M4maths Previous Puzzles

05 Jun 2014 Probability

There are 6 balls of same size, shape and colour. These balls has to be arranged in 6 boxes of same size, shape and colour. Total no. of possible methods are

OPtion

1) 8
2) 30
3) 12
4) 36
5) 144
6) 9
7) 11
8) 18
9) 60
10)None of these

Solution

Methods are (6,0,0,0,0,0), (5,1,0,0,0,0), (4,2,0,0,0,0), (4,1,1,0,0,0), (3,3,0,0,0,0), (3,2,1,0,0,0), (3,1,1,1,0,0),
(2,2,2,0,0,0), (2,2,1,1,0,0), (2,1,1,1,1,0), (1,1,1,1,1,1)

Option 7)

Correct Option: 7 Best Solution (3)

04 Jun 2014 Solve

A sheet has dimensions 80 cm.* 60 cm.* 1 mm. How many such sheets take a total volume of 0.4632 m3.

OPtion

1) 895
2) 985
3) 995
4) 975
5) 965
6) 885
7) 875
8) 865
9) 855
10)None of these

Solution

Volume of one sheet = length* width* thickness
= 80 cm.* 60 cm.* 0.1 cm.
= 480 cm.3
Total volume = 0.4632 m3
No. of sheets = 0.4632 m3/ 0.000480 m3
= 965

Correct Option: 5 Best Solution (41)

03 Jun 2014 Solve

How many numbers of two digits are divisible by 5.

OPtion

1) 8
2) 12
3) 15
4) 18
5) 20
6) 21
7) 22
8) 24
9) 19
10)None of these

Solution

10, 15, ...... 90, 95
Solve
Use AP
n = 18

Correct Option: 4 Best Solution (38)

02 Jun 2014 Sequence

What is the next number of the following sequence
1, 4, 11, 24, 47, 88, 163, .....

OPtion

1) 263
2) 279
3) 301
4) 208
5) 199
6) 258
7) 304
8) 274
9) 317
10)None of these

Solution

Differences of elements are the sum of two series
02, 04, 08, 16, 32, 64
01, 03, 05, 07, 09, 11

03, 07, 13, 23, 41, 75 Sum of these two series

Option 7)

Correct Option: 7 Best Solution (18)

31 May 2014 Solve

How many numbers of five digits can be formed by using 1, 2, 3, 4, 5, if 4 is necessarily taken at hundred's place and 2 is not allowed at unit's place. Repetition of numbers is not allowed.

OPtion

1) 72
2) 16
3) 12
4) 120
5) 96
6) 24
7) 60
8) 30
9) 18
10)None of these

Solution

4 is necessarily taken at hundred's place and 2 is not allowed at unit's place,
hence number of methods = 1*3*3*2*1 = 18
You can also check the answer by making different numbers under given conditions.

Option 9)

Correct Option: 9 Best Solution (7)

30 May 2014 Coded Language

If in coded language
MOHAN = 24
SALIM = 22
SURESH = 63
Then
YASHAR = ?

OPtion

1) 27
2) 32
3) 51
4) 54
5) 90
6) 29
7) 43
8) 36
9) 30
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
MOHAN = (M+O+H+A+N)-(M+N)
MOHAN = (13+15+8+1+14)-(13+14) = 51-27 = 24
SALIM = (19+1+12+9+13)-(19+13) = 54-32 = 22
SURESH = (19+21+18+5+19+8)-(19+8) = 90-27 = 63
Similarly
YASHAR = (25+1+19+8+1+18)-(25+18) = 72-43 = 29
Option 6)

Correct Option: 6 Best Solution (16)

28 May 2014 Solve

All 26 letters A B C D E F G H I J K L M N O P Q R S T U V W X Y Z in English alphabet are divided into 2 category
If one of the category contains A H M V Z ......etc
And other contains C G J O U ..........
Then which one of the following set contains all the letters of the same category

OPtion

1) E F G T
2) B C I Y
3) C G L T
4) D H M R
5) A K R X
6) A E I N
7) O P U Y
8) I L N R
9) B K W X
10)None of these

Solution

In this distribution all the letters having any curved part in it are taken in a category whereas letters
having no curved part are taken in other category
First category contains B C D G J O P Q R S U
Second category contains A E F H I K L M N T V W X Y Z

Option 6)

Correct Option: 6 Best Solution (2)

27 May 2014 Solve

Area of a field is 99 square meter. Convert it into square inch?
Given that 1 inch = 2.54 centimeter.

OPtion

1) 6387084
2) 0.0639
3) 2514600
4) 153450.3
5) 99
6) 638.7
7) 251.46
8) 1519.16
9) 15191580.38
10)None of these

Solution

Area = 99 sq. m.
= 99*100*100 sq. cm.
= 990000/(2.54*2.54)
Solve
Option 4)

Correct Option: 4 Best Solution (30)

26 May 2014 Sequence

What is the next number of the following sequence
17, 24, 32, 38, 62, 74, .......

OPtion

1) 86
2) 96
3) 102
4) 108
5) 116
6) 124
7) 136
8) 148
9) 150
10)None of these

Solution

17
17+ (1*7) = 17+7 = 24
24+(2*4) = 24+8 = 32
32+(3*2) = 32+6 = 38
38+(3*8) = 38+24 = 62
62+(6*2) = 62+12 = 74
Similarly
74+(7*4) = 74+28 = 102

Correct Option: 3 Best Solution (24)

23 May 2014 Coded language

If in coded language
AxyBzC = ZcbYaX
BbyCDw = YybXWd
Then
xvYBUz = ?

OPtion

1) caBYFe
2) ecBYFa
3) cfBYEa
4) ebCYFa
5) yeBCFa
6) ecBYDf
7) ceBYFa
8) caYBFe
9) eaFBYc
10)None of these

Solution

Rules for making these codes are
1. Capital letter should be capital.
2. Small letter should be small.
3. Letters are changed according to the sequence given below
a b c d e f g h i j k l m n o p q r s t u v w x y z
z y x w v u t s r q p o n m l k j i h g f e d c b a
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Z Y X W V U T S R Q P O N M L K J I H G F E D C B A

Option 7)

Correct Option: 7 Best Solution (17)