M4maths Previous Puzzles

17 Jul 2014 Probability

The sum of 3 different non-zero single digit integers is 11. What will be the probability for the greatest integer to be 6.

OPtion

1) 1/4
2) 4/5
3) 2/3
4) 1/3
5) 1/2
6) 4/3
7) 3/5
8) 1/5
9) 2/5
10) None of these

Solution

According to given condition
x+y+z = 11; x # y # z # 0 (# is not equal)
Possible cases are
8 2 1
7 3 1
6 4 1
6 3 2
5 4 2
Out of 5, 2 cases have 6 as greatest integer so probability = 2/5

option 9)

Correct Option: 9 Best Solution (47)

BHANU KUMAR   10 years AGO

sample space= 1,2,3
1,3,7
1,4,6
2,3,6
2,4,5
n(s)=5
event =6,1,4
6,2,3
n(e)=2
p=n(e)/n(s)
p=2/5

Like? Yes (8) | No   

Ravi Kumar Kodari   10 years AGO

Possibilities are 8 1 2
731
623
641
542

in this only two are having 6 as greatest number.

2/5

Like? Yes (3) | No (1)  

Ramesh Sriram   10 years AGO

8 1 2
7 3 1
6 2 3
6 4 1
5 4 2

there r two possibilities with Greatest number as 6

2/5

Like? Yes (3) | No (1)  

Ann Theressa   10 years AGO

possible outcomes are - (1,2,8) , (1,3,7),(1,4,6),(2,3,6) and (2,4,5)

required outcome - (1,4,6) , (2,3,6)

probability = 2/5

Like? Yes (2) | No (1)  

KRISHNA CHANDRA UPADHYAY   10 years AGO

no. of event=2
total no. of sample points in a sample space=5
therefore, required probability=no. of event/total no. of sample points in a sample space
=2/5

Like? Yes (2) | No (1)  

BITU KUMAR NIRALA   10 years AGO

Event Space=2,
Sample Space=5,
so p=2/5

Like? Yes (1) | No   

Harshad    10 years AGO

1+2+8=11
1+3+7=11
1+4+6=11
2+3+6=11
2+4+5=11
total 5 combinations,
Out of which 2 has "6" as greatest digit,so probability is 2/5

Like? Yes (1) | No   

paaredi muthyam reddy   10 years AGO

8 1 2
7 3 1
6 2 3
6 4 1
5 4 2
there are two possibilities with 6 as greatest number among 5 possibilities

2/5

Like? Yes (2) | No (1)  

HARDIP BHALANI   10 years AGO

1+2+8=11
1+3+7=11
1+4+6=11
2+3+6=11
2+4+5=11
total 5 combinations,
Out of which 2 has "6" as greatest digit,so probability is 2/5

Like? Yes (1) | No   

GOKULARAMANAN   10 years AGO

POSSIBLE SOLUTION IS 6+1+4,6+2+3,8+2+1,7+1+2,5+4+2
FROM ABOVE POSSIBLE TWO POSSIBLES ARE SATISFIES THE CONDITION .PROBABILTY IS 2/5,

Like? Yes (1) | No   

sandhya rani   10 years AGO

{6,4,1},{5,4,2},{6,2,3},{4,4,3},{5,3,3}
is are possible combinations
among them probability for the greatest integer to be 6 is 2/5

Like? Yes (1) | No   

sompon temtheerakij   10 years AGO

1 2 8
1 3 7
1 4 6
2 3 6
2 4 5

Like? Yes (1) | No   

RANJAN KUMAR PANDIT   10 years AGO

1 2 8
1 3 7
1 4 6
2 3 6
2 4 5
so possibility is : 2/5

Like? Yes (1) | No   

Jeniffer.D   10 years AGO

Let the three different non-zero single digit integers be
1 2 8
1 3 7
1 4 6
2 3 6
2 4 5
The probability that the greatest number is 6 is 2/5

Like? Yes (1) | No   

krishna kanth   10 years AGO

numbers will be 812,713,623,614,542,

Like? Yes (1) | No   

Raghvendra Pratap Singh   10 years AGO

All possible cases are:
1,2,8
1,3,7
1,4,6
2,3,6
2,4,5
Hence pblty of 6 being the greatest is : 2/5

Like? Yes (1) | No   

NEHA AGRAWAL   10 years AGO

since only 641,632 are favorable ourcomes from possibilities including 542,731,821 so 2/5.

Like? Yes (1) | No   

suman kumar pan   10 years AGO

The possible combinations are
8,2,1
7,1,3
6,1,4
6,2,3
5,2,4
So the probability is ..... 2/5

Like? Yes (1) | No   

sahil kumar jain   10 years AGO

total of 5 solutions are there ...but only 2 solutions are possible if 6 is
greatest number

Like? Yes (1) | No   

Sundar Kumar   10 years AGO

The sum of 3 different non-zero single digit integers is 11.
so possibles are 1+2+8=11, 1+3+7=11, 1+4+6=11, 2+3+6=11, 2+4+5=11.
And probability for the greatest integer to be 6. so here 2 (i.e 1+4+6=11, 2+3+6=11)

Answer 2/5 (i.e: probability for the greatest integer to be 6 /The sum of 3 different non-zero single digit integers is 11).

Answer : option 9) 2/5

Like? Yes (1) | No   

vibhu raj gupta   10 years AGO

by solving it's find that only 5 pairs are created for sum 11 which are 632,641,731,821,542. for 6 highest integer probability is 2 out of 5

Like? Yes (1) | No   

sangita kumari   10 years AGO

n(S)=(1,4,6),(1,2,8),(1,3,7),(2,3,6),(2,4,5)=5
n(E)=(1,4,6),(2,3,6)=2

p(E)=n(E)/n(S)=2/5

Like? Yes (1) | No   

Ashwin Dinesh   10 years AGO

All possible combinations to get 11 are:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6 BINGO!
2 + 3 + 6 BINGO!
2 + 4 + 5
So, You have 2 out of 5 combinations where you have largest integer as 6.
So probability would be 2/5
Which is option 9) 2/5.

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T.Aravinth kumar   10 years AGO

6/15

Like? Yes (1) | No   

Pranshu Chaurasia   10 years AGO

146,326 have 6,6 combinations and rest 173,128,524 also have 6 combinations each.so total outcome=30 and favorable=12.
probability=12/30=2/5

Like? Yes (1) | No   

vimal   10 years AGO

2/5+2/5+2/5=6/5
In this highest integer is 6 and the sum of both number is 11.
So,answer will be 2/5(option 9)

Like? Yes (1) | No (1)  

naina   10 years AGO

the possilble pairs can be 8,2,1
7,3,1
6,4,1
5,4,2
6,3,2
Total no of cases =5
req cases in which 6 is the greatest integer of all=2
probability=2/5

Like? Yes (1) | No (1)  

shabih abbas   10 years AGO

the combinations formed are
(1,2,8)
(1,3,7)
(1,4,6)
(2,3,6)
(2,4,5)
so the total combination is 5 and the combination which contain greatest integer 6 are (1,4,6) & (2,3,5)
so the probabilty is 2/5

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Varunraj Reddy   10 years AGO

probability=12/30=2/5

Option 9)

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Saraswathy   10 years AGO

Total no. of ways that gives a sum 11 is
(1,2,8)
(1,3,7)
(1,4,6)
(1,5,5)
(2,3,6)
(2,4,5)
Totally 5 ways [since nos should be different... (1,5,5) is not allowed]
No. of combinations having the greatest integer 6 => 2
(1,4,6) nd (2,3,6)

Probability ll be 2/5

Ans : 2/5 (Option 9)

Like? Yes (1) | No (1)  

Ravi Bhalani   10 years AGO

1+2+8=11
1+3+7=11
1+4+6=11
2+3+6=11
2+4+5=11
total 5 combinations,
Out of which 2 has "6" as greatest digit,so probability is 2/5

Like? Yes (1) | No (1)  

Sneha Goel   10 years AGO

there are 5 possibilities: (6,3,2)
(6,4,1)
(8,2,1)
(7,3,1)
(5,4,2)
hence, probability= 2/5

Like? Yes (1) | No (1)  

DILEEP KUMAR   10 years AGO

5 2 4
6 4 1
6 3 2
7 3 1
8 1 2

Like? Yes (1) | No (1)  

JANARTHANAN RAM   10 years AGO

options are (6,4,1),(7,3,1),(8,2,1)(6,3,2)(5,4,2)
so 2/4=2/5

Like? Yes (1) | No (1)  

Tark Patel   10 years AGO

Using 5 summations,
1+2+8
1+3+7
1+4+6
2+3+6
2+4+5

Like? Yes (1) | No (1)  

venkatesh   10 years AGO

(1,2,8) (1,3,7) (1,4,6) (2,3,6) (2,4,5) only two possibilities are there
so the answer is 2/5

Like? Yes (1) | No (1)  

Rakesh Kumar Jangam   10 years AGO

(1,2,8) (1,3,7) (1,4,6) (2,3,6) (2,4,5)

Like? Yes (1) | No (1)  

uma nath jha   10 years AGO

total possibility : 8,2,1
7,3,1
6,4,1
6,3,2
5,4,2

Like? Yes (1) | No (1)  

LOKESH SAMANT   10 years AGO

2/5

(1,2,8) (1,3,7) (1,4,6) (2,3,6) (2,4,5)

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

The total possibilities to get sum of three digit to be 11.
7+3+1
6+3+2,
6+4+1
5+2+4
2+8+1
the probability for the greatest integer to be 6.=2/5.
option 9).

Like? Yes (1) | No (1)  

siddhant   10 years AGO

Considering 6 as a solution...the remaining values come as (7,-2),(8,-3),(9,-4),(-2,7),(-3,8),(-4,9),(1,4),(2,3),(3,2),(4,1).

Therefore 6 is greatest in 4 cases out of 10... Therefore 2/5

Like? Yes (1) | No (1)  

RAHUL RANJAN   10 years AGO

we have the the sample space
(1,2,8)
(1,3,7)
(1,4,6)
(2,4,5)
(2,3,6)
so..n(s)=5
andn(E)=2
so,probablity=2/5

Like? Yes (2) | No (2)  

pulkit goyal   10 years AGO

following possibilities are:
1+2+8
1+3+7
1+4+6
2+3+6
2+4+5
therefore,probability is 2/5

Like? Yes (1) | No (1)  

Ajay Meena   10 years AGO

8+2+1=11
7+3+1=11
6+4+1=11
6+3+2=11
5+4+2=11

then 2/5 (6 coming twice)

Like? Yes (1) | No (1)  

Jasmine Khan   10 years AGO

total number of words=10
total possible numbers having 6 as the greatest number=2
P(6 is the largest number)=4/10=2/5

Like? Yes (1) | No (1)  

Rahul Pandey   10 years AGO

8+2+1=11
7+3+1=11
6+4+1=11
6+3+2=11
5+4+2=11
total 5 cases... out of which in 2 cases 6 is the greatest.
hence p=2/5

Like? Yes (1) | No (1)  

Bishwajeet kumar   10 years AGO

sum of 11 will be formed using combination: (128)=6ways,(236)=6ways,(245)=6ways,(173)=6ways,(164)=6ways
so total possible=30
& total favourable will be(236),(164)=12
so prob.=12/30=2/5

Like? Yes (1) | No (2)  

16 Jul 2014 Solve

The thousand digit of a number is half the units digit & hundreds digit is 1 less than ten's digit. If sum of all the digit of the number is 27, then the number will be

OPtion

1) 4796
2) 4788
3) 3776
4) 4672
5) 4876
6) 3876
7) 2874
8) 4768
9) 3766
10)None of these

Solution

According to given condition, if units digit is x, then thousand digit will be x/2, Similarly ten's digit & hundred digit will be y & y-1
Number will be 1000(x/2) + 100(y-1) + 10y + x;
besides it x/2 + y -1 + y + x = 27
3x + 4y = 56

for x/2 to be an integer, x will be even positive single digit number & y will be any digit from 1 to 9;

for x = 0, 2 & 4; y can not exist.
for x = 6; y = 38/4 non integer
x = 8 & y = 8
Number will be
1000(8/2) + 100(8-1) + 10(8) + 8
= 4788
Option 2)

Correct Option: 2 Best Solution (139)

Sundar Kumar   10 years AGO

4+7+8+8=27
Answer: option 2) 4788

Like? Yes (26) | No (6)  

Ann Theressa   10 years AGO

4788

1/2 of one's digit = 1/2*8 = 4 = thousand's digit
ten's digit - 1 = 8-1 = 7 = hundred's digit
sum of digits = 4+7+8+8 = 27

Like? Yes (4) | No   

prashant kumar   10 years AGO

let number is \'abcd\'
a=d/2
b=c-1
a+b+c+d=27
check the option
a=8/2=4
b=8-1=7
a+b+c+d=4+7+8+8=27
this answer satisfies all equestion

Like? Yes (3) | No   

Dr.Dipin Singh   10 years AGO

out of given options, only option 2 satisfaies the given conditions.
The thousand digit of a number (4) is half the units digit (8) & hundreds digit (7) is 1 less than ten's digit (8). If sum of all the digit of the number is 27 (4+7+8+8).

