M4maths Previous Puzzles

19 Jun 2014 Solve

The age of a man is thirty five years and seven and half a month. What is its age in decimal representation?

OPtion

1) 35.72
2) 35.75
3) 35.5
4) 35.71
5) 35.712
6) 35.075
7) 35.705
8) 35.625
9) 35.621
10)None of these

Solution

seven and half a month = 7.5/12 years = 0.625 years
hence the age is 35.625 years

Correct Option: 8 Best Solution (51)

Sundar Kumar   10 years AGO

Answer: option 8) 35.625

The age of a man is thirty five years and seven and half a month =35 + (1/12*7.5) = 35.625(age in decimal representation)

Like? Yes (8) | No (2)  

Saraswathy   10 years AGO

35 yrs nd 7 1/2 months
35 yrs nd 7.5 months
35 nd 7.5/12 yrs
35.625 yrs

Ans : 35.625

Ans : 35.625(Option 8)

Like? Yes (3) | No (1)  

sanghavi    10 years AGO

12 months is 1 year
hence 7.5 month is 0.625 year
ans=35+0.625

Like? Yes (1) | No   

Rahul Kumar   10 years AGO

7.5/12=.625

hence ans is 35.625

Like? Yes (1) | No   

Suresh   10 years AGO

7.5/12 = 62.5%,
While convert it for 10 it will be .625

Like? Yes (1) | No   

NITIN KUMAR GOYAL   10 years AGO

35+(7.5/12)

Like? Yes (1) | No   

tanu chaudhary   10 years AGO

35yrs+(7+1/2)months
35+15/24 yrs= 35.625

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

Ans-option 8.
35+7.5/12=35.625

Like? Yes (1) | No   

Gireraj   10 years AGO

35 + [ (7+(1/2)) / 12 ] = 35 + 0.625 = 35.625

Like? Yes (1) | No   

Nilay   10 years AGO

if 12 months than 1 year.
if 7.5 months than how many years???

Like? Yes (1) | No   

RAHUL KUMAR   10 years AGO

here 12 month= 1in decimal
so 1 month=1/12 dec
so 7.5month=7.5/12 in dec
=0.625in dec
thus age in dec =35+0.625
=35.625

Like? Yes (1) | No   

sompon temtheerakij   10 years AGO

7.5 months = 7.5/12 = 0.625 years

Like? Yes (1) | No   

javneet singh   10 years AGO

35+1/12*7:5 which is equal to 35.625

Like? Yes (1) | No   

sravani   10 years AGO

7.5/12=0.625
so 35+0.625=35.625

Like? Yes (1) | No   

Avishek Pattanaik   10 years AGO

1 year =12 months
therefore, 7.5/12=.625
so, the Answer is 35.625
i.e. option 8 is correct

Like? Yes (1) | No   

subramani   10 years AGO

1 year+12 month
So Decimal for 7.5 month= 7.5/12=.625
So total decimal Representation for 35 yrs and 7 and Half Month is 35.625

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

12 months= 1.00
9 months= 0.75
6 months= 0.50
3 months= 0.25


(9+6)/2=7.5
(.75+.50)/2=.625
hence total age 35+.625=35.625

Like? Yes (1) | No   

Girjesh kumar   10 years AGO

we can write 7 and half a month as 7.5 months so for year representation we will divide it by 12,
7.5/12 = 0.625,
and will add to 35 so answer will be 35.625

Like? Yes (1) | No   

D.Gnaphika   10 years AGO

35years+7months+1/2months=35years+7.5months=35years+7.5/12years=35+0.625=35.625years

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

7.5 months=0.625 years
hence ans is option 8

Like? Yes (1) | No   

saisudha sarva   10 years AGO

35.(915/2*12)=35.625

Like? Yes (1) | No   

shree   10 years AGO

35(7.5/12)=35+0.625
35.625

Like? Yes (1) | No   

RANJAN KUMAR PANDIT   10 years AGO

7.5/12=0.625
35+0.625=35.625

Like? Yes (1) | No   

Vishal Chugh   10 years AGO

If 12 months is considered to be equivalent to 1 then seven and a half months i.e. 7.5 is equivalent to 0.625.

Therefore the answer is 35.625

Like? Yes (1) | No   

rimsha naaz   10 years AGO

35+7.5/12 =35.625

Like? Yes (1) | No   

Shanmugapriya   10 years AGO

seven and a half month so 7.5
7.5/12=.625+35=35.625

Like? Yes (1) | No   

Aravind   10 years AGO

its 7 and a half month. so 7.5 months. since its in months we divide 7.5 by 12 which gives us 0.625
thus 35.625 is the right opton

Like? Yes (1) | No   

venkat   10 years AGO

because seven and half month decimal part is .625

Like? Yes (1) | No   

Vishnu Prasad V   10 years AGO

35yrs 7.5 months= 35yrs nd (7.5/12)yrs = 35.625

Like? Yes (1) | No   

Sandhiya Mohandas   10 years AGO

because 7.5 months of a year is 0.625 so 35 yrs 7.5 months is 35.625 yrs

Like? Yes (1) | No   

gowthamp   10 years AGO

it seems

Like? Yes (1) | No   

pankaj kumar   10 years AGO

35 + 7.5/12 = 35.625

Like? Yes (1) | No   

Anupam Banerjee   10 years AGO

7 and half a month means
( 7 and half a month/12 )year
= (15/24)year
= 0.625 year
So, the total age of the person in decimal is =
(35+0.625) = 35.625 year.

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

35(7.5/12)=35.625
or (35*12+7.5)/12=35.625

Like? Yes (1) | No (1)  

Vaishali Gupta   10 years AGO

age=35 years+ 7.5/12 year
=35+.625years
35.625years

Like? Yes (1) | No (1)  

Yogesh   10 years AGO

7.5/12=0.625
35+0.625=35.625

Like? Yes (1) | No (1)  

Dinesh thatti   10 years AGO

thirty five years and seven and half a month

per year 12 months

7 1/2 = 15/2 =>15/2*12=15/24
35 15/24=>35.625

Like? Yes (1) | No (1)  

paaredi muthyam reddy   10 years AGO

thirty five years is 35
7 1/2 months is divided by 12 gives 15/24=0.625
then total age in decimal is 35.625

Like? Yes (1) | No (1)  

Syeda Tahaseen Naaz   10 years AGO

12 months= 1 year
so 7 and half month= [7(1/2)*1]/12=.625
total age=35+.625=35.625

Like? Yes (1) | No (1)  

CHETNA TUTEJA   10 years AGO

Age is 35yrs and 7.5mnths.
As we knw,
12mnths------1yr
1mnth---------1/12yr
7.5mnths------7.5/12=0.625yrs
so total age=35+0.625=35.625
Hence option (8) is correct.

Like? Yes (2) | No (2)  

venkateswara   10 years AGO

7.5 is divided by 12 we will get .625 in years

Like? Yes (1) | No (1)  

Bobby Nayak   10 years AGO

Man's age: 35yrs + 7 and 1/2 months
=35yrs + 15/2 months
now convert the months in year
=35 + 15/(2*12)
=35 + 15/24
=35 + 0.625
=35.625yrs

Like? Yes (1) | No (1)  

MANIKONDA SAI PRASANNA   10 years AGO

35+(7.5/12)=35+(0.625)=35.625

Like? Yes (1) | No (1)  

Kowshik Sarker   10 years AGO

35 years 7.5 months
now 7.5 months= 7.5/12 years=0.625 years
so age in decimal representation will be(35+0.625)yr
that is 35.625 which is option no.8

Like? Yes (1) | No (1)  

Prerna   10 years AGO

The age of a man = thirty five years and seven and half a month
seven and half a month = 7.5/12 yrs = 5/8 yrs= .625 yrs
The age of a man = thirty five years and seven and half a month = 35.625 yrs

Like? Yes (2) | No (2)  

KODEISWARAN ELANGOVAN   10 years AGO

the answer is 35.625

Like? Yes (1) | No (1)  

pawan kumar chhipa   10 years AGO

convert all the entity in year
35 year + 7/12 year + 0.5 /12 year
35+ 0.5833 + 0.0416
= 35.6249 ~ 35.625
ans is option 8) 35.625

