M4maths Previous Puzzles

24 Apr 2014 Linear equation

Find a fraction which become 1/2 when 1 is subtracted from the numerator and 2 is added to the denominator and the fraction becomes 1/3 when 7 is subtracted from the numerator and 2 from denominator.

OPtion

1) 7/15
2) 15/16
3) 7/16
4) 7/26
5) 15/26
6) 19/29
7) 15/19
8) 1/15
9) 1/16
10)None of these

Solution

Let fraction be x/y
according to the question
2x-y = 4 (1)
3x-y = 19 (2)

To solve equ (1) and equ (2),
x = 15
y = 26

Hence the fraction is 15/26
Option 5)

Correct Option: 5 Best Solution (61)

Ann Theressa   11 years AGO

Let the fraction be x/y

(x-1)/(y+2) = 1/2
2x - 2 = y + 2
2x - y = 4 ----(1)

(x-7)/(y-2) = 1/3
3x - 21 = y - 2
3x - y =19 -----(2)

(2) - (1)

x = 15
and y = 26

Like? Yes (22) | No (6)  

Roopa kamale   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2))=1/3
solve
x=15 & y=26
hence x/y=15/26

Like? Yes (5) | No   

Sonal Singh   11 years AGO

Let x be the numerator and y be the denominator. From statement 1:
(x-1)/(y+2)=1/2
From statement 2:
(x-7)/(y-2)=1/3

Solving both, we get.
x=15 ; y=26
Therefore, fraction = 15/26

Like? Yes (4) | No   

Grishma Shah   11 years AGO

Let numerator be x and denominator be y

From given
2x-y = 4....(1)
3x-y = 19...(2)

Subtracting (2) from (1)

x=15, putting x in (1)
y=26

Like? Yes (4) | No (1)  

indrajeet yadav   11 years AGO

let fraction=x/y
x-1/y+2=1/2
x-7/y-2=1/3
on solving both equation
x=15
y=26
so fraction=15/26

Like? Yes (3) | No   

shubham raghuvanshi   11 years AGO

supposing the fraction is x/y so by the first statement (x-1)/(y+2)=1/2 and by the second statement (x-7)/(y-2)=1/3 which forms two equations with two unknowns and gives x=15,y=26

Like? Yes (2) | No   

Shamik Maity   11 years AGO

x=(5*y-23)/2
x=denominator y=numerator
y given 1,7,15,19 only
1,7 are are too small to produce a denominator of 15(given minimum denominator)
y=15 gives x=26

Like? Yes (2) | No   

harshal agrawal   11 years AGO

let fraction be x/y
then, a/q
(x-1)/(y+2)=1/2
=> 2x-2=y+2
=> 2x-y=4 .... (1)
and (x-7)/(y-2)=1/3
=>3x-21=y-2
=>3x-y=19 .... (2)
solving (1) and (2)
x=15 y=26
hence fraction is 15/26

Like? Yes (4) | No (3)  

nirmal kumar saini   11 years AGO

let numerator is x and denominator is y
so according to first statement:-
x-1/y+2=1/2
and according to second statement:-
x-7/y-2=1/3
and by calculating both equations we get-
x=15 and y=26
so the fraction is 15/26

Like? Yes (2) | No (1)  

Aman   11 years AGO

if x/y is desired fraction, then
(x-2)/(y+2)=1/2
(x-7)/(y-2)= 1/3
solving, x/y = 15/26

Like? Yes (4) | No (3)  

Yekollu Muneeswar   11 years AGO

let the fraction be x/y
then(x-1)/(y+2)=1/2 --(1)
and (x-7)/(y-2)=1/3 --(2)

equation(1)implies, 2x-y=04
eq.(2) implies , 3x-y=19

therefore x=15 y=26.
Ans is 15/26

Like? Yes (3) | No (2)  

ABHOY KUMAR   11 years AGO

let the fraction be: n/d. acc. to ques,
(n-1)/(d+2)=12
=>2n-d=4 .............(i)
and (n-7)/(d-2)=1/3
=> 3n-d=19 .............(ii)
solving (i) & (ii) , we get-
n=15 and d=26
so, (n/d)=15/26

Like? Yes (2) | No (1)  

Abhishek Jha   11 years AGO

We suppose the fraction is x/y.
Now, as per the 1st condition, (x-1)/(y+2) = 1/2
=> 2x-2 = y+2 => 2x-y = 4 ......(1)
From the 2nd condition, (x-7)/(y-2) = 1/3
=>3x-21 = y-2 => 3x-y = 19 .......(2)

From (2)-(1), x = 15; From (1), y = 26.
Hence, x/y = 15/26. Option (5).

Like? Yes (2) | No (1)  

AMIT KUMAR   11 years AGO

let numerator = n
denominator = d
q/c,
(n - 1) / (d + 2) = 1/2
2*n - d = 4 ....................(1)
&, (n - 7) / (d - 2) = 1/3
=> 3*n - d = 19 ...................(2)
eq (1) - eq (2)
2*n - d = 4
3*n - d = 19
- + -
-----------------
-n = -15
n = 15
putting the value of n in eq.(1)
d = 26
fraction = n/d = 15/26
ans>>>>>>>>>>5)15/26

Like? Yes (2) | No (1)  

Ayesha khatoon   11 years AGO

x-1/y+2=1/2
x-7/y-2=1/3
by solving these two equation we get x=15 n y=26
so our required fraction will be 15/26

Like? Yes (2) | No (1)  

TUSHAR    11 years AGO

let x/y is fraction then (x-1)/(y+2)=0.5, (x-7)/(y-2)=1/3 then x=15, y=26

Like? Yes (2) | No (1)  

Sudipta Mukherjee   11 years AGO

Eq 1. let denominator= y and numerator=x
x-1/y+2=1/2
Eq. 2 . x-7/y-2=1/3.
solving this we get
x=15,y=26.
15/26

Like? Yes (2) | No (1)  

shree   11 years AGO

let numerator=x and denominator=y
if we will put given input we get two equation
2x-y=4-------------(1)
3x-y=19------------(2)
after solving these equation
we get x=15 and y=26
so the fraction is 15/26

Like? Yes (2) | No (1)  

Keshav Kishlay   11 years AGO

let us assume fraction is x/y
(x-1)/(y+2)=1/2;2x-y=4....(1)
(x-7)/(y-2)=1/3;3x-y=19.....(2)
so, after subtracting from 2 to 1 then
x=15;y=26
so, fraction will be 15/26

Like? Yes (2) | No (1)  

Varunraj Reddy   11 years AGO

By verification only option 5) satisfies both conditions.

Like? Yes (2) | No (1)  

Pankaj Kumar Verma   11 years AGO

Let the fraction is x/y.
by the equation(1)
2(x-1)=y+2 ..........(1)
and by second equation
3(x-7)=y-2 ........(2)
after solving both equts
x=15
and y=26
so, fraction is 15/26.

Like? Yes (2) | No (1)  

Y.Rony Singh   11 years AGO

Taking numerator as x n denominator as y we have given equation as
2x-2=y+2
3x-21=y-2
Solving we have x= 15 and y= 26

Like? Yes (2) | No (1)  

RAVI KANT   11 years AGO

x-1/y+2=1/2 and
x-7/y-2=1/3

Like? Yes (2) | No (1)  

sahithya   11 years AGO

Let nunerator be x and denominator be y
so (x-1)/(y+2)=1/2 by simplifying we get 2x-1=4
and (x-7)/(y-2)=1/3 by simplifying we get 3x-y=19
on solving above equations x=15 and y=26
so ans is 15/26

Like? Yes (2) | No (1)  

gaurav arora   11 years AGO

(15-1)/(26+2)=1/2 and (15-7)/(26-2)=1/3
so answer is 15/26

Like? Yes (2) | No (1)  

Leelanand Kumar Yalla   11 years AGO

3x-y-19=0---->(1);
2x-y-4=0------>(2);

By solving 1 and 2 we will get 15/26...

