M4maths Previous Puzzles

27 Mar 2014 Solve

Solve following equations
3(2u+v) = 7uv (i)
3(u+3v) = 11uv (ii)

OPtion

1) u=2, v=1/4
2) u=3, v=3/2
3) u=4, v=5
4) u=1/3, v=1
5) u=4, v=1/2
6) u=1, v=3/2
7) u=3, v=1/2
8) u=5, v=1/5
9) u=1, v=1
10)None of these

Solution

Solve linear equation
divide uv in both site of equation
and put 1/u = x and 1/v = y
and solve

u=1, v=3/2

Option 6)

Correct Option: 6 Best Solution (73)

Ann Theressa   10 years AGO

3(2u+v) = 7uv ---(i)
3(u+3v) = 11uv --- (ii)

6u + 3V = 7uv ---(1)
3u +9v = 11uv ---(2)

multiply (2) by 2

6u +18v = 22uv---(3)

eqn (3) - (2)

15v = 15uv
==> u=1
v = 3/2

Like? Yes (27) | No (10)  

Sivanjali   10 years AGO

Given equations are
6u + 3v = 7uv --- (1)
3u + 9v = 11uv --- (2)
Multiplying eqn (2) by 2,
6u + 18v = 22uv --- (3)
After solving eqn (1) and (3)
15v = 15uv
u = 1 and v = 3/2

Like? Yes (13) | No (7)  

azharshahid01@gmail.com   10 years AGO

Given Equations
3(2u+v)=7uv--(1)
3(u+3v)=11uv--(2)
On solving,
6u+3v= 7uv---(1)
3u+9v= 11uv---(2)
On multiplying equation (2) by 2. We get,
6u+3v= 7uv---(1)
6u+18v= 11uv---(2)
On solving,
u=1 and v=3/2.
So, result is option 6)u=1, v=3/2.

Like? Yes (13) | No (8)  

saurabh agarwal   10 years AGO

6u+3v-7uv=0...(1)
3u+9v-11uv=0...(2)
solve 1 and 2 we get u=1,v=3/2.

Like? Yes (5) | No (2)  

D.Ragulkumar   10 years AGO

3(2u+v)=7uv
3(u+3v)=11uv
calculation
6u+3v=7uv
(*2)6u+18v=22uv
-15v=-15uv
u=1
u in above equation
3+9v=11v
v=3/2

Like? Yes (6) | No (3)  

Devendra Marghade   10 years AGO

3(2u+v) = 7uv (i)
3(u+3v) = 11uv (ii)
Simplifying (i),6u+3v=7uv ---(iii)
Simplifying (ii,3u+9v=11uv ---(iv)
Solving,(iii)&(iv),u=1, v=3/2

Like? Yes (3) | No (1)  

Surya Narayana K   10 years AGO

Given eqns are
6u+3v=7uv
3u+9v=11uv
after solving we get
u= 1, v = 3/2

Like? Yes (4) | No (2)  

SONU GUPTA   10 years AGO

6u+3v=7uv-----(1)
3u+9v=11uv-----(2)*2
6u+18v=22uv
-15v=-15uv
u=1; v=3/2

Like? Yes (3) | No (1)  

J.DHANDAPANI   10 years AGO

Dividing throughout by uv,we get
(6/v)+(3/u)=7.
(3/v)+(9/u)=11.
Solving gives u=1 and v=3/2.

Like? Yes (3) | No (1)  

Varunraj Reddy   10 years AGO

Multiply eq i) with 3 we get
18u+9v=21uv....i)

subtract eq ii)
18u+9v=21uv....i)
-3u-9v=-11uv....ii)
-----------------
15u=10uv
v=3/2
Put v value in eqn ii)we get u=1

Like? Yes (3) | No (1)  

nilu kumari   10 years AGO

GO through the option
and, option 6. satisfies both the conditions
ie. u=1, v=3/2

Like? Yes (4) | No (2)  

Deepa waswani   10 years AGO

6u+3v=7uv .....(1)
3u+9v=11uv ....(2)
from eqn (1) => uv=(6u+3v)/7
put the value of uv in eqn (2)
3u+9v=11[(6u+3v)/7]
solving this eqn, we get, 45u-30v=0....(3)
from eqn (3), u=2v/3
substituting the value of u in eqn (1), we get,
v=3/2
and then using the value of v , we obtain the value of u=1

Like? Yes (3) | No (1)  

muni   10 years AGO

substitute u and v values in given equations

Like? Yes (3) | No (1)  

Sudipta Mukherjee   10 years AGO

6/v+3/u=7
3/v+9/u=11
u=1,v=3/2

Like? Yes (5) | No (3)  

meghana   10 years AGO

given : 3(2u+v)=7uv ...........(1)
3(u+3v)=11uv............(2)
solve : eq(1)and eq(2) then we get
6u+3v=7uv................(3)
3u+9v=11uv................(4)
multiply eq(3) by 11 and eq(4) by 7 then equations become
66u+33v=77uv
21u+63v=77uv
By solving above 2 equations we get 45u-30v=0
=> 3u=2v-----------eq(5)
substitute eq-5 in eq-4 then we get "u=1".
substitute "u=1" in eq-(5) then we get "v=(3/2)".






.

Like? Yes (3) | No (1)  

K.Sumathi   10 years AGO

6u+3v=7uv ---1
3u+9v=11uv ---2
After solving 1 and 2
we get
u=1
v=3/2

Like? Yes (3) | No (1)  

ASHISH MITTAL   10 years AGO

by solving this equation we get
u=1, v=3/2

Like? Yes (3) | No (1)  

saikiran   10 years AGO

by solving two equations
we get u=1,v=3/2

Like? Yes (3) | No (1)  

S.SHAFI   10 years AGO

Given Equations are..

6u+3v = 7uv
3u+9v = 11uv

solving we get, u=1, v=3/2..

Like? Yes (4) | No (3)  

SHEREENA NISHAD   10 years AGO

6u + 3v = 7uv....(1)
3u + 9v = 11uv...(2)
Multiply eqn (2) by 2
6u + 18v = 22uv ....(3)
(3) - (1) gives
15v=15uv
Then
u=1
substitute u=1 in any eqn
we get v=3/2

Like? Yes (6) | No (5)  

Leelanand Kumar Yalla   10 years AGO

6U+3V=7UV--------->(1);
3U+9V=11UV---------->(2);
By solving these two equations we will get U=1, V=3/2;......

Like? Yes (3) | No (2)  

SAM   10 years AGO

6u+3v = 7uv......(1)*3
3u+9v = 11uv......(2)

on solving

u=1,v=3/2

Like? Yes (4) | No (3)  

Saidinesh   10 years AGO

solving equation 1 and 2
3u=2v;
u/v=2/3;
it happens for only 6th option

Like? Yes (2) | No (1)  

AVIJIT   10 years AGO

from 1st equation
3(2u+v)= 7uv
i.e 6u+3v=7uv
or, 6u-7uv= -3v
or, u = 3v/(7v-6)
now put the value of u in the 2nd equation
we will get 3[(3v/7v-6)+3v] = 11(3v/7v-6)v
or 3[21v^2 - 15v]=33v^2
or 10v^2 - 15v = 0
v= 3/2
put the value of v in the 1st equation well get u = 1
so u= 1,v=3/2

Like? Yes (2) | No (2)  

gopisetty utpala   10 years AGO

by solving above two equations
we get u=1,v=3\2

Like? Yes (2) | No (2)  

Sandeep Jadala   10 years AGO

3(2u+v)=7uv
3(u+3v)=11uv
6u+3v=7uv
3u+9v=11uv
solve both equations u=1 & v=3/2

Like? Yes (2) | No (2)  

B karthik   10 years AGO

u=1,v=3/2
by doing calculation

Like? Yes (1) | No (1)  

Pallekonda Rajesh   10 years AGO

6u+3v=7uv,3u+9v=11uv
equate uv from two equations we get u=(2/3)v
substitute in any above equation
we get ans u=1,v=3/2

Like? Yes (1) | No (1)  

avinash kumar   10 years AGO

6u + 3v = 7uv ... (I) ....
3u + 9v = 11uv ... (II) ....
Dividing uv in both sides of eqn (I) and (II) .....
6u + 3v = 7uv
---> 6u / uv + 3v / uv = 7uv / uv
---> 6 / v + 3 / u = 7 ... (III) ....
Also ....
3u / uv + 9v / uv = 11uv / uv
----> 3 / v + 9 / u = 11 ..... (IV) ...
multiplying 2 to eqn IV ....
we get :-
6 / v + 18 / u = 22 .... (V) ...
solving III and V :-
u = 1 ..... v = 3 / 2 ....
So, u = 1 .. (ans) ..
v = 3 / 2 ... (ans) ..

Like? Yes (1) | No (1)  

ANURAG VERMA   10 years AGO

6u + 3v = 7uv ... (I)
3u + 9v = 11uv ... (II)
Dividing uv in both sides of eqn (I) and (II)
6u + 3v = 7uv
---> 6u / uv + 3v / uv = 7uv / uv
---> 6 / v + 3 / u = 7 ... (III)
Also
3u / uv + 9v / uv = 11uv / uv
----> 3 / v + 9 / u = 11 ..... (IV)
multiplying 2 to eqn IV
we get :-
6 / v + 18 / u = 22 .... (V)
solving III and V :-
u = 1 ..... v = 3 / 2

Like? Yes (1) | No (1)  

ritika mehrotra   10 years AGO

6u+3v=7uv
3u+9v=11uv
divide the whole eq by uv
(6/v)+(3/u)=7
(3/v)+(9/u)=11
let (1/v)=x;(1/u)=y
6x+3y=7
3x+9y=11
thus x=(2/3);y=1
therefore;u=1;v=(3/2)

Like? Yes (1) | No (1)  

hanamant k   10 years AGO

on dividing (1)/(2)
we get
3u-2v=0
==>u=2/3v ----(3) put this value in equ (1)

so ,then u will get v=3/2

put this value in equ (3)
then u will get u=1

hence u=1,v=2/3

Like? Yes (1) | No (1)  

Abdullah Khilji   10 years AGO

3(2u+v) = 7uv (i)
3(u+3v) = 11uv (ii)
6u+3v = 7uv (i)
3u+9v = 11uv (ii)
now multiplying equation (ii) by 2, we get
6u+3v = 7uv (i)
6u+18v = 22uv (ii)
- - -
_______________
-15v = -15uv
dividing both sides by -15v, we get
1 = u
now putting value of u in eq. (i) we get
3(2u+v) = 7uv (i)
3(2+v) = 7v
6+3v = 7v
6 = 4v
v = 3/2
Q.E.D.

Like? Yes (1) | No (1)  

Sohar Lal Singh   10 years AGO

given equation are
3(2u+v)=7uv.........(i)
3(u+3v)=11uv.........(ii)
divide the equatuon (i) by (ii)
(2u+v)/(u+3v)=7/11
cross multiply
11*(2u+v)=7*(u+3v)
22u+11v=7u+21v
22u-7u=21v-11v
15u=10v
3u=2v
or
v=(3/2)*u.....(iii)
put this value in equation i
we get
3(2u+3/2*u)=7u*3/2u
21u=21u*u
u=1 ans
and from (iii)
v=3/2*u then
v=3/2
hence option 6

Like? Yes (1) | No (1)  

Rohit Agarwal   10 years AGO

from (1)
uv=(6u+3v)/7--------------->(3)
from (2)
uv=(3u+9v)/11-------------->(4)

comparing (3) and (4)

u=(2/3)v
putting value of u in equation (3)

v=3/2 so u=1

Like? Yes (1) | No (1)  

Rohit Singh Panwar   10 years AGO

6u+3v=7uv (i)
3u+9v=11uv (ii)

9u+18v=22uv (ii*2)

15v=15uv (ii*2-i)

u=1

from eq (i)

6+3v=7v
4v=6
v=3/2

Like? Yes (1) | No (1)  

Gudivada sunitha   10 years AGO

check all options and 6 th correct option.