Like? Yes (1) | No (1)  

Rahul Das   10 years AGO

age 35 years 7 months 15 days
total=35+7/12+15/(30*12)
=35+.5833+.0417
=35.625

Like? Yes (1) | No (1)  

mansi garg   10 years AGO

my opt is 8
35+7.5/12=35.625

Like? Yes (2) | No (3)  

Varunraj Reddy   10 years AGO

35 years 7 1/2 months
=35+ (7.5/12)
=35+ (0.625)
=35.625

Option 8)

Like? Yes (1) | No (2)  

RAKHI RAMTEKE   10 years AGO

to convert it in decimal,month i.e 7 will be 7/12=0.5833 and similarly 0.5/12=0.041667....therefore adding 35+0.5833+0.041667=35.625....i.e option 8

Like? Yes (1) | No (3)  

18 Jun 2014 Solve

A word (either meaningful or not) is formed of 2 vowels and 4 consonants. One vowel and one consonant revise itself therefore totally 8 letters are used in the word. The difference in the positions of revised consonants in the word is 1 and the difference in the positions of revised vowels in the word is 5. The starting letter of the word comes after 4 places than last letter of the word in English alphabet. The sum of positions in English alphabet of middle two letters in the word and the sum of positions in English alphabet of third letter from start and from end in the word are divisible by the number of days in a week. If the letters used in the word are A, H, M, N, O and R, then which one of the following word is incorrect according to the given condition

OPtion

1) RAMMOHAN,
2) RAHOMMAN,
3) RAMMHOAN,
4) ROHAMMON,
5) ROHAMMAN
6) RAOHMMAN,
7) ROMMAHON,
8) ROAHMMON,
9) ROMMHAON
10) None of these

Solution

The starting letter of the word comes after 4 places than last letter of the word in English alphabet,
This condition is valid only for N and R hence starting letter is R and last is N.
The sum of positions in English alphabet of middle two letters in the word and the sum of positions in English alphabet of third letter from start and from end in the word are divisible by the number of days in a week.
Possible sets of letters which satisfies the condition are (A, M), (H, M), (M, O), (N, N),
The difference in the positions of revised consonants in the word is 1,
Therefore revised consonants have successive positions.
The difference in the positions of revised vowels in the word is 5,
Therefore their definite positions are 2nd and 6th.
Arrange these conditions.

Correct Option: 5 Best Solution (23)

Sundar Kumar   10 years AGO

Answer: option 5) ROHAMMAN

A vowel repeated after 2 .. i.e 3rd..

Like? Yes (10) | No (3)  

Dolly   10 years AGO

In 5) ROHAMMAN
repeating vowel A-A are separated by 2 letters only.

Like? Yes (2) | No (1)  

Rahul Kumar   10 years AGO

difference of revised vowels in word is not 5.

Like? Yes (1) | No   

anusha   10 years AGO

difference between 2 vowels should be 5 but in 5th option the difference between two A's is 3.
so the word that didn't satisfies the given conditions is ROHAMMAN

Like? Yes (1) | No   

RAKESH   10 years AGO

in option 5
2nd letter from first & last are O & A, not SAME vowel.

Like? Yes (1) | No (1)  

mansi garg   10 years AGO

difference between a and a is 2

Like? Yes (4) | No (4)  

paaredi muthyam reddy   10 years AGO

from given question the difference between the given two revised vowels is 5.
but in option 5 the difference between two A's is 2

Like? Yes (2) | No (2)  

Ramesh Sriram   10 years AGO

Difference between two revised vowels must be 5, but in option 5 the difference is 2
so it is wrong

Like? Yes (2) | No (2)  

Anupam Banerjee   10 years AGO

The distance of revised vowel is not 5 in ROHAMMAN.
The revised vowel is A here.

Like? Yes (1) | No (2)  

venkateswara   10 years AGO

the difference in the positions of revised vowels in the word is not equal to 5

Like? Yes (1) | No (2)  

Saraswathy   10 years AGO

Difference in revised vowels is not 5 in ROHAMMAN...

Hence option 5 is incorrect...

Ans : ROHAMMAN (Option 5)

Like? Yes (2) | No (3)  

pawan kumar chhipa   10 years AGO

the difference of revise vowels is not 5 so it is incorrect
ans is 5) ROHAMMAN

Like? Yes (1) | No (2)  

Varunraj Reddy   10 years AGO

Option 5 does not satisfies the given conditions.

Like? Yes (1) | No (2)  

RISHABH SHARMA   10 years AGO

difference of position in revised vowel A is not 5 as in given condition..

Like? Yes (1) | No (2)  

Rahul Das   10 years AGO

difference in the positions of revised vowels in the word is 5
in option 5 this condition is not satisfied

Like? Yes (1) | No (2)  

REHAN AHMAD   10 years AGO

difference between vowel position is 3 in
ROHAMMAN.
so this is incorrect

Like? Yes (1) | No (2)  

MRITUNJAY KUMAR   10 years AGO

The option no .5 i.e, ROHAMMAN don't have the two same vowel having their difference 5 with respect to position of alphabets.

Like? Yes (1) | No (2)  

Narendar Reddy .Kancharla   10 years AGO

The difference between the vowels is not 5;
So the answer is option(5);

Like? Yes (1) | No (2)  

Rashmi bharti   10 years AGO

difference between revised vowel is not 5.

Like? Yes (2) | No (3)  

bhagya sree   10 years AGO

Option 5) doesnt satisfy the condition "the positions of revised vowels in the word is 5".
Remaining all other conditions are satisfied by all the conditions.

Hence ans : 5

Like? Yes (1) | No (2)  

Vishal Chugh   10 years AGO

One of the conditions is that the revised vowels should appear with difference in positions equal to 5.

But in ROHAMMAN they appear with difference equal to 2.Thus option (5) doesn't satisfy the conditon.

Like? Yes (1) | No (2)  

movva jagadeesh   10 years AGO

difference in the positions of the revised vowels is not 5

Like? Yes (1) | No (2)  

MANIKONDA SAI PRASANNA   10 years AGO

IN 5TH OPTION DIFFERENCE BETWEEN THE REVISED VOWELS IS NOT 5.SO 5TH OPTION IS WRONG

Like? Yes (1) | No (3)  

17 Jun 2014 Solve

Some birds sit on a tree. Square root of total birds moves away from there. Twice of the remaining birds are equal to the square of sum of birds flown away & square root of birds flown away. How many birds was on tree.

OPtion

1) 64
2) 16
3) 100
4) 56
5) 49
6) 99
7) 81
8) 121
9) 144
10)None of these

Solution

2(x-√x) = (√x+√√x)2
Solve
Option 7)

Correct Option: 7 Best Solution (28)

mansi garg   10 years AGO

if birds were 81 then there square root is 9
bird flown=9
remaining bird =72
according to given condition (9+3)^2=144
and twice of remaining bird =144
hence ans is 81

Like? Yes (6) | No (1)  

Sundar Kumar   10 years AGO

Answer : option 7)81

Like? Yes (6) | No (2)  

anuradha   10 years AGO

Let total no. of birds = x
birds flown away= x^1/2
so, 2(x-(x^1/2)) = ((x^1/2)+(x^1/4))^2 ...(1)
as we can see here that we have to find 1/4th of a no.
so from option find the no.s which can give 1/4th a integer.
64,100,56,49,99,121,144 is not posible
16,81 could be ans
put both values in equatn (1) one by one.
81 satisfires the equation. so 81 is ans.

Like? Yes (4) | No   

Ranjit Somisetty   10 years AGO

x2 be the total birds
2.(x2-x)=(x+sqrt(x))2
on solving we get x=9
hence total birds = x2=81

Like? Yes (3) | No   

Vikash Kumar   10 years AGO

let total birds be x
Remainin birds sqr root of x
Equation
2(x-root x)=(root x +root of root x)^2
Use hit and trial method
81 is correct answer.

