M4maths Previous Puzzles

15 Jul 2015 Time and Distance

Mukesh has to cover a distance of 6 km in 45 min. If he covers one half of the distance in 2/3 of the time, what should be his speed to cover the remaining distance in the remaining time?

OPtion

1) 18 kmph
2) 16 kmph
3) 8 kmph
4) 10 kmph
5) 3 kmph
6) 14 kmph
7) 15 kmph
8) 5 kmph
9) 12 kmph
10)None of these

Solution

Distance covered = 3 km
Time taken = 2/3 * 45 = 30
Remaining distance = 3 km
Remaining Time = 15 min
Required speed = D / T
3 / (15/60) = 12 kmph

Option 9)

Correct Option: 9 Best Solution (79)

priya paul   9 years AGO

45min time - 6km dist.
2/3 of time - 1/2 dist.=30min - 3km dist.
rest time=(45-30)=15min and rest dist=(6-3)=3km
so 15 min - 3km
1 min - 3/15
60min - 3/15)*60
=12km/hr. ans.
pp

Like? Yes (5) | No   

lokesh   9 years AGO

required speed = remaining distance / remaining time
= 3 km / 15 min
= 12 kmph

Like? Yes (4) | No (1)  

Ankita Sharma   9 years AGO

Total distance = 6km
Total time =45 min
Total distancce covered in 2/3 of time(i.e. 30 min) = 3 km
so the distance left to be covered = 3 km
and the time remaining = 15min=15/60 hours=1/4 hours
so the speed should be = remaining distance/remaining time
=3/(1/4)=3*4=12kmph

Like? Yes (3) | No   

santu ghosh   9 years AGO

remaining distance=6/2km=3km
remaining time=45-(45*2/3)min=15min
so ,his speed to cover the remainig dist, & rem. time =(3/15)*60=12kmph

Like? Yes (3) | No (1)  

Shiva Sharma   9 years AGO

3 km covered in 30min
3 km covered in 15 min which is 1/4 hr
So speed = 3*4 = 12 Km/hr

Like? Yes (3) | No (1)  

G Mounika   9 years AGO

Mukesh covers one half of the distance in 2/3 of the time.
Total distance=6 km
Remaining distance= 6 - (1/2*6) = 3 km.
Total time = 45 min.
Remaining time = 45 - (2/3*45) =15 min = 1/4 hr.
Speed= Remaining distance/ Remaining time
Speed= 3 km/ (1/4) hr =12 kmph.

Like? Yes (2) | No   

SAYAN CHATTERJEE   9 years AGO

he covers 3 km in 45*2/3= 30 min
so he has to cover remaining 3 km in 15 min
so speed will be 3/15 km/min
= 3/15*60= 12 kmph (9)

Like? Yes (1) | No   

pankaj kumar   9 years AGO

solu:- total distance = 6 km .
total time = 45 min.
one half dist coverd in 2/3 of time
so, he coverd 3km in 30 min
again , remaining dist = 3km
remaining time = 15 min
speed in kmph = dist/ time = 3* 60/15= 12 kmph
ans option is 9.

Like? Yes (1) | No   

ramakrishnateja   9 years AGO

given the dist=6km. one half of the dist = 3km time for that is 30 min. so rem dist =3km time left=15 min. speed=3km/15min=12kmph

Like? Yes (1) | No   

ankit dhingra   9 years AGO

6 km covered in 45 min
condition gives ,
1st 3 km covered in 30 min
so, next 3 km must be covered in 15 min
so, speed = D/T = 3/.25 [.25 as 15 min is 1/4th of an hour]
= 12 kmph

Like? Yes (1) | No   

shivjee yadav   9 years AGO

1/2 of his distance in 2/3 time..that means 3km distance in 45*2/3=30 minute.rest of distance 3 km in 15 minute(1/4 hour) that means distance cover 1/4 hour =3km,in 1hour must be 3/1/4=3*4=12kmph

Like? Yes (1) | No   

mamta kumari   9 years AGO

remaining distance = 3km
remaining time=1/3*45 = 15min=1/4hr
so . required speed = 3*4 km/hr =12km/hr

Like? Yes (1) | No   

SAURABH SINGH   9 years AGO

in remaining one third time i.e. 15 min he travells 3 km
that's why in 60 min he will travel 12 km.

Like? Yes (2) | No (1)  

rammohanrao   9 years AGO

half time means 3 hrs 30 mins he travelled
remaining 3 km he travelled in 15 means so (3*60)/15

Like? Yes (1) | No   

ruby karmakar   9 years AGO

3km 30 min. Speed for remaining 3km is 3000/(15*60)=10/3m/s. 10/3*18/5= 12kmph

Like? Yes (1) | No   

saikumar   9 years AGO

He covers 3km in 30 min,then he has to travel more 3km in 15min.so 15min=1/4hr
dis=speed*time
3=speed*1/4
speed=4*3=12

Like? Yes (1) | No   

charul kardam   9 years AGO

he travels first half i.e 3km in 45*2/3 min=30 min=1/2 hr
thn for nxt 3km in left 15min speed=distance/time= 3/(15/60)= 12kmph

Like? Yes (1) | No   

Aishwarya Buktare   9 years AGO

Mukesh has to cover 3kms in o.25 hr
3km : 0.25 hr
x : 1 hr????
x will give the answer.

Like? Yes (1) | No   

shiva   9 years AGO

He covered half of the distance in 2/3 of the time i.e., in 30 min, Then he has to cover the remaining 3 km in 15 min .
So his speed must be at 12 kmph to reach his destination

Like? Yes (1) | No   

palu   9 years AGO

he covers 6km - 45 min.
given 1/2(distance - 2/3(time)
=> 3km in 30 min
now remaining time is 45-30=15 min
rest is 3km in x min.
speed=d/s= 3km/15min=3*4=12. (14 min=1/4 hour)

ans) 12 kmph

Like? Yes (1) | No   

akanksha   9 years AGO

3 km is covered in 30 min
now time left is 15 min=3/12 hr
remaining distance=3 km
so speed must be=D/T=(3*12)/3=12kmph

Like? Yes (1) | No   

Kirty   9 years AGO

total dist=6 km
half distance=3 km in ((2/3)of 45 min)i.e. in 30 min
remaining distance=3 km in (45-30)min
speed=3*60/15 km/h
=12 km/h

Like? Yes (1) | No   

bhavya dubey   9 years AGO

mukesh had to cover 6 km in 45 min. he has covered half of distance means 3 km of distance in 2/3 of time means in 30 min. remaining time =45-30=15min
remaining distance=6-3=3km
speed=((3/15)*60)=12kmperhour

Like? Yes (1) | No   

Manish kumar   9 years AGO

6 km in 45 min.
6*(1/2)=3km in 45*(2/3)=30 min.
then 3km remaining in 15 min.
thus speed=3/(15/60)=12kmph

Like? Yes (1) | No   

ROHIT KUMAR   9 years AGO

Cover distance of 6 km in 45 min
Covers 6*1/2 in 45*2/3 min
i.e 3 km in 30 min
so remaining distance of 3 km should be cover in 15 min.
so speed= 12kmph

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

Distance remaining =3 Km, Time remaining=(1/3)*45 min.=15 min=1/4 hour
So required speed=3/(1/4)= 12 Kmph
Option (9)

Like? Yes (1) | No (1)  

Piyush Telang   9 years AGO

Total Distance ( D ) = 6 km
Total Time ( T ) = 45 min = 3/4 hr
Half Distance ( d1 ) = D / 2 = 3 km
Time Taken to cover d1 distance ( t1 ) = 2/3 x T = 1/2 hr
Remaining Distance ( d2 ) = D - d1 = 3 km
Time Left to cover d2 distance ( t2 ) = 1/3 x T = 1/4 hr
Speed required to cover d2 distance in t2 time is given as
S = d2 / t2 = 3 km / (1/4 hr) = 12 km/hr

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   9 years AGO

6KM in 45 min
Also given that 3 km he takes 2/3*45 = 30 min
It means he has 15 min left to travel 3km.
So 3/15*60 = 12 kmph
or

Time left = (1/3×45/60) hr = 1/4 hr
Distance left = 3 km
Speed required = (3+1/4) km/hr = 12 kmph

Like? Yes (1) | No (1)  

neha gupta   9 years AGO

Mukesh has covered 3 km in (2/3 of 45) 30 minutes.
Remaining distance= 3 km
Remaining time = 45-30 = 15 minutes = 15/60 = 1/4 hrs
speed required = 3/(1/4) = 3*4 = 12 kmph.

Like? Yes (1) | No (1)  

Dinni   9 years AGO

6km=45min
Given he has covered, 3km=30min
Remaining 3km should have to travel in 15 min
So, speed=(distance/time)
X=3/15*60 =12km/hr.

Like? Yes (1) | No (1)  

Nishant kumar   9 years AGO

one half distance is 6/2= 3
2/3 time of 45min = 30min
remaining 3 km should cover in 15 min
then speed should be- 12 kmph

Like? Yes (1) | No (1)  

Sukanya   9 years AGO

3km in 30 min is 6km/hr

Remaining 3km in 15 min is 12km/hr

Like? Yes (1) | No (1)  

Dinesh kumar   9 years AGO

He covers 1half in 2/3 of time.
45*(2/3)=30.
He covers the remaining distance (3 kms ) in 15 mins.
Therefore in 1 Hr he covers 12 kms.
therefore 12 kmph.

Like? Yes (1) | No (1)  

Archie   9 years AGO

Remaining dist=6km/2=3kms
Time taken to cover 3 kms =(2/3)*45=30mins or 1/2 hrs
Time left =15mins
Required speed
=Dist. left/Time left
=3/15mins
=(3*60)/15 kmph
=12kmph
Hence option 9 is correct

Like? Yes (1) | No (1)  

praveendas   9 years AGO

2/3 of time is 30 min coverd 3 km.
in order to cover 3km in 15 min the required speed is (3/15)*60=12

Like? Yes (1) | No (1)  

Soma Naresh   9 years AGO

remaining distance is 3 km
remaining time= 15 min
speed = 3km÷15 min
3×60/15 kmph
12kmph

Like? Yes (1) | No (1)  

Asha Verma   9 years AGO

Time in which rest distance of 3 Km has to be covered is = T-(2/3 )*T= T/3
Thus time= 45/3= 15min
Speed= 3÷(15/60)=12 km/hr

Like? Yes (1) | No (1)  

Sunil Sharma   9 years AGO

half means 3 km in 30 min
and rest 3 km in 12kmph

Like? Yes (1) | No (1)  

ANKUR ANAND   9 years AGO

left distance=3km
left time=15 min
So, required speed =(3*60/15)kmph=12kmph

Like? Yes (1) | No (1)  

SOMA NARESH   9 years AGO

another half of distance = 3KM
Remaining time = (1/3)*45 = 15min
speed = 3KM/15 min = 3*60/15 = 12 Kmph

Like? Yes (1) | No (1)  

Patralika Mitra   9 years AGO

6km -> 45 min
(1/2) * 6 = 3km and (2/3) * 45 = 30 min
Remaining time = 15 mins = 15/60 = 1/4 hour
Remaining distance = 3km

speed = dist/time = 3/(1/4) = 12km/hr

Like? Yes (1) | No (1)  

anand vijay   9 years AGO

time required to cover 3 km(i.e half of distance)=2/3*45 min=30 min
required speed to cover rest of the distance=left distance / left time=6-3/45-30=3*60/15 =12 kmh (1hour=60 minute)
option 9)

Like? Yes (1) | No (1)  

vivek kashyap   9 years AGO

left distance=6*(1-1/2)=3km
time left=(45/60)(1-2/3)=1/4 hr
required speed=3*4=12km/hr

Like? Yes (1) | No (1)  

Abhinav Jain   9 years AGO

3 KM distance is covered in 30 mins
and 3 Km distance is to be covered in remaining 15 mins
so the speed should be 12kmph