Like? Yes (2) | No (2)  

SriS   11 years AGO

Let the fraction be x/y
given x-1/y+2=1/2
x-7/y-2=1/3
by solving the equation we will get x=15 and y=26

Like? Yes (2) | No (2)  

sruthi   11 years AGO

let x/y be the fraction
so
x-1/y+2=1/2 equation 1
x-7/y-2=1/3 equation 2
from equation 1
2(x-1)=y+2
2x-2=y+2
2x-y=4
take equation 2
3(x-7)=y-2
3x-21=y-2
3x-y=19
fom these two equation find x and y
x=15 and y=26
so answer is 15/26
15-1/26+2=1/2
15-7/26-2=1/3

Like? Yes (2) | No (2)  

saikiran   11 years AGO

(x-1)/(y+2)=1/2 ---> 2x-y=4 -->eq1
(x-7)/(y-2)=1/3 ---> 3x-y=19 -->eq2
by solving eq1 and eq2
x/y=15/26

Like? Yes (3) | No (3)  

Gitanjali K   11 years AGO

let fraction be a/b
given, if 1 is subtracted from the numerator and 2 is added to the denominator fraction become 1/2
so, a-1/b+2=1/2
b+2=2a-2
2a-b=4 ...eq (1)

given, when 7 is subtracted from the numerator and 2 from denominator fraction become 1/3
so, a-7/b-2=1/3
b-2=3a-21
3a-b=19 ...eq(2)

therefore solving eq (1) and (2)
we get a=15 & b=26
therefore the fraction is 15/26

Like? Yes (2) | No (2)  

BHAVNISH BHUTANI   11 years AGO

from statement we can conclude
2x-y=4--(1)
3x-y=19--(2)
on solving 1 and 2 we get x=15 and y =26
so the fraction becomes 15/26

Like? Yes (2) | No (2)  

Tanvir Rahman   11 years AGO

Let the fraction is x/y.
Now from question
(x-1)/(y+2)=1/2 ---- 1
(x-7)/(y-2)=1/3 ---- 2

again,

2x-y=4 ---- 3
3x-y=19 ---- 4

by solving equation 3 and 4
x=15
y=26

So, the fraction is 15/26
ANS=option -- 5

Like? Yes (2) | No (2)  

Rashmi bharti   11 years AGO

let the fraction is x/y.
(x-1/y+2)=1/2----(i)
(x-7/y-2)=1/3-----(ii)
on solving,we get x=15,y=26.

Like? Yes (2) | No (2)  

shree   11 years AGO

5) 15/26 is answer

Like? Yes (2) | No (2)  

muni   11 years AGO

x-1/y+2=1/2----1
x-7/y-2=1/3-----2
solve 1 and 2
x/y=15/26

Like? Yes (2) | No (2)  

jagruti bhagwan salvi   11 years AGO

15/26=15-1/26+2=14/28=1/2
15/26=15-7/26-2=8/24=1/3

Like? Yes (2) | No (2)  

raj miglani   11 years AGO

X-1/y+2=1/2
2x-2=y+2
also,
x-7/y-2=1/3
3x-21=y-2
solving
x=15
y=26

Like? Yes (2) | No (2)  

Satish Zod   11 years AGO

Let the fraction is x/y
(x-1)/(y+2) = 1/2
(x-7)/(y-2) = 1/3

Solving this,
x/y = 15/26

Like? Yes (2) | No (2)  

Sundar Kumar   11 years AGO

take 15/26 in dat sub 1 from num nd add 2 to den then u vil get 1/2 as fraction dis s stated n d ques... similarly sub 7 from num nd 2 from dem u vil get 1/3 is also stated n ques... so 15/26 s d ans

Like? Yes (2) | No (2)  

RAKESH   11 years AGO

x-1/y+2 = 1/2

x-7/y-2 = 1/3

x=15, y=26

Like? Yes (1) | No (2)  

Udhaya kumar   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
by solving this we get
x=15
y=26

Like? Yes (2) | No (3)  

llamar   11 years AGO

assume that fraction is x/y111
(x-1)/(y+2)=(1/2)......(1)
(x-7)/(y-2)=(1/3).............(2)
solve above two equation
we get x=15,y=26

Like? Yes (1) | No (2)  

Purosotam Gupta   11 years AGO

Let, the fraction is x/y
then
by the question
1/2=(x-1)/(y+2)
y+2=2x-2
2x-y=4........equ(1)
again
by the question
1/3=(x-7)/(y-2)
y-2=3x-21
3x-y=19........equ(2)
from 1 and 2

x=15
y=26

Like? Yes (1) | No (2)  

goral   11 years AGO

x-1/y+2=1/2
so,2x-y=4........(1)
x-7/y-1=1/3
so,3x-y=19.......(2)
solving (1)-(2)
x=15
put value of x in (1) or(2)
get y=26
it means x/y=15/26

Like? Yes (2) | No (3)  

DILEEP KUMAR   11 years AGO

x-1/y+2 = 1/2
x-7/x-2 = 1/3
solving thesetwo.......
sol x/y=15/26

Like? Yes (2) | No (3)  

steffy edmond   11 years AGO

Ans:Option 5) 15/26
Let the numerator be 'x' and the denominator be'y'.
let the first equation be (x-1)/(y+2)=1/2
Solving,
2x-2=y+2
2x-4=y -->(1)
let the second equation be (x-7)/(y-2)=1/3
Solving,
3x-21=y-2
3x-19=y -->(2)
Equating (1) and (2),
2x-4=3x-19
x= 15
substituting value of x in equation (1),
2*15-4=y
30-4=y
y=26
therefore the fraction x/y =15/26

Like? Yes (1) | No (2)  

vishal gupta   11 years AGO

x-1/y+2=1/2
x-7/y-2=1/3
on solving both equation
x=15
y=26
so x/y=15/26

Like? Yes (1) | No (2)  

AJAY KUMAR   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
x=15,y=26
x/y=15/26

Like? Yes (1) | No (2)  

KALAIYARASI PADHMANABAN   11 years AGO

x-1/y+2=1/2 x-7/y-2=1/3
2x-2=y+2; 3x-21=y-2
2x-y=4 --->1 3x-y=19 --->2

solve (1)&(2)
x=15; y=26;

X/Y=15/26

Like? Yes (1) | No (2)  

Santosh Vishwakarma   11 years AGO

(x-1)/(y+2)=1/2 -------------(1)

(x-7)/(y-2)=1/3 --------------(2)

solve these.
x/y=15/26

Like? Yes (1) | No (2)  

Deepak Baran   11 years AGO

let required fraction be x/y
a/q
(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
after solving above equ..we get
x=15 and y=26
required fraction be 15/26

Like? Yes (1) | No (2)  

Devendra Marghade   11 years AGO

If 'x/y' is the fraction then
Ist case:(x-1)/(y+2)=1/2 ,2x-y=4 ---(i) &
2nd case:(x-7)/(y-2)=1/3,3x-y=19 ---(ii)
Solving (i)&(ii),we get x=15,y=26

Like? Yes (1) | No (3)  

KAUSTUBH BHARDWAJ   11 years AGO

let x=numerator and y=denominator
now from 1st condition
x-1/y+2=1/2;
from 2nd condition
x-7/y-2=1/3;
on solving by putting value of x from 1st eqn. to 2nd we can get,
x=15
and
y=26
s0 the fraction is x/y=15/26

Like? Yes (1) | No (3)  

Ghanshyam Gulati   11 years AGO

(x-1)/(y+2)=1/2
and
(x-7)/(y-2)=1/3

Like? Yes (1) | No (3)  

RANA MONDAL   11 years AGO

1st,
(x-1)/(y+2)=1/2
2nd,
(x-7)/(y-2)=1/3

x=15, y=26
Ans: 15/26

Like? Yes (1) | No (3)  

saisudha sarva   11 years AGO

(15-1)/(26-2)=1/2

Like? Yes (1) | No (3)  

NIRUPOM GHOSH   11 years AGO

1st eqn and 2nd eqn solve we get x/y=15/26.

