M4maths Previous Puzzles

08 May 2014 Time, speed and distance

The speed of a boat in still water is 11 km/hr. It can go 12 km upstream and return downstream to the original point in 2 hours 45 minutes. Find the speed of the stream.

OPtion

1) 2 km/hr
2) 3 km/hr
3) 4 km/hr
4) 5 km/hr
5) 6 km/hr
6) 7 km/hr
7) 8 km/hr
8) 9 km/hr
9) 10 km/hr
10)None of these

Solution

Solve
Speed of the boat in still water = 11 km/hr
Let the speed of stream = x km/hr
speed upstream = (11-x) km/hr
speed of downstream = (11+x) km/hr

According to the given condition
{12/(11+x)}+{12/(11-x)} = 11/4

Solve

Speed of the stream = 5 km/hr

Option 4)

Correct Option: 4 Best Solution (29)

Ann Theressa   10 years AGO

Let the speed of stream be x

Speed of boat in still water = 11
Speed of boat upstream = 11-x
Speed of boat downstream = 11+x

Distance = 12
Distance/speed = time

12/(11-x) + 12/(11+x) = 2 hours 45min
12*(22/(121-x^2) = 11/4
x^2 = 25
x = 5

Speed of stream = 5km/hr

Like? Yes (52) | No (21)  

susmit   10 years AGO

Let the speed of the stream be s km/hr.
Speed of boat in still water = 11km/hr
Speed of boat in upstream = (11- s) km/hr
Speed of boat in downstream = (11 + s)km/hr
Distance = 12km.
Therefore 12/(11-s)+12/(11+s) = 2(3/4)hr
12(11+s+11-s)/(11-s)(11+s) = 11/4
12*22/(121-s^2) = 11/4
12*2/(121-s^2) = ¼
Solving, s = 5
Speed of stream = 5km/hr
Hence option no.(4)

Like? Yes (35) | No (7)  

SAMPATH KUMAR   10 years AGO

The speed of boat in still water=11 km/hr distance=12 km
total time= 2 hrs 45 mins=11/4
let the speed of stream be x
and
the time taken by boat in still water be y
12/11=y
12/(11+x) + 12/(11-x)=11/4 (132-12x+12x+132)/121-x2 =11/4

264=1331-11x2/4
1056=1331-11x2 1
331-1056=11x2
275=11x2
25=x2
5=x
so the answer is 5km/hr

Like? Yes (11) | No (4)  

Devendra Marghade   10 years AGO

If the speed of the stream= x
12/(11+x) + 12/(11-x) = 11/4
On solving, 11x^2=275, x=5

Like? Yes (7) | No (3)  

Sanjeewani Indurkar   10 years AGO

let x be the speed of the stream.
upstream speed = (11-x) and downstream speed = (11+x)
Upstream Time=12/(11-x)[12kms is the distance]
Downstream Time=12/(11+x)
Total time =Upstream time + downstream time.

2hrs 45 mins =11/4 hours.
11/4=12/(11-x)+12/(11+x)

After solving x= +5 or -5. Speed is scalar qty therefore answer is 5.

Like? Yes (7) | No (4)  

DILEEP KUMAR   10 years AGO

let x km/hr be the speed of the stream
distance= 12km
time taken to upstream= 12/(11-x)
time taken to downstream = 12/ (11+x)
total time = 2hr 45 min = 11/ 4 hrs
so
(12/(11-x))+(12/(11+x))= 11/4
=> x= 5
i.e speed of the stream is 5 km/hr

Like? Yes (6) | No (3)  

MD SOHAIL AKHTER   10 years AGO

let the speed of stream be x km/hr
A/Q
12/(11+x)+12/(11-x)=11/4
on solving we get x= 5km/hr

Like? Yes (6) | No (4)  

RAKESH   10 years AGO

12[1/(11+x) + 1/(11-x)] = 2 3/4 = 11/4

=> x=5

Like? Yes (5) | No (3)  

PAWAN KUMAR   10 years AGO

[12/(11-x) + 12/(11+x)]=2.75
=>x=5 km/hr

Like? Yes (4) | No (2)  

Dada Khalandar   10 years AGO

t x=speed of stream
11+x=speed of boat downstream
11-x=speed of boat upstream
2 hr and 45 min=2.75 hr
Travel time=distance/speed
**


12/(11+x)+12/(11-x)=2.75
LCD:(11+x)(11-x)
12(11-x)+12(11+x)=2.75(11+x)(11-x)=2.75(121-x^2)=332.75-2.75x^2
132-12x+132+12x=332.75-2.75x^2
264=332.75-2.75x^2
2.75x^2=332.75-264=68.75
x^2=68.75/2.75=25
x=5
speed of stream= 5 km/hr

Like? Yes (4) | No (2)  

sushmita pattanaik   10 years AGO

Speed of boat in still water=x
Speed of stream=y
Total time taken= (12/(x+y))+(12/(x-y)) = 2+3/4 hrs
Solve for y

Like? Yes (7) | No (6)  

Bhagyashree Bhatt   10 years AGO

Let the speed of the stream be x km/hr.
Speed of boat in still water = 11km/hr
Speed of boat in upstream = (11- x) km/hr
Speed of boat in downstream = (11 + x)km/hr
Distance = 12km.
A.T.Q 12/11-x+12/11+x = 2(3/4)hr
12(11+x+11-x)/(11-x)(11+x) = 11/4
12x22/121-x2 = 11/4
12x2/121- x2 = ¼
121- x2 = 96
X = sqrt.(25) = 5
Speed of stream = 5km/hr.

Like? Yes (4) | No (3)  

Lavanya   10 years AGO

let distance=x
let speed of boat in still water=v1
let speed of stream=v2
as speed=distance/time
total time taken for journey=t=x/(v1+v2)+x/(v1-v2)
given x=12km
v1=11km/hr
t=2hours 45min=2+45/60 hours=11/4 hours
therefore 12/(11+v2)+12/(11-v2)=11/4
so, v2=5km/hr

Like? Yes (4) | No (4)  

DINESH KUMAR   10 years AGO

Let the speed of the stream be x km/hr.
Speed of boat in still water = 11km/hr
Speed of boat in upstream = (11- x) km/hr
Speed of boat in downstream = (11 + x)km/hr
Distance = 12km.
A.T.Q 12/11-x+12/11+x = 2(3/4)hr
12(11+x+11-x)/(11-x)(11+x) = 11/4
12x22/121-x2 = 11/4
12x2/121- x2 = ¼
121- x2 = 96
X = sqrt.(25) = 5
Speed of stream = 5km/hr.

Like? Yes (3) | No (3)  

AMIT   10 years AGO

let speed of stream =x km/hr
12/(11+x)+12/(11-x)=2*45/60
after solving we will get x=5

Like? Yes (4) | No (4)  

C.Aarthi   10 years AGO

speed in stream =x
Speed in still water =11
upsteam speed=11+x
downstream spead=11-x
todal distance =12
And time =165/60

(12/11+x) + (12/11-x) = 165/60
ans :x=5

Like? Yes (3) | No (3)  

Barun kumar singh   10 years AGO

> let speed of stream=x
> upstream=11-x , downstream=11+x
> time =distance /speed
> 12/(11+x)+12/(11-x)=2+(45/60)
> 12(11-x)+12(11+x)=2.75(11+x)(11-x)
> 132-12x+132+12x =2.75(121-x^2)
=332.75-2.75x^2
> 264=332.75-2.75x^2
> 2.75x^2=332.75-264
> x^2=68.75/2.75
=25
Ans x=5 km/hr

Like? Yes (2) | No (3)  

Udhaya kumar   10 years AGO

let x as speed of stream
(12/(11-x))+(12/(11+x))= 2.75....
by solving this we get x = 5.........

Like? Yes (3) | No (4)  

SONU GUPTA   10 years AGO

12/(11+x)+12/(11-x)=2.75
LCD:(11+x)(11-x)
12(11-x)+12(11+x)=2.75(11+x)(11-x)=2.75(121-x^2)=332.75-2.75x^2
132-12x+132+12x=332.75-2.75x^2
264=332.75-2.75x^2
2.75x^2=332.75-264=68.75
x^2=68.75/2.75=25
x=5
speed of stream= 5 km/hr

Like? Yes (2) | No (3)  

Gitanjali K   10 years AGO

let speed of stream=x
speed of boat downstream=11+x
speed of boat upstream=11-x

2 hr 45 min=2.75 hr

time=distance/speed

12/(11-x)+12/(11+x)=2.75
12[1/(11-x)+1/(11+x)]=2.75
12[22/121-x^2]=2.75
22/121-x^2=2.75/12
22*12/2.75=121-x^2
96=121-x^2
x^2=25
x=5
therefore,speed of stream = 5 km/hr

Like? Yes (4) | No (5)  

ravi prakash   10 years AGO

121-96=stream2
stream=5km/hr

Like? Yes (3) | No (4)  

murari kumar   10 years AGO

Let speed of stream.is=x
Therefore
{12÷(11+x)}+{12÷(11-x)}=2*(45÷60)
After solving this equation
X=5km/hr

Like? Yes (3) | No (4)  

chandan jha   10 years AGO

12/(11-x)+12/(11-x)=11/4;
x=5;

Like? Yes (3) | No (4)  

NAGENDRA P   10 years AGO

Let x=Speed of stream
11+x=Speed of boat downstream
11-x=Speed of boat upstream
travel time=2.75hour
travel time=Distance/Speed
12/(11+x)+12/(11-x)=2.75
x=5km/hr
So option(4)

Like? Yes (3) | No (4)  

harshal agrawal   10 years AGO

12/(11+x) + 12/(11-x) = 11/4

Like? Yes (2) | No (3)  

Harivignesh.B   10 years AGO

let x=speed of stream
11+x=speed of boat downstream
11-x=speed of boat upstream
2 hr and 45 min=2.75 hr
Travel time=distance/speed

12/(11+x)+12/(11-x)=2.75
LCD:(11+x)(11-x)
12(11-x)+12(11+x)=2.75(11+x)(11-x)=2.75(121-x^2)=332.75-2.75x^2
132-12x+132+12x=332.75-2.75x^2
264=332.75-2.75x^2
2.75x^2=332.75-264=68.75
x^2=68.75/2.75=25
x=5
speed of stream= 5 km/hr

Like? Yes (2) | No (3)  

indrajeet yadav   10 years AGO

let speed of stream=x kmph
12/11-x+12/11+x=11/4
on solving this equation
x=5 kmph

Like? Yes (2) | No (3)  

vicky kumar   10 years AGO

Let the speed of the stream be x km/hr.
Speed of boat in still water = 11km/hr
Speed of boat in upstream = (11- x) km/hr
Speed of boat in downstream = (11 + x)km/hr
Distance = 12km.
A.T.Q 12/(11-x)+12/(11+x) = 2(3/4)hr
12(11+x+11-x)/(11-x)(11+x) = 11/4
12*22/(121-x^2)=11/4
BY solving above
x=5

Like? Yes (2) | No (4)  

rajani   10 years AGO

the total time taken to complete the journey=2hrs45mins
time=distance/speed
i.e,11/4=(12/11-x)+(12/11+x),
on solving this we get x=5,
that is speed of stream=5km/hr

Like? Yes (3) | No (5)  

07 May 2014 Solve

A sector of circle of radius equal to one fourth of the diagonal of square is cut from the square taking one corner of the square as centre. If side of the square is 4 cm. then area of the remaining part is