Like? Yes (1) | No (1)  

himesh suthar   10 years AGO

6u + 3v = 7uv

---> 6u / uv + 3v / uv = 7uv / uv

---> 6 / v + 3 / u = 7 ... (III) ....

Also ....

3u / uv + 9v / uv = 11uv / uv

----> 3 / v + 9 / u = 11 ..... (IV) ...

multiplying 2 to eqn IV ....

we get :-

6 / v + 18 / u = 22 .... (V) ...

solving III and V :-

u = 1 ..... v = 3 / 2 ....

So, u = 1 .. (ans) ..

v = 3 / 2 ... (ans) ..

Like? Yes (1) | No (1)  

karthika kumar   10 years AGO

6u+3v=7uv ---- (1)
3u+9v=11uv ---- (2)
(2)*2 --> 6u+18v=22uv
(1)-----> 6u+3v=7uv (-)
15v=15uv
=> u=1
substitute u=1 in (1) we get, 6+3v=7v => v=6/4=3/2

Like? Yes (1) | No (1)  

jyoti   10 years AGO

6u/uv+3v/uv=7uv/uv=>6/v+3/u=7
3u/uv+9v/uv=11uv/uv=>3/v+9/u=11
solving the above equation we get u=1 and v=3/2

Like? Yes (1) | No (1)  

MD SOHAIL AKHTER   10 years AGO

multiply eqn1 by 11 and eqn2 by 7,on solving we get;
u=1 and v=3/2

Like? Yes (1) | No (1)  

Aakash Jain   10 years AGO

on solving both equations
we get u=1 and v=3/2

Like? Yes (1) | No (1)  

Kowshik Sarker   10 years AGO

(2u+v)/(u+3v)=7/11.solving this we get
u/v=2/3.
so,u=(2/3)*v
putting this value in 3(2u+v)=7uv we get v=3/2
thus u=1.which is option 6.

Like? Yes (1) | No (1)  

ADVAITA BASAK   10 years AGO

6u+3v=7uv
3u+9v=11uv

by solving u=1, v=3/2

Like? Yes (1) | No (1)  

Rahul Kesharwani   10 years AGO

Solve n simplify (i) equation, there u got
v = 7uv/3 - 2u
put this value in another one,
then solve again another one

Like? Yes (1) | No (1)  

Pooja LOhar   10 years AGO

6u + 3v = 7uv ... (I) ....
3u + 9v = 11uv ... (II) ....
Dividing uv in both sides of eqn (I) and (II) .....
6u + 3v = 7uv
---> 6u / uv + 3v / uv = 7uv / uv
---> 6 / v + 3 / u = 7 ... (III) ....
Also ....
3u / uv + 9v / uv = 11uv / uv
----> 3 / v + 9 / u = 11 ..... (IV) ...
multiplying 2 to eqn IV ....
we get :-
6 / v + 18 / u = 22 .... (V) ...
solving III and V :-
u = 1 ..... v = 3 / 2 ....
So, u = 1 .. (ans) ..
v = 3 / 2 ... (ans) ..

Like? Yes (2) | No (2)  

SUPROTIM PAUL   10 years AGO

by solving two equations we get the value of U & V

Like? Yes (1) | No (1)  

ram kiran   10 years AGO

substitute the options in equations

Like? Yes (1) | No (1)  

indu   10 years AGO

multiply equation (ii) with 2 and subtract from equation(i) then we will get
u=1,
by substituting u=1 in any of the two equations we will get
v=3/2.

Like? Yes (1) | No (1)  

P.Selva Dhasni   10 years AGO

Answer is 6) u=1, v=3/2

3(2u+v)=7uv => 6u+3v=7uv => i)
3(u+3v)=11uv => 3u+9v=11uv =>ii)

multiply 2nd equation with -2.we get,

-6u-18v=-22uv => ii)

now solve the two equations,

6u+3v = 7uv
-6u-18v= -22uv

the solutions are,

u=1 and v=3/2..........:)

Like? Yes (1) | No (1)  

Vivek Jain   10 years AGO

11*(i) - 7*(ii),we get
45u=30v
checking by option we get u=1,v=3/2

Like? Yes (1) | No (1)  

vishnuvardhan   10 years AGO

-5u=uv*-10/3
v=3/2,u=1

Like? Yes (1) | No (1)  

kedasu suresh   10 years AGO

from given equations

Like? Yes (1) | No (1)  

rahul   10 years AGO

by solving the equation u=1, v=3/2

Like? Yes (1) | No (1)  

karthik hariharan   10 years AGO

3(2u+v)=7uv *3
3(u+3v)=11uv *6

solve this equation in eliminating method..
u=1,v=3/2

Like? Yes (2) | No (2)  

Santosh Vishwakarma   10 years AGO

just put the values
u=1 and v=3/2.

Like? Yes (1) | No (1)  

R.RAVIKUMAR   10 years AGO

From given eqns,
6u+3v = 7uv
3u+9v = 11uv
By solving two eqns, we get u=1 and v=3/2

Like? Yes (1) | No (2)  

Rajasekhar Reddy   10 years AGO

6u+3v = 7uv
3u+9v = 11uv

solving above two equations we get
u = 1
v = 3/2

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

3(2u+v) = 7uv => 2/v + 1/u = 7/3 ---(1)

3(u+3v) = 11uv => 1/v + 3/u = 11/3 ---(2)

(1)*3-(2)
v=3/2 & u=1

Like? Yes (1) | No (2)  

ChinnaChowdaiah   10 years AGO

6u+9v=21uv -->(1)*3
3u+54v=11uv--->(2)*6
18u+9v=21uv
18u+54v=66uv
by solving this u=1
v=3/2

Like? Yes (1) | No (2)  

Soumya   10 years AGO

3(2u+v)=7uv=>6u+3v=7uv=>eqn*3=>18u+9v=21uv...........(1)
3(u+3v)=11uv=>3u+9v=11uv=>*by 6=>18u+54v=66uv........(2)
Now solvin eqn 1&2 we get
U=1 and v=3/2 hence option 6 is the answer.

Like? Yes (2) | No (3)  

virendra dubey   10 years AGO

3(2u+v)=7uv.==>6u+3v=7uv..(i)
3(u+3v)=11uv==>3u+9v=11uv..(ii)
now multiplying eq2 by 2
we get
6u+18v=22uv..(iii)
now subtract equation 3 from eq1
we get u=1 and v=3/2 so correct option(6)

Like? Yes (1) | No (2)  

Rashmi bharti   10 years AGO

the equations are
(3/v)+(9/u)=11
(6/v)+(3/u)=7
on solving we get,u=1 & v=3/2

Like? Yes (2) | No (3)  

rajesh   10 years AGO

by data

Like? Yes (1) | No (2)  

Bharat Bhushan Jha   10 years AGO

Satisfy only option 6

Like? Yes (1) | No (2)  

Soham Dalwadi   10 years AGO

6u + 3v = 7uv (i)
3u + 9v = 11uv (ii)
(i)

Like? Yes (1) | No (2)  

pawan kumar chhipa   10 years AGO

6u+3v=7uv .....(i)
3u+9v=11uv .....(ii)

equation (ii) multiply by 2 and subtract from (i)

15= 15u
u=1
and get v=3/2

Like? Yes (1) | No (2)  

champavat jaydipsinh padamsinh   10 years AGO

6u + 3v = 7uv (i)
3u + 9v = 11uv(ii)

equ(i) multiply by 6
equ(ii)multiply by 3

so,
18u + 9v =21uv
18u + 54v=66uv

solve both equ than

u = 1

v = 3/2

Like? Yes (1) | No (2)  

Snehasis   10 years AGO

the equations can be made are :
6u+3v=7uv(i)
3u+9v=11uv(ii)
After solving the equations,
u= 1 and v = 3/2

Like? Yes (2) | No (3)  

sandip   10 years AGO

3(2u+v)/3(u+3v)=7/11
or,22u+11v = 7u+21v
or,u=2v/3
let put the value of u in any equation we can get the value of v.
so V=2/3 and U=1.
hence ans is option 6.

Like? Yes (1) | No (2)  

Baburaya   10 years AGO

solve the simultaneous eqn . . .

Like? Yes (1) | No (2)  

nikhil   10 years AGO

on solving equations we u=1
and putting this value in any one equation we get v=3/2.

Like? Yes (1) | No (2)  

sethupathi.p   10 years AGO

solving the equation

Like? Yes (1) | No (2)  

26 Mar 2014 Find the Speed

Vijay travels 600 km to his home party by train and partly by car. He takes 8 hours if he travels 120 km by train and rest by car. He takes 20 minutes longer if he travels 200 km by train and rest by car. Find the speed of the train.

OPtion

1) 70 km/hr
2) 75 km/h4
3) 65 km/hr
4) 85 km/h4
5) 50 km/hr
6) 80 km/hr
7) 60 km/hr
8) 55 km/hr
9) 90 km/hr
10)None of these

Solution

Le the speed of the train be x km/hr and speed of car be y km/hr
Vijay travels 120 km by train, the distance covered by car 600-120 = 480 km
Now, time taken to cover 120 km by train = 120/xhr
And time taken to cover 480 km by car = 480/y
Total time taken to travel 600 km = 120/x + 480/y = 8 hr (i)
Similarly
200/x + 400/y = 8hr. 20minute = 8(20/60) (ii)

solve (i) and (ii)
we get
x = 60 km/hr and y = 80 km/hr

Option 7) speed of train 60 km/hr

Correct Option: 7 Best Solution (36)

Akanksha Mishra   10 years AGO

Given
Total distance = 600 km
Consider speed of Train = x km/h
Consider speed of Car = y km/h
According to the question:
We know Time = distance/speed

Situation 1
He takes 8 hours if he travels 120 km by train and rest by car

120/x + 480/y = 8-------(1)

Situation (2)
when he travels 200 km by train and rest by car he takes 8 hr 20 min
8 hr 20 min = 25/3 hr

200/x + 400/y = 25/3 ---------(2)

solve equation 1 and 2

you'll get x = 60
so the speed of the train = 60 km/h(option 7)

Like? Yes (53) | No (18)  

Amit Kumar Panda   10 years AGO

If he goes by train more 80 km den the time increases 20 minute ..
if he goes less 80 km den ime decreases by 20 minute
120km bytrain+480km by car=8 hr
40km by train+560 km bycar=7hr 40 min
600 km bycar=7hr 30 min
car speed=80 km/hr
=>train speed =60 km/hr

Like? Yes (29) | No (7)  

Snehasis   10 years AGO

for 120 km it takes 8 hours and for each 80 kms 20 minutes is taken more then, in 10 hrs the train can travel full 600 kms. therefore, the speed of the train is 60km/h.

Like? Yes (26) | No (17)  

Ann Theressa   10 years AGO

Let x be the speed of train and y speed of car in km/hr.

Distance/speed = time taken

120/x + 480/y = 8 ---(1)

200/x + 400/y =25/3---(2)[time taken is 8hr 20min]

Multiply (1) by 5/4 and (2) by 3/2

150/x + 600/y = 10 ---(3)

300/x + 600/y = 25/2 ---(4)

equation (4) - (3)

150/x = 5/2
x = 150 * 2/5 = 60

Like? Yes (10) | No (4)  

Surya Narayana K   10 years AGO

Answer 60km/hr (Option 7).

Let speed of the train x and speed of the car y.

In first case,total duration is 8 hours(480 min) and train travels 120 km so 480=(120/x)+(480/y)
==>120y+480x=480 --(1)

similarly in the second case, total duration is 8 hr 20 min (500 min) and train travels 200 km .So 500=(200/x)+(400/y)==>200y+400x=500xy--(2)

After solving (1) and (2), we get 3y=4x --(3)

Substitute (3) in (1) , then x=60km/hr and y=80km/hr.