Like? Yes (2) | No   

Anupam Banerjee   10 years AGO

Let there were x birds on the tree.
So, the equation will be....

2*(x - sqrt x) = (sqrt x + sqrt(sqrt x))^2

So, x - 3x^1/2 -2x^3/4 = 0

The solution of the equation gives
x = 81;

Like? Yes (2) | No   

Shashi nath jha   10 years AGO

the equation is 2(x -sqrt(x))=(sqrt(x)-sqrt(sqrt(x)))^2.
on solving x=81.

Like? Yes (3) | No (2)  

MANIKONDA SAI PRASANNA   10 years AGO

let total no of birds=x
accoding to the problem
2(x-x^1/2)=(x^1/2+x^1/4)^2
x=3x^1/2+2x^3/4
it is easy to verify the answers than by solving
x=81
81=3(9)+2(27)
81=81

Like? Yes (2) | No (1)  

Saraswathy   10 years AGO

Let y be the initial no. of birds nd x no. of birds flown away...
Then y=x^2 --->(1)
Birds left = y-x
2(y-x) = (x+sqrt(x))^2 --->(2)

Solving (1) nd (2),
We ll get x=9, y=81

Ans : 81 (Option 7)

Like? Yes (2) | No (1)  

CHETNA TUTEJA   10 years AGO

Let the total birds on tree be x
so as said x^1/2 birds flew away
remaining birds (x-x^1/2)
Now as per ques.
2 (x-x^1/2)=(x^1/2+x^1/4)^2
On solving the equatin we get,
x^1/4=3
So x=81, that is option (7) is correct

Like? Yes (1) | No   

Vaishali Gupta   10 years AGO

A.T.Q
2(x-x^1/2)=(x^1/2+(x^1/2)^1/2)^2
On solv,
X-3x^1/2=2x^3/4
X=81

Like? Yes (1) | No   

Syeda Tahaseen Naaz   10 years AGO

no. of birds moved away=square root of 81=9
remaining= 81-9=72
given :2( 72)=( 9+sqtr(9))2
144=144
hence no. of birds =81

Like? Yes (1) | No   

raghu   10 years AGO

2(x-srt(x))=(srt(x)+srt(srt(x)))^2
by checking options it would be 81 also double square root will be solved only by 81 since srt(81)=9 and srt(9)=3 in srt(srt(x)).

Like? Yes (1) | No   

bhagya sree   10 years AGO

Let 'x' be the no. of birds sitting on tree.
Then,
2(x-√x)= (√x)2 + √√x
By option verification, ans is 7)

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

let initial birds on tree is x so...
2(x-x^1/2)=( x^1/2 + (x^1/2)^1/2 )^2

Like? Yes (1) | No   

Manikandan   10 years AGO

total - 100=> 100-2*2=100=>twice=>2(2*2)=>4*4=16=>96-16=80
Answer may be = around 80 or 81

Like? Yes (1) | No   

Mallikharjuna   10 years AGO

2(x-sqrt(x))=(sqrt(x)+sqrt(sqrt(x)))^2
by back substitution

Like? Yes (1) | No   

venkateswara   10 years AGO

total birds =x
away from tree =sqrt(x)
remaining=y=(x-sqrt(x))
2y=[(sqrt(x))+(sqrt(sqrt(x)))]^2
by solving
x=2*sqrt(x)(sqrt(sqrt(x))+1)+sqrt(x)
take 81 as x it will satisfy condition

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

let x be the total no. of birds sitting on the tree.
A/Q the question we get the eqn;
2(x-x^1/2)=(x^1/2+x^1/4)^2;this equation satisfied only when x=81.

Like? Yes (1) | No   

Rashmi bharti   10 years AGO

let n^4 birds r there.
n^2(n^2-2n-3)=0
=>n=3
n^4=81

Like? Yes (1) | No   

sam   10 years AGO

total birds=x
2(x-root x)=(root x+root of root x)^2
so we get x=81
so,lhs=rhs
X=81

Like? Yes (1) | No   

pawan kumar chhipa   10 years AGO

let total birds is x^2
flown birds is x
remaining birds is x^2-x
according to the question
(x+ square root of x)^2= 2(x^2-x)

solve it
x=9
so total bird is 81
ans is option 7) 81

Like? Yes (1) | No   

Ajay Kumar   10 years AGO

let no of birds=x, after (x)^1/2 birds moves away there are only (x-sqrt(x)) birds remain.
Acording to the question
(x-sqrt(x))*2=(sqrt(x)+(x)^1/4)^2
2x-2sqrt(x)=x+sqrt(x)+2(x)^3/4
x-3sqrt(x)=2(x)^3/4
After squaring both sides, we get
x^2+9x-6(x)^3/2=4(x)^3/2
x^2+9x=10(x)^3/2
After taking x common from both sides, we get
x+9=10sqrt(x)
squaring both sides
x^2+81+18x=100x
x^2-82x+81=0
After solving this, we get
x=81,1

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

Sub the values in following in equation
2(X-√X)-(√X+√√X)=0.

Like? Yes (1) | No   

IFFAT IRAM   10 years AGO

let the birds on the tree be x
2(x-x^(1/2))=(x^(1/2)+x^(1/4))^2
2(x-x^(1/2))=(x+x^(1/2)+2x^(3/4)
x-2x^(3/4)-3x^(1/2)=0
x^(1/2)(x^(1/2)-2x^(1/4)-3)=0
x^(1/2)-2x^(1/4)-3=0
y=x^(1/4)
y^2-2y-3=0
y^2-3y+y-3=0
(y-3)(y+1)=0
y=3 or -1

x^(1/4)=3
x=3^4
x=81

Like? Yes (1) | No   

Varunraj Reddy   10 years AGO

By verification Option 7) only satisfies the given
condition

Like? Yes (1) | No   

RAKESH   10 years AGO

2(x -√x) = (√x + √√x)^2

x should of form 2^4,3^4,4^4,...
from options, x=16, 81 are possible
x= 81 satisfies eqn.

Like? Yes (2) | No (2)  

sruthi   10 years AGO

7 is the answer

Like? Yes (1) | No (3)  

16 Jun 2014 Sequence

What is the next number of the following sequence
637, 1373, 5104, 9119,……

OPtion

1) 13134
2) 18238
3) 145789
4) 457861
5) 34527
6) 15487
7) 197456
8) 12546
9) 157686
10)None of these

Solution

First number is 637
Next number is 637+736= 1373
Next number is 1373+3731= 5104
Next number is 5104+4015= 9119 similarly for next.

Option 2)

Correct Option: 2 Best Solution (35)

Sundar Kumar   10 years AGO

eg. 637 + 736 (reverse of 637)=1373
similarly,
637, 637+736=1373,1373+3731=5104,5104+4015=9119,
therefore , 9119+9119=18238……

Answer : Option 2) 18238

Like? Yes (10) | No (6)  

Yogesh   10 years AGO

637
1373
5104= using digits of 1373 i.e. 3+1=4 unit digit
3+7=10. using 0 as thn's digit and 1 as carry similarly 3+7+1=11 using 1 as caary and 100th place digit and 3+1+1=5
answer 5104

similarly 5104 is used to obtain 9119
and 9119 to obtain next number which is 18238

Like? Yes (1) | No   

D.Gnaphika   10 years AGO

difference between 637 and 1373 is 736 which is the reverse of 673 and so 637+736=1373 and difference between 1373 and 5104 is 3731 and reverse of 1373 is 3731 so 1373+3731=5104 similarly 9119+9119 where reverse of 9119 is 9119 and to get the blank we get 18238

Like? Yes (1) | No   

lekha   10 years AGO

we have to revers the nos nd add it...lik 637+736=1373 thn 1373+3731=5104 thn 5104+4015=9119 so 9119+9119=18238

Like? Yes (1) | No   

sruthi   10 years AGO

2 is answer

Like? Yes (1) | No   

Sneha   10 years AGO

Option 2 i.e., 18238
637+736=1373
1373+3731=5104
5104+4015=9119
9119+9119=18238

Like? Yes (1) | No   

Anupam Banerjee   10 years AGO

Here,
Next number of a number = summation of the number and the number after reversing its digits.