Like? Yes (1) | No (1)  

krishna chandrika   9 years AGO

6km in 3/4hr

one half distance i.e 3km in 2/3of time=2/3*3/4=1/2
3km in 1/2hr

remaining time=1/4hr
remaining distance=3km

speed=distance/time
=3*4 = 12kmph

Like? Yes (1) | No (1)  

k sureshbabu   9 years AGO

3KM COVERD IN 30MIN
REMAINING 3KM HAS TO COVER IN 15MIN
SO 4*3=12KMPH

Like? Yes (1) | No (1)  

Balaselvaraj M   9 years AGO

speed equal to distance/time.
he have also covered 3Km in 30 minutes.
so he should covered remaining distance of 3Km in 15minutes.
therefore the speed is 3*60/15 equal to 12Kmph.(here minutes are converted into equivalent hours)

Like? Yes (1) | No (1)  

SHUBHAM RAJ   9 years AGO

half distance cover in 2/3 of 45min
then remaining time to cover other half = 45*2/3= 15min

speed = 3km/15min *60 = 12kmph

Like? Yes (1) | No (1)  

RAJAT KHANDELWAL   9 years AGO

remaining distance = (1/2)*6= 3
remaining time = (1/3)*45 =15 min

speed = distance/time =(3/15)*60=12 km/hr

Like? Yes (1) | No (1)  

raviteja   9 years AGO

3km in 2/3 hr.
rem = 3km
rem time= 15min=1/4 hr
speed =3/1/4=12

Like? Yes (1) | No (1)  

kvsnlr   9 years AGO

remaining distance=3km
remaining time=15 min=0.25hr
velocity=distance/time=3/0.25=12kmph

Like? Yes (1) | No (1)  

Lavanya Rajendran   9 years AGO

30min=3km
Thn with remaining 15min he has to cover 3km so speed =(3*60)/15=
12km/hr

Like? Yes (1) | No (1)  

pooja jha   9 years AGO

initially distance =6/2=3km
time taken=45*2/3=30 min.
so reamianing time=15min and distance=3km.
therefore speed=3/(15/60)=12kmph

Like? Yes (1) | No (1)  

prem kishor   9 years AGO

time taken in cover half distance=30min
then left time=15min=14hr
so, speed= 3(14)=12kmph

Like? Yes (1) | No (1)  

Pinku Burnwal   9 years AGO

remaining distance=total distance-distance cover=6-3=3Km
time left=45-(2/3*45)=15min=15min
speed required=3*60/15=12kmph
option 9

Like? Yes (1) | No (1)  

Nitish Kumar Mahto   9 years AGO

first half distance travelled by 30 min. and in rest 15 min travell he should go 3km .ie speed=3km/(15/60)hr. which gives the required speed ..ie 12kmph

Like? Yes (1) | No (1)  

Deepak   9 years AGO

Remaining time, t = 15 / 60 hr,
Remaining distance to be covered, d = 3 km,
Speed = d/t = 3 * 60 / 15 = 12 kmph

Like? Yes (1) | No (1)  

pratyush   9 years AGO

he covers 3 km in 1/2 hr
Now remaining time (3/4-1/2)=1/4 and remaining distance=3km
so, Required speed=3*4=12

Like? Yes (1) | No (1)  

swethakottakota   9 years AGO

remaining time = 15 minutes= 1/4 hr

velocity = 3km/ .25 hr = 12kmph

Like? Yes (1) | No (1)  

vivek   9 years AGO

Remaining distance=3km
Remaining time=15 min
Speed= 3*60/15=12 km/hr

Like? Yes (1) | No (1)  

Ashu Kumar   9 years AGO

T=45MINUTE=(3/4)HOUR ,L=6 KM
V1=(L/2)/T1=3/(1/2)=6
V2=(L/2)/T2=3/(1/4)=12 ANSWER

Like? Yes (1) | No (1)  

JAHAGIRDAR RUPALI MANOJ    9 years AGO

Mukesh cover the 6 Km distance in 45 min.
for half of dist. i.e.3 km in 2/3 means 45*(2/3)=30 min

then remaining distance is 3 km covers in 15 min.
for calculating the speed use
Velocity=distance/time
v=3km/15 min
v=3/(15/60)=12kmph.
option 9)

Like? Yes (1) | No (1)  

Anubhav jain   9 years AGO

speed=d/t
speed=6*60/45=8 kmph
If half distance is 3km cover in 2/3 time(30 min)
Speed= 3*60/30=6 kmph
then remain. distance cover in remain. time is speed
d=3km
t=15min
Speed= 3*60/15=12kmph

Like? Yes (1) | No (1)  

rahul shaw   9 years AGO

one half means 3km which has been covered in ? of 45 min=30 min
so remaining time=15min and uncovered distance is 3km
speed =dist/time
(3*60)/15=12 km/hr
60 is multiplied because of conversion of min to hour.

Like? Yes (1) | No (1)  

ANKIT NIGAM   9 years AGO

bcz time factor will remain the same throughout the journey

Like? Yes (1) | No (1)  

sai   9 years AGO

he has to cover 6km in 45 min so that the speed is 6/3/4=8 km/hr
but he cover 1/2 of the distance i.e 3 km in 2/3 rd of the time i.e 30 min.
so he has to cover 3 km in 15 min..
so the speed=3/1/4=12 km/hr

Like? Yes (1) | No (1)  

sowjanya kasam   9 years AGO

6km->half=3km
45mins->2/3=30mins
remaining 15mins and 3km in order to achieve it he has to travel 12kmph

Like? Yes (1) | No (1)  

Ravikesh Kumar   9 years AGO

total 6km,time 45min=3/4hr
he covers half distance in 30mins i.e.1/2 hr
so,remaining distanc=3km and remaining time is 1/4hr
speed=distance/time=3/(1/2)=12km/hr

Like? Yes (1) | No (1)  

Deshbhushan Shivgonda Patil   9 years AGO

He covers 3km in 2/3 time means in 30 min. Then he has to cover another 3 km in 15 mintus so 3*4=12km/hr

Like? Yes (1) | No (1)  

Prateek Sharma   9 years AGO

remaning distance= 3km
remaning time = 15 min
so speed = 12kmph

Like? Yes (1) | No (1)  

chirag mehta   9 years AGO

6km - 45min
he has covered alrady 3km in 30min( 2/3 of 45)
he has to cover 3km more in 15 mins ,
since ans is in kmph ,.. it is 3(60)/15

Like? Yes (1) | No (1)  

Deepak kushwaha   9 years AGO

mukesh have to cover 6km in 45min(3/4hr)
he cover half distance in 2/3 time
means,
3km in 1/2hr
now he have to cover
3km in 1/4hr
speed=distance/time
speed=12kmph(option 9)

Like? Yes (1) | No (1)  

kesava   9 years AGO

he covered 3km in 30 min.for remaining 3 km he has to increase his speed to 12kmph.
3km=30min
3km=????

Like? Yes (1) | No (1)  

srilekha   9 years AGO

he covers first 3kms in 2/3*45=30min=
so he has to cover next 3 kms in 15 mins(1/4 hrs) bcoz 30+15=45
so as d=v*t; 3=v*(1/4);v=12km/hr

Like? Yes (1) | No (1)  

venkatesh pavuluri   9 years AGO

since he completed half the distance in d given time ,we get with 14hrs of time and 3km distance..

Like? Yes (1) | No (1)  

shivani gupta   9 years AGO

first half the distance cover 3km in 30 min (2/3 of 45 min)
and remaining distance 3km in 15 min(45-30=30min)
speed=distance/time
3*60/15=12 kmph

Like? Yes (1) | No (1)  

Purnima Paliwal   9 years AGO

mukesh cover 3km in 30 min. remaining 3 km in 15 min his speed should be 12 as d=s*t so
3=s*1/4
s=12

Like? Yes (1) | No (1)  

Arjun Raju   9 years AGO

3km covered in 30mins. hence for next 15 mins speed should be 3 kms.hence 12 kmph

Like? Yes (1) | No (1)  

RAJESH PARSHAD   9 years AGO

mukesh has to cover the remaining half distance in 1/4 hours

speed= distance*time
=3/(1/4)=12kmph

Like? Yes (1) | No (1)  

14 Jul 2015 Average

The average age of a family of 6 members is 22 years. If the age of the youngest member be 7 years, the average age of the family at the birth of the youngest member was

OPtion

1) 15 years
2) 15.5 years
3) 16 years
4) 16.5 years
5) 17 years
6) 17.5 years
7) 18 years
8) 18.5 years
9) 19 years
10)19.5 years

Solution

Total present age of the family (6*22) = 132 years
Total age of the family 7 years ago = (132 - 7*6) = 90 years
At that time, the number of member = 5
Therefore Average age at that time = 90/5 = 18 years

Option 7)

Correct Option: 7 Best Solution (28)

akanksha   9 years AGO

total age of all the 6 family members=22*6=132
7 years ago the youngest member was not there and the other members were 7 years younger than now.so the total age of a family of 5 members will be 132-(7*6)=90.therefore the average age of 5 members will be 90/5=18

Like? Yes (37) | No (8)  

SHUBHAM RAJ   9 years AGO

sum of age of 6 membar= 22*6= 132
sum of age of 5 member excluding yonger one= 132-7 =125

av. age of 5 member= 125/5= 25

av. age at the time of birth=25-7 =18

Like? Yes (34) | No (17)  

Reeniya Bopaiah A   9 years AGO

let average age of five people be x
5*x+7=6*22
x=25
average age before youngest was born is 25-7=18

Like? Yes (14) | No (4)  

Patralika Mitra   9 years AGO

18 yrs

The average age of a family of 6 members is 22 years.
Total age now = 22*6=132 years

If the age of the youngest member be 7 years,
Total age of 5 members 7 years ago = 132 -6*7 = 132-42 = 90 years
then the average age of the family of 5 members just before the birth of the youngest member = 90/5 = 18 yrs
the average age of the family of 6 members just after the birth of the youngest member = 90/6 = 15 years
Read more at http://www.m4maths.com/9566-The-average-age-of-a-family-of-6-members-is-22-years-If-the-age-of-the-youngest-member-be.html#hu1dFsfju9OvUzQW.99

Like? Yes (7) | No (1)  

SOMA NARESH   9 years AGO

sum of ages of 6 members = 22*6 = 132
sum of ages of 5 members + youngest one = 132
sum of ages of 5 members = 132-7 = 125
before 7 years the ages of each person is reduced by 7.
so total age reduced from all members = 7*5 = 35

before 7 years sum of ages of 5 members = 125-35 = 90
average age of 5 members = 90/5 = 18
Option(7)

Like? Yes (11) | No (8)  

MRITUNJAY   9 years AGO

total age= 22*6=132
age at the birth of youngest member=7*6=42
remaining age of family=132-42=90
average =90/5=18

Like? Yes (4) | No (2)  

vishal kumar   9 years AGO

At present the total age of the family = 6 * 22 =132

The total age of the family at the time of the birth of the youngest member = [132-7-(7*5)] = 90

Therefore, average age of the family at the time of birth of the youngest member = 90/5 = 18

Like? Yes (5) | No (4)  

DEEPAK RAJ   9 years AGO

Total age of family = 22*6 =132 years
7 years earlier, total age = 132- (7*6) = 90 years
So, Avg age = 90/5 = 18 years

Like? Yes (3) | No (3)  

sudiptaa   9 years AGO

Total age of the family = 22*6 = 132
total age before birth of the youngest member = 132-7-(7*5)=90
Avg age = 90/5=18 years

Like? Yes (2) | No (2)  

pankaj kumar   9 years AGO

total age of family member = 132
at the birth of youngest member total age of family member = 132- 6*7= 90
at birth of youngest member average age of family is 90/5= 18. option 7 is correct ans...