So train speed =60 km/hr (Option 7)

Like? Yes (8) | No (2)  

Nitin Jaiswal   10 years AGO

let the velocity of train be v1 and that of car be v2.
then,120/v1+480/v2=8
and 200/v1+400/v2=8.33
by solving the above 2 equations simultaneously we get v1(velocity of train)=60

Like? Yes (6) | No (2)  

S.SHAFI   10 years AGO

lets take speed of train be x km/h and speed of car be y km/h...
Equations will be

120/x + 480/y = 8 ---------(1)
200/x + 400/y = 25/3 ------(2) 8hr20min = 25/3hr

Solving these equations..

Speed of the train(x) = 60km/h
Speed of the car(y) = 80km/h..

Like? Yes (7) | No (4)  

Saidinesh   10 years AGO

120km by train. so remaining 480 by car. we can form an equation 120/x+480/y=8 eqn1 and if he travels 200km by train he took 20 mins extra. so 200/x+400/y=8hrs 20mins which is equal to 25/3 this is eqn no2. solve this both u can get value of x. x-speed of train& y-speed of car

Like? Yes (5) | No (2)  

AVIJIT   10 years AGO

let train's speed is and speed of car is y
1st equation is 120/x+480/y = 8.....(1)
and 2nd equation is 200/x+400/y = 25/3...(2)
8 hrs 20 min= 25/3 hrs
now solving two equation we will get x=60
train's speed is 60 km/hr

Like? Yes (4) | No (1)  

amit kumar   10 years AGO

120/x + 480/y =8
200/x + 400/y =8+20/60

2 equation and 2 unknown.solve for x and y

Like? Yes (5) | No (2)  

ARJYA HALDER   10 years AGO

Let, speed of the train be x &
speed of the bus be y.
From question (480/y)+(120/x)=8
& (400/y)+(200/x)=8+(1/3)

Solving these equations we get, x=60.

Like? Yes (4) | No (1)  

AKASH KUMAR   10 years AGO

Ans-7)60km/hr
equation:-
120/x + 480/y =8 (x=speed of train, y=speed of car)
from 2nd condition
200/x + 400/y =25/3 (a/q- 20 min more)
hence solving above 2 eq.
x=60km/hr
y=80km/hr.

Like? Yes (5) | No (2)  

Siddharth Singh   10 years AGO

let speed of train be t=1/x
and speed of car be c=1/y

when vijay travels 120 km by train and 480 by car,
the equation becomes:
=> 120/t +480/c = 8
=> 120x + 480y = 8

similarly, for second case
=> 200x + 400y= 25/3

solving the two equations,
=> 120x + 480y = 8
and
=> 200x + 400y= 25/3
we have x=1/60 and y=1/80

thus speed of train =>1/x = 60

Like? Yes (4) | No (1)  

muni   10 years AGO

consider speed of train is x and speed of car is y
total time equation if he travels on train 120km
120y+480x=8xy--1
total time equation if he travels on train 200km
200y+400x=25/3xy--2
solving 1 and 2 we get
x=60 and y=80

Like? Yes (3) | No (1)  

madanpal vishwakarma    10 years AGO

let assume that the speed of train is x and car is y
so according to the qustion
(120/x)+(480/y)=8h.......eq (i)
(200/x)+(400/y)=8h20minute

after solving this x=60 and y=80
so option 7 is corect

Like? Yes (3) | No (1)  

ANUP KUMAR   10 years AGO

We know that Time = Distance/speed
therefore there will be 2 eqn.
let x = speed of the train and y be the speed of car
1. 120/x + 480/y = 480 mins
2. 200/x + 400/y = 500 mins
by solving this 2 eqns we get x= 1 km/min = 60km/hr....
therefore speed of train is 60km/hr

Like? Yes (5) | No (3)  

SAM   10 years AGO

let speed of train = x km/hr
and speed of car = y km/hr
so,time taken by both in 1st case,

120/x + 480/y = 8......(1)
200/x + 400/y = 25/3......(2)

solve eqsn (1) & (2)

x=60km/hr
y=80km/hr

Like? Yes (5) | No (3)  

Vivek Jain   10 years AGO

120/Ts + 480/Cs = 8 ..(i)
200/Ts + 400/Cs = 25/3...(ii)
Ts=240/4=60Km/hr

Like? Yes (2) | No (1)  

Sudipta Mukherjee   10 years AGO

120/x+480/y=8
200/x+400/y=25/3
x=60km/hr

Like? Yes (2) | No (1)  

Suman Saurabh   10 years AGO

120/x + 480/y =8

200/x + 400/y = 25/3

so, x= 60km/hr

Like? Yes (2) | No (1)  

Rajasekhar Reddy   10 years AGO

120/T + 480/C = 8hr
200/T + 400/C = 8hr 20 min
solving above two equations
we get T = 60kmph

Like? Yes (4) | No (3)  

R.RAVIKUMAR   10 years AGO

Let the speeds of train and car be 'T' and 'C'..
From given instructions,

120/T + 480/C = 8hr
200/T + 400/C = 8hr.20min = 25/3 hr

By solving two equations,we get T = 60km/hr...

Like? Yes (4) | No (3)  

SIBNATH HALDER   10 years AGO

let train velocity=X,car velocity=Y
1st eq 120 X+480 Y=36000......(1)
2nd eq 200 X+400 Y=36020......(2)
after solve X=60.2 km/hr

Like? Yes (4) | No (3)  

saikiran   10 years AGO

480 minutes=(120/train velocity)+(480/car velocity)
500 minutes=(200/train velocity)+(400/car velocity)
by solving above euations
we get train vlocity=60km/hour

Like? Yes (3) | No (2)  

B karthik   10 years AGO

480 minutes=(120/train velocity)+(480/car velocity)
500 minutes=(200/train velocity)+(400/car velocity)
by solving above euations
we get train vlocity=60km/hour

Like? Yes (4) | No (3)  

Sofia Amreen   10 years AGO

et the speed of the train be x km/hr and that of the car be y km/hr.

Then, (120/x)+(480/y)= 8
(1/x)+(4/y)=1/15 ....(i)
And, (200/x) +(400/y)=25/3
(1/x)+(2/y)=1/24 ....(ii)
Solving (i) and (ii), we get: x = 60 and y = 80.

Like? Yes (4) | No (3)  

Kumar   10 years AGO

as we know distance/speed=time
as we write the equations as per formula
we will get
120/x+480/y=8
200/x+400/y=25/3
solve above equations
for simplicity assume a=1/x,b=1/y;
then solve the equations
we will get x=60kmph,y=80kmph
finally train speed=60kmph

Like? Yes (4) | No (3)  

himesh suthar   10 years AGO

total km=600
by train 120
car=480
480/80=6
120/60=2
6+2=8 hours
now by train 200 km means it will take 200 min..
means 3 hours nd 20 min
nd remaining 400/80kmph=5
total =5 hours +3 hour nd 20 min.
so it took 20 min extra. so train speed 60kmph

Like? Yes (3) | No (2)  

BHAVNISH BHUTANI   10 years AGO

[(400*120)-(480*200)]/[(400*8)-(480*25/3)]=60

Like? Yes (2) | No (1)  

RAKESH   10 years AGO

120/x + 480/y = 8

200/x + 400/y = (8+ 1/3)

=> x=60

Like? Yes (2) | No (2)  

Devendra Marghade   10 years AGO

If Speed of train=x, car=y
1st Condition:(120/x)+(480/y)=8 ---(i) &
2nd Condition:(200/x)+(400/y)=[8+(1/3)] ---(ii)
Solving (i) & (ii), x=60, y=80

Like? Yes (2) | No (2)  

ASHISH MITTAL   10 years AGO

(120/t)+(480/c)=8
(200/t)+(400/c)=25/3
after solving we get t=60

Like? Yes (2) | No (2)  

ADVAITA BASAK   10 years AGO

60 km/hr

Like? Yes (2) | No (2)  

Rohit Agarwal   10 years AGO

let the speed of the train is vx and spped of car is vy.
so according to first condition

8=120/vx + 480/vy

so vx *vy=15*vy + 60*vx---------------(1)

and according to second condition

time=8+1/3=25/3

so 25/3=200/vx + 400/vy

so vx*vy=24*vy + 48*vx--------------(2)

by first and second condition

24*vy + 48*vx = 15*vy + 60*vx

so vy=4/3 * vx

putting vy in equation (1)

vx=60 km/hr

Like? Yes (3) | No (3)  

SONU GUPTA   10 years AGO

answer will be 60km/hr

Like? Yes (2) | No (2)  

Prerna   10 years AGO

120/t + 480/C= 8
200/t + 400/C= 25/3
solving these eqns, we get,
t=60 kmph

Like? Yes (2) | No (4)  

25 Mar 2014 Solve

If Suraj obtains 10% marks more then Amit then how many % less marks are obtained by Amit than Suraj.

OPtion

1) 9
2) 9.08
3) 10
4) 10.1
5) 10.01
6) 9.09
7) 9.9
8) 9.8
9) 11
10)None of these

Solution

Let marks of Amit is x
Then according to given condition marks of Suraj is 1.1x
Difference of marks is 1.1x – x = 0.1x
Hence marks of Amit are (0.1x/1.1x)*100 = 100/11 = 9.09 % less than marks of Suraj.

Correct Option: 6 Best Solution (50)

ANUP KUMAR   10 years AGO

let Amit's marks=100
Then Suraj's marks =100+10% of 100=110
less marks= 10
%less marks compared to Suraj=(10/110)*100%=9.09%

Like? Yes (14) | No (2)  

Surya Narayana K   10 years AGO

percentage decrement of Amit than Suraj

((110-100)/110)*100 = 9.09

Like? Yes (2) | No   

virendra dubey   10 years AGO

let amit got x marks..
so suraj got x+(x/10)==>(11/10)x marks...
so amit obtain %less marks than suraj= (x*10*100)/(10*11x)==> 9.09...

Like? Yes (2) | No   

Dr.Dipin Singh   10 years AGO

If Suraj obtains 10% marks more then Amit then it means
If Suraj obtains 110 marks , then Amit gets 100 marks.
% less marks obtained by Amit than Suraj= 100*10/110=100/11=9.09% ..option 6

Like? Yes (3) | No (2)  

B karthik   10 years AGO

(1.1X-1X)/1.1X=0.09
0.09*100=9.09...

Like? Yes (1) | No   

Rashmi bharti   10 years AGO

marks=((110-100)/110)*100=9.09

Like? Yes (1) | No   

madanpal vishwakarma    10 years AGO

A is 10% more than B
A = B + 0.1 B
A = 1.1 B

B = 1/1.1 A
B = 0.909090909 A
B = (1 − 0.090909091) A
B = A − 0.090909091 A

B is 9.091% less than A

so option 6 ) 9.09 is correct

Like? Yes (2) | No (1)  

Sivanjali   10 years AGO

Percentage of decrement of Amit than Suraj
((110-100)/110)*100 = 9.09

Like? Yes (2) | No (1)  

Satish Zod   10 years AGO

10/110 x 100 = 9.09 %

Like? Yes (1) | No   

Saraswathy   10 years AGO

Amit = R/100+R * 100%
=====> 10/110 * 100
=====> 9.09

Option (6)

Like? Yes (3) | No (2)  

SIVA DARA   10 years AGO

let Amit got 100. then Suraj got 110.
the difference betweet Suraj and Amit is 10.
So (10/110)*100=9.09%

Like? Yes (1) | No   

Pallekonda Rajesh   10 years AGO

suraj=1.1*amit
amit=suraj/1.1=0.909090*suraj=1-0.0909*suraj
o.0909*100=9.09% less than suraj

Like? Yes (1) | No   

Saidinesh   10 years AGO

x+0.1x =y
1.1x=y
x=y/1.1
x=y*9.09

Like? Yes (1) | No   

Soumya   10 years AGO

answer is {[10/(100+10)]*100}%
=(10/110)*100%
=9.09%

Like? Yes (1) | No   

Gourab Dhargupta   10 years AGO

100/11=9.09090909...

