M4maths Previous Puzzles

03 Jul 2014 Solve

The cost (per Kg.) of mango and orange are between Rs 20 and 30. If total cost of 5 Kg mango and 7 Kg orange is a number X having unit's and hundred's place equal and sum of cost of 1 Kg mango and 1 Kg orange is Rs 50. Then the number X is

OPtion

1) 313
2) 282
3) 272
4) 333
5) 252
6) 292
7) 303
8) 323
9) 262
10)None of these

Solution

There are 9 possibilities
No. (Cost of mango/Kg.) (Cost of orange/Kg.)
1 21 29
2 22 28
3 23 27
4 24 26
5 25 25
6 26 24
7 27 23
8 28 22
9 29 21
Check the following cases.

Option 6)

Correct Option: 6 Best Solution (42)

mansi garg   10 years AGO

5x+5y=250
since rate of x+y=50
now range of 5x+7y can be 290-310
so 292 is answer coz 303 cant be answer coz its odd no

Like? Yes (9) | No (6)  

Varunraj Reddy   10 years AGO

29*5+21*7=292
All conditions are satisfied.
X=292

Ans:Option 6

Like? Yes (3) | No (2)  

Ravi Bhalani   10 years AGO

x+y=50
5x+7y=X
y=(X/2)-125
So,X=292 Only

Like? Yes (1) | No   

Vibhanshu Shukla   10 years AGO

5m+7o=x
m+o=50 (20-30)
o=(x-250)/2 (if x > 310 it give 30+ value )
(if x

Like? Yes (1) | No   

vinusha reddy   10 years AGO

given cost of 1kg mango+cost of 1kg orange=rs.50
then cost of mango and orange per kg is given in btn 20 to 30
let the cost of mango per kg be rs.29
cost of orange per kg be rs.21
then cost of 5kg mango=5*29=rs.145
cost of 7kg of orange=7*21=147
then total cost =145+147=Rs.292

Like? Yes (2) | No (1)  

Ravi Kumar Kodari   10 years AGO

1kg mango=29Rs. 1kg orange=21Rs.

5*29+7*21=292 answer.

Like? Yes (2) | No (1)  

Tark Patel   10 years AGO

Let,
1kg mango=x Rs.
1kg orange=y Rs.

Given,
x+y=50
5x+7y=X

Hence, x=175-(X/2) and y=(X/2)-125

so X must be even.

Then answer is 292.

Like? Yes (1) | No   

monika garg   10 years AGO

let mango per kg=M
let Oranget per kg=O
M+O=50
20

Like? Yes (2) | No (1)  

hitesh   10 years AGO

Cost of mango is 29&orange are 21

Like? Yes (2) | No (1)  

k sai krishna   10 years AGO

5 kg mango and 5 kg orange cost was 250
cost per kg >20 and less than 305 kg mango and 7 kg orange >290 and less than 310 check options 6 is correct

Like? Yes (1) | No   

munnu kumar   10 years AGO

5m+7o=xyx,o+m=50 >50+5m=250 so,2o=xyx-250it

Like? Yes (1) | No   

Mukesh Kumar   10 years AGO

the sum of cost of 5kg each = 250.and remaining 2kg of orange is double of (20 to 30) , means > 290 and less than 310. Since it is multiplied by 2 , so the result will be even. Ans is 292 . Having same digits 100th and unit place

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

let x as mango and y as orange..
then x+y=50
5x+7y=A
by substituting given answers 6th only satisfies all condition...

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

5*29+7*21=292

Like? Yes (1) | No   

Shanmugapriya   10 years AGO

1 kg mango + 1 kg orange = 50
5 kg mango + 7 kg orange = X
5 kg mango + 5 kg orange = 250
Per kg of mango and orange is between 20 and 30
min=40,max=60
so x can between 290 and 310

Like? Yes (1) | No   

sivakumari   10 years AGO

5 mango+7 kg orange=x
1kg mango+1kg orange=50
5 mango+5 orange+2 orange=x
5(1 mango+1 orange)+2 orange=x
5*50+2 orange=x
250+2*21=x
x=292 only possible orange value is 21

Like? Yes (1) | No   

PIYUSH ANAND   10 years AGO

let cost per kg of mango & orange be x &y respectively.
here,x+y=50
5x+7y=X
5(x+y)+2y=X
X=250+2y;
20

Like? Yes (1) | No   

suman kumar pan   10 years AGO

calculating the eqns the value of X is b/w the range of 290 to 310
So the answers are 292 & 303.
As the cost of mango & orange cannot be fraction for one kg so the best option is 292.

Like? Yes (1) | No   

shree   10 years AGO

292
29*5+21*7=292

Like? Yes (1) | No   

RANDHIR KUMAR   10 years AGO

satisfy the condn,x+y=50,5x+7y=292,

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

1kg mango (M)₹29
1kg Orange (O)₹21
5(M)+7(O)=292.
Position of one's and hundreds are equal.

Like? Yes (1) | No   

ABHIJEET PANDEY   10 years AGO

Ans.292..
21*7+29*5=292

Like? Yes (1) | No   

NAVNEET RAJ VAISH   10 years AGO

can be 292 as well as 303

let cost of mango be \'m\' and orange be \'o\'

m + o = 50
=> 5m + 5o= 250
but we have to find the total cost of 5m + 7o (5 mangoes and 7 oranges )
also, 20 < m,o < 30
=> 40< cost of two oanges 290 < 5m + 7o < 310
and both 292 and 303 satisfy this

Like? Yes (1) | No   

gowrisankart   10 years AGO

i am calculate as per take 21rs. and 29 rs.

Like? Yes (1) | No   

shahin raza   10 years AGO

5x+7y=X
x+y=50
on solving,2y=X-250 now luking at option only 292 satisfies condition which gives y=21 which iz between 20 to 30,no other option satisfies the conditon.

Like? Yes (1) | No   

kunchala kishore babu   10 years AGO

let cost of 1kg mangoes be 29 then for 5kg we have 5*29=145
and cost of 1kg oranges be 21 then for 7kg we have7*21=147
where x=5kg mangoes+7kgoranges=292
which hassame number at hundreds&units place

Like? Yes (1) | No   

RAKESH   10 years AGO

m+o=50
(m,o)=(21,29),(22,28),...,(29,21)

5m+7o=X = 1k1,2k2,3k3,...
5*21+7*29=
5*22+7*28=
5*23+7*27=
5*24+7*26=

5*29+7*21= 292

Like? Yes (1) | No (1)  

SUMIT   10 years AGO

check through options

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

ans-option 6)

Like? Yes (1) | No (1)  

amit baranga   10 years AGO

price of orange=21
price of mango=29

Like? Yes (1) | No (1)  

Yogesh   10 years AGO

there are 9 combinations are possibles
21-29,22-28,23-27,24-26,25-25,26-24,27-23,28-22,29-21
in all these combination
only 29-21 fulfill the combination.
29*5+21*7=292
other numbers didn't fulfill the condition.
so answer is 29.

Like? Yes (1) | No (1)  

RAKHI RAMTEKE   10 years AGO

Let per kg cost of mango=m
and per kg cost of orange=n
given, 5m+7n=X ....(1)
here X has unit's and hundered's place equal.
also, m+n=50...(2)
and 20

Like? Yes (1) | No (1)  

Debashis Dey   10 years AGO

There are 9 possibilities of price of mango and orange that is (21 29),(22 28),(23 27),(24 26),.....(29 21) and if we consider for (29 21) i.e. 29 per kg for mango & 21 per kg for orange then we get 29*5+21*7=292 hence option 6 is correct.

Like? Yes (1) | No (1)  

Anand Singh   10 years AGO

From options
option 6) full fill the conditions

Like? Yes (1) | No (1)  

Soham Dalwadi   10 years AGO

sum of cost of 1 Kg mango and 1 Kg orange is Rs 50

sum of cost of 5 Kg mango and 5 Kg orange is Rs 250

5kg mango + 5kg orange + 2kg orange = x

hence, 250 + 2kg orange = x
2kg orange = x - 250
1kg orange = (x-250)/2

by adjusting rates between 20 to 30, choose option

solving we get x = 292 orange = 21rs and mango 29rs

Like? Yes (1) | No (1)  

DAMARLA BALAJI   10 years AGO

1a+1b=50
5a+7b=x
5a+5b+2b=x
250+2b=x
since b value should be b/w 20 & 30 the values will be b/w 290-310
so b value should be 6 or 7 options 7 is not possible because 2b is not possible so the answer is 6
2b=2(21)
250+42=292

Like? Yes (1) | No (1)  

Devesh Agrawal   10 years AGO

a+b=50,
a=21,b=29
5a+7b=292=X

Like? Yes (1) | No (1)  

kapil singh   10 years AGO

the max value can go while takin cost 30 for oranges n 20 for mango i.e :310
hence ans wil b in 3 digit
make the combo of sum 50 btween 20 to 30
7*21+5*29=292

Like? Yes (1) | No (1)  

paaredi muthyam reddy   10 years AGO

use trial and error method for all combinations

Like? Yes (1) | No (1)  

RANJAN KUMAR PANDIT   10 years AGO

21 * 7 + 29 * 5 = 292

Like? Yes (1) | No (1)  

Dinesh kumar   10 years AGO

5m+7o=x------(1)
m+o=50-------(2)
assuming 5m+7o=292
m=50-o--------(3)
sub (3) in (1)
5(50-o)+7o=292
250-5o+7o=292
2o=42
o=21
sub o value in (3)
50-21=29=m
so ans is 292.......

Like? Yes (1) | No (1)  

AMIT SINGH   10 years AGO

cost of 1 kg mango=Rs 29
" " 5 " " =Rs 145
" " 1 "Orange=Rs 21
" " 5 " " =Rs 147

total cost=Rs(145+147)
=Rs 292.

Like? Yes (1) | No (2)  

02 Jul 2014 Solve

A car plate is written by taking 3 alphabets and 3 integers, if after 3 alphabets 3 zeros are not allowed, then total possible car plates with no code repeated are ?