Like? Yes (1) | No (1)  

Deepak kushwaha   9 years AGO

here average age of 6 family member is 22
then total age of family member =6*22=132
now at the birth of youngest member or & 7 years ago
total age of family is 132-42=90
now the family member is 5 (7 years ago)
so avg. age of 5 family member is 90/5=18(option 7)

Like? Yes (3) | No (3)  

sanu kumar verma   9 years AGO

present sum of age of family member=22*6=132 year now age of family member 7 year ago is 132-6*7=90 year now average age of family at the birth of youngest member is 90/5=18 yeari.e 18 year is answer

Like? Yes (4) | No (4)  

Supraja   9 years AGO

Tot age=6 x 22 =132
At the birth of youngest member (ie) before 7 years
7 x 6 =42(total age of 5 members)
Total age before 7 years =132-42=90
Average age= 90/5=18

Like? Yes (1) | No (1)  

pooja jha   9 years AGO

sum of the ages of 6 family member is 122*6=132.

sum of the ages of all the family member during birth of youngest = 132-(7*6) = 90.
therefore average age during the time of birth of youngest = 90/5=18

Like? Yes (1) | No (1)  

neha gupta   9 years AGO

The average age of six members is - 22
So their sum of ages = 22*6=132
the age of youngest member is 7, so the sum of ages of rest five members is = 132-7=125
7 years ago their sum og age had been = 125-(7*5) = 125-35 = 90
So the average is 90/5=18 years.

Like? Yes (1) | No (1)  

Surit Datta   9 years AGO

The average age of a family of 6 members is 22 years.
Total age now = 22*6=132 years

If the age of the youngest member be 7 years,
Total age of 5 members 7 years ago = 132 -6*7 = 132-42 = 90 years
then the average age of the family of 5 members just before the birth of the youngest member = 90/5 = 18 yrs
so option 7
that's it.

Like? Yes (3) | No (4)  

nirmal kumar saini   9 years AGO

because at the birth time of youngest member the average age is 15 including the birth child.
so we have to remove the birth child.so the sum of all age is 90 which must be devided by 5 to get the average
so average sum of the family is
90/5=18;

Like? Yes (2) | No (3)  

anand kumar   9 years AGO

total age=6x22=132
sum of age 5 members other than youngest=132-7=125
7 years earlier age= 125-35=90
average=90/5=18

Like? Yes (2) | No (3)  

Soma Naresh   9 years AGO

total age of 6 persons=22×5=132
total age excluding youngest one=132-7=125
total age of 5 members=125
before 7 years total age reduced by 5 from each member
so total age=125-(7×5)=125-35=90
average age of 5 members before birth of youngest one =90/5=18
Option (7)

Like? Yes (1) | No (2)  

POOJA SINGH   9 years AGO

At present the total age of the family = 6*22 = 132

The total age of the family at the time of the birth of the youngest member = [132-7-(7*5)] = 90

Therefore, average age of the family at the time of birth of the youngest member = 90/5 = 18

Like? Yes (4) | No (5)  

Asha Verma   9 years AGO

Sum of ages= average×number of members. So sum= 22× 6= 132
Now seven years before sum of average = 132-(7×6)=90.
Then average at the time of born of youngest member= 90/5= 18

Like? Yes (1) | No (2)  

santosh kumar patel   9 years AGO

The total age as of now = 22x6=132 years
so the age of 5 members excluding the youngest one= 132-7=125 years .

The youngest person was born 7 years before. So at that time the age of other five members in total was 125-7x5=90 years.

and their average was 90/5 =18 Years

Like? Yes (2) | No (3)  

Archie   9 years AGO

Avg age of 6 members=22
Sum of their ages =22*6 =135
sum of age 7 yrs ago i.e at the birth of youngest member
=132-(7*6)
=90
Required Avg age=90/5=18yrs
Option 7

Like? Yes (1) | No (2)  

krishna chandrika   9 years AGO

x1+x2+x3+x4+x5+x6=22*6

x6=7

x1+x2+x3+x4+x5=132-7=125

7yrs back

x1+x2+x3+x4+x5=125-(7*5) = 90

average = 90/5 = 18

Like? Yes (2) | No (3)  

vivek kashyap   9 years AGO

Total age of members = 6 x 22 = 132 yr

7 years ago,
total sum of ages = 132 – (6 x 7) = 90 yr

so average= 90 /5 = 18 years

Like? Yes (1) | No (2)  

kvsnlr   9 years AGO

since avg od all gamily mem is 22 sum of all agds would be 22×6 subtracting the age of youngest boy from th sum we get some of remaining members and this sum diveded by 5 would give avg as 7 yrs agi each ones age must be subtracted b 7 yhe avg also reduced by 7 so 25-7=18

Like? Yes (2) | No (3)  

sourav pal   9 years AGO

The total age as of now = 22x6=132 years and so the age of 5 members excluding the youngest one= 132-7=125 years .

The youngest person was born 7 years before. So at that time the age of other five members in total was 125-7x5=90 years.

and their average was 90/5 =18 Years

Like? Yes (2) | No (4)  

vimal tiwari   9 years AGO

sum of 5 member age = 22*6 - 7 =125;
avg = 125/5 =25
7 years ago = 25-7=18

Like? Yes (2) | No (4)  

13 Jul 2015 Sequence

What is the next number of the following sequence
37/4, 47/3, 58/3, 71/6, 79/2, .....

OPtion

1) 98/2
2) 95/2
3) 90/2
4) 95/4
5) 96/6
6) 95/7
7) 95/8
8) 95/6
9) 96/4
10)96/2

Solution

37/4 = Numerator is 37 / Denominator is |7-3| = 4
47/3 = Numerator is 37+(3+7) / Denominator is |7-4| = 3
58/3 = Numerator is 47+(4+7) / Denominator is |8-5| = 3
71/6 = Numerator is 58+(5+8) / Denominator is |1-7| = 6
79/2 = Numerator is 71+(7+1) / Denominator is |9-7| = 2
Similarly
95/4 = Numerator is 79+(7+9) / Denominator is |5-9| = 4

Option 4)

Correct Option: 4 Best Solution (51)

SAYAN CHATTERJEE   9 years AGO

in the numerators, the the next number is the summation of the preceding number's digital sum + that number
and, the denominator, is the digital difference between the numerator
so, the numerator of the result is 79 +(7+9)= 95
and, the denominator of the result is (9-5) =4
so, the result is (95/4) (4)

Like? Yes (1) | No   

Nonit Dua   9 years AGO

3+7=10;37+10=47(next numerator)
4+7=11;47+11=58(next numerator)
5+8=13;58+13=71(next numerator)
7+1=08;71+08=79(next numerator) so the next numerator will be 7+9=16;79+16=95
irrespective of sign:subtract the numerator digits like
3-7=4(demoninator)
4-7=3(denominator)
5-8=3(denominator)
7-1=6(denominator)
7-9=2(denominator)
similarly
9-5=4(denominator)
so no. is 95/4

Like? Yes (1) | No   

sudiptaa   9 years AGO

37+3+7=47
47+4+7=58
58+5+8=71
71+7+1=79
79+7+9=95

denominator = difference of the digits in the numerator
37:7-3=4
47:7-4=3
58:8-5=3
71:7-1=6
79:9-7=2
95:9-5=4

Like? Yes (1) | No   

ramakrishnateja   9 years AGO

in the given series the denominators are formed by the subtraction of the nrs. so probably the next num may be 95/4

Like? Yes (1) | No   

Testing Account   9 years AGO

substraction of higher number minus lower number in the numerator will give u denminator .... 37/4=>7-3=4 ... like 95/4=> 9-5=4
and for numerator 3+7=10=>37+10 will lead to next numerator like 4+7=11=>47+11 .... like 79+11=95

Like? Yes (1) | No   

Rahul kumar   9 years AGO

multiply the digits at ones place and tens place and then divide it by denominator the remainder in each case will be 1

Like? Yes (1) | No   

UJJWAL KANT   9 years AGO

In each sequence product of digits divided by denominator leaves odd quotient and 1 as remainder
7*3=21/4 leaves quotient 7 & rem 1
4*7=28/3 leaves quotient 9 & rem 1
5*8=40/3 leaves quotient 13 & rem 1
7*1=7/6 leaves quotient 1 & rem 1
7*9=63/2 leaves quotient 31 & rem 1
similarly 9*5=45/4 leaves quotient 11 & rem 1
and no other option leaves rem 1
hence option 2 is correct

Like? Yes (1) | No   

Dr.Dipin Singh   9 years AGO

37/4, 47/3, 58/3, 71/6, 79/2, .....
37/4 ....>>>> 47/3
37... 37+3+7=47 and 7-4=3 .......>> hence 37/4 ..>> 47/3
...
similarly 79/2 ..>> 79+7+9 =95 ; 9-5=4
so next number is 95/4.

Like? Yes (4) | No (3)  

anjana sethi   9 years AGO

numerator of fraction --
37 , 37+(7+3) =47 , 47+ (7+4) = 58 , 58+(5+8) =71 . 71+ 8=79 so next term should be 79+ 7+9 =95

denominator is the difference of the digits of numerator

so correct ans is 95 /4

Like? Yes (1) | No   

tejaswini   9 years AGO

37/4
3+7=10
37+10=47
7-3=4
47/3
4+7=11
47+11=58
8-5=3

Like? Yes (1) | No   

pankaj kumar   9 years AGO

sequence is- 37/4, 47/3, 58/3, 71/6, 79/2 , ..........
solu- 3+7=10+37=47 next term & 4-7=3
means the full sequence is 47/3 as remaining all sequence is 4+7= 11+47= 58 & 8-5= 3 so 58/3...
as remaining the final sequence is 95/4.....
7+9= 16+79 = 95 & 9-5 = 4 means full sequence is 95/4
ans is 4 ( option)

Like? Yes (1) | No   

RAKESH   9 years AGO

71+(7+1) = 79 & 9-7=2 so, 79/2

79 +(7+9) = 95 & 9-5=4 so, 95/4

Like? Yes (4) | No (4)  

Anubhav jain   9 years AGO

See That the demoniator is equal to Difference of numerator Digits.
3-4=4
7-4=3
8-5=3
7-1=6
9-7=2

Like? Yes (3) | No (3)  

Devendra Marghade   9 years AGO

Next numerator=Previous Numerator+Sum of its digits and
Denominator=Difference of the digits of Numerator
37+3+7=47 and 7-4=3 ,so 47/3
47+4+7=58 and 8-5=3 ,so 58/3
58+5+8=71 and 7-1=6 ,so 71/6
71+7+1=79 and 9-7=2 ,so 79/2
79+7+9=95 and 9-5=4 ,so 95/4
Answer option (4)

Like? Yes (1) | No (2)  

Harinder Singh   9 years AGO

addition of digits to get the next number in the numerator and difference in the digits for the denominator.

Like? Yes (1) | No (2)  

bhargav krishna   9 years AGO

the difference between every numerator is equal to the denominator

Like? Yes (1) | No (2)  

alex.p   9 years AGO

in numerator delete the small number from the large number,then you can get the dinominator.
37/4 =7-3=4
47/3 =7-4=3
58/3 =8-5=3
71/6 =7-1=6
79/2 =9-7=2
likewise
95/4 =9-5= 4

Like? Yes (1) | No (2)  

Alwira Sheikh   9 years AGO

no other options have the difference between the digits in numerator as the denominator

Like? Yes (1) | No (2)  

Akshay Bhandakkar   9 years AGO

in the sequence,difference between two digits of the number is given with it.
eg. 37/4
here 7-3=4....
in the given options,option 4 is correct as 9-5=4..
so 4)95/4 is correct answer

Like? Yes (1) | No (2)  

keerthi choudhry   9 years AGO

since we get (3-7)/4 as -1,(4-7)/3 as -1,(5-8)/3 as -1,(7-1)/6 as 1,(7-9)/2 as -1,...
then while trying with these, for option 4: (9-5)/4=1

Like? Yes (1) | No (2)  

ROHIT KUMAR   9 years AGO

Denominator is difference of digit of numerator and only option 4 satisfied

Like? Yes (2) | No (3)  

Sourabh Prasad   9 years AGO

Let ab/x
then condition be
a+x=b or b+x=a

condition satisfy only by option 4.

