = 69
69 - 6 = 63
63 - 6 = 57
57 - 5 = 52
52 - 5 = 47
Preceding value is subtracted by its tens digit number to get the following value in the series.
e.g. 84 is subtracted by its tens digit number '8' to get the following value 76 and similarly 76 is subtracted by its tens digit number '7' to get the following value 69 and so on.
So the value after 52 is 47.

Like? Yes (1) | No   

mustain ahmed   9 years AGO

84-8=76,76-7=69,69-6=63,63-6=57,57-5=52,52-5=47...so is correct ans

Like? Yes (1) | No   

satya ganapathi   9 years AGO

differences betwen previous and next elemnts for the series will be 8 7 6 6 5

Like? Yes (1) | No   

Subham Mahanta   9 years AGO

in the following sequence,
first no. is 84 . first no. of 84 is 8. so if we do (84-8), then we get 76
so, similarly,
76-7 = 69
69-6 = 63
63-6 = 57
57-5 = 52
so the next no. of following sequence is
52-5 = 47
ans is option 8

Like? Yes (1) | No   

Aarti Galar   9 years AGO

the logic is
whatever be the number at tens place is the no. to be subtracted from the no.
Ex. 84
here, 8 is in tens place so we subtract 8 from 84.
so the answer is 8) 47

Like? Yes (1) | No   

Pritam Das   9 years AGO

Number- its tens place digit
84-8=76
76-7=69
69-6=63
63-6=57
57-5=52
52-5=47

Like? Yes (1) | No   

Megha Goel   9 years AGO

84 ;84/10=8;
84-8=76 ;76/10=7;
76-7=69; 69/10=6
69-6=63; 63/10=6
63-6=57 57/10=5
57-5=52 52/10=5
hence
52-5=47

Like? Yes (1) | No   

Abhishek Sneh   9 years AGO

the diff betwn each from left to right is like
8 two times , 6 two times so it will 5 two times
so 52-5=47

Like? Yes (1) | No   

Deven Patidar   9 years AGO

Every next number is= previous number- first digit of previous number
next num in series will be = 52-5=47

Like? Yes (1) | No   

Kundan Gope   9 years AGO

5+2=710 i.e 5 becomes 5+1=6 and 2 from 12 is 2+1=3 i.e 63
6+3=910 i.e 6 becomes 6+1=7 and 5 from 15 is 5+1=6 i.e 76
7+6=13>10 i.e 7 becomes 7+1=8 and 3 from 13 is 3+1=4 i.e 84
so here 47 only the ans.
4+7=11>10 i.e 4 becomes 4+1=5 and 1 from 11 is 1+1=2 i.e 52

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

subtract tenth place number and get next number as-
84-8=76,
76-7=69,
69-6=63,
63-6=57,
57-5=52,
52-5=47
so answer is 47

Like? Yes (1) | No   

Prabakaran   9 years AGO

84 -first digit is 8 so (84-8)=76
76-first digit is 7 so (76-7)=69
69-first digit is 6 so (69-6)=63
63-first digit is 6 so (63-6)=57
57-first digit is 5 so (57-5)=52
52-first digit is 5 so (52-5)=47

Like? Yes (1) | No   

swetha   9 years AGO

the diff btwn each num is the first digit of every num
then after 52 the dif is 5 so the num is 47

Like? Yes (1) | No   

Sushmita Ghanty   9 years AGO

sequence is= prev no-1st digit of prev no.
84-8=76
76-7=69
69-6=63
63-6=57
57-5=52
52-5=47

Like? Yes (1) | No   

Debabrata Dey   9 years AGO

84-(its tens place digit)=next number... and so on...
84-8=76
76-7=69
.
.
.
52-5=47...

Like? Yes (1) | No   

Manikanta   9 years AGO

The answer was 48
Because the first number tens palace will be subtracted from itself to get the next preceding number
ie;
84-8=76;
76-7=69;
69-6=63;
63-6=57;
57-5=52;
52-5=48

Like? Yes (1) | No   

Subham Lal Burnwal   9 years AGO

The ten's place digit is being subtracted in every successive numbers.
That's why 52-5=47.
Option (8) is correct.

