M4maths Previous Puzzles

22 May 2014 Solve

The side of a square exceeds the side another square by 4 cm and the sum of the area of the two squares in 400 sq cm. Find the dimension of the square.

OPtion

1) 8cm and 12cm
2) 9cm and 13cm
3) 10cm and 14cm
4) 14cm and 18cm
5) 6cm and 10cm
6) 20cm and 24cm
7) 12cm and 16cm
8) 18cm and 22cm
9) 22cm and 26cm
10)None of these

Solution

Let side of smaller square be x cm
The side of other square = (x+4) cm
The sum of area of squares x^2+(x+4)^2 = 400
solve
12cm and 16cm sides

Option 7)

Correct Option: 7 Best Solution (46)

Ann Theressa   10 years AGO

Let the sides of squares be x and (x+4)

x^2 + (x+4)^2 = 400
2x^2 + 8x + 16 = 0
x^2 + 4x - 192 = 0
x = 12,-16
take x = 12(positive value)

So the dimension of 2 squares are 12cm and 16cm

Like? Yes (11) | No (4)  

Sumit yadav   10 years AGO

Let the side of the smaller square be x cm.
Side of the larger square = Side of the smaller square + 4 cm
∴ Side of the larger square = (x + 4) cm
Given, Area of the smaller square + Area of the larger square = 400 cm2

Side of the smaller square = 12 cm
Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm

Like? Yes (10) | No (6)  

SAIF UDDIN   10 years AGO

12*12=144
16*16=256
Now, 144+256=400

Like? Yes (5) | No (1)  

M VINOD KUMAR   10 years AGO

Let the side of one square is x cm then another one is x+4 cm
sum of areas (x+4)^2 + x^2 = 400
x^2 + 8x + 16 + x^2 =400
x^2 + 4x -192 = 0
solving x= 12 and -16
we took x=12cm , x+4 = 16cm

Like? Yes (6) | No (3)  

NAGENDRA P   10 years AGO

A^2+(A+4)^2=200...
SOLVING A=12CM..AND 16CM

Like? Yes (5) | No (2)  

manish chauhan   10 years AGO

12*12=144
16*16=256
16-12=4
144+256=400

Like? Yes (5) | No (3)  

prateek   10 years AGO

here 400=a^2+b^2
so 20^2=a^2+b^2
so we have to find pythagorean triplets matching the eqn.we know that 3,4,5 is a pythagorean triplet.so we get (5*4)^2=(4*4)^2+(3*4)^2.
thus we get sides as 12 and 16

Like? Yes (4) | No (2)  

shefali jain   10 years AGO

let the side of a square is=a
then the side of other square is=a+4
then
(a+4)^2+a^2=400
by solving this equation the value of
a=12cm (which is the side of first square)
a+4=16cm(which is the side of other square)

Like? Yes (3) | No (1)  

Meghana   10 years AGO

area of square=a^2
12^2+16^2=144+256=400&16-12=4

Like? Yes (3) | No (1)  

ANUP KUMAR   10 years AGO

let x = dimension of 1st square
Given, x+4 = dimension of other square
and x^2 + (x+4)^2 = 400
by solving,
x = 12
and x+4 = 16
option (7)

Like? Yes (6) | No (5)  

Dr.Dipin Singh   10 years AGO

x^2+(x+4)^2=400
solving, we get, x=12 cms
so sides of squares are 12 and 16 cms.

Like? Yes (8) | No (7)  

Karan   10 years AGO

if sides of squares are x and x+4 cms, then
x^2+(x+4)^2=400
x^2+4x-192=0
(x+16)*(x-12)=0
x=12 cms
so sides are 12 and 16 cms.

Like? Yes (8) | No (7)  

Varunraj Reddy   10 years AGO

Let the side of a square=x cm
Then the side of another square=x+4 cm
Sum of the areas of two squares=400 sq cm
x^2+(x+4)^2=400
x^2+x^2+16+8x-400=0
2x^2+8x-384=0
x^2+4x-192=0
x^2+16x-12x-192=0
x(x+16)-12(x+16)=0
x=12,-16
Option (7)

Like? Yes (5) | No (4)  

vishnuvardhan   10 years AGO

x^2+(x+4)^2=400
2x^2+8x-384=0
x=12,-16(as side is +ve)
x=12,x+4=16
12,16

Like? Yes (4) | No (3)  

sruthi   10 years AGO

12, 16 is answer

Like? Yes (6) | No (6)  

MD SOHAIL AKHTER   10 years AGO

let the side of the square be x cm
side of other square is (x+4) cm
A/Q
x^2+(x+4)^2=400
on solving we get
side of two squares are=12cm and 16cm

so correct option is (7)

Like? Yes (4) | No (5)  

hareesh   10 years AGO

x^2+(x+4)^2=400
x^2+4x-192=0
x^2+16x-12x-192=0
(x+16)(x-12)=0
x=-16,x=12

Like? Yes (4) | No (5)  

Devendra Marghade   10 years AGO

If side of squares are x & x+4
x^2+(x+4)^2=400
x^2+4x-192=0
(x+16)(x-12)=0, so x=12
So sides are 12 & 16

Like? Yes (2) | No (4)  

Jigyasa Kumar   10 years AGO

Answer : 12, 16
on solving (a-b)^2, we get ab = 192
and a,b = 12 and 16

Like? Yes (2) | No (4)  

abhilasha   10 years AGO

on solving (a-b)^2, we get ab = 192
and a,b = 12 and 16

Like? Yes (2) | No (4)  

SIBNATH HALDER   10 years AGO

X^2+(X+4)^2=400
X^2+4X-192=0
X=16
X=12

Like? Yes (2) | No (4)  

rajani   10 years AGO

Let side of square be xcm
Side of another square =(x+4)cm
And the sum of area of two squares=400 sqcm
--> x^2+(x+4)^2=400
2x^2+8x+16=400
x^2+4x-192=0
x^2+16x-12x-192=0
(x+16)(x-12)=0
x=12 or -16
So,x+4=12+4=16cm
the sides of both squares are 12cm and 16cm

Like? Yes (2) | No (4)  

P.Someshwar Reddy   10 years AGO

Answer is option(7)

Let the side of the square be s1
and the side of the other square be s2

Given the side of square exceeds the side of the other square by 4.c.m
=> s2=s1+4

Given sum of areas is 400.sq.c.m.
=>(s1^2)+(s2^2)=400
=>(s1^2)+((s1+4)^2))=400
=>(s1^2)+(s1^2+8s1+16)=400
=>2s1^2+8s1+16=400
=>2s1^2+8s1-384=0
dividing the equation by 2
=>s1^2+4s1-192=0
=>s1^2+16s1-12s1-192=0
=>s1(s1+16)-12(s1+16)=0
=>(s1+16)(s1-12)=0
=> s1= -16 or 12
since length can not be negative
the side of square is 12.cm.
=>s1=12.c.m.
=>s2=12+4=16.c.m.

therefore the two lengths are 12cm and 16cm

Like? Yes (3) | No (5)  

Deb Das   10 years AGO

x^2+(x+4)^2=400
x^2+x^2+8x+16=400
x^2+4x-192=0

(x+16)(x-12)=0

So, x=12
and the dimensions are 12 and (12+4)=16 cm

Like? Yes (2) | No (4)  

sanghavi    10 years AGO

let l1 be the side of one square
and side of another square is l2=l1+4
sum of area (l1)^2+(l1+4)^2=400
2(l1^2+4l1+8)=400
l1^2+4l+4+4=200
(l1+2)^2=196
l1+2=sqrt(196)
l1+2=14
l1=12
then l2=12+4=16

Like? Yes (2) | No (4)  

Arvind Yadav   10 years AGO

here it is given that one square exceeds the side to another by 4 cm .
so suppose one sqare side is x cm then another side is x+4.
and
we know that area of sqare =side^2
so sum of area of both sqares =x^2+(x+4)^2
and it is given that sum of area of squares =400
so x^2+(x+4)^2=400
so from option best ans is 12 and 16 which satisfy the above condition.

Like? Yes (2) | No (4)  

bithika das   10 years AGO

side of square1=a,side of another square =a+4
ares of two square=(a)^2+(a+4)^2=400
solving ,
we get a=12 and 16

Like? Yes (2) | No (4)  

subramani   10 years AGO

Area of Square= A^2
So...Two Squares area A1^2+ A2^2=400
A^2=400 then
a=20
To find square A1^2, Less Exceed side size 4 cm.. so
A1= 20-4=16cm

so A1^2=16^2=256
put the A1^2 in Total Area=A1^2+A2^2=400
16^2+A2^2=400
A2^2=400-256=144
A2^2=144 so
A2=Sqrt(144)
A2=12cm

so Sides of Two Squares are 12 & 16 Cm
Option 7 is correct

Like? Yes (2) | No (4)  

ABHOY KUMAR   10 years AGO

let the sides of two squares be s1,s2
s1^2+s2^2=400 ...(i)
s1=s2+4 ....(ii)
solving (i) & (ii)
s1=16 cm
s2=12cm

Like? Yes (2) | No (4)  

AMIT SINGH   10 years AGO

sides of square are x and x+4 cm
then x^2 +(x+4)^2 =400
=>x=12
so, dimension of square are 12cm and 16cm.

Like? Yes (2) | No (4)  

Pranjali Das   10 years AGO

let one side be x and the other be y
so according to the qs
x-y=4 and x^2 + y^2= 400
so solving the equations y=12 and x=16
so the answer is option 7

Like? Yes (2) | No (4)  

Dhruva Rathore   10 years AGO

X is 12 after solving so when the second side exceeds by 4 . Which implies other side is x+4 = 16

Like? Yes (2) | No (4)  

SREEVIDHYA P P   10 years AGO

12cm &16cm
Area of a square of side 12cm is 144sq.cm.
Area of a square of side 16cm is 256sq cm.
Sum of the area of squares is 144+256=400sq cm.
Ans. Is option 7...12cm &16cm

Like? Yes (2) | No (4)  

Ravi Raj   10 years AGO

12^2+16^2 = 400

Like? Yes (2) | No (4)  

SHUBHAM KUMAR   10 years AGO

x*x+(x+4)*(x+4)=400
on solving x=12

Like? Yes (2) | No (4)  

Leelanand Kumar Yalla   10 years AGO

x^2+(x+4)^2=400; by solving this we will get x=12 and x+4= 16cms......

Like? Yes (2) | No (4)  

Naveen Ganesh   10 years AGO

a^2 + (a+4)^2 = 400

Like? Yes (2) | No (4)  

Rownaz Haque   10 years AGO

Let the side of the square be x.
Side of other square=x+4
Sum of area of two squares= 400
so,
x sq + (x +4) sq = 400
2x sq + 16+ 8x = 400

putting the values from options we see that option 7 satisfies the equation....so ans is option 7.