5+4=9

Like? Yes (1) | No (2)  

Sagar    9 years AGO

by subtracting the two numbers on the numerator we get the denominator

Like? Yes (1) | No (2)  

sonali gaur   9 years AGO

next numerator is the previous numerator+sum of the digits and denominator is the subtraction of the the 2 digits of the numerator.
1st term Nr 37..next 37+3+7=47; Dr:7-4=3 i.e 47/3
similarly last Nr 79 therefore next Nr: 79+7+9= 95 & Dr: 9-5=4 i.e 95/4

Like? Yes (1) | No (2)  

Ashok   9 years AGO

7-3=4 =>37/4
7-4=3 =>47/3
8-5=3 =>58/3
7-1=6 =>71/6
9-7=2 =>79/2
by this way 9-5=4 =>95/4

Like? Yes (1) | No (2)  

A M ANKIT KALLURAYA   9 years AGO

To find numerator of next number, add sum of digits of current numerator to current numerator. Denominator is difference between digits of numerator.

Like? Yes (1) | No (2)  

RAVAL   9 years AGO

higher number minus lower number in the numerator will give u denominator .... 37/4=>7-3=4 ... like 95/4=> 9-5=4
and for numerator 3+7=10=>37+10 will lead to next numerator like 4+7=11=>47+11 .... like 79+11=95

Like? Yes (1) | No (2)  

Rhul Sharma   9 years AGO

7 9=16
79 16 = 95
9-5 = 4
95/4

Like? Yes (1) | No (2)  

raviteja   9 years AGO

37/4 rem1,47/3 rem +1 makes perfectly divisible and it contiues.answer is95/4 because 95+1=96 which is divisible by 4.but y 4????b/se 9-5 (difference of two digits is taken).hope u will understand

Like? Yes (1) | No (2)  

dharani kumar   9 years AGO

37/4 --> 7-3=4(denominator)
47/4 --> 7-4=3
58/3 -->8-5=3
71/6 --> 7-1=6(any order we can substract i think)
79/2 --> 9-7=2
similarly in options only 95/4--> gives as 9-5=4(denominator)

Like? Yes (1) | No (2)  

santhosh   9 years AGO

denominator is difference of two nembers in the nemerator

Like? Yes (1) | No (2)  

Vimal   9 years AGO

3+7=10 so 37+10=47 and continues .. 3-7-=4
Therefore 95/4

Like? Yes (1) | No (2)  

Mayank Koul   9 years AGO

Because sum of 5 and 4 is 9.in rest of the numbers also we see that the sum of one of the numbers of numerator and denominator results in other number in numerator.

Like? Yes (1) | No (2)  

SOUVIK PAL   9 years AGO

7-3 = 4
7-4 = 3
8-5 = 3
7-1 = 6
9-7 = 2
9-5 = 4
so option 4

Like? Yes (1) | No (3)  

Ramdas Singathiya   9 years AGO

difference b/w the digits in numerator is equals to denominator for each fraction

Like? Yes (1) | No (3)  

lokesh   9 years AGO

numerator is the sum of digits of numerator of previous number and denominator is the subtraction of the digits of numerator.

Like? Yes (1) | No (3)  

SAGNIK DATTA   9 years AGO

numerator=addition of previous two digits+ prevous no.
deno= subtract of previous two digits

Like? Yes (1) | No (3)  

Chandrima Goswami   9 years AGO

3+7=10 => 37+10 = 47
4+7 = 11 => 47+11 = 58
5+8 = 13 => 58+14 = 71
7+1 =8 => 71+8 = 79
7+9 = 16 => 79+16 = 95

and, 7-3 = 4 => 37/4
7-4 = 3 => 47/3
8-5 = 3 => 58/3
7-1 = 6 => 71/6
9-7 = 2 => 79/2
9-5 = 4 => 95/4

So ans is option 4)

Like? Yes (1) | No (3)  

SURAJ NIRALA   9 years AGO

37/4=3+4,47/3=4+3,58/3=5+3.71/6=1+6,79/2=7+2
similarly 95/4=5+4
here sum of either units digit or ten's digit and denominator digit is equal to unit's digit or ten's digit of numerator..

Like? Yes (1) | No (3)  

Asha Verma   9 years AGO

To get numerator add the terms of previous numerator 9+7=16.
And then 16+ 79=95. To get denominator subtract 9-5=4 . Thus we get 95/4.

Like? Yes (1) | No (3)  

Sambit Pal   9 years AGO

the series format is :- previous number+ (sum of digit of previous number)/(difference of digit of present number)
=79+(9+7)/(difference )
=95/(9-5)=95/4
ANS=4).

Like? Yes (1) | No (3)  

Pankaj Merisha   9 years AGO

7-3=4
7-4=3
8-5=3
7-1=6
9-7=2
For each fraction difference between digits of numerator is equal to its denominator.
Ans..
9-5=4
i.e) 95/4

Like? Yes (1) | No (3)  

vivek   9 years AGO

Addition of previous two digit number and the number itself is equal to next number in numerator part.And subtraction of digits of number is the denominator part.so answer is 95/4

Like? Yes (1) | No (3)  

rahul shaw   9 years AGO

subtract both the digits of numerator and the answer is the denominator ....so
ans is 95/4

Like? Yes (1) | No (3)  

Pinku Burnwal   9 years AGO

part 1: to find next numerator
add the digit and add it to the number to get next numerator.
eg- 3+7=10, add 10 to 37 which give 47
part 2: to find next denominator
subtract larger number to small number and put the result to denomenator of next number.
eg- 7-3=4
therefore, result to 95/4
option-4

Like? Yes (1) | No (3)  

Ashu Kumar   9 years AGO

WE SEE THAT DOMINATOR IS THE DIFFERENCE OF TWO DIGIT OF NoMINATOR SO FROM OPTION CORRECT ANSWER IS OPTION 4

Like? Yes (1) | No (3)  

Purnima Paliwal   9 years AGO

7-3=4
7-4=3
8-5=3
7-1=6
9-7=2
so in all options only one option can fulfill the condition as 9-5=4

Like? Yes (1) | No (3)  

Yathiraj   9 years AGO

Denominator is the difference of the two digits of numerator.
taking the sequence of numerator
37, 47, 58, 71, 79..
Next number of the above sequence is the Prev. Number + sum of digits of Prev. number

Hence, next number in the above sequence is
79 + 7+9 => 95
and denominator is 9-5=4

So, 95/4

Option 4.

Like? Yes (2) | No (5)  

Dinni   9 years AGO

37/4, 47/3, 58/3, 71/6, 79/2,....
Numerator = previous numerator no. + sum of their digits.
Denominator = difference of present numerator digits.
So numerator=79+7+9=95
denominator = 9-5=4
So ans. is 95/4.

Like? Yes (1) | No (4)  

k sureshbabu   9 years AGO

HIGHER DIGIT-LOWER DIGIT IN NUMERATOR =DENMINATOR

Like? Yes (1) | No (4)  

Archie   9 years AGO

Denominator is equal to difference in the digits of numerator..
7-3=4
7-4=3
8-5=3
7-1=6
9-7=2
Hence according to this pattern the next number should also have denominator equal to differnce of digits in numerator.
i.e,
95/4.(Since 9-5=4)
Hence option 4 is correct

Like? Yes (1) | No (4)  

10 Jul 2015 Volume and surface areas

How many lead shots each 0.3 cm in diameter can be made from a cuboid of dimensions .09 m * .11 m * .12 m ?

OPtion

1) 7200
2) 7600
3) 8400
4) 8600
5) 72000
6) 76000
7) 84000
8) 86000
9) 82000
10)None of these

Solution

Number of lead shots = Volume of sphere / volume of 1 lead
solve 9*11*12 cm^3 / (4/3 * 22/7 * (.03/2)^3

Solve
84000
Option 7)

Correct Option: 7 Best Solution (30)

neha gupta   9 years AGO

As leadshots are spherical in shape therefore its volume is calculated using 4*pi*r*r*r/3

Number of leadshots formed =
Volume of cuboid/Volume of 1 leadshot
= (.09*.11*.12)/(4*pi*(0.003/2)^(3)/3)
=84000

Like? Yes (11) | No (3)  

Abhishek   9 years AGO

No. of lead shots * volume of each lead shot = Volume of cuboid.
N * (4/3 * pi *r^3) = L*B*H
N * (4/3 * 22/7 * 3/20 * 3/20 * 3/20) = 9*11*12
N * 99/7000 = 1188
N =1188*7000/99
N = 7000 * 12
N = 84000
No. of lead shots = 84000

Like? Yes (8) | No (3)  

vini   9 years AGO

volume of the cuboid= 9*11*12 = 1188 cm^3
Volume of the sphere(Lead) = 4/3 * pi * r^3 = 4/3*3.14*(0.15)^3 = .01413 cm^3
No . of shots = Volume of cuboid / volume of sphere
No.of shots = 84000

Like? Yes (5) | No (2)  

santhosh   9 years AGO

volume of d each lead shot= 4/3×22/7×(0.3/2)^3 =99/7000
.no.of leadshots = (9×11×12×7000/99)=84000

Like? Yes (1) | No   

pankaj kumar   9 years AGO

d=0.3cm
r=0.15cm
volume of sphere=4/3pi r^3= 4/3*pi*(r^3)

dimension of cube= 1188 cm^3

total no of lead shots= 1188/(4/3*pi*r^3)= 84034.8 approx=84000
ans= 7

Like? Yes (3) | No (2)  

Aarti Galar   9 years AGO

volume of cuboid = lbh
=0.09 m x 0.11 m x 0.12 m

volume of each lead shot = 4/3 x 22/7 x r^3
=( 4/3 x 22/7 x 0.3 x 0.3 x 0.3) m^3
Number of shots = Volume of cuboid/ Volume of each lead
shot
On calculating, we got the answer as 84000
option 7)

Like? Yes (3) | No (2)  

sudiptaa   9 years AGO

Volume of 1 lead shot = (4/3)*(22/7)*(0.3/2000)^3 m^3.........(1)
Volume of cuboid =.09 * .11 * .12 = .001188 m^3 .........(2)

(2) /(1) = 84000

Like? Yes (1) | No   

anjana sethi   9 years AGO

No. of lead shots = vol. of cuboid / vol. of one lead shot
( 9* 11*12)/ 4/3 pi (.3/2)^3 = 84000

Like? Yes (1) | No   

pratyush   9 years AGO

as we know , .09m=9cm
.11m=11cm
.12m=12cm
so,
no.of shots= volume of cuboid/volume of shots
=9*11*12/(4/3*pi*(0.3/2)^3)=84000

Like? Yes (3) | No (2)  

sompon temtheerakij   9 years AGO

volume of cuboidal = 9x11x12 = 1188 cu.cm.
volume of lead shot = 4/3 x pi x radius^3
can be made = 1188/(4/3x22/7x0.15x0.15x0.15) = 84000

Like? Yes (1) | No   

abhishek kumar   9 years AGO

volume of cuboid is=.09*.11*.12=.001188m^3 =1188cm^3 Now radius of lead shot=.3/2=/.15 since lead shot is in the shape of sphere so volume of lead shot=4*3/14*.15*.15*.15=.01414286 Now 1188/.01414286=83999.983=84000.

Like? Yes (4) | No (4)  

praveendas   9 years AGO

volume of cubiod/volume of one lead shot=total no of lead shots
=>1188/(4/3*22/7*(.3/2)^3)=84000

Like? Yes (3) | No (3)  

akanksha   9 years AGO

volume of cuboid=0.09*0.11*0.12=0.001188m^3=1188cm^3
volume of shot=(9*pi)/2000
so number of shots= (1188*2000)/(9*pi)=84000

Like? Yes (3) | No (3)  

Shiva Sharma   9 years AGO

volume of cuboid = 9*11*12 = 1188 cm^3
volume of one lead shots = (4/3)*(22/7)*0.15*0.15*0.15 = 0.014142857 cm^3
so nmber of lead shots = 1188/0.014142857 = 84000

Like? Yes (3) | No (3)  

ramakrishnateja   9 years AGO

given the dia of lead shot is 0.3cm,r=0.15*10^-2. volume is 4pi*r^3/3. but cuboid vol is 0.09*0.11*0.12m^3. let no of lead shots is x. hence x.4pi*r^3/3=0.09*0.11*0.12 hence x=84000 aprrox.