Like? Yes (4) | No (2)  

Anitha   10 years AGO

1st condition: The thousand digit is half the unit digit.
=>In the solution the thousand digit is 4 and the unit digit is 8
8/2=4(4 is half the digit 8..1st condition is satisfied)

2nd Condition: Hundreds digit is 1 less than the ten's digit.
=>In the solution the hundreds digit is 7 and ten's digit is 8.
8-1=7(7 is 1 less than 8..2nd condition is satisfied)

3rd Condition: The sum of the number is 27
=>4+7+8+8=27(3rd condition is satisfied)

So the solution is 4788(option 2)

Like? Yes (3) | No (1)  

Komala.G   10 years AGO

Option 2
thousand digit is 4 which is half of unit digit
hundreds digit is 7 which is 1 less than ten's digit
ten's digit is 8 in accordance to hundred's place
unit digit is 8 in accordance to thousand's place

Like? Yes (3) | No (1)  

Ravi Kumar Kodari   10 years AGO

by verification
using first condition and second condition 2 satisfied and sum of the digits is 27

Like? Yes (3) | No (1)  

ravindra   10 years AGO

4788 satifies all the conditions

Like? Yes (2) | No   

Ashwin Dinesh   10 years AGO

Just count the sum of digits mahhnn... I think you shouldn't have given options...

Like? Yes (2) | No   

Aman   10 years AGO

last digit can be 2,4,6,8.
sum of digits is 27, then
last digit should be 8 and first digit will be 4 so that balance sum of 15 from 2 digits can be obtained by choosing 7 and 8.
so required number is 4788.

Like? Yes (2) | No (1)  

rahi   10 years AGO

there is only one number that's sum is 27 and and full fill asked
question criteria is 4788.
option is 2.

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priyanka    10 years AGO

answer is second...add 4+7+8+8..
some tym answer give u hint

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Asha Praveena   10 years AGO

thousand digit of a number is half the unit digit number by this condition we remove some of the given answers.
by condition some of the answers are removed.
remaining answer is 4788 and the sum is 27.so the answer is 4788.

Like? Yes (2) | No (1)  

sompon temtheerakij   10 years AGO

Ans. 2) 4788
4+7+8+8 = 27
4 is a half of 8
7 is 1 less than 8

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Priya Verma   10 years AGO

use hint & trial method

Like? Yes (2) | No (1)  

Pradeep   10 years AGO

4788 as the thousand digit number is half of its unit digit ;; in this unit digit is 8 and its half is thousand digit 8/2=4;; and hundred digit is less than ten's digit ;; in this tens digit is 8 and 8-1=7 will be the hundreds digit and finally sum is 4+7+8+8=27

Like? Yes (1) | No   

monika garg   10 years AGO

4+7+8+8=27

Like? Yes (2) | No (1)  

Sandeep singh   10 years AGO

8/2=4,8-1=7,4+7+8+8=27
therefore no.is 4788

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Amrita priyadarshi   10 years AGO

answer will be 2-4788 by hit and trial method only option 2 is satisfying all conditions...

Like? Yes (2) | No (1)  

T.RAJAMADHANGI   10 years AGO

hundred digit:7
Ten's digit:8
So 7 is less than 8.
Possibilities are 4788 and 4672
then the sum of 4+7+8+8=27
ANS:4788

Like? Yes (1) | No   

HARDIP BHALANI   10 years AGO

By checking Options

Like? Yes (1) | No   

Ravi Bhalani   10 years AGO

by checking options

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Harshad    10 years AGO

by checking options

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paaredi muthyam reddy   10 years AGO

by verification

Like? Yes (4) | No (3)  

nalini singh   10 years AGO

As per question:
8/2=4(thousand digit of a number is half the units digit)
8-1=7(hundreds digit is 1 less than ten\'s digit)
so 2nd option is correct.

Like? Yes (2) | No (1)  

VIMALRAJ V   10 years AGO

Sum of the numbers in 4+7+8+8=27
Thousand digit is 4 which is half of ones digit i.e 8
Hundred digit is 7 which is 1 less than tens digit i.e 7
Therefor answer is option 2 i.e. 4788

Like? Yes (2) | No (1)  

Kowshik Sarker   10 years AGO

Let the no.is wxyz. According to the given condition..
w=z/2 and x=y-1 and
w+x+y+z=27
or,w+(y-1)+y+(2*w)=27
or,3w+2y=28
w must be between 1,2,3,4 because if w>4 then 2w=z will be greater than 10 which is impossible as z is the unit place no. so by trial and error method we get
(3*4)+(2*8)=12+16=28
so w=4 and y=8
so z=4*2=8 and x=8-1=7
thus the no.is 4788.

Like? Yes (1) | No   

ABU ZAFAR   10 years AGO

4+7+8+8=27
4=1/2*8
7=8-1

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sangita kumari   10 years AGO

According to question
x/2+(y-1)+y+x=27
3*x+4*y=56
x=8,y=8
then
4+7+8+8=27
number will be 4788

Like? Yes (1) | No   

Jyotsna   10 years AGO

8/2=4
7 is less than 1
so ans is 2) 4788

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shachi   10 years AGO

check by answers

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Vignesh   10 years AGO

because the sum of all digits is 27

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sureshkumar   10 years AGO

because the answer follows all the logic in the question

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rahul   10 years AGO

4788- unit digit 8 nd thousand digit is 4 so i,e half
7 hundred is 1 less than tens i.e 8 and the sum of digit is 4+7+8+8=27 so 4788 is correct.

Like? Yes (1) | No   

Aravinth kumar   10 years AGO

Ans=4788
The thousand digit (4) of a number is half the units digit (8)
hundreds digit ( 7 ) is 1 less than ten's digit( 8 )
(4+7+8+8)=sum of all the digit of the number is 27

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Nikhil chavan   10 years AGO

Jst check options...

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Rakesh Kumar Jangam   10 years AGO

let n be a digit of the given four digit number.
accirding to given condition, lets have a logic equation as
(n)(2n-1)(2n)(2n) → eqn(1) be given four digit number
now n+2n-1+2n+2n=27;
7n=28;
n=4
now substitute n in given eqn(1) we get
ans: 4788

Like? Yes (1) | No   

Sasikumar   10 years AGO

Thousand's digit : 4 (which is half of Unit digit : 8)
Hundred's digit : 7 (which is 1 less than ten's digit : 8)
Sum of 4+7+8+8 = 27

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Aravinthkumar   10 years AGO

(4+7+8+8)=sum of all the digit of the number is 27

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nagineni sukumar   10 years AGO

4+7+8+8=27

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rohit   10 years AGO

It follows all the condition given in question

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Tark Patel   10 years AGO

Thosand digit of a number is half the unit digit so 4 is half of 8 ,

Hundred digit is 1 less then the ten's digit so 7 is 1 less then 8 ,

and sum is 27 so 4+7+8+8=27.
Answer is 4788

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S M ANIRUDH   10 years AGO

Checking all the options

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Satishbabu   10 years AGO

By checking the options with the given info,
=> sum of all digits=27
Therefore answer is option(2)

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Neelakumar   10 years AGO

unitdigit=8
1000sdigit=4
10s digit=8
100sdigit=7
total number=28
number=4788

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Swapnil Shah   10 years AGO

4+7+8+8= 27 4 is half of 2 , 7 is one less of 8

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JayaNagasri Valicherla   10 years AGO

all the options are not equal to 27
in that only 2nd option is equal to 27
so option 2)4788

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Kaustubh karekar   10 years AGO

this is the only number with sum=27

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sriniveditha   10 years AGO

8/2=4;8-1=7&4+7+8+8=27

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nehal parmar   10 years AGO

let no be abcd...
now a=d/2 .....(1)
b=c-1......(2)
a+b+c+d=27......(3)
so, using d=2a and b=c-1
we get 3a +2c=28......(4)

only 4788 follows all 4 equations...so ans is 4788

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S.Rosyponmary   10 years AGO

4 is the half of unit digit 8,
7 is 1 less than the 8
sum of all digits are equal to 27

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savita   10 years AGO

in option 2 thousand digit is 4 & unit digit is 8 &4 is half of 8.hundred digit is 7 & tens digit is 8. 7 is 1 less than 8 so the option 2 is the correct

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Hari Sankhar   10 years AGO

in 4788 4 (thousand digit) is half of 8 (unit digit) and 8(hundred digit)>7(ten digit) sum of 4+7+8+8=27

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Ramsb   10 years AGO

the sum of digits is 27..
the only 2 option is 4+7+8+8=27

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NAMBURU L V S MOUNIKA   10 years AGO

8/2=4&8-1=7=>answer is4788

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Rayapureddy V Sai Kiran   10 years AGO

go for trail n error method....

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ANANDAKUMAR   10 years AGO

4+7+8+8=27

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Srikanth   10 years AGO

half of 8 is 4....7 is 1 less than 8...sum is 27

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ANUP KUMAR   10 years AGO

check option

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Dheeraj   10 years AGO

it has all the requirements what should be

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goli kiranmaye   10 years AGO

by solving the equation 3a+2c=28
by verifying the options 4788 is the correct answer

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sai naveen vanapalli   10 years AGO

w+x+y+z=27
w=z/2 ; x=y-1
(3z/2)+2y=28
3z+4y=56

also z and y must be natural numbers b/w 1-9
by verification ans is 4788

Like? Yes (1) | No   

Pragati Raut   10 years AGO

As the thausand digit is half the unit digit then option 1,4,5 are cancel out...
then check hundreds digit is less than ten's digit...then only 2 answer is come out.

Like? Yes (1) | No   

Nilesh Dattatraya Veer   10 years AGO

by up plying conditions on number.

Like? Yes (1) | No   

Anand Singh   10 years AGO

from options.............

Like? Yes (1) | No   

sushant narayan   10 years AGO

all condition satisfy in this number 4788

Like? Yes (1) | No   

Tamilarasi   10 years AGO

answer is 4788

unit digit\'s=8
thousand\'s digit=4
ten\'s digit=8
hundred digit\'s=7
sum=4+7+8+8=27

Like? Yes (1) | No   

pandit abhilash   10 years AGO

4 is 1/2 of 8 and 7 is 1 less than 8 and 4+7+8+8=27

Like? Yes (1) | No   

sanat maity   10 years AGO

from option,it is clear that,
The thousand digit of a number is half the units digit is only matched with option 2,7,8.
as sum of all the digit of the number is 27,
so option 2 is correct.

Like? Yes (1) | No   

Brijesh Rawat   10 years AGO

4788
4 is half of 8
7 is 1 less then 8
4+7+8+8=27

Like? Yes (1) | No   

chaitanya anand   10 years AGO

sum of number is 27

Like? Yes (1) | No   

priya saha   10 years AGO

it satisfies all the condition given abv

Like? Yes (1) | No   

Anilkumar   10 years AGO

The only number that fulfil the parameters is 4788.

Like? Yes (1) | No   

Rahul Pandey   10 years AGO

4=1/2 of 8
7= 1 less than 8

Like? Yes (1) | No   

nirmal kumar saini   10 years AGO

assume the digit are a,b,c,d for thousand,hundred...... respectively
given
a=d/2;
b=c-1;
and
a+b+c+d=27;
solving all we get the answer

Like? Yes (1) | No   

sravya   10 years AGO

from the option verification..
option 2 satisfies all the conditions....
so ans is..2)4788

Like? Yes (1) | No   

Rahul   10 years AGO

4+7+8+8=27 and rest all in not 27

Like? Yes (1) | No   

AMIT SINGH   10 years AGO

in 4788 all the conditions given are fullfilled...

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

4+7+8+8=27

Like? Yes (1) | No   

KRISHNA CHANDRA UPADHYAY   10 years AGO

7=8-1 and 4=8/2

Like? Yes (2) | No (2)  

Ramesh Sriram   10 years AGO

By verification
1. condition is satisfied by 2,3,6,7,8,9 options
eliminate remaining options
2.condition satisfied by 2 option only and
3.condition 4+7+8+8=27
hence ans 2 option

Like? Yes (3) | No (3)  

pawan kumar chhipa   10 years AGO

from option
2) 4788

Like? Yes (1) | No (1)  

Shashank Kumar    10 years AGO

thousand digit = 4
unit digit = 8
hundred digit = 7
tens digit = 8
sum= 4+8+7+8 = 27

Like? Yes (1) | No (1)  

Saroj kumar   10 years AGO

By checking options we get the answer.....