Like? Yes (1) | No (4)  

ASHISH MITTAL   10 years AGO

12^2+16^2=144+256=400

Like? Yes (1) | No (4)  

Arun Kumar Tiwari   10 years AGO

x^2 + (x+4)^2 = 400
=>x^2 + x^2 + 16 + 8x = 400
=>2x^2 +16+8x=400
=>x^2 +4x+8=200
=>(x+16)(x-12)=0
=>x=-16 or 12

since the length of the square can not be negative
Therefore x=12

so, lenght of first square is
12
and second square is x+4=16

Thus answer is 12 and 16

Like? Yes (1) | No (4)  

pravesh singh khatri   10 years AGO

since
area of square1 + area of square2= 400,
a1^2 + a2^2 = 400,
since a2= a1+4
a1^2 + (a1+4)^2=400,
a1=12,
a2=16

Like? Yes (1) | No (4)  

yeshwanth   10 years AGO

let x be one side of the small square,
big squares side = x+4
area sum =x*x+(x+4)*(x+4)=400
x2+x2+4x+4x+16=400
2x2+8x+16=400
x2+4x+8=200


solving this x=

Like? Yes (1) | No (4)  

srilakshmi   10 years AGO

let the side of one square is xcm,then then the second one will be (x+4)cm.
some of area of those 2 squares is 400sqrcm
so
x^2+(x+4)^2 = 400
x^2+x^2+16+8x = 400
x^2+4x+8 = 200
x^2+4x+4 = 196
(x+2)^2 = 196
x+2 = 14
x = 12
so
x+4 = 16
12cm and 16cm is answer

Like? Yes (1) | No (5)  

harshal agrawal   10 years AGO

a-b = 4
400-2ab = 16
ab=192
hence
a=16 b=12

Like? Yes (1) | No (5)  

DILEEP KUMAR   10 years AGO

a^2 + (a+4)^2 = 400
a=12,16.

Like? Yes (1) | No (5)  

Gokul Krishnan   10 years AGO

x^2+(x+4)^2=400

x=12,16

Like? Yes (1) | No (5)  

21 May 2014 Solve

In an examination of 500 marks (5 subjects & 100 marks for each subject), Amit got first class certificate with 67.8 %. If he got perfect square marks in all the subjects, then what are the number of possible methods for taking these marks in all the subjects.

OPtion

1) 28
2) 20
3) 4
4) 120
5) 15
6) 12
7) 60
8) 30
9) 243
10) None of these

Solution

The possible combination of marks is 49, 64, 64, 81, 81 Total number of methods for providing 81 marks for any 2 subjects out of 5 subjects is 10, then number of methods for providing 64 marks for any 2 subjects out of remaining 3 subjects is 3, then 49 marks is provided for the last subject. Hence total number of methods are 10*3*1 = 30

Option 8)

Correct Option: 8 Best Solution (5)

Prerna   10 years AGO

Amit got first class certificate with 67.8 %.
i.e. 339 out 0f 500.
If he got perfect square marks in all the subjects,
then he got 81 in 2 subjects, 64 in 2 subjects and 49 in one subject.
number of possible methods for taking these marks in all the subjects = 5!/(2!*2!)= 120/4=30

Like? Yes (7) | No (1)  

Ramsb   10 years AGO

67.8%=339 marks
amit got 64,64,49,81,81
then 5!/2!.2!
120/4=30

Like? Yes (3) | No (1)  

Ann Theressa   10 years AGO

Percentage marks = 67.8
total marks = 67.8*5 = 339

Since he got perfect square marks in all subjects
His marks can be
49,64,81 and 100

49+64+64+81+81 = 339

No of possible ways for taking these marks = 5!/(2!*2!) = 30

Like? Yes (3) | No (3)  

DILEEP KUMAR   10 years AGO

marks are 64,64,81,81,49
possibilities 5!/2!*2! = 30

Like? Yes (3) | No (3)  

Varunraj Reddy   10 years AGO

The possible ways are (64,64,49,81,81)

These values can be arranged in 5!/(2!*2!) ways

Total no.of possible methods=120/4=30

Like? Yes (2) | No (2)  

20 May 2014 Quadratic equation

Solve
3^(4x+1) - 2*3^(2x+2) = 81

OPtion

1) 9
2) 18
3) 7
4) -6
5) 5
6) 24
7) -3
8) 2
9) 1
10)None of these

Solution

3^4x* 3^1 - 2*3^2x*3^2 = 81
let 3^2x = y
3y^2 - 18y - 81 = 0

Solve
x = 1
Option 9)

Correct Option: 9 Best Solution (26)

Sundar Kumar   10 years AGO

3^(4x+1) - 2*3^(2x+2) = 81
3^4x*3-2*3^2x*3^2=81
3^2x(3^2*3-2*3^2)=81
3^2x(9)=3^4
3^2x=3^4/3^2
3^2x=3^2
2x=2
x=1

Like? Yes (7) | No (2)  

abhilasha   10 years AGO

the equation gets fulfilled on keeping x = 1

Like? Yes (2) | No (1)  

Suraj   10 years AGO

put 3^2(x+1)= y

and then solve you wil get y^2-54y-2187=0

factorise and you will get y as 81 and -27

discard -27 as the 3^2(x+1) cannot be -ve. equate
3^2(x+1)= 81 you will get the answer as 1

Like? Yes (2) | No (1)  

IFFAT IRAM   10 years AGO

3^(4x+1) - 2*3^(2x+2) = 81
3*9^2x - 18*9^x = 81
9^2x - 6*9^x = 27
y=9^x
y^2-6y-27=0
(y+3)(y-9)=0
y=9 or -3

9^x=9 or 9^x=-3(not possible)
x=1

Like? Yes (3) | No (2)  

Arigela Naga Vineel   10 years AGO

i got it by substitution

Like? Yes (1) | No   

SREEVIDHYA P P   10 years AGO

3^(4x+1)-2*3^(2x+2)=81
3(3^4x-6*3^2x)=81
3^4x-6*3^2x=27
(3^x)^4-6*(3^x)^2-27=0
Solving this equation we get x=1.
Option is 9

Like? Yes (2) | No (1)  

hareesh   10 years AGO

put x=1

Like? Yes (2) | No (1)  

kaushlendra dutt trivedi   10 years AGO

first put x=1 in the equaction
then i get
LHS=RHS
thus i mark the option no (9)

Like? Yes (2) | No (1)  

harshal agrawal   10 years AGO

taking 3^2x = y
y^2-6y-27=0
i.e. x=1

Like? Yes (2) | No (1)  

vishnuvardhan   10 years AGO

3^(2x)=t
3t^2-18t-81=0
t=9,-3
3^(2x)=9
3^(2x)=3^2
x=1

Like? Yes (1) | No   

AMIT SINGH   10 years AGO

substituting 1 in place of x
we get the required equation,
that is,
LHS=3^(4*1+1)-2*3^(2*1+2)=3^5-2*3^4
=81
RHS=81.
hence value of x=1.

Like? Yes (3) | No (2)  

Sukanya   10 years AGO

substituting x=1
3^5-2*3^4=243-2*81=243-162=81
since x=1 satisfies the given equation, x=1

Like? Yes (2) | No (1)  

Anupam Banerjee   10 years AGO

3^(4x+1)-2*3^(2x+2)=81
or, 3*3^4x-2*3*3*3^2x=81
or, 3^4x-2*3*3^2x=27
(Adding 9 with both side)
or, (3^2x)^2-2*(3^2x)*3+9=27+9
or, (3^2x - 3)^2 = 36
or, 3^2x - 3 = 6
or, 3^2x = 9
or, 2x = 2
or, x=1;

Like? Yes (2) | No (1)  

srilakshmi   10 years AGO

by options
if we replace x with 1(9th option)
3^5-2*3^4 = 243-162 = 81

(or)

3^4x+1 - 2.3^2x+2 = 81
3^4x.3 - 2.3^2x.3^2 = 81(a^m+n = a^m.a^n)
(3^2x)^2*3 - 18*3^2x = 81
let us assume
3^2x = t
3t^2-18t-81 = 0
t^2-6t-27 = 0
by solving this
t = 9
3^2x = 9
9^x = 9^1
so
x=1(as bases equal powers also equal).

Like? Yes (2) | No (2)  

ravi prakash   10 years AGO

3^5=243
2*3^4=162
243-162=81

Like? Yes (2) | No (2)  

Saraswathy   10 years AGO

3^(4x+1) - 2*3^(2x+2) = 81
3^4x * 3^1 - 2* 3^2x * 3^2 = 81
3^2x * 3[3^2 - 2*3] = 3^4
3^2x * 3^2 = 3^4
3^(2x+2) = 3^4
Equate the powers since base is same
2x+2 = 4
x=1
Hence Option (9)

Like? Yes (2) | No (2)  

SIBNATH HALDER   10 years AGO

option 9-1 ans

Like? Yes (1) | No (1)  

manish chauhan   10 years AGO

x=1
3^(4+1)-2*3^(2+2)=81
3^5-2*3^4=81
3^4(3-2)=
81(1)=81 prove

Like? Yes (2) | No (2)  

rajani   10 years AGO

By options on substituting 1 in that equation it is satisfying.
3^5-2(3^4)=243-162=81

Like? Yes (2) | No (3)  

SHEREENA NISHAD   10 years AGO

81= 3^4
3*3^4 - 2* 3^4 =3^4
3^3^4 =3^5 = 3^(4x+1)
4x+1 = 5
x=1

Like? Yes (1) | No (2)  

Deb Das   10 years AGO

3^(4x+1) - 2*3^(2x+2) = 81
3*3^4x-2*9*3^2x=81
3^4x-6*3*3^2x=27
3^4x-9*3^2x+3*3^2x-27=0
3^2x(3^2x-9)+3(3^2x-9)=0
(3^2x-9)(3^2x+3)=0

So,
3^2x=9
3^2x=3^2
2x=2
x=1

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

3^(4x+1) - 2*3^(2x+2) = 81
put 2x=t
3^(2t+1) -2*3^(t+2) = 81
[(3^2t)*3]- [2*(3^t)*3^2] =81
3^t[(3^2)*3 - 2*3^2]=81
3^t(27-18)=81 ,t=2=2x, so x=1

Like? Yes (1) | No (2)  

Jigyasa Kumar   10 years AGO

on putting x = 1 the equation gets satisfied

Like? Yes (1) | No (2)  

Aarush Singh   10 years AGO

x=1 satisfies the equation

Like? Yes (1) | No (2)  

Ramsb   10 years AGO

(3^4x.3)-(2*3^2x*3^2)=81
3(3^4x-6.3^2x)=81
3^2x(3^2-6)=27
3^2x(3)=27
3^2x+1=3^3
2x+1=3
x=1

Like? Yes (1) | No (2)  

Varunraj Reddy   10 years AGO

If x=1 then the equation satisfies.

Like? Yes (1) | No (2)  

19 May 2014 Sequence

What is the next number of the following sequence.
17, 88, 176, 847, 1595,........