Like? Yes (1) | No (3)  

ashish kumar   11 years AGO

jst by looking options....we can get it i.e: 15/26

Like? Yes (1) | No (3)  

ASHISH MITTAL   11 years AGO

(x-1)/(y+2)=1/2
(x-7)/(y-2)=1/3
after solving we get
x/y=15/26

Like? Yes (1) | No (3)  

SIBNATH HALDER   11 years AGO

by solved get 2 eqn
2X-Y=4 & 3X-Y=19
X/Y=15/26

Like? Yes (1) | No (3)  

abirami   11 years AGO

num is x/y
x-1=a and y+2=2a
become y+2=2(x-1)
eq 1: 2x-y=4
x-7=b and y-2=3b
become y-2=3(x-7)
eq 2:
3x-y=19

solve:

ans: x=15 and y=26
num is 15/26

Like? Yes (1) | No (3)  

23 Apr 2014 Solve

How many combinations are possible if 3 one rupee coin, 4 fifty paise coin and 2 twenty five paise coin are available. It is compulsory to select any one of the coin

OPtion

1) 23
2) 24
3) 59
4) 55
5) 60
6) 26
7) 12
8) 9
9) 6
10)None of these

Solution

Out of 3 one rupee coin, total possible combinations are
0 one rupee coin, 1 one rupee coin,
2 one rupee coin, 3 one rupee coin,
Out of 4 fifty paise coin, total possible combinations are
0 fifty paise coin, 1 fifty paise coin, 2 fifty paise coin, 3 fifty paise coin, 4 fifty paise coin,
Similarly out of 2 twenty five paise coin, total possible combinations are
0 twenty five paise coin, 1 twenty five paise coin, 2 twenty five paise coin,
Therefore total number of methods = 4*5*3 � 1= 60-1 = 59
(1 case is deducted because in a case no coin is selected)

Correct Option: 3 Best Solution (11)

Ann Theressa   11 years AGO

Number of ways in which atleast one object may be selected out of 'p' alike objects of one type and 'q' alike objects of second type and 'r' alike objects of 3rd type is,

(p+1)*(q+1)*(r+1)-1 = (2+1)*(3+1)*(4+1) - 1
=3*4*5 - 1
=60-1
=59

Like? Yes (6) | No (3)  

Pargat Pal Singh   11 years AGO

4*5*3-1=60-1=59 combinations

Like? Yes (4) | No (2)  

llamar   11 years AGO

4*3*2+4*3+4*2+3*2+4+3+2=24+12+8+6+9=59

Like? Yes (1) | No   

Aman   11 years AGO

Total possible combinations from
000 to 342 will be 4*5*3=60.
But 000 is not permitted as It is compulsory to select any one of the coin .
so possible combinations = 60-1=59

Like? Yes (3) | No (2)  

RAKESH   11 years AGO

(3+1)*(4+1)*(2+1)-1
=59

Like? Yes (2) | No (1)  

harshal agrawal   11 years AGO

(1,0,0),(1,0,1),(1,0,2)
(2,0,0),(2,0,1),(2,0,2)
(3,0,0),(3,0,1),(3,0,2) 9 cases
similarly with 1,2,3,4 coins from 50 pse, and 0,1,2 from 25 pse , (4*9) = 36 more cases
total becomes 45
now if 0 coin drawn from one ruppee,
i.e. 15 more caese. but (0,0,0) not allowed.
hence 45+14 = 59 cases.

Like? Yes (2) | No (2)  

Keshav Kishlay   11 years AGO

Total possible combinations = (3+1)*(4+1)*(2+1)=60
But It is compulsory to select any one of the coin.
so 0 one rupee coin, 0 fifty paise coin and 0 twenty five paise coin selection is not allowed.
so desired combinations = 60-1=59

Like? Yes (1) | No (1)  

shree   11 years AGO

Total possible combinations = (3+1)*(4+1)*(2+1)=60
But It is compulsory to select any one of the coin.
so 0 one rupee coin, 0 fifty paise coin and 0 twenty five paise coin selection is not allowed.
so desired combinations = 60-1=59

Like? Yes (1) | No (1)  

Pallab Das   11 years AGO

total possible combination = (3+1)*(4+1)*(2+1)=60
But It is compulsory to select any one of the coin

so 60-1=59

Like? Yes (1) | No (1)  

steffy edmond   11 years AGO

Number of ways in which atleast one object may be selected out of 'p' alike objects of one type and 'q' alike objects of second type and 'r' alike objects of 3rd type is,
(p+1)*(q+1)*(r+1)-1 = (2+1)*(3+1)*(4+1) - 1
= 3*4*5 - 1
= 60-1
= 59

Like? Yes (1) | No (2)  

RANA MONDAL   11 years AGO

total combination is...
=(4+3+2)+{(4*3)+(3*2)+(4*2)}+(4*3*2)
=9+26+24
=59

Like? Yes (1) | No (3)  

22 Apr 2014 Solve

What is the value of x for the following equation
(x^2-4)/(x-2) = 4

OPtion

1) 1
2) -1
3) 2
4) -2
5) 1/2
6) -1/2
7) 4
8) 1/4
9) -4
10)No solution

Solution

On solving the equation
(x^2-4)/(x-2)=4
(x+2)(x-2)/(x-2) = 4
x+2 = 4
x = 2
but this value does not satisfy the initial equation so can not be a solution

Correct Option: 10 Best Solution (8)

ANUP KUMAR   11 years AGO

(x^2-4)/(x-2) = 4---(1)
here,x-2 != 0
x!=2

after solving the eq-(1)
we get, x=2, but this is not possible
so, it has no solution

Like? Yes (4) | No (2)  

ankur panwar   11 years AGO

because at x=2,left side is undefinite

Like? Yes (4) | No (2)  

Ann Theressa   11 years AGO

(x^2-4)/(x-2) = 4
(x+2)(x-2)/(x-2)=4
x+2 = 4
x = 2

When x = 2 is substituted in the original equation, it causes a division by zero in the original equation. So x = 2 is an extraneous solution.

Since the only possible solution causes division by zero, this equation really has no solution.

Like? Yes (5) | No (4)  

harshal agrawal   11 years AGO

for L.H.S. domain of function (x^2-4)/(x-2), x can never equal to 2.
because denominator becomes 0 in that case.
now a/q,
=>(x-2)(x+2)/(x-2)=4
=>(x+2)=4
=>not possible
hence no solution

Like? Yes (4) | No (3)  

RAKESH   11 years AGO

(x^2-4)/(x-2) = 4
=> (x+2)*(x-2)/(x-2)= 4
=> (x+2) = 4 [ x is not equal to 2]
=> x = 2

No solution

Like? Yes (1) | No (3)  

vishesh saxena   11 years AGO

no soln, none of the values satisfy the eqn.

Like? Yes (1) | No (3)  

SriS   11 years AGO

by options

Like? Yes (1) | No (4)  

siva   11 years AGO

not a valid question

Like? Yes (1) | No (4)  

21 Apr 2014 Sequence

What is the next number of the following sequence
16,22,26,38,62,74,......

OPtion

1) 85
2) 102
3) 98
4) 132
5) 112
6) 96
7) 106
8) 118
9) 104
10)None of these

Solution

16
16+(1*6) = 16+6 = 22
22+(2*2) = 22+4 = 26
26+(2*6) = 26+12 = 38
38+(3*8) = 38+24 = 62
62+(6*2) = 62+12 = 74
Similarly
74+(7*4) = 74+28 = 102

Option 2)

Correct Option: 2 Best Solution (51)

azharshahid01@gmail.com   11 years AGO

16,
16+1*6=22
22+2*2=26
26+2*6=38
38+3*8=62
62+6*2=74
74+7*4=102.
Answer is 102.

Like? Yes (14) | No (8)  

ANUP KUMAR   11 years AGO

74=74+7*4=102

Like? Yes (8) | No (5)  

Akash Agarwal   11 years AGO

16+(1*6)=22
22+(2*2)=26
26+(2*6)=38

Like? Yes (4) | No (1)  

Aman   11 years AGO

Multiply digits of each number and add to number to get next number.