Like? Yes (1) | No (1)  

Udai Pratap Singh   10 years AGO

number= x/2 y-1 y x
4y-2+3x=54
4y+3x=56
put x=8 ,y=8 we get 56

Like? Yes (1) | No (1)  

Arijit Acharyya   10 years AGO

4 is half of 8 and 8 is less than 7 sum of all digits=27 so, the number is 4788

Like? Yes (1) | No (1)  

Siva Narayana Racharla   10 years AGO

4 is half of 8
7 is one less than 8
the total sum of digits is 4+7+7+7=27

Like? Yes (1) | No (1)  

deepak   10 years AGO

let no is xmny
given that y=2x & n=m+1
x+m+n+y=27
x+m+m+1+2x=27
3x+2m=26
only 4788 satisfy the above equation and given condition.
hence ans=4788

Like? Yes (1) | No (1)  

naina   10 years AGO

from option using 4788
4 is half of digit at unit place &hundred digit(7)is 1 less than ten's(8)
also sum of all 4 digit is 27

Like? Yes (1) | No (1)  

V SARATH KUMAR   10 years AGO

Option is 2)4788
number in thousands digit is 4 which is half of units digit(8).
hundred digit(7) is one less than tens digit(8).
On adding all the numbers we get 27.

Like? Yes (1) | No (1)  

vinusha reddy   10 years AGO

units digit=x
thousands digit=x/2
tens digit=x
hundreds digit=x-1
sum of all the digits =27
x/2+x-1+x+x=27
x=8
then the num=4788

Like? Yes (1) | No (1)  

RAHUL RANJAN   10 years AGO

from the given option 2)4788
all the condition is matched.

Like? Yes (3) | No (3)  

selvakumar v   10 years AGO

4788
4--8 thousands digit is half of unit digit
-78- hundreds digit is 1 less than the tens digit
4+7+8+8=27

so answer must be option 2

Like? Yes (1) | No (1)  

SUMIT   10 years AGO

Check through options only 2 will satisfy.

Like? Yes (1) | No (1)  

siddhant   10 years AGO

Possible values for unit place can be..2,4,6,8
If 2 is unit place digit then thsnd place is 1..
Therefore 1+(x-1)+x+2=27
Bt x is not integer
Now if unit place 4..not satisfied
If unit place 6 ..not satisfied
If unit place 8 then thousand place 4...
Therefore 4+(x-1)+x+8=27
X=8...
Therefore no is 4788

Like? Yes (1) | No (1)  

LOKESH SAMANT   10 years AGO

The thousand digit of a number is half the units digit & hundreds digit is 1 less than ten's digit.

and 4+7+8+8=27

Like? Yes (1) | No (1)  

Logesh   10 years AGO

Option 2 only satisfies all the given condition

Like? Yes (1) | No (1)  

ananthavalli   10 years AGO

Thousand digit =4 because which half of its unit digit 8
Hundred digit =7 which is less than 1 of its ten's digit 8
Then 4+7+8+8 =27
so option 2) is correct

Like? Yes (1) | No (1)  

dushyant singh pawar   10 years AGO

4+7+8+8=27

and thousand digit(4)=1/2 of(unit digit)(8)

hundred digit (7)=tenth digit (8)-1

hence answer is option 2

Like? Yes (1) | No (1)  

chauhan dhara vinayakkumar   10 years AGO

8/4=2
8-7=1
4+7+8+8=27

Like? Yes (1) | No (1)  

suman kumar pan   10 years AGO

the eqn is ,
x+x/2+y+(y-1)=27.
=> 3x+4y=27...
from the eqn it is clear...the value of x is eithet 2/4/6/8
from this the value of x is 8...& y is 8....
so the no is .... 4788

Like? Yes (1) | No (1)  

Madan   10 years AGO

4=8/2
7=8-1
4+7+8+8=27

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

IN the given option only one number satisfy the condition given in question.
i.e. option 2)

Like? Yes (1) | No (1)  

Nippun Kumar   10 years AGO

4788, is the correct option. 4 is in Thousand place which is half of 8 in the unit place. 7 is in the hundreds place which is less then one in the tens place. and the sum is 27. hence it is one of the fusible solution..

Like? Yes (1) | No (1)  

G.manikanda prabu   10 years AGO

sum is 27

Like? Yes (1) | No (1)  

Shashi nath jha   10 years AGO

only option with all constrant..

Like? Yes (1) | No (1)  

Shaik Riyaz   10 years AGO

in the 2option the total sum is27,and in
hundred digit is less than tens digit..

Like? Yes (1) | No (1)  

kanithi.venkatesh   10 years AGO

by checking given conditions and options , option 2satisfies all conditions

Like? Yes (1) | No (1)  

Lakshmi Narmada   10 years AGO

4 IS HALF OF 8 and 7 is one less than 8 and the sum of the digits is 27 hence 4788 is the ans

Like? Yes (1) | No (1)  

Ishan Gautam   10 years AGO

in no. 4788 the thousand digit i.e., 4 is the half of unit digit i.e., 8.
also the hundred digit i.e., 7 is one less than ten digit i.e.,8

Like? Yes (1) | No (1)  

Siddharth Patel   10 years AGO

Becoz sum of all the number is 27.

Like? Yes (1) | No (1)  

sabir ahmd   10 years AGO

here ,
1000 digit is 4 which is half of units digit (8);
100 digit is 7 which is i less than ten's digit (8);
and sum of all digit is =4+7+8+8=27

Like? Yes (1) | No (1)  

Sneha   10 years AGO

8/4=2
8=7+1
4+7+8+8=27
so option 2 i.e., 4788

Like? Yes (1) | No (1)  

Kritika Kathi   10 years AGO

8/2=4 (which is at thousand's place).
7 is one less than 8 (hundred's and ten's place digit)
4+7+8+8=27

Like? Yes (1) | No (1)  

nagarajarao   10 years AGO

unit digit = 8
thousand digit = 8/2= 4
hundred digit = 7 one less than ten's dgit 8

therefore answer is 4788

Like? Yes (1) | No (1)  

NEHA AGRAWAL   10 years AGO

by putting the values of suppose abcd no...now make an eqn accordingly..i.e. 3a+2c=28..therefore a=4,b=8..also other values are also satisfied

Like? Yes (1) | No (1)  

Rashmi bharti   10 years AGO

4=8/2 and 7=8-1.
4+7+8+8=27.
so 4788 is correct

Like? Yes (1) | No (1)  

SHUBHAM KUMAR   10 years AGO

thousand = 1/2*unit digit
hundred=ten-1

Like? Yes (1) | No (1)  

Radhika   10 years AGO

only option 2 has sum of digits equal to 27 and thousand digit is 4 which is half of 8 and hundred digit is 7 less than one (8-1)=7

Like? Yes (1) | No (1)  

santhosh reddy   10 years AGO

4+7+8+8=27
7 is in 100's digit which is 1 less than 8 i.e., in 10's digit

Like? Yes (1) | No (1)  

Liti   10 years AGO

4+7+8+8=27

Like? Yes (1) | No (1)  

BANDELA PRASHANTH   10 years AGO

sum of all digits is 27

Like? Yes (1) | No (1)  

Nitin   10 years AGO

by solving the equations !!!

Like? Yes (1) | No (1)  

RANJAN KUMAR PANDIT   10 years AGO

by option 2
thousand digit no - 4
unit digit no -4*2=8
tens digit no=8
hundred digit no=8-1=7

Like? Yes (2) | No (3)  

Yogesh   10 years AGO

Let unit digit is x & tenth digit is y.
Thousand digit is x/2.
Hundred digit is y-1.
then by options
only 2nd option satisfy the condition.
x=8 y=8
thousand digit=8/2=4
hundred digit=8-1=7
answer=4788.

Like? Yes (2) | No (3)  

shabih abbas   10 years AGO

The thousand digit of number in the option is 4 and units digit is 8 so thousand\'s digit is half of units digit and 100th digit is 7 which is 1 less than 10's digit(8) and the sum is 27 so option 2 is suitable.

Like? Yes (1) | No (2)  

Dinesh thatti   10 years AGO

we take 4788
thousand digit is half of unit digit
4 which is half of 8

hundreds digit is 1 less than ten's digit
7 which is 1 less than 8

sum of the digits is 27

so answer is 4788

Like? Yes (1) | No (2)  

Satyaki    10 years AGO

Go with the options.. And check each numbers.. 4788 satisfies all the conditions!!

Like? Yes (1) | No (2)  

dheeraj   10 years AGO

simple

Like? Yes (1) | No (2)  

Saraswathy   10 years AGO

Option (2) satisfies all the conditions...

Like? Yes (1) | No (2)  

shree   10 years AGO

5555555555555555

Like? Yes (1) | No (2)  

BHANU KUMAR   10 years AGO

7=8-1
and 4=8/2

Like? Yes (4) | No (5)  

Sneha Goel   10 years AGO

All the conditions are satisfied only by option 2.

Like? Yes (1) | No (2)  

Basavasagar   10 years AGO

4 is half of 8,7 is one less than 8 and sum is 4+7+8+8=27

Like? Yes (1) | No (2)  

Sourojit Dhua   10 years AGO

4=8/2
7=8-1
4+7+8+8=27
therefore answer= 4788

Like? Yes (4) | No (5)  

pankaj kumar   10 years AGO

4788
here thousand digit 4= unit didgit 8/2
and hundreds digit 7 is 1 less than ten's digit 8
and sum of digit is 27

Like? Yes (2) | No (3)  

Varunraj Reddy   10 years AGO

Option 2) satisfies all the conditions given.

Like? Yes (2) | No (3)  

Satyaki Chowdhury   10 years AGO

LET THE NUMBER IS REPRESENTED BY ABCD.
ACCORDING TO SUM, A=0.5D, B+1=C AND A+B+C+D=27
NOW,
A+B+1+C+D=28
or,2C+A+2A=28 (SINCE B+1=C & D=2A)
or,2C+3A=28

Now, checking the options on this condition, we will see that only 4788 satisfies it.

So answer = 4788. (OPTION 2)

Like? Yes (1) | No (2)  

Soheli Bhaduri   10 years AGO

ANs:Option 2 (4788)
Let the no. be wxyz
w=1/2z,x=y-1,x+y+z=27
Only option 2 i.e 4788 satisfies the three equations.
So,ans:2 (4788)

Like? Yes (1) | No (3)  

15 Jul 2014 Solve

If 3^x - 3^(x-1) = 18, then the value of x^x is

OPtion

1) 3
2) 18
3) 8
4) 19
5) 27
6) 36
7) 216
8) 81
9) 64
10)None of these

Solution

3^x - 3^(x-1) = 18
3^x - (3^x/3) = 18
Let 3^x = a
a - a/3 = 18
2a = 54; a = 27
3^x = 27
x = 3
x^x = 3^3 = 27
Option 5)

Correct Option: 5 Best Solution (76)

Sundar Kumar   10 years AGO

3^x - 3^(x-1) = 18
3^x-3^x.3^-1=18
3^x(1-1/3)=18
3^x=18*3/2
3^x=27
3^x=3^3
here x=3
then , x^x=3^3=27
Answer: option 5) 27

Like? Yes (77) | No (18)  

Sourojit Dhua   10 years AGO

3^3- 3^(3-1) = 18
therefore,
3^3=27

Like? Yes (94) | No (79)  

nigarashraf   10 years AGO

3^x(2/3)=18
x=3
x^x=3^3=27

Like? Yes (22) | No (17)  

SUMIT   10 years AGO

3^x-1(3-1)=18
so,3^x-1=9
x=3
so x^x=27

Like? Yes (6) | No (2)  

priyanka    10 years AGO

3^x-3^x/3=3^x(1-1/3)=18
3^x(2/3)=18
x=3
x^x=3^3=27

Like? Yes (7) | No (4)  

Sandeep singh   10 years AGO

3^3=27, 3^(3-1)=9. 27-9=18
Therefore x=3
Now 3^3=27

Like? Yes (6) | No (3)  

Arpan Bhattacharyya   10 years AGO

3^x=3^3
x=3
again x^x=3^3
=27

Like? Yes (6) | No (4)  

sompon temtheerakij   10 years AGO

3^x - 3^x-1 = 18
3^3 - 3^3-1 = 18
x = 3
x^x = 3^3 = 27

Like? Yes (3) | No (1)  

devmitra   10 years AGO

3^x(1-1/3)=18
=>3^x(2/3)=18
=>3^x=27
=>3^x=3^3
=>x=3=>3^3=27...option 5

Like? Yes (3) | No (2)  

Ravi Bhalani   10 years AGO

here x=3
so,27-9=18
3^3=27

Like? Yes (4) | No (4)  

S M ANIRUDH   10 years AGO

3^x-3^(x-1)=18
Clearly x= 3 satisfies above equation
X^x= 3^3 = 27

Like? Yes (3) | No (3)  

Sneha Goel   10 years AGO

solving the equation, we get
3^x=3^3
x=3
hence, x^x=3^3=27

Like? Yes (5) | No (6)  

Satyaki    10 years AGO

LET x^3=a
so our equation becomes ,
a-a/3=18
Solving we get, a=27
so. x^3=27 ,
then x=3
so x^x= 3^3 = 27

Like? Yes (4) | No (6)  

naina   10 years AGO

put x= 3
3^3-3^(3-1)=18
=>x=3
x^x=3^3=27

Like? Yes (3) | No (5)  

monika garg   10 years AGO

3^x(1-(1/3))=18

(3^x)*(2/3)=18

3^x=27

x=3

then x^x=27

Ans = 27

Like? Yes (2) | No (4)  

dushyant singh pawar   10 years AGO

Given 3^x-3^(x-1)=18

or 3^x-(3^x/3)=18

or 3*3^x-3^x=18*3=54

or 3^x(3-1)=54

or 3^x=54/2

or 3^x=27

or 3^x=3^3

hence, if bases are same therefore, x=3

hence x^x=3^3=27 [Answer is option 5]

Like? Yes (2) | No (4)  

pankaj kumar   10 years AGO

3^x - 3^(x-1) =18
3^(x-1) { 3-1 } =18
3^(x-1) = 18/2 =9 =3^2
x-1 =2
x=3

so x^x = 3^3 =27

Like? Yes (3) | No (5)  

KRISHNA CHANDRA UPADHYAY   10 years AGO

let x = 3 then 3^3- 3^2=18 satisfied so we can take x=3 then
x^X=3^3=27

Like? Yes (4) | No (6)  

Nilesh Dattatraya Veer   10 years AGO

3^x - 3^(x-1)= 3^x - 3^x/3 = 3^x(1-1/3)=18
3^x *(2/3)=18
3^x=27
x=3
so (x^x)=3^3=27

Like? Yes (2) | No (4)  

Soheli Bhaduri   10 years AGO

Ans:5 (27)
3^x-3^x-1=18
3^x-3^x/3=18
3^x[1-1/3]=18
3^x=18*3/2=27=3^3
So,x=3.
x^x=3^3=27.