Like? Yes (1) | No (2)  

Urvil shah   9 years AGO

[0.09*.11*.12*1000000 cm / (4/3)3.14*(0.15)(0.15)(0.15)]=ans

Like? Yes (2) | No (3)  

Lavanya Rajendran   9 years AGO

volume of cuboid=l*b*h
=0.09*0.11*0.12=1.188*10^-3
volume of lead shot i.e sphere=(4/3)*22/7*(0.15*10^-2)^3
=1.414*10^-8
no.of lead shot = volume of cuboid/volume of sphere
=84000

Like? Yes (1) | No (2)  

ROHIT PANDEY   9 years AGO

first we calculate the volume of metal contained in the cube the we calculate the same for the circular shot ....the we divide the previous data by the latter one ...we get 84000

Like? Yes (2) | No (3)  

pavan kumar   9 years AGO

radius of shot=0.3/2=0.15cm
volume of shot =(4/3)?r3=0.01413cm3
volume of cuboid=lbh=9*11*12=1188cm3
no.of lead shots made=1188/0.01413~=84000

Like? Yes (1) | No (2)  

Vibhu Banka   9 years AGO

I divided the volume of cuboid by the volume of each lead shot(sphere).

The exact answer when taking pi=3.14 is 84076

Like? Yes (2) | No (3)  

Bimlendu Kumar   9 years AGO

vol lead=(4/3)*(22/7)*{(3/20)}^3
vol cuboid= l*b*h simply all in same parameters
no leads=vol coboid/vol of one lead

Like? Yes (2) | No (3)  

Piyush Telang   9 years AGO

Volume of Cuboid ( A )= L x B x H = 9 x 11 x 12 cubic cm
Volume of Lead Shots ( B ) = Pi x ( Diameter ^ 3 ) / 24 = 22 x 0.3 x 0.3 x 0.3 / ( 7 x 24 )
Number of Lead Shots = A / B = 84000

Like? Yes (1) | No (3)  

Sushmita Ghanty   9 years AGO

no. of lead shots=volume of cuboid/volume of a lead shot =(.09*.11*.12 *100*100*100) cm^3/(4/3*22/7*.15*.15*.15) cm^3=84000

Like? Yes (1) | No (3)  

Bagmita Chanda   9 years AGO

diameter = .3 cm = .003m
so, radius = .0015m
volume of each lead shot = (4/3)*(22/7)*(.0015)^3 = 297/(21 * 10^9)

Now Volume of cuboid = .09*.11*.12 = .001188

so number of lead shots are = .001188/(297/(21*10^9)) = 84000

Like? Yes (1) | No (3)  

Archie   9 years AGO

Required number of shots=(volume of cuboid/Area of sphere)

= (.09*.11*.12m^2)/((4/3)*pi*r^3)
where r=.3/200=0.0015m
Solving we get,
Required number of shots=84000
Hence option 7 is correct

Like? Yes (1) | No (3)  

Shashank Choudhary   9 years AGO

simply divide the volume of cuboid to volume of shots (sphere)

Like? Yes (1) | No (3)  

anuj gupta   9 years AGO

0.3cm we will need radius here not diameter therefore:
dia = 2r = 0.3cm
r = 0.3cm / 2 = 0.15cm

cuboid 9cm x 11cm x 12cm

now, we need to calculate volumes of the cuboid as well as the shot

a x b x h = 9cm x 11cm x 12cm = 1188cm3

(4(pi)r^3)/3 = ( 4 x 3.14 x 0.15cm^3) / 3 = 0.01413cm3

we need now to divide cuboid volume by volume of the sphere:

1188cm3 / 0.01413cm3 = 84076.433...

therefore from presented cuboid, after round up, you will made 84076 shots...

Like? Yes (1) | No (3)  

vimal tiwari   9 years AGO

area of cuboid / area of shot

= .09 * .11 *. 12 / 4/3 *pi* (0.3/200)^3
= 84000

Like? Yes (1) | No (3)  

RAJAT KHANDELWAL   9 years AGO

no of lead shots = volume of the cuboid/ volume of the lead shot

no of leadshots = (0.09*0.11*0.12)/4/3*3.14*(0.003/2)^3= 84000

Like? Yes (1) | No (3)  

Rishikesh Ranjan   9 years AGO

no of lead shots= (9*11*12)cm^3 / (4/3)*(22/7)*{3/(2*10)}^3 cm^3 = 84000

Like? Yes (1) | No (4)  

09 Jul 2015 Area

Four Horses are tethered at four corners of a square plot of side 63 metres, so that they just cannot reach one another. The area left ungrazed is

OPtion

1) 675.5 m^2
2) 690.8 m^2
3) 650.5 m^2
4) 765.6 m^2
5) 875.6 m^2
6) 850.5 m^2
7) 820.5 m^2
8) 785.8 m^2
9) 805.6 m^2
10)780.6 m^2

Solution

Area left ungrazed
= 63*63 - 4 *(1/4 * 22/7 * 63/2 * 63/2)
= (3969 - 3118.5) m^2
= 850.5 m^2

Option 6)

Correct Option: 6 Best Solution (37)

Shiva Sharma   9 years AGO

Area of square is 63*63 = 3969 m^2
Area of four quarter circle is = 4*(1/4)*pi*(63/2)*(63/2) = 3118.5 m^2
so ungrazed area is = 3969-3118.5 = 850.5 m^2

Like? Yes (21) | No (8)  

Aravinth kumar   9 years AGO

The length of the rope in which the horses tied should be equal to half of the side of the
square plot so that they just cannot reach one another.
Therefore, the length of the rope is 31.5m (63/2).
The area covered by each horse should be equal to the area of sector with radius of 63/2 =
31.5m(length of the rope).
Total area covered by the four horses = 4* area of sector of radius 31.5 metres = Area of

circle of radius 31.5m.
Area left grazed by the horses = Area of square field - Area covered by four horses.
= 632 - (22/7)*31.5*31.5 = 3969 - 3118.5 = 850. sq.m

Like? Yes (15) | No (7)  

vini   9 years AGO

Area of ungrazed field = Area of square - Area of circle.
Area of ungrazed field = (63*63) - (3.14 * 31.5 * 31.5 )
Area of ungrazed field = 850.5 m^2

Like? Yes (6) | No (1)  

sudiptaa   9 years AGO

area of square = 63*63=3969 m^2
area inside the square that is grazed =4*area of quadrants of 4 circles
= 4*(1/4)*(22/7)*(63/2)*(63/2) =3118.5
area left ungrazed = 3969-3118.5=850.5

Like? Yes (4) | No (1)  

pankaj kumar   9 years AGO

solu- r^2-pi*r^2= ans(6)
63^2-3.142*(63/2)^2= 852.35m^2 approx 850.5m^2

Like? Yes (3) | No (1)  

Miriyala. siva sankar   9 years AGO

Area ungrazed = 63^2 - 4*1/4* Pi*(63/2)^2= 63^2 (1-22/28)
= 63*63*6/28
= 9*63*3/2= 63*27/2 = 850.5 sq mtr

Like? Yes (4) | No (3)  

Nonit Dua   9 years AGO

area ungrazed=total area of square(63*63)-area grazed(?r^2)
where r=63/2

Like? Yes (3) | No (2)  

santhosh   9 years AGO

required area =(63×63-4×1/4×22/7×63/2×63/2)

Like? Yes (1) | No   

SAYAN CHATTERJEE   9 years AGO

area ungazed = 63^2-4*22/7*1/4*(63/2)^2
= 850.5 m^2

Like? Yes (2) | No (2)  

RAKESH   9 years AGO

(63)^2 - pi *(63/2)^2

= 63*63 * (1- 22/28) = 850.5 m^2

Like? Yes (5) | No (6)  

Dinni   9 years AGO

The length of the rope in which the horses tied should be equal to half of the side of the square plot so that they just cannot reach one another. Therefore, the length of the rope is 31.5m (63/2). The area covered by each horse should be equal to the area of sector with radius of 63/2 = 31.5m(length of the rope). Total area covered by the four horses = 4* area of sector of radius 31.5 metres = Area of circle of radius 31.5m. Area left ungrazed by the horses = Area of square field - Area covered by four horses. = 632 - (22/7)*31.5*31.5 = 3969 - 3118.5 = 850. sq.m.

Like? Yes (2) | No (4)  

Pinku Burnwal   9 years AGO

four horses are tethered at four corner and each horse can graze one-forth of area of circle of radius 31.5m.
therefore, four horses will graze 4 times one-forth area of circle of=3.143*31.5*31.5=3118.64 sq.metre.

area of square=63*63=3969 sq.metre

therefore area ungrazed=area of square- area of circle=850.5 sq.metre

Like? Yes (3) | No (5)  

akanksha   9 years AGO

area of region grazed by the horses will be 4*{(90/360)*pi*(63/2)^2} and area of the plot will be 63^2.So ungrazed area will be total area-grazed area.so answer will be 850.5m^2

Like? Yes (2) | No (4)  

Bagmita Chanda   9 years AGO

As the sides of the square plot is 63 m, the area would be 63*63 m^2 = 3969 m^2.

and As the horses are tethered at 4 corners of the square and can't reach each other, four of them are covering atmost total 4*(1/4)*(22/7)*(63)^2 m^2 area =3118.5 m^2.

So the ungrazed area = (3969 - 3118.5) m^2 = 850.5 m^2

Like? Yes (1) | No (4)  

Chandrima Goswami   9 years AGO

Area of square = 63 * 63 = 3969 m^2

Area grazed = 22/7 * (63/2) * (63/2) = 3118.5 m^2

Area ungrazed = 3969 - 3118.5 = 850.5 m^2

So ans is option 6)

Like? Yes (1) | No (4)  

POOJA SINGH   9 years AGO

area ungrazed is given by
total area - 4*area grazed by each horse
63*63 - (22/7)*(63/2)^2
850.5m^2

Like? Yes (1) | No (4)  

Sambit Pal   9 years AGO

four horses at four corners can graze in a circular arc...and to just not meet each other they form a quarter of a circle with radius 63/2=31.5 m... so for 4 horses area grazed=area of circle of radius 31.5 m=3115.665 m sq. and total area of square field=63*63=3969 m sq. therefore area ungrazed=3969-3115.665 nearly equal to 851 m sq... nearest option is 6. so ans is 6)

Like? Yes (1) | No (4)  

Akshay Yelpale   9 years AGO

Since horses should not reach to each other.
Length of rope should be half of the side of square.
Length of Rope = 63/2 .

Area grazed by each horse = area of sector of radius 63/2.
Area grazed by 4 horses = 4 * area of sector of radius 63/2.
= area of circle with radius 63/2.

Area left ungrazed =Area of square - area of circle with radius 63/2.
= 63 * 63 - ( 22/7 * 63/2 * 63/2 )
=850.5

Like? Yes (1) | No (4)  

Archie   9 years AGO

Required area= Area of plot-Area covered by four horses
=63^2-((22/7)*(63/2)*(63/2))
=850.5

Like? Yes (1) | No (4)  

NAVEEN   9 years AGO

area of square-4(quater of circle)=3969-4(779.3125)

Like? Yes (1) | No (4)  

RAJAT KHANDELWAL   9 years AGO

area left for grazing= area of square field - area of the grazing part
= 63*63 - (22/7)*31.5*31.5 =850.5

Like? Yes (1) | No (4)  

Balamurugan A   9 years AGO

area of square 63*63=3969-->1
4 quarter circles=1circle then
area of circle=Ï€r^2
r=63/2=31.5
applying in circle formula=22/7*31.5*31.5
=3118.5----> 2
substitute 1-2 we get 850.5m^2

Like? Yes (1) | No (4)  

ABHINAV PUSHPAM   9 years AGO

Area ungrazed = 63^2 - 4*1/4* Pi*(63/2)^2= 63^2 (1-22/28) = 63*63*6/28 = 9*63*3/2= 63*27/2 = 850.5 sq mtr

Like? Yes (1) | No (4)  

Jawahar   9 years AGO

Area left ungrazed by the horses = Area of square field - Area covered by four horses.