OPtion

1) 15.68 cm^2
2) 14.43 cm^2
3) 12.78 cm^2
4) 10.34 cm^2
5) 14.73 cm^2
6) 13.14 cm^2
7) 14.14 cm^2
8) 11.88 cm^2
9) 11.83 cm^2
10)None of these

Solution

Diagonal of the square = 4√2 cm.
Hence radius of the circle = 4√2/4 cm. = √2 cm.
Area of the sector of circle = 1/4 (π* radius2)
= 1/4 (π* (√2)2 )
= π/2
Area of the square = 4*4 = =16 cm.2
Hence area of remaining part = 16- (π/2) cm.2
= 14.43 cm^2

Option 2)

Correct Option: 2 Best Solution (27)

PAWAN KUMAR   10 years AGO

4^2-(3.14*(2^1/2)/4)=14.43 cm^2

Like? Yes (1) | No   

Nimisha Pandey   10 years AGO

area of sector=90/360*2
area 0f square=16
remaining area=area of sqr-area of sector=14.43

Like? Yes (1) | No   

chandan jha   10 years AGO

16-3.14*1/2=14.43;

Like? Yes (1) | No   

Param Kothari   10 years AGO

Two adjacent sides of a square and its diagonal form
a 45-45-90 triangle
Thus diagonal = (Root of 2)* side Threfore diagonal = 4(Root of 2) cm
Therfore radius of circle =1/4 * diagonal=0.25*4(Root 2)=(root 2)
Angle of the sector=90
Thus its area=(90/360)*3.14* (Root 2)^2
=2*3.14*0.25
=1.57
Area of square= side^2 = 4^2= 16
Therefore area of remaining part = 16 - 1.57
=14.43 cm

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

Area of square = 4*4=16 cm^2
diagonal of square = Sq root (4^2+4^2)= 4 Root 2
radius of circle taking one corner of the square as centre= (4 root 2)/4= root 2.
Area of remaining part = 16- (pi*(root2)^2)/4= 14.43 cm^2

Like? Yes (3) | No (3)  

MD SOHAIL AKHTER   10 years AGO

side of the square =4cm
diagnol of square= 4√2cm
diameter of square= 4√2/4=√2cm
area of circle under square= π*(√2)^2*(1/4)
=π/2 cm
area of remaining part in square= 4^2-1.57=14.43cm
ans option(2)

Like? Yes (3) | No (3)  

Ann Theressa   10 years AGO

Side of square, a = 4cm
diagonal of square = a*sqrt(2)
=4*sqrt(2)

Radius of sector,r = 1/4 of diagonal
= 1/4*4*sqrt(2)
=sqrt(2)

Area of sector = n/360*pi*r^2
=90/360*pi*r^2
=1/4*22/7*2
11/7

Area of square = a^2
=4^2
=16

Area of remaining part = 16-11/7
=101/7
=14.43 cm^2

Like? Yes (3) | No (4)  

azharshahid01@gmail.com   10 years AGO

Side of the Square=4
So, diagonal of square= Square root of (4^2+4^2)= Square root (32)
Radius of circle is 1/4th of diagonal. So radius= square root(32)/4
Area of circle = 3.14*(32/16)= 6.28.
Circle center is a corner of square so 1/4th of circle will be in square.
Circle 1/4th area= 6.28/4= 1.57

Area of square= 4*4= 16
Area of remaining square which is not covered by circle= 16-1.57 = 14.43

Like? Yes (2) | No (4)  

SriS   10 years AGO

total area of circle is -- 6.28cm^2
sector area is -- 1.57cm^2

so remaining area of circle is = 4.71cm^2
total area of square is = 16cm^2
remaining area of square is = 16-1.57 = 14.43cm^2

Like? Yes (1) | No (3)  

muni   10 years AGO

square radius is 2 so diagonal is 4 sqrt(2)
one corner is the center so it covers 90 degrees with sqrt(2) radius area in square.
required area= square area- sector area
=16-1.57( formula: sectorangle/2 * pi/180* r^2 )=14.43

Like? Yes (1) | No (3)  

Gitanjali K   10 years AGO

let radius of circle=r cm
diagonal of square=d cm
side of square=a cm

given, radius of circle equal to one fourth of the diagonal of square
so r=(1/4)d ...eq(1)
and d=2^1/2 * a
d=2^1/2 * 4 (given side of square=4cm)
therefore d=5.66 cm
put value of d in eq(1) we get
r=1.415 cm

Now, area of square=(side)^2
=4^2
=16 cm^2

And area of sector=(1/2)*angle in radian*(radius)^2
=(1/2)*(90*pi/180)*(1.415)^2
=1.57 cm^2

so,area of the remaining part is =(16-1.57)cm^2
=14.43 cm^2
so option (2) is the answer

Like? Yes (1) | No (3)  

KAUSTUBH BHARDWAJ   10 years AGO

AREA OF REMAINING PART=(AREA OF SQUARE)-((3.14)*(R^2)/4)
SO AREA OF SQUARE=16
2ND PART=3.14*2/4=1.57
SO
AREA OF REMAINING PART=16-1.57=14.43CM^2

Like? Yes (1) | No (3)  

gaurav arora   10 years AGO

ans is 16-1.57=14.43

Like? Yes (1) | No (3)  

Satish Zod   10 years AGO

(4^2) - ((((Sqrt(4^2+4^2))/4)^2)*22/7)/4 = 14.43

Like? Yes (1) | No (3)  

khushboo singh   10 years AGO

side of square= 4cm
so r=sqroot(2)*4/4=sqrt(2)
as corner of square is centre =>sector makes angle *area of circle
so area remaining=(4)^2-(1/4)(3.14*sqrt(2)*sqrt(2))
=14.43

Like? Yes (1) | No (3)  

harshal agrawal   10 years AGO

16-(.25*3.14*sqrt2)
= 14.43

Like? Yes (1) | No (3)  

Md.Sultan Khichi   10 years AGO

side of square =4cm
so diagonal=4 sqrt(2)
so radius=sqrt(2)
area of circle=pi*r^2=6.28
Hence area of that sector of circle will be 1/4*(6.28)=1.57
so.area of remaining part of the square=16-1.57=14.43cm^2..ans

Like? Yes (1) | No (3)  

P Dhananjaya Dora   10 years AGO

it is given that side of a square is 4 cm.
diagonal^2=32
radius^2=2
remaining area=area of square-area of sector
=16-(22*radius^2*angle of sector/7*360)
angle of sector is 90 as one of the corner is the center of the circle
solve the above

Like? Yes (1) | No (3)  

indrajeet yadav   10 years AGO

radius of circle=1/4*diagonal of square
=1/4*4sqrt(2)
=sqrt(2)
area of reamining part=total area of square-area of sector of circle=(4)^2-pi*[sqrt(2)]^2*90/360
=16-pi*2*1/4
=16-pi*1/2
=16-1.57
=14.43 cm^2

Like? Yes (1) | No (3)  

Praful   10 years AGO

Area of square = 4*4 =16 cm2
Area of sector = (90/360)*3.14*[sqrt(2)]2 = 1.57 cm2
Remaining area = 16-1.57 = 14.43 cm2

Like? Yes (1) | No (3)  

RAKESH   10 years AGO

r= d/4 = √2x/4 = √2*4/4 = √2
area of sector = pi*r^2/4 = pi/2 = 1.57

area of remaining part = 4^2 - 1.57 = 14.43 cm^2

Like? Yes (1) | No (4)  

SHEREENA NISHAD   10 years AGO

required area = area of square - area of sector
area of square = 16
area of sector = (angle of sector /360)* pi * r^2
angle of sector = 90
radius, r = d/4 where d is diagonal of square and d= side of square * square root (2)= 4*sq. root of(2)
r = sq. root (2)
r^2 = 2
req. area = 16- (90/360)* (22/7)* 2
= 16 - (11/7)
= 14.43 cm^2

Like? Yes (1) | No (4)  

Devendra Marghade   10 years AGO

As 1/4 of the diagonal of square=radius of circle
So,Radius of a circle=(1/4)*Sqrt[4^2+4^2]
=(1/4)Sqrt(32) =Sqrt(2)
Area of a sector of a circle at corner of square
=(1/4)*Pi*[Sqrt(2)]^2=(1/4)*(22/7)*2=11/7
Area of the remaining part of a square=4^2-(11/7)
=101/7 =14.429

Like? Yes (1) | No (4)  

Mukesh Nayal   10 years AGO

remaining area=16-3.14/2=14.43

Like? Yes (1) | No (4)  

ABHOY KUMAR   10 years AGO

radius of sector=r
side of square=s
diagonal(d)=s*sqrt(2)
r=1/4*d
r=1/4*(4*sqrt(2))
r=sqrt2
remaining area(A)=(area of square)-(area of sector)
A=(4^2)-(1/4*(3.14*2))
=14.43cm^2

Like? Yes (1) | No (4)  

rajani   10 years AGO

side of square=4cm
radius of circle=1/4*sqrt(4^2+4^2)=sqrt(2)cm
area of sector is 1.57cm^2
and the total area of square=16cm^2
Now the remaining part will be
16-1.57=14.43cm^2

Like? Yes (1) | No (4)  

srilakshmi   10 years AGO

diagonal of square is 4*sqrt2
radius of circle is -- sqrt2 cm
total area of circle is -- 6.28cm^2
sector area is -- 1.57cm^2

so remaining area of circle is = 4.71cm^2
total area of square is = 16cm^2
remaining area of square is = 16-1.57 = 14.43cm^2

Like? Yes (1) | No (4)  

06 May 2014 Solve

The sum of squares of three successive integers is 27650. Sum of these integers is

OPtion

1) 297
2) 256
3) 198
4) 234
5) 304
6) 252
7) 312
8) 288
9) 228
10)none of these

Solution

(a-1)^2 + a^2 + (a+1)^2 = 27650 , solve the equation

Correct Option: 8 Best Solution (49)

Ann Theressa   10 years AGO

Let the integers be (x-1), x, and (x+1)

(x-1)^2 + x^2 + (x+1)^2 = 27650
x^2 - 2x + 1 + x^2 + x^2 + 2x +1 = 27650
3x^2 + 2 = 27650
3x^2 = 27648
x^2 = 9216
x = 96

Therefore the numbers are 95, 96 and 97
Sum = 95+96+97 = 288

Like? Yes (7) | No (3)  

DILEEP KUMAR   10 years AGO

let n-1,n,n+1 be the number
then 3n^2+2=27650
then 3n=288 which is sum of those numbers

Like? Yes (3) | No (1)  

MD SOHAIL AKHTER   10 years AGO

let the no. be x
three successive nos. are x, x+1,x+2
so, x^2+(x+1)^2+(x+2)^2=27650
on solving we get,
x=95
sum of the three given no. =95+96+97=288
ans option (8)

Like? Yes (3) | No (2)  

Varunraj Reddy   10 years AGO

Consider 3 successive integers are (x-1),x,(x+1)
Given sum of squares of these integers=27650
i.e,(x-1)^2+x^2+(x+1)^2=27650
By solving we get x^2=9216
x=96
Then sum of these integers=95+96+97=288

Like? Yes (2) | No (1)  

Mahalakshmi   10 years AGO

95^2+96^2+97^2=27650
95+96+97=288

so ans is 8)288

Like? Yes (3) | No (2)  

llamar   10 years AGO

take (x-1)^2+x^2+(x+1)^2=27650
=>x=96
the three successive elements is 95,96,97
ans:288

Like? Yes (1) | No   

SREEVIDHYA P P   10 years AGO

(n-1)^2+n^2+(n+1)^2=27650
Solving this we get 3n^2+2=27650
n^2=9216
n=96
(n-1)+n+(n+1)=95+96+97=288

Like? Yes (1) | No   

Suman Saurabh   10 years AGO

Let number are x , x+1 and x+2.
3x^2 + 6x + 5 = 27650
x=95
so sum = 95+96+97 =288

Like? Yes (2) | No (1)  

steffy edmond   10 years AGO

Ans: 8)288
Let the three consecutive integers be x, (x+1) and (x+2)
then sum of their squares = x^2+(x+1)^2+(x+2)^2=27650
solving x we get x=95
substituting the value of x and adding the integers we get 288.