OPtion

1) 11232000
2) 17576000
3) 17576
4) 17593576
5) 17558424
6) 14236560
7) 15600000
8) 17568424
9) 12812904
10)None of these

Solution

total alphabets are 26 hence total possibilities for taking 3 alphabets are 26*26*26 = 17576
Total integers are 10 hence total possibilities for taking 3 integers are
10*10*10 = 1000
Total number of avoided cases are 26*26*26*1*1*1 = 17576
Therefore answer is 17576 * 1000 - 17576 = 17558424

Option 5)

Correct Option: 5 Best Solution (8)

Ravi Kumar Kodari   10 years AGO

10^3*26^3-26^3
=17558424

Like? Yes (5) | No (1)  

RAKESH   10 years AGO

26*26*26*10*10*10 - 26*26*26*1
= 26^3 * 999
= 17558424

Like? Yes (5) | No (2)  

Ann Theressa   10 years AGO

out of 26 alphabets 3 are taken (26^3)
out of 10 numbers (0 to 9) 3 are taken (10^3)
after 3 alphabets 3 zeros are not allowed.
===> 26^3 out of total combinations is not allowed.

possible combinations = 26^3 * 10^3 - 26^3
= 17576000-17576
=17558424

option : 5

Like? Yes (4) | No (2)  

Ramesh Sriram   10 years AGO

10^3*26^3-26^3*1
=17558424

Like? Yes (3) | No (1)  

Udhaya kumar   10 years AGO

26^3*10^3 - 26^3 = 17558424

Like? Yes (3) | No (1)  

kapil singh   10 years AGO

3 alphabet = 26*26*26=17576
3 integer no. without(000)=999
so, no. of cars plate =17576*999=17558424

Like? Yes (2) | No (1)  

MRITUNJAY KUMAR   10 years AGO

26^3*10^3-(26^3)=17558424

Like? Yes (2) | No (1)  

kavya   10 years AGO

26 alphabets in 3 aggangements so (26)^3
10 integers in 3 (10)^3-1 since 000 case eliminated so both multiplied together gives 17558424

Like? Yes (1) | No   

01 Jul 2014 Solve

23 .... 8 .... 0.54 .... 2 .... 12 = 13.795
Fill all the blank spaces by mathematical operations

OPtion

1) + x / -
2) / + - x
3) - x / +
4) / x + -
5) - + x /
6) x / + -
7) - + / x
8) x / - +
9) / - x +
10)None of these

Solution

23 / 8 - 0.54 x 2 + 12 = 13.795

Option 9)

Correct Option: 9 Best Solution (46)

Sundar Kumar   10 years AGO

23 / 8 - 0.54 * 2 + 12 = 13.795

Like? Yes (17) | No (6)  

RAKESH   10 years AGO

23/8 ~ 3
.54*2 ~ 1
13.795 ~ 14

23 .... 8 .... 0.54 .... 2 .... 12 = 13.795
/ - x +

Like? Yes (5) | No (4)  

Priyanka   10 years AGO

according to BODMAS
1.Divide 23/8=2.875
2.Multiply -0.54*2=-1.08
3.Add 2.875+12=14.875
4.Subtract 14.875-1.08=13.795

Like? Yes (3) | No (2)  

Ravi Kumar Kodari   10 years AGO

23/8-.54*2+12
2.875-1.08+12=13.795

Like? Yes (2) | No (1)  

paaredi muthyam reddy   10 years AGO

23/8-.54*2+12
2.875-1.08+12=13.795

Like? Yes (2) | No (1)  

Ramesh Sriram   10 years AGO

23/8-.54*2+12
2.875-1.08+12=13.795

Like? Yes (2) | No (1)  

sravani   10 years AGO

23/8=2.875,
0.54*2=1.08,
2.875-1.08+12=13.795

Like? Yes (1) | No   

mansi garg   10 years AGO

23/8-0.54*2+12=13.75

Like? Yes (2) | No (1)  

Ravi Bhalani   10 years AGO

23/8-.54*2+12=13.795

Like? Yes (1) | No   

DAMARLA BALAJI   10 years AGO

23/8-0.54*2+12
=2.875-0.54*2+12
=2.875-1.08+12
=14.875-1.08
=13.795

Like? Yes (2) | No (1)  

bandaru sonia   10 years AGO

23/8-0.54*2+12=13.795

Like? Yes (1) | No   

Shanmugapriya   10 years AGO

By BODMAS rule,23/8-0.54*2+12
23/8=2.875
0.54*2=1.08
2.875-1.08=1.795+12=13.795

Like? Yes (1) | No   

Tark Patel   10 years AGO

(23/8)-(0.54*2)+12 = 13.795

Like? Yes (1) | No   

sivakumari   10 years AGO

23/8-0.54+12=13.795

Like? Yes (1) | No   

saloni daga    10 years AGO

23/8=2.875
(2.875)-(2*0.54)=1.795
12+1.795=13.795

Like? Yes (1) | No   

Ajith kumar   10 years AGO

23/8-0.54*2

Like? Yes (1) | No   

KODEISWARAN ELANGOVAN   10 years AGO

23/8-0.54*2+12

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

Check the question by 9 choices.

Like? Yes (1) | No   

Nilesh Choudhary   10 years AGO

23/8-0.54*2+12=13.795

Like? Yes (1) | No   

Anupam Banerjee   10 years AGO

23 / 8 - 0.54 * 2 + 12 = 13.795

Like? Yes (1) | No   

RANDHIR KUMAR   10 years AGO

bodmas rule

Like? Yes (1) | No   

Varunraj Reddy   10 years AGO

23 .... 8 .... 0.54 .... 2 .... 12 = 13.795

According to BODMAS rule
23/8-0.54*2+12=13.795

So answer is option 9)

Like? Yes (1) | No (1)  

amit baranga   10 years AGO

23/8-0.54x2+12= 13.795

Like? Yes (3) | No (3)  

Mohammed Farook.S   10 years AGO

23/8-0.54*2+12

Like? Yes (1) | No (1)  

RAKHI RAMTEKE   10 years AGO

bcuz...
(23/8)-(0.54*2)+12=13.795
i.e....option 9

Like? Yes (1) | No (1)  

guddu   10 years AGO

23/8-0.54*2+12=13.795

Like? Yes (1) | No (1)  

vinusha reddy   10 years AGO

23/8-0.54*2+12
according to BODMAS rule
23/8=2.875
2.875-(0.54*2)+12
2.875-1.08+12=14.875-1.08=13.795

Like? Yes (1) | No (1)  

Shashi nath jha   10 years AGO

=>23/8-0.54*2+12
=>2.875-0.54*2+12
=>2.875-1.08+12
=>1.795+12
=>13.795 ans.

Like? Yes (1) | No (1)  

naveenkumar   10 years AGO

23/8 -0.54* 2 + 12 = 13.795
2.875-0.54*2+12=13.795
2.875-1.08+12=13.795
1.795+12=13.795
13.795=13.795

Like? Yes (1) | No (1)  

kapil singh   10 years AGO

23/8=2.875
.54*2=1.08
2.875-1.08=1.795
12+1.795=13.795

Like? Yes (1) | No (1)  

suhana   10 years AGO

23/8=2.875;0.54*2=1.08.
2.875-1.08+12=13.795

Like? Yes (1) | No (1)  

Dinesh Arora   10 years AGO

23/8-0.54*2+12=13.795
acc to bodmas
(23/8)-(0.54*2)+12
2.875-1.08+12=13.795
13.795=13.795

Like? Yes (1) | No (1)  

Liti   10 years AGO

23/8-.54x2+12=13.795

Like? Yes (1) | No (1)  

ATTARU NASIMUNNI   10 years AGO

23/8= 2.875
0.54*2 = 1.08
2.875-1.08+12 = 13.795
23/8-0.54*2+12 = 13.795

Like? Yes (1) | No (1)  

mohd waseem   10 years AGO

(23/8)-(0.54*2)+12 = 2.875 - 1.08 + 12 = 13.795

Like? Yes (1) | No (1)  

Yogesh   10 years AGO

Using the bodmass rule of mathematics
23/8-0.54*2+12=13.795
23/8=2.875
0.54*2=1.08
2.875-1.08=1.795
1.795+12=13.795

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

by choosing from the option .
option -9.

Like? Yes (1) | No (1)  

PURIDI MOUNIKA   10 years AGO

23/8-0.54*2+12

Like? Yes (1) | No (1)  

Dipak Shaw   10 years AGO

23 / 8 - 0.54 x 2 + 12 = 13.795

Like? Yes (1) | No (1)  

Dinesh kumar   10 years AGO

23/8=2.875
0.54*2=1.08
2.875-1.08+12=13.975

Like? Yes (1) | No (1)  

G. SATYAVENI   10 years AGO

23/8-0.54*2+12=13.795
using bodmas rule

Like? Yes (1) | No (1)  

Aalvin   10 years AGO

23/8-0.54×2+12

Like? Yes (1) | No (1)  

Rohan Kumrawat   10 years AGO

23/8-0.54*2+12
BY BODMAS RULE:-
23/8=2.875
2.875-0.54*2+12
2.875-1.08+12
14.875-1.08
13.795

Like? Yes (1) | No (1)  

Dinesh thatti   10 years AGO

if we calculate by using 9th option we get answer

23/8-0.54*2+12=13.795

Like? Yes (1) | No (1)  

tadikamalla sukumar   10 years AGO

23/8-0.54*2+12 = 2.875-1.08+12
= 14.875-1.08
= 13.795

Like? Yes (1) | No (1)  

Alpana Kumari   10 years AGO

23/8-0.54*2+12= 2.875-1.08+12= 1.795+12= 13.795

Like? Yes (1) | No (1)  

30 Jun 2014 Sequence

What is the next number of the following sequence
1, 4, 13, 40,......

OPtion

1) 94
2) 64
3) 49
4) 56
5) 121
6) 157
7) 164
8) 136
9) 78
10)None of these

Solution

1
1+3 = 4
1+3+3^2 = 13
1+3+3^2+3^3 = 40
1+3+3^2+3^3+3^4 = 121

Option 5)

Correct Option: 5 Best Solution (105)

arti jaiswal   10 years AGO

1*3+1=4
4*3+1=13
13*3+1=40
40*3+1=121

Like? Yes (26) | No (8)  

Nikhill Jaynat Supekar   10 years AGO

1*3=3+(1)=4
4*3=12+(1)=13
13*3=39+(1)=40
so 40*3=120+(1)=121

Like? Yes (12) | No   

D.Sree Navya   10 years AGO

1,4,13,40..
Difference between the numbers is 3,3*3,9*3 then last 27*3=81 therefore 40+81=121

Like? Yes (13) | No (3)  

Sundar Kumar   10 years AGO

1+3^0=1 , 1+3^1=4 , 4+3^2=13 , 13+3^3=40 , 40+3^4= 121

Answer : option 5) 121

Like? Yes (15) | No (10)  

vinothkumar.R   10 years AGO

1+3=4
4+9=13
13+27=40
40+81=121

Like? Yes (10) | No (5)  

Sneha   10 years AGO

1 4 13 40 121
4-1=3=3
13-4=9=3*3
40-13=27=3*3*3
121-40=81=3*3*3*3

Like? Yes (6) | No (2)  

sharath chandra kumar   10 years AGO

121
because 40*3+1

Like? Yes (4) | No (2)  

Ankur Tamrakar   10 years AGO

Each term is added with powers of 3.
So 40+(3^4)=121. So 5)120 is the answer.

Like? Yes (4) | No (2)  

NIRUPOM GHOSH   10 years AGO

3^4(next no is 40+81=121)

Like? Yes (2) | No   

Anand Singh   10 years AGO

1
1+3=4
4+3^2=13
13+3^3=40
40+3^4=121

Like? Yes (1) | No   

Liti   10 years AGO

1*3+1
4*12+1
13*3+1
40*3+1=121

Like? Yes (2) | No (1)  

Rasika Sangle   10 years AGO

difference 3,9,27,81

Like? Yes (1) | No   

Devesh Agrawal   10 years AGO

difference between the consecutive numbers is 3,9,27,... So, next difference should be 81. Hence, next number will be 40+81 = 121.