= 632 - (22/7)*31.5*31.5 = 3969 - 3118.5 = 850. sq.m.

Like? Yes (1) | No (4)  

Patralika Mitra   9 years AGO

Area ungrazed = 63^2 - 4*1/4* Pi*(63/2)^2= 63^2 (1-22/28) = 63*63*6/28 = 9*63*3/2= 63*27/2 = 850.5 sq mtr

Like? Yes (1) | No (4)  

aditi goyal   9 years AGO

we have a square and we need to subtract 4 quaderants from it..so side*side-(pi)*r*r=850.5 m^2

Like? Yes (1) | No (4)  

Ashu Kumar   9 years AGO

AREA OF SQUARE IS=63*63m^2 , AND All 4 HORSE ARE AT 4 CORNER OF SQUARE. EACH HORSE GRAZE QUARTER PART OF CIRCLE. SO UNGRAZED AREA=63*63 -( 22*4*63*63*4)/4*7 =850.5 m^2

Like? Yes (1) | No (4)  

santosh kumar patel   9 years AGO

Area ungrazed = 63^2 - 4*1/4* Pi*(63/2)^2
= 63^2 (1-22/28)
= 63*63*6/28
= 9*63*3/2= 63*27/2
= 850.5 sq mtr

Like? Yes (2) | No (5)  

Narendra Gopi   9 years AGO

=63^2 - 4*1/4* Pi*(63/2)^2
= 63^2 (1-22/28)
= 63*63*6/28
= 9*63*3/2
= 63*27/2
= 850.5 sq mtr

Like? Yes (1) | No (4)  

abhishek kumar   9 years AGO

since there will be 4 quarter part in that field so radius of one part is 63/2. Now area of 4 quarter are 4*(3.14*31.5*31.5)/4=3118.5 so area of ungrazed part=63*63-3118.5=850.5

Like? Yes (2) | No (5)  

Surit Datta   9 years AGO

Area ungrazed = 63^2 - 4*1/4* Pi*(63/2)^2= 63^2 (1-22/28) = 63*63*6/28 = 9*63*3/2= 63*27/2 = 850.5 sq mtr
so option 6
that's it.

Like? Yes (1) | No (5)  

Veerraj Chauhan   9 years AGO

The four horses will graze in quadrants of radius = 63/2 m=31.5 m
therfore the grazed area by all the four horses will be = 4*( π * 31.5^2 * (1/4)) = 3117.245 m^2
the ungrazed area will be = 63^2 - 3117.245 = 851.755 m^2

The nearest option is 6

Like? Yes (1) | No (5)  

Pranati Kundu   9 years AGO

area of square - area of circle of radius 31.5
i.e. 63²-?31.5²
=850.5

Like? Yes (1) | No (5)  

ROHIT KUMAR   9 years AGO

Ungrazed area=Total area-(area of 4 quarter circle of radius 63/2)
=> 63*63-(1/4*4*(63/2)^2)
=>850.5 m^2

Like? Yes (2) | No (6)  

vimal tiwari   9 years AGO

total area = 63*63 = 3969

if horse can meet than the length of rope
will be equal or > to half of side i.e. 31.5

area grazed by 4 horse = 4 * (90/360 )(3.14 * 31.5*31.5);

required area = 3969 - area grazed by 4 horses = 854.3 m^2

but the horses just can't meet thus value of rope will be just less than 31.5
so and will be just less tha 853.3
i.e. 850.5 m^2

Like? Yes (1) | No (5)  

Sushmita Ghanty   9 years AGO

the area of the sqare plot= 63*63= 3969m^2
1 hosre can eat up=(1/4*22/7*63/2*63/2)m^2
as there are 4 horses so,
the area left ungrazed is= 3969 - {4*(1/4*22/7*63/2*63/2)}=850.5m^2

Like? Yes (1) | No (5)  

SOMA NARESH   9 years AGO

The length of the rope in which the horses tied should be equal to half of the side of the
square plot so that they just cannot reach one another.
Therefore, the length of the rope is 31.5m (63/2).

The area covered by each horse should be equal to the area of sector with radius of 63/2 =
31.5m(length of the rope).

Total area covered by the four horses = 4* area of sector of radius 31.5 metres = Area of
circle of radius 31.5m.
Area left ungrazed by the horses = Area of square field - Area covered by four horses.
= 63^2 - (22/7)*31.5*31.5
= 3969 - 3118.5
= 850. 5q.m.

Like? Yes (1) | No (5)  

08 Jul 2015 Simple Interest

A man invests an amount of Rs. 15860 in the names of his three sons A, B and C in such a way that they get the same interest after 2, 3 and 4 years respectively. If the rate of simple interest is 5%, then the ratio of the amounts invested among A, B and C will be

OPtion

1) 10:15:20
2) 11:12:13
3) (1/10):(1/15):(1/20)
4) (1/11):(1/12):(1/13)
5) (1/110):(1/115):(1/120)
6) (1/25):(1/50):(1/75)
7) 110:115:120
8) 25:50:75
9) 120:125:130
10)(1/120):(1/125):(1/130)

Solution

Let the amount invested be x, y and z respectively
Then
(x*2*5)/100 = (y*3*5)/100 = (z*4*5)/100
Therefore
10x = 15y = 20z = k
Therefore
x : y : z = 1/10 : 1/15 : 1/20

Option 3)

Correct Option: 3 Best Solution (19)

HARMEET KAUR   9 years AGO

A man invests an amount of Rs. 15860 in the names of his three sons A ( amount a), B( amount b) and C ( amount c)in such a way that they get the same interest after 2, 3 and 4 years respectively.
then
2a=3b=4c
2=2c, b=(4/3)c
hence ratio of the amounts invested among A, B and C will be 2:4/3:1
or
6:4:3
or
1/10 : 1/15 : 1/20 ( dividing each term by 60)

Like? Yes (11) | No (4)  

abhishek kumar   9 years AGO

since interest is same so let interest is x then money(A)=p1 B=p2 C=p3 Now p1=10x p2=20x/3 p3=5x onadding all we get x=732. p1=7320, p2=4880, p3=3660 Now ratio is 732:488:366 i.e 1/10:1/15:1/20

Like? Yes (5) | No (1)  

Nonit Dua   9 years AGO

let x,y,z be the amount invested than x*0.05*2=y*0.05*3=z*0.05*4 therefore

Like? Yes (2) | No (1)  

Shubham Goel   9 years AGO

x*2*5/100 = y*3*5/100
then x:y = 6:4
similarly y:z = 4:3
so x:y:z = 6:4:3

or 1/10 : 1/15 : 1/20

Like? Yes (5) | No (5)  

Chandrima Goswami   9 years AGO

The amounts invested be a, b, c respectively
Then, a * 2 * 5/100 = b * 3 * 5/100 = c * 4 * 5/100 = k
=> a = 10k , b = 20k/3 , c = 5k
=> a : b : c = 10k : 20k/3 : 5k = 1/10 : 1/15 : 1/20

So ans is option 3)

Like? Yes (2) | No (4)  

anand kumar   9 years AGO

SI=P*r*t/100;
since si is same for all sons. so Principle is inversely proportional to time.
(1/2):(1/3):(1/4) or(1/10):(1/15):(1/20)

Like? Yes (2) | No (4)  

RAJAT KHANDELWAL   9 years AGO

LET THE AMOUNTS INVESTED FOR A, B AND C BE p1,p2,p3

SINCE INTEREST IS SAME FOR ALL THE CASES
THEREFORE
(p1*r*2)/100=(p2*r*3)/100=(p3*r*4)/100=k
from here
p1=k/2
p2=k/3
p3=k/4
so by multiplying it with 1/5
we get
p1:p2:p3=1/10:1/15:1/20
so answer is option 3

Like? Yes (1) | No (3)  

Soumen Maity   9 years AGO

Say A got RS a
B got RS b
C got RS c
So, A's interest = (a*2*5)/100=a/10
B's ,, = (b*3*5)/100=3b/20
C's ,, = (c*4*5)/100= c/5

now, a/10=3b/20=c/5
So, a:b:c= 6:4:3
=(1/10):(1/15):(1/20)

Like? Yes (2) | No (4)  

Ashu Kumar   9 years AGO

Let A,B & C INVEST RESPECTLY X,Y & Z RUPEES Simple interest si for A=X*2*5/100
si for B=Y*3*5/100 & si for C=Z*4*5/100
GIVEN SI FOR A=B=C , SO 2X=3Y=4Z SO CORRECT ANSWER IS OPTION 3

Like? Yes (1) | No (3)  

Shiva Sharma   9 years AGO

Let x1,x2,x3 are money of one two and third respectively
2*x1=3*x2=4*x3
so:
1/2:1/3:1/4
multiply by 1/5 we get answer

Like? Yes (2) | No (4)  

Pinku Burnwal   9 years AGO

Simple interest=(amount invested*rate of interest*time)/100
therefore, amount invested by:-
A=(100*S.I)/2*5,
B=(100*S.I)/3*5,
C=(100*S.I)/4*5,
A:B:C=1/2:1/3:1:4=1/10:1/15:1/20
option 3

Like? Yes (4) | No (6)  

RAKESH ARYA   9 years AGO

if the amount of intrest = M
then , a's amount
(a*5*2)/100=M =>a=100M/10

b's amount
(b*5*3)/100=M =>b=100M/15

c's amount
(c*5*4)/100=M =>c=100M/20


=> a:b:c = 1/10 : 1/15 : 1/20

Like? Yes (1) | No (3)  

radhakrishna r   9 years AGO

let a,b and c are investments on A,B and C respectively
Given that
(5%of a)*2=(5%of b)*3=(5%of c)*4 after calculations
then it will
a/10:3*b/20:c/5
now 1/2:1/3:1/5 i.e nothing but 1/10:1/15:1/20

Like? Yes (1) | No (3)  

Kumar Gaurav   9 years AGO

As all three sons get the same amount of interest after after 2, 3 and 4 years repectievely so
suppose x, y and z is the amount invested by the for their son A, B and C respectively thus
x*2*5/100= y*3*5/100 = z*4*5/100
=> 10x = 15y = 20z
so x:y:z = 1/10: 1/15: 1/20

Like? Yes (1) | No (3)  

RAKESH   9 years AGO

10a:15b:20c => a:b:c = (1/10):(1/15):(1/20)

Like? Yes (1) | No (4)  

praveendas   9 years AGO

the amounts are in the ratio,6:4:3
verify with above ans given we can get it

Like? Yes (1) | No (4)  

Tapas Ranjan Sahu   9 years AGO

A=10p/100
B=15p/100
C=20p/100
Then
10p/100 +15p/100 +20p/100=k
=>p=k/10 ,k/15 ,k/20
So the ratio is (1/10, 1/15, 1/20)

Like? Yes (1) | No (4)  

Abhisheak Kumar Missu   9 years AGO

Let their share be x,y,z
Then S.I=x*100/2*5=y*100/3*5=z*100/4*5
SI=10x=20y/3=15z
ratio of their S.i=ratio of their share=6x:4y:3z
i.e (1/10):(1/15):(1/20)

Like? Yes (1) | No (4)  

Nikhil chavan   9 years AGO

Sum =15860 then devidedevide as per given

Like? Yes (1) | No (5)  

07 Jul 2015 Profit and loss

A sold a watch to B at a gain of 5% and B sold it to C at a gain of 4%. If C paid Rs. 1092 for it, the price paid by A is

OPtion

1) Rs. 993.72
2) Rs. 900
3) Rs. 896.50
4) Rs. 996
5) Rs. 1000
6) Rs. 995.90
7) Rs. 1050
8) Rs. 982.40
9) Rs. 1200
10)Rs. 890.50