16, 1*6 = 6
next is 22,
2*2= 4 then its 26 and go on..
..
answer is
74+7*4=102

Like? Yes (9) | No (7)  

barisettyamulya   11 years AGO

1*6=6--->16+6=22
2*2=4--->22+4=26
2*6=12-->26+12=38
3*8=24-->38+24=72
6*2=12-->62+12=74
7*4=28-->74+28=102

Like? Yes (4) | No (2)  

Md Mahabub Alam   11 years AGO

16 + (1*6) = 22, 22 + (2*2) = 26
26 + (2*6) = 38, 38 + (3*8) = 62
62 + (6*2) = 74, 74 + (7*4) = 102

Like? Yes (3) | No (2)  

shree   11 years AGO

16 + (1*6) = 22
22 + (2*2) = 26
26 + (2*6) = 38
38 + (3*8) = 62
62 + (6*2) = 74
74 + (7*4) = 102

Like? Yes (3) | No (2)  

Dr.Dipin Singh   11 years AGO

16,22,26,38,62,74,......
1*6=6
16+6=22..2*2=4
22+4=26... 2*6=12
16+12=38
..
7*4=28 .... 74+28=102

Like? Yes (4) | No (4)  

Md Shahid Akhter   11 years AGO

16+1*6=22
22+2*2=26
26+2*6=38
38+3*8=62
62+6*2=74
74+7*4=102 (option 2)

Like? Yes (6) | No (6)  

llamar   11 years AGO

16,22,26,38,62,74,......
16+1*6=22,22+2*2=26,26+2*6=38,38+3*8=62,62+6*2=74
74+7*4=74+28=102

Like? Yes (2) | No (2)  

Naveen Kumar   11 years AGO

16
22=16+1*6
26=22+2*2
38=26+2*6
62=38+3*8
74=62+6*2
102=74+7*4

Like? Yes (4) | No (4)  

Clair Christ D   11 years AGO

74+7*4
=74+28
=102

Like? Yes (2) | No (2)  

ankur panwar   11 years AGO

first difference 6x1=6,, 16+6=22
2nd difference 2x2=4 ,, 22+4=26
3rd difference 2x6=12 26+12=38
like this 7x4=28
so 74+28=102

Like? Yes (6) | No (6)  

shivendra pratap singh   11 years AGO

1*6=6
16+6=22
22+4=26
26+12=38
38+24=62
62+12=74
74+28=102

Like? Yes (2) | No (2)  

suman kumar   11 years AGO

16+(1*6)=22
74+(7*4)=102

Like? Yes (2) | No (2)  

Bharat Bhushan Jha   11 years AGO

yty5 2

Like? Yes (2) | No (2)  

sudipta sadhukhan   11 years AGO

just multiply each no and then add with it you'ii get the next no

Like? Yes (2) | No (2)  

Pallab Das   11 years AGO

16+(6*1)=22+(2*2)=26+(2*6)=38+(3*8)=62+(6*2)=74+(4*7)=102

Like? Yes (2) | No (2)  

MP    11 years AGO

16,22,26,38,_,74. ...
22
26=22+2×2
38=26+2×6
62=38+3×8
74=62+6×2
74+7×4=102

Like? Yes (4) | No (5)  

Niraj   11 years AGO

16=16+1×6=16+6=22
22=22+2×2=22+4=26
26=26+2×6=26+12=38
38=38+3×8=38+24=62
62=62+6×2=62+12=74
74=74+7×4=74+28=102

Like? Yes (2) | No (3)  

harshal agrawal   11 years AGO

16+(1*6)=22
22+(2*2)=26
26+(2*6)=38
38+(3*8)=62
62+(6*2)=74
74+(7*4)=102
hence option 2) 102 is correct answer

Like? Yes (2) | No (3)  

Parshwa Shah   11 years AGO

7*4=28
74+28=102

Like? Yes (1) | No (2)  

saisudha sarva   11 years AGO

7*4=28
74+28=102

Like? Yes (1) | No (2)  

Keshav Kishlay   11 years AGO

f(n) = n + (the product of the nonzero digits of n).

Then, beginning with any positive integer, by iterating f we create an increasing sequence of integers. For example, with n=1, we have

1, 2, 4, 8, 16, 22, 26, 38, 62, 74, 102

Like? Yes (1) | No (2)  

Devendra Marghade   11 years AGO

Add the number with multiplication of its digit to get the next number
16+(1*6)=22
22+(2*2)=26
26+(2*6)=38
38+(3*8)=62
62+(6*2)=74
74+(7*4)102

Like? Yes (1) | No (3)  

RAKESH   11 years AGO

16+1*6=22
22+2*2=26
26+2*6=38
38+3*8=62
62+6*2=74
74+7*4=102

Like? Yes (3) | No (5)  

ChinnaChowdaiah   11 years AGO

16,
16+(1*6)=22
22+(2*2)=26
.
.
62+(6*2)=74
then the next number will be
74+(7*4)=102

Like? Yes (1) | No (3)  

VIVEK AGRAWAL   11 years AGO

(1*6)+6
(2*2)+22
(2*6)+26
(3*8)+38
(6*2)+62
(7*4)+74=102

Like? Yes (1) | No (3)  

srinivasan R   11 years AGO

Let n be a positive integer, written in base 10. Then define

f(n) = n + (the product of the nonzero digits of n).

Then, beginning with any positive integer, by iterating f we create an increasing sequence of integers. For example, with n=1, we have

1, 2, 4, 8, 16, 22, 26, 38, 62, 74, 102, 104, 108, 116, 122, 126, 138, 162, 174, 202, 206, 218, 234, 258, 338, 410, 414, 430, 442, 474, 586, 826, 922, 958, 1318, 1342, 1366, ...

For example, at 26 we add (2)(6)=12 to obtain 38; at 102 we ignore the 0 and add (1)(2).

Like? Yes (1) | No (3)  

Nitesh Joshi   11 years AGO

16,22,26,38,62,74,.....
here next no. = no.+ multiplication of their digits
16+(1*6)=22
22+(2*2)=26
26+(2*6)=38
38+(3*8)=62
62+(6*2)=74
74+(7*4)=102

Like? Yes (1) | No (3)  

SONU GUPTA   11 years AGO

16,
22=1*6+16,
26=22+2*2,
38=26+2*6,
62=38+3*8,
74=62+2*6,
102=74+7*4

Like? Yes (1) | No (3)  

Purosotam Gupta   11 years AGO

16+1*6=22
22+2*2=26
26+2*6=38
38+3*8=62
62+6*2=74
74+7*4=102

Like? Yes (1) | No (3)  

ASHISH MITTAL   11 years AGO

previous no+multiplication of digit
so 74+7*4=74+28=102
so option (2)

Like? Yes (1) | No (3)  

Sourish Barman   11 years AGO

16+(1*6)=22
22+(2*)2=26
26+(2*6)=38
38+(3*8)=62
62+(6*2)=74
74+(7*4)=102... Ansssss

Like? Yes (1) | No (3)  

srilakshmi   11 years AGO

16+(6*1)=22
22+(2*2)=26
26+(2*6)=38
.
.
.
74+(7*4)=102.
102 is answer.

Like? Yes (2) | No (4)  

SriS   11 years AGO

16,22,26,38,62,74...
16+6*1=22
22+2*2=26
26+2*6=38..
74+7*4=102

Like? Yes (1) | No (3)  

Gitanjali K   11 years AGO

just * digits in given no. and add in the same number,
like,
1*6=6 then 16+6=22 is the next no.

22+2*2=26
26+2*6=38
38+3*8=62
62+6*2=74
74+7*4=102
so ans is 102

Like? Yes (1) | No (3)  

lakshman   11 years AGO

16+1*6=22
22+2*2=26
.
.
74+7*4=102.