Like? Yes (3) | No (2)  

Dolly   10 years AGO

If nos are (x-1),x,(x+1)
(x-1)^2+x^2+(x+1)^2= 27650
3x^2=27648
x^2=9216
x=96
nos are 95,96,97
sum of nos.= 288

Like? Yes (2) | No (1)  

chandan jha   10 years AGO

a^2+(a+1)^2+(a+2)^2=27650
3a(a+2)=27645
a(a+2)=9215
a(a+2)=95*97
a=95
so
a+a+1+a+2=288
ans will be 288;

Like? Yes (1) | No   

Ninipriyankaa   10 years AGO

the number is 979695 and 97^2+96^2+95^2=27650
and sum 97,96,95 is 288

Like? Yes (1) | No   

Pradeep   10 years AGO

95+96+97=288 {96^2+97^2+98^2 =27650}

Like? Yes (1) | No   

Ramsb   10 years AGO

x^2+(x^2+1)+(x^2+2)=27650
3x^2+6x-27645=0
x=95
95+96+97=288

Like? Yes (1) | No   

Gitanjali K   10 years AGO

Let 3 successive integers are x,x+1,x+2
Given:The sum of squares of three successive integers is 27650
Therefore equation will be
x^2+(x+1)^2+(x+2)^2=27650
x^2+x^2+2x+1+x^2+4x+4=27650
3x^2+6x+5=27650
3x^2+6x-27645=0
x^2+2x-9215=0
(Factors of -9215 are +97 and -95)
Therefore x^2+97x-95x-9215=0
(x+97)(x-95)=0
Therefore x=95
Next Successors are x+1=96 and x+2=97
therefore Sum of these Successive integers is: 95+96+97=288
So Option (8)is the answer

Like? Yes (1) | No   

Rajasekhar Reddy   10 years AGO

let the three numbers will be x,x+1,x+2

the sum of the squares of the three numbers is 27650

x^2+(x+1)^2+(x+2)^2 = 27650

x^2+2x-9215 = 0


solving this we get x=95

and the sum is 95+96+97 = 288

Like? Yes (1) | No   

vishnuvardhan   10 years AGO

x^2+(x+1)^2+(x+2)^2=27650
3x^2+6x-27645=0
x=95,-97
95+96+97=288

Like? Yes (1) | No   

SUDHARSHAN   10 years AGO

x^2+(x+1)^2+(x+2)^2 = 27650
x^2+x^2+1+2x+x^2+4+4x= 27650
3x^2 + 6x + 5 = 27650
3x^2 + 6x - 27645 = 0
x^2 +2x - 9215 = 0
X^2 +97x - 95x -9215 = 0
x( X + 97 ) -95( x + 97 ) = 0
(x+97)(x-95) = 0
x = 95
So
values of x, x+1 , x+2 is 95 , 96 , 97 .
sum of these values is 288

Like? Yes (1) | No   

S.SHAFI   10 years AGO

95^2+96^2+97^2 = 27650
95+96+97 = 288

Like? Yes (1) | No   

AMIT SINGH   10 years AGO

x^2+(x+1)^2+(x+2)^2=27650
=>3x^2+6x-27645=0
=>so, roots of x are 95 and -97.
then we take 95 as our required root
so, 95+96+97=288.

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

(x-1)^2 + x^2 + (x+1)^2 = 277650
by solving this we get x = 96
hence , numbers 95,96,97
95+96+97 = 288.........

Like? Yes (1) | No   

priya   10 years AGO

a^2 + (a+1)^2+ (a+2)^2 = 27645
a^2+2a-9215=0
a^2 +97a-95a-9215=0
a=95,-97
-97 is rejected, so a=95 hence 95+96+97 =288

Like? Yes (1) | No   

animesh bosu   10 years AGO

three (x+1),x, and (x-1)
then, x=96
and the sum is= 288

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

If three successive integers are x, x+1, x+2
then x^2+(x+1)^2+(x+2)^2=27650
x^2+2x-9215=0
(x+97)(x-95)=0, x=95
So integers are 95,96,97
Sum=95+96+97= 288

Like? Yes (2) | No (2)  

susmit   10 years AGO

27650 = 95^2 + 96^2 + 97^2
Therefore 95 +96 + 97 = 288
Hence, option no.8

Like? Yes (1) | No (1)  

Ashik Kuppili   10 years AGO

95^2 + 96^2 + 97^2 = 5528 + 5529 + 5530 + 5531 + 5532 = 27650

Like? Yes (1) | No (1)  

srilakshmi   10 years AGO

let us assume three consecutive no are...(x-1),x,(x+1)
so,
(x-1)^2+x^2+(x+1)^2 = 27650
.
.
.
by solving this equation we will get x = 96.
so,
95+96+97 = 288

Like? Yes (1) | No (1)  

rajani   10 years AGO

(x-1)^2+x^2+(x+1)^2=27650,by solving this x=96
And the sum will be 3x=3*96=288

Like? Yes (1) | No (1)  

SHEREENA NISHAD   10 years AGO

let three consecutive numbers are
(x-1), x, (x+1)
Sum of their squares
(x-1)^2 + (x)^2 + (x+1)^2 = 27650
3x^2 + 2 = 27650
3x^2 = 27648
x^2= 27648/3 = 9216
x= 96
So numbers are
95, 96, 97
Their sum = 288

Like? Yes (1) | No (1)  

Bhagyashree Bhatt   10 years AGO

95+96+97= 288
there square is 27650

Like? Yes (1) | No (1)  

SAMRIDHI   10 years AGO

let 3 values b (x-1)(x)(x+1)
(x-1)2+(x)2+(x+1)2=27650
x=sqrt(9216)
x=96
so 95+96+97=288

Like? Yes (1) | No (1)  

Sundar Kumar   10 years AGO

288/3=96. so let us consider three successive integers are 95, 96, 97.
sum of these integers=95+96+97=288
sum of squares of three successive integers =95^2+96^2+97^2=27650
so Answer option 8) 288

Like? Yes (1) | No (1)  

harshal agrawal   10 years AGO

let no be (x-1),x,(x+1)
then a/q
(x-1)^2+x^2+(x+1)^2=27650
=> x=96
thus sum is 95+96+97=288

Like? Yes (1) | No (1)  

SONU GUPTA   10 years AGO

right anwer will be 288

Like? Yes (1) | No (1)  

DHIRENDRA    10 years AGO

95^2+96^2+97^2=9025+9216+9409=27650
95+96+97=288

Like? Yes (1) | No (1)  

T.Aravinth kumar   10 years AGO

X=95.
95+96+97=288.

Like? Yes (1) | No (1)  

NIRUPOM GHOSH   10 years AGO

Let the numbers x,x+1,x+2.solve x^2+(x+1)^2+(x+2)^2=27650 we get x=95,x+1=96,x+2=97.The sum of three succ. Integer 288.

Like? Yes (1) | No (1)  

nitin siingla   10 years AGO

95+96+97=288
let any no. 'a' and according to question
a^2+(a+1)^2+(a+2)^2=27650
3a^2+6a+5=27650
after solving :
a=95 or -97
-97 is neglected :
thus 95 is appropriate for the solution
hence 95 ,96,97 are the consecutive intergers and whose total is 288

Like? Yes (1) | No (1)  

harish   10 years AGO

sum of three condecutive numbers is
(x-1)^2+x^2+(x+1)^2=27650
on solving this we get,
3x^2+2=27650
3x^2=27648
so x=96
sum of integers is 95+96+97=288...

Like? Yes (1) | No (1)  

sonu   10 years AGO

let first no= x-1,
so , 2nd & 3rd would be \\\'x\\\', \\\'x+1\\\'
as per ques.
(x-1)^2+x^2+(x+1)^2=27650
it implies that
x=96 and nos are 95, 96 and 97 hence
95+96+97=288 ans..

Like? Yes (1) | No (1)  

ABHOY KUMAR   10 years AGO

let nos. be- (n-1),n,(n+1)
(n-1)^2+n^2+(n+1)^2=27650
3*(n^2)+2=27650
3*(n^2)-27648=0
n^2-9216=0
n=sqrt(9216)
n=96
sum(s) = (n-1)+n+(n+1)
s=3*n
s=288[answer]

Like? Yes (1) | No (1)  

IFFAT IRAM   10 years AGO

let the three successive integers be (x-1), x, (x+1)
(x-1)^2+x^2+(x+1)^2=27650
3x^2+2=27650
3x^2=27648
x^2=9216
x=96
sum of the integers=3x=3*96=288

Like? Yes (1) | No (1)  

Praful   10 years AGO

Let no. be x.
x2+(x=1)2+(x=2)2 =27650.
Solving for x, we get x=95.
Hence 95+96+97=288

Like? Yes (1) | No (1)  

ASHISH MITTAL   10 years AGO

x+(x+1)^2+(x+2)^2=27650
3x^2+6x-27645=0
after solving we get x=95 and -97
so sum of these integer will
95+96+97=288

Like? Yes (1) | No (1)  

Govind raj   10 years AGO

let numbers are n,n+1,n+2.
now a/q;sqr(n)+sqr(n+1)+sqr(n+2)=27650 then
3n^2+6n=27645..n^2+2n=9215.add 1 on both side and solve we get n=95;
95+96+97=288

Like? Yes (1) | No (1)  

Komala.G   10 years AGO

(x+1)^2+(x+2)^2+(x+3)^2 = 27650
(x^2+1+2x)+(x^2+4+4x)+(x^2+9+6x) = 27650
3x^2+14+12x = 27650
3x^2+12x = 27650-14
3x^2+12x-27636 = 0---- divide by 3
x^2+4x-9212 = 0
x(x+98)-94(x+98)
(x-94)(x+98) = 0
x = 94, -98
(x+1)^2+(x+2)^2+(x+3)^2 = 27650
95^2+96^2+97^2 = 27650
The integers are 95, 96, 97
Sum of these integer is = 288

Like? Yes (1) | No (1)  

Harivignesh.B   10 years AGO

Sum of squares of 3 consecutive integers expressed as the sum of 5 consecutive integers

(x – 1)^2 + x^2 + (x + 1)^2 = (a – 2) + (a – 1) + a + (a + 1) + (a + 2)

(x – 1)^2 + x^2 + (x + 1)^2 = 5*a

n = 20
95^2 + 96^2 + 97^2 = 5528 + 5529 + 5530 + 5531 + 5532 = 27650

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

(x-1)^2+x^2+(x+1)^2=27650
=> 3x^2+2=27650
=> 3x^2=27648
=> x^2=9216
=> x=96
no.s are 95,96,97 &
sum=95+96+97=288

Like? Yes (2) | No (3)  

sruthi   10 years AGO

take the values as
x,x+1,x+2
x^2+(x+1)^2+(x+2)^2=27650
x^2+x^2+2x+1+x^2+4x+4=27650
3x^2+6x+5=27650
3x^2+6x=27645(27650-5)
3(x^2+2x)=27645
x^2+2x=9215(27645/3)
so the quadratic equation is
x^2+2x-9215=0
the roots are 95 and -97
take positive root 95
x=95
x+1=96
x+2=97
the integer values is 95,96,97

Like? Yes (1) | No (3)  

05 May 2014 Sequence

What is the next number of the following sequence
22, 43, 84, 165, 326, 647, ........