Like? Yes (3) | No (6)  

Grishma Shah   10 years AGO

dividing the given eq by 3^x
resulting to: 2/3 = 18/3^x
hence Solving above 3^x = 27
Therefore X = 3
X^X = 3^3 = 27

Like? Yes (3) | No (6)  

S.Rosyponmary   10 years AGO

3^x-3^(x-1)=18
the x value is 3 so 27-9=18;

3^3=27

Like? Yes (1) | No (4)  

Abhishek Jana   10 years AGO

3^x-3^(x-1)= (3.3^x-3^x)/3=3^x(3-1)/3=18
3^3=27
x= 3
X^X=27

Like? Yes (1) | No (4)  

Barun Kumar   10 years AGO

3^(x-1)*{3-1}=18
3^(x-1)=9
3^(x-1)=3^2
equating the powers
x-1=2
=>x=3
therefore x^x=3^3=27 ans

Like? Yes (1) | No (4)  

Subhajit Naskar   10 years AGO

x=3
then x^x = 27

Like? Yes (1) | No (4)  

RANJAN KUMAR PANDIT   10 years AGO

3^3-3^(3-1)=18
so x=3
x^x=27

Like? Yes (1) | No (4)  

BHANU KUMAR   10 years AGO

let x =3
then 3^x=3^3=27
3^x-1=3^2=9
hence it satisfies the given equation.
so x^x=3^3=27

Like? Yes (3) | No (6)  

Brijesh Rawat   10 years AGO

3^3-3^(3-1)=18
3^3=27

Like? Yes (1) | No (4)  

Supriyo Dey   10 years AGO

By calculating,x=3 so x^x=27

Like? Yes (1) | No (4)  

saurabh gupta   10 years AGO

3^x(1-1/3)=18
3^x=27
x=3
ans=27

Like? Yes (1) | No (4)  

Anitha   10 years AGO

On substituting x=3 , the equation is satisfied.. so 3^3=27.
The answer is 27(option 5)

Like? Yes (1) | No (4)  

Dr.Dipin Singh   10 years AGO

3^x - 3^(x-1) = 18
let
3^(x-1) = y;
then
3y-y=18
y=9=3^(x-1)=3^2
(x-1)=2
x=3
x^x=3^3=27

Like? Yes (3) | No (6)  

Sasikumar   10 years AGO

x= 3
3^3 = 27
3^(3-1) = 9
27 - 9 = 18

x^x = 3^3 = 27

Like? Yes (1) | No (4)  

Shaik Riyaz   10 years AGO

Substitute through options...let x=3
After substitute 18 is answer..after that 3 to the power of 3 nothing but 27

Like? Yes (1) | No (4)  

Ashish kumar   10 years AGO

3^x = 3^3
x = 3
so, 3^3 = 27

Like? Yes (1) | No (4)  

Ankur Tamrakar   10 years AGO

3^x(1-1/3)=18
3^x=(18*3)/2
3^x=27
x=3
x^x=27 So 5)

Like? Yes (1) | No (4)  

deepak   10 years AGO

by hit & trail method...
x=3 satisfy this equation
hence x=3;
so, 3^3=27

Like? Yes (1) | No (4)  

NITIN KUMAR GOYAL   10 years AGO

X=3

Like? Yes (1) | No (4)  

HARMEET KAUR   10 years AGO

If 3^x - 3^(x-1) = 18, then
x=3
the value of x^x =3^3=27

Like? Yes (2) | No (5)  

saira fatma   10 years AGO

3^(x-1)[3-1]=3^2.2
=3^(x-1).2=3^2.2
=(x-1)=2

=x=3
x^x=3^3=27

Like? Yes (1) | No (4)  

SHANMUGAPRIIYAN   10 years AGO

x is 3
3^3=27-3^(3-1)=18
SO x^x=3^3=27

Like? Yes (2) | No (5)  

vishnuvardhan   10 years AGO

let 3^x=y
2y/3=18
y=27
3^x=27
x=3
x^x=3^3=27

Like? Yes (1) | No (4)  

Jonibek   10 years AGO

3*3^x-3^x=3*18
3^x(3-1)=54
3^x=27
x=3
x^x=27

Like? Yes (1) | No (4)  

juhi   10 years AGO

3^x-1(3-1)=3^2*2
value of x will be equal to 3 then the value of x^x means 3^3 is 27.

Like? Yes (1) | No (4)  

Ann Theressa   10 years AGO

3^x - 3^(x-1) = 18
==> x = 3

x^x = 3^3 = 27

Like? Yes (2) | No (6)  

RAKESH   10 years AGO

3^x - 3^(x-1) = 18
=> 3^x - 3^x / 3 = 18
=> 2/3 * 3^x = 18
=> 3^x = 27
=> x = 3
=> x^x = 27

Like? Yes (3) | No (7)  

Yogesh   10 years AGO

3^x-3^(x-1)=18
3^x(1-1/3)=18
3^x(2/3)=18
3^x=27
3^x=3^3
x=3
x^x=3^3=27

Like? Yes (1) | No (5)  

Devendra Marghade   10 years AGO

3^x- 3^(x-1)=18
3^x[1-(1/3)]=18
3^x=27 ,x=3
So x^x= 3^3= 27

Like? Yes (4) | No (8)  

V SARATH KUMAR   10 years AGO

On solving the above equation we have x=3 so 3^3=27.27 is the answer

Like? Yes (2) | No (6)  

Varunraj Reddy   10 years AGO

3^x-3^(x-1)=18
3^x-3^x.3^-1=18
3^x(1-3^-1)=18
3^x(2/3)=18
3^x=27
x=3
Then x^x=3^3=27

Option 5)

Like? Yes (2) | No (6)  

aditya saraswat   10 years AGO

3^x-3^(x-1)=18
3^x(1-1/3)=18
3^x*2/3=18
3^(x-1)=9 => x-1=2
x=3 =>x^x=3^3=27

Like? Yes (1) | No (5)  

vinusha reddy   10 years AGO

3^x-3^x/3=18
3^x(1-1/3)=18
3^x=27
3^x=3^3
x=3
then 3^3=27

Like? Yes (2) | No (6)  

Shashank Kumar    10 years AGO

3^3=27
3^2=9
27-9=18
so value of x is 3
x^x=3^3=27

Like? Yes (1) | No (5)  

Lakshmi Narmada   10 years AGO

3^3-3^(3-1)=27-9=18 hence 3^3=27

Like? Yes (1) | No (5)  

suman kumar pan   10 years AGO

the value of x is 3...so 3^3=27

Like? Yes (1) | No (5)  

shahin raza   10 years AGO

3^3-3^(3-1)=27-9=18 so x=3,x^x=3^3=27

Like? Yes (1) | No (5)  

Ravi Kumar Kodari   10 years AGO

3^x-3^x/3=18
3^x(2/3)=18
x=3
so,x^x=27

Like? Yes (3) | No (7)  

Ramesh Sriram   10 years AGO

3^x-3^(x-1)=18
3^x-3^x/3=18
3^x(3-1)=18*3
3^x=18*3/2
3^x=27
3^x=3^3
x=3
x^x=3^3=27

Like? Yes (3) | No (7)  

Anish Mathur   10 years AGO

3^(x-(x-1))=18
x=3
3^3=27

Like? Yes (1) | No (5)  

sai naveen vanapalli   10 years AGO

x=3
and x^x=27

Like? Yes (1) | No (5)  

ATUL KUMAR   10 years AGO

(3^3)-(3^(3-1))=18
3^3=27

Like? Yes (1) | No (5)  

ganesh saicharan rao   10 years AGO

3^x(1-1/3)=18
3^x(2/3)=18
3^x-1=9
so x=3
x^x=3^3=27

Like? Yes (1) | No (5)  

VENKATESH V C   10 years AGO

3^x-3^(x-1)=18
3^x(3)-3^x=54
3^x(3-1)=54
3^x=27
x=3
so
3^3=27

Like? Yes (1) | No (5)  

MRITUNJAY KUMAR   10 years AGO

3^x(1-1/3)=18
x=3.
x^x=3^3=27.
ans-option 5)

Like? Yes (2) | No (6)  

rahi   10 years AGO

assume 3^x=z
then
z-z/3=18
=>z=27
so,
3^x=3^3
x=3
x^x=3^3=27

Like? Yes (1) | No (5)  

Britto prabhu   10 years AGO

27-9=18

3^3-3^2=18

so,3^3=27

Like? Yes (1) | No (5)  

pawan kumar chhipa   10 years AGO

3^x- 3^x*3^-1 =18
3^x(1-1/3) =18
3^x=18*(3/2)
solve it x=3
3^3=27

Like? Yes (1) | No (5)  

ravi   10 years AGO

of the options 3^3 is the only one that satisfies x^x
so cross checked with x=3

Like? Yes (1) | No (5)  

Aravinth kumar   10 years AGO

=3^3 - 3^(3-1)
=27 - 9
=18
so,
Ans : 3^3=27

Like? Yes (1) | No (5)  

Ajay Meena   10 years AGO

Put x=3

Like? Yes (1) | No (5)  

Saraswathy   10 years AGO

3^x - 3^(x-1) = 18
3^x - (3^x/3) = 18
3^x ( 1-1/3) = 18
3^x * 2/3 = 3^2 * 2
3^(x-1) = 3^2
x-1 = 2
x = 3
x^x = 3^3 = 27

Ans : 27 (Option 5)

Like? Yes (4) | No (9)  

Tark Patel   10 years AGO

-> 3^x - 3^(x-1) = 18
-> 3^x = 3^3
so x=3
Hence x^x = 3^3 =27

Like? Yes (2) | No (7)  

mansi garg   10 years AGO

3^x-3^(x-1)=18
3^x(1-3^-1)=18
3^x=18*3/2
3^x=27
x=3
x^x=27

Like? Yes (4) | No (9)  

shree   10 years AGO

27777777777777777

Like? Yes (1) | No (6)  

abhilash kumar   10 years AGO

3^x-3^(x-1)=18
3^x(1-3^-1)=18
3^x=27
X=3
X^x=27

Like? Yes (2) | No (7)  

Saroj kumar   10 years AGO

Given, 3'x-3'(x-1)=18
Or, 3'x-3'x3=18
Or, 3'x(1-1/3)=18
Or, 3'x=18*3/2
Or, 3'x=27
Or, x=3.
So, x'x=3'3=27...

OK

Like? Yes (2) | No (7)  

14 Jul 2014 Sequence

What is the next number of the following sequence
10, 16, 26, 41, 62, .....

OPtion

1) 94
2) 88
3) 86
4) 87
5) 89
6) 91
7) 92
8) 93
9) 90
10) None of these

Solution

Difference of successive numbers are 6, 10, 15, 21,....
6 = 1+2+3
10 = 1+2+3+4
15 = 1+2+3+4+5
21 = 1+2+3+4+5+6
Hence next difference is 1+2+3+4+5+6+7 = 28

Option 9)

Correct Option: 9 Best Solution (71)

Sundar Kumar   10 years AGO

10, 16, 26, 41, 62, .....