Like? Yes (1) | No   

Vamsi   10 years AGO

4-1 = 3 = 3^1
13-4 = 9 = 3^2
40-13 = 27 = 3^3
let next no be x
x-40 = 3^4 = 81
hence x = 121

Like? Yes (1) | No   

gowthami   10 years AGO

1+3=4
4+9=13
13+27=40
40+81=121

Like? Yes (1) | No   

Amit Agrawal   10 years AGO

series difference is....
3,9,27... so next difference will be 81
and 40 +81=121

Like? Yes (1) | No   

Md Intshamuddin   10 years AGO

1
4==1+3
13==1+3+3^2
40==1+3+3^2+3^3
so next number will be
1+3+3^2+3^3+3^4=121

Like? Yes (2) | No (2)  

RAKESH   10 years AGO

40*3+1=121

Like? Yes (2) | No (2)  

Krupa Pareshkumar Shah   10 years AGO

difference between 1 & 4 =3 (1*3)
4 & 13=9 (3*3)
13 & 40=27 (9*3)
so...(27*3)=81 so 40+81= 121ans

Like? Yes (1) | No (1)  

abhilash kumar   10 years AGO

Consider the sequence 1 4 13 40
Here the difference bw terms 3 9 27 where each proceeding term is multiplied by 3 to get next term
So the next term is 40+27*3= 40+81=121

Like? Yes (1) | No (1)  

Vijit Mangla   10 years AGO

the difference of the consecutive terms is a GP with first term =4-1=3
second term =13-4=9
third term =40-13=27
so common ratio is 9/3=27/9 = 3
now the next term is found by adding 3*3*3*3=81
therefore 40+81= 121

Like? Yes (1) | No (1)  

Alok Mandal   10 years AGO

Difference between 1 and 4 = 3,
Difference between 4 and 13 = 9,
Difference between 13 and 40 = 27
There is difference of 3*3=9*3=27*3=81
So add 81 to previous no i.e. 40,
81+40=121

Like? Yes (2) | No (2)  

Dinesh kumar   10 years AGO

1+3=4
4+3^2=13
13+3^3=40
40+3^4=121
ans = 121

Like? Yes (1) | No (1)  

paaredi muthyam reddy   10 years AGO

1,4,13,40
the difference between the numbers is in the powers of 3.i.e.,3,9,27,81....
so the next number is 81+40=121

Like? Yes (1) | No (1)  

Ravi Kumar Kodari   10 years AGO

Given: 1,4,13,40
1+3^1=3
4+3^2=13
13+3^3=40
40+3^4=121 ans.

Like? Yes (1) | No (1)  

Ambuj tiwari   10 years AGO

Difference between no is in form of 3 ,3^2,3^3,3^4

Like? Yes (1) | No (1)  

amit baranga   10 years AGO

difference between each term is muliple of 3 in a particular pattern, 3, 9, 27.. next will be 81, add 81 to 40
ans 121

Like? Yes (1) | No (1)  

Tark Patel   10 years AGO

Difference between two numbers is multiple of 3.
(4-1)=3 , (13-4)=9 which is 3^2 , (40-13)=27 which is 3^3.
Hence next number is 121 (next is 3^4, 40+81=121).

Like? Yes (1) | No (1)  

Bhavna   10 years AGO

1,1*3+1,4*3+1,13*3+1,40*3+1

Like? Yes (1) | No (1)  

kapil singh   10 years AGO

look at d diffrences they are in multiple of 3
i.e.
1+3=4
4+3*3=13
13+3*3*3=40
so,
40+3*3*3*3=121
thats our ans! ;)

Like? Yes (4) | No (4)  

vandana   10 years AGO

the series is increasing in the order that the number is being added by the increasing power of 3,=>1,1+3^1=4,4+3^2=13,13+3^3=40,40+3^4=121,so option 5 is the answer=121

Like? Yes (1) | No (1)  

Aalvin   10 years AGO

4-1=3
13-4=9
40-13=27
difference is in multiples of 3
therefore next number is 40+81=121

Like? Yes (1) | No (1)  

sona   10 years AGO

121 is the answer.
1+3=4
4+9=13
13+27=40
here series of 3 to the power n is going on where n=1,2,3..
therefore next term will be
40+81=121 i.e 3*3*3*3=81

Like? Yes (1) | No (1)  

vamshikrishna kuruva   10 years AGO

1+3=4
4+3*3=13
13+3*3*3=40
40+3*3*3*3=121

Like? Yes (1) | No (1)  

Rivu Sengupta   10 years AGO

4-1=3
13-4=9
40-13=27
121-40=81

Like? Yes (1) | No (1)  

Hanish   10 years AGO

as difference is in the order of 3^x where x=1,2,3,4.....

Like? Yes (1) | No (1)  

Rashmi bharti   10 years AGO

40+27*3=121

Like? Yes (1) | No (1)  

pawan kumar chhipa   10 years AGO

3 times + 1 of last digits

Like? Yes (1) | No (1)  

YUVA   10 years AGO

SEQUENCE IS IN CUBE OF 3

Like? Yes (1) | No (1)  

vaibhav soni   10 years AGO

4-1=3=3^1
13-4=9=3^2
40-13=27=3^3

so answer will be = 40+(3^4)=121

Like? Yes (1) | No (1)  

Dinesh Arora   10 years AGO

4-1=3
(3*3)+4=13
13-4=9
(9*3)+13=40
40-13=27
(27*3)+40=121

Like? Yes (1) | No (1)  

pankaj kumar   10 years AGO

1 , 1+3, 4+9, 13+27, similarly
40+81 =121

Like? Yes (1) | No (1)  

pritam kumar singh   10 years AGO

4-1=3
13-4=9
40-13=27
x-40=81
x=121.

Like? Yes (1) | No (1)  

Logesh   10 years AGO

4-1=3
13-4=9(3*3)
40-13=27(9*3)so
121-40=81(27*3)
So Ans is 121

Like? Yes (1) | No (1)  

Varunraj Reddy   10 years AGO

1,4,13,40,...
differences are 3,9,27,...
next difference is 27*3=81
So next number is 40+81=121

Option 5)

Like? Yes (1) | No (1)  

aviral gupta   10 years AGO

4-1=3
13-4=9
40-13=27
so next number would be 81 greater than the preious number
so next number is 40+81=121

Like? Yes (1) | No (1)  

neha gupta   10 years AGO

let no is a, then, 4-1=3, 13-4=9, 40-13=27
so, the diff is increased by table of 3.
hence, a-40=81
a=40+81=121.
next no is 121.

Like? Yes (1) | No (1)  

Satish Zod   10 years AGO

40 * 3 + 1 = 121

Like? Yes (1) | No (1)  

Garima   10 years AGO

1*3=3+1=4
4*3=12+1=13
13*3=39+1=40
40*3=120+1=121

Like? Yes (1) | No (1)  

anusha   10 years AGO

1 4 13 40 y
3 9 27 x

40+81=121

Like? Yes (1) | No (1)  

vinusha reddy   10 years AGO

1x3+1=4
4x3+1=13
13x3+1=40
40x3+1=121

Like? Yes (1) | No (1)  

Sanjeev jain   10 years AGO

here,in first number increment by 3 then with 2nd number increment by 9.viceversa.....increse series with n*3.

Like? Yes (1) | No (1)  

Brindha.N   10 years AGO

1+3=4,4+9=13,13+27=40,40+81=121.answer is 121.each number is multipled by 3

Like? Yes (1) | No (1)  

ATTARU NASIMUNNI   10 years AGO

from 1 to 4 difference is 3
4 to 13 difference is 3*3 = 9
13 to 40 difference is 9*3 = 27
after 40 the number is 40+(27*3) = 121

Like? Yes (2) | No (2)  

RANJAN KUMAR PANDIT   10 years AGO

4-1=3
13-4=9
40-13=27
121-40=81

Like? Yes (1) | No (1)  

bandi gowthami   10 years AGO

1+3=4
4+9=13
13+27=40
40+81=121

Like? Yes (1) | No (1)  

Rohan Kumrawat   10 years AGO

4-1=3
13-4=9
40-13=27
so....121-40=81

Like? Yes (1) | No (1)  

T.Aravinth kumar   10 years AGO

40+81=121

Like? Yes (1) | No (1)  

Amrita   10 years AGO

1+3=4
4+(3*3)=13
13+(3*3*3)=40
40+(3*3*3*3)=121

Like? Yes (1) | No (1)  

sravani   10 years AGO

121 (4-1=3,
13-4=9,
40-13=27,
121-40=81)

Like? Yes (1) | No (1)  

Bobby Nayak   10 years AGO

3^0+0=1
3^1+1=4
3^2+4=13
3^3+13=40
3^4+40=121
answer is option 5:121

Like? Yes (2) | No (2)  

nagineni sukumar   10 years AGO

difference of no's are 3,9,27,81...
the answer is 121

Like? Yes (1) | No (1)  

ananthavalli   10 years AGO

The difference between the sequence is multiples of 3
1+3=4
4+9=13
13+27=40
similarly 40+81=121
so option 5) is correct

Like? Yes (1) | No (1)  

Soham Dalwadi   10 years AGO

the pattern is by multiples of 3 added to the preceding number;

example, 1+3= 4 that's 3
4+9=13 because 3*3 is 9
13+27=40 coz 9*3 is 27
40+81=121

Like? Yes (1) | No (1)  

vishalgoyal   10 years AGO

40+81=121

Like? Yes (1) | No (1)  

surabhi   10 years AGO

(1*3)+1=4
(4*3)+1=13
(13*3)+1=40
similarly
(40*3)+1=121

Like? Yes (2) | No (2)  

harish   10 years AGO

the diffrence between the numbers is in powers of 3
like 4-1=3
13-4=9=3*3
40-13=27=3*3*3
x-40=3*3*3*3 =>x=121

Like? Yes (1) | No (1)  

Shanmugapriya   10 years AGO

Difference between 1,4=3^1
Difference between 4,13=3^2
Difference between 13,40=3^3
Difference between 40,x=3^4=81
so 40+81=121

Like? Yes (1) | No (1)  

D.Gnaphika   10 years AGO

4-1=3
13-4=9
40-13=27
x-40=81
x=40+81=121

Like? Yes (1) | No (1)  

MANOJ KUMAR MAHANTA   10 years AGO

(1*1)+3=4
(4*3)+1=13
(13*3)+1=40
(40*3)+1=121

Like? Yes (1) | No (1)  

Meenakshi Nagchaudhuri   10 years AGO

40+ (27*3)

Like? Yes (1) | No (1)  

Shashi nath jha   10 years AGO

4-1=3
13-4=9
40-13=27
121-40=81

Like? Yes (2) | No (2)  

sivaraman   10 years AGO

1-4=3
3*3=9+4=13
9*3=27+13=40
27*3=81+40=121

Like? Yes (1) | No (1)  

Narendra   10 years AGO

Look at the differences:
1 4 13 40 121
3 9 27 81

Like? Yes (1) | No (1)  

jennifer mary   10 years AGO

1
4
1+3=4
4+0=4
1+2+1=4
after the first number ,the sum of all the digits is equal to 4

Like? Yes (2) | No (2)  

Anupam Banerjee   10 years AGO

1 + 3^1 = 4
4 + 3^2 = 13
13 + 3^3 = 40
40 + 3^4 = 121

So, the next no. is = 121;

Like? Yes (1) | No (1)  

sivasridola   10 years AGO

1-4=3 4-13=9 13-40=27 40-121=81

Like? Yes (1) | No (1)  

Shivani Enabotula   10 years AGO

1,1x3+1=4,4x3+1=13,13x3+1=40,...
Therefore 40x3+1=121

Like? Yes (1) | No (1)  

suhana   10 years AGO

1,(1*3)+1=4,(4*3)+1=13,(13*3)+1=40,(40*3)+1=121

Like? Yes (2) | No (2)  

abhinav jain   10 years AGO

to get next digit = (previous number*3+1)

answer is = option 5

Like? Yes (1) | No (1)  

Arpan Bhattacharyya   10 years AGO

difference between tow no in the form of 3^n

Like? Yes (1) | No (1)  

Udhaya kumar   10 years AGO

x+3power n ...