Like? Yes (1) | No (3)  

Chithra   11 years AGO

16+1*6=22
22+2*2=26
26+2*6=38
38+3*8=62
62+6*2=74
74+7*4=102

Like? Yes (1) | No (3)  

goral   11 years AGO

1*6+16=22
2*2+22=26
.
.
.
7*4+74=102

Like? Yes (1) | No (3)  

SAMPATH KUMAR   11 years AGO

16,22,26,38,62,74,102

(1*6)+16=6+16=22
(2*2)+22=4+22=26
(2*6)+26=12+26=38
(3*8)+38=24+38=62
(6*2)+62=12+62=74
(7*4)+74=28+74=102

so 102 is the next number

Like? Yes (1) | No (3)  

soumya   11 years AGO

16,22,26,38,62,74

the difference between the 2 no.s is the product of the numbers from first multiple.
like 16 + (6*1) = 22
22 + (2*2) = 26
26 + (2*6)= 38 and so on..

so 74 + (7*4) = 102

Like? Yes (1) | No (3)  

Avinash Aryan   11 years AGO

16,22,26,38,62,74
difference b/w two no is 6,4,12,24,12.
now 1*6=6
2*2=4
2*6=12
3*8=24
6*2=12
then
7*4=28
so 74+28=102.
2) is Right Option.

Like? Yes (1) | No (3)  

karthik hariharan   11 years AGO

just * each number and add,
1*6=6
so,16+6=22
2*2=4
so,22+4=26
similarly,
7*4=28
so,74+28=102
answer is 102

Like? Yes (1) | No (3)  

Santosh Vishwakarma   11 years AGO

add the multiplication of digit

Like? Yes (1) | No (3)  

vishesh saxena   11 years AGO

multiply digits of no. to each other and to itself, we get the next no. and so on.
i.e.
16=1*6=6 & 6+16=22,
22=2*2=4 & 4+22=26, and so on..

Like? Yes (1) | No (3)  

Krsihna Prasad   11 years AGO

7*4=28
74+28=102

Like? Yes (1) | No (3)  

MAHESH POLURI   11 years AGO

Logic multiply the each digit and add the digit
Sol:
1*6=6
16+6=22,
2*2=4,4+22=26
and so on
74=>7*4=28
28+74=102

Like? Yes (1) | No (3)  

NIRUPOM GHOSH   11 years AGO

22
26=22+2×2
38=26+2×6
62=38+3×8
74=62+6×2
102=74+7×4

Like? Yes (1) | No (3)  

susmit   11 years AGO

Multiply 2 digits of a number and then add to that number to get the next number.
1*6=6, 16+6 = 22
2*2=4, 22+4 = 26
2*6=12,26+12 = 38
So,
7*4 =28, 74+28 = 102
Hence,the next number will be 102(option no.2)

Like? Yes (1) | No (4)  

Subhash chandra pal   11 years AGO

Multiply digits and sum to the current term gives next term;

Like? Yes (1) | No (4)  

18 Apr 2014 Coded language

If in coded language
MAMTA = 8
SAUMYA = 80
MONIKA = 35
then
RASHMI = ?

OPtion

1) 16
2) 26
3) 42
4) 38
5) 14
6) 81
7) 39
8) 14
9) 27
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
MAMTA = (13)(1)(13)(20)(1) = 28-20 = 8 (Sum of Odd no - Sum of Even no)
SAUMYA = (19)(1)(21)(13)(25)(1) = 80-0 = 80
MONIKA = (13)(15)(14)(9)(11)(1) = 49-14 = 35
Similarly
RASHMI = (18)(1)(19)(8)(13)(9) = 42-26 = 16
Option 1)

Correct Option: 1 Best Solution (18)

Dr.Dipin Singh   11 years AGO

R-18
A-1
S-19
H-8
M-13
I-9

Sum of nos. Having odd values = 1+ 19 + 13 + 9=42
Sum of nos. Having even values = 18+8= 26
Their difference = 42-26= 16

Like? Yes (17) | No (7)  

llamar   11 years AGO

assign values to alphabets as follows
a=1,b=2......................z=26
MAMTA = 8
l.h.s=13,1,13,20,1(mamta)
=sum of odd values-sum of even values
=(13+1+13+1)-20
=28-20=8
like wise SAUMYA=19+1+21+13+25+1=80
MONIKA =(13+15+9+11+1)-14=35
RASHMI = (1+19+13+9)-(18+8)=16

Like? Yes (1) | No   

Karan   11 years AGO

RASHMI.... 18 1 19 8 13 9
(1+19+13+9)-(18+8)= 16

Like? Yes (6) | No (6)  

azharshahid01@gmail.com   11 years AGO

Subtract even from odd.
MAMTA = 13,1,13,20,1=> (13+1+13+1)-20= 8
SAUMYA= 19,1,21,13,25,1=> 80
MONIKA= 13,15,14,9,11,1=> (13+15+9+11+1)-14= 35
Similarly,
RASHMI= 18,1,19,8,13,9=>(1+19+13+9)-(18+8)=16
So, answer is 16.

Like? Yes (7) | No (9)  

Ann Theressa   11 years AGO

Put A=1,B=2...Z=26

ans = sum of odd numbers - sum of even numbers

MAMTA
(13+1+13+1)-20 = 8

SAUMYA
(19+1+21+13+25+1)-0 = 80

MONIKA
(13+15+9+11+1)-14 = 35

RASHMI
(1+19+13+9)-(18+8) = 16

Like? Yes (5) | No (8)  

B. SIREESHA   11 years AGO

a=1,b=2,....
MAMTA=13+1+13-20+1=8
SAUMYA=19+1+21+13+25+1=80
MONIKA=13+15-14+9+11+1=35
(difference between sum of all even nos and sum of all odd nos)
RASHMI=-18+1+19-8+13+9= 42-26=16

Like? Yes (3) | No (6)  

MD SOHAIL AKHTER   11 years AGO

A=1, B=2,C=3,....Z=26
Add all the even no. and odd no., then subtract the even no. from odd no.
MAMTA=(13+1+13+1)-20=8

similarly
RASHMI=(1+19+13+9)-(18+8)=16

Like? Yes (3) | No (7)  

ANUP KUMAR   11 years AGO

M(13),A(1),M(13),T(20),A(1)
(sum of odd no.)-(sum of even no.)
(13+1+13+1)-(20)=8 =MAMTA
S(19),A(1),U(21),M(13),Y(25),A(1)
(19+1+21+13+25+1)-(0)=80 =SAUMYA
M(13),O(15),N(14),I(9),K(11),A(1)
(13+15+9+11+1)-(14) = 35 =MONIKA
THEN
R(18),A(1),S(19),H(8),M(13),I(9)
(1+19+13+9)-(18+8)=16 = RASHMI

Like? Yes (2) | No (6)  

Varunraj Reddy   11 years AGO

Given MAMTA=8
(Sum of odd num characters)-(sum of even num characters)=(13+1+13+1)-(20)=8
Similarly
RASHMI=(1+19+13+9)-(18+8)=42-26=16

Like? Yes (2) | No (6)  

shree   11 years AGO

remain- 16

Like? Yes (2) | No (6)  

Naveen Kumar   11 years AGO

(sum of odd no. encountered)-(sum of
even no. encountered)

Like? Yes (3) | No (7)  

sruthi   11 years AGO

for M A M T A - add odd values and subtrat it from even number
13+1+13+1=28
28-20=8

for R A S H M I
1+19+13+9=42
42-18+8=16
16 IS THE ANSWER

Like? Yes (2) | No (6)  

Vinay Sipani    11 years AGO

Add all alphabets of odd number and subtract alphabets of even number.

MAMTA=> M+A+M-T+A = 8
MONIKA=> M+O-N+I+K+A = 35
RASHMI=> -R+A+S-H+M+I = 16

Like? Yes (1) | No (5)  

DILEEP KUMAR   11 years AGO

Let A=1,B=2,....Z=26 then
EXAMPLE:
M A M T A = 13 1 13 20 1
THEN FIND DIFFERENCE BETWEEN SUM OF ODD VALUE AND SUM OF EVEN VALUES
EX:
(13+13+1+1)-(20)=8
LIKE WISE
RASHMI= 18,1,19,8,13,9
ANS=(1+19+13+9)-(18+8) = 16

Like? Yes (1) | No (5)  

Santosh Vishwakarma   11 years AGO

ANS =(sum of odd positons-sum of even postons)

NOTE: Take A=1,B=2,........Z=26.

Like? Yes (1) | No (5)  

Surya Narayana K   11 years AGO

Coding as follows..

Result will be
(sum of the odd numbered alphabets) -(sum of the even numbered alphabets).