OPtion

1) 5951
2) 6591
3) 7548
4) 6546
5) 7546
6) 5546
7) 7542
8) 7556
9) 7572
10)None of these

Solution

17
17+71 = 88 (number + reverse number)
88+88 = 176
176+671 = 847
847+748 = 1595
Similarly
1595+5951 = 7546

Correct Option: 5 Best Solution (28)

rajani   10 years AGO

adding the given number and reverse of number gives the next number.
17+71=88
88+88=176

..........
........
1595+5951=7546

Like? Yes (6) | No (3)  

Saraswathy   10 years AGO

17, 88, 176, 847, 1595, x

Current no. + reverse of current no. = Next number
17 + 71 = 88
88 + 88 = 176
176 + 671 = 847
847 + 748 = 1595
1595 + 5951 = 7546
x = 7546

Ans : Option (5)

Like? Yes (5) | No (2)  

Pradeep   10 years AGO

17+71=88;;88+88=176;;176+671=847;;847+748=1595;;1595+5951=7546

Like? Yes (1) | No   

prateek   10 years AGO

17
88=(1+7)(1+7)
176=(8+8)

Like? Yes (1) | No   

Priyanka   10 years AGO

17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546

Like? Yes (1) | No   

Pargat Pal Singh   10 years AGO

reverse the digits and add to number to get next number.
17
17+71=88
88+88=176
..
..
1595+5951= 7546

Like? Yes (2) | No (2)  

Dr.Dipin Singh   10 years AGO

17, 88, 176, 847, 1595,........
17+71=88
88+88=176
176+671= 847
847+748 = 1595
1595+5951= 7546 ... option 5

Like? Yes (2) | No (2)  

Leelanand Kumar Yalla   10 years AGO

17+71=88; 88+88=176 LIKE THE WAY 1595+5951=7546; THIS IS THE ANSWER......

Like? Yes (2) | No (2)  

Sundar Kumar   10 years AGO

Solution: The digits in each number are reversed and the number so formed is added to the original number.
17 + 71 = 88; 88 + 88 = 176; 176 + 671 = 847 and so on.
Similarly, 1595 + 5951 = 7546.

Like? Yes (2) | No (2)  

jagadeesh   10 years AGO

given number+reverse of that number
17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546

Like? Yes (2) | No (2)  

T.Aravinth kumar   10 years AGO

1595+5951=7546

Like? Yes (2) | No (2)  

srilakshmi   10 years AGO

17+71(reverse of 17) =88
88+88(reverse of 88) = 176
176+671(reverse of 176)=847
847+748(reverse of 847)=1595
1595+5951(reverse of 1595) = 7546

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

17+71=88
88+88=176
176+671=847

1595+5951=7546

Like? Yes (1) | No (2)  

Avishek Pattanaik   10 years AGO

Current no.+ Reverse of the current no = Next no.
17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546

Like? Yes (1) | No (2)  

Anupam Banerjee   10 years AGO

Here sum of each number and the number after reversing the order of its digits is equal to the next number.

Like, 17+71=88;
88+88=176;
176+671=847;
847+748=1595;
And so the next number is = 1595+5951 = 7546;

Like? Yes (1) | No (2)  

subramani   10 years AGO

17,88,176,847,1595....
from the above series...
add the first number with its reverse .like that for every number..
so
17+71=88
88+88=176
176+671=847
847+748=1595
so..after 1595
1595+5951=7546
option A is correct

Like? Yes (2) | No (3)  

P.Someshwar Reddy   10 years AGO

Adding the given number and reverse of number gives the next number in sequence. i.e.

17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546

so the next number in sequence is 7546, option(5)

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

Add the number with its digits reversed to get the next number
17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546

Like? Yes (1) | No (2)  

Bhagyashree Bhatt   10 years AGO

17+ rev of 17 ie 71 =88
88 + reverse ie 88 =176
176 + reverse ie 671 = 847
1595 + reverse ie 5951 = 7546

Like? Yes (1) | No (2)  

Ranjan Kumar   10 years AGO

Reverse the no and then ADD reversed no to original no..
17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546
will be ans

Like? Yes (2) | No (3)  

Komala.G   10 years AGO

Reverse the number in series and add as shown below
17+71 = 88
88+88 = 176
176+671 = 847
847+748 = 1595
1595+5951 = 7546

Like? Yes (1) | No (2)  

Rownaz Haque   10 years AGO

Reverse the number and add this reversed number to the actual number will give the next number.
17+71=88
88+88=176
176+671=847
847+748=1595
so,
1595+5951= 7546

Like? Yes (1) | No (2)  

Suraj   10 years AGO

sum of the number with its reversed version
17+71=88
88+88=176...
similarly
1595+5951=7546

Like? Yes (1) | No (2)  

Pranjali Das   10 years AGO

88-17=71(17 becomes 71 i.e., reversed)
176-88=88(88 becomes 88)
847-176=671(176 becomes 671)
1595-847=748(847 becomes 748)
similarly,
x-1595=5951(1595 will become 5951)
So by solving x=7546 (Option 5)

Like? Yes (1) | No (2)  

Balasaheb Rathod   10 years AGO

17+71=88, 88+88=176, 671+176=847, 748+847=1595, 5951+1595=7546

Like? Yes (1) | No (2)  

SREEVIDHYA P P   10 years AGO

17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546
So ans.is 7546.
Option 5

Like? Yes (1) | No (2)  

Ramsb   10 years AGO

17 + 71 = 88; 88 + 88 = 176; 176 + 671 = 847 and so on.
Similarly, 1595 + 5951 = 7546.

Like? Yes (1) | No (2)  

Keshav Kishlay   10 years AGO

17+71=88
88+88=176
176+671=847
847+748=1595
1595+5951=7546

Like? Yes (1) | No (2)  

16 May 2014 Coded language

If in coded language
MAN = AHB
YOU = GHGE
SAID = FHD
Then
SUM = ?

OPtion

1) FGH
2) GHAJ
3) HAG
4) EAHG
5) BEDG
6) FKA
7) EFAB
8) EBH
9) BCKF
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
MAN = 13*1*14 = 182 = AHB (According to positions of letters)
YOU = 25*15*21 = 7875 = GHGE
SAID = 19*1*9*4 = 684 = FHD
Similarly
SUM =19×21×13 =5187

Now 5187 = EAHG (According to positions of letters)

Option 4)

Correct Option: 4 Best Solution (9)

Dr.Dipin Singh   10 years AGO

MAN = AHB
13-1-14....13*1*14= 182... AHB
YOU = GHGE
25-15-21...25*15*21= 7875 ... GHGE
Similarly
SAID = FHD
Then
SUM = EAHG
19-21-13..19*21*13= 5187... EAHG

Like? Yes (11) | No   

azharshahid01@gmail.com   10 years AGO

MAN= 19*1*14= 182= AHB
YOU= 25*15*21= 7875= GHGE
SAID= 19*1*9*4= 684= FHD

Similarly,
SUM= 19*21*13= 5187= EAHG

Like? Yes (4) | No (2)  

Devendra Marghade   10 years AGO

Multiply the digits of a letter and result is represented as letter corresponding to digits.
MAN =13*1*14=182=AHB
YOU =25*15*21=7875=GHGE
SAID=18*1*9*4=648=FDH
SUM =19*21*13=5187=EAHG

Like? Yes (3) | No (2)  

Ann Theressa   10 years AGO

MAN ==> 13*1*14 = 182 ===> AHB
YOU ==> 25*15*21 = 7875 ===> GHGE
SAID ==> 19*1*9*4 = 684 ===> FHD
SUM ==> 19*21*13 = 5187 ===> EAHG

option 4)EAHG

Like? Yes (3) | No (3)  

Ranjan Kumar   10 years AGO

here letter nos are
M-13
A-1
N-14
13*1*14=182
i.e
1=A
8=h
2=B
same like that
S=19
U=21
M=13
(19*21*13)=5187
i.e
5=E
1=A
8=H
7=G
HENCE ANSWER IS 4 (EAHG)

Like? Yes (1) | No (3)  

Anupam Banerjee   10 years AGO

Let the letters(A to Z) represent the integers(1 to 26).
Like,
A=1,B=2,C=3,D=4,...............,W=23,X=24,Y=25,Z=26;

Here the coding technique used is,
Step 1:Change each of the letter into corresponding integers.
Step 2:Then multiply the integers.
Step 3:Every digit in the product is taken implicitly.
Step 4:Convert the digits into corresponding letter;
Like,
M A N = 13 1 14;
13*1*14=182;
1 8 2 = A H B;
So, MAN=AHB;

And hence, SUM = 19*21*13 = 5187 = EAHG;

Like? Yes (1) | No (3)  

sruthi   10 years AGO

FOR MAN

M=13
A=1
N=14

13*14*1=182

A=1
H=8
B=2

MAN=AHB

SIMILARLY,

S=19
U=21
M=13

19*21*13=5187

E =5
A=1
H=8
G=7

SUM=EAHG

Like? Yes (1) | No (4)  

rajani   10 years AGO

MAN=(13)(1)(14)=182=AHB
YOU=(25)(15)(21)=7875=GHGE
SAID=(19)(1)(9)(4)=684=FHD

In the Same Way,SUM=(19)(21)(13)=5187=EAHG

Like? Yes (1) | No (4)  

SREEVIDHYA P P   10 years AGO

A=1,B=2,.....Y=25,& Z=26
MAN=13*1*14=182=AHB
YOU=25*15*21=7875=GHGE
THEN SUM=19*21*13=5187=EAHG
ANSWER IS OPTION 4.

Like? Yes (1) | No (5)  

15 May 2014 Quadratic Equation

Solve
(x-1)(x-2)(3x-2)(3x+1) = 21

OPtion

1) (4+Sqrt 85)/6, (4-Sqrt 85)/6
2) (3+Sqrt 75)/6, (3-Sqrt 75)/6
3) (5+Sqrt 75)/6, (5-Sqrt 75)/6
4) (7+Sqrt 7)/6, (7-Sqrt 7)/6
5) (5+Sqrt 5)/6, (5-Sqrt 5)/6
6) (3+Sqrt 26)/6, (3-Sqrt 26)/6
7) (5+Sqrt 85)/6, (5-Sqrt 85)/6
8) (4+Sqrt 5)/6, (4-Sqrt 5)/6
9) (5+Sqrt 10)/6, (5-Sqrt 10)/6
10)None of these

Solution

Solve
Take 3 as common factor from last two factor to get
9(x-1)(x-2)(x- 2/3)(x+ 1/3) = 21
The sum of constant terms of first factor and third factor is same as the sum of the constant terms of second and fourth factor.
(3x^2-5x+2)(3x^2-5x-2) = 21
let 3x^2-5x = t
(t+2)(t-2) = 21
Solve

Answer is (5+Sqrt 85)/6, 5-Sqrt 85)/6

Option 7)

Correct Option: 7 Best Solution (17)

Dr.Dipin Singh   10 years AGO

(x-1)(x-2)(3x-2)(3x+1) = 21
(x-1)*(3x-2)(3x+1)*(x-2) = 21
(3x^2-5x+2)(3x^2-5x-2)=21
put 3x^2-5x=y
(y+2)*(y-2)=21
y^2=25
y= +-5
put y= 3x^2-5x=5
3x^2-5x-5=0
then
x= (5+Sqrt 85)/6, (5-Sqrt 85)/6 ... option 7

Like? Yes (17) | No (3)  

Ann Theressa   10 years AGO

(x-1)(x-2)(3x-2)(3x+1) = 21
(x-1)(3x-2)(x-2)(3x+1) = 21
(3x^2-5x+2)(3x^2-5x-2) = 21

put 3x^2 - 5x = y

(y+2)(y-2) = 21
y^2 - 4 = 21
y^2 = 25
y = (+-)5

3x^2 - 5x = 5
3x^2 - 5x -5 = 0

x = {5(+-)sqrt(25+60)}/6
=(5+Sqrt 85)/6, (5-Sqrt 85)/6

Like? Yes (12) | No (5)  