Like? Yes (1) | No (1)  

Talluri Harish   10 years AGO

4-1=3^1
13-4=3^2
40-13=3^3
x-40=3^4
=>x=121

Like? Yes (1) | No (1)  

mayank gahlot   10 years AGO

the series goes as follows:

1+3^1=4;
4+3^2=13;
13+3^3=40;
40+3^4=121(option 5)

Like? Yes (1) | No (1)  

Abhishake Agarwal   10 years AGO

1*3+1=4
4*3+1=13
13*3+1=40
40*3+1=121

Like? Yes (1) | No (1)  

naveenkumar   10 years AGO

1*3=3+1=4
4*3=12+1=13
13*3=39+1=40
40*3=120+1=121

Like? Yes (1) | No (1)  

Gourango   10 years AGO

0*3+1=1
1*3+1=4
4*3+1=13
13*3+1=40
40*3+1=121

Like? Yes (1) | No (1)  

susmit   10 years AGO

difference of 3,9,27
so the next difference will be 81
so the next number will be 40+81=121

Like? Yes (1) | No (2)  

SHEREENA NISHAD   10 years AGO

1 + (3^1) = 1 + 3 = 4
4 + (3^2) = 4 + 9 = 13
13+ (3^3) = 13 + 27 = 40
40+ (3^4) = 40 + 81 = 121

Like? Yes (1) | No (2)  

Saraswathy   10 years AGO

Difference is successive powers of 3

1, 4, 13, 40, x
4 - 1 = 3^1
13 - 4 = 3^2
40 - 13 = 3^3
x - 40 = 3^4
x = 121

Ans : 121 ( Option 5)

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

1+3^1= 1+3=4
4+3^2= 4+9=13
13+3^3=13+27=40
40+3^4=40+81=121

Like? Yes (1) | No (2)  

Mahalakshmi   10 years AGO

1 + 3 = 4
4 + 9 = 13
13 + 27 = 40
40 + 81 = 121
so ans is 5)121

Like? Yes (3) | No (4)  

Yogesh   10 years AGO

1*3+1=4
4*3+1=13
13*3+1=40
40*3+1=121

Like? Yes (1) | No (2)  

shree   10 years AGO

Lik lik hi hi

Like? Yes (1) | No (2)  

Mohammed Farook.S   10 years AGO

Find the difference of each number so we can get. The answer

Like? Yes (1) | No (2)  

Vishal Chugh   10 years AGO

The series given is:1,4,13,40
Differences between the numbers are 3,9,27 respectively,i.e.,the numbers are multiplied by 3 for each consecutive number.

Therefore the next difference will be 81 and the number 40+81=121

Like? Yes (1) | No (2)  

Veepuru Manoj   10 years AGO

difference is power of 3

Like? Yes (1) | No (2)  

RANDHIR KUMAR   10 years AGO

1*3=3+1=4,4*3=12+1=13,13*3=39+1=40,40*3=120+1=121.

Like? Yes (1) | No (2)  

Tharun   10 years AGO

Difference between each digit is multiple of 3

Like? Yes (1) | No (2)  

guddu   10 years AGO

here, 1,4,13,40...
if we take difference 2nd no. - 1st no.result is mutiplication of 3
4-1=3
13-4=9
40-13=27
x-40=81
x=121

Like? Yes (1) | No (2)  

mansi garg   10 years AGO

1*3+1=4
4*3+1=13
13*3+1=40
40*3+1=121

Like? Yes (1) | No (2)  

Dipak kumar saha   10 years AGO

its increasing in order of 3,3^2,3^3,3^4 & so on adding 2 next no.'s
so 1+3=4
4+3^2=13
13+3^3=40
40+3^4=121
so ans is 5)121

Like? Yes (1) | No (2)  

Alpana Kumari   10 years AGO

its 121 coz 1+3=4, 4+3*3=13, 13+3*3*3=40...then 40+3*3*3*3=121.

Like? Yes (1) | No (2)  

RAKHI RAMTEKE   10 years AGO

multiply by 3 plus 1...
40*3+1=121

Like? Yes (2) | No (3)  

Smitha    10 years AGO

1 + 3(3 pow 1) = 4
4 + 9(3 pow 2) = 13
13+ 27(3 pow 3) = 40
40+ 81(3 pow 4) = 121

Like? Yes (1) | No (2)  

27 Jun 2014 Coded language

If in coded language
VAIBHAV = -13
BHUWAN = 25
CHANDAN = 7
then
RATNESH = ?

OPtion

1) -8
2) 12
3) 19
4) -19
5) -4
6) 36
7) 13
8) 18
9) -16
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
VAIBHAV = 22+1-9+2-8+1-22 = 26-39 = -13
BHUWAN = 2+8-21+23-1+14 = 47-22 = 25
CHANDAN = 3+8-1+14-4+1-14 = 26-19 = 7
Similarly
RATNESH = 18+1-20+14-5+19-8 = 52-33 = 19

Option 3)

Correct Option: 3 Best Solution (19)

Saraswathy   10 years AGO

VAIBHAV => 22,1,9,2,8,1,22 => (22-9-8-22)+(1+2+1)
=> -17+4 = -13
BHUWAN => 2,8,21,23,1,14 => (2-21-1)+(8+23+14)
=> -20+45 = 25
CHANDAN = 3,8,1,14,4,1,14 => (3-1-4-14)+(8+14+1)
=> -16+23 = 7

Similarly
RATNESH = 18,1,20,14,5,19,8
=>(18-20-5-8)+(1+14+19) => -15+34 = 19

Ans : 19 (Option 3)

Like? Yes (12) | No (4)  

RAKHI RAMTEKE   10 years AGO

RATNESH=
Numbering all alphabets from 1 to 26....
R=18,A=1,T=20,N=14,E=5,S=19,H=8
Using addition and substraction alternatively we get,18+1-20+14-5+19-8=19
i.e option 3

Like? Yes (4) | No   

Lakshya   10 years AGO

-13+25+7=19

Like? Yes (1) | No   

Abhra Layek   10 years AGO

V A I B H A V if we take numbers equivalent to the letters, and taking the numbers of prime numbers positions and adding them, and subtracting from the sum of rest, we find
(V A B A)-(I H V)= (22+1+2+1)-(9+8+22)=-13
B H U W A N}
(B H W N)-(U A)=(2+8+23+14)-(21+1)=25
C H A N D A N
(C H N A)-(A D N)=(3+8+14+1)-(1+4+14)=7
Hence
R A T N E S H
(R A N S)-(T E H)=(18+1+14+19)-(20+5+8)=19

Like? Yes (2) | No (1)  

Aashu   10 years AGO

Using + and - alternatively
VAIBHAV = 22+1-9+2-8+1-22 = 26-39 = -13
BHUWAN = 2+8-21+23-1+14 = 47-22 = 25
then
RATNESH = 18+1-20+14-5+19-8 = 52-33 = 19

Like? Yes (2) | No (1)  

ananthavalli   10 years AGO

RATNESH=18+1-20+14-5+19-8=19
OPTION 3) IS CORRECT

Like? Yes (1) | No   

Nitish   10 years AGO

vaibhav= 22+1-9+2-8+1-22= -13
bhuwan= 2+8-21+23-1+14= 25

similarly
ratnesh
18+1-20+14-5+19-8= 19

Like? Yes (1) | No   

vinusha reddy   10 years AGO

viabhav=v+a-i+b-h+a-v=22+1-9+2-8+1-22=-13
bhuvan=b+h-u+v-a+n=2+8-21+23-1+14=25
chandan=c+h-a+n-d+a-n=3+8-1+14-4+1-14=7
similarly
ratnesh=r+a-t+n-e+s-h=18+1-20+14-5+19-8=19

Like? Yes (2) | No (1)  

BINAY   10 years AGO

first convert each alphabet in number format. Now add the first two number and the subtract it with the next. repeat the steps ...

Like? Yes (1) | No   

Aalvin   10 years AGO

18 1 20 14 5 19 8
R A T N E S H
18+1-20+14-5+19-8 = 19

Like? Yes (1) | No   

saisudha sarva   10 years AGO

RATNESH=18+1-20+14-5+19-8

Like? Yes (1) | No   

RAKESH   10 years AGO

put alternate + & -
RATNESH = R+A-T+N-E+S-H = (R+A+N+S)-(T+E+H)= (18+1+14+19)-(20+5+8)= 19

Like? Yes (1) | No   

KODEISWARAN ELANGOVAN   10 years AGO

19 is the answer

Like? Yes (1) | No   

Gautam Anand   10 years AGO

18+1-20+14-5+19-8=19

Like? Yes (1) | No   

guddu   10 years AGO

VAIBHAV=22+1-9+2-8+1-22=-13
BHUWAN=2+8-21+23-1+14=25
CHANDAN=3+8-1+14-4+1-14=7
RATNESH=18+1-20+14-5+19-8=19

Like? Yes (1) | No   

D.Gnaphika   10 years AGO

a=1,b=2........z=26 and adding even places and adding odd places seperately and then subtracting odd from the even and then add 2*value of 1st alphabet then we get ratnesh code as 19

Like? Yes (1) | No   

Tark Patel   10 years AGO

Let's assign a number to each individual aplhabet like
(A-1 , B-2 , C-3 , ... , X-24 , Y-25 , Z-26).

1) VAIBHAV = -13
-> V+A-I+B-H+A-V = 22+1-9+2-8+1-22 = -13

2)BHUWAN = 25
-> B+H-U+W-A+N = 2+8-21+23-1+14 = 25

3)CHANDAN = 7
-> C+H-A+N-D+A-N = 3+8-1+14-4+1-14 = 7

Hence,

--->> RATNESH
-> R+A-T+N-E+S-H = 18+1-20+14-5+19-8 = 19

Answer is RATNESH = 19 (Pattern of coding is +,-,+,-,+,-...)

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

18+1-20+14-5+19-8=19

Like? Yes (1) | No   

Bobby Nayak   10 years AGO

V+A-I+B-H+A-V
22+1-9+2-8+1-22= -13
similarly,
R+A-T+N-E+S-H
18+1-20+14-5+19-8= 19
answer is option 3: 19

Like? Yes (1) | No   

26 Jun 2014 Solve

Three numbers are formed by taking three successive powers of 4. The sum of these three numbers is 21504. What is the greatest power raised

OPtion

1) 10
2) 8
3) 9
4) 6
5) 5
6) 4
7) 11
8) 7
9) 12
10)None of these

Solution

4^x + 4^(x+1) + 4^(x+2) = 21504
=> 4^x (1+4+4^2) = 21504
=> 4^x = 21504/21
=> 4^x = 1024
=> x = 5
Hence greatest power is 7

Option 8)

Correct Option: 8 Best Solution (51)

Sundar Kumar   10 years AGO

4^7+4^6+4^5= 21504
greatest power is 7
Answer option 8) 7

Like? Yes (13) | No (4)  

Aalvin   10 years AGO

(4^x)+(4^(x+1))+(4^(x+2))=21504
4^x(1+4+16)=21504
4^x=1024
x=5
greatest power raised=7

Like? Yes (2) | No   

Shashank   10 years AGO

4^x+4^(x+1)+4^(x+2)=21504
this form g.p. with r =4 and a= 4^x
use sum of g.p. formula
we get 4^5,4^6,4^7
7 is maximum power

Like? Yes (1) | No   

Ravi Bhalani   10 years AGO

4^5+4^6+4^7=21504

Like? Yes (1) | No   

Krupa Pareshkumar Shah   10 years AGO

4^5+4^6+4^7=21504

Like? Yes (1) | No   

akrati   10 years AGO

4^x+4^x+1+4^x+2=21504
4^7+4^6+4^5=21505

Like? Yes (1) | No   

vandana   10 years AGO

power of 4's=4,16,64,256,1024,4096,16384
16384 is 4^7.16384+4096+1024=21504
therefore highest power is 7

Like? Yes (3) | No (2)  

Jainisha Sankhavara   10 years AGO

Let first number be x.
Hence second and third numbers are 4x and 16x.
x+4x+16x = 21504
21x=21504
x=1024=4^5
the greatest power raised is the power of third number which is equal to 16x(4^5)= 4^7
Therefore ans is 7(option number 8).