Like? Yes (1) | No   

Anupreet Kaur   9 years AGO

subtract the first digit of the number to get the desired number

Like? Yes (1) | No   

vikram   9 years AGO

84(1st digit 8)-8=76,76-7=69,69-6=63,63-6=57,57-5=52,52-5=47

Like? Yes (1) | No   

konduru.sindhu priya   9 years AGO

from the sequence first digit will be 4.so 47

Like? Yes (1) | No   

Amber Singh   9 years AGO

the next term in series is obtained by subtracting the digit in the tens place from the number itself..
84-8=76
76-7=69
69-6=63
63-6=57
57-5=52
52-5=47

Like? Yes (1) | No   

pankaj kumar   9 years AGO

first digit of number is decreases by its number

Like? Yes (1) | No   

Khurshid   9 years AGO

84, 76, 69, 63, 57, 52
second number+first digit of second number=first number
76+8=84
69+7=76
63+6=69
57+6=73
52+5=57
47****+5=52

ANS.47

Like? Yes (1) | No   

sanjeev kumar   9 years AGO

(8*4)/4=8, 84-8=76
(7*6)/6=7, 76-7=69
(6*9)/9=6, 69-6=63
(6*3)/3=6, 63-6=57
(5*7)/7=5, 57-5=52
(5*2)/2=5, 52-5=47

Like? Yes (1) | No   

himanshu shekhar   9 years AGO

each no.can be written as
52=5+2 =7I.e. no carry bit so write it as 57
57=5+7 =12 I.e carry so add 1 to 2 and add 1 to 5 I.e. 63
63=6+3 no carry so 69
69=6+9=15 I.e. add 1 to 5 and add 1 to 6 I.e. 76
76=7+6=13 I.e. add 1 to 3 and 1to 7 I.e. 84
option 8 has answer 47
47=4+7 I.e. 11 add1 to 1 and add 1 to 4 I.e. 52

Like? Yes (1) | No   

Archie   9 years AGO

84-76=8
76-69=7
69-63=6
63-57=6
57-52=5
52-47=5
series is based on differnce between 2 succesive numbers and difference is such that while subtracting the two numbers the result is the digit at ten's place of larger number.

Like? Yes (1) | No   

deenbandhu Kumar    9 years AGO

84-8(1st no)=76
76-7(1st no)=69
69-6(1st no)=63
63-6(1st no)=57
57-5(1st no)=52
52-5(1st no)=47...so 47 is d right answer

Like? Yes (1) | No   

31 Jul 2015 Area

A man builds a circular pool of radius 5 m inside a circular garden of radius 12 m. In order to compensate the area lost due to the construction of pool, he extends the radius by 'r' m while keeping the garden still circular, so that the area of the garden remains the same. The value of r (in m) is

OPtion

1) 1
2) 3
3) Sqrt(3)
4) Sqrt(5)
5) 6-Pi
6) Sqrt(12-5)
7) 5/Pi
8) Sqrt(7)
9) Sqrt(5)-Pi
10)None of these

Solution

Area of garden = Pi*12^2 = 144 Pi m^2
Area of pool = Pi*(5)^2 = 25 Pi m^2
Therefore Pi*(12+r)^2 - Pi*(12)^2 = 25 Pi m^2
Or r^2 + 24 r - 25 = 0
(r+25) (r-1) = 0
r = 1
Option 1)

Correct Option: 1 Best Solution (1)

Subinraj   9 years AGO

If we extend the radius by 1 only,The area of the garden remains the same

Like? Yes (5) | No   

30 Jul 2015 Time and Distance

A man walking at the rate of 3 kmph crosses a square field diagonally in 2 minutes. The area of the field (in ares) is (1 are = 100 m^2)

OPtion

1) 25
2) 30
3) 35
4) 75
5) 45
6) 20
7) 55
8) 60
9) 50
10)65

Solution

Length of diagonal = distance covered in 2 min
= 3600/60 * 2 = 100 m
Area of the field = 1/2 (diagonal)^2 = 1/2 * 100 * 100
= 5000 m^2 = 50 ares

Option 9)

Correct Option: 9 Best Solution (59)

Dinesh kumar   9 years AGO

A man covers the distance diagonally in 2 mins at the speed rate of 3 km/hr...
We converting speed rate into m/min
3*1000/60 = 50m/min
In 2 mins he covers 100m
The distance of diagonal is 100m
By this we can find the length of the square by,
Sin 45 = opp/hyp
1/root 2 =a/100
a=100/root 2
area = a*a = (100/root 2)* (100/root 2)= 10000/2 = 5000 sq.m
In ares = 5000/100 = 50ares

Like? Yes (7) | No (1)  

Gaurav Verma   9 years AGO

60 min ~ 3000m
1 min ~ 3000/60
2min ~ 100m =diagonal

area = 1/2 * d^2
= 5000 m^2 = 50 are

Like? Yes (7) | No (1)  

Abhishek Mohanty   9 years AGO

speed =3kmph=15/18(m/s).
time = 120secs.
so diagonal distance =15*120/18=100.
so area = 5000m^2.
so area in acres=5000/100=50.