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

let amit=100
suraj= 110

so,
less percent = 10/110 *100
= 9.09

Like? Yes (1) | No   

sandip   10 years AGO

r=(r/100+r)*100
if given no is more than another no..
r=(r/100-r)*100
if given no is less than another no..


here suraj obtain 10% marks \"more\" than amit...
so here r = (10/110)*100=9.09

Like? Yes (1) | No   

ASHISH MITTAL   10 years AGO

(100*10)/(100+10)
=1000/110
=9.09

Like? Yes (1) | No   

Sudipta Mukherjee   10 years AGO

10/110*100=9.09

Like? Yes (1) | No   

suraj shaw   10 years AGO

amit got x marks
suraj got 110x/100
so amit got less marks =(110x/100-x)/(110x/100)

Like? Yes (1) | No   

nirmal kumar saini   10 years AGO

let Amit gets marks=100
then Suraj gets=110
then Amit get less than Suraj=110-100=10
so the percentage less than Suraj=(10/110)*100=9.09090909...%

Like? Yes (1) | No   

IFFAT IRAM   10 years AGO

let amit obtain x
suraj obtains 11x/10

difference=x/10
%=(x/10)/(11x/10)*100
= 100/11%
=9.09%

Like? Yes (1) | No   

meghana   10 years AGO

There is a formula for that :
let given 10%=x
then,less marks obtain amit than suraj is (x/(100+x)*100).
that is equal =(10/(100+10) *100) =10*100/110 =9.09

Like? Yes (1) | No   

AMIT TIWARI   10 years AGO

(10/110)*100

Like? Yes (1) | No   

R.RAVIKUMAR   10 years AGO

Let Amit marks be 'x'..
Suraj obtains 10% more than amit=x+ 10% of x =1.1x

so, to find how much less marks amit obtains than suraj..

i.e. (1.1x-x)/1.1x *100% = 9.09%

Like? Yes (2) | No (1)  

Rohit Agarwal   10 years AGO

we know that if A obtain R% marks more than B,then % marks less than A,Obtain by B=R/(100+R)*100%

SO ACCORDING TO ABOVE FORMULA,
R=10
so
10/(110)*100=9.09%

Like? Yes (1) | No   

Vivek Jain   10 years AGO

S=1.1A
then S-A/A*100=1/11*100=9.09

Like? Yes (1) | No   

Siddharth Singh   10 years AGO

say suraj has 110 marks and and amit has 100, thus satisfying the condition.

Now Amit's lags behind suraj by 10 marks,
which is=
=> ((110-100)/110)*100
=>.0909090909*100
=>09.09

Like? Yes (1) | No   

VIKASH RAY   10 years AGO

we know option 6 is currect.

Like? Yes (1) | No   

Rajasekhar Reddy   10 years AGO

let amit obtains 100 marks
and suraj obtains 110 marks
% less marks are obtained by Amit than Suraj is
(10/110)*100 = 0.909

Like? Yes (1) | No   

nilu kumari   10 years AGO

let suraj marks = 110
amit mark's= 100
% less marks= (110-100)*100/110
= 9.09

Like? Yes (1) | No   

Nitin Jaiswal   10 years AGO

Let us suppose that Amit got 100 marks then Suraj marks=110.
%age of marks Amit got less than Suraj=(110-100)/110*100=9.09%
Hence the answar will be 9.09%.

Like? Yes (1) | No   

SIBNATH HALDER   10 years AGO

required percentage =[{10/(100+10)}*100]%=9.09%

Like? Yes (1) | No   

Roopa Gnanashekar   10 years AGO

consider amit=100 then suraj=110
so their difference is 10
(10/110)*100=9.09

Like? Yes (1) | No   

shamma mohammad   10 years AGO

[R/(R+100)*100]
[10/(10+100)*100]=9.09

Like? Yes (1) | No   

basha shaik   10 years AGO

[R/(R+100)*100]
[10/(10+100)*100]=9.09

Like? Yes (1) | No   

Juie Talavia   10 years AGO

Assume that the marks scored by Amit are 100. Hence, marks scored by Suraj are 110.
Now, %less marks obtained by Amit than Suraj= (10*100)/110
=9.090909

Like? Yes (1) | No   

anubhav verma   10 years AGO

if amit = 100
then suraj = 110
(10/110)*100=9.09

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

if a is r% more than b...then b is less than a by..
r/(100+r)*100..
10/(100+10)*100..
100/11=9.09
so option (6)..

Like? Yes (1) | No   

saisudha sarva   10 years AGO

solutn :) (10/110)*100

Like? Yes (1) | No   

Gudivada sunitha   10 years AGO

if amit obtained 100 marks then suraj marks are 110
(110-100)/110=9.09

Like? Yes (1) | No   

Manasa Papaiahgari   10 years AGO

if suraj got 110 then amith will get 100.so he will get 10 marks less than suraj..but we have to calculate it in %basis.so
110 - 10
100 - ?
(100*10)/110 = 9.09

Like? Yes (1) | No   

Sohar Lal Singh   10 years AGO

let suraj gets 110 marks and amit 100 marks
then differ in marks=110-100
=10
% marks less than suraj got amit= differ in marks/suraj marks*100=10/110*100
=9.09 % ans

Like? Yes (1) | No   

ashish kumar   10 years AGO

let the marks obtained by amit is 100
then the marks obtained by suraj =110
%less marks obtained by amiit than suraj
= 100/110*100
=9.09%

Like? Yes (1) | No (1)  

Ann Theressa   10 years AGO

Let Amith's marks = x
Suraj's marks = y

y = x+ 10%x
=(110/100)*x
=110% *x

x = (100/110)*y
= (1000/11)% *y
= 90.90% *y
= y - 9.09% y

===> x is 9.09% less than y
Amith's marks is 9.09% less than Suraj's marks

Like? Yes (1) | No (1)  

Leelanand Kumar Yalla   10 years AGO

Suppose Amit obtains 100 marks then Suraj obtains 110 marks.. then % less marks are obtained by Amit than Suraj is 10/110*100= 9.09...... this is the answer....

Like? Yes (1) | No (1)  

hanamant k   10 years AGO

assume amit marks are 100
then suraj marks are 110===>given
so,

100*10/110=9.09

Like? Yes (1) | No (1)  

muni   10 years AGO

suraj obtains 10% marks greater than amith so

let us assume amith is getting 100 marks

suraj--110

diff b/w amith and suraj is=10
10/110*100=9.09%

Like? Yes (1) | No (1)  

Devendra Marghade   10 years AGO

If marks of Amit=100 then
Marks of Suraj=110
% of Marks of Amit compared to Suraj=100*100/110
=1000/11
% less marks obtained=100-(1000/11)=100/11=9.09

Like? Yes (1) | No (1)  

Mahalakshmi   10 years AGO

LET AMIT MARK BE 100 THEN SURAJ MARK WILL BE 110.
THE DIFFERENCE BETWEEN TWO IS 10
SO 10% of 110 is 9.09

Ans 6)9.09

Like? Yes (2) | No (3)  

24 Mar 2014 Sequence

What is the next number of the following sequence
1,17,17,34,33,51,49,.......

OPtion

1) 67
2) 52
3) 68
4) 66
5) 49
6) 61
7) 102
8) 119
9) 86
10)None of these

Solution

Two series
1,17,17,34,33,51,49,.......
Ist - 1,17,33,49 (Difference is 16)
IInd - 17,34,51,(68) (17 table)

Option 3)

Correct Option: 3 Best Solution (81)

Ann Theressa   10 years AGO

16,17 18... is added to alternating numbers subtracting o,1,2... inbetween.

1+16=17

17-0=17

17+17=34

34-1=33

33+18=51

51-2=49

49+19=68

Like? Yes (10) | No (2)  

ashish kumar   10 years AGO

look at the series it is the multiple of 17 and the next no is 17n-(n-1).
17*1=17
17-0=17
17*2=34
34-(2-1)=33
17*3=51
51-(3-1)=49
17*4=68

Like? Yes (9) | No (4)  

azharshahid01@gmail.com   10 years AGO

There is alternate addition and subtraction in the series.
1,17,17,34,33,51,49...

1+16 = 17
17-0 = 17
17+17= 34
34-1 = 33
33+18= 51
51-2 = 49
49+19= 68
Thus answer is option 3)68

Like? Yes (4) | No (1)  

Varunraj Reddy   10 years AGO

Given sequence
1,17,17,34,33,51,49,.....
Difference between 2nd and 1st number=17-1=16
4th and 3rd number=34-17=17
6th and 5th number=51-33=18
similarly
8th and 7th number=x-49=19 (+1 increase)
x=19+49=68

Like? Yes (4) | No (1)  

Saraswathy   10 years AGO

Divide the series like below

(1, 17, 33, 49 ) (17, 34, 51, x)

In the first group of numbers, difference between each number is 16

In the second group, Multiply by "17" with 1, 2, 3, 4

1 * 17 = 17
2 * 14 = 34
3 * 17 = 51
4 * 17 = x ==> 68

So option is (3)

Like? Yes (4) | No (1)  

RAKESH   10 years AGO

1,17,17,34,33,51,49,..
(1,17),(17,34),(33,51),(49,x)
1+16=17
17+17=34
33+18=51
49+19=68

Like? Yes (4) | No (2)  

Krsihna Prasad   10 years AGO

1
17*1=17
1+16=17
17*2=34
17+16=33
17*3=51
33+16=49
17*4=68
Ans=68

Like? Yes (3) | No (1)  

Pulkit Dureja   10 years AGO

Seq..17*0-(0-1),17*1,17*1-(1-1),17*2,17*2-(2-1)...

Like? Yes (2) | No   

PINKY   10 years AGO

1 (17) 17 (34) 33 (51) 49 .... (68)
two sequence are working here
First->1, (1+16=17), (17+16=33),(33+16)..
Second-> multiple of 17

Like? Yes (2) | No   

Arnab Majumder   10 years AGO

1,17,17,34,33,51,49
next-
1,1*17,(1*17-0),(2*17),(2*17-1),(3*17),(3*17-2)
so next no. = 4*17=68

Like? Yes (2) | No   

VEERENDRA KUMAR K G   10 years AGO

alternate numbers addition is 16 even places .
then even number places addition is 17. hence
1+16=17
17+16=33
33+16=49

next series is
17+17=34
34+17=51
last is
51+17=68

Like? Yes (2) | No   

shamma mohammad   10 years AGO

17*1=17
17-0=17
17*2=34
34-1=33
17*3=51
51-2=49
17*4=68

Like? Yes (2) | No   

basha shaik   10 years AGO

17*1=17
17-0=17
17*2=34
34-1=33
17*3=51
51-2=49
17*4=68

Like? Yes (2) | No   

haritha   10 years AGO

check the difference between the numbers

Like? Yes (2) | No   

Soham Dalwadi   10 years AGO

In Following sequence 1,17,17,34,33,51,49,.......

The no. in odd place is incremented with +16
1+16=17, 17+16=33, 33+16=49

The no. in even place is incremented with +17
17+17=34, 34+17=51, 51+17=68

hence answer is 68

Like? Yes (3) | No (1)  

subramani   10 years AGO

1
17
(1*17)-0=17
2*17=34
(2*17)-1=33
3*17=51
(3*17)-2=49
4*17=68

Like? Yes (2) | No   

Mahalakshmi   10 years AGO

Take alternate series of 1,17,17,34,33,51,49,?
if we take alternate series we will get two sequence
1,17,33,49(addition of 16)
17,34,51,?(addition of 17 or multiples of 17)
1 * 17 =17
2 * 17 =34
3 * 17 =51
4 * 17 =68
so ans is 3)68

Like? Yes (2) | No (1)  

Sunku Mounika   10 years AGO

A/c to the series the second number is 17. and the multiples of 17 are repeating in the respective even places.
So the ans is 68.