Solution

Let C.P. be Rs. x Then
104% of (105% of x) = 1092
104/100 * 105/100 x = 1092
x = 1000

Correct Option: 5 Best Solution (18)

Abhishek   9 years AGO

B sold at 4% gain to C so, x + 4x/100 = 1092
104 x=109200
x= 1050
A sold at 5% gain to B, so y+5y/100=1050
105 y =10500
y=1000
A paid Rs. 1000

Like? Yes (19) | No (7)  

santhosh   9 years AGO

Assume Cost price for A = x
Selling price = y
given (y-x/x)*100 =5% => y=21x/20
and for b
(selling price-y/y)*100=4
selling price of B is cost price of C given 1092
so from there we get y
through which we get x value by above equation Y
x=1000

Like? Yes (7) | No (3)  

SUSHANT KUMAR   9 years AGO

104x/100=1096
x=1050
105x/100=1050
x=1000

Like? Yes (10) | No (7)  

Dhanraj Wanjare   9 years AGO

C paid 1092 to B
and B paid to A in - 1092*100/104=1050;
and A paid 1050 - 1050*100/105=1000;
so option 5 is satisfied

Like? Yes (11) | No (8)  

PIYUSH KUMAR   9 years AGO

100 ---5%----105---4%---109.20
109.20%---------- =1092
100%--------------- =1000

Like? Yes (7) | No (5)  

Surit Datta   9 years AGO

the question is wrong.
it should be like.
1092 in place of 1902
then the answer will be 1000

Like? Yes (5) | No (8)  

karthiga   9 years AGO

A(105/100)*(104/100)=1092;
A = 1092*100*100/(105*104)= 1000

Like? Yes (4) | No (7)  

Urvil shah   9 years AGO

b's purchase price is =100*1092/104=1050
a's purchase price=100*1050/105=1000

Like? Yes (3) | No (6)  

Anil Gautam   9 years AGO

The cost price of C is the selling price of B,
So,S.P of B= C.P of C =1092
Let, C.P of B is 'x' then
(1092-x)/(x)*(100)=4
1092-x=0.04x
x=1050
x is the cost price of B,
the cost price of B is the Selling price of A
So, s.p of A= c.p of B =1050
let, c.p of A be 'y' then
(1050-y)/(y)*100=5
1050-y=0.05y
y=1000
hence c.p of A is Rs.1000

Like? Yes (6) | No (9)  

MRITUNJAY   9 years AGO

let cp be x
Cp for B= x+x*5/100=y
cp for C =y*y*4/100=1092
solve the valve of y and x we x=1000

Like? Yes (4) | No (7)  

K Madhav Rao   9 years AGO

let A purcase the watch at Rs. x.
selling price of A=cost price of B= x+5% of x
=>cost price of B=x+((5/100)*x)
=>cost price of B=105x/100
now,
cost price of C= selling price of B= (105x/100)+ 4% of 105x/100
=>cost price of C=10920x/10000
given,
=>cost price of C=1092
=>10920x/10000=1092
=>x=1000 ans

Like? Yes (4) | No (7)  

Dinni   9 years AGO

Let c.p of A be x
Gain=5% = 21x/20=c.p of B
Gain=4% =273x/250=1092=c.p of C
X=Rs.1000.

Like? Yes (3) | No (6)  

Chandrima Goswami   9 years AGO

Let the price be x
A sold to B at price = 21x/100
B sold to C at price = 21x * 52/1000

21x * 52/1000=1902
=> x = 1000

So ans is option 5)

Like? Yes (7) | No (11)  

Navin   9 years AGO

B+(4B/100) = 1092
104B = 109200
B=1050

A+(5A/100) = 1050
105A = 105000
A = 1000

Like? Yes (3) | No (7)  

Narendra Jadon   9 years AGO

Let the price at which A bought watch be x rs
B got it for = (105/100)*x
C got it for = (104/100)*(105/100)*x = 1092
Finding the values of x we get 1000.
Hence Price paid by A is 1000 Rs.

Like? Yes (4) | No (8)  

Aarti Galar   9 years AGO

104% of 105% of A
104/ 100 x 105 /100 x A = 1092
A=1000
therefore, ans. is 5) 1000.

Like? Yes (4) | No (8)  

Archie   9 years AGO

Let price paid by A is Rs.100 then price paid by B=100+(5%of100)=Rs 105
Price paid by C=105+(4%of 105)=Rs 109.2
When C paid Rs.109.2
A paid 100
When C pays Rs.1092
A would have paid Rs. (1092/109.2)*100
= Rs. 1000
Hence option 5 is correct

Like? Yes (4) | No (8)  

Tanmay Shah   9 years AGO

B's purchase price=100*1092/104
=1050
A's purchase price=100*1050/105
=1000

Like? Yes (3) | No (8)  

06 Jul 2015 Ratio and proportion

What least number must be subtracted from each of the number 14, 17, 34, 42 so that the remainder may be proportional?

OPtion

1) 0
2) 1
3) 2
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10)3

Solution

Let x must be subtracted
Then
14-x / 17-x = 34-x / 42-x
(14-x)(42-x) = (34-y)(17-x)
x^2-56x+558 = x^2-51x+578
5x = 10
x = 2

Option 3)

Correct Option: 3 Best Solution (36)

Surit Datta   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.
that's it.

Like? Yes (20) | No (5)  

Subhadip Samanta   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (11) | No (1)  

Abhishek   9 years AGO

Let x be subtracted from each no.

(14 - x) : (17 - x) : : (34 - x) : (42 - x)

i.e. (14 - x) / (17 - x) = (34 - x) /(42 - x)

By cross multiplication:

(14 - x) * (42 - x) = (17 - x) * (34 - x)

on solving the brackets
588- 14x - 42x + x^2 = 578 - 17x - 34x + x^2

x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

so, number 2 is subtracted from each of the no.so that remainder are in proportion.

Like? Yes (9) | No   

viswambher   9 years AGO

If you subtract 2 from 14 and 17, you get 12 and 15. If you subtract 2 from 34 and 42, you arrive at 32 and 40. The ratios 12:15 and 32:40 both simplify to 4:5 (or 4/5 or .8).
The solution is "2"

Like? Yes (14) | No (6)  

SAYAN CHATTERJEE   9 years AGO

if 2 is subtracted, then the no.s become 12, 15, 32, 40
now 12:15=4:5
and 32:40= 4:5
so ans is 2 (3).

Like? Yes (9) | No (1)  

Rajanikanta Pradhan   9 years AGO

Proportion means a/b = b/c
So from hit and trail method if we substract 2 then it will satisfy

Like? Yes (8) | No   

mohita verma   9 years AGO

Checking by options...
14-2=12
17-2=15
34-2=32
42-2=40
remainders are...
12, 15 32, 40
12*40=15*32
480=480
thus, 2 is the correct option

Like? Yes (11) | No (3)  

Soma Naresh   9 years AGO

Let the number be a
Then after subtraction the numbers are 14-a 17-a 34-a 42-a
Proportionality can be determined as
(14-a)/(17-a)=(34-a)/(42-a)
By solving we will get a=2

Like? Yes (8) | No (1)  

swarupa nuggu   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (8) | No (2)  

Billal Hossain   9 years AGO

Let, the subtracted number=x
so,14-x, 17-x, 34-x and 42-x to be proportional
14-x 34-x
----- = -------
17-x 42-x
=>(14-x)(42-x) = (34-x)(17-x)
=>14*42 -56x +x^2 = 34*17 -51x + x^2
=>14*42-34*17 = 5x
=>2(294-289) => 10= 5x or x=2
Therefore, Answer will be 2

Like? Yes (6) | No   

Aravinth kumar   9 years AGO

Let the required number be x.
Then,
=>(14 - x) : (17 - x) : : (34 - x) : (42 - x)
=>(14 - x) * (42 - x) = (17 - x) * (34 - x)
=> x^2 - 56x + 588 = x^2 - 51x + 578
=>5x = 10
=>x = 2
Ans= 2

Like? Yes (5) | No   

Karthika   9 years AGO

14-x:17-x=34-x:42-x
(14-x)(42-x)=(17-x)(34-x)
on solving,
x=2

Like? Yes (5) | No   

santosh kumar patel   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2

Like? Yes (5) | No   

RUPALI DADHE   9 years AGO

14-x, 17-x, 34-x and 42-x to be proportional

14-x 34-x
----- = -------
17-x 42-x

=>(14-x)(42-x) = (34-x)(17-x)
=>14*42 -56x +x^2 = 34*17 -51x + x^2
=>14*42-34*17 = 5x
=>2(294-289) => 10= 5x or x=2

so 12 15 32 and 40 will be proportional

Like? Yes (5) | No (1)  

Pranati Kundu   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Like? Yes (3) | No   

Jawahar   9 years AGO

(14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x=2

Like? Yes (3) | No   

sudiptaa   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2

Like? Yes (3) | No   

SUSHANT KUMAR   9 years AGO

14-x, 17-x, 34-x and 42-x to be proportional

14-x 34-x
----- = -------
17-x 42-x

=>(14-x)(42-x) = (34-x)(17-x)
=>14*42 -56x +x^2 = 34*17 -51x + x^2
=>14*42-34*17 = 5x
=>2(294-289) => 10= 5x or x=2

so 12 15 32 and 40 will be proportional

Like? Yes (3) | No   

shubham shukla   9 years AGO

on subtracting the numbers from 2 we get:
12,15,32,40 which is on proportional form as 4:5::4:5
as required.

Like? Yes (3) | No   

ABHINAV PUSHPAM   9 years AGO

Let the required number be x.
(14 - x) : (17 - x) : : (34 - x) : (42 -x)

(14 - x) (42 - x) = (17 - x) (34 - x)

x^2 - 56x + 588 = x2 - 51x + 578

5x = 10

x = 2
Required number = 2.

Like? Yes (3) | No   

POOJA SINGH   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (3) | No   

Dinni   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (3) | No   

Kethineni Vinodh   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (3) | No   

SOMA NARESH   9 years AGO

Let the required number be x.

Then, (14 - x) / (17 - x) = (34 - x) / (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2
option.(3)

Like? Yes (3) | No   

RAJAT KHANDELWAL   9 years AGO

let r be the remainder that must be subtracted from each no
so
(14-r)/(17-r)=(34-r)/(17-r)
from here
r=2

Like? Yes (3) | No   

Abhishek Sharma   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (3) | No   

ADERU CHENCHU NITHISH   9 years AGO

Let the required number be x

(14 - x) : (17 - x) : : (34 - x) : (42 - x)

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2

Like? Yes (3) | No   

ayswariyauvaraj   9 years AGO

if we subtract 2 from those nos.,it will be divisible by 2

Like? Yes (3) | No   

RAVAL   9 years AGO

14-2=12 & 17-2=15
so,
12/15=4/5
and,
34-2=32 & 42-2=40
so,
32/40= 8/10= 4/5

Like? Yes (3) | No   

prasanna   9 years AGO

subtracting 2
numbers will be 12,15,32,42
to show proportionality a:b::c:d
ad=bc
here 12x42=15x32
hence proved

Like? Yes (3) | No   

Anuj Rai   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

5x = 10

x = 2

Required number = 2.

Like? Yes (3) | No   

MRITUNJAY   9 years AGO

subtract 2 from each number we get
12 15 32 40
12/15=4/5
32/40=4/5

Like? Yes (3) | No   

Ravi shankar   9 years AGO

Let the required number be x.

Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x).

(14 - x) * (42 - x) = (17 - x) * (34 - x)

solving quadratic equation we will get

5x = 10

x = 2

ans=2 , option= 3

Like? Yes (4) | No (2)  

Chandrima Goswami   9 years AGO

Let the required number be x.
Then, (14 - x) : (17 - x) : : (34 - x) : (42 - x)

=> (14 - x) * (42 - x) = (17 - x) * (34 - x)

=> x^2 - 56x + 588 = x^2 - 51x + 578

=> 5x = 10

=> x = 2

So ans is Option 3)

Like? Yes (3) | No (1)  

Archie   9 years AGO

Let the least number be x such that
(14-x):(17-x)::(34-x):(42-x)
Since numbers are proportional according to question
Hence,
Product of mean =Product of extreme
----> (17-x)*(34-x)=(14-x)*(42-x)
Solving we get x=2
Hence option 3 is correct.