10, 10+6=16,16+(6+4)=26,26+(10+5)=41,41+(15+6)=62, 62+(21+7)=90
answer: option : 9)90

Like? Yes (41) | No (29)  

Vishal Chugh   10 years AGO

The difference between successive numbers in the series is
16 - 10 = 6
26 - 16 = 10
41 - 26 = 15
62 - 41 = 21
Thus the difference between these differences is in series 4, 5, 6
Therefore the next difference should be equal to
21 + 7 = 28
and 62 + 28 = 90

Like? Yes (7) | No (4)  

Smriti   10 years AGO

16 = 10 + 6 = 10 + 1 + 2 + 3
26 = 16 + 10 =16 + 1 + 2 + 3 + 4
41 = 26 + 15 = 26 + 1 + 2 + 3 + 4 + 5
62 = 41 + 21 = 41 + 1 + 2 + 3 + 4 + 5 + 6

Next number = 62 + 28 = 62 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 90

Like? Yes (8) | No (6)  

SUMIT   10 years AGO

16-10=6
26-16=6+4=10
41-26=10+5=15
62-41=15+6=21
so x-62=21+7=90
and x=90

Like? Yes (1) | No   

Dinesh kumar   10 years AGO

10+6=16
16+(6+4)=26
26+(10+5)=41
41+(15+6)=62
62+(21+7)=90
Hence ans is 90.......

Like? Yes (3) | No (2)  

GAJENDRA SINGH PANWAR    10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
Then, we have 6, 10, 15, 21
So the next sequence number will be 28.
After adding 28 to 62 we will get 90.
So, answer is 90.

Like? Yes (2) | No (1)  

anusha   10 years AGO

10 16 26 41 62 x
6 10 15 21 y
4 5 6 7
y=21+7=28
x=62+28=90

Like? Yes (3) | No (2)  

Pradeep   10 years AGO

90 as {10+6=16;; 16+10=26;;26+15=41;; 41+21=62;; ? ;; the added numbers 6,10,15,21,? diff is 4,5,6,? next shud be 7 so 21+7=28;; 62+28=90}

Like? Yes (1) | No   

priyanka    10 years AGO

difernces bt nubers...
diff 6 b/w 10 nd 16
diff 10 b/w 16 nd 26
diff 15 b/w 41 nd 26

diff 21 b/w 62 nd 41
nxt diff 28 b/w 90 nd 62...
bcz in differnces bw their diff are 5,6,7...
62+28=90

Like? Yes (1) | No   

JANARTHANAN RAM   10 years AGO

10+6=16;
16+10=26;
26+15=41;
41+21=62;
62+28=90;

Like? Yes (3) | No (2)  

Ravi Bhalani   10 years AGO

10 16 26 41 62 90
6 10 15 21 28
4 5 6 7

Like? Yes (1) | No   

Divyshri Jain   10 years AGO

16-10 =6
26-16=10
41-26=15
62-41= 21

6, 10, 15, 21
10-6= 4
15-10=5
21-15 = 6

4, 5, 6 is an increasing AP with d= 1 and a= 4
so next term is 7
ie 21+7= 28

so nxt term is 28+62= 90
hence the answer is 90

Like? Yes (3) | No (2)  

saira fatma   10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
THUS 2ND SERIES FORMED=6,10,15,21
DIFFERENCE=10-6=4
15-10=5
21-15=6
THUS NEXT NO DIFEERENCE=7
THUS 28-21=7
HENCE,62+28=90ANS

Like? Yes (3) | No (2)  

Grishma Shah   10 years AGO

10 16 26 41 62 90
6 10 15 21 28
4 5 6 7

Like? Yes (4) | No (3)  

sompon temtheerakij   10 years AGO

ans 9) 90
16 - 10 = 6
26 - 16 = 10
41 - 26 = 15
62 - 41 = 21
90 - 62 = 28

Like? Yes (1) | No   

krishna kanth   10 years AGO

difference sum is increasing constantly as
6,10,15,21
4,5,6,7
so next difference should be 28 then number is 90

Like? Yes (1) | No   

sangita kumari   10 years AGO

10+6=16
16+10=26;.....6+4=10
26+15=41;.....10+5=15
41+21=62;.....15+6=21
then .........21+7=28,...so
62+28=90

Like? Yes (5) | No (4)  

mansi garg   10 years AGO

6+4=10 10+5=15 15+6=21 21+7=28

10+6=16
16+10=26
26+15=41
41+21=62
62+28=90

Like? Yes (3) | No (3)  

Saraswathy   10 years AGO

10---16---26---41---62---x
---6---10---15---21----y
-----4----5----6----7

y = 21+7 = 28
x = 62+28 = 90

Ans : 90 (Option 9)

Like? Yes (6) | No (6)  

Varunraj Reddy   10 years AGO

10, 16, 26, 41, 62, .....
Difference between these numbers are
6,10,15,21,...
Again difference is
4,5,6,....
So next difference is 7
So 21+7=28
So next number=62+28=90

Answer Option 9)

Like? Yes (3) | No (3)  

RAKESH   10 years AGO

62+28=90

Like? Yes (2) | No (2)  

Bholanath    10 years AGO

16-10=6
26-16=10--->10-6=4
41-26=15--->15-10=5
62-41=21--->21-15=6
x-62=28---->28-21=7
so, x=90

Like? Yes (2) | No (2)  

ANJIREDDY   10 years AGO

10 16 26 41 62 (90)
6 10 15 21 (28)
4 5 6 7

Like? Yes (2) | No (2)  

Saranjit Singh   10 years AGO

10, 16, 26, 41, 62,
--6,10,15,21
---4,5,6,7
next no will be 62+28=90

Like? Yes (3) | No (3)  

Satyaki    10 years AGO

DIFFERENCE BETWEEN SUCCESSIVE NUMBERS IS -
6,10,15,21....
NOW,
6=1+2+3
10=1+2+3+4
.
.
.
SIMILARLY NEXT DIFFERENCE WILL BE,
1+2+3+4+5+6+7 = 28
SO, 62+28 = 90 IS THE ANSWER.

Like? Yes (2) | No (2)  

Gaurav Kumar   10 years AGO

Difference is 6 10 15,21 all have differences of 4,5,6 o the next difference will be 21+7=28.So 62+28=90

Like? Yes (2) | No (2)  

NITIN KUMAR GOYAL   10 years AGO

difference between numbers are 6 10 15 21 27

Like? Yes (2) | No (2)  

Amrita priyadarshi   10 years AGO

difference between numbers of series are 6,10,15,21...
here we can see that difference are increasing by 1.
like: 10-6=4
15-10=5
21-15=6
hence next number will have a difference of 21+7=28
i.e. 62+28=90
hence 90 will be the answer.

Like? Yes (2) | No (2)  

nigarashraf   10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
so, 6,10,15,21 is the new series
10-6=4
15-10=5
21-15=6
so,next difference will be 7
7+21=28
28+62=90
so using difference twice this series can be solved

Like? Yes (2) | No (2)  

VENKATESH V C   10 years AGO

16-10=6 3*2=6
26-16=10 5*2=10
41-16=15 5*3=15
62-41=21 7*3=21
so
7*4=28
28+62=90
is d answer

Like? Yes (2) | No (2)  

Dinesh thatti   10 years AGO

16-10 =6 \
4
26-16=10 /
5
41-26=15 /
6
62-41=21 /
7
90-62=28

so answer is 90

Like? Yes (2) | No (2)  

Saroj kumar   10 years AGO

10 16 26 41 62 a
Diff. 6 10 15 21 a-62
Diff. 4. 5. 6 7

Soln: a-62-21=7
Or, a=90....

Like? Yes (2) | No (2)  

Debashis Dey   10 years AGO

10*1+6=16
16*1+10=26
26*1+15=41
41*1+21=62 similarly
62*1+28=90 since 6+4=10 10+5=15 15+6=21 21+7=28 (4,5,6,7 are in a.p. with common difference 1)

Like? Yes (3) | No (3)  

Vishal   10 years AGO

The difference between sequence (10,16,26,41,62....) is (6,10,15,21).
the difference between this series (6,10,15,21) is (4,5,6).
So, the difference is increasing by 1.
Thus the last difference must be 7.
Hence the result will be 90

Like? Yes (2) | No (2)  

dev kumar   10 years AGO

16=10+(6)
26=16+(6+4)
41=26+(6+4+5)
62=41+(6+4+5+6)
next = 62+(6+4+5+6)

Like? Yes (2) | No (2)  

Aalvin   10 years AGO

16-10=6
26-16=10
41-21=15
62-41=21
diff between 6,10,15,21.... follows the sequence 4,5,6,7,.....

Like? Yes (2) | No (2)  

dheeraj   10 years AGO

16-10 = 6
26-16 = 10
41-26 = 15
62-41 = 21

diff== 4,5,6
next diff will be 7...
21+7 = 28..
next no.
62+28 = 90..

Like? Yes (2) | No (2)  

Sonu Khandelwal   10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
Difference between these ans. is 4,5,6 so now difference comes 7 so new answer is 62+21+7=90

Like? Yes (2) | No (2)  

vamshikrishna kuruva   10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
again
10-6=4
15-10=5
21-15=6
so next number is 21+7=28
hence the series would be
62+28=90

Like? Yes (2) | No (2)  

MRITUNJAY KUMAR   10 years AGO

10, 16, 26, 41, 62,90...
6, 10, 15 ,21,28, .
0ption 9)

Like? Yes (2) | No (2)  

Brijesh Rawat   10 years AGO

10+6=16
16+6+4=26
26+6+4+5=41
41+6+4+5+6=62
62+6+4+5+6+7=90

Like? Yes (2) | No (2)  

V SARATH KUMAR   10 years AGO

for each successive numbers we add 6,10,15,21
we get the above sequence by adding 4,5,6 successively and in this way next number is 7,so on adding 7 to 21 we get 28.Now we have to add 28 to 62 to get 90 as the answer...

Like? Yes (2) | No (2)  

Parmeet Singh Pahwa   10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
90-62=27

the difference is incremented by 1

Like? Yes (2) | No (2)  

Satish Zod   10 years AGO

16 = 10 + 6
26 = 16 + 6 + 4
41 = 26 + 6 + 4 + 5
62 = 41 + 6 + 4 + 5 + 6
90 = 62 + 6 + 4 + 5 + 6 + 7

Like? Yes (2) | No (2)  

Raman   10 years AGO

62+28=90

Like? Yes (3) | No (3)  

manikanta   10 years AGO

the difference between the two consequative numbers are like in the order of 6,10,15,21 so the next number is must be add 28 to last number...
so the answer is 62+28=90

Like? Yes (2) | No (2)  

nagarajarao   10 years AGO

diff series .....6 ,10, 15 ,21, 28

Like? Yes (2) | No (2)  

Tark Patel   10 years AGO

16 - 10 = 6 ,
26 - 16 = 10 (6 + 4 = 10),
41 - 26 = 15 (10 + 5 = 15),
62 - 41 = 21 (15 + 6 = 21)
so next will be,
62 + 28 = 90 (21 + 7 = 28 which is difference of 90 and 62).
Hence answer is 90

Like? Yes (2) | No (2)  

Nitin   10 years AGO

difference b/w no is increasing by 1

Like? Yes (2) | No (2)  

Shashi nath jha   10 years AGO

10 16 26 41 62
6 10 15 21
4 5 6
1 1
1+6+21+62=90 ans

Like? Yes (2) | No (2)  

santhosh   10 years AGO

difference between each number are 6,10,15,21 and next one is 28

so add 28+62=90

Like? Yes (2) | No (2)  

Vinoth Kumar   10 years AGO

differnce between the consecutive numbers increases by 1

Like? Yes (2) | No (2)  

Ramesh Sriram   10 years AGO

Difference is
6,10,15,21 next will be 28
because difference increase by 1
i,e
4,5,6,next 7
hence next number is 90

Like? Yes (4) | No (4)  

Tushar Kale   10 years AGO

the difference between differences of number increases by 1

Like? Yes (2) | No (2)  

Sneha Goel   10 years AGO

16-10=6
26-16=10 ( 10-6=4)
41-26=15 (15-10=5)
62-41=21 (21-15=6)
90-62=28 (28-21=7)

Like? Yes (2) | No (2)  

Pranav Verma   10 years AGO

10+6=16
16+6+4=26
26+10+5=41
41+15+6=62
62+21+7=90

Like? Yes (2) | No (2)  

Arpit khandelwal   10 years AGO

10+6=16
16+10=26
26+15=41
41+21=62
62+28=90

Like? Yes (2) | No (2)  

indrajeet singh   10 years AGO

16-10=6
26-16=10
41-26=15
62-41=21
x-62=28 ; hence next term will be 90

Like? Yes (2) | No (2)  

KarishmaKatam   10 years AGO

the difference b/w numbers is 6,10,15,21,28 so answer is 90

Like? Yes (2) | No (2)  

shahin raza   10 years AGO

16-10=6
26-16=6+4=10
41-26=10+5=15
62-41=15+6=21
so next will be 62+(21+7)=62+28=90

Like? Yes (3) | No (3)  

RAJIV   10 years AGO

10+6=16
16+10=26
26+15=41
41+21=62
62+28=90

Like? Yes (2) | No (2)  

sivagami   10 years AGO

because 10-16=6,26-16=10,41-26=15,62-41=21
and then we will get 6,10,15,21,
10-6=4,15-10=5,21-15=6
we will get 4,5,6 then next number will be 7,so after 21,s8 will come,then 62=28=90
so ans is 90

Like? Yes (2) | No (2)  

NITESH KUMAR   10 years AGO

16-10=6;
26-16=10;
41-26=15;
62-41=21;
difference between new numbers is 1 greater than than the previous difference .therefore the difference now become 28.
number is 62+28=90

Like? Yes (2) | No (3)  

rahi   10 years AGO

10,16,26,41,62
diff between 16 and 10 is 6
then 26 is written as 16+6+4
41 is written as 26+6+4+5
62 is written as 41+6+4+5+6
hence
90 is written as 62+6+4+5+6+7

Like? Yes (2) | No (3)  

Ashwin Dinesh   10 years AGO

6, 10, 15, 21 numbers are added...
So next number that should be added is 28.
So 62 + 28 = 90.