MAMTA=(13+1+13+1)-20=8
SAUMYA=19+1+21+13+25=80.
MONIKA=13+15-14+9+11+1=35
Similarly
RASHMI=-18+1+19-8+13+9=16

So ans is 16(Option 1)

Like? Yes (1) | No (5)  

Panchanand   11 years AGO

MAMTA 13 1 13 20 1 =(13+1+13+1-20= 8) (SUM OF ODD NUMBERS - SUM OF EVEN NUMBERS)
SAUMYA 19 1 21 13 25 1 = (19+1+21+13+25+1 = 80)
MONIKA 13 15 14 9 11 1 = (13+15+9+11+1-14 = 35)
RASHMI 18 1 19 8 13 9 = (1+19+13+9-18-8 = 16)

Like? Yes (1) | No (5)  

SHUBHAM KUMAR   11 years AGO

mamta=13+1+13+20+1=28-20=8
saumya=19+1+21+13+25+1=80-0=80
monika=13+15+14+9+11+1=49-14=35
rashmi=18+1+19+8+13+9=42-26=16

Like? Yes (2) | No (6)  

17 Apr 2014 Solve

If x^2 + y^2 + z^2 - xy - yz - zx < 0 then which one statement is correct.

OPtion

1) x = y = z
2) x > y > z
3) x < y < z
4) x ≠ y = z
5) x = y ≠ z
6) x ≠ y ≠ z
7) x, y, z have negative values
8) any one of x, y, z is negative
9) any two of x, y, z are negative
10) Not possible

Solution

x^2 + y^2 + z^2 � xy - yz � zx < 0
2x^2 + 2y^2 + 2z^2 � 2xy - 2yz � 2zx < 0
x^2 + y^2 - 2xy + y^2 + z^2 - 2yz + z^2 + x^2 - 2zx < 0
(x � y)^2 + (y � z)^2 + (z � x)^2 < 0
(x � y)^2 + (y � z)^2 + (z � x)^2 ,
This expression is the sum of three perfect square numbers and it is not possible to make this expression less than 0.

Option 10) Not possible

Correct Option: 10 Best Solution (17)

Dr.Dipin Singh   11 years AGO

(x-y)^2 + (y-z)^2 + (z-x)^2 >= 0
2 (x^2 + y^2 + z^2 - xy - yz - zx) >= 0
x^ + y^ + z^2 - xy - yz - zx >= 0

so x^2 + y^2 + z^2 - xy - yz - zx < 0
is not possible.

Like? Yes (4) | No (3)  

PAWAN KUMAR   11 years AGO

2*{x^2+y^2+z^2-xy-yz-zx}={(x-y)^2 +(y-z)^2 +(z-x)^2}
As RHS>0, SO, LHS must be >0.

Like? Yes (1) | No   

RAKESH   11 years AGO

x^2 + y^2 + z^2 - xy - yz - zx
= 1/2 *[(x-y)^2+(y-z)^2+(z-x)^2] always > 0

so, x^2 + y^2 + z^2 - xy - yz - zx < 0
is not possible.

Like? Yes (5) | No (5)  

MP    11 years AGO

(x-y)^2 + (y-z)^2 + (z-x)^2 >= 0
2 (x^2 + y^2 + z^2 - xy - yz - zx) >= 0
x^ + y^ + z^2 - xy - yz - zx >= 0

so x^2 + y^2 + z^2 - xy - yz - zx can never be less than zero.

Like? Yes (3) | No (4)  

Ann Theressa   11 years AGO

The equation,

(x - y)^2 + (x - z)^2 + (y - z)^2 >= 0

by virtue of being a sum of squares.
Expanding the equation,

2x^2 + 2y^2 + 2z^2 - 2xy - 2xz - 2yz >= 0.

x^2 + y^2 + z^2 >= xy + xz + yz

From the given equation,
x^2 + y^2 + z^2 - xy - yz - zx < 0
===>
x^2 + y^2 + z^2 < xy + yz + zx
which is not possible

Like? Yes (2) | No (4)  

V. Mohan   11 years AGO

not possible

Like? Yes (1) | No (3)  

Rashmi bharti   11 years AGO

it would be always a positive value.

Like? Yes (2) | No (4)  

shree   11 years AGO

10) it will be never negative.

Like? Yes (1) | No (3)  

Saranya   11 years AGO

on substituting the following conditions we are not getting

Like? Yes (1) | No (3)  

Niraj   11 years AGO

x^2 + y^2 + z^2 -xy - yz- zx < 0
=> 1/2{(x-y)^2 + (y-z)^2 + (z-x)^2 } < 0
=> (x-y)^2 + (y-z)^2 + (z-x)^2 < 0

Which is not possible

Like? Yes (1) | No (3)  

Pulkit Dureja   11 years AGO

by substituting a few eg.s such as 1,1,1 for x,y,z for equal no.
123 for x

Like? Yes (1) | No (4)  

sabyasachi dey   11 years AGO

no option can satisfy the equation so its not possible

Like? Yes (1) | No (4)  

SriS   11 years AGO

NotPossible

Like? Yes (1) | No (4)  

Sohini Neogi   11 years AGO

On Simplifying this
(x-y^2 + (y-z^2+(z–x)^2,
This expression is the sum of three perfect square numbers

Like? Yes (1) | No (4)  

Nitesh Joshi   11 years AGO

Because square term-relative multiplication term is always greater than 0.

Like? Yes (1) | No (4)  

gaurav arora   11 years AGO

this cant be possible

Like? Yes (1) | No (4)  

hanamant k   11 years AGO

none will follow the statement..
hence option 10) is answer

Like? Yes (1) | No (4)  

16 Apr 2014 Solve

8 men and 10 boys do a work in the same days as 4 men and 16 boys do. 1 man and 3 boys start a work to finish it in 40 days. After eighteen days, 9/20th part of the work had been finished. How many boys should be increased to make the work complete in exact time.

OPtion

1) 8
2) 7
3) 6
4) 5
5) 4
6) 3
7) 2
8) 1
9) 0
10) None of these

Solution

In 18 days, (9/20)th part of work is finished
Thus in 1 day, {9/(20*18)}th = 1/40th part of work is finished
Hence in 40 days, work will be complete.
No additional boys are required.

Correct Option: 9 Best Solution (14)

Dr.Dipin Singh   11 years AGO

8 men and 10 boys do a work in the same days as 4 men and 16 boys do. 1 man and 3 boys start a work to finish it in 40 days. After eighteen days, 9/20th part of the work had been finished.

1 man and 3 boys finish 9/20 work it in 18 days.
1 man and 3 boys finish 1 work it in 18*20/9=40 days.
so no additional boys/men are required.

Like? Yes (13) | No (2)  

MD SOHAIL AKHTER   11 years AGO

1 man and 3 boys start a work to finish the work in 40 days.
after 18 days they hv done 9/20th part of work
so 1-9/20=11/20th part of work is left
so they can do it in 22 days

so 0 days extra a boy requires.

Like? Yes (3) | No (1)  

ANUP KUMAR   11 years AGO

1 man and 3 boys start a work to finish the work in 40 days.
after 18 days they hv done 9/20th part of work
so 1-9/20=11/20th part of work is left
so they can do it in 22 days

so 0 days extra a boy requires.

Like? Yes (3) | No (1)  

TUSHAR    11 years AGO

8m+10b=4m+16b;
m=1.5b;
(1m+3b)*18=(9/20)W;
w=180b;
(1m+(3+x)*b)*22=(11/20)*w;
x=0

Like? Yes (3) | No (1)  

MP    11 years AGO

1 man and 3 boys start a work to finish it in 40 days. After eighteen days, 9/20th part of the work had been finished.
Balance 11/20 work will be completed by same workers in 22 days as 1/40 work is completed per day.
so additional zero boys are needed.

Like? Yes (3) | No (2)  

lakshman   11 years AGO

one day work by 1 men ad 3 boys will be=1\40
now in 18 days work is 1\40*18=9\20.
which is exactly the work done by 1 men and three boys.
therefore no need of increment in boys.
ans is zero

Like? Yes (2) | No (1)  

Meena   11 years AGO

As 9/20 work is completed in 18 days,
total work will be completed by same workers in 40 days.
0 boys should be increased.