Like? Yes (3) | No (1)  

neha gupta   9 years AGO

Let the number to be subtracted be x,then
(14-x):(17-x)::(34-x):(42-x)
Using product of extremes = product of means
(14-x)(42-x)=(17-x)(34-x)
588-56x+x^2 = 578-51x+x^2
588-578=56x-51x
10=5x
2=x
Therefore answer is 2.

Like? Yes (3) | No (3)  

03 Jul 2015 True Discount

Rs.20 is the true discount on Rs.260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same

OPtion

1) Rs. 10
2) Rs. 10.40
3) Rs. 15.20
4) Rs. 13
5) Rs. 14.50
6) Rs. 14.80
7) Rs. 16.20
8) Rs. 16.50
9) Rs. 12
10)Rs. 12.50

Solution

S.I. on Rs. 240 for a given time = Rs. 20
S.I. on Rs. 240 for half the time = Rs. 10
Therefore Rs. 10 is T.D. on Rs. 250
So. T.D. on Rs. 260 = Rs.(10/250 * 260) = Rs. 10.40

Option 2)

Correct Option: 2 Best Solution (35)

Abhishek   9 years AGO

Simple Interest on Rs. (260 - 20) for a given time = Rs. 20.

Simple Interest on Rs. 240 for half the time = Rs. 10.

True Discount on Rs. 250 = Rs. 10.

True Discount. on Rs. 260 = Rs.
10*260/250 = Rs. 10.40

Like? Yes (6) | No (2)  

santosh kumar patel   9 years AGO

given TD=20, S=260 from these we can know PW=S-TD=260-20=240
given TD for sum is 20
SI on PW is TD
=>SI on 240 is 20
now given TD is half of the former time
=> SI on 240 is 10
=> TD on 250(i.e 240+10) is 10 (since given TD on sum=PW+TD is half the former time)
=> TD on 260=(10/250)*260= Rs10.40

Like? Yes (3) | No (1)  

SUSHANT KUMAR   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40

Like? Yes (1) | No   

Pradyumna K S   9 years AGO

given TD=20, S=260 from these we can know PW=S-TD=260-20=240
given TD for sum is 20
SI on PW is TD
=>SI on 240 is 20
now given TD is half of the former time
=> SI on 240 is 10
=> TD on 250(i.e 240+10) is 10 (since given TD on sum=PW+TD is half the former time)
=> TD on 260=(10/250)*260=Rs10.40

Like? Yes (1) | No   

Dinesh Kumar Kumawat   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.
Answer
S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. (10/250)*260 = Rs. 10.40

Like? Yes (2) | No (1)  

Jawahar   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

Like? Yes (1) | No   

pavan kumar   9 years AGO

amount=present worth+true discount
so present worth=260-20=240
true discount=pw*t
where former time t
so t=20/240=1/12
in second case
let's take true discount as x
pw=260-x
time is half of former time i.e t/2
hence t=1/24. (1/2*12)
now true discount,x=(260-x)*1/24
x=10.4

Like? Yes (1) | No   

KAVITHA   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 =Rs.(10/250)*260=10.40

Like? Yes (1) | No   

Archie   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40
250

Like? Yes (1) | No   

viswambher   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs.(10/250) x 260 = Rs. 10.40

Like? Yes (1) | No   

Veerraj Chauhan   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
T.D. on Rs. 260 = Rs. (10/240)x 260 = Rs.10.40

Like? Yes (1) | No   

yashas   9 years AGO

If after certain time the discount is 20 then after half of certain time the discount is 20/2=10

Like? Yes (1) | No   

arush gupta   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40
250

Like? Yes (1) | No   

sourav pal   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. (10/250 x 260 )= Rs. 10.40

Like? Yes (2) | No (2)  

kanithi.shanmukharao   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10/250*260 = Rs. 10.40

Like? Yes (1) | No (1)  

Aravinth kumar   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20
S.I. on Rs. 240 for half the time = Rs. 10
T.D. on Rs. 250 = Rs. 10
T.D. on Rs. 260 = Rs. 10 x 260 /250
=> Rs.10.40

Like? Yes (2) | No (2)  

Chandrima Goswami   9 years AGO

Simple Interest on Rs. (260 - 20) for a given time = Rs. 20
Simple Interest on Rs. 240 for half the time = Rs. 10

True Discount on Rs. 250 = Rs. 10
Therefore, True Discount on Rs. 260 = Rs. (10/250 x 260 ) = Rs. 10.40

i.e Option 2)

Like? Yes (1) | No (1)  

anand vijay   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs.10 /250 x 260 = Rs. 10.40

Like? Yes (1) | No (1)  

Pranati Kundu   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   9 years AGO

Answer:Option- 2)

Explanation:

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = (10x 260)/250= Rs. 10.40

Like? Yes (1) | No (1)  

Anuj Rai   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs.10/250 x 260 = Rs. 10.40

Like? Yes (2) | No (2)  

Dinni   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10. 
T.D. on Rs. 260 = Rs.(10/250)x260= Rs. 10.40

Like? Yes (1) | No (1)  

Anuj Rai   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40
250

Like? Yes (1) | No (1)  

Rohit Kumawat   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.
Answer
S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. (10/250)*260 = Rs. 10.40

Like? Yes (1) | No (1)  

RUPALI DADHE   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. (10 x 260)/250 = Rs. 10.40

Like? Yes (1) | No (1)  

Subhadip Samanta   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs.((10/250)x260)= Rs. 10.40

Like? Yes (2) | No (2)  

Venkatesh kadali   9 years AGO

Simple Interest on (260-20) for a given time=Rs 20

Simple Interest on 240 for half time=Rs 10

true discount on Rs 250=rs 10

true discount on rs 260 is=(10/250)*260=10.40
so answer is 10.40

Like? Yes (1) | No (1)  

Rajanikanta Pradhan   9 years AGO

Si on Rs (260-20) for a given time Is 20
Si. On rs 240 for half the time = rS 10
TD on rs 250 = rs 10
Now TD on 260 =
(10/250)*260 = rs 10.40

Like? Yes (1) | No (1)  

Karthika   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40

Like? Yes (1) | No (1)  

Vivek   9 years AGO

S.I on Rs .(260 -20) for a given time =Rs 20
S.I on Rs 240 for half the time =Rs 10
TD on Rs 250 =Rs 10
TD on Rs 260 =10*260/250=Rs 10.4
Therefore the answer is 2)

Like? Yes (1) | No (1)  

varun Galar   9 years AGO

S.I on Rs (260-20) for a given time = Rs 240
S.I on Rs 240 for half the time = Rs 10
T.D. on Rs 250= Rs 10
Therefore
T.D. on Rs 260= Rs((10/250) x 260) = 10.40

Like? Yes (1) | No (1)  

SOMA NARESH   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = (10/250)* 260 = Rs. 10.40

Like? Yes (1) | No (1)  

MOHAN   9 years AGO

here (260-20)=240
Rs 20 = 240 rate of interest
rate of interest time =1/12

p w=260-x

half of the former time =1/24


x=(260-x)*1/24

24 x=260-x
24 x+x=260
25 x=260
x=260/25
x=10.40
so answer is 10.40

Like? Yes (1) | No (1)  

Abhishek Sharma   9 years AGO

S.I. on Rs. (260 - 20) for a given time = Rs. 20.

S.I. on Rs. 240 for half the time = Rs. 10.

T.D. on Rs. 250 = Rs. 10.

T.D. on Rs. 260 = Rs. 10 x 260 = Rs. 10.40
250

Like? Yes (1) | No (1)  

Shiva Sharma   9 years AGO

Let say rate is x and y year
so-
260*x*y/100=20
after half a former year discount = 10
so total = 250
so in half a year discount = 10.40

Like? Yes (2) | No (3)  

02 Jul 2015 Time and work

Three taps A, B & C are connected to a tank either to fill or empty the tank. All three together can fill the tank in 8 minute whereas only A & B can fill it in 12 min. In a particular day all the three taps are used to fill the tank, they all are opened for 4 min, then A is closed, remaining 2 works for next 2 min then B is closed. Finally C fill the tank in 1 min. In how much time B alone can fill the tank.

OPtion

1) 10 minute
2) 12 minute
3) 12 minute
4) 5 minute 15 second
5) 10 minute 30 second
6) 10 minute 40 second
7) 5 minute 20 second
8) 24 minute
9) 25 minute 50 second
10)18 minute

Solution

Let A, B & C fill the tank in x, y, z min respectively then according tot he given condition.
1/x + 1/y + 1/z = 1/8 (i)
1/x + 1/y = 1/12 (ii)
4/x + 6/y + 7/z = 1
On solving
y = 16/3 minute

Option 7)

Correct Option: 7 Best Solution (7)

Abhishek   9 years AGO

tank filled by C in 1 minute = 1/8 - 1/12 = 1/24 = 4.16%
In 4 minutes all of them filled the tank 50%.
now for next 2 minutes B & C works
i.e. B's 2 minute work + 8.33%
now C fills the tank in 1 minute = 4.16%
total 50% + B's 2 minute work + 12.50%=100%
B's 2 minute work =37.50%
B's one day work = 18.75%
So, B can do whole work in 100/18.75 = 5.33 minutes = 5 minute 20 second.

Like? Yes (7) | No (1)  

Vivek   9 years AGO

Let time taken by A to completely fill the tank be x min
Let time taken by B to completely fill the tank be y min
Let time taken by C to completely fill the tank be z min
Then Given
1/x +1/y +1/z =1/8
Also
1/x+1/y=1/12
Therefore 1/z=1/24
On that particular day
We have
4*(1/x+1/y+1/z)+2*(1/y+1/z)+1*1/z=1
4*1/8 +2*(1/y +1/24)+1/24=1
Simplifying this we get
y=16/3
=5 1/3 =5 min 20 sec
Therefore The answer is 7)

Like? Yes (5) | No   

Shiva Sharma   9 years AGO

Let speed of fluid is x1, x2,x3
let total quantity is Y
so:
12*x1+12*x2 = Y
8*x1+8*x2+8*x3 = Y
2*x2+3*x3 = Y/2
x3 = Y/24
x2 = 3*Y/16
so total time = 16/3 min = 5 min 20 sec

Like? Yes (3) | No   

vimal tiwari   9 years AGO

A+B+C=1/8 in 1 min
A+B= 1/12 in 1 min
so C will be 1/8 - 1/12 = 1/24

NOW all 3 works for 4 min so work after 4 min left
1 min = 1/8
4 min = 4*1/8 = 1/2

and C has to work for 1 min at last i.e. 7th min
and it can work 1/24 in 1 min so

definatly

1/2 - 2min work of B+c =1/24

so B+C = 11/48

B = 3/16 work in 1 min.
B can do full work in 16/3 min or 5min 20 sec

Like? Yes (3) | No   

Chandrima Goswami   9 years AGO

C alone can fill in 1 min= 1/8 - 1/12 = 1/24 part
B+C can fill in 2 min = 1- ( 1/2 + 1/24) = 11/24 part
and in 1 min = 11/48 part
B alone can fill in 1 min = 11/48 - 1/24 = 3/16 part
i.e B alone can fill the tank in 16/3 min = 5 min 20 sec
i.e Option 7)

Like? Yes (2) | No   

Nikhil chavan   9 years AGO

(1/x)+(1/y)+(1/z)=1/8
(1/x)+(1/y)=1/12
from here z=24
then solve 4(1/x+1/y+1/z)+2(1/y+1/z)+1/z=1
y=5 hours 20sec

Like? Yes (2) | No   

praveendas   9 years AGO

all togetherr fill in min is 1/8 ..for 4 miin half of the tank is filled..
c alone fill in min 1/8-1/12=1/24..
then from above cal we can find b is to take 48/9min to fill the tank

Like? Yes (1) | No