Dada Khalandar   10 years AGO

(x-1)(x-2)(3x-2)(3x+1) = 21

9x^4 - 30x^3 + 25x^2 - 4 = 21

9x^4 - 30x^3 + 25x^2 = 25

(3x^2 - 5x)^2 = 25

3x^2 - 5x - 5 = 0 or 3x^2 - 5x + 5 = 0

x = (5 ± √85) / 6 or x = (5 ± i√35) / 6

Like? Yes (7) | No (2)  

MD SOHAIL AKHTER   10 years AGO

(x-1)(x-2)(3x-2)(3x+1) = 21
(3x^2-5x+2)(3x^2-5x-2)= 21
(3x^2-5x)^2= 25
(3x^2-5x)^2-5^2=0
(3x^2-5x-5)(3x^2-5x+5)=0

on solving, we get
x=(5+Sqrt 85)/6, (5-Sqrt 85)/6

o option (7) is correct

Like? Yes (5) | No (3)  

Udhaya kumar   10 years AGO

(x-1)(3x-2)(x-2)(3x+1)=21
by solving 3x^2-5x-5=0
x=5+sqrt85/6

Like? Yes (4) | No (3)  

subasini matheswaran   10 years AGO

9x^4 - 30x^3 + 25x^2 - 4 = 21

9x^4 - 30x^3 + 25x^2 = 25

(3x^2 - 5x)^2 = 25

3x^2 - 5x - 5 = 0 or 3x^2 - 5x + 5 = 0

x = (5 - √85) / 6 , x = (5- srqt 85) / 6

Like? Yes (2) | No (1)  

Bhagyashree Bhatt   10 years AGO

first expand:
(x - 1)(x - 2)(3x - 2)(3x + 1) = 21
(x² - 3x + 2)(9x² - 3x - 2) = 21
(9x^4 - 3x³ - 2x²) + (-27x³ + 9x² + 6x) + (18x² - 6x - 4) = 21
9x^4 - 30x³ + 25x² + 0x - 4 = 21
take out common factor x² and move constant to RHS:
x²(9x² - 30x + 25) = 25
the bit in parentheses is a square:
x²(3x - 5)² = 25
take square root of both sides:
x(3x - 5) = 5
rearrange:
3x² - 5x - 5 = 0
sub these numbers into the equation to solve for roots of quadratic:
x = (-b ± sqrt(b² - 4ac))/(2a)
= (5 ± sqrt(25 - (4*3*-5))/(2*3)
= (5 ± sqrt(25 - (-60))/6
= (5 ± sqrt(85))/6

Like? Yes (2) | No (2)  

sanghavi    10 years AGO

9x^4-30x^3+25x^2=25
x^2(3x-5)^2=25
x(3x-5)=5
3x^2-5x-5=0
by solving this equation
we get option 7

Like? Yes (1) | No (2)  

AMIT SINGH   10 years AGO

(x-1)(3x-2)(x-2)(3x+1)=21
(3x^2-5x+2)(3x^2-5x-2)=7*3
on equating
3x^2-5x+2=7 and 3x^2-5x-2=3
we have,
3x^2-5x-5=0
hence, on solving
x=(5+sqrt85)/6,(5-sqrt85)/6.

Like? Yes (2) | No (3)  

sruthi   10 years AGO

7 th one is the answer

Like? Yes (1) | No (2)  

Sushma   10 years AGO

Regroup the factors.
put 3x^2-5x=y
solve new quadratic eqn to get y= +-5.
solve 3x^2-5x=y=5 to get the result.

Like? Yes (2) | No (3)  

srilakshmi   10 years AGO

(x-1)(x-2)(3x-2)(3x+1) = 21
(x-1)(3x-2)(x-2)(3x+1) = 21
(3x^2-5x+2)(3x^2-5x-2) = 21
let us assume 3x^2-5x = x
by solving the above we will get
3x^2-5x-5= 0
roots are
-b+(or)-Sqrt(b^2-4ac)/2a
(5+Sqrt 85)/6,(5-Sqrt 85)/6

Like? Yes (1) | No (3)  

T.Aravinth kumar   10 years AGO

Sub options in equation

Like? Yes (1) | No (3)  

deepak kumar   10 years AGO

normal calculation by quadratic equation.

Like? Yes (1) | No (3)  

rajani   10 years AGO

(x-1)(3x-2)(x-2)(3x+1)=21
->(3x^2-5x+2)(3x^2-5x-2)=21
let 3x^2-5x be 'a'
(a+2)(a-2)=21
a^2-4=21
->a^2=25
->a=+5 or -5
By taking the root as -5,
eq is 3x^2-5x=-5
on solving this we get (5+sqrt85)/6 and (5-sqrt 85)/6

Like? Yes (1) | No (4)  

Gitanjali K   10 years AGO

(x - 1)(x - 2)(3x - 2)(3x + 1) = 21
(x^2 - 3x + 2)(9x^2 - 3x - 2) = 21
9x^4 - 30x^3 + 25x^2 - 4 = 21
9x^4 - 30x^3 + 25x^2 = 25
x^2(9x^2 - 30x + 25) = 25
x^2(3x - 5)^2 = 25

take square root of both sides:
x(3x - 5) = 5
3x^2 - 5x - 5 = 0

solve quadratic equation using

x = (-b (+/-) sqrt(b^2 - 4ac))/(2a)
= (5 (+/-) sqrt(25 - (-60))/6
= (5 (+/-) sqrt(85))/6
therefore
x=(5+Sqrt 85)/6, x=(5-Sqrt 85)/6
so option (7) is the answer

Like? Yes (1) | No (4)  

Anupam Banerjee   10 years AGO

(x-1)(x-2)(3x-2)(3x+1)=21
or, (x-1)(3x-2)(x-2)(3x+1)=21
or, (3x^2 -5x +2)(3x^2 -5x -2)=21

Let, 3x^2-5x=z;
So, (z+2)(z-2)=21
or, z^2 - 4=21
or, z=5;

So, 3x^2 - 5x = 5
or, 3x^2 - 5x - 5=0
or, x=(5+Sqrt(25+60))/6,
x=(5-Sqrt(25+60))/6;

Like? Yes (1) | No (4)  

14 May 2014 Mathematical Operation

(16, 8, 36), (28, 11, 48), (12, 7, 32) are 3 set of integers according to some mathematical operations, a similar set based on the similar operations are

OPtion

1) (12, 6, 30)
2) (28, 7, 40)
3) (4, 5, 24)
4) (24, 8, 36)
5) (36, 13, 58)
6) (40, 14, 48)
7) (32, 10, 44)
8) (20, 10, 44)
9) (44, 16, 68)
10)None of these

Solution

Formula used to solve a set
(a, b, c) is b = [(a/4) + 4] and c = [b*4 + 4]

Only
(4, 5, 24)
b = (4/4 + 4) = 5
c = (5*4 + 4) = 24

Option 3)

Correct Option: 3 Best Solution (34)

Ann Theressa   10 years AGO

second number = first number/4 + 4
third number = first number + 20
or
third number = (second number+1)*4

(16,8,36)
===>16/4 + 4 = 8
===> 16+20 = 36
===>(8+1)*4 = 36

(28,11,48)
===>28/4 + 4 = 11
===> 28+20 = 48
===> (11+1)*4 = 48

(12,7,32)
===>12/4 + 4 = 7
===> 12+20 = 32
===> (7+1)*4 = 32

(4,5,24)
===>4/4 + 4 = 5
===> 4+20 = 24
===> (5+1)*4 = 24

Like? Yes (3) | No (2)  

sruthi   10 years AGO

(16,8,36) ,(28,11,48) , (12,7,32)
here
36-16=20
48-28=20
32-12=20
so (4,5,24) 24-4=20

Like? Yes (3) | No (2)  

PAWAN KUMAR   10 years AGO

16=4*4
8=4+4
36=4*(4+4+1)=4*8+1
Similarly others

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

diff bw fst & last numbers is 20.......

Like? Yes (3) | No (2)  

Pradeep   10 years AGO

Jst tak the 1st and 3rd numbers of each set.the dfrnc is 20.and also nw cnsider the middle one in each set multiply that number by 4 and add 4 to the resultant value which givs the third nmbr

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

4*4,4+4,4*(8+1)=(16,8,36)
4*7,4+7,4*(11+1)=(28,11,48)
4*3,4+3,4*(7+1)=(12,7,32)
Similarly..
4*1,4+1,4*(5+1)=(4,5,24)..
so option (3)

Like? Yes (1) | No   

paulprashanth   10 years AGO

(12-4,7-1,32-4)=(8,6,28)=(8-4,6-1,28-4)=(4,5,24)

Like? Yes (1) | No   

manish chauhan   10 years AGO

6 are same as 36 right side=6
8 are also same right of 48
similary in 12, 2 are also 32 rihght side and
8*4+4=36
11*4+4=48
7*4+4=32
similary 5*4+4=24 also 4 r both left and right of 24

Like? Yes (1) | No   

Dhananjay singh   10 years AGO

36-16=20
48-28=20
32-12=20
ans:3) 24-4=20

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

(16, 8, 36), (28, 11, 48), (12, 7, 32) are 3 set of integers according to some mathematical operations.
operation is given by
(4x 4+x 4((4+x+1))
(16, 8, 36)....... when x=4
(28, 11, 48)... when x=7
(12, 7, 32) ... when x=3
and
(4, 5, 24).. when x=1

Like? Yes (3) | No (3)  

Karan   10 years AGO

when difference of first and last term is 20.
only (4, 5, 24) satisfies this condition.

Like? Yes (2) | No (2)  

SHEREENA NISHAD   10 years AGO

(16 8 36) - 4*4 4+4 (8+1)*4
(28 11 48)- 7*4 7+4 (11+1)*4
(12 7 32) - 3*4 3+4 (7+1)*4
(4 5 24) - 1*4 1+4 (5+1)*4

Like? Yes (1) | No (1)  

sanghavi    10 years AGO

(4*4,4+4,4*9)=(16,8,36)
(4*7,4+7,4*12)=(28,11,48)
(4*3,4+3,4*8)=(12,7,32)
(4*1,4+1,4*6)=(4,5,24)

Like? Yes (1) | No (1)  

SHUBHAM KUMAR   10 years AGO

16,8,24=4*4,4+4*1,4*9
28,11,48=4*7,4+7*1,4*12
12,7,32=4*3,4+3*1,4*8
4,5,24=4*1,4+1*1,4*6

Like? Yes (1) | No (1)  

Varunraj Reddy   10 years AGO

Given sets are
(16,8,36),(28,11,48),(12,7,32)

These sets follows the operation
(4n-16, n ,4n+4)

So only option 3) satisfies this operation
ie.,(4,5,24)

Like? Yes (1) | No (1)  

Sundar Kumar   10 years AGO

answer : (4,5, 24)
because
(16,8,36)=> 30-12= 20
(28, 11, 48)=> 48-28=20
(12, 7, 32)=>32-12=20
similarly (4,5, 24)=>24-4 =20

Like? Yes (1) | No (1)  

Ankush Kumar   10 years AGO

Here i only found similarity :
Diff(16,36)=20
Diff(28,48)=20
Diff(12,32)=20
And from option only this one is fit-
Diff(4,24)=20

Like? Yes (1) | No (1)  

SREEVIDHYA P P   10 years AGO

consider first (16,8,36)
36-16=20
8*4=32+4=36
ie.,last no-first=20& (middle *4)+4 = last
similarly,second
48-28=20 & (11*4)+4=48
32-12=20 & (7*4)+4=32
24-4 =20 & (5*4)+4=24
therefore the answer is (4,5,24).
So option (3) is the answer

Like? Yes (1) | No (1)  

gaurav arora   10 years AGO

(8*4-16, 8, 8*4+4)
(11*4-16, 11, 11*4+4)
(7*4-16, 7, 7*4+4)

so option 3) is correct

(5*4-16, 5, 5*4+4)

Like? Yes (3) | No (3)  

Akhilesh   10 years AGO

series goes on as (4,5,24),(8,6,28),(12,7,32)i.e.(4+4x,5+x,24+4x)

Like? Yes (1) | No (1)  

Clair Christ D   10 years AGO

16,16/4+4=8,8*4+4=36
28,28/4+4=11,11*4+4=48
12,12/4+4=7,7*4+4=32
4,4/4+4=5,5*4+4=24(4,5,24)

Like? Yes (1) | No (1)  

Ranjan Kumar   10 years AGO

16+20=36,
28+20=48,
12+20=32,

in the same way only 4+20=24 means options no 3 only satisfying this conditions and this is the options.