Like? Yes (1) | No   

Arun Karthick   10 years AGO

we can perform successive division on the number 21504 only 7 times
So its obviously the power of 4 cant be more than 7.
the sum of 4^5 + 4^6 + 4^7

Like? Yes (1) | No   

Tark Patel   10 years AGO

(4^5)+(4^6)+(4^7)=21504
so greatest power is 7.

Like? Yes (1) | No   

Vibha   10 years AGO

4^n + 4^(n+1) +4^(n+2) =21504
4^n (1 + 4 + 16) = 21504
4^n(21) = 21504
4^n=1024
4^n =4^5
=> n = 5
=> greatest power = 7

Like? Yes (1) | No   

DHIRENDRA    10 years AGO

5^4 + 6^4 + 7^4= 1024 + 4096 + 16384 = 21504

Like? Yes (1) | No   

suraj jha   10 years AGO

4^7=16384.....(1)
4^6=4096......(2)
4^5=1024......(3)
adding (1),(2),(3) we get 21504.
so the greatest power raised=7

Like? Yes (1) | No   

paaredi muthyam reddy   10 years AGO

4^x+4^(x+1)+4^(x+2)=21504
solve it we get x=5
x+2=7

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

4^x+4^(x+1)+4^(x+2)=21504
solve it we get x=5
x+2=7

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

4^5+4^6+4^7

Like? Yes (1) | No   

joyal   10 years AGO

4^7=16384
4^6=4096
4^5=1024
So 4^7+4^6+4^5=21504

Like? Yes (1) | No   

NAVNEET RAJ VAISH   10 years AGO

4^x+4.4^x+4.4.4^x=21504
(1+4+4.4)4^x=21504
21.4^x=21504
4^x=1024
4^x=4^5
x=5

and highest power will be 4.4.4^5
that is 7

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

4^5+4^6+4^7 = 21504

Like? Yes (1) | No   

mansi garg   10 years AGO

4^5+4^6+4^7=21504
hence

Like? Yes (2) | No (3)  

Devendra Marghade   10 years AGO

IThe three numbers formed by successive power of 4 as 4^a, 4^(a+1), 4^(a+2)
Given, [4^a+ 4^(a+1)+ 4^(a+2)]=21504
[4^a+(4^a)*(4^1)+(4^a)*(4^2)]=21504
4^a[1+4+16]=21504 ,4^a=1024, a=5
So greatest power of 4 raised=a+2=5+2=7

Like? Yes (1) | No (2)  

NITIN KUMAR GOYAL   10 years AGO

(4^x)+(4^(x+1))+(4^(x+2))=21504
x=5
so maximum power will be 5+2=7

Like? Yes (1) | No (2)  

pawan kumar chhipa   10 years AGO

by hit and trial
ans is 8) 7

Like? Yes (1) | No (2)  

Bhavna   10 years AGO

4^x+4^(x+1)+4^(x+2)=21504
x=5;
max power=x+2
=7

Like? Yes (1) | No (2)  

Dipak Shaw   10 years AGO

4^5+4^6+4^7=21504

Like? Yes (1) | No (2)  

kapil singh   10 years AGO

4^(x-1)+4^(x)+4^(x+1)=21504
4^x(1/4+1+4)=21504
x=6
hence greatest power = x+1 i.e 7

Like? Yes (1) | No (2)  

Saraswathy   10 years AGO

4^x + 4^(x+1) + 4^(x+2) = 21504
4^x + 4^x * 4 + 4^x * 16 = 21504
4^x(1+4+16) = 21504
4^x = 1024
4^x = 4^5
x=5
Max. power is (x+2) => 7

Ans : 7 (Option 8)

Like? Yes (1) | No (2)  

NAGENDRA P   10 years AGO

4^A+4^(A+1)+4^(A+2)=21504
4^A*(1+4+16)=21504
4^A=1024
A=5..
A+2=7..
SO OPTION (8) IS ANSWER

Like? Yes (1) | No (2)  

Anand Singh   10 years AGO

Let first successive number is x
so, Second successive number is x+1
and third successive number is x+2
According to question...
4^x+4^(x+1)+4^(x+2)=21504...
by solving above equation we get
x=5,
then greatest number is 7.ANS

Like? Yes (1) | No (2)  

saira fatma   10 years AGO

8)7 is the answer because 4^7=16384,4^6=4096,4^5=1024 on adding these no=16384+4096+1024 we get 21504

Like? Yes (1) | No (2)  

ROMA SINGH   10 years AGO

4^x+4^(x+1)+4^(x+2)=21504
4^x(1+4+16)=21504
4^x(21)=21504
4^x=1024
x=5; x+1=6 x+2=7
ans= 7

Like? Yes (1) | No (2)  

akshansh shrivastav   10 years AGO

4^5+4^6+4^7=21504

Like? Yes (1) | No (2)  

sruthi   10 years AGO

8 is the answer

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

4^x + 4^(x+1)+ 4^(x+2)= 21504
=> 4^x(1+4+16)= 21504
=> 4^x = 1024
=> x=5
(x+2)=7

Like? Yes (1) | No (3)  

akash Khandale   10 years AGO

check ooptin

Like? Yes (1) | No (3)  

Gitanjali K   10 years AGO

4^7+4^6+4^5=16384+4096+1024=21504
so 7 is the greatest power of 4 and option (8) is the answer..

Like? Yes (1) | No (3)  

Yogesh   10 years AGO

4^5+4^6+4^7=21504

4^7=16384
4^6=4096
4^5=1024

Like? Yes (1) | No (3)  

Shashi nath jha   10 years AGO

4^5+4^6+4^7=21504

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

4^5+4^6+4^7=21504

So greatest power raised=7

Option 8)

Like? Yes (1) | No (3)  

D.Gnaphika   10 years AGO

let X be the power raised and so three numbers can be 4^x,4^(x+1),4^(x+2) according to the condition sum of them is 21504 and the we get x=5 and greatest power raised would be x+2=5+2=7

Like? Yes (1) | No (3)  

Bobby Nayak   10 years AGO

let the 1st power of 4 be x, then 2nd and 3rd will be x+1 and x+2 respectively.

4^x + 4^(x+1) + 4^(x+2) = 21504
4^x + (4^x)4 + (4^x)16 =21504
4^x(1+4+16) =21504
4^x(21)=21504
4^x= 21504/21
2^2x = 1024
2^2x= 2^10
2x=10 and x=5
thus the powers are 5, 6 and 7.

answer is option 8 i.e.,7

Like? Yes (1) | No (3)  

pankaj kumar   10 years AGO

4^x + 4^(x-1) +4^(x-2) = 21504

4^(x-2) { 4^2+4+1} =21504

4^(x-2) = 21504/21 =1024

4^x = 4^7

so x=7

Like? Yes (1) | No (3)  

Sumesh TS   10 years AGO

changed

Like? Yes (1) | No (3)  

Dinesh thatti   10 years AGO

Three numbers are formed by taking three successive powers of 4

take 5,6,7 we get 4^5=1024
4^6=4096
4^7=16384
total=21504
The sum of these three numbers is 21504.

the greatest power raised is 4^7

Like? Yes (1) | No (3)  

Rashmi bharti   10 years AGO

4^n(1+4+16)=21504
=>n=5

Like? Yes (1) | No (3)  

Vishal Chugh   10 years AGO

Let the powers be n, n+1 and n+2.Now according to the question the equation formed will be:

4^n + 4^(n+1) + 4^(n+2) = 21504
Taking '4^n' common from the above equation we get:
4^n(1+4+16) = 21504
which gives
n = 5
Hence greatest power will be n + 2 = 7

Like? Yes (3) | No (5)  

vaibhav soni   10 years AGO

Given:
4^n + 4^(n+1) + 4^(n+2) = 21504
=> 4^n(1+4+16) = 21504
=> 4^n = 1024
=> 4^n = 4^5
=> n=5

so greatest power raised is = n+2 = 7

Like? Yes (1) | No (3)  

RAKHI RAMTEKE   10 years AGO

as,4^8 is greater than 21504 and by calculations 4^5+4^6+4^7=21504.......
so the greatest power here is 7....i.e option 8

Like? Yes (1) | No (3)  

shree   10 years AGO

7 is the greatest power of 4.

Like? Yes (1) | No (3)  

Dinesh Arora   10 years AGO

4^x + 4^x+1 +4^x+2 = 21504

4^x*4^0 + 4^x*4^1 + 4^x*4^2=21504
4^x(1+4+16)=21504
4^x*(21)=21504
4^x=1024
4^x=4^5
so x=5 and max successive is x+2 ie 5+2 = 7

Like? Yes (1) | No (3)  

Anupam Banerjee   10 years AGO

Let the successive nos are x, x+1, x+2;

So,4^x + 4^(x+1) + 4^(x+2) = 21504

solving this, x = 5;

So, the highest power is = 7;

Like? Yes (1) | No (3)  

25 Jun 2014 Solve

Two pipes running together can fill a cistern in 6 minute. If one pipe takes 5 minutes more than the other to fill the cistern, find the time in which each pipe would fill cistern.

OPtion

1) 8 min and 12 min
2) 12 min and 16 min
3) 10 min and 16 min
4) 6 min and 10 min
5) 14 min and 18 min
6) 15 min and 10 min
7) 9 min and 14 min
8) 18 min and 22 min
9) 20 min and 25 min
10)None of these

Solution

Let the volume of cistern = V litre (L)
let the flow rate of one pipe be x L/min and that of other pipe be y L/min
Since 6 minute are needed to fill the pipe
6x+6y = V = total volume (1)
V/x = time taken by one pipe and V/y = time taken by other pipe
V/x + V/y = 5 min
1/x - 1/y = 5/V (2)

Solve
Time taken by one pipe = 15 min
and Time taken by other pipe = 10 min
Option 6) 15 min and 10 min

Correct Option: 6 Best Solution (47)

Krupa Pareshkumar Shah   10 years AGO

let total work done by two pipes in one minute is
1/6.
one of them done in one minute is 1/x & another one done it in one minute is 1/(x+5).
so that
1/x +1/(x+5)=1/6
After solving this...
x=10...
x+5=15

Like? Yes (42) | No (3)  

Amrita priyadarshi   10 years AGO

let us suppose pipe 1 takes x minutes to fill the tank so in 1 minute it would fill 1/x part of tank.
then 2nd pipe will take x+5 minutes so in 1 minute it would fill 1/(x+5) part of tank.
both pipe will take 6 minutes to fill up the tank.
hence (1/x)+[1/(x+5)]=1/6
after solving we will get 10 and -3 as solution of x. x=(-3) can't be a solution.
thus 1st pipe will take 10 minutes
and 2nd pipe will take x+5 = 15 minutes.