Like? Yes (2) | No (1)  

Snehasis   10 years AGO

Just write the multiplication table of 17 with the numbers repeating two times where the repeated number is decremented by 1 every time a new number appears.
17*1=17
17*1=17

17*2=34
17*2=34-1=33

17*3=51
17*3=51-2=49

17*4=68................this is the required no.
17*4=68-3=65

Like? Yes (2) | No (1)  

ADVAITA BASAK   10 years AGO

68

Like? Yes (1) | No   

arun prakash singh   10 years AGO

17*4=68 is

Like? Yes (1) | No   

ASHISH MITTAL   10 years AGO

1 17*1
17 17*2
33 17*3
49 17*4
so answer will be 68 option no (3)

Like? Yes (1) | No   

J.DHANDAPANI   10 years AGO

2nd,4th,6th,8th...terms are multiples of 17.so,ans:17x4=68

Like? Yes (1) | No   

B karthik   10 years AGO

1 to 17 =increment is 16
17 to 17=decrement is 0
17 to 34=increment is 17
34 to 33=decrement is 1
33 to 51=increment is 18
15 to 49=decrement is 2
49 to 68=increment is 19..
like this series will continue...
1,17,17,34,33,51,49,68,65....
Ans=68

Like? Yes (1) | No   

Rahul Kesharwani   10 years AGO

Even places are multiple of 17, so next digit would be 68 only

Like? Yes (1) | No   

Keshav Kishlay   10 years AGO

17*1=17,17*2=34,17*3=51,17*4=68

Like? Yes (1) | No   

AMIT KUMAR   10 years AGO

1 17 17 34 33 51 49 .. ..
here there are two series
1st is......1 17 33 49 here each term added 16..so next will be 65 which is not require
............................................
2nd is......17 34 51 which is find to add 17 in each term......next will be 68
explain.......
17 17+17 =34 34+17 = 51 51+17 = 68ans>>>>>68

Like? Yes (1) | No   

muni   10 years AGO

the sequence is
1,17,17,34,33,51,49
it is fallowing like
16,0,17,1,18,2,19

Like? Yes (1) | No   

Leelanand Kumar Yalla   10 years AGO

Here Alternate digits are added with 16 and 17...
1+16= 17;
17+17=34;
17+16=33;
34+17=51;
33+16=49;
51+17=68; this is the answer.......

Like? Yes (2) | No (1)  

Dinesh thatti   10 years AGO

take alternative series
we get 1,17,33,49
17,34,51, ?
from 1st series 17*1-0=17
17*2-1=33
17*3-2=49

from 2nd series 17*2=34
17*3=51
17*4=68

so answer is 68 which is 3rd option

Like? Yes (1) | No   

Pallekonda Rajesh   10 years AGO

1,17,17,34,33,51,49,.....
1 +16=17 then 17-0=17
17+17=34 then 34-1=33
33+18=51 then 51-2=49
similarly
49+19=68 so ans:68

Like? Yes (1) | No   

TRIMURTULU   10 years AGO

differenc
1,17=16
17,17=0
17,34=17
34,33=1
33,51=18
51,49=2
x-49=19
x=68

Like? Yes (1) | No   

SHEREENA NISHAD   10 years AGO

1,17,17,34,33,51,49....
17-0=17
34-1=33
51-2=49
second, fourth , sixth etc terms are
17,34,51,....
34=17+17
51=34+17
So next term is
51+17=68

Like? Yes (1) | No   

Dishant   10 years AGO

1ST SEQUENCE TABLE OF 17...17,34,51,68
2ND SEQUENCE 1,1+16,1+16+16,1+16+16+16

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

1+16=17..
17-0=17..
17+17=34..
34-1=33..
33+18=51..
51-2=49..
49+19=68..
SO OPTION (3)..

Like? Yes (1) | No   

Vikram Saini   10 years AGO

1 17 17 34 33 51 49 68
16 0 17 1 18 2 19
so ans is 68

Like? Yes (1) | No   

Hemalatha   10 years AGO

17*4=68

Like? Yes (1) | No   

mafidul   10 years AGO

17*1-0, 17 17
17*2-1, 34 33
17*3-2, 51 49
17*4-3, 68

Like? Yes (1) | No   

Manikumar R   10 years AGO

series is like this
1
17*1=17,17-0=17
17*2=34,34-1=33
17*3=51,51-2=49
17*4=68

Like? Yes (1) | No   

gomathi baskar   10 years AGO

17*1=17
17*2=34
17*3=51
17*4=68

Like? Yes (1) | No   

tejaswini g   10 years AGO

1,17,17,34,33,51,49,...

alternate series:1,17,33,49...
17,34,51,....

1,17,33,49..
1x16=16+1=17
2x16=32+1=33
3x16=48+1=49
4x16=64+1=65..........

17,34,51...
17x2=34
17x3=51
17x4=68

so answer is 68

Like? Yes (1) | No   

KEERTHIPALLE SUDHEERKUMAR   10 years AGO

1*17=17,17-0=17
2*17=34,34-1=33
3*17=51,51-2=49
4*17=68,68-3=65

Like? Yes (1) | No   

PRAGATHI G   10 years AGO

Odd places numbers have 16 as difference.. And even place numbers have 17 as difference
1+16= 17
17+16=33
33+16=49
Similarly in even place,
17+17=34
34+17=51
51+17=68

Like? Yes (1) | No   

Rajat Goyal   10 years AGO

Add 17

Like? Yes (1) | No   

MAHESH CV   10 years AGO

alternate number is added by 17 and another is added 17,16

Like? Yes (1) | No   

Sudipta Mukherjee   10 years AGO

17,34,51,68

Like? Yes (1) | No   

meghana   10 years AGO

Given series is 1,17,17,34,33,51,49,__
This series contain two series.
1: 1,17,33,49
2: 17,34,51,__
the next number we want to find will follow second series.
2: 17*1=17
17*2=34
17*3=51
17*4=68
so,the answer is 68.

Like? Yes (1) | No   

salma   10 years AGO

to solve this series we need to divide series into 2 parts like below
1,17,33,49,....=difference is 16 so next number in the series is 65
1,17,34,51,......=here series is increasing by multiple of 17 so next num is 68

Like? Yes (1) | No   

hanamant k   10 years AGO

there are two siries
17,34,51,...
1,17,33,49,...

in first siries 17*1=17
17*2=34
17*3=51
17*4=68...

Like? Yes (1) | No   

kedasu suresh   10 years AGO

from sequence

Like? Yes (1) | No   

nazar   10 years AGO

1
17
17-0=17
17+17=34
34-1=33
34+17=51
51-2=49
51+17=68
so ans is 3)68

Like? Yes (1) | No   

Gourab Dutta   10 years AGO

1,17,33,49...17-1=33-17=49-33=16
17,34,51,68..17+17=34..34+17=51..51+17=68..

Like? Yes (1) | No   

tanya bhatia   10 years AGO

ans is 68 bcz The odd terms go up by 16:
1 .. 17 .. 33 .. 49

The even terms go up by 17:
.. 17 .. 34 .. 51

Like? Yes (1) | No   

khazi mohammad azharuddin   10 years AGO

two series give
first series:1,17,33,49
second series:17,34,51
first series add 16 to previous number.
second series multiples of 17..
so answer is 17*4=68

Like? Yes (1) | No   

vipin kumar   10 years AGO

1+16=17
17-17=0
17+17=34
34-1=33
33+18=51
51-2=49
49+19=68

Like? Yes (1) | No   

AVIJIT   10 years AGO

here two seres 1,17,33,49--> difference 16
and another is 17,34,51,68 ---> difference is 17
so ans is 68.

Like? Yes (1) | No   

K.Bhagyasri   10 years AGO

17*4=68

Like? Yes (1) | No   

Satish Zod   10 years AGO

49 + 19 = 68
i.e. Answer (3)

Like? Yes (1) | No   

rana chowdhury   10 years AGO

1*17=17
17-0=17
2*17=34
34-1=33
3*17=51
51-2=49
4*17=68

Like? Yes (1) | No   

Sohar Lal Singh   10 years AGO

1...17...17..34..33...51..49..
16 0 17 1 18 2 hence there will be
49+19=68

Like? Yes (1) | No   

usharani   10 years AGO

differencce is 17

Like? Yes (1) | No   

Komala.G   10 years AGO

Option (3)
this is a jumble sequence
1 1st no in sequence
add 16
1+16 = 17 3rd
17+16 = 33 5th
33+16 = 49 7th
add 17
17 2nd
17+17 = 34 4th
34+17 = 51 6th
51+17 = 68 8th

Like? Yes (1) | No   

swarnalatha   10 years AGO

1 17 33 49 as one series
17 34 51 as other series are multiples of 17
so next term is 17*4=68

Like? Yes (1) | No   

VIMALRAJ V   10 years AGO

difference between 34 & 17 is 17.Then 17 is added to 51 it gives 68.
17+17=34.
34+17=51.
51+17=68.
Answer is 68.

Like? Yes (1) | No   

SIBNATH HALDER   10 years AGO

1,17,17,34,33,51,49,..
you divided the series into 2 section
1st one odd place value
1,17,33,49,..
that addition of 16 the series go on
2nd one for even place value
17,34,51,..
that's multiplication of 17
so next value is
17*4=68;
the series may be
1,17,17,34,33,51,49,68,65,85...
the ans is option 3=>68

Like? Yes (1) | No   

R.RAVIKUMAR   10 years AGO

1,17,17,34,33,51,49,?
let's consider given series as combination of two series alternatively...

1st series: 1,17,33,49.. here increment is 16..
2nd series: 17,34,51,? here increment is 17.. so, next number in the series is 51+17 = 68..

Like? Yes (2) | No (1)  

Gotlooru Venkata Kartheek Kumar   10 years AGO

Dividing in to two halves as odd and even numbers
and then

Adding 16 to the 1st number and adding 17 to the 2nd number


1+16=17
17+17=34
17+16=33
34+17=51
33+16=49
51+17=68

Like? Yes (1) | No   

chinni gayatri   10 years AGO

51+17=68

Like? Yes (1) | No   

gyan ranjan panigrahi   10 years AGO

every even place is sum of 17

Like? Yes (1) | No   

Rahul Verma   10 years AGO

Difference Between Alternative Sequence is 16 and 17

ex
49-33=16
33-17=16
17-1=16

same as

68-51=17
51-34=17
34-17=17

Like? Yes (1) | No   

saisudha sarva   10 years AGO

divide ito 2 series :

so.. 2nd series 17+17=34
34+17=51
51+17=68

Like? Yes (1) | No   

Sandeep Jadala   10 years AGO

17*1=17
17*2=34
17*2=34-1=33
17*3=51
17*3=51-2=49
17*4=68

Like? Yes (1) | No   

jhinuk sikder   10 years AGO

There is a sequence of 1+16=17, 17-0=17,17+16+1=34,34-1=33,33+18=51,51-2=49,49+19=68
so 68 is the answer

Like? Yes (1) | No   

geet kalani   10 years AGO

double series is going on table of 17.

Like? Yes (1) | No   

Vivek Jain   10 years AGO

Two series 1,17,33,49 with common difference 16 and
17,34,51,? with common difference of 17 so next number will be 51+17=68
Hence option 3) 68 is the answer

Like? Yes (1) | No   

Rajasekhar Reddy   10 years AGO

1,17,33,49 means adding 16 to previous number
17,34,51,68 multiples of 17
so ans is 68

Like? Yes (2) | No (1)  

Gopal Tamrkar   10 years AGO

here two series like this

1, 17,17, 34,33, 51,49.....

in first
1, 17, 34, 51, so that next is 68

and also
n second series dependent on first like

1, 17=17-0, 34=34-1, 51=51-2 so here next is

68=68-3 like that

Like? Yes (1) | No   

Khushboo Kumari   10 years AGO

there r 2 series.....
1).1,17,33,49...
2).17,34,51,...
In first series there is a difference of 16
and in the 2nd one there is a difference of 17...

Like? Yes (1) | No   

eswariteja   10 years AGO

1,17,17,34,33,51,49 diff is:
17-1=16
17-17=0
34-17=17
34-33=1
51-33=18
51-49=2
68-49=19

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

Alternate series
1,17,33,49,65,.. &
17,34,51,68,..