Like? Yes (8) | No (3)  

Piyush Telang   9 years AGO

Let 'A' be the measurement of the side of the square field.
Walking Rate = 3 kilometers per hour = 3000 meters per 60 minutes = 50 meters per minute.
If a man walks for 2 minutes along the diagonal of the square field the the distance traveled by him is given as
2 minutes x 50 meters per 1 minute = 100 meters.
Thus Diagonal's measurement is 100 meters.
As we know that Diagonal of a square is given as square root of 2 times the measurement of side of the square.
=> Diagonal = A x sqrt ( 2 ) = 100
=> A = 100 / sqrt ( 2 )
Area of square is given as A ^ 2
=> Area = A ^ 2 = { 100 / sqrt ( 2 ) } ^ 2 = 100 x 100 / 2 = 5000 square meters.
Since 100 square meters = 1 are.
Then Area = 50 ares.

Like? Yes (8) | No (4)  

suriya   9 years AGO

s=2*60=120s;
d=3*(5/18)*120=100m;
area=(d^2)/2=5000m^2
area=50 ares

Like? Yes (4) | No (1)  

ROHIT KUMAR   9 years AGO

speed is 3kmph converting into m/min
we get 3000/60=50m/min
distance cover in 2 min =100m
so diagonal d=100m
area=1/2*d^2
=>1/2*100*100
=>5000 sq.m
=> 50 ares

Like? Yes (4) | No (1)  

MRITUNJAY   9 years AGO

distance= speed *time
=3*2/60=1/10 km= 100m
diagnoal of square =(2)^1/2*a
100m=(2)^1/2*a
a=100/(2)^1/2
area of square= 50 acre. option 9.

Like? Yes (4) | No (2)  

Ayush Singhal   9 years AGO

we know that
distance = speed*time
so length of diagonal= 3*(120/3600) km
= 100 meter
By Pythagoras' theorem
we get
2*a^2=100^2 m^2
so area
a^2=5000 m^2
given
1 are = 100 m^2
so area = 50 are
so answer is (9)

Like? Yes (3) | No (1)  

Vivek   9 years AGO

speed = 3kmph = 3* 5/18 =5/6 m/s
The length of the diagonal = 5/6 * 120 = 100 m
The length of the side = 100/ sqrt(2)
The area of the square = (100/sqrt(2))^2 = 5000 m^2
The area in ares = 50 ares
Therefore the answer is option 9)

Like? Yes (4) | No (2)  

Devendra Marghade   9 years AGO

If side of a square field=x meters, then distance of diagonal crossed in 2 min.=3000*1/30=100 m.
As Diagonal^2=2*x^2, so x=Sqrt(100^2/2)
Area of square field=x^2=Sqrt(100^2/2)^2
=10000/2=5000 m^2
As 100 m^2=1 are, so 5000 m^2=5000/100=50 ares

Answer is Option (9)

Like? Yes (3) | No (1)  

RAHUL KUMAR   9 years AGO

Speed of the man = 3*5/18 = 5/6 m/sec
time taken = 2*60 = 120 sec
length of diagonal = speed*time = 5/6*120=100m
area of field = 1/2*(diagonal)^2 = 1/2*100*100= 5000m^2
so, 1 area = 100m^2, therefore area of field is 50.