Like? Yes (21) | No (4)  

Sundar Kumar   10 years AGO

Let volume of cistern be V litres

Pipe 1 rate of filling = V / x litres / min
Pipe 2 rate of filling = V / ( x + 5) litres / min

Combined rate of filling = V / 6 litres / min

V / x + V / ( x + 5 ) = V / 6

6 ( x + 5 ) V + (6 x ) V = x ( x + 5 ) V

6x + 30 + 6 x = x ² + 5 x

x ² - 7 x - 30 = 0

( x - 10 ) ( x + 3 ) = 0

x = 10

Pipes take 10 min and 15 min /(6)
1/x + 1/(x + 5) = 1/6
6(2x + 1) = 11x(x + 1)
60x + 30 = 11x^2 + 11x
11x^2 - 49x - 30 = 0
(x - 5)(11x + 6) = 0
One pipe takes 5 minutes and the other 6 minutes to fill the cistern.

Like? Yes (20) | No (8)  

Bobby Nayak   10 years AGO

let pipe 1 takes x min to fill cistern
and pipe 2 takes (x+5) min to fill
therefore,

cistern filled by pipe 1 in 1min = 1/x
cistern filled by pipe 2 in 1min = 1/(x+5)
and together they fill 1/6 in 1min.

so, 1/x + 1/(x+5)= 1/6
by solving for x, we get x=10
thus, pipe 1 takes 10 min and
pipe 2 takes 15 min

answer is option 6

Like? Yes (8) | No (4)  

ananthavalli   10 years AGO

Two pipes can fill a cistern in 6 minute
Let the cistern filled by first pipe take 5 minutes more..so it is (x+5)
Then,second pipe fill it in x minutes
1/(x+5)+1/x=1/6
By solving the equation we get:(x-10)&(x+3)
By taking positive value x=10..Second cistern will take =10 minute
So,the first cistern will take(10+5)=15 minute
Option 6) is correct

Like? Yes (4) | No (1)  

Purnendu Giri   10 years AGO

eliminate the options a

Like? Yes (5) | No (2)  

IFFAT IRAM   10 years AGO

let the time taken by cistern A be x
time taken by cistern B =x+5
1/x + 1/(x+5)=1/6
12x+30=x(x+5)
x^2-7x-30=0
x^2-10x+3x-30=0
(x-10)(x+3)=0
x=10
x+5=15
10 mins and 15 mins
option 6

Like? Yes (4) | No (3)  

vandana   10 years AGO

both pipes one minute work is =1/6
one pipe one minute work is x and other pipes work is x+5.
1/x+1/(x+5)=1/6
=>x^2-7x-30=0
on solving x=10,therefore pipes takes x=10 and x+5=15 minutes

Like? Yes (3) | No (2)  

akrati   10 years AGO

According to ques
Eq are
1/x+1/(x+5)=1/6
On solving them we get
X^2-7x-30=0
X(x-10)+3(x-10)=0
x=-3,10
y=10+5=15
And is
15,10

Like? Yes (3) | No (3)  

Ravi Bhalani   10 years AGO

let one pipe taks x min so another pipe takes x+5 min
now according to given condition ;
(x(x+5))/(x+x+5)=6
solving we get x=10 so ans is in option 6

Like? Yes (1) | No (1)  

Shashank   10 years AGO

let i pipes fill in x thn other fill in x+5
1/x+1/(x+5)=1/6
after solving x=10,-3
time cant not be -ve thn we take 10
other is 10+5 which is 15

Like? Yes (2) | No (2)  

Hanish   10 years AGO

as 1/(x-5)+1/x=1/6
solving,we get
option 6)
..

Like? Yes (1) | No (1)  

NITIN KUMAR GOYAL   10 years AGO

(1/x)+[1/(x+5)]=1/6
x=10

Like? Yes (1) | No (1)  

Udhaya kumar   10 years AGO

(1/6) = (1/x)+(1/(x+5))
by soving this we get x=10... so 10,15....

Like? Yes (2) | No (2)  

rojaranivutukuri   10 years AGO

p1 -> t minutes, p2 ->t+5 minutes
in one minute,
1/t + 1/t+5 = 1/6
=> t=10
=> t+5=15

Like? Yes (1) | No (1)  

mansi garg   10 years AGO

1/X+1/(X+5)=1/6
HENCE X= 10

Like? Yes (2) | No (3)  

Lakshya   10 years AGO

Because 1st pipe take 5 minute more than other

Like? Yes (2) | No (3)  

shree   10 years AGO

(1/X)+(1/X+5)=(1/6)
12X+30=X^2+5X
X^2-7X-30=0
X=10
Time=15 min and 10 min

Like? Yes (2) | No (3)  

Amit kumar   10 years AGO

Let A pipe takes x mins and B takes (x+5)mins.
ATQ
1/x+1/(x+5)=1/6
==> x= 10 mins
Ans 10 mins. and 15 mins.

Like? Yes (2) | No (3)  

D.Gnaphika   10 years AGO

let x be the time taken by one pipe let x+5 be the time taken by other pipe according to the question 1/((1/x)+(1/(x+5)))=1/(1/6) by sloving we get x=10 and x+5=15

Like? Yes (2) | No (3)  

MRITUNJAY KUMAR   10 years AGO

the cistern filled by both pipe in 1 min will be 1/6.
let one pipe filled the cistern in x min.another pipe will fill in x+5 min.
(1/(x+5))+1/x=1/6; we get x=10,-3.neglect -3.
ams will be 10 & 15.

Like? Yes (2) | No (3)  

Ambuj tiwari   10 years AGO

T1*T2/ T1+T2

Like? Yes (2) | No (3)  

Kowshik Sarker   10 years AGO

let one pipe takes x min so another pipe takes (x+5)min. So we can get a equation that is
(1/x)+(1/x+5)=1/6
solving this we get x^2-7x-30=0
solving this we get x=10
so one pipe will take 10min and another will take 15min. so the correct option will be 6.

Like? Yes (2) | No (3)  

AMIT KUMAR ANAL   10 years AGO

x,x+5
(1/x)+(1/x+5)=1/6

Like? Yes (2) | No (3)  

Shanmugapriya   10 years AGO

Let the pipes be x and x+5
Now,
1/x+1/x+5=1/6
since,two pipes fill the cistern in 6 min
Solving the equation, we get
x=10 and -3
Negative answer is rejected
so ans is 10 min and 15 min

Like? Yes (1) | No (2)  

Rashmi bharti   10 years AGO

let one pipe fills the cistern in x min and other in (x+5)mins.
=>(1/x)+(1/(x+5))=1/6
=>x=10 min
other pipe would 15 mins.

Like? Yes (2) | No (3)  

himani chawla   10 years AGO

x-y=5
1/x+1/y=1/6
by solving we get x=15 and y=10

Like? Yes (1) | No (2)  

pankaj kumar   10 years AGO

let speed of first pipe is x
then
6((1/x)+(1/(x+5)))=1
after solution we get x=10
so answer is 10,15

Like? Yes (1) | No (2)  

akash Khandale   10 years AGO

check options

Like? Yes (1) | No (2)  

AMIT SINGH   10 years AGO

let 1st pipe takes x min. to fill the cistern
so, 2nd pipe take x+5 min.
hence the equation becomes
6(1/x +1/(x+5))=1
x=10 or -3
therefore,x=10 (since time cannot be negative).
so,pipes would take 10min and 15min to fill the cistern separately.
option(6).

Like? Yes (1) | No (2)  

nagineni sukumar   10 years AGO

one pipe takes=x min.
another pipe takes =x+5 min.
in one minute 1/x +1/(x+5)=1/6
solve above equation get x=10min
difference in filling two pipes=5
so that other pipe it takes=15 min

Like? Yes (1) | No (2)  

NAVNEET RAJ VAISH   10 years AGO

looking at the options only 6 and 9 satisfy the 5 min difference condition.

for 6 mins time of operation

1st pipe will fil 0.6times cistern
2nd pipe fills 6/15 i.e. 0.4 times cistern hence on taking them together whole (0.4+0.6)times i.e full cistern is filled

Like? Yes (1) | No (2)  

juhi   10 years AGO

work of first pipe=1/x+5;
work of second pipe=1/x;
then 1/6=1/x+1/x+5;
after solving it x=10

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

If one pipe fill the cistern in 'x' minutes, then other will take (x+5) minutes
(1/x)+1/(x+5)= 1/6
x^2-7x-30=0
(x-10)(x+3)=0,
x=10,so (x+5)=15

Like? Yes (1) | No (3)  

Anand Singh   10 years AGO

let first pipe fill the cistern in x minute
and second pipe fill the cistern in y minute
According to question....
x-y=5-----------------(1)
and
(1/x+1/y)6=1-----------(2)
By solving equation (1)&(2)
we get x=15.
and y=10.
so first pipe fill the cistern in 15 minute.
and Second pipe fill the cistern in 10 minute.

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

Let one pipe can fill the cistern in x min.
Other pipe can fill the cistern in (x+5) min.
Two pipes can fill the cistern in 6 min.

i.e., 1/x + 1/(x+5)=1/6

By solving we get,
x=10 or -3
Then x=10 min, x+5=15 min

Ans: Option 6)

Like? Yes (1) | No (3)  

Anupam Banerjee   10 years AGO

Let, 1st pipe takes x min;
2nd pipe takes (x+5) min;

Together they fill,
(1/x)+(1/x+5) part of the cistern in 1min;

So, 6* [(1/x)+(1/x+5)] = 1;
By solving it, we have x = 10;

So the time taken to fill the cistern by each pipe will be 10 min and (10+5) = 15 min;

Like? Yes (1) | No (3)  

Saraswathy   10 years AGO

Let 1st pipe takes x minute to fill the cistern
1/x + 1/(x+5) = 1/6
Solving, we ll get x = 10 min
x = 10mins, x+5 = 15min

Ans : 15 min and 10 min (Option 6)

Like? Yes (1) | No (3)  

Vaishali Gupta   10 years AGO

1/a+1/b=1/6
1/a+1/(a+5)=1/6
on solving
a^2-7a-30=0
a^2-10a+3a-30=0
(a-10)(a+3)
a=10
b=a+5
10+5
b=15

Like? Yes (1) | No (3)  

D.Sree Navya   10 years AGO

1/x+1/x+5=1/6 this is the equation we get from the given question.
By solving the above equations we get x value as 10 then x+5=15..
15,10

Like? Yes (1) | No (3)  

pawan kumar chhipa   10 years AGO

both the pipe takes 6
then in one minute he takes 1/6 full
let one pipe take x minute
other take 5 more then x+5
in one minute both can fill the pipe 1/x or 1/(x+5)

total in one minute
1/x+1/(x+5)=1/6
solve it
x=10
x+5 =15
ans is 6)

Like? Yes (1) | No (3)  

Dimple   10 years AGO

1/15 +1/10=1/6

Like? Yes (1) | No (3)  

abhilash kumar   10 years AGO

Let time taken by one pipe be x min.then the time taken by other pipe l be x+5 min
Then 1/x + 1/(x+5) =1/6
Solving we get x=10
Hence it is 15 n 10 mins

Like? Yes (1) | No (3)  

krishn kumar gupta   10 years AGO

pipes A an B together filled the cistern in 6 min.:
(1/A+1/B)=1/6----------(1)

now another condition is
A=B+5
now from eq-(1)
we will get B=10,-3(not possible)
so
Pipe A will take (10+5)=15 min
Pipe B will take 5 min
so option 6 is correct!!!