Like? Yes (1) | No (1)  

anubhav verma   10 years AGO

A PAIR OF TWO
1+16=17
17+17=34
33+18=51
49+19=68
HENCE ANSWER=68

Like? Yes (1) | No (1)  

21 Mar 2014 Coded language

If in coded language
MOHAN = 29
SURESH = 64
MANAN = 15
Then
MANOJ = ?

OPtion

1) 18
2) 21
3) 26
4) 29
5) 38
6) 46
7) 52
8) 63
9) 72
10)None of these

Solution

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
MOHAN = 13 15 8 1 14 = (13+15+1) = 29 (Sum of odd no)
SURESH = 19 21 18 5 19 8 = (19+21+5+19) = 64
MANAN = 13 1 14 1 14 = (13+1+1) = 15
Similarly
MANOJ = 13 1 14 15 10 = (13+1+15) = 29

Option 4)

Correct Option: 4 Best Solution (50)

Krsihna Prasad   10 years AGO

add the odd
M=13
A=1
N=14
O=15
J=10
by adding odd numbers we get,
13+1+15=29

Like? Yes (25) | No (15)  

ROHIT KUMAR YADAV   10 years AGO

add place value of each position position 1+2+4

eg:- for MOHAN=13+15+1=29
same for MANOJ=13+1+15=29

Like? Yes (1) | No   

Venkat   10 years AGO

mohan=m+o+a=29(odd alphabet sum)
manoj=m+a+o=29

Like? Yes (1) | No   

satyanarayana   10 years AGO

m+a+0=29

Like? Yes (1) | No   

Rajapraveen.P   10 years AGO

Mohan=13+15+8+1+14(this is by a=1,b=2,c=3,d=4....)
by adding odd numbers we get 29
similarly
for manoj m=13 a=1 n=14 0=15 j=10
ans is 29

Like? Yes (1) | No   

ekta rani   10 years AGO

MOHAN=13,15,8,1,14
SUM OF 1,2&5 TERMS ARE 13+15+1=29
MANAN=13,1,14,1,14
SUM OF 1,2&5 TERMS ARE 13+1+1=15
MANOJ=13,1,14,15,10
SUM OF 1,2&5 TERMS ARE 13+1+15=29

Like? Yes (1) | No   

aparna lakshmi    10 years AGO

mohan-29 m-13,o-15,h-8,a-1,-14 where 13+15+1=29.
suresh-64 s-19,u-21,r-18,e-5,s-19,h-8 19+21+5+19=64
manan-15 m-13,a-1,n-14,a-1,n-14 13+1+1=15
manoj m-13,a-1,n-14,o-15,j-10 13+1+15=29
letter are assigned values according to their alphabetical order

Like? Yes (1) | No   

NATHIYA   10 years AGO

mohan=13+15+8+1+14(add all odd numbers)=29
similarly manoj=13+1+14+15+10
add odd numbers
manoj=13+1+15=29.

Like? Yes (1) | No   

nabarun guha   10 years AGO

find it out

Like? Yes (1) | No   

Hari Sankhar   10 years AGO

add 1st 2 no and add the 4th of each name

Like? Yes (1) | No (1)  

mohd zakir   10 years AGO

write abcd... as 1234...
add odd values of name

Like? Yes (1) | No (1)  

AMIT KUMAR   10 years AGO

ADD ONLY THESE ALPHABET WHOSE NUMERICAL VALUE FROM A(1)....TO Z(26) IS ODD NUMBER.
M=13,O=15,H=8,A=1,N=14 ==13+15+1=29
S=19,U=21,R=18,E=5,S=19,H=8 ==19+21+5+19=64
M=13,A=1,N=14,A=1,N=14==13+1+1=15
M=13,A=1,N=14,O=15,J=10==13+1+15=29
ANS>>>>>>>4) 29

Like? Yes (1) | No (1)  

sruthi   10 years AGO

take mohan ....m=13,o=15,h=8,a=1,n=14 so ...adding odd values 13+15+1=29
hence
manoj considering its postion value m=13 a=1 n=14 o=15 j=10 ...add the odd values ie 13+1+15=29 so ans is 29

Like? Yes (1) | No (1)  

Ghanshyam Gulati   10 years AGO

A(1),B(2),C(3),D(4),E(5),F(6),G(7),H(8),I(9),J(10),k(11),L(12),M(13),N(14),0(15),P(16),Q(17),R(18), S(19),T(20),U(21),V(22),W(23),X(24),Y(25),Z(26).

NOW
M O H A N = 29
13 15 8 1 14 =13+15+1(SUM OF ODD NUMBERS)

AND

S U R E S H =64
19 21 18 5 19 8 =19+21+5+19(SUM OF ODD NUMBERS)

AND

M A N A N = 15
13 1 14 1 14 = 13+1+1

HENCE
M A N O J
13 1 14 15 10=13+1+15=29

THUS ANS IS 29

Like? Yes (1) | No (1)  

mohini gupta   10 years AGO

sum of odd numbers
mohan, m=13, o=15, a=1, total=29
suresh, s=19, u=21, e=5, s=19, total=64
manoj, m=13, a=1, o=15, total=29

Like? Yes (1) | No (1)  

Varunraj Reddy   10 years AGO

Given that MOHAN=29
We know that M=13 0=15 H=8 A=1 N=14
Consider only odd number alphabets sum
i.e.,M+O+A=13+15+1=29

Now SURESH=S+U+E+S=19+21+5+19=64

MANAN=M+A+A=13+1+1=15

Similarly,
MANOJ=M+A+O=13+1+15=29
Answer is option 4)

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

sum of odds

Like? Yes (1) | No (1)  

Dr.Dipin Singh   10 years AGO

sum of place value of letters having odd place value.
like A=1,
C=3
E=5

MOHAN .... 13 15 08 01 14.... 13+15+1=29
Similarly
SURESH = 64
MANAN = 15
Hence MANOJ... 13 01 14 15 10... 13+1+15=29

Like? Yes (9) | No (15)  

azharshahid01@gmail.com   10 years AGO

In code Language,
A=1,
B=2,
C=3,
...
...
z=26
In each word add only odd numbers.
MOHAN 13,15,8,1,14 => 13+15+1=29
SURESH 19,21,18,5,19,8 => 19+21+5+19=64
MANAN 13,1,14,1,14 => 13+1+1 = 15
In the same way,
MANOJ 13,1,14,15,10 => 13+1+15 = 29
Thus answer is option 4)29

Like? Yes (4) | No (11)  

Akanksha Mishra   10 years AGO

Given

MOHAN = 29
SURESH = 64
MANAN = 15
Then
MANOJ = ?

A(1),B(2)..............................Y(25),Z(26)

MOHAN = M(13), O(15),H(8), A(1) ,N(14)

ADD odd place alphabets
M(13) + O(15) + A(1) = 29

Similarly
MANOJ = M(13),A(1),N(14),O(15),J(10)
ADD odd place alphabets
M(13) + A(1) + O(15) = 29

So answer will be 29(option 4)

Like? Yes (5) | No (14)  

MD SOHAIL AKHTER   10 years AGO

A=1, B=2,.........Z=26
NOW ADD THE ODD NO. CORRESPONDING TO THE DIGIT
MOHAN=13+15+1=29
MANOJ=13+1+15=29

Correct option.is 4

Like? Yes (2) | No (11)  

Pulkit Dureja   10 years AGO

Add all the odd terms i.e. M+A+O=13+1+15

Like? Yes (1) | No (10)  

Ann Theressa   10 years AGO

put
M=13, O=15, H=08, A=01, N=14

S=19, U=21, R=18, E=05, S=19, H=08

M=13, A=01, N=14, A=01, N=14

M=13, A=01, N=14, O=15, J=10

adding all alphabets except 3rd and last one we get
MOHAN = M+O+A = 13+15+01 = 29
SURESH = S+U+E+S = 19+21+05+19 = 64
MANAN = M+A+A = 13+01+01 = 15
and
MANOJ = M+A+O = 13+01+15 = 29

Like? Yes (1) | No (10)  

Saraswathy   10 years AGO

for odd no. of alphabets, do total-(3rd alphabet - 5th alphabet)

mohan -----> 13+15+8+1+14 =51
51 - (8+14) = 29
manan -----> 13+1+14+1+14 = 43
43 - (14+14) = 15

for even no. of alphabets, do total-(2nd alphabet - 4th alphabet)

suresh ----> 19+21+18+5+19+8=90
90 - (21+5) = 64

so "manoj" contains odd no. of alphabets
manoj ----> 13+1+14+15+10 = 53
53 - (14+10) = 29

Ans : option (4)

Like? Yes (2) | No (11)  

VEERENDRA KUMAR K G   10 years AGO

MOHAN= M+O+A=29
SURESH=S+U+E+S=64
MANAN=M+A+A=15

MANOJ=M+A+O=29

Like? Yes (1) | No (10)  

J.DHANDAPANI   10 years AGO

odd numbers are added.so,ans=29

Like? Yes (1) | No (11)  

Pallekonda Rajesh   10 years AGO

given number is the sum of the odd numbers of all
alphabets
mohan=13,15,8,1,14=13+15+1=29
suresh=19,21,18,5,19,8=19+21+5+19=64
similarly manoj=13,1,14,15,20=13+1+15=29 so
ans:29

Like? Yes (1) | No (11)  

SHEREENA NISHAD   10 years AGO

M=13
A=1
N=14
O=15
J=10
SUM OF ODD NUMBERS= 13+15+1 =29

Like? Yes (1) | No (11)  

R.RAVIKUMAR   10 years AGO

A-1,B-2,....Z-26.

The coding follow that first two letters and the letters between third letter and last letter...

MOHAN = M+O+A = 13+15+1 = 29
SURESH = S+U+E+S = 19+21+5+19 = 64
MANAN = M+A+A = 13+1+1 = 15

similarly,
MANOJ = M+A+O = 13+1+15 = 29

Like? Yes (2) | No (12)  

ashish kumar   10 years AGO

its sum of value of alphabets on odd position.
m=13,a=1,n=14,0=15,j=10
add 13+1+15=29

Like? Yes (2) | No (12)  

B karthik   10 years AGO

Conditions For Summation:
For Odd numbers..
we have remove 3,5 charecters...
For Even Numbers..
2,4 charecters...
MOHAN count is odd no. so M+O+A=13+15+1=29(3,5 not adding to summation)
SURESH Count is even no. so S+R+S+H=19+18+19+8=64(2,4 not adding to summation)
MANAN count is odd no. so M+A+A=13+1+1=15(3,5 not adding to summation)
MANOJ count is odd no. so M+A+O=13+1+15=29(3,5 not adding to summation)..
MANOJ=29..(Ans.)

Like? Yes (3) | No (13)  

TRIMURTULU   10 years AGO

sum of the odd numerals of the corresponding alphabets.

Like? Yes (1) | No (11)  

Rohit Agarwal   10 years AGO

here if number of letters in the word is odd then add 1st,2nd and 4th letter.

if number of letters in the word is even then add 1st,2nd,4th,5th letter.

so MOHAN(odd)==13+15+1=29
SURESH(even)=19+21+5+19=64
MANAN(odd)=13+1+1=15
MANOJ(odd)=13+1+15=29

Like? Yes (1) | No (11)  

saikiran   10 years AGO

for even number letter words we remove 2 and 4 letters
in suresh
s+r+s+h=19+18+19+8=64
for odd number letter words we remove 3 and 5 letters
in manan
m+a+a=13+1+1=15
like in manoj
m+a+o=13+1+15=29

Like? Yes (3) | No (13)  

ASHISH MITTAL   10 years AGO

if a=1,b=2,c=3 and so on..
in all words add only odd no to get answer so for manoj,answer will be 13+1+15=29
option no(4)

Like? Yes (1) | No (11)  

Surya Narayana K   10 years AGO

Answer : 29 (Option 4).

Coding : Sum of letters with odd value when they are arranged in alphabetical order.

MOHAN=13+15+8+1+14= 29 (13+15+1)
SURESH=19+21+18+5+19+8=64 (19+21+5+19)
MANAN=13+1+14+1+14=15 (13+1+1)

Similarly
MANOJ=13+1+14+15+10=29 (13+1+15)

So answer is 29.