Like? Yes (1) | No (1)  

subasini matheswaran   10 years AGO

28-16=12
11-8=3
48-36=12
28-12=12
11-7=4
48-32=12
so option 3

Like? Yes (1) | No (1)  

indrajeet yadav   10 years AGO

(16,8,36)->third term=8*4+4=36 and First term=36-20=16
(28,11,48)->third term=11*4+4=48 and First term=48-20=28
(12,7,32)->third term=7*4+4=32 and First term=32-20=12
similarly
(4,5,24)->third term=5*4+4=24 and first term=24-20=4

Like? Yes (1) | No (1)  

Anupam Banerjee   10 years AGO

The elements in each set are in a increment series.

Every next set is defined as,
1st element = 1st element of previous set + 4;
2nd element = 2nd element of previous set + 1;
3rd element = 3rd element of previous set + 4;

So, calculating back, the only option that satisfy the condition is the set (4,5,24);

The list can be,
(4,5,24)
(8,6,28)
(12,7,32)
(16,8,36)
(20,9,40)
(24,10,44)
(28,11,48)
(32,12,52) and so on..........

Like? Yes (1) | No (1)  

vishesh saxena   10 years AGO

4,5,(2+4=6)

Like? Yes (1) | No (1)  

Devendra Marghade   10 years AGO

If set contains integers(a,b,c) then,there is a difference of 20 in the sum of (a+b) & (b+c)
16+8=24 , 8+36=44,& 44-24=20
28+11=39 , 11+48=59, & 59-39=20
12+7=19, 7+32=39, & 39-19=20 similarly
4+5=9 , 5+24=29 & 29-9=20 ,
So option(3)

Like? Yes (1) | No (2)  

T.Aravinth kumar   10 years AGO

4+20=24.
(4,5,24)

Like? Yes (1) | No (2)  

DILEEP KUMAR   10 years AGO

the difference between The first number and third number in the set is 20.

Like? Yes (1) | No (2)  

AMRIT SHANKAR   10 years AGO

difference between 1st and 3rd integer is 20 so answer is option 3

Like? Yes (1) | No (2)  

Gitanjali K   10 years AGO

3rd number = 1st number + 20
so option (3) is the answer

Like? Yes (1) | No (2)  

vemula mounika   10 years AGO

the difference between first and last number is 20

Like? Yes (1) | No (2)  

Gokul Krishnan   10 years AGO

(4,5,24)=24-4=20

Like? Yes (1) | No (2)  

Mahalakshmi   10 years AGO

(4,5,24)=>4+20=24
(5+1)*4=24
so ans is option 3

Like? Yes (2) | No (4)  

13 May 2014 Solve

A man wished to give Rs. 12 to each person and found that he fell short of Rs. 6 when he wanted to give to all the person present. He therefore distributed Rs. 9 to each person and found that Rs. 9 was left over. How much money did he have and how many person were there?

OPtion

1) Rs. 64 and person = 7
2) Rs. 74 and person = 6
3) Rs. 68 and person = 3
4) Rs. 54 and person = 5
5) Rs. 54 and person = 2
6) Rs. 76 and person = 8
7) Rs. 74 and person = 9
8) Rs. 96 and person = 8
9) Rs. 54 and person = 1
10)None of these

Solution

Let man have x rupees with him and let the number of person by y, A man wishes to give Rs. 12 to each person and found that he fell short of Rs. 6
12y = x + 6 (i)
When he distributed Rs.9 to each person, he has left with Rs. 9 with him
9y = x - 9 (ii)
Solve
Rs. 54 and number of person 5
Option 4)

Correct Option: 4 Best Solution (62)

Dada Khalandar   10 years AGO

Let the number of persons be x and the total money be Rs y
Given when Rs 12 is given to each person he was short of Rs 6
Hence 12x − y = 6 → (1)
Also when Rs 9 is given to each person he is left with Rs 9
Hence y − 9x = 9 → (2)
Add (1) and (2), we get
3x = 15
∴ x = 5
Number of persons is 5
Put x = 5 in (1), we get 12(5) − y = 6
⇒ y = 60 − 6 = 54
Hence the money is Rs 54.

Like? Yes (28) | No (3)  

NAGENDRA P   10 years AGO

12X-6=9X+9...
Solving the above equation..
3X=15..
X=5..Therefore 5 persons..
12*5-6=54...
so option (4)..

Like? Yes (3) | No   

AMIT SINGH   10 years AGO

let no. of persons be \'x\'
then total sum of money,S=12*x-6-----(1)
and also,S= 9*x+9-----(2)
on solving both equations,
we get x(no. of persons)=5
and total sum of money,S=54

Like? Yes (3) | No (1)  

Hanish   10 years AGO

12*5=60-6=54
9*5=45+9=54

Like? Yes (4) | No (2)  

sanghavi    10 years AGO

9x+9=y
12X-6=y
x=5
y=54

Like? Yes (2) | No   

manish chauhan   10 years AGO

9*5=45 distribute 9 left 45+9=54
12*5=60 60-6=54 so 5 person 54 Rs.

Like? Yes (2) | No   

subasini matheswaran   10 years AGO

12*5=60
60-54=6
9*5=45
54-45=9
so option 4 is the answer

Like? Yes (2) | No   

PAWAN KUMAR   10 years AGO

solve using options

Like? Yes (2) | No (1)  

mohit srivastava   10 years AGO

when he decide Rs. 12 the 12*5=60 but Rs 54 he have so shortage of 6.
and when he decide Rs 9 then 9*5=45 he have Rs. 9 left

Like? Yes (1) | No   

sravanibatchu   10 years AGO

x-persons,y-total money
12*x-6=y
9*x+9=y
solving these x=5persons and y=54

Like? Yes (1) | No   

ANUP KUMAR   10 years AGO

LET, X = TOTAL AMOUNT AND Y = no.OF PERSON
Y = 12X - 6----(1)
Y = 9X + 9----(2)
SOLVING eq(1) AND eq(2),we get
x = 5
y = 54
Rs. 54 and person = 5

Like? Yes (5) | No (4)  

venkatesh   10 years AGO

Let us say there are X people.
Let the total amount be Rs.Y
Man tried to distribute certain amount among cetain number of people and found that he fell short of 6 rs. So if we consider the number of people to be X
the total amount man has is
Y=X*12-6--------[1]
Now man distributed 9 rs among X persons and found that he was left with 9 rs.
hence the total amount can be calculated as
Y=X*9+9---------[2]
equating [1] and [2]
we have Y=X*12-6=X*9+9
this gives
X=5(no of people)
and Y= Rs.54 (total amount with the man)

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

let x as number of persons
then by given 12x-6 = 9x+9
by solving this we get x=5
amount 12x-6 = 54.........

Like? Yes (3) | No (3)  

sakshi   10 years AGO

Let no of person is x
So 12x-6=9x+9
So x=5
Total money =9*5=45

Like? Yes (3) | No (3)  

Pradeep   10 years AGO

54rs and 5 persons he left 9rs , and he given each person 9rs so 9*5=45+9 (he left ) =54 and at first he wished to give 12rs but 6rs is less if he give 12rs to five persons 12*5=60 - 6rs less so answer is 54 and 5 persons

Like? Yes (2) | No (2)  

sivaraman   10 years AGO

The money he had must be a factor of both 12 and 9.if we check out the options we have only 54 that satisfies the condition. therfore the answer is option 4

Like? Yes (1) | No (1)  

Priya Dharshini   10 years AGO

because...12*5=60;
let us assume for 5 persons.
and amount is 54;
so there is shortage of 6;
and if 9 rs is shared between 5 persons then 9 rs will be left over;

Like? Yes (2) | No (2)  

Rahul Bhadana   10 years AGO

let the no of person is X and he has money Y

12X-Y = 6
(as distribute Rs 12 to X people and short with Rs 3)

9X - Y = -9

(distribute Rs 9 to X people and left with Rs 9)


subtract 2 from 1 this will give u

X = 5 (no of person)
put the value in first equation and we get

Y = 54 the money he had

Like? Yes (2) | No (2)  

azharshahid01@gmail.com   10 years AGO

Let no of Persons are x and total Rupees is y.
According to first distribution,
12*y-6 = x
According to second distribution,
9*y+9 = x
on solving x=5 and y=54.
option 4) Rs 54 and Person=5

Like? Yes (2) | No (3)  

T.Aravinth kumar   10 years AGO

12x-6
9x+9
X=5 & ans=54

Like? Yes (2) | No (3)  

Mukesh Nayal   10 years AGO

12x=total money-6
and 9x=total money+9
onsolving these equations
x=5 and totalmoney=54

Like? Yes (1) | No (2)  

indrajeet yadav   10 years AGO

let person=x
then 12x-6=9x+9
3x=15
x=5
person=5 and rupees=12*5-6=54

Like? Yes (1) | No (2)  

Gitanjali K   10 years AGO

let he had M money and no. of person's he wanted to give present are P
so, in first case he wanted to give 12Rs & came up with 6Rs shortage
12P-6=M
12P-M=6..eq(1)

and in 2nd case,he wanted to give 9Rs and had left with 9Rs
9P+9=M
9P-M=-9..eq(2)

solving eq (1) & (2)
we get P=5 & M=54 that means he had 54Rs & wanted to give present to 5 people

so When he tried to give 12Rs to 5 people he needed 60Rs & came up with 6Rs shortage
and,When he tried to distribute 9Rs to 5 people he used 45Rs and had left with 9Rs

so option (4) is the answer

Like? Yes (4) | No (5)  

SHEREENA NISHAD   10 years AGO

In both case total money will be same
let number of persons = n
First case
total money = (n-1)* 12+6
second case
total money = 9n + 9
(n-1)*12 +6 = 9n +9
3n = 15
n=5
total money = 54