Like? Yes (1) | No (3)  

Mohammed Farook.S   10 years AGO

1/x+1/(x+5)=1/6

Solve the eqn we get x=10 and 15

Like? Yes (1) | No (3)  

Yogesh   10 years AGO

1/x +1/(x+5)=1/6

from this we got

x^2-7x-30=0

x(x-10)+3(x-10)=0

x=10,-3
-3 is not possible
so x=10
x+5=15

Like? Yes (1) | No (3)  

Gourango   10 years AGO

eliminate the options and then check the options.

Like? Yes (1) | No (5)  

24 Jun 2014 Solve

A year ago, the father's age was 8 times his son's age. His present age is square of his son's age. Find their present ages.

OPtion

1) 6, 48
2) 8, 40
3) 5, 40
4) 6, 36
5) 7, 56
6) 7, 36
7) 9, 52
8) 8, 48
9) 7, 49
10)None of these

Solution

Let present age of son = x years
Father's present age = x^2 years
Given
x^2-1 = 8(x-1)

solve
7 and 49
son's and father's age

Option 9)

Correct Option: 9 Best Solution (60)

Dinesh Arora   10 years AGO

let son present age be x
then father's age x^2

one year ago..
son age (x-1)
father age 8(x-1)

so present age . now be...
8(x-1)+1=x^2
8x-8+1=X^2
x^2-8x+7=0
X^2 -7x-x+7=0
x(x-7)-1(x-7)=0
(x-1)(x-7)=0
so x=7 and x=1;
according to x=7..
where x is son's age.. so present son's age is 7
present father's age .. x^2= 7^2=49

Like? Yes (9) | No (3)  

Krupa Pareshkumar Shah   10 years AGO

A year ago it was 6 and 48 and now it is 7 & 49

Like? Yes (2) | No   

RISHABH SHARMA   10 years AGO

let current age is x and y then
x-1=8(y-1) and x=y^2

Like? Yes (2) | No   

Rahul Kumar   10 years AGO

father=y
son=x
y=x^2
y-1=8(x-1)
y-1=8x-8
y-8x+7
x^2-8x+7=0
x^2-7x-x+7=0
x=7,1
hance ans=7,49

Like? Yes (1) | No   

ananthavalli   10 years AGO

for this question the equation is:
Present age of father and son is x^2&x then the equation becomes (x^2-1)=8(x-1),by solving this we get x=7..son's age=7,father's age=49

Like? Yes (1) | No   

kusuma   10 years AGO

lets take father age=x,son\'s age=y
from given information,
x-1=8(y-1)..............(1)
x=y^2...................(2)
by solving above two equations we can get y=1,7
y=1 is not possible so y=7 and x=49

Like? Yes (1) | No   

Ravi Bhalani   10 years AGO

present age of son y and that of father is x;
now according to given condition,
x-1=8(y-1)......(1)
x=y^2...........(2)
Solving (1) & (2) we get y=1 or y=7
y=1 is not possible since if y=1 then x=1
So,y=7 & x=49
Present age of father is 49
Present age of son is 7

Like? Yes (1) | No   

Madhavee latha   10 years AGO

Solving the euations f-1=8(s-1) and f=s^2 we get the father age 49 ans sons age is 7

Like? Yes (1) | No   

akrati   10 years AGO

Let father present age is y and son present age is x
It is given that
(y-1)=8(x-1)
y=x*x
x^2-8x+7=0
x=7
y=49

Like? Yes (1) | No   

Nilay   10 years AGO

7-1=6
49-1=48
&6*8=48

Like? Yes (1) | No   

swati nath   10 years AGO

X-1=8(Y-1)
X=Y^2
So Y^2-1=8(Y-1)
(Y-1)(Y+1)=8(Y-1)
Y+1=8
Y=7
So X=49

Like? Yes (1) | No   

Arigela Naga Vineel   10 years AGO

7and 49 a year ago it would be 6:48 that is eight times

Like? Yes (1) | No   

sruthi   10 years AGO

9 is answer 7,49

Like? Yes (1) | No   

Anshu kumar   10 years AGO

sqrt of 49 = 7
49-1=48
7-1=6
6*8=48

Like? Yes (1) | No   

Hanish   10 years AGO

Let x be fathers age and y be sons age
then,A.T.Q,
(x-1)=8(y-1) -1)
x=y^2 -2)
from 1 and 2,we have
y=7 and x=49
Therefore option 9)

Like? Yes (1) | No   

bandi gowthami   10 years AGO

let father's present age=f
son's present age=s
given
f=x^2
&
f-1=8*(s-1)
f-1=8s-8
put f=s^2
s^2-1=8s-8
s^2-8s+7=0
solving this
s=1 or s=7
if s=7;
f=49

ans:9

Like? Yes (1) | No   

mulakala kota naga harish babu   10 years AGO

from options only two options produce a square so beter to go with optons

Like? Yes (1) | No   

nagineni sukumar   10 years AGO

Let father's age=x ,son's age=y
one year ago (x-1)=8(y-1)
present year x=y2
y2-8y-7=0
y=7; x=49

Like? Yes (1) | No   

D.Gnaphika   10 years AGO

let fathers present age be f and son,s present age be s then according to conditions f-1=8(s-1) n f=s^2
so sloving above equations we get s=7 and f=49

Like? Yes (1) | No   

hareesh   10 years AGO

suppose 1 year ago 6,48
then present 7,49=>7^2=49
so their present ages is 7,49

Like? Yes (1) | No   

AMIT SINGH   10 years AGO

current age of father and son be x and y.
so, x=y^2 -----(1)
and 1 year ago, the relation is
x-1=8(y-1)
x+7=8y
substituting equation 1
y^2-8y+7=0
so, y=1 or 7
selecting 7 as our required solution
hence, age of son=7 years
age of father=49 years.

Like? Yes (1) | No   

aditya   10 years AGO

quadratic and linear eqautions according to the given question give the answer as option 9 on solving

Like? Yes (1) | No   

Saran kumar    10 years AGO

Equations:
r-1 = 8(s-1)
r = s^2
----
Substitute for "r" and solve for "s":
s^2-1 = 8s-8
s^2-8s+7 = 0
Factor:
(s-7)(s-1) = 0
Acceptable solution:
s = 7 yrs (son's age now)
----
r = s^2 = 49 (father's age now)

Like? Yes (1) | No   

shree   10 years AGO

465735h

Like? Yes (1) | No   

mansi garg   10 years AGO

F=S^2
F+1=8(S+1)
S^2-8S+7=0
S=7 F=49

Like? Yes (2) | No (4)  

ANUP KUMAR   10 years AGO

let age of the son is S and age of the father is R
A/Q before 1 year age of the son is S-1 and that of father is R-1.so, at this time R-1=8(S-1)---(1)
now at present time R=S^2---(2)
by solving (1) and (2)
S=7 & R=49
option (9) is correct

Like? Yes (3) | No (5)  

Bhavna   10 years AGO

current father age=f
son age=s
f=s^2
(f-1)=8(s-1)
(s^2-1)=8(s-1)
s=7
f=s^2=49

Like? Yes (1) | No (3)  

Devesh Agrawal   10 years AGO

Let father and son's current age be x and y respectively. Then,
x-1=8(y-1) and x=y^2. Hence, solving y^2-8y+7=0.
x=49,y=7

Like? Yes (1) | No (3)  

Kowshik Sarker   10 years AGO

Let father's and son's present age respectively x and y. So according to the given condition
(x-1)=8(y-1)....and x=y^2
solving this 2 equation we get y=7,x=49
which is option 9.

Like? Yes (1) | No (3)  

Anand Singh   10 years AGO

let father's present age is x,
and son's present age is y,
now according to question.......
(x-1)=8(y-1)------------------(1)
and

x=y^2---------------------(2)
by solving both equation we find
x=49.
y=7.
so
father's present age is 49
and son's present age is 7.

Like? Yes (1) | No (3)  

vishnuvardhan   10 years AGO

let fathers be f sons be s
f-1=8*(s-1)
f=s^2;
solving
f=8s-7
s^2-8s+7=0
s=1,7
s cannot be1
s=7
f=49

Like? Yes (1) | No (3)  

Vishal Chugh   10 years AGO

Let the age of father be 'f' and that of son be 's'
The two equations formed will be:
f - 1 = 8(s - 1) ---- (1)
f = s^2 ---- (2)

Solving the two equations we get:
s = 1, 7
But for s = 1, the answer will be invalid, therefore, the solution will be s = 7 and f = 49

Like? Yes (1) | No (3)  

pankaj kumar   10 years AGO

f-1 =8(t-1)
f=t^2

so f=1,7
1 is not possible
so 7,49

Like? Yes (1) | No (3)  

Rahul Das   10 years AGO

let 1 years ago
son's age=x
father's age=8x
present age of
son=x+1
father=8x+1
so that according to question 8x+1=(x+1)^2
x=6
so son's present age=x+1=7
father's present age=8x+1=49

Like? Yes (1) | No (3)  

shreyansh pandey   10 years AGO

let,
present age of son = x
then,
present age of father = x^2
One year ago,
age of father = x^2 - 1
age of son = x - 1
according to question
father\'s age = 8 * son\'s age
then,
x^2 - 1 = 8 * ( x - 1 )
x^2 - 1^2 = 8 * ( x - 1)
( x - 1 )( x + 1 ) = 8 * ( x - 1)
x + 1 = 8
x = 7
thus
present age of son = 7
&
present age of father = 7^2 = 49
answer : 9)7,49

Like? Yes (2) | No (4)  

MRITUNJAY KUMAR   10 years AGO

A year ago let x be the age of son,then father age will be 8x.
present age of son and father will be (x+1)and (8x+1) resp.
A/Q (x+1)^2=8x+1;x=0&6,
hence present age of son and father will be 7 and 49 resp.

Like? Yes (1) | No (3)  

Gaurav shah   10 years AGO

fathers present age=x
sons present age=y
(x-1)=8(y-1) and x=y^2
y^2-1=8y-1
y=7 and x=49

Like? Yes (1) | No (3)  

VIMALRAJ V   10 years AGO

consider present age of father is 49.
his age is square of his son age i.e. 7 square is 49.
a year ago means father age is 48 then it is 8 times the son age(6*8=48).
Answer is 49,7 option 9

Like? Yes (1) | No (3)  

haritha   10 years AGO

let the present age of father be \'f\' and son be \'s\'
f=s*s
f-1=8(s-1)
8s-f=7
8s-s*s=7
(s-7)*(s-1)=0
s=7, s=1
s=7 and f=49

Like? Yes (1) | No (3)  

KODEISWARAN ELANGOVAN   10 years AGO

f=s^2
f-1=8*(s-1)
by this eqns says that the answer is s=7&f=49

Like? Yes (1) | No (3)  

guddu   10 years AGO

A year ago,
let sun's age=x
father's age =8x
now,
present age of son's=x+1
present age of father's=8x+1
A/Q,
8x+1=(x+1)^2
after solving we get,x=6 i.e son's age a year ago
and their present age is 7,and father present age is 49.