OPtion

1) 1188
2) 1287
3) 1286
4) 1288
5) 1387
6) 1289
7) 1388
8) 1389
9) 1282
10)None of these

Solution

22
(2*2)(2+1) = (4)(3) = 43
(4*2)(3+1) = (8)(4) = 84
(8*2)(4+1) = (16)(5) = 165
(16*2)(5+1) = (32)(6) = 326
(32*2)(6+1) = (64)(7) = 647
Similarly
(64*2)(7+1) = (128)(8) = 1288
Option 4)

Correct Option: 4 Best Solution (89)

Ann Theressa   10 years AGO

22
22*2 - 1 = 43
43*2 - 2 = 84
84*2 - 3 = 165
165*2 - 4 = 326
326*2 - 5 = 647
647*2 - 6 = 1288

Like? Yes (8) | No (2)  

RAKESH   10 years AGO

22, 43, 84, 165, 326, 647, ...
2 2, 4 3, 8 4, 16 5, 32 6, 64 7, 128 8

1288

Like? Yes (6) | No (1)  

Dr.Dipin Singh   10 years AGO

22*2-1=43
43*2-2=84
84*2-3= 165
165*2-4= 326
326*2-2-5= 647
647*2-6= 1288

Like? Yes (2) | No   

Mahalakshmi   10 years AGO

22+21=43
43+41=84
84+81=165
165+161=326
326+321=647
647+641=1288
so ans is 4)1288

Like? Yes (2) | No (1)  

Rajasekhar Reddy   10 years AGO

22+(22-1) = 43
43+(43-2) = 84
84+(84-3) = 165
.
.
. 647+(647-6) = 1288

Like? Yes (2) | No (1)  

upendra singh chahar   10 years AGO

add 1 in unit digit;
and double remaining digits, as
2*2 = 4; 2+1 = 3 => 43
same
(64*2) = 128; 7+1 = 8 => 1288

Like? Yes (2) | No (1)  

RAVI GUPTA   10 years AGO

22*1=22
22*2=44-1=43
43*2=86-2=84
84*2=168-3=165
165*2=330-4=326
326*2=652-5=647
647*2=1294-6=1288

Like? Yes (1) | No   

SREEVIDHYA P P   10 years AGO

First number 22
Then (2*2)(2+1)=43
(4*2)(3+1)=84.......
last (64*2)(7+1)=1288

ie.,first no.

Like? Yes (1) | No   

Vivek Tiwari   10 years AGO

the second number is two times the first number -1, the third no is two times the second no -2 and so on, hence the last number would be two times 647-6 i.e 647*2-6=1288

Like? Yes (1) | No   

chandan jha   10 years AGO

22*2=44-1=43
43*2=86-2=84
...647*2=1294-6=1288.

Like? Yes (1) | No   

garima singh   10 years AGO

the sequence has the last bit in increasing order and the starting bits are exactly double of the previous number's starting bit.

Like? Yes (1) | No   

vivek poddar   10 years AGO

multiply by 2 and minus by 6

Like? Yes (1) | No   

Rahur Kumar Sinha   10 years AGO

Each number multiplied by to and then subtracted 1,2,3,4,5,6... sequently to get the next consecutive number

Like? Yes (1) | No   

Ranjitha   10 years AGO

Add the two digits of previous number which is the first digit of next number and the second digit is obtained by incrementing second digit of previous number.

Like? Yes (1) | No   

indrajeet yadav   10 years AGO

22*2=44-1=43
43*2=86-2=84
84*2=168-3=165
165*2=330-4=326
326*2=652-5=647
647*2=1294-6=1288

Like? Yes (1) | No   

manish chauhan   10 years AGO

647*2-6=1288

Like? Yes (1) | No   

AMIT SINGH   10 years AGO

as 43=22*2-1
84=43*2-2
165=84*2-3
similarly
647*2-6=1288

Like? Yes (1) | No   

llamar   10 years AGO

22+21=43
43+41=84
84+81=165
165+161=326
326+321=647
647+641=1288

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

2 4 8 16 32 64 128
2 3 4 5 6 7 8
1288........

Like? Yes (2) | No (1)  

ankita jain   10 years AGO

the firt digits are like 2, 2 square....64*2=128
next second digits are like=2,3,4,5,6,7,8
so ans-1288

Like? Yes (1) | No   

srilakshmi   10 years AGO

22 --> (2*2)(2+1) = 43
43 ---> (4*2)(3+1) = 84
84 ----> (8*2)(4+1) = 165
.
.
.
.
647 ----> (64*2)(7+1) = 1288

Like? Yes (1) | No (1)  

Devendra Marghade   10 years AGO

22*2-1= 44-1 =43
43*2-2= 86-2 =84
84*2-3=168-3 =165
165*2-4=330-4=326
326*2-5=652-5=647
647*2-6=1294-6=1288

Like? Yes (1) | No (1)  

MD SOHAIL AKHTER   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

so the correct option is (4)

Like? Yes (1) | No (1)  

ASHISH MITTAL   10 years AGO

22+21=43
43+41=84
84+81=165
165+161=326
326+321=647
647+641=1288
so answer will be option (4)

Like? Yes (1) | No (1)  

Sagar Jinachandran   10 years AGO

43-22= 21
84-43= 41
165-84= 81
326-165= 161
647-326= 321
the next difference is 641
so next number = 647+641=1288
Option 4

Like? Yes (1) | No (1)  

ravi prakash   10 years AGO

Multiply The digit except unit digit with 2 and increment by 1 to unit place digit and write the no.
64*2=128
and
7+1=8 in unit place
1288 is the answer

Like? Yes (1) | No (1)  

susmit   10 years AGO

22*2-1=43
43*2-2=86 and so on
so
647*2=6= 1288

Like? Yes (1) | No (1)  

harshal agrawal   10 years AGO

22*2 - 1 = 43
43*2 - 2 = 84
84*2 - 3 = 165
165*2 - 4 = 326
326*2 - 5 = 647
647*2 - 6 = 1288

Like? Yes (1) | No (1)  

SIBNATH HALDER   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

pravallika pasam   10 years AGO

Double the number and reduce 1,2,3,4,5,6
22+22-1=43
43+43-2=84
.
.
.
647+647-6=1288

Like? Yes (1) | No (1)  

Leelanand Kumar Yalla   10 years AGO

647*2-6=1288;

Like? Yes (1) | No (1)  

vicky kumar   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

S Prakash   10 years AGO

Take Difference in first 2 numbers,then subtract -1 and multiply by 2 and add +1.Then add this new value and previous value.

43-22=21
(21-1)*2+1=41
43+41=84
(41-1)*2+1=81
84+81=165
(81-1)*2+1=161
165+161=326
(161-1)*2+1=321
326+321=647
(321-1)*2+1=641
647+641=1288
Answer is 1288.
Option 4.

Like? Yes (1) | No (1)  

Keshav Kishlay   10 years AGO

64*2=128
7+1=8
so, 1288

Like? Yes (1) | No (1)  

Yekollu Muneeswar   10 years AGO

ans 1288
22 * 2 = 44 -1 =43
43 * 2 = 86 -2 =84
84 * 2 = 168 -3 =165
165 * 2 = 330 -4 =326
326 * 2 = 652 -5 =647
647 * 2 = 1294 -6 =1288

Like? Yes (1) | No (1)  

gowtham   10 years AGO

IN GIVEN SERIES
first digit is power of 2^(n+1) for n=0,1,2,3...
where as second digie is order ie.,2 3 4
2=2
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
where as second 2,3,4,....
compare with giwen serise
22,43,84,165,326,647,is the next serise number 1288

Like? Yes (1) | No (1)  

Ramesh.V   10 years AGO

The reason for MULTIPLY TO THE FIRST DIGIT
EG:-2*2=4,4*2=8,8*2=16,16*2=32,32*2=64,(64*2=128).
so the sequence will be start for 128 next the lost digit will find out for digits 2,3,4,5,6,7,( 8 ).
THAT'S WILL BE THE ANSWER[1288].

Like? Yes (1) | No (1)  

T.Aravinth kumar   10 years AGO

647+ 641=1288

Like? Yes (1) | No (1)  

Sudipta Mukherjee   10 years AGO

647*2=1294-6=1288

Like? Yes (1) | No (1)  

ABHOY KUMAR   10 years AGO

22
43=22*2-1
84=43*2-2
165=84*2-3
326=165*2-4
647=326*2-5
NEXT=647*2-6=1288

Like? Yes (1) | No (1)  

MONIKA   10 years AGO

22
22+21=43
43+41=84
84+81=165
165+161=326
326+321=647
647+641=1288

Like? Yes (1) | No (1)  

KALIA MUDULI   10 years AGO

Given Sequence are 22, 43, 84, 165, 326, 647, .....

22*2-1 = 44-1=43
43*2-2 = 86-2= 84
84*2-3 = 168-3= 165
165*2-4 = 330-4= 326
326*2-5 = 652-5= 647
647*2-6 = 1294-6= 1288

so Ans- Op(4)

Like? Yes (1) | No (1)  

arijit roy   10 years AGO

each gap between 2 consequtve number increases like
(2 * before gap value) - 1

Like? Yes (1) | No (1)  

RAJESHKUMAR   10 years AGO

22*2-1= 43
43*2-2= 86
86*2-3= 165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

sruthi   10 years AGO

22,43,84,165,326,647,
here take
22 =2+2 =4 and 2+1=3 so next number 43
43=4+4=8 and 3+1=4 so next number is 84
84=8+8=16 and 4+1=5 so next number is 165
165=16+16=32 and 5+1=6 so next number is 326
326=32+32=64 and 6+1=7 so next number is 647
647=64+64=128 and 7+1=8 so next number is 1288
option 4 is answrer

Like? Yes (1) | No (1)  

SHUBHAM KUMAR   10 years AGO

647*2-6

Like? Yes (1) | No (1)  

g.soujanya   10 years AGO

22+22=44-1=43
43+43=86-2=84
84+84=168-3=165
165+165=330-4=326
326+326=652-5=647
647+647=1294-6=1288

Like? Yes (1) | No (1)  

steffy edmond   10 years AGO

Ans:Option 4) 1288
The given sequence is 22, 43, 84, 165, 326, 647, ........
The last digit in each number is in the increasing order 2,3,4,5,6,7.... so the next number will be 8.
the first digits in each number2,4,8,16,32,64etc are multiplied by 2to get the next=2,4,8,16,32,64,....so the next number is 64*2=128
so the ans is 1288

Like? Yes (1) | No (1)  

Hemalatha   10 years AGO

64*2=128 and adding 8

Like? Yes (1) | No (1)  

salma   10 years AGO

22+20+1=43
43+40+1=84
84+80+1=165
165+160+1=326
326+320+1=647
647+640+1=1288

Like? Yes (1) | No (1)  

Mukesh Nayal   10 years AGO

second number is twice plus 1 of first number

Like? Yes (1) | No (1)  

Purosotam Gupta   10 years AGO

by the question
22*2=44-1=43
43*2=86-2=84
84*2=168-3=165
.
.
.
same as
647*2=1294-6=1288

Like? Yes (1) | No (1)  

NIRUPOM GHOSH   10 years AGO

Prev no are 22,43,84,165,326.Differences of difference is increasing double.Next no. is 647+641=1288.