Like? Yes (2) | No   

Rupa Kumari   9 years AGO

speed= 3 kmph =5/6 m/s ; time= 120 sec;
Distance= speed*time = (5/6)*120 = 100 m;
diagonal of a square = (sqr root 2)* side = 100 m; area of square=(side)sqr ; so, area = (10000/2)= 5000 m sqr = 50 ares

Like? Yes (2) | No   

Abhishek Sa   9 years AGO

diagonal is 100m....then sides will 5 root 2.....when we find area 25*2=50

Like? Yes (2) | No   

vishal kumar   9 years AGO

The speed of the man in m/min=(3*1000)/60=50 m/min
distance travelled by man=speed*time=50*2=100 m

Diagonal of square is 2^1/2*a where a is side of the square.
a=100/2^1/2.
Area of the square =(100*100)/(2*100) arc
=50 arc

Like? Yes (2) | No   

manish mishra   9 years AGO

by applying speed distance time formula , diagonally distance will be 100 m and after applying Pythagoras theorem it will come 5000 m2 which is 50 are

Like? Yes (2) | No   

Niharika Vardhan   9 years AGO

diagonal is of 100m (as derived by speed and time)
now we have diagonal of square so we find side of square and hence area of square

Like? Yes (2) | No   

aditi goyal   9 years AGO

The area of square is given by...side*side
to calculate the side ..we need to calculate the length of diagnol ..speed is given and time is also given so speed*time=distance i.e diagnol's length
d=3*5*2*120/18*6=100 so diagnol=100/sqrt2 nd area=100*100/2=5000 i.e 5are

Like? Yes (2) | No   

JAHAGIRDAR RUPALI MANOJ    9 years AGO

Dist =speed*time
=3*(5/18)*(2*60)=100m
by using pythagorous theorem
let consider side is 'x'
(100)^2=x^2+x^2
2x^2=100*100
x^2=50*100
area of square is (side)^2
area=5000m^2
area in ares=5000/100=50

Like? Yes (2) | No   

PUSHPENDRA KUMAR   9 years AGO

given that
1hrs=3km
1*60min=3*1000meters
60min=3000 meters
1min=3000/60 meters
1min=50 meters
2min=50*2 meters
2min=100 meters
by using pythagoras theorem
AC^2=AB^2+BC^2
we know that the side of square is equal then
a^2+a^2=100 meters
2a^2=100 meters
a^2=50 meters

Like? Yes (2) | No   

anand vijay   9 years AGO

length of diagonal=3*5*120/18=100m
let x be one of the side of square and y be its diagonal
x^2+x^2=100 (Pythagoras theorem)
x^2=50 (area of square)
option 9)

Like? Yes (3) | No (2)  

K SRILEKHA   9 years AGO

given speed = 3Km/hr
let distance travelled be 'd'
time taken = 2 min = 1/30 hrs
d= s*t = 3*(1/30) = 0.1 km
area of square = (d*d)/2 (since d is diagonal of the square) = (0.1*0.1*1000*1000)/2 sq.m = 5000 sq.m = 50 are
since 1 are = 100 sq.m

Like? Yes (1) | No   

sudiptaa   9 years AGO

d= s*t
= 3 * (2/60)= 1/10 km^2
Area of a square = A= 1/2 * d^2= 1/200 km^2
= 50 ares

Like? Yes (1) | No   

Narendra Gopi   9 years AGO

length of diagonal=distance covered in 2min=3000/60*2=100m
area=1/2*100*100
=5000m^2=50ares

Like? Yes (1) | No   

Anuj Rai   9 years AGO

Length of diagonal= distance covered in 2 minutes=3000/60*2=100m
Therefore, required area= 1/2*100*100=5000m^2
and 1 are=100m^2
so the area of square is 50 ares

Like? Yes (1) | No   

Anuj Rai   9 years AGO

Length of diagonal= distance covered in 2 minutes=3000/60*2=100m
Therefore, required area= 1/2*100*100=5000m^2
so the area of square is 50 ares

Like? Yes (1) | No   

Dinni   9 years AGO

Length of the diagonal= Distance covered in 2 min. at 3 km/hr.

= (3000/ 60 *2)= 100m.

Therefore, Area of the field= 1/2 * diagonal2

= ½ * 100*100 = 5000 m2=50 ares.