Like? Yes (1) | No (3)  

AMIT KUMAR ANAL   10 years AGO

Son- x
Father- x^2
(X^2-1)/(X-1)=8

Like? Yes (1) | No (3)  

Devendra Marghade   10 years AGO

If age of father=F, Son=S
F-1=8(S-1), F-8S=-7 ---(i) &
F=S^2 ---(ii)
From (i) & (ii), S^2-8S+7=0, (S-1)(S-7)=0, S=7
So F=S^2=49

Like? Yes (1) | No (4)  

Dr.Dipin Singh   10 years AGO

If F is father's age and S is son's age now,
F-1=8*(S-1)
F=s^2,
solving these eqns, we get
S=7,1 (ignored)
so ages are 7,49.

Like? Yes (3) | No (6)  

Vaishali Gupta   10 years AGO

Let son's age -x
Fatherr age-x^2
1 year ago,
Fathet age -8(x-1)
8(x-1)+1=x^2
0n solving,
X=7
Son age-7,father age-49

Like? Yes (1) | No (4)  

pawan kumar chhipa   10 years AGO

let age of father and son is
x : y
a year ago is
x-1 = 8(y-1)
x-1-8y+8=0 ..........eq 1
present age is

x= y^2 .......eq2
solve we get
y=7
and x= 49
ans is 9) son 7 father is 49

Like? Yes (1) | No (4)  

Anupam Banerjee   10 years AGO

Let before 1 year sons as was x year.
So, father's age was = 8x year;

Present age of son = x+1
Present age of father = 8x+1

And as per the information provided
8x+1 = (x+1)^2
By solving it we got, x = 6;

So, present age of father = 8x+1 = 49 year;
present age of son = x+1 = 7 year;

Like? Yes (1) | No (4)  

Gitanjali K   10 years AGO

father's present age= x yrs
son's present age=y yrs

given, a year ago, the father's age was 8 times his son's age
x-1=8(y-1)........eq(1)

given, father's present age is square of his son's age
x=y^2............eq(2)

solving eq(1)&(2)
we get y=7 and x=49
so option (9) is the answer

Like? Yes (1) | No (4)  

SAM   10 years AGO

7^2 = 49
1 year ago son's age was 6 and father's age was 48 which is 8 times of son's age.

Like? Yes (1) | No (4)  

ram   10 years AGO

Because 7 is a square of the 49 and also in a previous year a fathers age is 48 and sons age 6 , so it is 8 times greater of sons age . So 7,49 is the answer

Like? Yes (1) | No (4)  

Bobby Nayak   10 years AGO

Present age of son= x
thus, present age of father= x^2

1 year ago,
son's age= x-1
father's age= x^2-1

Since father's age is 8 times the son's age 1 year ago, the equation formed is

x^2-1=8(x-1)
x^2-1=8x-8
x^2-8x+7=0
x^2-7x-x+7=0
x(x-7)-1(x-7)=0
(x-1)(x-7)=0
thus x=7
x cannot be 1 as father's age cannot be 1

Correct answer is option 9
Son's age= 7yrs
Father's age= 49yrs

Like? Yes (1) | No (4)  

pranshu goyal   10 years AGO

as,7's square is 7*7=49.And a year ago his son's age would be 6 and his age would be 48 and 6*8=48. that's the reason why the option 9 is correct

Like? Yes (2) | No (5)  

Mohammed Farook.S   10 years AGO

Let father's age = f; and son's age = s;
a year ago, f-1=s-1;
the father's age was 8 times his son's age, f-1=8(s-1)
f-1=8s-8;

And,
His present age is square of his son's age.
f=s2;

Substitute,
f-1=8s-8;
s2-1=8s-8;
s2-8s=-7;
s2-8s+7=0;
(s-1)(s-7)

so son,s age s=7;
father's age =f2=(7)2=49

so option 9 is correct.

Like? Yes (2) | No (5)  

sanghavi    10 years AGO

let x be fathers age and y be son's age
by the condition
x-1=8(y-1)
x=y^2
by substituting x
y^2-1=8y-8
y^2-8y+7=0
by solving above equation we get y=1 and y=7
then x=y^2
x=49

Like? Yes (1) | No (4)  

Santosh Sharma   10 years AGO

Let sons present age be S, and father's be F

A year ago
8(S-1)=F-1 -----(i)

And now
S*S=F -----(ii)
Substituting the value of F in (i)

Eq.
S*S-8S+7=0

quadratic eq. roots =1,7.
1 is not possible as S*S=F,
as Father and Son's Age can't be equal.

The answer is 7
and its square (father's age)=49.

Like? Yes (1) | No (4)  

Dinesh thatti   10 years AGO

r-1 = 8(s-1)
r = s^2
----
Substitute for \"r\" and solve for \"s\":
s^2-1 = 8s-8
s^2-8s+7 = 0
Factor:
(s-7)(s-1) = 0
Acceptable solution:
s = 7 yrs (son\'s age now)
----
r = s^2 = 49 (father\'s age now)

Like? Yes (1) | No (4)  

Varunraj Reddy   10 years AGO

Option 9 follows both conditions.

Like? Yes (1) | No (4)  

Gourango   10 years AGO

Let their current age be F and S
so, (F-1)=8(S-1)...(1)
and F=S^2...(2)
solving (1) and (2)
s^2-1=8S-8
or S^2-7S-S+7=0
or (s-7)(s-1)=0
s can't be 1
so, s=7 F=49

Like? Yes (1) | No (4)  

MUNISH YADAV   10 years AGO

Let present ages of father and son be f and s years.
So, f-1=8(s-1)
f=s^2
Solving we get f=49,s=7

Like? Yes (1) | No (4)  

vandana   10 years AGO

one year ago,father age=8x if the son age was x.
present age of father is 8x+1.and the son age is x+1.
A/Q,8x+1=(x+1)^2
=>8x+1=x^2+1+2x
=>x^2-6x=0
=>x=6,
present age of father=8x+1=49,sons age=x+1=7

Like? Yes (1) | No (4)  

23 Jun 2014 Sequence

How many terms at most can be taken in sequence
1, 74, 894, 9688, 88997, 897999

OPtion

1. 10
2. 20
3. 8
4. 9
5. 1177
6. 25
7. 597
8. 10000000
9. 200000000
10.Infinite

Solution

This sequence contains 1 digit extra in every next number.
1 | 74 | 894 | 9688 | 88997 | 897999
=> 1 | 7 + 4 |8 + 9 + 4| 9 + 6 + 8 + 8| 8 + 8 + 9 + 9 +7|8 + 9 + 7 + 9 + 9 + 9 |
=> 1| 11| 21 | 31 | 41 | 51| ….
In ninth term sum of all digit of the number will be 81.
After that it should be 91 in tenth term which is not possible because the greatest
number of ten digit is 9999999999, the sum of its all digits = 9 × 10 = 90

Correct Option: 4 Best Solution (11)

Sundar Kumar   10 years AGO

1 1 1
74 11 2
894 21 3
9688 31 4
88997 41 5
897999 51 6
8989999 61 7
89999999 71 8
999999999 81 9

Like? Yes (21) | No (4)  

Dr.Dipin Singh   10 years AGO

Number of digits in each term is increasing by 1 and sum of digits in increasing by 10.
1.. number of digits =1.... sum of digits 1
74....................2..................11
894...................3..................21
..
..
999999999..............9..................81
not possible to get sum as 91 with 10 digits.
so max terms in series=9 .. option 4

Like? Yes (9) | No (2)  

Anita   10 years AGO

1,.. digits 1.. sum ..1
74, .. digits 2... sum ..11
894,
9688,
88997,
897999
..
...
999999999... digits 9.. sum =81
so 9 terms at the most can be taken in sequence
as 10 digits can not give sum as 91.

Like? Yes (5) | No (2)  

Inder   10 years AGO

number of digits increase by 1 up to 9 digits and sum of digits increase by 10 up to 81.

Like? Yes (4) | No (2)  

Anupam Banerjee   10 years AGO

The sum of all digits in a no. in the series is increasing by 10 one after another.
Like,
1 = 1;
74 = 11;
.......
88997 = 41;
897999 = 51;

But when sum is = 91;
it cant be denoted by a 10 digit number, as max sum of 10 digits can be 90;
So there can be max 9 number in the sequence.

Like? Yes (2) | No (1)  

Prasanth   10 years AGO

1
7+4=11
8+9+4=21
9+6+8+8=31
8+8+9+9+7=41
...........51
...............61
...................71
......................81
..........................91
so the answer is option 4.9

Like? Yes (1) | No (1)  

Niraj   10 years AGO

Add every digit of number ttill it becomes single digit number. So maximum 9 terms can be in series.

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

1+0=1
7+4=11=>1+1=2
8+9+4=21=>2+1=3
9+6+8+8=31=>3+1=4
8+8+9+9+6=41=>4+1=5
8+9+7+9+9+9=51=>5+1=6

in this way addition of numbers will be at the max 9 because when addition of no. is 10 it will again get converted into 1
so option (4) is the answer...

Like? Yes (2) | No (3)  

Yogesh   10 years AGO

it consist the difference of one digit.
1/74/894/9688/88997/897999
1/7+4/8+9+4/9+6+8+8/8+8+9+9+7/8+9+7+9+9+9
1/11/21/31/41/51 and so on
in the 9th term sum will be 81
at 10th it contains 91 but the largest number of 10 digit is 9999999999 i.e. 9*10=90
91 is greater than 90 so only 9 terms are possible in this sequence...

i hope my answer and reason is correct..

Like? Yes (1) | No (2)  

pankaj kumar   10 years AGO

1 = 1
74 = 7+4 =11 = 1+1 = 2
894=8+9+4=21=2+1 = 3
9688=9+6+8+8=31=3+1 = 4
similarly
9 sequence is possible

Like? Yes (1) | No (2)  

pawan kumar chhipa   10 years AGO

at most 9 because
the addition of term became a series of like
1,11,21,31,41,51,61,71,81

and the maximum addition of any value is 81 is
999999999=81(addition)
ans is 4) 9

Like? Yes (1) | No (2)  

20 Jun 2014 Coded language

By applying some arithmetic operations, we got.
1234 = 1
2345 = 2
4567 = 19
5678 = 8
Then 6789 = ?

OPtion

1) 9
2) 4
3) 30
4) 40
5) 8
6) 10
7) 1
8) 3
9) 25
10)None of these

Solution

Here
1234 = 1*2*3*4/1+2+3+4 = 24/10 = 12/5
after dividing 12 by 5 we get 2 as divisor and 2 as reminder
2/2 = 1
4567 = 4*5*6*7/4+5+6+7 = 840 /22 = 420/11
after dividing 420 by 11 we get 38 as divisor and and 2 as reminder
38/2 = 19

on applying same rule
6789
=6*7*8*9/6+7+8+9 = 3024/30 = 1512/15 = 504/5
after dividing 504 with 5 we get 100 as divisor and 4 as reminder
100/4 = 25

Option 9)

Correct Option: 9 Best Solution (1)

RAKESH   10 years AGO

multiply digits tgen divde by sum of digits then Q/R Gives result.

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