Like? Yes (1) | No (1)  

gaurav bhatt   10 years AGO

22= 2*2=4 and 2+1=3 so next digit = 43
same as
647= 64*2=128 and 7+1=8 so next digit= 1288
Answer: option 4

Like? Yes (1) | No (1)  

DINESH KUMAR   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

subramani   10 years AGO

22
(22*2)-1=43
(43*2)-2=84
(84*2)-3=165
(165*2)-4=326
(326*2)-5=647
(647*2)-6=1288
so ans is 1288 and option is 4

Like? Yes (1) | No (1)  

SOUVIK TALUKDAR   10 years AGO

because 647:
(64*2)(7+1)
=(128)(8)
=1288

Like? Yes (1) | No (1)  

S.SHAFI   10 years AGO

First digit in the number is double of previous number's first digit..
Second digit in the number is increased by 1 to the previous number's second digit....

Like? Yes (1) | No (1)  

Sundar Kumar   10 years AGO

22,22+21,43+41,84+81,165+161,326+321,647+641...
answer = 4) 1288

Like? Yes (1) | No (1)  

Komala.G   10 years AGO

Option (4)
22*2 = 44-1 = 43
43*2 = 86-2 = 84
84*2 = 168-3 = 165
165*2 = 330-4 = 326
326*2 = 652-5 = 647
647*2 = 1294-6 = 1288

Like? Yes (1) | No (1)  

Sriparna Boote   10 years AGO

Here 2*2=4 and 2+1=3 so 2nd no is 43
similarly, 4*2=8 and 3+1=4 3rd no is 84
in this way 64*2=128 and 7+1=8 so the no is 1288

Like? Yes (1) | No (1)  

adarsh yadav   10 years AGO

22+21=43,44+41=84,84+81=165,165+161=326,326+321=647,647+641=1288, hence the answer is 1288

Like? Yes (1) | No (1)  

Govind raj   10 years AGO

22*2=44-1=43
43*2=86-2=84
84*2=168-3=165
165*2=330-4=326
326*2=652-5=647
647*2=1294-6=1288....

Like? Yes (1) | No (1)  

vasu kumari   10 years AGO

22*2-1=43,43*2-2=84.........647*2-6=1288

Like? Yes (1) | No (1)  

SAMRIDHI   10 years AGO

IF WE Check last digit of the sequence so it is forming a series 2,3,4,5,6,7, so next answer will be the one who have 8 in its last digit then the previous digit are the double of the one before 2*2=4
4*2=8
8*2=16
16*2=32
32*2=64
64*2=128
so answer will be 1288

Like? Yes (1) | No (1)  

Parveen Soni   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

Satish Zod   10 years AGO

647 + (647 - 6) = 1288

Like? Yes (1) | No (1)  

Ankush Kumar   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

Chithra   10 years AGO

64*2=128
next last digit 8
1288

Like? Yes (1) | No (1)  

Hari Sankhar   10 years AGO

add the number with same number and subtract each by 1,2,3,4,5,6etc.,

Like? Yes (1) | No (1)  

sai keerthi mettu   10 years AGO

first digit is power of 2 followed by the next number of previous number

Like? Yes (1) | No (1)  

yellapanthula pranav   10 years AGO

22 * 2 -1 =43
43 * 2 -2 =84
84 * 2 -3 =165
165 * 2 -4 =326
326 * 2 -5 =647
647 * 2 -6 =1288

Like? Yes (1) | No (1)  

Nishdha Bhatt   10 years AGO

22* 2 = 44, 44-1=43
43* 2 = 86, 86-2=84
84* 2 = 168, 168-3=165,,,,, so,,,, going on like this we get 647*2=1294, 1294-6= 1288

Like? Yes (1) | No (1)  

Clair Christ D   10 years AGO

22,22*2-1,43*2-2,84*2-3,165*2-4,326*2-5,647*2-6

Like? Yes (1) | No (1)  

priya agarwal   10 years AGO

the difference b/w them is number divided by 10 + 1

Like? Yes (1) | No (1)  

VIVEK VICTOR   10 years AGO

1st diff : 22-1=21
2nd diff: 43-2=41
...
...
Diff after 647 = 647-6 i.e. 641
so, no. Is 1288

Like? Yes (1) | No (1)  

Sukanya   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
Similarly 647*2-6=1288

Like? Yes (1) | No (1)  

Rajesh Pattanaik   10 years AGO

(647*2)-6=1288

Like? Yes (1) | No (1)  

AMIT   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2=4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

Ajinkya Bhagat   10 years AGO

first digit is x*2 like 2*2=4 4*2=8...
second digit is like 2,3,4,5,6,7,8

Like? Yes (1) | No (1)  

Varunraj Reddy   10 years AGO

22=>2 2=>2*2 2+1=>4 3=>43
43=>4 3=>4*2 3+1=>8 4=>84
84=>8 4=>8*2 4+1=>16 5=>165
165=>16 5=>16*2 5+1=>32 6=>326
326=>32 6=>32*2 6+1=>64 7=>647
647=>64 7=>64*2 7+1=>128 8=>1288 Ans

Like? Yes (1) | No (1)  

Rahul Bhadana   10 years AGO

22
(2*2),(2+1)=43
(4*2),(3+1)=84
(8*2),(4+1)=165
(16*2),(5+1)=326
(32*2),(6+1)=647
so finally
(64*2),(7+1)=1288

Like? Yes (1) | No (1)  

DHANANJAY Kumar   10 years AGO

2 2
*2| |+1
4 3
*2| |+1
8 4
| |
16 5
| |
32 6
| |
64 7
*2| |+1
128 8 ----- ans: 1288
--------------

Like? Yes (1) | No (1)  

Thrinadhsai   10 years AGO

first do the difference between to numbers
43-22=21
84-43=41
165-84=81
here units place doesn't change but tens place changes in multiples of two
326-165=161
647-326=321
so ans is 1288
because 1288-647=641

Like? Yes (1) | No (1)  

jagruti bhagwan salvi   10 years AGO

22+22=44=44-1=43
43+43=86=86-2=84
84+84=168=168-3=165
165+165=330=330-4=326
326+326=652=652-5=647
647+647=1294=1294-6=1288

Like? Yes (1) | No (1)  

Pallab Das   10 years AGO

22*2-1=43
43*2-2=84
84*2-3=165
165*2-4=326
326*2-5=647
647*2-6=1288

Like? Yes (1) | No (1)  

amit singh   10 years AGO

647*2-6=1288

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

22 + 22 = 44-1 = 43 is the next no.
43+43 = 86-2 = 84
84+84 = 168-3 = 165
165+165 = 330-4 = 326
326+326 = 652-5 = 647
647+647 = 1294-6 = 1288 is the answer

Like? Yes (1) | No (2)  

SAMPATH KUMAR   10 years AGO

22,43,84,165,326,,647
(twice of the number)(sequence number)
(2)(2)
(4)(3)
(8)(4)
(16)(5)
(32)(6)
(64)(7)
so most probably the next number is
(128)(8)
and the answer is 1288

Like? Yes (1) | No (2)  

02 May 2014 Coded language

If in coded language
RAKESH = 144
DIPIN = 896
NIRAJ = 2520
Then
KALPESH = ?

OPtion

1) 1472
2) 1536
3) 1538
4) 1572
5) 1596
6) 1632
7) 1636
8) 1672
9) 1736
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
RAKESH = 18 1 11 5 19 8 = 18*8 = 144 (R*H)(Multiplication of even no)
DIPIN = 4 9 16 9 14 = 4*16*14 = 896 (D*P*N)
NIRAJ = 14 9 18 1 10 = 14*18*10 = 2520 (N*R*J)
Similarly
KALPESH = 11 1 12 16 5 19 8 = 12*16*8 = 1536

Option 2)

Correct Option: 2 Best Solution (15)

RAKESH   10 years AGO

RAKESH = 144
18 1 11 5 19 8
product of even no.s = 18*8 = 144

KALPESH
11 1 12 16 5 19 8
=> 12*16*8 = 1536

Like? Yes (15) | No (3)  

Dr.Dipin Singh   10 years AGO

Multiply the even place value of alphabets of names to get equivalent code...
RAKESH..18 01 11 05 08...... 18*8 = 144
similarly
DIPIN = 896
NIRAJ = 2520
Then
KALPESH .. 11 01 12 16 08.... 12*16*8= 1536

Like? Yes (4) | No (2)  

nirmal kumar saini   10 years AGO

multiply the even terms
12*16*8=1536;
so ans is 2

Like? Yes (2) | No (2)  

srilakshmi   10 years AGO

multiplication of even values

Like? Yes (2) | No (3)  

rajani   10 years AGO

the product of even numbers gives the solution .
RAKESH -(18*8)-144
DIPIN-(4*16*14)-896
NIRAJ-(14*18*10)-2520
so,KALPESH-(12*16*8)-1536

Like? Yes (2) | No (3)  

ASHISH MITTAL   10 years AGO

if A=1,B=2,C=3...AND SO ON
THEN MULTIPLY THE EVEN NO TO GET THE ANSWER
SO FOR KALPESH EVEN NO WILL BE 12,16,8
AND THIER MULTIPLICATION WILL BE 1536 OPTION(2)

Like? Yes (2) | No (3)  

Ann Theressa   10 years AGO

Multiply the even numbers

RAKESH = 18*8 = 144
DIPIN = 4*16*14 = 896
NIRAJ = 14*18*10 = 2520

KALPESH = 12*16*8 = 1536

Like? Yes (2) | No (3)  

azharshahid01@gmail.com   10 years AGO

Multiply Even Numbers.

RAKESH= 18,1,11,5,19,8=> 18*8= 144

Similarly,
KALPESH= 11,1,12,16,5,19,8=> 12*16*8= 1536

Like? Yes (1) | No (3)  

ravi prakash   10 years AGO

Multiply the even no of respective alphabet
RAKESH=18 1 11 5 19 8 =18*8 = 144
DIPIN=4 9 16 9 14= 4*16*14 = 896
Similarly
KALPESH=11 1 12 16 5 19 8=12*16*8=1536

Like? Yes (1) | No (3)  

Tharun   10 years AGO

Product of even no

Like? Yes (1) | No (3)  

DILEEP KUMAR   10 years AGO

R A K E S H = 18 1 11 5 19 8
PRODUCT OF EVEN NUMBERS = 18*8=144
LIKE
K A L P E S H = 11 1 12 16 5 19 8
12*16*8=1536

Like? Yes (1) | No (3)  

Sunku Mounika   10 years AGO

Multiply the even numbers in the alphabet values..

Like? Yes (1) | No (4)  

SHEREENA NISHAD   10 years AGO

product of even

Like? Yes (1) | No (4)  

MD SOHAIL AKHTER   10 years AGO

A=1,B=2,........Z=26
multiply the even no., we get
RAKESH (18 1 11 5 19 8)= 18*8=144
similarly,
KALPESH (11 1 12 16 5 19 8)= 12*16*8=1536

so correct option is (2)

Like? Yes (1) | No (4)  

NIRUPOM GHOSH   10 years AGO

KALPESH=12*16*8=1536(L=12,P=16,H=8)divisible by 2.Same as RAKESH,DIPIN,NIRAJ.