Like? Yes (3) | No (2)  

Clair Christ D   11 years AGO

works needs to be finished in 40 days.
in 18 days 45 percent completed
so 5 percent works gets cmpleted in 2 days
so remaining 55 can be complted in 22 days with the same number of boys and men . so no extra addition required.

Like? Yes (1) | No   

susmit   11 years AGO

8x + 10y =4x + 16y
2x = 3y
x=3 units/day
y=2 units/day
1 man and 3 boys complete 18 ( 3 + 6 ) units in 18 days = 162 units
162 = 9/20 * total work
360 units = total work
work remaining = 198 units
So,
198 = 22 [ 3 + (3+k)2 ]
9 = 3 + 6 + 2k
k = 0
Hence, option no. 9

Like? Yes (1) | No   

Udhaya kumar   11 years AGO

by solving finally x+3 = 3
hence x=0........... where x = no of boys should increased..

Like? Yes (2) | No (1)  

Ann Theressa   11 years AGO

1 men and 3 boys can finish the work in 40 days

Their 1 day's work = 1/40
18 days work = 18/40 = 9/20

Given in 18 days 9/20th part of work had been finished.

===> 1 men and 3 boys can complete the work in 40 days.

Like? Yes (1) | No (1)  

ASHISH MITTAL   11 years AGO

8m+10b=4m+16b
4m=6b
1m=(3/2)
so 1m+3b=3/2+3=(9/2)b
and equation is
(9/2)*(18/22)*(11/20)*(20/9)=9/2
this is same no of boys who is initially working so no of boys required is=(9/2)-(9/2)=0
and option (9)

Like? Yes (1) | No (1)  

Rashmi bharti   11 years AGO

only 1 man and 3 boys can do the work in 40 days.

Like? Yes (1) | No (1)  

Nitesh Joshi   11 years AGO

since after 18 days finished work is = (9/20)th
therefore effeciency of per day is 9/(20*18)= 1/40
therefore no xtra boy should be required

Like? Yes (1) | No (2)  

15 Apr 2014 Quadratic equation

Solve
Sqrt(2x^2-2x+1)-2x+3 = 0

OPtion

1) 1, 4
2) 3, 4
3) 1
4) 1, 6
5) 4
6) 5, 6
7) 2, 3
8) 6
9) 6, 8
10)None of these

Solution

Take square to get
2x^2 - 2x + 1 = 4x^2 + 9 - 12x
solve
x = 1, and x = 4
Put x = 1
Sqrt(2-2+1)-2+3 (not=) 0
Hence x = 1 is not a solution
for x = 4
Sqrt(2*4^2-2*4+1)-8+3 = Sqrt(32-8+1)-5 = Sqrt(25) - 5 = 5 - 5 = 0
The only root is x = 4
Option 5)

Correct Option: 5 Best Solution (12)

Ann Theressa   11 years AGO

Sqrt(2x^2-2x+1)-2x+3 = 0

Sqrt(2x^2-2x+1) = 2x-3

Squaring both sides

2x^2-2x+1 = (2x-3)^2

2x^2-2x+1 = 4x^2 - 12x + 9

2x^2 - 10x + 8 = 0

x^2 - 5x + 4 = 0

(x-4)(x-1) = 0

x = 1,4

checking the answers
when x = 4

Sqrt(2x^2-2x+1)-2x+3 = sqrt (32-8+1)-8+3
=sqrt(25) - 5
=5-5 = 0

when x = 1

Sqrt(2x^2-2x+1)-2x+3 = sqrt (2-2+1)-2+3
=sqrt(1) +1
=1+1 = 2 (not equal to zero)

So x = 4 is the solution

Like? Yes (7) | No (4)  

Santosh Vishwakarma   11 years AGO

put the value.

Like? Yes (1) | No   

Charu jain   11 years AGO

Put options in the equation on putting 4 we can have equation like
5-8+3 =0

Like? Yes (1) | No   

Udhaya kumar   11 years AGO

1,4 will be find through given eqn.
bt 1 doesn't satisfy abv eqn...
hence 4 will be only answer........

Like? Yes (2) | No (1)  

S M ANIRUDH   11 years AGO

Verify the options

Like? Yes (1) | No   

RAKESH   11 years AGO

Sqrt(2x^2-2x+1)-2x+3 = 0
=> 2x^2-2x+1=(2x-3)^2
=> x^2-5x+4=0
=> x = 1,4
but x=1 doesn't satisfy given eqn

x=4 only

Like? Yes (1) | No (1)  

ASHISH MITTAL   11 years AGO

After solving we got x=1 and 4 but x=1 is not satisfying the condition so x=4 and option no (5)

Like? Yes (1) | No (1)  

Sudipta Mukherjee   11 years AGO

from the answer ...Only x-4 satisfy the equation...

Like? Yes (1) | No (1)  

arnold   11 years AGO

substitute option 5 in equation we get
LHS=RHS

Like? Yes (1) | No (1)  

Rahul Das   11 years AGO

just put the value x=4 you will get get answer coming =0

Like? Yes (1) | No (1)  

NIRUPOM GHOSH   11 years AGO

soln:sqrt(2x^2-2x+1)=2x-3
both sides squares then solve:(2x^2-2x+1)=(2x-3)^2
we get x=1,4 but x=1 not satisfy the eqn: sqrt(2x^2-2x+1)-2X+3=0 so x=4.

Like? Yes (1) | No (1)  

KAUSTUBH BHARDWAJ   11 years AGO

becz. only 4 is the solution of above eqn.by hit n trial method

Like? Yes (1) | No (2)  

14 Apr 2014 Sequence

What is the next number of the following sequence
59,73,83,94,107,115,121,123,.....

OPtion

1) 124
2) 125
3) 129
4) 127
5) 136
6) 149
7) 172
8) 189
9) 192
10)None of these

Solution

59
59 + (5+9) = 59+14 = 73 (No + sum of first and last digit)
73 + (7+3) = 73+10 = 83 (Similar)
83 + (8+3) = 83+11 = 94 (Similar)
94 + (9+4) = 94+13 = 107 (Similar)
107 + (1+7) = 107+8 = 115 (No + sum of first and last digit)
115 + (1+5) = 115+6 = 121 (Similar)
121 + (1+1) = 121+2 = 123 (Similar)
Similarly
123 + (1+3) = 127
Option 4)



Option 4)

Correct Option: 4 Best Solution (26)

ANUP KUMAR   11 years AGO

59+(1st+last digit)=59+(5+9)=73
73+(7+3)=83
83+(8+3)=94
94+(9+4)=107
107+(1+7)=115
similarly,
123+(1+3)=127

Like? Yes (8) | No (3)  

NAGENDRA P   11 years AGO

59+(5+9)=73..
73+(7+3)=83..
83+(8+3)=94..
94+(9+4)=107..
107+(01+07)115..
115+(1+5)=121..
121+(1+1)=123..
123+(1+3)=127..
so option (4)..

Like? Yes (2) | No   

RAKESH   11 years AGO

59,73,83,94,107,115,121,123,...

59+5+9=73
73+7+3=83
....
94+9+4=107
107+1+7=115
115+1+5=121
121+1+1=123
123+1+3=127

Like? Yes (4) | No (2)  

Bhawika Jethwani   11 years AGO

logic : add the sum of 1st and last digit of the previous number to number itself to get the next number.

59 : 5+9=14 , hence 59+14=73 (i.e. the next number)
73 : 7+3=10, hence 73+10=83 (i.e. the next number)
.
.
.
121 : 1+1=2, hence 121+2=123 (i.e. the next number)
similarly,
123 : 1+3=4, hence 123+4=127 (i.e. the next number)

Like? Yes (2) | No   

Santosh Vishwakarma   11 years AGO

just add the sum of first and last digits of privious number

Like? Yes (2) | No   

llamar   11 years AGO

add 1st and last number of each term to itself to get next number
i.e 59+5+9=73
73+7+3=83
83+8+3=94
94+9+4=107
107+1+7=115
115+1+5=121
121+1+1=123
123+1+3=127

Like? Yes (2) | No (1)  

Dr.Dipin Singh   11 years AGO

59,73,83,94,107,115,121,123,.....
59+5+9=73.... Add first and last digit to get next number.
73+7+3=83 .... Add first and last digit to get next number.