Like? Yes (1) | No (11)  

NavyaBharathi   10 years AGO

First we can add corresponding 2 numbers of alphabets leave one letter then add one number corresponding to alphabet

Like? Yes (1) | No (11)  

Rajasekhar Reddy   10 years AGO

adding of odd numbers of alphabets
MANOJ = 13 1 14 15 10
by adding odd numbers
13+1+15 = 29

Like? Yes (1) | No (11)  

Satish Zod   10 years AGO

If A=1, B=2,..................Y=25, Z=26.
Add only odd numbers of alphabets used in name.
M=13, A=1, N=14, O=15, J=10.
Add 13+1+15 (Only odd numbers) = 29
i.e. sr. no. 4.

Like? Yes (1) | No (11)  

rajesh   10 years AGO

mohan=m+o+a=29(odd number alphabet)
manoj=m+a+o=29

Like? Yes (1) | No (11)  

Soumya   10 years AGO

MOHAN=13+15+8+1+14 IN THAT ADD ONLY ADD NUMBERS THEN ANS IS 29
LIKEWISE
SURESH=19+21+18+5+19+8=64
MANAN=13+1+14+1+14=15
THEN
MANOJ=13+1+14+15+10=29 SO ANS IS 29.

Like? Yes (3) | No (13)  

ch rajesh   10 years AGO

mohan=m+o+a=29(odd alphabet sum)
manoj=m+a+o=29

Like? Yes (1) | No (11)  

Soham Dalwadi   10 years AGO

ACCORDING TO A-1 TO Z-26
SUM OF ODD EQUIVALENT NUMBER TO ALPHABET

M A N O J=?
13 1 14 15 10

ODD SUM = 13 + 1 + 15 = 29
ANSWER 29

Like? Yes (1) | No (11)  

champavat jaydipsinh padamsinh   10 years AGO

ACCORDING TO A-1 TO Z-26
SUM OF ODD EQUIVALENT NUMBER TO ALPHABET

M A N O J=?
13 1 14 15 10

ODD SUM = 13 + 1 + 15 = 29
ANSWER 29

Like? Yes (1) | No (11)  

AKANKSHA NAYAK   10 years AGO

in five digit number
total is sybtracted by 3rd and 5th place
like
total is-53
sum of 3rd and 5th place is-24
subtract:-(53-24=29)

Like? Yes (3) | No (13)  

Bupathikavya   10 years AGO

sum of odd alphabet in the given question.
manoj==>m(13)+a(1)+o(15)=29

Like? Yes (1) | No (11)  

deepak kumar   10 years AGO

sum of odd numbers.

Like? Yes (1) | No (11)  

m b naga lakshmi   10 years AGO

sum of odd numbering of the alphabatics

Like? Yes (2) | No (12)  

SIBNATH HALDER   10 years AGO

ANS OPTIONS IS 4
MOHAN=13+15+8+1+14=51
TOTAL SUM-(3RD PLACE+5TH PLACE VALUE)
=51-(8+14)=29
SO, MOHAN=29
SURESH=19+21+18+5+19+8=90
TOTAL SUM-(3RD PLACE+5TH PLACE VALUE)
=90-(18+8)=64
SO, SURESH=64
MAHAN=13+1+8+1+14=37
TOTAL SUM=(3RD PLACE+5TH PLACE VALUE)=
37-(8+14)=15
SO,MAHAN=15
MANOJ=13+1+14+15+10=53
TOTAL SUM-(3RD PLACE+5TH PLACE VALUE)
=53-(14+10)=29
SO,MANOJ=29

Like? Yes (1) | No (11)  

roshani munde   10 years AGO

count odd no variables only

Like? Yes (1) | No (11)  

20 Mar 2014 Ratio

60 % of a number is equal to 80 % of another. Ratio of the numbers is

OPtion

1) 1/5
2) 2/3
3) 1/2
4) 4/3
5) 5/6
6) 5/2
7) 1/3
8) 1/4
9) 3/5
10)None of these

Solution

60a/100 = 80b/100
6a = 8b
a/b = 8/6 = 4/3

option 4)

Correct Option: 4 Best Solution (113)

Krsihna Prasad   10 years AGO

let the two numbers be x and y
given
60% of x = 80 of y ie;
60/100*x = 80/100*y
x/y=80/60
x/y=4/3
hence ratio is 4:3 which equals 4/3

Like? Yes (12) | No (9)  

G.Madhumitha   10 years AGO

60/100 of x = 80/100 of y

x/y = 80/60 = 4/3

Like? Yes (2) | No   

Venkat   10 years AGO

number1=x
number2=y
60% of number1=0.6x
80% of number2=0.8y
then,
x/y=4/3

Like? Yes (1) | No   

PRAGATHI G   10 years AGO

Let numbers be x and y..
Given tat 0.6x=0.8y
So x/y= 4/3

Like? Yes (1) | No   

vishnuvardhan   10 years AGO

60x/100=80y/100
x/y=4/3

Like? Yes (1) | No   

suryam surada   10 years AGO

WE HAVE TO FOLLOW RULE "BODMAS"(BRACKET, OF, DIVISION,MULTIPLICATION, ADDITION, SUBTRACTION)

Like? Yes (1) | No   

Rituparna Chakraborty   10 years AGO

Let two number=x,y
so, 60% of x=80% of y
=>(6o/100)*x=(80/100)*y
=>x/y=80/60=4/3

Like? Yes (1) | No   

shailja soni   10 years AGO

Let the numbers be x1 and x2 respectively.
now 60% of x1= (60/x1)*100
and 80% of x2= (80/x2)*100
(60/x1)*100=(80/x2)*100
x2/x1=8/6
x2/x1=4/3

Like? Yes (1) | No   

Souvik Mitra   10 years AGO

Suppose two number is x and y
60% of x=.6x
80% of y=.8y
.6x=.8y
so x/y=8/6=4/3

Like? Yes (1) | No   

ekta rani   10 years AGO

let first no.=x,second no= y
60% * x=80% *y
60/100 x=80/100 y
x/y=80/60
x/y=4/3

Like? Yes (1) | No   

sethupathi.p   10 years AGO

the reason is ratio

Like? Yes (1) | No   

Juie Talavia   10 years AGO

Let the first number be x and the second number be y.
Now, (60*x)/100=(80*y)/100
=>(3*x)=(4*y)
=>(x/y)=4/3

Like? Yes (1) | No   

shivangi agarwal   10 years AGO

60%x=80%y
x/y=80%/60%
i.e,x/y=8/6
i.eratio is 4/3

Like? Yes (1) | No   

purnya   10 years AGO

0.6x=0.8y
y/x=8/6=4/3

Like? Yes (1) | No   

NATHIYA   10 years AGO

(80/100)=(60/100)
cancellation we get ans is 4:3

Like? Yes (1) | No   

ChinnaChowdaiah   10 years AGO

x is one number
y is another number
(60*x)/100 = (80*y)/100
x/y=4/3

Like? Yes (1) | No   

TRIMURTULU   10 years AGO

(60/100)(x)=(80/100)y
x/y=4/3

Like? Yes (1) | No   

Anjali   10 years AGO

60% of x= 80% of y
60x=80y
x/y=80/60=4/3

Like? Yes (1) | No   

Ghanshyam Gulati   10 years AGO

let the numbers are x and y
60% of x is 0.6x
80% of y is 0.8y
given that
0.6x=0.8y
so x/y=0.8/0.6=4/3

Like? Yes (1) | No   

Siddharth Singh   10 years AGO

le t the numbers be x and y

no
60% of x= 80% of y

=> x*(60/100)= y*(80/100)
=> x/y= 4/3

hence option 4) 4/3 is the answer

Like? Yes (1) | No   

MANISH SHARMA   10 years AGO

let no. be X and other no. be Y
60/100 of X=80/100 of Y
3/5*X=4/5*y
so, X/Y=4/3

Like? Yes (1) | No   

shamma mohammad   10 years AGO

60/100*x=80/100*y

X/Y=4/3

Like? Yes (1) | No   

basha shaik   10 years AGO

60/100*x=80/100*y

X/Y=4/3

Like? Yes (1) | No   

Sriparna Boote   10 years AGO

Let the numbers be x and y.
so
60/100*x=80/100*y
or x/y=8/6
or x/y=4/3
or x:y=4:3

Like? Yes (1) | No   

Arka Paul   10 years AGO

60 % * x=80 % * y
x/y =4/3

Like? Yes (1) | No   

Mohit Singh   10 years AGO

8/6 is 4/3

Like? Yes (1) | No   

ipsita dash   10 years AGO

let 60% of 100 = 60
80% of 75 is 60
100/75=4/3

Like? Yes (1) | No   

Rinkal   10 years AGO

let the nos. are x and y.
Then acc. to question 60x/100=80y/100
On solving we get x:y=4:3

Like? Yes (1) | No   

Dibyajyoti Biswas   10 years AGO

let the numbers are 100x,100y.
60% of 100x is 60x. and 80 of 100y is 80y.so 60x=80y
then x/y=4/3.
so 100x:100y=4:3

Like? Yes (1) | No   

Dwarsala lakshmi nikitha   10 years AGO

6=8
4/3

Like? Yes (1) | No   

prasanna vadlamudi   10 years AGO

suppose the first no is 100.then 60% of 100 is 60.
from the problem
60=(80/100)x
x=6000/80=75
sp ratio=100/75=4/3

Like? Yes (1) | No   

ram   10 years AGO

0.6a=0.8b a/b=4/3

Like? Yes (1) | No   

maria   10 years AGO

60% x=80% y
x/y=4/3

Like? Yes (1) | No   

Inderjeet Singh   10 years AGO

x/y = x/(6/8)x=1/(3/4)=4/3

Like? Yes (1) | No   

AVIJIT   10 years AGO

let two numbers are a and b
so as per qtn (a*60)/100=(b*80)/100
i.e a/b=4/3

Like? Yes (1) | No   

Bojedla Durgabhavani   10 years AGO

60%x=80%y
x/y=80%/60%
x/y=4/3

Like? Yes (1) | No   

azharshahid01@gmail.com   10 years AGO

Let one number is x and another is y.
According to question, (60/100)*x= (80/100)*y
On solving, x/y= 4/3.
Thus, answer is 4) 4/3.

Like? Yes (3) | No (6)  

Snehasis   10 years AGO

60% of a number is equal to 80% of a number means its 4:3 or 4/3
60/100 * x = 80/100 * y
=> x/y = 4/3
I.e x:y = 4:3

Like? Yes (4) | No (7)  

virendra dubey   10 years AGO

let 1st no=x;
and 2nd no.=y;
now, as mention 60% of x=80% of y;
60% of x==>(60*x)/100==>(3/5)x;
80% of y==>(80*y)/100==>(4/5)y;
hence (3/5)x=(4/5)y;
so (x/y)=(4/5)*(5/3)=4/3;
hence answer = 4/3..option 4

Like? Yes (1) | No (4)  

VIKASH RAY   10 years AGO

Let two numbers A & B
According to the given question,
60% of A=80% OF B
or, 60A= 80B
or, A:B=80/60
or, A:B=4/3
so, option 4 is correct.

Like? Yes (1) | No (4)  

Sudipta Mukherjee   10 years AGO

60/100x=80/100y,x/y=4/3

Like? Yes (1) | No (4)  

Rohit Agarwal   10 years AGO

suppose first number is a and another number is b

so a* 60% = b*80%

so ratio a/b=80/60 =4/3

Like? Yes (1) | No (4)  

saurabh agarwal   10 years AGO

let number is x and y then
x*60%=y*80% solve it we get x/y=4/3.