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Sushmita Ghanty   9 years AGO

he goes 3000 metres in 60 minutes
then he goes in 2 minutes 3000*2/60= 100 metres
hypotenuse^2 = base^2 + perpendicular ^2
so, 100^2 = 2 * base^2
base^2= 5000m^2
area= 50are

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Deven Patidar   9 years AGO

let square field's side length= a
so diagonal will be= root(2)*a;
and area will be= a^2;

now 3km=3000m in 1hour(60 minute) (given in question)
distance traveled in 1 minute= 3000/60=50;
so distance traveled in 2 minute= 50*2=100meter(=Diagonal length)
diagonal length=(root 2)*a;
100=(root2)*a => a=50*(root 2)
AREA=a^2 => [50*(root 2)]^2=50*50*2=5000meter^2
in question 1=100m^2 so AREA = 5000m^2/100m^2=50

given

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neha kumari   9 years AGO

time=2min=1/30 hr
speed= 3km/h
distance of diagonal= speed*time=1/10km
area of square = 1/2 *diagonal^2=5*10^(-3)km^2 = 50are

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praveendas   9 years AGO

length of the diagonal sqroot(2)*a=3*(1000)*2/60=100.
from this we have a=100/(sqrroot(2))..
a^2=10000/(2*100)=50ares

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S R Y Farhan   9 years AGO

x m is the side of the square;
speed = distance time
speed = 3 kmph = 300060 mpmin
distance = 2^0.5*x
time = 2 min
on putting the value we get x = 100/2^0.5
we want x^2 100 are = 50 .
ans = 50 .

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PraveeNkumar   9 years AGO

In a square, All sides are equal
Length of diagonal of square =(3)(2/60)
=0.1km =100m
Therefore from Pythagaros theorem,
we have a^2 +a^2 =100^2
2a^2 =10000m
Therefore, a^2 = 5000m
Hence option 9) 50

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shivani gupta   9 years AGO

s=3kmph=3*5/18m/s
t=2min
d=5*2*60/6
d=100m
(100)^2=x^2+x^2
10000=2x^2
5000=x^2
1 area=100m^2
100m^2=1area
1m^2=5000/100=50m^2

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G Mounika   9 years AGO

Speed of the man= 3 Kmph =3*(5/18)= 5/6 m/sec
Time taken to cross square field diagonally = 2 min = 120 sec.
Length of diagonal = (5/6)*120 = 100 m
Let the side of the square = a m
according to pythogoras theorem
a^2+a^2= 100^2.
2a^2=10000
a^2=5000 m^2.
The area of the square = 5000 m^2.
1 are= 100 m^2
so 5000 m^2 =5000/100 are = 50 are.

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Praveenkumar Kalikeri   9 years AGO

In square , All sides are equal...
let us assume it to be ' a 'meters.
Length of diagonal= (3)(2/60) =0.1 km.
0.1 km =100 m
Therefore., a^2+a^2=100^2
2a^2=100^2
a^2=5000
Therefore area of square is 5000 m ?? a^2 =50.

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V.Latha   9 years AGO

S = 3kmph = 50mpm
t = 2m
st=d
d=50*2 = 100 m*2
d was the diagonal distance
so
Length of the diagonal = √(a2 + a2) = √(2a2^2) = a√2 units
a√2 = 100
a = 100/√2
area = a*2 = 5000 m*2
1 are = 100 m*2
there fore area in are = 5000/100 = 50 are

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Santosh Kumar   9 years AGO

Distance travelled by man in 2 mints=3000/60 *2=100m
this becomes the digonal of the square.
Hence,area of square=1/2*(digonal)^2
=1/2*100*100=5000m^2
required ans=5000/100=50

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Rajeswar Guin   9 years AGO

3000*2/60=100m distance he covered
sqrt(2)*side=100,side=50sqrt2
area=side*side=5000 m2=50 acre

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Ria Chandra   9 years AGO

let sides of the square field be s
length of diagonal will be s*(2^(1/2))
speed of the man is 3 kmph
and if he could cover the diagonal in 2 minutes the the lentgh of the diagonal will be 3*2/60=0.1 km
so s will become .1/(2^1/2) hence area is 5000 meterquare.Since 1 are = 100 m^2,
so area will become 50 are

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g lokesh   9 years AGO

diagonal=speed*time
=120*5/6
=100m
area=1/2*(diagonal)*(diagonal)
0.5*100*100
=5000 ares

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GITANJALI GOSWAMI   9 years AGO

3 kmph=3000/60=50mt/min
2 min=100metre
sqrt2*a=100
a^2=10000/2
=5000 m^2
=50 arc

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THUMMALA VINEESHA   9 years AGO

area of the diagonal=(3*1000/60)*2= 100m
area= (1/2)diagonal^2= 10000/2=5000m^2=50(100m^2)=50are

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santosh kumar patel   9 years AGO

Length of diagonal = distance covered in 2 min = (3000/60)*2
= 100m
so required area= (1/2)*100*100 = 5000m^2
=50 ares

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Yogendra Kumar   9 years AGO

2^1/2(a)=3*5/18*2*60=100
or a=100/2^1/2
So, area=a^2=5000 m^2 = 50 ares.