Like? Yes (1) | No (4)  

01 May 2014 Quadratic Equation

Solve
(x+1)(x+2)(x+3)(x+4)+1 = 0

OPtion

1) {-5+sqrt(5)}/2, {-5-sqrt(5)}/2
2) {-2+sqrt(2)}/5, {-2-sqrt(2)}/5
3) {-4+sqrt(2)}/2, {-4-sqrt(2)}/2
4) {-6+sqrt(2)}/4, {-6-sqrt(2)}/4
5) {-4+sqrt(5)}/2, {-4-sqrt(5)}/2
6) {-3+sqrt(3)}/2, {-3-sqrt(3)}/2
7) {-3+sqrt(5)}/2, {-3-sqrt(5)}/2
8) {-5+sqrt(5)}/4, {-5-sqrt(5)}/4
9) {-2+sqrt(2)}/3, {-2-sqrt(2)}/3
10)None of these

Solution

Multiply first factor with last and second with third factor to get
(x^2+5x+4)(x^2+5x+6)+1 = 0
Let x^2+5x = t
then
(t+4)(t+6)+1 = 0
Solve
(t+5)^2 = 0
t = -5
x^2+5x = -5
x^2+5x+5 = 0
Solve
Option 1)

Correct Option: 1 Best Solution (16)

ABHOY KUMAR   10 years AGO

(x+1)(x+2)(x+3)(x+4)+1=0
(x+1)(x+4)(x+2)(x+3)+1=0
(x^2+5x+4)(x^2+5x+6)+1=0
let x^2+5x=t ......(i)
(t+4)(t+6)+1=0
t^2+10t+24+1=0
t^2+10t+25=0
(t+5)^2=0
t=-5
put t=-5 in eq.(i)
x^2+5x=-5
x^2+5x+5=0
x=(-5+sqrt(5))/2
and x=(-5-sqrt(5))/2
{-5+sqrt(5)}/2, {-5-sqrt(5)}/2[answer]

Like? Yes (16) | No (7)  

Ann Theressa   10 years AGO

(x+1)(x+2)(x+3)(x+4)+1 = 0
(x^2+3x+2)(x^2+7x+12) + 1 = 0
x^4 + 10x^3 + 35x^2 + 50x + 25 = 0
(x^2 + 5x + 5)^2 = 0

Taking square root on both sides

x^2 + 5x + 5 = 0
x = (-5 (+-) sqrt(25-20)}/2

x = {-5-sqrt(5)}/2 ,{-5+sqrt(5)}/2

Like? Yes (22) | No (15)  

PAWAN KUMAR   10 years AGO

solving using options,
1st option:
(-4*4)/16 +1=0
here, LHS=RHS
hence answer 1 is correct.

Like? Yes (5) | No (1)  

llamar   10 years AGO

by trail and error method
the given equation is clearly
(x+1)(x+2)(x+3)(x+4)+1 =(x^2+5x+5)^2=0
x^2+5x+5=0 by solving it we get
{-5+sqrt(5)}/2, {-5-sqrt(5)}/2 as roots

Like? Yes (6) | No (2)  

vishnuvardhan   10 years AGO

(x+1)(x+4)(x+2)(x+3)+1=0
(x^2+5x+4)*(x^2+5x+6)+1=0
put x^2+5x=t
(t+4)*(t+6)+1=0
t=-5
x^2+5x=-5
x=(-5+sqrt5)/2,(-5-sqrt5)/2

Like? Yes (5) | No (2)  

SIBNATH HALDER   10 years AGO

{(x+1)(x+4)}{(x+2)(x+3)}+1=0
we get
(x^2+5x+4)(x^2+5x+6)+1=0
let x^2+5x=a
(a^2+4)(a^2+6)+1=0
a=+5,-5;
put value of a=-5
x^2+5x+5=0
x=option(1)
ans

Like? Yes (5) | No (3)  

Dr.Dipin Singh   10 years AGO

(x+1)(x+2)(x+3)(x+4)+1 = 0
(x+1)(x+4)(x+2)(x+3)+1 = 0
(x^2+5x+4)*(x^2+5x+6)+1=0
Let x^2+5x=y
(y+4)*(y+6)+1=0
y^2+10+25=0
(y+5)^2=0
y=-5
x^2+5x+5=0
solving ,
we get
x= {-5+sqrt(5)}/2, {-5-sqrt(5)}/2... option 1

Like? Yes (6) | No (5)  

azharshahid01@gmail.com   10 years AGO

On putting values of x in the equation.
only option(1) will satisfy the equation.

Like? Yes (7) | No (6)  

VIMALRAJ V   10 years AGO

on simplification x⁴ + 10x³ + 35x² + 50x + 25 = 0.
then by using long division method, the quotient becomes x^2 + 5x + 5 = 0.
then by factorization method the answer obtained is {-5+sqrt(5)}/2, {-5-sqrt(5)}/2.
therefore option 1 is correct....

Like? Yes (3) | No (2)  

nandini keshari   10 years AGO

(x+1)(x+2)(x+3)(x+4)+1=0
(x+1)(x+4)(x+2)(x+3)+1=0
(x^2+5x+4)(x^2+5x+6)+1=0
Let x^2+5x=p
(P+4)(P+6)+1=0
P^2+10P+25=0
(P+5)^2=0
P+5=0
x^2+5x+5=0
So
x=-5-sqrt(5)/2 or -5+sqrt(5)/2

Like? Yes (4) | No (3)  

Purosotam Gupta   10 years AGO

put the value of x in equation it satisfied.

Like? Yes (3) | No (3)  

RAKESH   10 years AGO

(x+1)(x+2)(x+3)(x+4)+1 = 0
=> (x^2+5x+4)(x^2+5x+6)+1=0
=> (y+4)(y+6)+1=0
=> y^2+10y+25=0
=> y+5=0
=> x^2+5x+5=0
=> x=[-5+-sqrt(5)]/2

Like? Yes (3) | No (4)  

indrajeet yadav   10 years AGO

(x+1)(x+2)(x+3)(x+4)+1=0
(x+1)(x+4)(x+2)(x+3)=-1
(x^2+5x+4)(x^2+5x+6)=-1
x^2+5x+4=-1 or x^2+5x+6=-1
x^2+5x+5=0 or x^2+5x+7=0
x1={-5+sqrt(5)}/2 or x1={-5+i sqrt(3)}/2
x2={-5-sqrt(5)}/2 or x2={-5-i sqrt(3)}/2
but given option x can't be imaginary.
so x1={-5+sqrt(5)}/2
x2={-5-sqrt(5)}/2

Like? Yes (6) | No (7)  

Tanu   10 years AGO

(x+1)(x+4)(x+2)(x+3)+1=0
(x^2+5x+4)(x^2+5x+6)+1=0--------------------eq1

Let x^2+5x=y--------------------------------eq2

Putting above
(y+4)(y+6)+1=0
y+10y+25=0
y=5

x^2+5x=y
x^2+5x=5
x^2+5x+5=0

x= {-5+sqrt(5)}/2, {-5-sqrt(5)}/2

Like? Yes (2) | No (3)  

MD SOHAIL AKHTER   10 years AGO

on substituting the above option in given eqn, we get;
x= -5+sqrt(5)}/2, {-5-sqrt(5)}/2

so option (1) is correct

Like? Yes (1) | No (4)  

ASHISH MITTAL   10 years AGO

by solving equation for x

Like? Yes (2) | No (5)  

30 Apr 2014 Time, Distance and Speed

Two train, Each 80 m long, passes each other on parallel lines. If they are going in same direction, the faster train takes one minute to pass the other completely. If they are going in the opposite directions, they over take each other in three second. Find the rate of each train in meter per second.

OPtion

1) 28 m/sec, 76/3 m/sec
2) 25 m/sec, 76/3 m/sec
3) 27 m/sec, 25 m/sec
4) 26 m/sec, 77/3 m/sec
5) 29 m/sec, 28 m/sec
6) 28 m/sec, 25 m/sec
7) 28 m/sec, 101/4 m/sec
8) 35 m/sec, 30 m/sec
9) 38 m/sec, 28 m/sec
10)None of these

Solution

Let the speed of faster train be x m/sec and other train be y m/sec
Since
T = D/S
Then we get
x - y = 8/3 (i)
x + y = 160/3 (ii)
Now solving (i) and (ii)
x=28 m/sec and y=76/3 m/sec

Option 1

Correct Option: 1 Best Solution (15)

Ann Theressa   10 years AGO

Let the speed of trains be x and y
distance d = 80+80 = 160

speed = distance/time
x-y = 160/60 ---(1)
x+y = 160/3 ---(2)

(1) + (2)
2x = 56
x = 28m/sec

y = 76/3 m/sec

Like? Yes (23) | No (8)  

nirmal kumar saini   10 years AGO

let first train speed=v1;
and second train speed=v2;
so when these are going in one direction the resultant speed is=v1+v2;
and when going in opposite direction the resultant speed=v1-v2;
so in first condition equation is:-
d/v1+v2=60; .............(1)
and in second condition equation is:-
d/v1-v2=3; .............(2)
solving both of equation we get
v1=28 m/sec; and
v2=76/3 m/sec;ans

Like? Yes (14) | No (7)  

Purosotam Gupta   10 years AGO

let
the speed of one train=x
speed of second train=y
then
the question
x-y=160/60........equ 1
x+y=160/3.......equ 2
then from 1 and 2
x=28 m/s
y=76/3 m/s

Like? Yes (6) | No (2)  

indrajeet yadav   10 years AGO

let both trains speed=u and v m/sec
according to question
160/u-v=60........(1)
160/u+v=3.........(2)
solve both equation
u=28 m/sec
v=76/3 m/sec

Like? Yes (5) | No (2)  

PAWAN KUMAR   10 years AGO

Let speed of trains be x,y m/sec
now, (x-y)=160/60=8/3 m/sec
and (x+y)=160/3 m/sec
hence, x=28 & y=76/3 m/sec.

Like? Yes (4) | No (3)  

MD SOHAIL AKHTER   10 years AGO

let the speed of two trains be x and y (m/sec)

A/Q
160/(y-x)=60........... (1)
and
160/(y+x)=3...............(2)

on solving (1) & (2), we get
x=76/3m/sec
y=28 m/sec
ans- option 1

Like? Yes (4) | No (5)  

Udhaya kumar   10 years AGO

160/(x-y)=60
160/(x+y)=3
by solving this we get x=28 , y=76/3.....

Like? Yes (4) | No (5)  

KALIA MUDULI   10 years AGO

Let speed of first and second train are S1 and S2.
Given that:lenght of train are 80 m each
1 min=60 sec

according to the first condition:
60=(80+80)/(S1-S2)
S1-S2=8/3 ...........(1)

and according to second condtion:
3=(80+80)/(S1+S2)
S1+S2=160/3 ............(2)

by solving both eque (1)&(2)
we get....

S1=28 m/sec, S2=76/3 m/sec.

Like? Yes (3) | No (5)  

Aakash Jain   10 years AGO

after solving partially these 2 equations are formed,
r1+r2=160/3 and r1-r2=8/3
after solving these two equation, ans is 28m/s and 76/3 m/s

Like? Yes (2) | No (4)  

harshal agrawal   10 years AGO

160/(v-u)=60
160/(v+u)=3
v=28 u=76/3

Like? Yes (2) | No (4)  

AJAY KUMAR   10 years AGO

3x-3y=8
3x+3y=160
x=28m/s
y=(76/3)m/s

Like? Yes (1) | No (3)  

Indira   10 years AGO

say s1 n s2 r speeds of two trains..
s1-s2 = 80+80/60 ..
s1+s2 = 80+80/3 ..
solve and
s1= 28m/sec and s2= 76/3 m/sec

Like? Yes (1) | No (3)  

gaurav arora   10 years AGO

ans is 1st option

Like? Yes (1) | No (3)  

Rashmi bharti   10 years AGO

28 m/sec,76/3 m/sec

Like? Yes (2) | No (5)  

ASHISH MITTAL   10 years AGO

60x-60y=160
x+y=160
after solving we get
x=28
and y=76/3
so option (1)

Like? Yes (2) | No (5)  

29 Apr 2014 Probability

Three non parallel tangents are drawn in a circle. What is the probability that it would be an incircle.