Like? Yes (1) | No (2)  

ROHIT   10 years AGO

x= no of men
12x-6= 9x+9
x=5
12x-5=54

Like? Yes (1) | No (2)  

murari kumar   10 years AGO

Let no. Of persons= x
And amount of money =y
Therefore,
12*x=y+6,
9*x=y-9
After solving we get..x=5 and y=54

Like? Yes (1) | No (2)  

Rashmi bharti   10 years AGO

let person=x
12(x-1)+6=9x+9
x=5

Like? Yes (1) | No (2)  

steffy edmond   10 years AGO

Let X be the number of persons.Then,
12X-6=9X+9
3X=15
X=5
so substituting the value of X
12X-6=60-6= 54

Like? Yes (1) | No (2)  

vaijayanthi   10 years AGO

let the no of person be x and the total amount be y.
12x-6=y---(1)
9x+9=y----(2)
so we can write as 12x-y=6 and 9x-y=-9
solving the above 2 eq we get x=5(no.of persons) and y=54(total amount)

Like? Yes (1) | No (2)  

Sukanya   10 years AGO

12*5=60 -6 =54
9*5=45 +9 =54
hence 54 rs 5 persons

Like? Yes (1) | No (2)  

KALIA MUDULI   10 years AGO

Through Options:
if he pay 12 to each then
12*5=60 6(short)

and if he pay 9 to each then
9*5=45 which is 9 less then 54

so OP (4)

Like? Yes (1) | No (2)  

MD SOHAIL AKHTER   10 years AGO

let the total money be y
and tota no. of person be x
A/Q
12x-6=y............(1)
and 9x+9=y.........(2)
on solving eqn (1)&(2), we get;
x=5 and y=54
ans option (4)

Like? Yes (1) | No (2)  

istekhar hussain   10 years AGO

Let total man= x,
12x - 6 = 9x + 9,
Value will be x = 5

Like? Yes (1) | No (2)  

sonu sahoo   10 years AGO

he fell short by 6 rupees , it means if he has 18 rupee in hand then each one get equal amount. only 54 is completely divisible by 18. if there are 5 persons then only rs. 9 left over.

Like? Yes (1) | No (2)  

Leelanand Kumar Yalla   10 years AGO

12*x-6=9*x+9; by solving this we will get x=5; so amount is 54 and persons are 5....

Like? Yes (1) | No (2)  

SREEVIDHYA P P   10 years AGO

Check one by one the option
Rs.54 &no.of persons=5
First 12*5=60
He has only 54 rupees.ie.,60-54=6rupees short.
Next 9*5=45
Ie.,he gave Rs.9 to each 5 persons.Rs.45
Then remaining amt.is 9
So ans. Is Rs.54&5persons

Like? Yes (1) | No (2)  

Rohit Singh Panwar   10 years AGO

9x+9=12x-6
hence x=5

and money = 54

Like? Yes (1) | No (2)  

P.Someshwar Reddy   10 years AGO

By using options, it is easy to solve this puzzle.
By option 4, there are 5 persons and initially if everyone has to be given Rs.12 then he must have Rs.60, but he has Rs.54 so he fell short of Rs.6 and if everyone were given Rs.9 then he must have Rs.45, since he had Rs.54, he is left with Rs.9.

this will not happen to any other option hence the correct answer is option 4.

Like? Yes (1) | No (2)  

rajkumarreddy   10 years AGO

cross verfication
4 * 12 =48 + 6 =54
5 * 9 = 45 + 9 = 54

Like? Yes (1) | No (2)  

Keshav Kishlay   10 years AGO

let x is no of person and y is total money
then 12*x-6=y & 9*x+9=y
so,
x=5 & y=54

Like? Yes (1) | No (2)  

Arun Kumar Tiwari   10 years AGO

Let x be the total no. person.

therefore, 12x-6=9x+9
=> 3x=15
=> x=5

Now, total money= 9x+9
= 9X5+9
= 54

Thus, the answer is Rs. 54 and person = 5

Like? Yes (1) | No (2)  

Jinal Sanghvi   10 years AGO

12x=y-6
9x=y+9
Solve for x and y
X=5 and y=54

Like? Yes (1) | No (2)  

Deb Das   10 years AGO

Let 5 people were there,5*12=60
Short 6 Rs. So total amount,60-6=54
Now
5*9=45
and 45+9=54
so option 4.

Like? Yes (1) | No (2)  

vemula mounika   10 years AGO

12x-y=-6
9x-y=9
on solving these we get 4 th option

Like? Yes (1) | No (2)  

Anupam Banerjee   10 years AGO

Let no. of person=x;
So 1st case,
Total money = 12*(x-1)+6;

2nd case,
Total money = 9*x+9;

So,
12*(x-1)+6 = 9*x+9
or,12x-12+6 = 9x+9
or,3x = 15
or,x = 5;

So, number of person = 5;
Total money = (12*4)+6 = 54;

Like? Yes (1) | No (2)  

Sundar Kumar   10 years AGO

if we assume as 5 persons
if we give Rs.12 per each then 12*5=60
they said as Rs. 6 wil be shortage so total will be Rs. 54
if we give Rs.9 per head means then 9*5= 45 and remaining Rs.9 as said in question so total Rs. 54 and 5 members.

Like? Yes (1) | No (2)  

SHUBHAM KUMAR   10 years AGO

12x-6=9x+9, where x is the nuber of peoples
x=5
total money 12*5-6=54

Like? Yes (1) | No (2)  

DHIRENDRA    10 years AGO

Rs. 54 and person = 5
accordin to condition
12*5=60=60-6=54------condition true
9*45=45=45+9=54------condition true

Like? Yes (1) | No (2)  

Dundi   10 years AGO

12 x p - 6 = 9 x p + 9
by solving the above we will get number persons as 5....and amount will be 54

Like? Yes (1) | No (2)  

shibraj aditya   10 years AGO

the conditions given in the question goes with option 4 only. 5*12=60, 60-54=6. also 5*9=45, 54-45=9.

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

If number of person=x, then
12x-6=9x+9
x=5
Total money=12x-6 or 9x+9 =54

Like? Yes (1) | No (3)  

ravi prakash   10 years AGO

let person be X
then A/Q
9x + 9=12x - 6
15=3x
x=5
5 person is there
amount=12*5-6 = 54

Like? Yes (1) | No (3)  

rajani   10 years AGO

let no.of persons be x,
then 12(x)-6=9(x)+9
3x=15
x=5
so persons are 5
and the amount is 9(5)+5=54

Like? Yes (1) | No (3)  

srilakshmi   10 years AGO

by options
ans is 4.

(5*12) = 60 (54+6) -- 6rs short to 54
(5*9) = 45 (54 - 9) -- 9rs was left over to 45.

so ans is option 4.

Like? Yes (1) | No (3)  

Ann Theressa   10 years AGO

Let the number of persons he found be x

12x-6 = 9x+9
3x = 15
x = 5

Amount of money he had = 12x-6
=60 - 6
=Rs 54

Number of persons he found = x
=5

Like? Yes (1) | No (3)  

Sagar Jinachandran   10 years AGO

Let x be the number of persons
y be the amount in hand
12*x=y+6
12x-y=6-------(1)
9*x=y-9
9x-y=-9-------(2)
solving this we get
3x=15
x=5
putting this in equation 1
12*5-y=6
y=60-6
y=54
option 4

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

Let the money he have = x Rs.
Let the no.of persons = y
According to given conditions

12*y = x+6 ------(1)
9*y = x-9 ------(2)

By solving eq. (1) & (2)
we get y=5
Substitute y=5 in eq. (1)
We get x=54 Rs.

Ans is Option 4)

Like? Yes (2) | No (4)  

sruthi   10 years AGO

Rs. 54 and person =5

there are 5 persons if 9/- given for each
money will be equal to 45

54-45=9

left money is 9/-

so option 4 is the answer

Like? Yes (1) | No (3)  

ASHISH MITTAL   10 years AGO

12x-6=9x+9
x=5
and rupee will be
12*5-6=54
so option (4)

Like? Yes (1) | No (3)  

Bhagyashree Bhatt   10 years AGO

he had R, and the number of people he's giving money to N

In the first case he wanted to give out 12 and came up 6 short

12N = R + 6

In the 2nd case he wanted to give out 9 and had 9 left over

9N = R - 9

Turing this into R = 9N + 9 we can substitue this for R in the first equation to get

12N = 9N + 9 + 6
12N = 9N + 15
3N = 15
N = 5

Then using R = 9N + 9 we get

R = 9(5) + 9 = 45 + 9 = 54

When he tried to give 12 to 5 people he needed 60 and was 6 short
When he tried to get 9 to 5 people he only used 45 and had 9 left over.

Like? Yes (1) | No (3)  

AMIT   10 years AGO

Money he has=12*x-6...(i)
again Money he has=9x+9...(ii)
therefore by solving x=5
money he has=12*5-6=54
so option (4)

Like? Yes (1) | No (3)  

bithika das   10 years AGO

no of person=x
(12x-6)=(9x+9)
x=5
putting value of x
rs 54

Like? Yes (1) | No (3)  

12 May 2014 Sequence

What is the next number of the following sequence.
7, 13, 25, 49, 97, ....

OPtion

1) 108
2) 123
3) 136
4) 142
5) 154
6) 168
7) 173
8) 186
9) 193
10)None of these

Solution

(6+1), (6*2+1), (12*2+1), (24*2+1), (48*2+1), (96*2+1)
(6+1), (12+1), (24+1), (48+1), (96+1), (192+1 = 193)
Option 9)

Correct Option: 9 Best Solution (94)

gaurav arora   10 years AGO

7*2=14-1=13
13*2=26-1=25
25*2=50-1=49
49*2=98-1=97
so
97*2=194-1=193
so 193 is answer

Like? Yes (28) | No (7)  

MONIKA   10 years AGO

7+7-1=13
13+13-1=25
25+25-1=49
49+49-1=97
so,
97+97-1=193

Like? Yes (8) | No   

Rahul Bhadana   10 years AGO

1)7+(6*1) = 13

2)13+(6*2) = 25

3)25+(6*4) = 49

4)49+(6*8) = 96

5)96+(6*16) = 193

so ans is 193

Like? Yes (8) | No (3)  

MD SOHAIL AKHTER   10 years AGO

multiply the no. by 2 and subtract 1 from it
7*2-1=13
13*2-1=25
similarly
97*2-1=193

correct option (9)

Like? Yes (6) | No (2)  

Dada Khalandar   10 years AGO

(7*2)-1,=13
(13*2)-1=25
(25*2)-1=49
(49*2)-1=97
(97*2)-1=193

Like? Yes (4) | No   

sruthi   10 years AGO

7,13,25,49,97

7+7=14 then 14-1=13
13+13=26 then 26-1=25
so
similarly,
97+97=194
194-1=193
option 9 is the right answer

Like? Yes (3) | No   

vemula mounika   10 years AGO

7+6=13
13+12=25
25+24=49
49+48=97
97+96=193

Like? Yes (3) | No   

Devendra Marghade   10 years AGO

7+(6*1)=13
13+(6*2)=25
25+(6*4)=49
49+(6*8)=97
97+(6*16)=193

Like? Yes (2) | No   

T.Aravinth kumar   10 years AGO

97+96=193

Like? Yes (2) | No   

KALIA MUDULI   10 years AGO

7*2=14-1=13
13*2=26-1=25
.....
similarly
97*2=194-1=193

Op (9)

Like? Yes (4) | No (2)  

Pradeep   10 years AGO

193 as 7*2=14-1=13;13*2=26-1=25,25*2=50-1=49,49*2=98-1=97;97*2=194-1=193}

Like? Yes (2) | No   

sakshi   10 years AGO

97*2=194-1=193

Like? Yes (2) | No   

ANUP KUMAR   10 years AGO

7
7*2-1=13
13*2-1=25
similarly,
97*2-1=193
option (9)

Like? Yes (5) | No (3)  

sonu   10 years AGO

7+6=13
13+12=25
25+24=49
49+48=97
97+96=193

Like? Yes (2) | No   

RAKESH   10 years AGO

(2*97-1)=193

Like? Yes (2) | No   

rajani   10 years AGO

the next no.is double the current no.-1.
so,2(97)-1=193

Like? Yes (1) | No   

ravi prakash   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (2) | No (1)  

azharshahid01@gmail.com   10 years AGO

7
7+(7-1)=13
13+(13-1)=25
25+(25-1)=49
49+(49-1)=97
97+(97-1)=193

Like? Yes (2) | No (1)  

Varunraj Reddy   10 years AGO

Given sequence is
7,13,25,49,97,...