..
..
107+1+7=115.... Add first and last digit to get next number.

115+1+7= 123.... Add first and last digit to get next number.

123+1+3=127.... Add first and last digit to get next number.

Like? Yes (3) | No (2)  

Sourish Barman   11 years AGO

73+7+3=83
83+8+3=94

94+9+4=107
107+1+0+7=115
115+5+1(thousand digit)=121
121+1+1(thousand digit)=123
123+3+1=127

Like? Yes (2) | No (1)  

Roopali   11 years AGO

option 4 i.e 127 is correct answer.

Like? Yes (2) | No (1)  

Udhaya kumar   11 years AGO

add the sum of first & last digits of prev no & prev no..........

Like? Yes (3) | No (2)  

Pallab Das   11 years AGO

59=(9+5)i.e 14=59+14=73
73=(7+3)i.e 10=73+10=83
.
.
115=(1+5)i.e 6=115+6=121
.
123=(1+3)i.e 4=123+4=127

Like? Yes (2) | No (1)  

Soham Ghosh Hazra   11 years AGO

59+5+9=73
73+7+3=83
83+8+3=94
94+9+4=107
107+1+0+7=115
115+5+1(thousand digit)=121
121+1+1(thousand digit)=123
123+3+1=127

Like? Yes (2) | No (2)  

Pargat Pal Singh   11 years AGO

add 1st and last digit to the number and get next number.
123+1+3=127

Like? Yes (1) | No (1)  

Devendra Marghade   11 years AGO

Add the First & last digit of existing number to get next number
59+(5+9)=73
73+(7+3)=83
83+(8+3)=94
94+(9+4)=107
107+(1+7)=115
115+(1+5)=121
121+(1+1)=123
123+(1+3)=127

Like? Yes (3) | No (4)  

Naveen Kumar   11 years AGO

59
73=59+(5+9)
83=73+(7+3)
94=83+(8+3)
107=94+(9+4)
115=107+(1+7);taking the outer digits only
121=115+(1+5);taking the outer digits only
123=121+(1+1);taking the outer digits only
Now,
123+(1+3)=127;Ans

Like? Yes (4) | No (5)  

Ann Theressa   11 years AGO

Next number = previous number + sum of 1st and last digits of the previous number

59
59 + (5+9) = 59+14 = 73
73 + (7+3) = 73+10 = 83
83 + (8+3) = 83+11 = 94
94 + (9+4) = 94+13 = 107
107 + (1+7)= 107+8 = 115
115 + (1+5)= 115+6 = 121
121 + (1+1)= 121+2 = 123

123 + (1+3) = 123+4 = 127

Like? Yes (2) | No (3)  

Ankit Ranjan   11 years AGO

59 i.e 5+9=14, therefore the next term is 59+14 i.e 73 and so on till 94, and for three digit numbers add unit and 100th place numbers and add to the number to get the new number i.e,
for 107 the next term will be 107+(7+1)=115,115+5+1=121,121+1=1=123,123+3+1=127

Like? Yes (2) | No (3)  

vicky kumar   11 years AGO

In every no. add 1st and last digit and add this result to the no itself to get the next no.

5+9=14+59=74
1+7=8+107=115
1+1=2+121=123
1+3=4+123=127

Like? Yes (1) | No (3)  

MD SOHAIL AKHTER   11 years AGO

add the 1st + last digit with the prev digit
73=59+(5+9)

similarly
123+(1+3)=127

Like? Yes (1) | No (3)  

Md Shahid Akhter   11 years AGO

Take sum of 1st+last digit and add with the no. to get next no.
Ex.
59+(5+9)=73
Similarly,
107+(1+7)=115
123+(1+3)=127 is the answer

Like? Yes (1) | No (3)  

susmit   11 years AGO

Adding first and last digit to the number, we get the next number
59 + 5 + 9 = 73
73 + 7 + 3 = 83
So,
123 + 3+ 1 = 127

Like? Yes (1) | No (4)  

AJAY KUMAR   11 years AGO

5+9=14
59+14=73
......

123+(1+3)=127

Like? Yes (1) | No (4)  

Satish Zod   11 years AGO

Add sum of first and last digit of a number to get next number.

Like? Yes (1) | No (4)  

Ravi Vaghela   11 years AGO

5+9 =14 ==> 59 +14=73
likewise
and then
107 ==>1+7=8 ==> 107+8=115
likewise
123 ==>1+3=4 ==> 123+4=127

Like? Yes (1) | No (4)  

ASHISH MITTAL   11 years AGO

add corner digit of the no and the no to get next no,so number will be 123+1+3=127 i.e option (4)

Like? Yes (1) | No (4)  

shree   11 years AGO

123+4=127

Like? Yes (1) | No (5)  

11 Apr 2014 Coded language

If
1+2+3 = 24
7+2+8 = 216
5+8+10 = 594
then
6+7+8 =

OPtion

1) 720
2) 792
3) 864
4) 432
5) 385
6) 594
7) 504
8) 378
9) 693
10)None of these

Solution

In this question
1+2+3 = 2*3*4 = 24 (add 1 to every digit and multiply all of them)
7+2+8 = 8*3*9 = 216
5+8+10 = 6*9*11 = 594
Similarly
6+7+8 = 7*8*9 = 504

Option 7)

Correct Option: 7 Best Solution (10)

Dr.Dipin Singh   11 years AGO

increase the numbers by 1 and take the product to get required result.
1+2+3 = 24 as 2*3*4=24
hence
6+7+8=504 as 7*8*9=504

Like? Yes (20) | No (2)  

Dr. Divya   11 years AGO

7x8x9=504

Like? Yes (10) | No (1)  

MP    11 years AGO

1+2+3.. (1+1)(2+1)(3+1)..2*3*4 = 24
7+2+8 ..... 8*3*9= 216
5+8+10.... 6*9*11 = 594
then
6+7+8 = 7*8*9=504

Like? Yes (10) | No (3)  

Inder   11 years AGO

1+2+3 = 24
7+2+8 = 216
5+8+10 = 594
then
6+7+8 = 7*8*9=504

Like? Yes (8) | No (2)  

Ann Theressa   11 years AGO

1+2+3 = (1+1)*(2+1)*(3+1) = 24
7+2+8 = (7+1)*(2+1)*(8+1) = 216
5+8+10 = (5+1)*(8+1)*(10+1) = 594

6+7+8 = (6+1)*(7+1)*(8+1) = 504

Like? Yes (13) | No (12)  

vishnuvardhan   11 years AGO

2*3*4=24
8*3*9=216
6*9*11=594
7*8*9=504

Like? Yes (1) | No   

Santosh Vishwakarma   11 years AGO

multplcation of 1 incrimented terms.
2*3*4=24
8*3*9=216
6*9*11=594
similarly......
7*8*9=504

Like? Yes (1) | No   

azharshahid01@gmail.com   11 years AGO

1+2+3= 24
(1+1)*(2+1)*(3+1)= 24,
7+2+8=216
(7+1)*(2+1)*(8+1)=216,
5+8+10=594
(5+1)*(8+1)*(10+1)=594,
Similarly,
(6+1)*(7+1)*(8+1)=504.
Thus, answer is 7)504

Like? Yes (4) | No (4)  

Surya Narayana K   11 years AGO

Ans 504 (Option 7).

Add one every number and multiply them.

1+2+3=(1+1)(2+1)(3+1)=24
7+2+8=(7+1)(2+1)(8+1)=216
5+8+10=(5+1)(8+1)(10+1)=594

Similarly
6+7+8=(6+1)(7+1)(8+1)=7*8*9=504

Ans 504(Option 7)

Like? Yes (5) | No (6)  

SHEREENA NISHAD   11 years AGO

1+2+3 = 24 = 2*3*4
7+2+8 = 216 = 8*3*9
5+8+10 = 594 = 6*9*11
So
6+7+8 = 7*8*9 = 504

Like? Yes (3) | No (5)