OPtion

1) 1/2
2) 1/3
3) 1/4
4) 1
5) 0
6) 3/4
7) 2/3
8) 4/5
9) 3/5
10)None of these

Solution

A set of three lines have 1 incircle and 3 excircles, thus probability is 1/4.

Correct Option: 3 Best Solution (2)

Ann Theressa   10 years AGO

Let there be n points on the circle
Probability that the circle is an incircle for the 3 tangents
= 1/(2n-2)*2*{1/(2n-4)+2/(2n-4)+....+(n-2)/(2n-4)}
= 1/(2n-2)*1/(2n-4)*2*{1+2+3+....+(n-2)}
=1/4*1/(n-1)*1/(n-2) *(n-2)*(n-1)
= 1/4

Like? Yes (5) | No (3)  

steffy edmond   10 years AGO

Ans: option 3)1/4

Like? Yes (3) | No (2)  

28 Apr 2014 Sequence

What is the next number of the following sequence
11, 15, 51, 87, 312, 348,........

OPtion

1) 384
2) 400
3) 436
4) 472
5) 476
6) 548
7) 573
8) 648
9) 701
10)None of these

Solution

11
11+(1+1)^2 = 11+2^2 = 11+4 = 15
15+(1+5)^2 = 15+6^2 = 15+36 = 51
51+(5+1)^2 = 51+6^2 = 51+36 = 87
87+(8+7)^2 = 87+15^2 = 87+225 = 312
312+(3+1+2)^2 = 312+6^2 = 312+36 = 348
Similarly
348+(3+4+8)^2 = 348+15^2 = 348+225 = 573

Option 7)

Correct Option: 7 Best Solution (38)

Pradeep   10 years AGO

573 {11;1+1=2;11+2^2=15;;15+6^2=51;;51+6^2=87 SIMILARLY 348+(3+4+8)^2=573}

Like? Yes (1) | No   

llamar   10 years AGO

11+(1+1)^2=15
15+(1+5)^2=15+36=51
51+(5+1)^2=51+36=87
87+(8+7)^2=87+225=312
312+(3+1+2)^2=312+36=348
348+(3+4+8)^2=348+225=573

Like? Yes (1) | No   

Hanish   10 years AGO

11,15,51,87,312,348,.........
11=(1+1)=2
15=(11+2^2)
15=(1+5)
51=(15+6^2)
similarly,
348=(3+4+8)
therefore required no. is:-n=(348+15^2)=573

Like? Yes (1) | No   

sravanibatchu   10 years AGO

348+square(3+4+8)=573

Like? Yes (1) | No   

nirmal kumar saini   10 years AGO

11+(1+1)^2=15;
15+(1+5)^2=51;
51+(5+1)^2=87;
87+(8+7)^2=312;
312+(3+1+2)^2=348;
348+(3+4+8)^2=573;
so 573 is the answer

Like? Yes (3) | No (3)  

SriS   10 years AGO

11,15,51,87,312,348..
11-15=4(1+1=2,2*2=4)
15-51=36(1+5=6,6*6=36)
51-87=36(5+1=6,6*6=36)
312-87=225(8+7=15,15*15=225)
348-312=36(3+1+2=6,6*6=36)
so answer is 3+4+8=15...15*15=225
348+225=573

Like? Yes (2) | No (3)  

ANUP KUMAR   10 years AGO

11+(1+1)^2 = 15
15+(1+5)^2 = 51
87+(8+7)^2 = 312
312+(3+1+2)^2 = 348
348+(3+4+8)^2 = 573

Like? Yes (3) | No (4)  

ABHOY KUMAR   10 years AGO

ANSWER:573
11+2^2=15;(2^2 BECOZ 11 IS WRITTEN AS (1+1)^2)
15+6^2=51;(6^2 BECOZ 15 IS WRITTEN AS (1+5)^2)
51+6^2=87;(6^2 BECOZ 51 IS WRITTEN AS (5+1)^2)
87+15^2=312;(15^2 BECOZ 87 IS WRITTEN AS (8+7)^2)
312+6^2=348;(6^2 BECOZ 312 IS WRITTEN AS (3+1+2)^2)
348+15^2=573(15^2 BECOZ 348 IS WRITTEN AS (3+4+8)^2)

Like? Yes (2) | No (3)  

subramani   10 years AGO

11
11+(1+1)^2=15
15+(1+5)^2=51
51+(5+1)^2=87
87+(8+7)^2=312
312+(3+1+2)^2=348
like that..
348+(3+4+8)^2=573
So the Answer is "573" Option 7)

Like? Yes (2) | No (3)  

OM PRAKASH JHA   10 years AGO

11
15=11+(1+1)*(1+1)
51=15+(1+5)*(1+5)
87=51+(1+5)*(1+5)
similarly,348+(3+4+8)+(3+4+8)=573

Like? Yes (1) | No (2)  

Ann Theressa   10 years AGO

next number = previous number + square of sum of digits of previous number

11 + (1+1)^2 = 15
15 + (1+5)^2 = 51
51 + (5+1)^2 = 87
87 + (8+7)^2 = 312
312 + (3+1+2)^2 = 348
348 + (3+4+8)^2 = 573

Like? Yes (3) | No (5)  

Devendra Marghade   10 years AGO

11+(1+1)^2=11+4=15
15+(1+5)^2=15+36=51
51+(5+1)^2=51+36=87
87+(8+7)^2=87+225=312
312+(3+1+2)^2=312+36=348
348+(3+4+8)^2=348+225=573

Like? Yes (1) | No (3)  

Nitesh Joshi   10 years AGO

348+(3+4+8)^2= 348+225= 573
next no= no + (sum of digits)^2

Like? Yes (1) | No (3)  

Md Shahid Akhter   10 years AGO

11+(1+1)^2 = 15
15+(1+5)^2 = 51
87+(8+7)^2 = 312
312+(3+1+2)^2 = 348
348+(3+4+8)^2 = 573

Like? Yes (1) | No (3)  

AJAY KUMAR   10 years AGO

3+4+8=15
348+(15^2)=573

Like? Yes (1) | No (3)  

Grishma Shah   10 years AGO

11
11+ (1+1)^2 = 15
15+ (1+5)^2 = 51
51+ (5+1)^2 = 87
87+ (8+7)^2 = 312
312+ (3+1+2)^2 = 348
348+ (3+4+8)^2 = 573

Like? Yes (1) | No (3)  

Varunraj Reddy   10 years AGO

Given sequence 11,15,51,87,312,348,...

Take 1st number in the sequence 11=>1+1=2=>2^2=4
11+4=15(2nd number)

Take 2nd number 15=>1+5=6=>6^2=36
15+36=51(3rd number)
.........
.........
similarly,
348=>3+4+8=15=>15^2=225
348+225=573 option 7)

Like? Yes (1) | No (3)  

Gitanjali K   10 years AGO

1+1=2
11+2^2=15
1+5=6
15+6^2=51
5+1=6
51+6^2=87
8+7=15
87+15^2=312
3+1+2=6
312+6^2=348
3+4+8=15
348+15^2=573 is the answer

Like? Yes (1) | No (3)  

DHIRENDRA    10 years AGO

Given
11, 15, 51, 87, 312, 348,........
first term
11=11+(1+1)^2=11+4=15
15=15+(1+5)^2=15+36=51
51=51+(5+1)^2=51+36=87
same as
348=348+(3+4+8)^2=348+225=573

Like? Yes (1) | No (3)  

Satish Zod   10 years AGO

Add square of sum of individual digits of a number to same number.

Like? Yes (1) | No (3)  

Mahalakshmi   10 years AGO

11
11+(1+1)^2=15
15+(1+5)^2=51
51+(5+1)^2=87
87+(8+7)^2=312
312+(3+1+2)^2=348
348+(3+4+8)^2=573
so ans is 7)573

Like? Yes (1) | No (3)  

harshal agrawal   10 years AGO

11 + (1+1)^2 = 15
15 + (1+5)^2 = 51
51 + (5+1)^2 = 87
87 + (8+7)^2 = 312
312 + (3+1+2)^2 = 348
348 + (3+4+8)^2 = 573

Like? Yes (2) | No (4)  

Aman   10 years AGO

Next term is the sum of previous term and the square of the sum of its digits.
11, 15, 51, 87, 312, 348,.......
15= 11+(1+1)^2
51= 15+(1+5)^2
..

next no will be 348+(3+4+8)^2= 348+15^2= 348+225=573

Like? Yes (1) | No (3)  

Dr.Dipin Singh   10 years AGO

11+(1+1)^2=11+4=15
15+(1+5)^2=15+36=51
..
..
so 348+(3+4+8)^2=573 .. option 7

Like? Yes (1) | No (3)  

DILEEP KUMAR   10 years AGO

11 + (1+1)^2 = 15,
15 + (1+5)^2 = 51
51 + (5+1)^2 = 87.
.....
348 + ( 3+ 4+8)^2 = 573

Like? Yes (1) | No (3)  

Govind raj   10 years AGO

(sum of digit)^2 then add to next...as
11=(1+1)^2=4..11+4=15
15=(1+5)^2=36..36+15=51
51=(5+1)^2=36..36+51=87
87=(8+7)^2=225..225+87=312
312=(3+2+1)^2=36..312+36=348
lly (3+4+8)^2=225+348=573

Like? Yes (1) | No (3)  

indrajeet yadav   10 years AGO

11+(1+1)^2=11+4=15
15+(1+5)^2=15+36=51
51+(5+1)^2=51+36=87
87+(8+7)^2=87+225=312
312+(3+1+2)^2=312+36=348
348+(3+4+8)^2=348+225=573

Like? Yes (1) | No (3)  

Anantharaman   10 years AGO

Formula:
Add the previous number square of sum of digits in previous number in sequence
11
11+(1+1)^2=11+(2)^2=11+4=15
15+(1+5)^2=15+(6)^2=15+36=51
51+(5+!)^2=51+(6)^2=51+36=87
87+(8+7)^2=87+(15)^2=87+225=312
312+(3+1+2)^2=312+(6)^2=312+36=348
348+(3+4+8)^2=348+(15)^2=348+225=573

Answer Option 7

Like? Yes (1) | No (3)  

TUSHAR    10 years AGO

573

Like? Yes (1) | No (3)  

adarsh yadav   10 years AGO

15-11=4,which is the square of 1+1 i.e 2,
51-15=36,which is the square of 1+5 i.e 6,
87-51=36,which is the square of 5+1 i.e 6,
312-87=225,which is the square of 8+7 i.e 15,
348-312=36,which is the square of 3+1+2 i.e 6,
similarly,573-348=225,which is the square of 15,
and hence the answer is 573

Like? Yes (1) | No (3)  

OM PRAKASH JHA   10 years AGO

11
15=11+(1+1)*(1+1)
51=15+(1+5)*(1+5)
87=51+(1+5)*(1+5)
similarly,348+(3+4+8)+(3+4+8)=573

Like? Yes (1) | No (3)  

Udhaya kumar   10 years AGO

11+(1+1)^2 = 15
similarly
348+(3+4+8)^2= 573.........