The pattern is like this
7,(7*2)-1,(13*2)-1,(25*2)-1,(49*2)-1,..

So the next no. in this sequence is
(97*2)-1=193

So answer is Option 9)

Like? Yes (2) | No (1)  

srilakshmi   10 years AGO

double the number and subtract 1 from that.

Like? Yes (1) | No   

gowtham   10 years AGO

7,7+7-1=13,13+13-1=25...97+97-1=193

Like? Yes (1) | No   

Gitanjali K   10 years AGO

add the same no. in given no. and subtract 1 from it's addition

7+7=14-1=13
13+13=26-1=25
25+25=50-1=49
49+49=98-1=97
97+97=194-1=193
so, option (9) is the answer

Like? Yes (1) | No   

Purosotam Gupta   10 years AGO

By the question
7*2=14-1=13
13*2=26-1=25
25*2=50-1=49
49*2=98-1=97
97*2=194-1=193

Like? Yes (1) | No   

Sundar Kumar   10 years AGO

7,7+6,13+12,25+24,49+48,97+96=193

Like? Yes (1) | No   

pushpanjali   10 years AGO

7*2-1=13
13*2-1=25
.
.
.
97*2-1=193

Like? Yes (1) | No   

ASHISH MITTAL   10 years AGO

Add 6*1,6*2,6*4,6*8 and so on

Like? Yes (1) | No   

ABHOY KUMAR   10 years AGO

7
7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

M NAGAMOUNICA   10 years AGO

7+6,13+12,25+24,49+48,
97+96

Like? Yes (1) | No   

Ashish Purohit   10 years AGO

the difference b/w number are, multiple of 2...like.....2,4,8,16.....therefore, 6*16=96....and we add 96 to last number 97.....the next series no. will be 193....:)

Like? Yes (1) | No   

Bhanu Pratap Singh   10 years AGO

97+96=193

Like? Yes (1) | No   

Pranjali Das   10 years AGO

The answer is 193 because :
7*2-1=13
again 13*2-1=25
again 25*2-1=49
again 49*2-1=97
So following this sequence the next number must be
97*2-1=193.

Like? Yes (1) | No   

indrajeet yadav   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

Rahul   10 years AGO

7+(7-1)=13
13+(13-1)=25
25+(25-1)=49
49+(49-1)=97
97+(97-1)=193

Like? Yes (1) | No   

BHAVANA MADHAVARAM   10 years AGO

97*2-1

Like? Yes (1) | No   

usha   10 years AGO

Let the number be x
13-7=6
25-13=12
49-25=48
So x-97=96
x=193

Like? Yes (1) | No   

Deepak Baran   10 years AGO

7
7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

Bhargav g   10 years AGO

7+6=13 for next number add 6*2=12
13+12=25 for next number add 12*2=24
25+24=49 for next number add 24*2=48
49+48=97 for next number add 48*2=96
97+96=193 this is the next number

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

7+6=13
13+6*2=25
25+6*4=49
49+6*8=97
97+6*16=193

Like? Yes (1) | No   

jitendra kumar   10 years AGO

number * 2-1 is the next number and process is continue

Like? Yes (1) | No   

Bhagyashree Bhatt   10 years AGO

7*2= 14 -1 = 13
13*2=26 -1 = 25
25*2=50 -1= 49
.
.
.
97*2=194-1=193

Like? Yes (1) | No   

kumar rishi   10 years AGO

7*2-1=13
13*2-1=25
........
97*2-1=193

Like? Yes (1) | No   

SREEVIDHYA P P   10 years AGO

7*2=14-1=13
13*2=26-1=25
25*2=50-1=49
49*2=98-1=97
97*2=194-1=193
the answer is 193.

Like? Yes (1) | No   

vicky kumar   10 years AGO

7+6=13
13+12=25
25+24=49
49+48=97
97+96=193

Like? Yes (1) | No   

Plabanee Panda   10 years AGO

3*2^1+1=7
3*2^2+1=13
3*2^3+1=25
3*2^4+1=49
3*2^5+1=97
3*2^6+1=193

Like? Yes (1) | No   

Rownaz Haque   10 years AGO

The series follows the condition for the next number in series:
next number=(present number*2) - 1
if present number= 7
next number= (7*2)- 1= 13
then the
next number= (13*2)- 1= 25
and so on

in the case when present number= 97
next number=(97*2)-1= 193....
So the answer is option 9) 193.

Like? Yes (1) | No   

anand singh   10 years AGO

7*2-1=13
13*2-1=25
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

ROHIT   10 years AGO

7+6=13
13+12=25...
97+96=193

Like? Yes (1) | No   

Praful   10 years AGO

7+6=13
13+12=25
25+24=49
49+48=97
97+96=193

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

difference between the nos. are twice of the previous difference. i.e 1st difference = 6
2nd difference between next two nos. = 12
3rd difference = 24,next 48, next will be 96
so the next number will be 193

Like? Yes (1) | No   

Aarush Singh   10 years AGO

This is following a pattern in which the difference between the nos. are twice of the previous difference.1st difference = 6
2nd difference between next two nos. = 12
3rd difference = 24,next 48, next will be 96
so the next number will be 193

Like? Yes (1) | No   

abhilasha   10 years AGO

Sequence is the difference between the nos. .the differnece is twice of the previous difference.1st difference = 6
2nd difference between next two nos. = 12
3rd difference = 24,next 48, next will be 96
so the next number will be 193

Like? Yes (1) | No   

rahul sharma   10 years AGO

double the previous number and minus 1(a+a-1, b+b-1)

Like? Yes (1) | No   

DINESH KUMAR   10 years AGO

7*2-1= 13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

So the answer is 193

Like? Yes (1) | No   

P.ARUNA   10 years AGO

7+6=13,13+12=25,25+24=49,49+48=97,97+96=193

Like? Yes (1) | No   

DHIRENDRA    10 years AGO

Doubble the no then subtract 1
7*2=14-1=13
13*2=26-1=25
25*2=50-1=49
49*2=98-1=97
97*2=194-1=193

Like? Yes (1) | No   

Ramakrishna   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
similarly 97*2-1=193

Like? Yes (1) | No   

Govind raj   10 years AGO

(number*2)-1...s0 97*2=194-1=193

Like? Yes (1) | No   

Gunasekaran M   10 years AGO

7 = 7*2-1 = 13
13 =13*2-1 = 25
similarly,
97 = 97*2-1 = 193

Like? Yes (1) | No   

Sukanya   10 years AGO

7
7+6
13+12
25+24
49+48
97+96=193

Like? Yes (1) | No   

mahesh   10 years AGO

13-7=6,25-13=12,49-25=24,97-49=48,193-97=96
here the result of diff is getting doubled

Like? Yes (1) | No   

SHUBHAM KUMAR   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

Deb Das   10 years AGO

7+6=13
13+12=25
25+24=49
48+49=97
97+96=193

Like? Yes (1) | No   

arjun   10 years AGO

difference is 6,12,24,48,96

Like? Yes (1) | No   

yashi bhardwaj   10 years AGO

the difference betwwen the numbers is getting double.

Like? Yes (1) | No   

saurav   10 years AGO

7+6=13
13+12=25
25+24=49
49+48=97
97+96=193
Each no is gettin added up with the double of that previous no

Like? Yes (1) | No   

steffy edmond   10 years AGO

Ans: 9)193
The given number sequence is 7, 13, 25, 49, 97, ....
It is Given in such a way that if x is the first number then the next number is x*2-1 and it goes on..so the next number in the sequence is 97*2-1= 193.

Like? Yes (2) | No (1)  

KIRAN KUMARI   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

Ganesh Hembram   10 years AGO

7 + 6 = 13
13 + 12 = 25
25 + 24 = 49
49 + 48 = 97
97 + 96 = 193

Like? Yes (1) | No   

sagar wagh   10 years AGO

because,
7+7=14 -1 =13
13+13=26 -1=25
& so on so ... 97+97=194 -1=193

Like? Yes (1) | No   

Sourangsu Bandyopadhyay   10 years AGO

13-7=6
25-13=12(6*2)
49-25=24(12*2)
97-49=48(24*2)
Hence the next number=97+(48*2)=97+96=193

Like? Yes (1) | No   

Ann Theressa   10 years AGO

7*2-1 = 13
13*2-1 = 25
25*2-1 = 49
49*2-1 = 97
97*2-1 = 193

Like? Yes (2) | No (1)  

M.hari Kishore Reddy   10 years AGO

4x2-1=7(8-1)
7x2-1=13(14-1)
13x2-1=25(26-1)
25x2-1=49(50-1)
49x2-1=97(96-1)
97x2-1=193(194-1)

Like? Yes (1) | No   

PIYUSH PAREEK   10 years AGO

All the subsequent no are one less than its previous square no.

Like? Yes (1) | No   

manish chauhan   10 years AGO

7*2=14-1
13*2=26-1
25*2=50-1
similary
97*2=194-1=193

Like? Yes (1) | No   

k.neharika   10 years AGO

between two numbers the series is like.6+6=12,12+12=24,24+24=48,48+48=96

Like? Yes (1) | No   

sanghavi    10 years AGO

7+6=13+12=25+24=49+48=97+96=193

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

7+7=14=14-1=13
13+13=26=26-1=25
25+25=50=50-1=49
49+49=98=98-1=97
97+97=194=194-1=193
so option (9)

Like? Yes (1) | No   

Rajasekhar Reddy   10 years AGO

97+(97-1) = 193

Like? Yes (1) | No   

AMIT SINGH   10 years AGO

7+ 6=13
13+12=25
25+24=49
49+48=97
therefore, the net no. is
97+96=193.