Like, 637 + 736 = 1373;
1373 + 3731 = 5104;
so.....
The 5th number of the series will be,
9119 + 9119 = 18238;

Like? Yes (1) | No   

Ann Theressa   10 years AGO

637+736 = 1373
1373+3731 = 5104
5104+4015 = 9119
9119+9119 = 18238

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

9119+9119(Reverse of the number)

Like? Yes (1) | No   

Devesh Agrawal   10 years AGO

1373-637 = 736 (inverse of the number being subtracted)
5104-1373= 3731
9119-5104= 4015
so, next number will be 9119 + 9119 = 18238

Like? Yes (1) | No   

Syeda Tahaseen Naaz   10 years AGO

subtract the first no. from second no. we get the first no. but in reverse order...
ex:1373-637=736(reverse of first no. 637)
5104-1373=3731( reverse of 1373)
9119-5104=4015(reverse of 5104)
finally from option 2. 18338-9119=9119( reverse of 9119)

Like? Yes (2) | No (2)  

Udhaya kumar   10 years AGO

xyz+zyx = 9119+9119=18238...

Like? Yes (2) | No (3)  

Parthiban C   10 years AGO

9119+
9119
=18238

Like? Yes (3) | No (4)  

RAKESH   10 years AGO

637+736=1373


9119+9119= 18238

Like? Yes (1) | No (3)  

DILEEP KUMAR   10 years AGO

637+736=1373
1373+3731=5104
5104+4015=9119
9119+9119=18238

Like? Yes (2) | No (4)  

Dr.Dipin Singh   10 years AGO

637, 1373, 5104, 9119,…
If xyz is one numbver,
next number is
xyz+zyx.
as in
637+736= 1373
..
..
9119+9119=18238

Like? Yes (5) | No (7)  

Varunraj Reddy   10 years AGO

637, 1373, 5104, 9119,....

Number+Reverse of that number=Next number

637+736=1373
1373+3731=5104
5104+4015=9119
Similarly,

9119+9119=18238

Ans:Option 2)

Like? Yes (1) | No (3)  

Kunal Arora   10 years AGO

637+736=1373 (number+its reverse)
Similarly
9119+9119 = 18238

Like? Yes (1) | No (3)  

Gitanjali K   10 years AGO

Addition of given number and its reversed number will give us the next number

so 637+736=1373
1373+3731=5104 and so no...

therefore series will be 637,1373,5104,9119,18238

so, option (2) is the answer..

Like? Yes (1) | No (3)  

SHEREENA NISHAD   10 years AGO

637+736 =1373
1373+3731 =5104
5104+4015 =9119
9119+9119 =18238

Like? Yes (1) | No (3)  

MANIKONDA SAI PRASANNA   10 years AGO

present number+(reverse of present number)=next number
637+736=1373
1373+3731=5104
5104+4015=9119
9119+9119=18238

Like? Yes (1) | No (3)  

pawan kumar chhipa   10 years AGO

we add the number with its reverse
637+736=1373
1373+3731=5104
5104+4015=9119
like that
9119+9119=18238 ans is 18238

Like? Yes (1) | No (3)  

MRITUNJAY KUMAR   10 years AGO

1373-637=673
5104-1373=3731
9119-5104=4015
x-9119=9119;x=18238.
here the number we obtain after subtracting two digit is reverse of the preceding digit(smaller one).

Like? Yes (1) | No (3)  

sirisha vechalapu   10 years AGO

637 reverse the number and add it to original number
then we can get the next number
637+736=1373
1373+3731=5104
5104+4015=9119
9119+9119=18238 like......

Like? Yes (1) | No (3)  

Prasanth   10 years AGO

reverse the first number and add it
637+736=1373..............
...........
9119+9119=18238

Like? Yes (1) | No (3)  

Ramsb   10 years AGO

every no reverse and adding....

Like? Yes (1) | No (3)  

sivaraman   10 years AGO

637 and reverse 736 so 1373 so 9119 and reverse 9119 so 18238

Like? Yes (1) | No (3)  

Niraj   10 years AGO

Next Number = Previous Number + (Reverse of the Previous Number)

Like? Yes (1) | No (3)  

anchalanshri   10 years AGO

1373-637=736 which on reversing gives:637
5104-1373=3731 which on reversing gives:1373
so let the next number is x
x-9119=9119: here 9119 is the number after reversing
this gives x=18238

Like? Yes (1) | No (3)  

Brijesh Rawat   10 years AGO

1373=637+reverse of 637(736),so each term is reverse of the preceding term,so next number=9119+9119=18238

Like? Yes (1) | No (3)  

Rashmi bharti   10 years AGO

9119+9119=18238

Like? Yes (1) | No (3)  

Rajesh kumar   10 years AGO

the last digit of every next number is sum of first and last term of previous number

Like? Yes (1) | No (3)  

sharathbabu   10 years AGO

637+reverse of 637(736)= 1373
1373+reverse of 1373(3731)= 5104
5104+reverse of 5104(4015)= 9119
9119+reverse of 9119(9119)= 18238

Like? Yes (1) | No (3)  

susmit   10 years AGO

Adding the first number to the number got by reversing the order gives us the next number.
637 + 736 =1373
1373+3731 = 5104
5104 + 4015 = 9119
So,
9119+9119 = 18238(option no.2)

Like? Yes (1) | No (4)  

Saraswathy   10 years AGO

No. + Rev of no. = next no.

637 + 736 = 1373
1373 + 3731 = 5104
5104 + 4015 = 9119
9119 + 9119 = 18238

Ans : 18238 (Option 2)

Like? Yes (2) | No (5)  

13 Jun 2014 Coded language

If in coded language
MOHAN = 195
DHAWAN = 23
VANDANA = 1
Then
SATISH = ?

OPtion

1) 5
2) 126
3) 3249
4) 369
5) 7345
6) 1278
7) 81
8) 649
9) 625
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
MOHAN = 13 15 8 1 14 = 13*15*1 = 195 (Multiply odd numbers)
DHAWAN = 4 8 1 23 1 14 = 1*23*1 = 23
VANDANA = 22 1 14 4 1 14 1 = 1
Similarly
SATISH = 19 1 20 9 19 8 = 19*1*9*19 = 3249

Option 3

Correct Option: 3 Best Solution (14)

Sundar Kumar   10 years AGO

A(1),B(2),C(3),D(4),E(5),F(6),G(7),H(8),I(9),J(10),K(11),L(12),N(13),M(14),O(15),P(16),Q(17),R(18),S(19),T(20),U(21),V(22),W(23),X(24),Y(25),Z(26)
ANSWER=PRODUCT OF odd number
MOHAN = 13/15/8/1/14=> 13*15*1=195
DHAWAN = 4/8/1/23/1/14=> 1*23*1=23
VANDANA =22/1/14/4/1/14/1=> 1*1=1
Then
SATISH =19/1/20/9/19/8=> 19*1*9*19=3249

Like? Yes (20) | No (10)  

Pargat Pal Singh   10 years AGO

MOHAN = 195
MOHAN--- 13 15 08 01 14---- odd numbers here are 13,15 1... 13*15*1= 195
DHAWAN = 23--- 04 08 01 23 01 14... odd 01 01..1*1=1
VANDANA = 1
Then
SATISH = 19 01 20 09 19 08 ... 19*9*19 = 3249

Like? Yes (4) | No (4)  

Udhaya kumar   10 years AGO

multiply of odd alphanumerics.

Like? Yes (6) | No (6)  

Saraswathy   10 years AGO

Multiply the value of the alphabets having odd values...