Like? Yes (2) | No (4)  

nathiya   10 years AGO

1+1=2,2*2=4,11+4=15
1+5=6,6*6=36,36+15=51
5+1=6,6*6=36,36+51=87
8+7=15,15*15=225,225+87=312
3+1+2=6,6*6=36,36+312=348
3+4+8=15,15*15=225,225+348=573

Like? Yes (1) | No (3)  

MD SOHAIL AKHTER   10 years AGO

11
15=11+(1+1)^2
51=15+(1+5)^2
similarly
348+(3+4+8)^2=573

Like? Yes (2) | No (4)  

Rathinavel   10 years AGO

11+(1+1)^2=15, 15+(1+5)^2=51.... 348+(3+4+8)^2=573

Like? Yes (1) | No (3)  

RAKESH   10 years AGO

11, 15, 51, 87, 312, 348,...

11+(1+1)^2=15
15+(1+5)^2=51
...

312+(3+1+2)^2=348
348+(3+4+8)^2=573

Like? Yes (1) | No (4)  

steffy edmond   10 years AGO

Ans:option 7)573
reason: 15= 11+(1+1)^2
51= 15+(1+5)^2
87= 51+(5+1)^2
312= 87+(8+7)^2
348=312+(3+1+2)^2
so the next number x=348+(3+4+8)^2
= 573

Like? Yes (2) | No (5)  

Leelanand Kumar Yalla   10 years AGO

573

Like? Yes (1) | No (4)  

25 Apr 2014 Coded language

If in coded language
SUNDAY = 24
MONDAY = 12
TUESDAY = -3
Then
WEDNESDAY = ?

OPtion

1) 26
2) -26
3) -46
4) -36
5) 46
6) -23
7) -28
8) -32
9) 33
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
SUNDAY = (S+U+N)-(D+A+Y) = (19+21+14)-(4+1+25) = 54-30 = 24
MONDAY = (M+0+N)-(D+A+Y) = (13+15+14)-(4+1+25) = 42-30 = 12
TUESDAY = (T+U+E)+(S+D+A+Y)= (20+21+5)-(19+4+1+25)=46-49 = -3
Similarly
WEDNESDAY = (W+E+D)-(N+E+S+D+A+Y)=(23+5+4)-(14+5+19+4+1+25)=32-68 = -36

Option 4)

Correct Option: 4 Best Solution (28)

Dr.Dipin Singh   10 years AGO

Sum of number value of first 3 letters - sum of number value of balance letters
SUNDAY.... 19 21 14 04 01 25..... (19+21+14)-(4+1+25) = 24
similarly
MONDAY = 12
TUESDAY = -3
Then
WEDNESDAY .... 23 05 04 14 05 19 04 01 25...... 32-68 = -36

Like? Yes (13) | No (5)  

ANUP KUMAR   10 years AGO

sum of 1st three number - remaining numbers

S(19) U(21) N(14) D(4) A(1) Y(25)
(19+21+4)- (4+1+25) = 24
similarly,
T(20) U(21) E(5) S(19) D(4) A(1) Y(25)
(20+21+5)-(19+4+1+25) = -3
Then
W(23) E(5) D(4) N(14) E(5) S(19) D(4) A(1) Y(25)
(23+5+4)-(14+5+19+4+1+25) = -36 ans

Like? Yes (6) | No (5)  

llamar   10 years AGO

take A=1,B=2................Z=26
logic:
(sum of the first three letters of the word)-(sum of the remaining letters of the word)
SUNDAY =(19+21+14)-(4+1+25)=24
TUESDAY =(20+21+5)-(19+4+1+25)=-3
WEDNESDAY =(23+5+4)-(14+5+19+4+1+25)=-36

Like? Yes (1) | No   

Ann Theressa   10 years AGO

SUNDAY = (19+21+14)-(4+1+25) = 24
MONDAY = (13+15+14) - (4+1+25) = 12
TUESDAY = (20+21+5) - (19+4+1+25) = -3
Then
WEDNESDAY = (23+5+4) - (14+5+19+4+1+25) = -36

Like? Yes (6) | No (6)  

DHIRENDRA    10 years AGO

decode the letter
like
A=1,B=2,............Z=26
the sum the first the letter and subtract the remaining letter from the first three letter

Like? Yes (2) | No (2)  

OM PRAKASH JHA   10 years AGO

(ADD FIRST THREE LETTERS)- (ADD REST OF LETTERS)
WEDNESDAY=(WED)-(NESDAY)=(23+5+4)-(14+5+19+4+1+25)=-36

Like? Yes (2) | No (2)  

MONIKA   10 years AGO

if a=1,b=2.....z=26
S+U+N-D-A-Y=19+21+14-4-1-25=24
similarly M+O+N-D-A-Y=13+15+14-4-1-25=12
and T+U+E-S-D-A-Y=20+21+5-19-4-1-25=-3
so,W+E+D-N-E-S-D-A-Y=23+5+4-14-5-19-4-1-25=-36

Like? Yes (2) | No (2)  

OM PRAKASH JHA   10 years AGO

(ADD FIRST THREE LETTERS)- (ADD REST OF LETTERS)
WEDNESDAY=(WED)-(NESDAY)=(23+5+4)-(14+5+19+4+1+25)=-36

Like? Yes (2) | No (2)  

vivek kumar dubey   10 years AGO

(ADD FIRST THREE LETTERS)- (ADD REST OF LETTERS)
WEDNESDAY=(WED)-(NESDAY)=(23+5+4)-(14+5+19+4+1+25)=-36

Like? Yes (2) | No (2)  

lovely verma   10 years AGO

according to position of alphabets....
Rule:-
(Addition of first three alphabets)-(addition of remaining alphabets)

[S(19)+U(21)+N(14)]-[D(4)A(1)Y(25)] =54-30=24
[M(13)+O(15)+N(14)]-[D(4)+A(1)+Y(25)] =42-30=12
[T(20)+U(21)+E(5)]-[S(19)+D(4)+A(1)Y(25)]=46-49=-3
[W(23)+E(5)+D(4)]-[N(14)+E(5)+S(19)+D(4)+A(1)+Y(25)]= 32-68= -36
so finally answer is 36.

Like? Yes (2) | No (3)  

shree   10 years AGO

4) -36
we have to take sum of 1st 3 letters and subtract them from the rest .

Like? Yes (2) | No (3)  

abhishekkumar   10 years AGO

first write all all letter into number like A=1
then add starting 3 and after that add remaining letter and subtract sum of starting 3 letter to sum of remaining letter .

Like? Yes (2) | No (3)  

Udhaya kumar   10 years AGO

w+e+d-n-e-s-d-a-y.........
23+5+4-14-5-19-4-1-25=-36...........

Like? Yes (3) | No (5)  

Ghanshyam Gulati   10 years AGO

A(1),B(2),......Y(25),Z(26)

S(19)U(21)N(14)D(4)A(1)Y(25)=24
19+21+14-4-1-25

M(13)O(15)N(14)D(4)A(1)Y(25)=12
13+15+14-4-1-25

T(20)U(21)E(5)S(19)D(4)A(1)Y(25)=-3
20+21+5-19-4-1-25

HENCE WEDNESDAY=-36
23+5+4-14-5-19-4-1-25

Like? Yes (3) | No (5)  

SIBNATH HALDER   10 years AGO

1st 3 term -last all term
example
sunday=19+21+14+4+1+25
(10+21+14)-(4+1+25)=24
similarly
wednesdy=23+5+4+14+5+19+4+1+25
(23+5+4)-(14+5+19+4+1+25)=-36
ans (4)

Like? Yes (2) | No (4)  

Sundar Kumar   10 years AGO

SUNDAY = 19+21+14-4-1-25=24
MONDAY=13+15+14-4-1-25=12
TUESDAY=20+21+5-19-4-1-25=-3
WEDNESDAY=23+5+4-14-5-19-4-1-25=-36
take 1st 3 letters are +ve and remaining letters are -ve..

Like? Yes (2) | No (4)  

AMIT JAISWAL   10 years AGO

according to position of alphabets....
(Addition of first three alphabet's value)-(addition of remaining alphabet's value)

[S(19)+U(21)+N(14)]-[D(4)A(1)Y(25)] =54-30=24
[M(13)+O(15)+N(14)]-[D(4)+A(1)+Y(25)] =42-30=12
[T(20)+U(21)+E(5)]-[S(19)+D(4)+A(1)Y(25)]=46-49=-3
[W(23)+E(5)+D(4)]-[N(14)+E(5)+S(19)+D(4)+A(1)+Y(25)]= 32-68= -36 ans.

Like? Yes (2) | No (4)  

julee verma   10 years AGO

(Addition of first three alphabets)-(addition of remaining alphabets) = value

[S(19)+U(21)+N(14)]-[D(4)A(1)Y(25)] =54-30=24
[M(13)+O(15)+N(14)]-[D(4)+A(1)+Y(25)] =42-30=12
[T(20)+U(21)+E(5)]-[S(19)+D(4)+A(1)Y(25)]=46-49=-3
[W(23)+E(5)+D(4)]-[N(14)+E(5)+S(19)+D(4)+A(1)+Y(25)]= 32-68= -36 answer is 36.

Like? Yes (2) | No (4)  

muni   10 years AGO

remove first 3 numbers sum from remaining numbers

Like? Yes (2) | No (4)  

RAKESH   10 years AGO

WEDNESDAY = WED-NESDAY = -36

Like? Yes (2) | No (4)  

sruthi   10 years AGO

eg;sunday s+u+n-d+a+y=54-30=24
that is wednesday =32-68=-36
so ans is -36

Like? Yes (2) | No (4)  

RANA MONDAL   10 years AGO

SUNDAY=24
(19+21+14)-(4+1+25)=24
MONDAY=12
(13+15+14)-(4+1+25)=12
TUESDAY=-3
(20+21+5)-(19+4+1+25)=-3
WEDNESDAY
(23+5+4)-(14+5+19+4+1+25)=-36
Ans: -36

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harshal agrawal   10 years AGO

(23+5+4)-(14+5+19+4+1+25)
-36

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Rashmi bharti   10 years AGO

-36 is the answer.

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Nitesh Joshi   10 years AGO

IN THIS PUZZLE, answer is the [{sum of first 3 alphabet}-{sum of rest alphabet}] SUNDAY= s(19)+U(21)+N(14)-D(4)-A(1)-Y(25)=24
MONDAY= M(13)+O(15)+N(14)-D(4)-A(1)-Y(25)=12
TUESDAY=T(20)+U(21)+E(5)-S(19)-D(4)-A(1)-Y(25)= -3
THEREFORE,
WEDNESDAY= W(23)+E(5)+D(4)-N(14)-E(5)-S(19)-D(4)-A(1)-Y(25)= -36

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mansi garg   10 years AGO

s=19 u=21 n=14 d=4 a=1 y=25
s+u+n=54
d+a+y=30
sun-day=24

logic is sum of first three term -sum of rest of the number
w=23 e=5 d=4 n=14 e=5 s=19 d=4 a=1 y=25
wed=32
nesday=68
wed-nesday=-36

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ASHISH MITTAL   10 years AGO

if a=1,b=2,c=3,d=4 and so on
no of first three words - no of remaining word
so for wednesday
23+5+4-(14+5+19+30) =-36 option(4)

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Dinesh thatti   10 years AGO

add first 3 digits sum and subtract it from remaining sum of digits
SUN=19+21+14=54 DAY=04+01+25=30 54-30=24
MON=13+15+14=42 DAY=04+01+25=30 42-30=12
TUE=20+21+05=46 SDAY=19+04+01+25=49 46-49=-3
WED=23+05+04=32 NESDAY=14+05+19+04+01+25=68=-36

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