Like? Yes (3) | No (4)  

abhilash kumar   10 years AGO

10 16 26 41 62
First order difference
6 10 15 21
Second order difference
4 5 6 7 and so on
So 21+7=28
62+28=90

Like? Yes (2) | No (3)  

Md Akhtar Husain   10 years AGO

+6 +10 +15 +21 ?=+27
(+4) (+5) (+6) (+7)

Like? Yes (2) | No (3)  

kapil singh   10 years AGO

62+28=90

Like? Yes (2) | No (3)  

Kaustubh karekar   10 years AGO

the difference increase by 1
last difference was 6 so now it will be 7
so 21+7=28
and 28+62=90
ans=90

Like? Yes (2) | No (3)  

Anish Mathur   10 years AGO

gape between nmbers 10 and 16 are 6
16 and 26 gaps=10
26 and 41 gaps=15
41 and 62 gaps 21
then
gap between 6 and 10 are 4
gap between 10 and 15 are 5
gaps between 15 and 21 are 6
so gap between 21 and 28 are 7
so we can add 28 in number 62
so answer is 90

Like? Yes (2) | No (4)  

Sourojit Dhua   10 years AGO

|10-16|, |16-26|, |26-41|, |41-62|, |62-x|
6 , 10 , 15 , 21 , 62-x
Now,
6-10, 10-15, 15-21, 21-62+x
diff= 4 , 5 , 6 , 7

hence, 21+7=28
and 62+28= 90

Like? Yes (17) | No (29)  

11 Jul 2014 Play with numbers

If
49-33 = 123
78-32 = 214
94-72 = 632
Then
96-53 = ?

OPtion

1) 764
2) 824
3) 453
4) 567
5) 678
6) 679
7) 448
8) 763
9) 452
10)None of these

Solution

Here
49-33=(4*3)*10+(9/3)*1=120+3=123
78-32=(7*3)*10+(8/2)*1=210+4=214
And
94-72=(9*7)*10+(4/2)*1=630+2=632
Similarly
96-53=(9*5)*10+(6/3)*1=450+2=452

Option 9)

Correct Option: 9 Best Solution (50)

Sundar Kumar   10 years AGO

96-53
=> * both 1st digit= 6*5 = 45
=> / both last digit = 6/3 = 2
Answer : 9) 452

Like? Yes (79) | No (38)  

Ravi Bhalani   10 years AGO

49-33 = 123 [4*3=12 and 9/3=3 hence 123]
78-32 = 214 [7*3=21 and 8/2=4 hence 214]
94-72 = 632 [9*7=63 and 4/2=2 hence 632
Then
96-53 = [9*5=45 and 6/3=2 hence 452]

Like? Yes (1) | No   

HARDIP BHALANI   10 years AGO

49-33 = 123 [4*3=12 and 9/3=3 hence 123]
78-32 = 214 [7*3=21 and 8/2=4 hence 214]
94-72 = 632 [9*7=63 and 4/2=2 hence 632
Then
96-53 = [9*5=45 and 6/3=2 hence 452]

Like? Yes (1) | No   

priyanka    10 years AGO

this is bcz
4*3=12
9/3=3
so 49-33=123
same as above
96-53=9*5 6/3=452 ans 9)452

Like? Yes (1) | No   

Anitha   10 years AGO

9*5(first digits of the given numbers)=45(first two numbers of the solution)

6/3(last digits of the given numbers)=2(last digit of the solution)\\

so the solution is 452....

Like? Yes (3) | No (2)  

shubham raghuvanshi   10 years AGO

digits on the unit places are divided and digits on the 10th places are multiplied....

Like? Yes (1) | No   

Saroj kumar   10 years AGO

Here,
49-33=(4*3:9/3)=(12:3)=123.....

78-32=(7*3:8/2)=(21:4)=214.....

94-72=(9*7:4/2)=(63:2)=632.....

Similarly,

96-53=(9*5:6/3)=(45:2)=452....

Like? Yes (3) | No (5)  

Komala.G   10 years AGO

Option 9
49-33 = 123(4*3 = 12, 9/3 = 3)
78-32 = 214(7*3 = 21, 8/2 = 4)
94-72 = 632(9*7 = 63, 4/2 = 2)
similarly,
96-53 = 452(9*5 = 45, 6/3 = 2)

Like? Yes (2) | No (6)  

Saraswathy   10 years AGO

1st digit of 1st no. * 1st digit of 2nd no. = 1st 2 digits of the result
2nd digit of 1st no. / 2nd digit of 2nd no. = last digit of the result

49-33 = 123
4*3=(12), 9/3=(3) => combine it => 123
78-32 = 214
7*3=21, 8/2=4 => 214
94-72 = 632
9*7=63, 4/2=2 => 632
Then
96-53
9*5=45, 6/3=2 => 452

Ans : 452 (Option 9)

Like? Yes (6) | No (11)  

Dinesh kumar   10 years AGO

49-33 = 123
from above one. multiplying the 1st term of the two and dividing the 2nd terms....
4*3 = 12 , 9/3 = 3. This gives 123.
Like wise 78-32 = 214...
7*3=21 , 8/2 =4. This gives 214...
Similarly 96-53 = (5*9) and (6/3)
Ans is 452

Like? Yes (2) | No (7)  

Soheli Bhaduri   10 years AGO

Ans:9
49-33=123.Here taking the 1st digits and multiplying 4*3=12 and 2nd digits and dividing 9/3=3.So 123.
78-32=214.Here 7*3=21 and 8/2=4.
94-72=632.Here 9*7=63 and 4/2=2
So,96-53=452 as 9*5=45 and 6/3=2.

Like? Yes (1) | No (6)  

rajani   10 years AGO

multiplication of first digits in each numer ,and divison of next digits in each number gives the result..
49-33=(4*3)(9/3)=123
78-32=(7*3)(8/2)=214
in the same way,
for 96-53=(9*5)(6/3)=452

Like? Yes (2) | No (7)  

T.Aravinth kumar   10 years AGO

(9*5),(6/3)=452=96-53.

Like? Yes (1) | No (6)  

amol jain   10 years AGO

49-33=4*3,9/3=123
96-53=9*6,6/3=452

Like? Yes (1) | No (6)  

madanpal vishwakarma    10 years AGO

49-33 = (4*2)(9/3)=123
78-32 =(7*3)(8/2) =214
94-72 =(9*7)(4/2)= 632
Then similarly
96-53 = (9*5)(6/2)=452

Like? Yes (1) | No (6)  

kedasu suresh   10 years AGO

by multiiplicatio&division

Like? Yes (1) | No (6)  

AMIT JAISWAL   10 years AGO

here, 49-33 = 123 , bcoz 4*3 =12 and 9%3=3 similarly , in all the cases multiply the tens digit of each number and divide the unit digit from the unit digit and associate and write both numbers i.e, 123

so , 96-53= 9*5 = 45 & 6%3 = 2 . hence, 452 is answer

Like? Yes (1) | No (6)  

vimal   10 years AGO

49-33=123(4*3)=12and(9/3)=3 so,123
78-32 = 214(7*3)=21and(8/2)=4 so,214
94-72 = 632(9*7)=63 and(4/2)=2 so,632
then
96-53='452'(9*5)=45 and (6/3)=2 so, 452 is Ans

Like? Yes (1) | No (6)  

Lakshmi Narmada   10 years AGO

49-33=123 (4*3=12,9/3=3 together 123)
78-32=214(7*3=21,8/2=4 written together 214
similarly 96-53=452 bcoz 9*5=45 and 6/3=2 so 452

Like? Yes (2) | No (7)  

Mukund Shandilya   10 years AGO

1st digit in both number perform multiply then
2nd digit in both number perform division .
example :-
49-33=123 // 4*3=12 & 9/3=3 ->123
78-32=214 // 7*3=21 & 8/2=4 ->214
94-72=632 // 9*7=63 & 4/2=2 ->632
then
96-53=452 //9*5=45 & 6/3=2 ->452

Like? Yes (1) | No (6)  

naina   10 years AGO

9*5|6/3=452

Like? Yes (1) | No (6)  

Satyaki    10 years AGO

96-53 = (9*6)*(6/3)

Like? Yes (2) | No (7)  

Kaustubh karekar   10 years AGO

sequence is multiply tens digit of numbers and divide units digit of the numbers

Like? Yes (1) | No (6)  

Deepak   10 years AGO

9*5 then 6/3

Like? Yes (1) | No (6)  

uzair hossain   10 years AGO

9*5=45 and 6/3=2
Ie 452

Like? Yes (1) | No (6)  

dheeraj   10 years AGO

9*7=63 && 4/2=2

Like? Yes (1) | No (6)  

goral   10 years AGO

49-33=(4*3)(9/3)=123
78-32=(7*3)(8/2)=214
....
96-53=(9*5)(6/3)=452

Like? Yes (1) | No (6)  

Grishma Shah   10 years AGO

AB-CD = A*C B/D
49-33 = 4*3 9/3 = 12 3 = 123
96-53 = 9*5 6/3 = 45 2 = 452

Like? Yes (4) | No (9)  

Vikamsinh Harisinh Champavat   10 years AGO

9*5 and 6/3=452

Like? Yes (1) | No (6)  

Yogesh   10 years AGO

Multiply 1st digit of both numbers & Divide 2nd digit of 1st by 2nd.
49-33=4*3 9/3=123
78-32=7*3 8/2=214
94-72=9*7 4/2=632
96-53=9*5 6/3=452

Like? Yes (1) | No (7)  

Vibhanshu Shukla   10 years AGO

49-33=123
2nd place digit (4 )from(49) * 2nd place digit from 33
and than unit place is 9/3=3 so result 123
so 96-53=(9*5)(6/3)=452

Like? Yes (1) | No (7)  

Bholanath    10 years AGO

49-33=(multiple of 1st digits)(division of 2nd digits)=(4*3)(9/3)=123
similarly,
96-53=(9*5)(6/3)=452 Ans.

Like? Yes (1) | No (7)  

amit baranga   10 years AGO

49-33, 4*3= '12'- 1st 2 digits of answer, 9/3=3, last digit of answer
similary,
96-53, 9*5= '45' , 6/3=2
so answer is 452

Like? Yes (1) | No (7)  

Ashwin Dinesh   10 years AGO

96 - 53 = 452
Step 1: Multiply the first digits of both numbers: 9 * 5 = 45
Step 2: Then divide second digit of first number by second digit of second number: 6 / 3 = 2
Step 3: Combine the answers of both the steps: 452 (option 9)

Like? Yes (3) | No (9)  

srishti talreja   10 years AGO

49-33=FIRST DIGIT OF BOTH TWO DIGIT NUMBER ARE MULTIPLIED=4*3 AND SECOND DIGIT OF BOTH TWO DIGIT NUMBER ARE DIVIDED=(9/3)=123. SIMILARLY FOR OTHERS THREE ALSO

Like? Yes (1) | No (7)  

manikanta   10 years AGO

43-33=4*3,9/3(first 2 digits multiply and next two digits divide)..
so 96-53=9*5,6/3=452

Like? Yes (1) | No (7)  

Tausif Rizwan   10 years AGO

Simple 49-33=4*3(9/3)=123
78-32=7*3(8/2)=214
94-72=9*7(4/2)=632
so 96-53=9*5(6/3)=452

Like? Yes (1) | No (7)  

Anish Mathur   10 years AGO

ab-cd
=ac/bd
=96-53=9*5/6%3
=45/2
=452

Like? Yes (3) | No (9)  

JANARTHANAN RAM   10 years AGO

49-33=(4*3)(9/3)=123
78-32=(7*3)(8/2)=214
94-72=(9*7)(4*/2)=632
96-53=(9*5)(6/3)=452

Like? Yes (2) | No (8)  

anusha   10 years AGO

49-33=123
9/3=3
4*3=12
78-32=214
8/2=4
7*3=21
94-72=632
4/2=2
9*7=63
96-53=452
6/3=2
9*5=45

Like? Yes (2) | No (8)  

ganesh saicharan rao   10 years AGO

49-33=(4*3)(9/3)=123
78-32=(7*3)(8/2)=214
94-72=(9*7)(4/2)=632
96-53=(9*5)(6/3)=452