MOHAN =>(13)(15)(8)(1)(14) => 13*15*1 = 195
DHAWAN => (4)(8)(1)(23)(1)(14) => 1*23*1 = 23
VANDANA => (22)(1)(14)(4)(1)(14)(1) => 1*1*1 = 1
Similarly
SATISH => (19)(1)(20)(9)(19)(8) => 19*9*19 = 3249

Ans : 3249 (Option 3)

Like? Yes (6) | No (6)  

sruthi   10 years AGO

satish
multiply odd vlues

19*1*9*19=3249

Like? Yes (2) | No (5)  

ANUP KUMAR   10 years AGO

M(13),O(15),H(8),A(1),N(14)
MOHAN = product of odd no.= 13*15=195
similarly,
S(19),A(1),T(20),I(9),S(19),H(8)
SATISH=19*9*19 = 3249

Like? Yes (4) | No (8)  

Dada Khalandar   10 years AGO

A=1,B=2...........Z=26.
MOHAN=13 15 8 1 14 =MULTIPLICATION OF ODD NUMBERS.. 13*15*1=195,
SATISH=19 1 20 9 19 8 = 19*1*9*19=3249.

Like? Yes (1) | No (5)  

shree   10 years AGO

519840/160=3249

Like? Yes (1) | No (5)  

susmit   10 years AGO

Taking A = 1, B = 2........ Z = 26 and then taking product of the odd digits related to the concerned letter .
MOHAN : 13,15,8,1,14
So, multiplying odd digits 13*15 = 195
Similarly,
DHAWAN : 1*23*1 = 23
VANDANA : 1*1*1 = 1
Hence,
SATISH : 19*1*9*19 = 3249
Hence option no. (3)

Like? Yes (1) | No (5)  

Varunraj Reddy   10 years AGO

A=1 B=2 C=3 D=4......X=24 Y=25 Z=26

Given that
MOHAN=195

MOHAN=13 15 8 1 14
=13*15*1=195 (Odd numbers multiplication)
....
Similarly

SATISH=19 1 20 9 19 8
=19*9*19=3249

Ans:Option 3)

Like? Yes (2) | No (7)  

SHEREENA NISHAD   10 years AGO

product of odd

Like? Yes (2) | No (7)  

mohini gupta   10 years AGO

multiplication of odd alphabets

Like? Yes (1) | No (6)  

T.Aravinth kumar   10 years AGO

Product of odd numbers.

Like? Yes (2) | No (7)  

RAKESH   10 years AGO

product off odd no.s

SATISH = 19 1 20 9 19 8 => 19*9*19 =

Like? Yes (1) | No (7)  

12 Jun 2014 Solve

If (x-b) is the HCF of f(x) = x^2 + ax + 1 and g(x) = x^2 - 3x + 2, find the value of a and b.

OPtion

1) a = -2, b = 1
2) a = 2, b = -2
3) a = 1/2, b = 2
4) a = 3, b = 1
5) a = 3, b = -5/2
6) a = 4, b = -2
7) a = 1, b = 1
8) a = 1, b = -1
9) a = 5/2, b = -1
10) None of these

Solution

As (x-b) is the HCF of f(x) and g(x), (x-b) must be a factor of f(x) and g(x)g
Using factor theorem
Solve
Option 1)

Correct Option: 1 Best Solution (18)

Saadana Saravanan   10 years AGO

The factors of g(x) = x^2 - 3x + 2 are
(x-2) and (x-1). this implies the value of b will be either 2 or 1. Therefore it is enough to check the options which has b=2 or b=1.
i.e., options - 1) 3) 4) 7)
Out of these options, we can easily find only option 1) a = -2 , b = 1 satisfies the equation with factors (x-1)& (x-1).
HCF is (x-1).
Therefore option 1)

Like? Yes (1) | No   

Vishnu Prasad V   10 years AGO

Only for a=-2 && b=1 the above eqn satisfies the condition

Like? Yes (1) | No   

IFFAT IRAM   10 years AGO

f(x) = x^2 + ax + 1
g(x) = x^2 - 3x + 2
f(b) = b^2 + ab + 1 =0
g(b) = b^2 - 3b + 2=0
a=-2, b=1

Like? Yes (1) | No   

mansi garg   10 years AGO

X^2-3X+2=(x-1)(x-2)
since (x-b)is hcf so b can be 1 or 2
by taking b=1 we can say that x=-2

Like? Yes (1) | No   

Sundar Kumar   10 years AGO

consider x=1, a=-2, b=1
f(1)=1+(-2*1)+1 = 0
g(1)=1-(3*1)+2 =0 so HCF of (f(1),g(1))= 0
HCF= (x-b) = (1-1) = 0
Similarly,
f(2)= 4+(-2*2)+1= 1
g(2)= 4-(3*2)+2= 0
HCF of (1,0) = 1
(x-b)= (2-1)=1
Answer option 1) a=-2, b=1

Like? Yes (7) | No (7)  

Kunal Arora   10 years AGO

As (x-b) is a factor.
f(b) and g(b) should be zero.
Putting in f(x) and g(x).
we have..
b(a+3)=1
only (1) satisfies

Like? Yes (3) | No (4)  

krishn kumar gupta   10 years AGO

g(x)=x^2-3x+2
=(x-1)(x-2)
now by option 1
a=-2, b=1
then
f(x)=x^2-2x+1
=(x-1)(x-1)
therefore
H.C.F.=(x-1)
b=1 which satisfy the option 1.

Like? Yes (2) | No (3)  

Pargat Pal Singh   10 years AGO

a = -2, b = 1
f(x) = x^2 + ax + 1= x^2 -2x + 1= (x-1)*(x-1)
g(x) = x^2 - 3x + 2= (x-1)*(x-2)
HCF is (x-1)

Like? Yes (3) | No (5)  

Varunraj Reddy   10 years AGO

If a=-2
f(x)=x^2-2x+1=(x-1)(x-1)
g(x)=x^2-3x+2=(x-1)(x-2)

Then HCF becomes (x-1)
(x-b)=(x-1)
i.e.,b=1

Then a=-2,b=1
Ans:Option 1)

Like? Yes (2) | No (4)  

Prakash kumar   10 years AGO

for g(x), x= 2 or 1
now hit n trial

if b=1
a= -2 putting b=2 in eqn f(x)= 0
we get satisfy only for option 1)

Like? Yes (1) | No (3)  

Vaishali Gupta   10 years AGO

Factor of x^2-3x+2 is (x-1)(x-2)
So b can be 1 or 2. For b=2 equ x^2+ax+1 can not be factored for corresponding a value.for a=-2 & b=1the factor (x-1) become hcf

Like? Yes (1) | No (3)  

REHAN AHMAD   10 years AGO

x^2-3x+2=(x-1)(x-2)
if x=-2 then
equation will be x^2-2x+1=(x-1)^2
so this is satisfying the condition
so x-1 is the hcf for the above equation..
answer is 1..a=-2 b=1

Like? Yes (1) | No (3)  

Saraswathy   10 years AGO

x=b

Since x-b is the HCF, x=b is completely divisible by b^2+ab+1 nd b^2-3b+2
From (2), b=1 or b=2

Wen b = 1, a = -2
Wen b = 2, a = -5/2

Ans : a=-2, b=1 (Option 1)

Like? Yes (2) | No (4)  

Girjesh kumar   10 years AGO

if (x-b) is the HCF of f(x) and g(x) then x = b will satisfy both equation .
so b^2 + ab + 1 =0 and b^2 - 3b +2 = 0 ,
then first option is satisfying above equation.

Like? Yes (1) | No (3)  

paaredi muthyam reddy   10 years AGO

substitute x=b in both the equations then solve them
then we will get the values of b as 1 and 2.

if b=1 then a will become -2
if b=2 then a will become -5/2


from given options 1 is correct

Like? Yes (1) | No (4)  

CHETNA TUTEJA   10 years AGO

f (x)=x^2+ax+1
g (x)=x^2-3x+2
When a=-2
Then f (x)=x^2-2x+1 and g (x)=x^2-3x+2
On solving f (x) and g (x), we get
x-1=0
since (x-b) is the HCF of f (x) & g (x),
So we get b=1
Hence ans. Is (1) a=-2, b=1

Like? Yes (2) | No (5)  

Ramesh Sriram   10 years AGO

(x-b) is a factor so b is a root for this equation

substitute b in both equations

solve equations
then
a=-2 and b=1

Like? Yes (1) | No (4)  

MRITUNJAY KUMAR   10 years AGO

As (x-b)is factor of f(x) and g(x),then both will be divisible by (x-b).
after division we get,
b^2-3b+2=0 & b^2+ab+1=0.after solving,we get b=1&b=2,take b=1& we get a=-2.here we have to b=1 only bcz (x-1) is the only factor which is common.