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paavai   9 years AGO

diagonal d^2=a^2+a^2
d =(2a^2)^(1/2)
=(2^(1/2))*a
distance =speed*time
(2^(1/2))*a=3*(5/18)*2*60
(2^(1/2))*a=100
a=100/(2^(1/2))
area of square=a^2
=(100/(2^(1/2)))^2
=(100*100)/2
=50*100 m^2
=50ares(as 1 are=100m^2)

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Amit ambastha   9 years AGO

since distance will be equal to its diagonal which is equal to sqrt(2)a, and distance is equal to speed *time . speed = 3*1000/60 (chngs in meter per min) and time = 2 min so put all these in equation and from their we get the value of a. which is 10/sqrt(2) , and area of square is a^2 so we get 50 answr by solving

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BalaGanesh S   9 years AGO

diagnol=3*(5/18)*2*60=100 mtrs=sqrt(2*a^2)
a^2=5000
1are=100m^2
area=50 ares

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Sravani   9 years AGO

Distance covered by man=(3*2*1000)/60=100m=Diagnol of the square
If 'a' is side of square 2a^2=(100)^2
a=5000m^2
=50ares

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venkatasubbareddy   9 years AGO

diagonal =3*(5/18)*2*60 meters

area = d^2/2;
=50 ares

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santu ghosh   9 years AGO

let, the length one side of squre field=a
so,a*2^0.5=(3000*2)/60
so area =a^2=100^2/2 m2=50ares

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Rahul kumar   9 years AGO

let side of square be 'a' m
diagnol=√2 a =distance travelled
d=speed*time
√2a=3*(5/18)*120
a =100/√2
area =a*a=10000/2=5000 m^2 =5000/100 are=50 are

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UJJWAL KANT   9 years AGO

let side of square be 'a' m
diagnol=√2 a =distance travelled
d=speed*time
√2a=3*(5/18)*120
a =100/√2
area =a*a=10000/2=5000 m^2 =5000/100 are=50 are

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saravanan.m   9 years AGO

a man walks at the rate of 3 kmhr = (3*5/18) msec = 5/6msec
he takes 120secs to cross the square field diagonally (ie., 2 mins)
distance=speed*time
= (5/6)*120 m = 100 m
the distance of diagonal of a square field is 100 m
now, area of the square field is = (1/2) of diagonal^2(m^2)
= (1/2)*(100^2) m^2
=5000 m^2
given, 100 m^2 = 1 acre
then 5000 m^2 = (1/100) * 5000 acre
= 50 acre
the ans. is option 9

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aadi   9 years AGO

Use simple speed=distance/time to find the distance travelled by the man. This is also the length of diagonal of the square.
Since, length of side =diagonal/sqrt(2),
the area can be calculated by square of length of side.

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Pinku Burnwal   9 years AGO

man's walking speed=3 kmph= 50 m/min
let, side of square field be x metre
therefor, length of diagonal=x√2 metre
according to above condition,
x√2/50=2
which give,x=50√2
area of field in ares=50
option 9

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Sanjeetha.R   9 years AGO

speed=3km/hr
=5/6 m/sec.
time=2 min =120 sec
distance=speed*time
=(5/6)*120
=100m
area of the square= (diagonal^2)/2
=5000m^2
=50 acre

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Rajan kumar   9 years AGO

diagonal of square=100 m
then area= 1/2(100)^2
=50

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sai   9 years AGO

the total distance covered by him=time taken *speed
=2/60*3=1/10 km
=100 m
the diagonal of a square= sqart(2)*side=100
then side= 100/sqrt(2)
area = (100*100)/(2)=50 ares

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Testing Account   9 years AGO

initial velocity(u)=3kmph=5/6 m/s
time (t) = 2 min.= 120 second
final velocity(v)=0 m/s
distance(s)= t(u+v)/2
solve this formula and get 50m .
so the required ares is 50
amswer is 9) 50

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