Like? Yes (2) | No (8)  

nigarashraf   10 years AGO

451
first 2 digit
4*3=12
7*3=21
9*7=63
9*5=45
last 1 digit
27/(3*3)=3
24/(3*2)=4
28/(7*2)=2
30/(5*3)=2
l

Like? Yes (2) | No (8)  

Devendra Marghade   10 years AGO

49-33= [4*3][9/3]=123
78-32= [7*3][8/2]=214
94-72= [9*7][4/2]=632
96-53= [9*5][6/3]=452

Like? Yes (2) | No (9)  

Varunraj Reddy   10 years AGO

49-33 = (4*3)(9/3)=(12)(3)=123
78-32 = (7*3)(8/2)=(21)(4)=214
94-72 = (9*7)(4/2)=(63)(2)=632
Similarly,
96-53 = (9*5)(6/3)=(45)(2)=452

Ans:Option 9)

Like? Yes (2) | No (9)  

Tark Patel   10 years AGO

49-33 = 123 [4*3 = 12 and 9/3 = 3 hence 123]
78-32 = 214 [7*3 = 21 and 8/2 = 4 hence 214]
94-72 = 632 [9*7 = 63 and 4/2 = 2 hence 632]

answer is
96-53 = 452 [9*5 = 45 and 6/3 = 2 hence 452]

Like? Yes (1) | No (8)  

Dr.Dipin Singh   10 years AGO

If
49-33 = 123....
AB-CD= A*C*10+C/D...
49-33 = 4*3*10+9/3= 120+3=123
78-32 = 214
94-72 = 632
Then
96-53 = 10*9*5+6/3= 450+2=452

Like? Yes (2) | No (9)  

Mukesh Nayal   10 years AGO

9*5=45
and 6/3=2
so 452 is the write answer

Like? Yes (2) | No (9)  

Ravi Kumar Kodari   10 years AGO

given,
49-33=123; 4*3=12 9/3=3 so,123
78-32=214; 7*3=21 8/2=4 214
94-72=632; 9*7=63 4/2=2 632
similarly,
9*5=45 6/3=2 so, answer is 452.

Like? Yes (2) | No (9)  

paaredi muthyam reddy   10 years AGO

49-33=[4*3][9/3]
=123
.
.
96-53=[9*5][6/3]
=452

Like? Yes (2) | No (9)  

Sourojit Dhua   10 years AGO

(4)9-(3)3=(4)*(3)*10+ 9/3 = 120+3= 123
similarly;
7*3*10 + 8/2 = 214
9*7*10 + 4/2 = 632
9*5*10 + 6/3 = 452
Hence, answer is option 9) 452

Like? Yes (32) | No (54)  

10 Jul 2014 Solve

Marks of Physics are printed in reverse order in the mark sheet of Surjeet. If printed marks are less than the correct marks and he gets 67 % after this mistake then which % out of these options is incorrect for the correct mark sheet (It is given that Surjeet gets success either according to mark sheet obtained or according to corrected mark sheet. Total marks of the examination are 500)

OPtion

1) 74.2
2) 76.0
3) 70.6
4) 72.4
5) 79.6
6) 68.8
7) 77.8
8) 67.8
9) 69.4
10) None of these

Solution

In this reverse printing procedure possible conditions are as given below
Correct marks -- Printed marks -- Difference
43 ------------- 34 ------------- 9
53 ------------- 35 ------------- 18
54 ------------- 45 ------------- 9
63 ------------- 36 ------------- 27
64 ------------- 46 ------------- 18
65 ------------- 56 ------------- 9
73 ------------- 37 ------------- 36
74 ------------- 47 ------------- 27
75 ------------- 57 ------------- 18
76 ------------- 67 ------------- 9
83 ------------- 38 ------------- 45
84 ------------- 48 ------------- 36
85 ------------- 58 ------------- 27
86 ------------- 68 ------------- 18
87 ------------- 78 ------------- 9
93 ------------- 39 ------------- 54
94 ------------- 49 ------------- 45
95 ------------- 59 ------------- 36
96 ------------- 69 ------------- 27
97 ------------- 79 ------------- 18
98 ------------- 89 ------------- 9
Therefore possible increments in % are 1.8, 3.6, 5.4, 7.2, 9.0, 10.8
Hence the solution is 79.6 % with
increment of 12.6 %.

Correct Option: 5 Best Solution (0)

09 Jul 2014 Solve

Amzad, Ali and Abbas start a shop with their investment ratio of 6:7:8. Amzad withdraws his investment after 2 month. If profit is distributed between them yearly, then ratio of profit of Abbas and profit of Amzad in the business is -

OPtion

1) 8:7
2) 7:8
3) 7:1
4) 8:1
5) 1:8
6) 1:7
7) 3:4
8) 4:3
9) 1:6
10)None of these

Solution

The effective proportion of Abbas = 8 * 12 (month) = 96
And the effective proportion of Amzad = 6 * 2 (month) = 12
Hence ratio is 96 : 12 = 8 : 1

Option 4)

Correct Option: 4 Best Solution (31)

Sourojit Dhua   10 years AGO

The effective proportion of Abbas = 8 x 12 (month) = 96
And the effective proportion of Amzad = 6 x 2 (month) = 12
Hence ratio is 96 : 12 = 8 : 1

Like? Yes (27) | No (13)  

Ravi Bhalani   10 years AGO

Amzzad 6x,
Ali 7x
Abbas 8x
Time for investment
6x*2=12x(Amzad)
7x*12=84x(Ali)
8x*12=96x(Abbas)
Total investment for year =12x+84x+96x=192x
Amzad's share= 12x/192x =1/16
Abbas's share= 96x/192x =1/2
Ratio (1/2)/(1/16)=8:1

Like? Yes (3) | No   

PAWAN KUMAR   10 years AGO

abbas:amzad = (8/21*1)/(6/21*2/12)=8:1

Like? Yes (1) | No   

ANJIREDDY   10 years AGO

6*2 : 7*12 : 8*12

1 : 7 : 8

abbas : amzad = 8 : 1

Like? Yes (1) | No   

naina   10 years AGO

8*12/6*2

Like? Yes (1) | No   

Satyaki    10 years AGO

Profit will be in ratio of 8*12 and 6*2

It means ratio of profit will be

96:12 or 8:1

Like? Yes (1) | No   

souharda   10 years AGO

amzads share rolls for 2months..hence amzad=6*2=12
ali=7*12
abbas=8*12
hence abbas:amzad= 8*12:12=8:1

Like? Yes (1) | No   

Ramsb   10 years AGO

Amzad, Ali, Abbas profits = 6:7:8
amzad is 2 months only => 6*2 =12
abbas is 1 year => 8*12=96
the ratio abbas and amzed is=96:12
8:1

Like? Yes (2) | No (3)  

Debashis Dey   10 years AGO

let the total profit be x. And ratio of their capital investment=(6*2):(7*12)*(8*12)=12:84:96=1:7:8
profit earned by abbas=8*x/(1+7+8)=8x/16
profit earned by amzad=1*x/(1+7+8)=x/16
hence required ratio=8:1

Like? Yes (2) | No (5)  

Yogesh   10 years AGO

Profit for abbas for one year = 8*12 = 96
profit for amzad for 2 months = 6*2 = 12
Ratio of abbas & Amzad= 96:12

Solution=8:1

Like? Yes (3) | No (6)  

NITIN KUMAR GOYAL   10 years AGO

6*2:7*12:8*12
96/12=8/1

Like? Yes (1) | No (4)  

siddhant   10 years AGO

Let profit be m after 1 Year,profit of amzad will be (6m/21)*2 For two months,abbas eill hv profit of(8m/21)*12,therefore abbas: Amzad=8:1

Like? Yes (1) | No (4)  

Saraswathy   10 years AGO

Ratio of their investment 6x:7x:8x
6x*2 : 7x*12 : 8x*12
12x : 84x : 96x
Abbas : Amzad => 96x : 12x
8 : 1

Ans : 8 : 1 (Option 4)

Like? Yes (6) | No (9)  

Jigyasa Kumar   10 years AGO

The effective proportion of Abbas = 8: 12 (month) = 96
And the effective proportion of Amzad = 6 : 2 (month) = 12
Hence ratio is 96 : 12 = 8 : 1

Like? Yes (1) | No (4)  

shree   10 years AGO

4557676

Like? Yes (1) | No (4)  

Aarush Singh   10 years AGO

The effective proportion of Abbas = 8: 12 (month) = 96
And the effective proportion of Amzad = 6 : 2 (month) = 12
Hence ratio is 96 : 12 = 8 : 1

Like? Yes (2) | No (5)  

Dinesh kumar   10 years AGO

Ratio of Amzad:Ali:Abbas = 6:7:8.
Amzad withdraws after 2 months.
here amzad invested for 2 months, rest of them for 12 months.
(6*2): (7*12): (8*12)
1 : 7 : 8
The ratio of Abbas and Amzad is 8 : 1..........

Like? Yes (1) | No (4)  

Varunraj Reddy   10 years AGO

=>6*2:7*12:8*12
=>1:7:8
Required ratio=8:1

Like? Yes (1) | No (4)  

abhilasha   10 years AGO

The effective proportion of Abbas = 8: 12 (month) = 96
And the effective proportion of Amzad = 6 : 2 (month) = 12
Hence ratio is 96 : 12 = 8 : 1

Like? Yes (1) | No (4)  

Ashwin Dinesh   10 years AGO

Since Amzad had 6 parts in investment, but he left after 2 months, so he will have 1 part of profit.
While Abbas has 8 parts.
So ratio of profit of Abbas to Amzad is 8:1 which is option 4.

Like? Yes (1) | No (4)  

Satishbabu   10 years AGO

Let 'x' be the profit for 1yr.

=> Amazad's profit=6*x/(6+7+8)
=6*x/21 (for 1yr)

=> Abbas's profit=8*x/21 (for 1yr)

but Amazad left for 2 months,
so Amazad's profit=2(6*x/21)/12=x/21

Now ratio becomes 8*x/21 : x/21 =8:1
Therefore Ans is (4 option)--> 8:1

Like? Yes (1) | No (4)  

Nilesh Dattatraya Veer   10 years AGO

amzad investment-- 6x for 2 months=12x
abbas investment--- 8x for 12 months==96x
abbas/amzad=96x/12x=8/1

Like? Yes (1) | No (4)  

RANJAN KUMAR PANDIT   10 years AGO

6*2 : 7*12 : 8:12
= 1 : 7 :8

Like? Yes (1) | No (4)  

kapil singh   10 years AGO

profit ratio of abbas n amjzad= (8*12)/(6*2)
=8:1

Like? Yes (1) | No (4)  

paaredi muthyam reddy   10 years AGO

6*2:7*12:8*12=1:7:8

Like? Yes (2) | No (5)  

Ravi Kumar Kodari   10 years AGO

6*2:7*12:8*12=1:7:8
SO, Abbas:Amzad=8:1ans

Like? Yes (2) | No (5)  

ANUP KUMAR   10 years AGO

Let total profit = x per year
given investment ratio = 6:7:8
profit of amzad in a year = 6/(6+7+8)*x = 6*x/21;
so pro. of amzad in two months(6*x/21)/12*2=x/21;
and profit of abbas in a year=8/(6+7+8)*x =8*x/21;
so,ratio of profit of Abbas and profit of Amzad = (8*x/21):(x/21)= 8:1 option (4)

Like? Yes (2) | No (5)  

dheeraj   10 years AGO

simple calculation

Like? Yes (1) | No (4)  

Ramesh Sriram   10 years AGO

6*2:7*12:8*12=1:7:8

Like? Yes (2) | No (6)  

MRITUNJAY KUMAR   10 years AGO

profit =P*R*T/100.
ratio of their investment=6:7:8.
ratio of profit=(8x*R*1yr)/(6x*R*1/6)=8:1
option 4)8:1.

Like? Yes (1) | No (5)  

Dr.Dipin Singh   10 years AGO

Amzad, Ali and Abbas start a shop with their investment ratio of 6:7:8. Amzad withdraws his investment after 2 month. If profit is distributed between them yearly, then ratio of profit of Amzad, Ali and Abbas will be 6*2:7*12:8*12 and ratio of profit of Abbas and profit of Amzad in the business is 96:12 or 8:1.

Like? Yes (1) | No (5)  

08 Jul 2014 Sum of Series

2000+1000+500+250+125+62.5+.......up to infinite

OPtion

1) 5000
2) 4500
3) 4001
4) 5001
5) 3999
6) infinite
7) 6000
8) 4000
9) 4999
10)None of these

Solution

Solve
a/(1-r) = 2000/(1-0.5) = 4000

Correct Option: 8 Best Solution (68)

Sourojit Dhua   10 years AGO

2000+1000+500+250+125+62.5+...
This represents sum of infinite gp where the common divisor is 1/2.