Like? Yes (2) | No (5)  

11 Jun 2014 Solve

If y = (6+x)^2/(6-x)^2 is not a perfect square integer and x is less than 6 and greater than 0; then the value of y is

OPtion

1) 100/9
2) 16/3
3) 81/8
4) 1/2
5) 20
6) 49/25
7) 121
8) 25
9) 25/16
10)None of these

Solution

On taking x = 1, 2, 3, 4, 5 respectively, we get
y = 49/25, 4, 9, 25, 121
Only 49/25 is not a perfect square integer, hence is the solution

Option 6)

Correct Option: 6 Best Solution (30)

Sundar Kumar   10 years AGO

put X=1 in y = (6+x)^2/(6-x)^2
=> y = (6+1)^2/(6-1)^2=49/25 is not a perfect square integer
answer : option 6)49/25

Like? Yes (8) | No (5)  

REHAN AHMAD   10 years AGO

for x=1, y=(6+1)^2/(6-1)^2=49/25 (not a perfect square)
for x=2, y=(6+2)^2/(6-2)^2= 4 perfect square
for x=3, y=(6+3)^2/(6-3)^2= 9 perfect square
for x=4, y=(6+4)^2/(6-4)^2= 25 perfect square
for x=5, y=(6+5)^2/(6-5)^2= 121 perfect square
so 20

Like? Yes (1) | No   

CHETNA TUTEJA   10 years AGO

x=1
y=(6+1)^2/(6-1)^2= 7^2/5^2= 49/25

Like? Yes (1) | No   

AQIB JALLAL   10 years AGO

by putting the value of x in the equation
y = (6+x)^2/(6-x)^2 where 0

Like? Yes (1) | No   

sankar   10 years AGO

if x is 1, then y=(6+1)^2/(6-1)^2
then y=49/25
while if x=2,then y=64/16 =>y=4
if x=3, y=81/9 => y=9
if x=4, y=100/25 => y=4
if x=5, y=121/1 => y=121
all the above values of y are perfect squares except for x=1.
therefore the answer is y=49/25

Like? Yes (1) | No   

hareesh   10 years AGO

put x=1

Like? Yes (1) | No   

p.chandrasekhar   10 years AGO

1.if x=1 then y=49/25.
for remaining values of x=2,3,4,5.the values of y are 4,9,25,121 which are perfect squares

Like? Yes (1) | No   

Kowshik Sarker   10 years AGO

0

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

x can be 1,2,3,4,5 only so y will be 49/25 , 64/16 ,

81/9 , 100/4 and 121 recpectively so here only 49/25 is not a perfect square integer all other are perfect suqare integers so ans will be 49/25

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

Solve the equation using x value is 1,2,3,4,5.

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

y = (6+x)^2/(6-x)^2 = [(6+x)/(6-x)]^2
y will not be perfect integer square only if
[(6+x)/(6-x)]is not an integer.
It is possible only when x=1.
In that case
[(6+x)/(6-x)]= 7/5
and hence
y = (6+x)^2/(6-x)^2 = 49/25 ... option 6

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

A/Q to ques. x take the value b/w 1 to 5.
if we put the valve of x in eqn of y from 1 to 5 ,we get 49/25,4,9,25,121 respectively.Among all this valve y takes 49/25 bcz this is not a perfect square integer.

Like? Yes (1) | No   

paaredi muthyam reddy   10 years AGO

possible values for x are 1,2,3,4,5

if substitute 2,3,4,5,in place of x then it gives 4,9,25,121 which are perfect square integers.
but if substitute 1 then it gives 49/25
so the answer is option 6

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

By trial and error method substitute x values from 1 to 5
for x=1 y=49/25
for x=2 y=4
for x=3 y=9
for x=4 y=25
for x=5 y=121
Hence y value should not perfect square integer
for x=1 y value=49/25

Like? Yes (1) | No   

Vishnu Prasad V   10 years AGO

For Values of X from 1 to 5(Since X lies b/w 0 & 6),only when X=1 we would get a non square integer and the corresponding value of Y= 49/25

Like? Yes (1) | No   

Saraswathy   10 years AGO

x can take values of 1,2,3,4 nd 5

If x = 1, y = 49/25
If x = 2, y = 4
If x = 3, y = 9
If x = 4, y = 25
If x = 5, y = 121

Here except y=49/25, others are perfect square integer... So ans is 49/25...

Ans : 49/25 (Option 6)

Like? Yes (1) | No   

sanghavi    10 years AGO

if x=0 y=1
x=1 y=49/25
x=2 y=4
x=3 y=25 ....

Like? Yes (1) | No   

NITIN KUMAR GOYAL   10 years AGO

when x=1 then y=49/25 which is not a integer

Like? Yes (1) | No   

Ramsb   10 years AGO

y = (6+x)^2/(6-x)^2 (x0)
put 1 y value is 49/25
put 2 y value is 4
put 3 y value is 9
put 4 y value is 25
put 5 y value is 121
put 6 y value is infinity

this is all are perfect squres
so answer is 49/25

Like? Yes (1) | No   

eswariteja   10 years AGO

result in not a perfect square because
To check the values: 1,2,3,4,5.in b/w 0&6
substitute 1 in x value =
y=(6+1)^2/(6-1)^2=7^2/5^2=49/25
y=49/25 is not a perfect square

Like? Yes (1) | No   

vky   10 years AGO

put x=1

Like? Yes (1) | No   

ghazala   10 years AGO

by checking it according to the options given the possible answer is 49/25 i think so.

Like? Yes (1) | No   

shahvez akhtar   10 years AGO

For the value of x is 1
y=49/25
for every other value of x except 1 and 5 (6+x) will be a multiple of (6-x) so division of their squares will be a perfect square.For x=5 the denominator becomes 1 thus the numerator which is 121 will remain as it is.

Like? Yes (1) | No   

Parul Agnihotri   10 years AGO

we need none square no which is possible only if we put one as x

Like? Yes (1) | No   

RAVI RANJAN KUMAR JHA   10 years AGO

ans is 6th option because when be put 1 which is less 6 and greater then 0 ..
y=(6+1)^2/(6-1)^2=49/25.

Like? Yes (1) | No   

bithika das   10 years AGO

x=1
y=7^2/5^2
y=49/25

Like? Yes (1) | No   

himanshu   10 years AGO

We have (1,2,3,4,5) as an input(x) which will give perfect square integer,except at x=1.It\'s perfect square but non-integer value

Like? Yes (1) | No   

Gitanjali K   10 years AGO

given
y = (6+x)^2/(6-x)^2 is not a perfect square integer
and 0

Like? Yes (1) | No   

Kunal Arora   10 years AGO

In this equation putting integer values of x from 0 to 6..
For all the values except 1 y is coming out to be perfect square.
So we have x=1
Putting
y= 49/25

Like? Yes (2) | No (6)  

Varunraj Reddy   10 years AGO

If x=1 only satisfies the given condition
Then y=(6+1)^2/(6-1)^2
y=49/25

Like? Yes (3) | No (7)  

10 Jun 2014 Solve

Mr. Sonkar says to his son Suresh, " My age was two years more than 7 times of your’s age before 30 and 1/2 a year and after 2 and 1/2 a year, my age will be twice of yours age of 1/2 a year before". What will be the age of Suresh after 12 and 1/2 a year.

OPtion

1) 36 & 1/2
2) 46 & 1/2
3) 42
4) 52 & 1/2
5) 40
6) 41 & 1/2
7) 39 & 1/2
8) 50
9) 48
10)None of these

Solution

Let the present ages of father and son are "x" and "y" respectively.
According to the first condition given
(x - 30.5) = 7 ( y - 30.5 ) + 2 (i)
According to the second condition given
(x + 2.5) = 2 ( y – 0.5) (ii)
On solving these equations we get the solution.