Like? Yes (1) | No   

bithika das   10 years AGO

7*2=14-1=13
similarly
97*2=194-1=193

Like? Yes (1) | No   

Keshav Kishlay   10 years AGO

97*2-1=193

Like? Yes (1) | No   

NIRUPOM GHOSH   10 years AGO

difference increasing 6,12,24,48,96.so answer is 193

Like? Yes (1) | No   

Anupam Banerjee   10 years AGO

1st no. = 7
2nd no. =(previous no * 2)-1 = (7*2)-1 = 13;
3rd no. = (13*2)-1 = 25;
4th no. = (25*2)-1 = 49;
5th no. = (49*2)-1 = 97;
So, 6th no. = (97*2)-1 = 193 (Ans.);

Like? Yes (1) | No   

Jaydev Dinda   10 years AGO

7*2-1=13;
13*2-1=25;
25*2-1=49;
.........;
97*2-1=193;
so the ans is 9)193

Like? Yes (1) | No   

Yekollu Muneeswar   10 years AGO

num=prev_num*2-1
hence,num=97*2-1
=193

Like? Yes (1) | No   

Priya Dharshini   10 years AGO

7..13..25..49..97
7*2=14-13=1;
14*2=28-25=3;
28*2=56-49=7;
56*2=112-97=15;
now see all the obtained results....
1...3...7...15

the difference between 1 and 3 is 2;
the difference between 3 and 7 is 4;
the difference between 7 and 15 is 8; so obviously,the next one is 16 ...therefore add 16+15=31;
112*2=224-31=19 which is the answer;

Like? Yes (1) | No   

Anvesh kumar   10 years AGO

multiply every no with 2 and substact with 1 inorder to generate next no

Like? Yes (1) | No   

NAYAN   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
so
97*2-1=193

Like? Yes (1) | No   

animesh bosu   10 years AGO

7, 7+(6), 13+(6*2),25+(12*2),49+(24*2), 97(24*3)

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

N+(N-1),,,,,,,,,
97+96=193

Like? Yes (1) | No   

Pallab Das   10 years AGO

7*2-1=13
13*2-1=25
25*2-1=49
49*2-1=97
97*2-1=193

Like? Yes (1) | No   

SriS   10 years AGO

double the number and subtract 1 one to get next number

Like? Yes (1) | No (1)  

Hemalatha   10 years AGO

96*2+1=193

Like? Yes (1) | No (1)  

C.Cheniappan   10 years AGO

7+13=20;
20+5=25;
20+25=45;
45+4=49;
etc.

Like? Yes (1) | No (1)  

09 May 2014 Coded language

If in code language
SEVEN = 455
FIVE = 210
THREE = 168
Then
EIGHT = ?

OPtion

1) 292
2) 490
3) 343
4) 372
5) 392
6) 492
7) 472
8) 376
9) 356
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
SEVEN = (19+5+22+5+14)*7 = 65*7 = 455
FIVE = (6+9+22+5)*5 = 42*5 = 210
THREE = (20+8+18+5+5)*3 = 56*3 = 168
Similarly
EIGHT = (5+9+7+8+20)*8 = 49*8 = 392

Option 5)

Correct Option: 5 Best Solution (28)

Dr.Dipin Singh   10 years AGO

Take numerical value of letters , add them and multiply with actual number.
SEVEN means (19+5+22+5+14)x7= 455
FIVE ---( 6+9+2+5)x5= 210
THREE = 168
Then
EIGHT----- (5+9+7+8+20)x8= 49x8=392

Like? Yes (9) | No (5)  

bhavitha   10 years AGO

seven=19+5+22+5+14=65*7=455
five=6+9+22+5=42*5=210
similarly
eight=5+9+7+8+20=49*8=392

Like? Yes (1) | No   

Pradeep   10 years AGO

a=1,b=2,c=3 ...... z=26 then seven {19+5+22+5+14= 65 ;; 65*7=455 ;; five = 6+9+22+5 =42; 42*5=210 ;; similarly 5+9+7+8+20=49*8=392

Like? Yes (1) | No   

SREEVIDHYA P P   10 years AGO

SEVEN-19+5+22+5+14=65 * 7=455
FIVE -6+9+22+5 =42 *5=210
THREE-20+8+18+5+5 =56 *3=168
EIGHT-5+9+7+8+20=49*8=392

Like? Yes (1) | No   

Rahul Bhadana   10 years AGO

SEVEN(7) * S(19)+E(5)+V(22)+E(5)+N(14) = 7*65 =455

FIVE(5) * F(6)+I(9)+V(22)+E(5) = 5*41 = 210

THREE(3) * T(20)+H(8)+R(18)+E(5)+E(5) = 3*56 = 168

then the solution is

EIGHT(8) * E(5)+I(9)+G(7)+H(8)+T(20) = 8*49 = 392

Like? Yes (5) | No (4)  

ANUP KUMAR   10 years AGO

S(19),E(5),V(22),E(5),N(14)
SEVEN=(19+5+22+5+14)*7=65*7=455

SIMILARLY,

E(5),I(9),G(7),H(8),T(20)
EIGHT=(5+9+7+8+20)*8=49*8=392
OPTION (5)

Like? Yes (6) | No (6)  

Grishma Shah   10 years AGO

The code is:
E=5
I=9
G=7
H=8
T=20
Add the no. 49
Multiplying with the no. Eight
Result 49*8=392

Like? Yes (5) | No (5)  

Ann Theressa   10 years AGO

SEVEN = (19+5+22+5+14)*7 = 455
FIVE = (6+9+22+5)*5 = 210
THREE = (20+8+18+5+5)*3 = 168

EIGHT = (5+9+7+8+20)*8 = 392
Sum of digits * number

option 5)392

Like? Yes (4) | No (5)  

Varunraj Reddy   10 years AGO

SEVEN=S+E+V+E+N=19+5+22+5+14=65
=>65*7=455

FIVE=F+I+V+E=6+9+22+5=42
=>42*5=210

THREE=T+H+R+E+E=20+8+18+5+5=56
=>56*3=168

EIGHT=E+I+G+H+T=5+9+7+8+20=49
=>49*8=392
Option 5)

Like? Yes (4) | No (5)  

Dimple   10 years AGO

SEVEN ... (19+5+22+5+14)*7= 455
FIVE ......( 6+9+2+5)*5= 210
Similarly
THREE = 168
Then
EIGHT.... (5+9+7+8+20)*8= 49*8=392 .. option 5

Like? Yes (3) | No (4)  

abhishek kumar   10 years AGO

sum of digits multiplied by the numerical value of digit..I mean ki sum of digit=49 n numerical value of digit=8,so 49*8=392

Like? Yes (2) | No (3)  

Udhaya kumar   10 years AGO

(E+I+G+H+T)*8 = 392.....

Like? Yes (3) | No (4)  

Bhagyashree Bhatt   10 years AGO

S + E + V + E + N = 65 *7 = 455

F + i + v + e = 42 *5 = 210
.
.
.
E + i + g + h + t = 49 * 8 =392

Like? Yes (3) | No (4)  

ASHISH MITTAL   10 years AGO

if A=1,B=2,C=3 AND SO ON
FOR SEVEN=(19+5+22+5+14)*7=455
SO FOR
EIGHT=(5+9+7+8+20)*8=392
SO OPTION (5)

Like? Yes (1) | No (3)  

Devendra Marghade   10 years AGO

Numbering A,B,C,D,.....as 1,2,3,4,...
numbers*Sum of the numbers corresponding to letters = Answer

SEVEN = 7*(19+5+22+5+14)=7*65=455
FIVE = 5*(6+9+22+5)=5*42 =210
THREE = 3*(20+8+18+5+5)=3*56 =168
EIGHT = 8*(5+9+7+8+20)= 8*49 =392

Like? Yes (1) | No (3)  

subramani   10 years AGO

A=1,B=2, ....Z=26
in SEVEN, S=19 E=5 V=22 E=5 N=14 so first add allthe numbers and multiply by 7 (SEVEN)from the words.
so SEVEN= (19+5+22+5+14)*7=455

like that for EIGHT= (5+9+7+8+20)*8 = 392.
Option 4 is correct.

Like? Yes (1) | No (3)  

MD SOHAIL AKHTER   10 years AGO

SEVEN= (19+5+22+5+14)*7=455
FIVE= (6+9+22+5)*5=210
SIMILARLY
EIGHT= (5+9+7+8+20)*8=392
OPTION (5) IS CORRECT

Like? Yes (2) | No (4)  

Gitanjali K   10 years AGO

SEVEN=19+5+22+5+14=65*7=455
FIVE=6+9+22+5=42*5=210
THREE=20+8+18+5+5=56*3=168
EIGHT=5+9+7+8+20=49*8=392
so option (5) is the answer

Like? Yes (1) | No (3)  

ravi prakash   10 years AGO

Sum all respective Digit and multiply eith respective no
SEVEN=19+5+22+5+14=65*7=455
Five=6+9+22+5=42*5=210
Similarly
EIGHT=5+9+7+8+20=49*8=392

Like? Yes (1) | No (3)  

Ramsb   10 years AGO

19+5+22+5+14=65, 455/7=65
6+9+22+5=42, 210/5=42
20+8+18+5+5=56, 168/3=56
same as
5+9+7+8+20=49,
by options
392/8=49

Like? Yes (1) | No (3)  

indrajeet yadav   10 years AGO

seven=(19+5+22+5+14)*7=455
five=(6+9+22+5)*5=210
simlarly
eight=(5+9+7+8+20)*8=392

Like? Yes (1) | No (3)  

ABHOY KUMAR   10 years AGO

SEVEN=445 ... (19+5+22+5+14)*7=445
FIVE=210 ...(6+9+22+5)*5=210
THREE=168 ...(20+8+18+5+5)*3=168
EIGHT=? ...(5+9+7+8+20)*8=392
option-5(392 is the answer)

Like? Yes (1) | No (3)  

RAKESH   10 years AGO

SEVEN = 455
(19+5+22+5+14)*7=455

FIVE = 210
(6+9+22+5)*5=210

EIGHT =
(5+9+7+8+20)*8=392

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Sukanya   10 years AGO

Consider the number position of alphabets.
SEVEN= 19+5+22+5+14=65 *7 =455
FIVE=6+9+22+5=42 *5 =210
THREE=20+8+18+5+5=56 *3 =168
Similarly EIGHT=5+9+7+8+20=49 *8 =392

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rajani   10 years AGO

Seven=(19+5+22+5+14)*7=455
five=(6+9+22+5)*5=210
three=(20+8+18+5+5)*3=168
in the same way,
eight=(5+9+7+8+20)*8=392

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Purosotam Gupta   10 years AGO

s(19),e(5),v(22),e(5),n(14)
add all value
19+5+22+5+14=65
divide
455/65=7
same as
eight
5+9+7+8+20=49
then
49*8=392

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murari kumar   10 years AGO

SEVEN=7×(19+5+22+5+14)=455
FIVE=5×(6+9+22+5)
THREE=3×(20+8+18+5+5)=168
Similarly..
EIGHT=8×(5+9+7+8+20)=392.
Therefore ans is 5(392)

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vemula mounika   10 years AGO

seven=19+5+22+5+14=65
=65*7=455
five=6+9+22+5=42
=42*5=210
three=20+8+18+5+5=
=56*3=168
then eight=5+9+7+8+20=49
49*8=392

Like? Yes (1) | No (5)