So,sum= a/(1-r) where, a=2000 and r=1/2=0.5

therefore,
sum= 2000/1-0.5 = 4000

Like? Yes (16) | No (2)  

Ravi Bhalani   10 years AGO

2000/(1-0.5)=4000

Like? Yes (1) | No   

Rishabh   10 years AGO

2000+1000+500+....
2000+2000/2+2000/4+...
2000(1+1/2+1/4+...)
2000{1/(1-0.5)}
2000*2
4000
reason:-1+1/2+1/4+1/8...
is an infinite gp series with c.d. 1/2
therefore summation of infinite gp series is a/a-r
i.e. first term/(first term - common difference)

Like? Yes (1) | No   

R. Divya   10 years AGO

first number is 2000 and from that each preceding number is half of the previous number. If you add all those numbers we will be getting 3999.99895. while rounding the number we get 4000 as the answer.

Like? Yes (1) | No   

Sakshi Sao   10 years AGO

Its a gp

Like? Yes (1) | No   

piyush khullar   10 years AGO

sum=a/1-r

Like? Yes (1) | No   

vidhijain   10 years AGO

since it is a infinite gp with r=1/2

Like? Yes (1) | No   

sivaramakrishna   10 years AGO

terms are in G.P.
sum of terms upto infinity in G.P...=a/(1-r)
a=2000
r=1/2
==>2000*2=4000

Like? Yes (1) | No   

shruti   10 years AGO

this is a gp with a common ratio equal to 1/2.so sum of infinite terms of gp is a/(1-r)=2000/(1-0.5)

Like? Yes (1) | No   

suman kumar pan   10 years AGO

formula= a*(1-r^n)/(1-r)
where a= 2000,r=0.5,n=infinite..
so the sum will be =4000...

Like? Yes (1) | No   

Kaushlesh Kumar   10 years AGO

This is a GP series, first term 2000 and common ratio 1/2 this series up to infinite.
sum= first_term/(1-common_ratio)
sum=2000/(1-1/2) =2*2000 = 40000

Like? Yes (1) | No   

sravani   10 years AGO

2000+1000+500+250+125+62.5+.........
2000(1+1/2+1/4+1/8+........)
1/2+1/4+1/8...........=(1/2)/1-1/2=1
2000(1+1)=4000

Like? Yes (1) | No   

vinay pal   10 years AGO

use a/(1-r) in gp sum

Like? Yes (1) | No   

Venkateswarlu   10 years AGO

it is an geometric series
sum of infinite terms = a/1-r
2000/(1-(1/2))=4000

Like? Yes (1) | No   

surbala   10 years AGO

the above is a infinite G.P. with common ratio -1

Like? Yes (1) | No   

kavya   10 years AGO

sum of infinite terms in geometric progression is a/(1-r) where a is first term and r is ratio here a=2000 r 1/2 so sum=4000

Like? Yes (1) | No   

Laxmi    10 years AGO

sum=a/1-r for GP series,a=1st term, r=common ratio
sum=2000/(1-1/2)=4000

Like? Yes (1) | No   

priyanka    10 years AGO

we knw tht gp infinte frmula
s=a/1-r
2000/1-(1/2)=4000

Like? Yes (1) | No   

paaredi muthyam reddy   10 years AGO

terms are in geometric progression of common ratio 1/2
sum of infinity terms=a/(1-r)

2000/(1-1/2)=4000

Like? Yes (2) | No (2)  

RANJAN KUMAR PANDIT   10 years AGO

infinite sum of g.p
= a/(1-r)
= 2000/(1-1/2)
=4000

Like? Yes (2) | No (2)  

Soheli Bhaduri   10 years AGO

The numbers are half of the previous number.So,add them and get the result.
Ans:4000 option(8)

Like? Yes (2) | No (3)  

RagunathKC   10 years AGO

gp order...simply 2000*2 ( when a =2000,r=1/2..upto infinite)
sum =a(1-r^n)/1-r...here a=2000...r=1/2..

Like? Yes (1) | No (2)  

Debashis Dey   10 years AGO

the series forms an infinite geometric progression(GP) with common ratio(r)=1/2 hence its sum will be a/1-r=2000/(1-1/2)=4000 a is the 1st term of the series

Like? Yes (3) | No (4)  

Barun Kumar   10 years AGO

The giver series is in G.P. with common ratio 0.5
sum of infinite terms of gp is given by a/1-r
here a=2000 r=0.5
therfore sum =2000/1-0.5=4000
so option 8

Like? Yes (1) | No (2)  

kanchan   10 years AGO

this is in GP with ratio = 0.5 which is smaller than 1.
so the sum will be = (2000)/(1-0.5)=4000

Like? Yes (1) | No (2)  

MRITUNJAY KUMAR   10 years AGO

su mof series in G.P fir infinite terms=a/1-r.
so, r=1/2.
a=2000.
s=2000/1-0.5 =4000.

Like? Yes (1) | No (2)  

NITIN KUMAR GOYAL   10 years AGO

a/(1-r)=sum
a=2000,r=0.5
sum=4000

Like? Yes (1) | No (2)  

Amar   10 years AGO

Sum of GP = a/(1-r)

2000+1000+500+250+125+62.5+.......up to infinite = 2000/(1-0.5)= 4000

Like? Yes (2) | No (3)  

Dr.Dipin Singh   10 years AGO

2000+1000+500+250+125+62.5+.......up to infinite = 2000/(1-0.5)= 4000

Like? Yes (2) | No (3)  

Kowshik Sarker   10 years AGO

2000+1000+500+250+125+62.5+..=2000(1+1/2+1/4+1/8+..)
so we get
2000(1+(1/2)+1/(2^2)+1/(2^3)+...)=2000* 1/[1-(1/2)]
= 2000* 1/(1/2)=2000*2=4000.

Like? Yes (1) | No (2)  

abhishek srivastava   10 years AGO

sum of Infinite geometric progression=a/(1-r)
here.. series is as follows:-
2000 + 2000*1/2 + 2000*1/4...........
a=2000
r=1/2

Like? Yes (1) | No (2)  

Rohan Kumrawat   10 years AGO

by series formula a/1-r

2000/(1-1/2)

Like? Yes (1) | No (2)  

Sundar Kumar   10 years AGO

Answer: option 8) 4000

Like? Yes (1) | No (2)  

Niket saini   10 years AGO

2000/(1-1/2)=4000
Infinite gp
So formula is a/1-r with common difference 1/2

Like? Yes (1) | No (2)  

REHAN AHMAD   10 years AGO

2000(1 + 1/2 + 1/4 + 1/8.........)
series in g.p
so this is equal to 2000(2)=4000

Like? Yes (1) | No (2)  

Avishek Pattanaik   10 years AGO

It\'s a converging G.P. Series
Use the formula Sum=a/(1-r)
a=1st term=2000
r=common ratio=1000/2000=500/1000=250/500.....=0.5

Answer= 2000/(1-0.5)= 4000 (option 8)

Like? Yes (2) | No (3)  

Dinesh thatti   10 years AGO

sum of G.P. to infinite terms
a/(1-r)=2000/(1-1/2)=4000

Like? Yes (1) | No (2)  

ABHIJEET PANDEY   10 years AGO

Ans.4000
Sum=a(1/1-r)
a=2000,
r=1/2.

Like? Yes (1) | No (2)  

Jigyasa Kumar   10 years AGO

infinite series with common ratio 1/2.formula is a/1-r ; r-- common ratio
so answer is 4000

Like? Yes (2) | No (3)  

sugandhi   10 years AGO

2000+1000+500+250+125+.....infinity it goes on if u add until the 0.(decimal values)u ll get 3999 then adding it wil giv oly 4000.

Like? Yes (1) | No (2)  

Aarush Singh   10 years AGO

infinite series with common ratio 1/2.formula is a/1-r ; r-- common ratio
so answer is 4000

Like? Yes (2) | No (3)  

abhilasha   10 years AGO

infinite series with common ratio 1/2.formula is a/1-r ; r-- common ratio
so answer is 4000

Like? Yes (2) | No (3)  

TUSHAR    10 years AGO

IT IS SUM OF INFINITE G.P. SERIES

Like? Yes (1) | No (2)  

vishnuvardhan   10 years AGO

2000[1+1/2+1/4+1/8+1/16+_ infinite]
2000*[1/(1-1/2)] [formula a/(1-r)]
4000

Like? Yes (1) | No (2)  

charitha   10 years AGO

Given series is in G.P
first term a=2000,
r=1/2
sum of infinite series in G.P is a/(1-r)
so, 2000/(1-0.5)=4000

Like? Yes (1) | No (2)  

Gourango   10 years AGO

sum=x+x/2+x/2^2+x/2^3+.....
=x/(1-1/2)
Here x= 2000
so, sum=2000/(1/2)=4000

Like? Yes (1) | No (2)  

Ramesh Sriram   10 years AGO

terms are in geometric progression of common ratio 1/2
sum of infinity terms=a/(1-r)

2000/(1-1/2)=4000

Like? Yes (2) | No (3)  

Anupam Banerjee   10 years AGO

The series can be written as,
2000*(1 + 1/2 +1/4 + 1/8 +........upto infinity)

= 2000 * (1/(1- 1/2))

= 2000 * 2

=4000;

Like? Yes (1) | No (2)  

Nilesh Dattatraya Veer   10 years AGO

2000+1000+500+---=2000+(2000/2)+(2000/4)+--infinity
2000(1+(1/2)+(1/4)+(1/8)+-----)
but (1/2)+(1/4)+(1/8)+(1/16)----infinity=(1/2)/(1-(1/2))=1
so 2000(1+1)
2000*2=4000

Like? Yes (1) | No (2)  

Sudhanshu   10 years AGO

a = first term
r = common ratio
n = number of terms

Sum of infinite terms = a/(1-r) where r < 1
sum=> 2000/(1-(1/2))
=> 2000/(1/2)
=> 2000*2=4000

Like? Yes (1) | No (2)  

PRIYA PANDEY   10 years AGO

gp of infinite series =a/1-r , 2000/1-(1/2) =2000*2 =4000

Like? Yes (1) | No (2)  

ANANDAKUMAR   10 years AGO

2000+1000+500+250+125+62.5+.......+infinitive
2000(1+1\2+1\4+1\8+1\16+......)
2000(1-1\2)power -1
based on binomial theorem
2000(1\2)power -1
so 2000* 2

=4000 ans,,

Like? Yes (1) | No (2)  

Priya Kumar   10 years AGO

a=2000,r=1/2
sum of the G.P up to infinite terms=a/1-r=2000/1-(1/2)=4000

Like? Yes (1) | No (2)  

Ghanshyam Gulati   10 years AGO

sum of infinite G.P
a/1-r
a=2000=first term
r=0.5=common ratio

Like? Yes (1) | No (2)  

ashutosh   10 years AGO

This series in G.P. with r=1/2.
So sum=2000/1-1/2=4000

Like? Yes (1) | No (2)  

Abhishek   10 years AGO

This is an infinite GP series problem.So,
a/c to question
2000(1+1/2+1/4+1/8+.....upto infinity)
2000*(1/1-1/2)
=2000*2
=4000
hence,8)4000 is correct

Like? Yes (1) | No (2)  

amit baranga   10 years AGO

sum to infinity of GP=[a/(1-r)]=[2000/1-0.5]=4000

Like? Yes (3) | No (5)  

SAHIL DIWAN   10 years AGO

its a converging geometric infinite progression
so sum=a/1-r where a is first term n r is common ratio
so acc to ques sum=2000/(1-1/2)=4000

Like? Yes (1) | No (3)  

Vishal Chugh   10 years AGO

Sum of infinite geometric progression is:

S = a/(1-r)
Here a = 2000
r = 1/2
Therefore,
S = 4000

Like? Yes (4) | No (6)  

dheeraj   10 years AGO

infinite gp = a/(1-r)
= 2000/(1-.5)
=4000

Like? Yes (1) | No (3)  

Vibhanshu Shukla   10 years AGO

sum of infinite GP= a/(1-r)
so answer is 4000

Like? Yes (1) | No (3)  

Ann Mary Jolly   10 years AGO

sum = 2000/(1-1/2)= 4000

Like? Yes (1) | No (3)  

Saraswathy   10 years AGO

a = 2000
ar = 1000
r = 1/2
Sum of infinite terms in GP is a/1-r [since r

Like? Yes (1) | No (3)  

kapil singh   10 years AGO

sum of infinity=a/(1-r)
=2000/(1-.5)
=4000

Like? Yes (1) | No (3)  

Tark Patel   10 years AGO

using the formula s = a/(1-r),
a=2000,r=(1/2)
s = 2000 / (1-(1/2)) = 4000

Like? Yes (1) | No (3)  

Yogesh   10 years AGO

simply use the progression...
nearly after 18th term the value is too small..
so that the value is neglected.
and the sum obtained is 4000...

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

2000+1000+500+250+125+62.5+31.25+15.625+7.8125+....
=4000
Ans:Option 8)

Like? Yes (1) | No (3)  

Abhinav Khare   10 years AGO

because sum of gp to infinite is a/r-1, where -1

Like? Yes (1) | No (3)