Correct Option: 9 Best Solution (12)

Udhaya kumar   10 years AGO

let x as father's age y as son's age...
from given
7(y-30.5)+2=(x-30.5)
2(y-0.5)=(x+2.5)
By solving this we get x=67.5 & y=67.5
After 12.5 years their ages will be x=80 y=48...

Like? Yes (4) | No (3)  

Ann Theressa   10 years AGO

Let x be the present age of Suresh and y Mr.Sonkar

y - 61/2 = 2 + 7*(x - 61/2) ---(1)

y + 5/2 = 2*( x - 1/2) ---(2)

Solving (1) and (2)
x = 35 and 1/2

So after 12 and 1/2 a year
Suresh's age = 48

Like? Yes (1) | No   

shree   10 years AGO

9) 48 is right answer..

Like? Yes (1) | No   

RAKESH   10 years AGO

(m-30.5)=7(s-30.5)+2

(m+2.5)=2(s-.5)

=> s=35.5
after 12.5 , s=48

Like? Yes (1) | No   

Saraswathy   10 years AGO

f-61/2 = 7(s-61/2)+2 -->(1)
f+5/2 = 2(s-1/2) -->(2)

Solving (1) nd (2), we ll get
f = 135/2
s = 71/2
After 12 1/2 years , son's age ll be
71/2 + 25/2
=> 96/2 = 48

Ans : 48 (Option 9)

Like? Yes (3) | No (4)  

Dr.Dipin Singh   10 years AGO

If F & S are ages of Sonkar and Suresh, then
(F-30.5)= 7*(S-30.5)+2
(F+2.5)= 2*(S-0.5)
solving these eqns, we get
S= 35.5 yrs
so age of Suresh after 12 and 1/2 a year will be 35.5+12.5=48 yrs

Like? Yes (4) | No (5)  

abhilash kumar   10 years AGO

Let sonkars present age be y years and suresh\'s present age be x years
Then according given conditions
We have y-30.5=7(x-30.5)+2
y+2.5=2(x-0.5)
Solving we get x=35.5
Suresh age after 12.5 years is 35.5+12.5 = 48 years

Like? Yes (1) | No (2)  

mohit   10 years AGO

Present age of sonkar and suresh be x & y.
eq1 : x-30.5 = 7(y-30.5)+2
eq2 : x + 2.5 = 2(y-0.5)
solving y = 35.5
after 12.5 years
suresh's age = 48

Like? Yes (1) | No (2)  

Devesh Agrawal   10 years AGO

say present age of Mr. Sonkar is x and present age of Suresh is y.
x-30.5=2+7(y-30.5) and x+2.5=2(y-0.5)
solving these two, we get, x=67.5 and y=35.5
So, after 12.5 years, age of Suresh = y+12.5=35.5+12.5= 48 years

Like? Yes (1) | No (2)  

Vishal Chugh   10 years AGO

Let Suresh's present age is 's' and that of Sonkar is 't'
From the given data equations will be:

t - 30.5 = 7(s - 30.5) + 2 ---- (1)
t + 2.5 = 2(s - 0.5) ----(2)

Solving these equations we get, s = 35.5
So after 12.5 years Suresh's age will be :
35.5 + 12.5 = 48

Like? Yes (1) | No (2)  

Bhavna   10 years AGO

let the age of suresh=x
(7x-181)+5/2=2(x-1/2)
x=71/2
after 12 and 1/2 year age will be=71/2+25/2=48

Like? Yes (1) | No (2)  

mansi garg   10 years AGO

let f and s age of father and son before 30.5 yr
7s+2=f
let F and S be there current age
F=7s+30.5+2
S=s+30.5
F+2.5=2S
7s+2+33=2s+60
s=5
age after 12.5 yr=48 yrs

Like? Yes (1) | No (3)  

09 Jun 2014 Sequence

What is the next number of the following sequence
673, 697, 10117, 125422, 878842,.........

OPtion

1) 897723432
2) 4567583
3) 23489763
4) 12854980
5) 980932452
6) 89121199
7) 991657899
8) 987043526
9) 5678437
10)None of these

Solution

673 is converted as (6+1)|(7+2)|(3+3), on reversing we get 697,
697 is converted as (6+1)|(9+2)|(7+3), on reversing we get 10117,
10117 is converted as (1+1)|(0+2)|(1+3)|(1+4)|(7+5), on reversing we get 125422
Take similar steps for finding answer.

Option 6)

Correct Option: 6 Best Solution (9)

Dr.Dipin Singh   10 years AGO

673, 697, 10117, 125422, 878842,.........
673...697
add 1 to 6 to get 7.
add 2 to 7 to get 9.
add 3 to 3 to get 6.
place numbers in reverse order to get 697.
similarly 697... 10117
..

so for next number from 878842..
add 1 to 8 to get 9.
add 2 to 7 to get 9.
add 3 to 8 to get 11.
add 4 to 8 to get 12.
add 5 to 4 to get 9.
add 6 to 2 to get 8.
so next number will be 89121199.... option 6

Like? Yes (10) | No (2)  

Saraswathy   10 years AGO

(673, 697, 10117), (125422, 878842,x)
Divide the series into 2 group...

3rd no. = (2nd no.) + (Reverse of diff. of 1st nd 2nd calculated digit-by-digit)

1) Diff. between 673 nd 697
6-6=(0)... 9-7=(2)...7-3=(4)... (ie diff. is 024)
3rd no. = 693+Reverse of (024) => 697+420
=> 6+4=(10)... 9+2=(11)...7+0=(7) = 10117

Similarly for 2nd group
2) Diff. between 125422 nd 878842 is
8-1=(7)...7-2=(5)...8-5=(3)...8-4=(4)...4-2=(2)...2-2=(0)...
Diff is 753420

So x = 878842 + Rev(753420)
=> 878842 + 024357
8+0=(8)... 7+2=(9)... 8+4=(12)... 8+3=(11)...4+5=(9)... 2+7=(9)
x = 89121199

Ans : 89121199 (Option 6)

Like? Yes (6) | No (2)  

kewal   10 years AGO

next number of the following sequence
673, 697, 10117, 125422, 878842,......... 89121199
673....(6+1..7+2..3+3)..... (7 9 6)..>> 697

878842... 9-9-11-12-9-8 .... 89121199

Like? Yes (3) | No (1)  

Karan   10 years AGO

add 1 in 1st digit, 2 in 2nd digit, .....
now put all the new numbers in reverse order to get next number.
From 878842
8+1=9
7+2=9
..
..
2+6=8
so next number = 89121199

Like? Yes (2) | No (1)  

RAKESH   10 years AGO

673=(6+1)(7+2)(3+3) = 796 rev = 697

878842=(8+1)(7+2)(8+3)(8+4)(4+5)(2+6)= 9 9 11 12 9 8 rev
89121199

Like? Yes (1) | No   

mansi garg   10 years AGO

87+2=89
8+4=12
8+3=11
and so on

Like? Yes (1) | No   

susmit   10 years AGO

by trial and error method

Like? Yes (1) | No   

rajani   10 years AGO

Take the First 3 as the group,
6 7 3
+0 +2 +4
6 9 7
+4 +2 +0
10 11 7
And now for the next number,
1 2 5 4 2 2
+7 +5 +3 +4 +2 +0
8 7 8 8 4 2
+0 +2 +4 +3 +5 +7
8 9 12 11 9 9

Like? Yes (2) | No (2)  

abhilash kumar   10 years AGO

It is coded as follows
673 is coded as (6+1)(7+2)(3+3)=796 on reversing we get 697
Similarly intermediate nos are coded
Now 878842 is coded as(8+1)(7+2)(8+3)(8+4)(4+5)
(2+6)=99111298 on reversing we get 89121199

Like? Yes (1) | No (2)  

06 Jun 2014 Coded language

If in coded language
NAVAL = 3646
MANISH = 248912
VIJAY = 49433
Then
SURESH =

OPtion

1) 682250
2) 7646
3) 4922005
4) 5458230
5) 6822
6) 6823005
7) 6862020
8) 6834290
9) 4869
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
NAVAL = (N*A*V*A*L)-(N+A+V+A+L)
NAVAL = (14*1*22*1*12)-(14+1+22+1+12) = 3696-50 = 3646
MANISH = (13*1*14*9*19*8)-(13+1+14+9+19+8) = 248976-64 = 248912
VIJAY = (22*9*10*1*25)-(22+9+10+1+25) = 49500-67 = 49433
Similarly
SURESH = (19*21*18*5*19*8)-(19+21+18+5+19+8) = 5458320-90 = 5458230

Option 4)

Correct Option: 4 Best Solution (26)

Dr.Dipin Singh   10 years AGO

NAVAL ... (14*1*22*1*12)- (14+1+22+1+12)= 3646
similarly
MANISH = 248912
VIJAY = 49433
hence
SURESH = ( 19*21*18*5*19*8)-(19+21+18+5+19+8)= 5458320-90= 5458230 .. option 4

Like? Yes (11) | No (7)  

Saraswathy   10 years AGO

NAVAL = 3646
(N*A*V*A*L- (N+A+V+A+L)) => (14+*1*22*1*12 -(14+1+22+1+12)) = 3696 - 50 = 3646

Similarly
SURESH
(19*21*18*5*19*8 - (19+21+18+5+19+8)) = 5458230

Ans : 5458230 (Option 4)

Like? Yes (10) | No (8)  

Pradeep   10 years AGO

SURESH = 19*21*18*5*19*8 = 5458320 - (19+21+18+5+19+8) =5458320-90= 5458230

Like? Yes (1) | No   

mahi juttu   10 years AGO

SURESH->(S*U*R*E*S*H - S+U+R+E+S+H)
-> (19*21*18*5*19*8 - 19+21+18+5+19+8) = 5458230

Like? Yes (1) | No   

Manoj Kumar   10 years AGO

Multiply each alphabet number
ex man
m=13
a=1
n=14
ans=13*1*14=182

Like? Yes (1) | No   

paaredi muthyam reddy   10 years AGO

(multiply the digit values)-(sum of digit values)

digit values are a=1,b=2,c=3,.......z=26

Like? Yes (1) | No   

elby   10 years AGO

A=1 B=2 C=3 etc.
SxUxRxExSxH - S+U+R+E+S+H

Like? Yes (1) | No   

Jeevan   10 years AGO

A=1
B=2
..
Z=26

ABCDE = 1*2*3*4*5 - (1+2+3+4+5)

Like? Yes (4) | No (6)  

Udhaya kumar   10 years AGO

(s*u*r*e*s*h)-(s+u+r+e+s+h) = 5458230.....
where a=1,b=2............z=26

Like? Yes (3) | No (6)  

Gitanjali K   10 years AGO

A=1,B=2,C=3,D=4,..........,X=24,Y=25,Z=26

NAVAL=(14*1*22*1*12)-(14+1+22+1+12)=3646
MANISH=(13*1*14*9*19*8)-(13+1+14+9+19+8)=248912
VIJAY=(22*9*10*1*25)-(22+9+10+1+25)=49433
and
SURESH=(19*21*18*5*19*8)-(19+21+18+5+19+8)=5458230

so option (4) is the answer..

Like? Yes (5) | No (8)  

Varunraj Reddy   10 years AGO

NAVAL =(14*1*22*1*12)-(14+1+22+1+12)
=3696-50
=3646

MANISH =(13*1*14*9*19*8)-(13+1+14+9+19+8)
=248976-64
=248912

VIJAY =(22*9*10*1*25)-(22+9+10+1+25)
=49500-67
=49433

SURESH =(19*21*18*5*19*8)-(19+21+18+5+19+8)
=5458320-90
=5458230

Ans:Option 4)

Like? Yes (5) | No (9)  

Vishal Chugh   10 years AGO

Multiply the numbers corresponding to the letters:
NAVAL = 14*1*22*1*12 = 3696
Subtract this result with the sum of digits:
NAVAL = 14+1+22+1+12 = 50
So, corresponding code for NAVAL = 3696 - 50 = 3646
Similarly for SURESH:
Step 1(Multiplication):19*21*18*5*19*8 = 5458320
Step 2(Addition) : 19+21+18+5+19+8 = 90
Step 3(Subtraction) : 5458320 - 90
=5458230

Like? Yes (3) | No (7)  

T.Aravinth kumar   10 years AGO

Product of all the numbers-sum of all the numbers

Like? Yes (3) | No (7)  

rajani   10 years AGO

(product of the letters)-(sum of the letters)=result
so,For Naval=(14*1*22*1*12)-(14+1+22+1+12)=3646
in the Same Way,
SURESH=(19*21*18*5*19*8)-(19+21+18+5+19+8)
= 5458320-90
=5458230

Like? Yes (1) | No (6)  

Dada Khalandar   10 years AGO

a=1,b=2,..........z=26
NAVAL = 14*1*22*1*12=3696,,
14+1+22+1+12=50,, 3696-50=3646.
like that "multiplications of number - adding the total numbers
SURESH= 19*21*18*5*19*8=5458320-90=5458230

Like? Yes (1) | No (6)  

Datla Kanthi   10 years AGO

Product of the alphabets - sum of the alphabets in the name
SURESH Product = 19*21*18*5*19*8= 5458320
SURESH Sum = 19+21+18+5+19+8=90

Option = 5458320 - 90 = 5458230

Like? Yes (1) | No (6)  

kiran mallipudi   10 years AGO

Total alphanumeric product Minus alphanumeric sum hence answer is 5458230
5458320-90=5458230

Like? Yes (1) | No (6)  

REHAN AHMAD   10 years AGO

N=14
A=1
V=22
A=1
L=12

SUM=50 AND MUL= 3696
SO MUL-SUM=3646

SAME LOGIC FOR ALL
S=19
U=21
R=18
E=5
S=19
H=8

SUM=90 MUL=5458320
MUL-SUM= 5458230
THIS IS THE ANSWER (OPTION 4)

Like? Yes (1) | No (6)  

AKSHAY MISHRA   10 years AGO

SURESH =(S*U*R*E*S*H - S+U+R+E+S+H)
=> (19*21*18*5*19*8 - 19+21+18+5+19+8) = 5458230

Like? Yes (1) | No (6)  

SREEVIDHYA P P   10 years AGO

NAVAL=(14*1*22*1*12)-(14+1+22+1+12)=3696-50=3646
................................
SURESH=(19*21*18*5*19*8)-(19+21+18+5+19+8)
=5458320-90=5458230.
SO ANSWER IS OPTION 4.

Like? Yes (1) | No (6)  

DHIRENDRA    10 years AGO

decode the no each no by A=1,B=2,C=3.....Z=26
multiply the no then subtract the sum of the no.

Like? Yes (1) | No (6)  

shree   10 years AGO

5458320-90=5458230

Like? Yes (1) | No (6)  

Ranjit Somisetty   10 years AGO

S=19,U=21,R=18,E=5,H=8

19*21*18*5*19*8=5458230

Hence option 4

Like? Yes (1) | No (7)  

Kunal Arora   10 years AGO

Write first numeric value of every code.
Then multiply all the values and add sum of all values.
SURESH= 19,21,18,5,19,8
Ans= (19*21*18*5*19*8)+(19+21+18+5+19+8)=5458230

Like? Yes (2) | No (8)  

Sundar Kumar   10 years AGO

A(1),B2,C3,D4,E5,F6,G7,H8,I9,J10,K11,L12,N13,M14,O15,P16,Q17,R18,S19,T20,U21,V22,W23,X24,Y25,Z26
ANSWER=PRODUCT OF EACH LETTERS-SUM OF EACH LETTERS
NAVAL = 3646
MANISH = 248912
VIJAY = 49433
Then
SURESH =option 4) 5458230

Like? Yes (1) | No (7)  

SIBNATH HALDER   10 years AGO

option 4 ans

Like? Yes (1) | No (7)