Like? Yes (1) | No (4)  

Vikram Saini   10 years AGO

60/100*a=80/100*b
a/b=4/3

Like? Yes (1) | No (4)  

Pritesh Saurav   10 years AGO

60x=80y
=> x/y=4/3

Like? Yes (1) | No (4)  

sravya   10 years AGO

let the two numbers be x and y
60%x=80%y
solving this we get
x/y=4/3

Like? Yes (1) | No (4)  

Dinesh thatti   10 years AGO

let the numbers be N1,N2.
60 % of a number is equal to 80 % of another
60/100 N1=80/100 N2.
3N1=4N2.
N1/N2=4/3

so answer is 4/3 4th option

Like? Yes (1) | No (4)  

Gudivada sunitha   10 years AGO

60% of x = 80% OF Y
(60/100)*X = (80/100)*Y
3X= 4Y
X/Y=4/3

Like? Yes (1) | No (4)  

ARJYA HALDER   10 years AGO

Let, the two nos. be a & b.
From question, 60% of a=80% of b
i.e, (60a/100) = (80b/100)
i,e, (a/b)= (4/3)

So, option 4 is the correct option.

Like? Yes (1) | No (4)  

Satish Zod   10 years AGO

If x & y are the numbers,
60x/100 = 80y/100
6x/8y = 1
x/y = 8/6 = 4/3

i.e. Sr. No. 4

Like? Yes (1) | No (4)  

naveen reddy   10 years AGO

0.6x=0.8y
x/y=0.8/0.6
x/y==4/3

Like? Yes (1) | No (4)  

eswariteja   10 years AGO

60a=80b;
a/b=80/60
a/b=4/3

Like? Yes (1) | No (4)  

mohini gupta   10 years AGO

60*x/100=80*y/100;
x:y=4:3

Like? Yes (1) | No (4)  

Saraswathy   10 years AGO

X , Y be the two numbers

60x=80y
x=4/3y

4/3Y : Y

4/3/1== 4/3

Like? Yes (2) | No (5)  

muni   10 years AGO

6o% of number=60/100*x
80% of another number=80/100*Y
so
60/100x=80/100Y
x/y=4/3

Like? Yes (1) | No (4)  

Pulkit Dureja   10 years AGO

.6x=.8y

Like? Yes (1) | No (4)  

Hemalatha   10 years AGO

60*x=80*y
3x=4y
x/y=4/3

Like? Yes (2) | No (5)  

Mohit Kumar Soni   10 years AGO

let two numbers are= a and b.
ATQ :- 60 % of a= 80% of b
=> 60/100*a = 80/100*b
=> 3a = 4b
=> a/b = 4/3

Hence, Ratio = 4/3

Like? Yes (1) | No (4)  

RAHUL JINDAL   10 years AGO

60% of x = 80% of y
so x/y = 80/60 = 4/3

Like? Yes (1) | No (4)  

Amit Kumar Panda   10 years AGO

x*60%=y*80%
=>x/y=80%/60%
=>x/y=4/3

Like? Yes (1) | No (4)  

Soham Dalwadi   10 years AGO

suppose
x 60/100 = y 80/100
x/y = 8/6 = 4/3 answer

Like? Yes (3) | No (6)  

R.RAVIKUMAR   10 years AGO

let the two numbers be x and y..
so, 60% of x = 80% of y
by solving we get x/y = 4/3

Like? Yes (1) | No (4)  

Manikumar R   10 years AGO

two numbers x,y
60*x/100=80*y/100
x/y=4/3

Like? Yes (1) | No (4)  

hanamant k   10 years AGO

lets numbers be x and y
so,
60/100x=80/100y ||given

=>x/y=4/3

Like? Yes (1) | No (4)  

nuthalapati.vijaya lakshmi   10 years AGO

if we assume two numbers as x and y then 60% of x is equal to 80% of y so...
0.6x=0.8y
==>x/y=(0.8/0.6)=(4/3)
so in my view option 4 is right answer for this question

Like? Yes (1) | No (4)  

Keshav Kishlay   10 years AGO

0.6*x=0.8*y;
x:y=4:3=4/3

Like? Yes (1) | No (4)  

K DHARANI VENKATESH   10 years AGO

0.6x=0.8y
x/y=0.8/0.6
x/y=8/6
x/y=4/3

Like? Yes (1) | No (4)  

Sourav Mohanty   10 years AGO

let the two no.s be a & b

So, 60% of a = 80% of b
=> 60/100 * a = 80/100 * b
=> a/b =80/60
=4/3

Like? Yes (1) | No (4)  

kedasu suresh   10 years AGO

by dividing 80 by 60 we get 1.33 from option 4 we get 1.33

Like? Yes (1) | No (4)  

Rupali Dhiman   10 years AGO

60%= 3/5 and 80%= 4/5
then (4/5)*(5/3))=4/3

Like? Yes (1) | No (4)  

vinusha reddy   10 years AGO

let two numbers be x and y
given
60%x=80%y
=>6x=8y
=>x/y=8/6=>x:y=4:3

Like? Yes (1) | No (4)  

karthik hariharan   10 years AGO

60%=60/100=0.6
80%=80/100=0.8
so 4th option 4/3 is correct
that is
4*0.6=2.4
3*0.8=2.4

Like? Yes (1) | No (4)  

C.Aarthi   10 years AGO

ans: 4/3
let x,y be 2 no's
(60 * x)/100=(80*y)/100
x/y=80/60=4/3

Like? Yes (1) | No (4)  

ravindra   10 years AGO

0.8:0.6
8:6
4:3

Like? Yes (1) | No (4)  

SIBNATH HALDER   10 years AGO

let number is X and Y
in question
X of 60%=y of 80%
X*(60/100)=Y*(80/100)
X/Y=80/60
X/Y=4/3

Like? Yes (2) | No (5)  

Sohar Lal Singh   10 years AGO

let first number is a and second is b so
a*60/100=b*80/100
then a/b=80/100*100/60
=4/3;
hence option 4 is correct

Like? Yes (1) | No (4)  

Anantharaman   10 years AGO

Given:

60% of x = 80% of y

60/100 * x = 80/100 * y

x/y = 80/60 = 8/6 = 4/3

Option 4

Like? Yes (1) | No (4)  

anubhav verma   10 years AGO

let the number be X and Y
hence accordingly (60x/100) = (80y/100)
(X/Y)= 80/60
= 4/3

Like? Yes (1) | No (4)  

Hanumesh   10 years AGO

60x=80y
x/y=80/60
x/y=4/3

Like? Yes (1) | No (4)  

rakesh   10 years AGO

80/60=4/3

Like? Yes (1) | No (4)  

soumya khilar   10 years AGO

80/60=4/3

Like? Yes (1) | No (4)  

Ann Mary Jolly   10 years AGO

Let x and y be the first and second no.s respectively.
Given: 0.6x=0.8y
=> x/y = 8/6 = 4/3

Like? Yes (1) | No (4)  

Ann Theressa   10 years AGO

Let the numbers be x and y

60% of x = 80% of y
60/100 * x = 80/100 * y
60* x = 80* y

x/y = 80/60
=4/3

Like? Yes (1) | No (5)  

Mahalakshmi   10 years AGO

60%of x=80% of y
x/y=80/60
x/y=4/3
so ans is option 4)4/3

Like? Yes (1) | No (5)  

ITHA Naresh Babu   10 years AGO

let the two numbers be x,y

then by the given statement,

0.6x=0.8y

=>x/y=8/6

=>x/y=4/3

Like? Yes (1) | No (5)  

Surya Narayana K   10 years AGO

Answer is 4/3 (Option 4).
Let a and b be two numbers.

Given that 60% of a number is equal to 80% of another number. So, .6a=.8b
=>a/b=.8/.6=8/6=4/3.

So, Ratio of the number is 4/3

Like? Yes (1) | No (5)  

Sunku Mounika   10 years AGO

A/C to the prob..
60% of x = 80 % of y
0.6 x = 0.8 y
x/y = 0.8/0.6
x/y = 4/3.
So, ans is option (4)

Like? Yes (1) | No (5)  

ashish kumar   10 years AGO

x*(60/100)=y*(80/100)
now, x/y = 80/60 = 4/3

Like? Yes (1) | No (5)  

J.DHANDAPANI   10 years AGO

Let p and q be the req. no.
(60/100) x p = (80/100)x q.
Therefore,p/q=4/3

Like? Yes (1) | No (5)  

Akanksha Mishra   10 years AGO

Consider the First No. is x
60% of first no. = x * 60/100

Consider the second No.is y
80% of second no = y * 80/100

According to the question

x * 60/100 = y * 80/100

x/y = 8/6
x/y = 4/3
so answer will be 4/3(option 4)

Like? Yes (5) | No (9)  

rajesh   10 years AGO

60 % of x=3x
80 % of y=4y
3x=4y
x/y=4/3

Like? Yes (1) | No (5)  

Naveen Kumar   10 years AGO

let the first no. be x and another be y,then acc. to question,
60% of x=80% of y
=>0.6x=0.8y
=>x/y=0.8/0.6=4/3

Like? Yes (1) | No (5)  

Rajasekhar Reddy   10 years AGO

let two numbers be x&y
60% 0f x = 80% 0f y
x/y = 80%/60% = 4/3

Like? Yes (1) | No (5)  

Vivek Jain   10 years AGO

0.6N1=0.8N2
Hence N1/N2=4/3

Like? Yes (1) | No (5)  

Varunraj Reddy   10 years AGO

Given that
60% of a number is equal to 80% of another
i.e. 60% of x = 80% of y
=> (60/100)*x = (80/100)*y
=> (3/5)*x = (4/5)*y
=> 3x=4y
=> x/y=4/3
So ratio of numbers=4/3 option 4)

Like? Yes (1) | No (5)  

Sivanjali   10 years AGO

60/100*x = 80/100 *y
x/y = 4/3

Like? Yes (1) | No (5)  

K.Bhagyasri   10 years AGO

x(6/10)=y(8/10)
x/y=(4/3)

Like? Yes (1) | No (5)  

deepak kumar   10 years AGO

normal calculation of percentage

Like? Yes (1) | No (5)  

Pallekonda Rajesh   10 years AGO

as per given conditions
lets assume the numbers as x ans y
0.6*x=0.8*y so x/y=8/6=4/3

Like? Yes (2) | No (6)  

ch rajesh   10 years AGO

3x=4y
x/y=4/3

Like? Yes (1) | No (5)  

madanpal vishwakarma    10 years AGO

let assume that those numbers are a and b

according to the question

(60%)of a=(80 % )of b

so
(60/100)*a =(80/100)*b

(a/b)=(80*100)/(60*100)
(a/b)=80/60
(a/b)=4/3
so option 4 is correct

Like? Yes (2) | No (6)  

B karthik   10 years AGO

(a/x)*100=60
(b/y)*100=80
here ..a=b
a=60/100*x
b=80/100*y
we have to find x:y ratio..
x/y=4/3..

Like? Yes (2) | No (6)  

Saidinesh   10 years AGO

x(60/100)=y(80/100);
and solving this
x/y =4/3

Like? Yes (2) | No (6)  

saikiran   10 years AGO

(a/x)*100=60
(b/y)*100=80
a=b
we have to find x:y
then x/y=4/3

Like? Yes (2) | No (6)  

kadali mohan chittibabu   10 years AGO

ans is 4/3
60x/.100 equal to 80y/100
x/y equal to 80/60 equal to 4/3

Like? Yes (1) | No (5)  

SHEREENA NISHAD   10 years AGO

80/60=4/3

Like? Yes (1) | No (5)  

mohd zakir   10 years AGO

60x=80y
x/y=4/3

Like? Yes (1) | No (5)  

NavyaBharathi   10 years AGO

=>(60/100 )*x=(80/100*)y
=>(3/5)*x=(4/5)*y
=> x/y=4/3
=> x:y=4:3

Like? Yes (1) | No (5)  

Dishant   10 years AGO

60/100 of x= 80/100 of y
hence y/x=4/3

Like? Yes (1) | No (5)  

ASHISH MITTAL   10 years AGO

60% of x=80% of y
=>x/y=80/60=4/3

Like? Yes (1) | No (5)  

salma   10 years AGO

60% x=80% y
x/y=8/6=4:3

Like? Yes (1) | No (5)  

Dr.Dipin Singh   10 years AGO

60 % of a number (x) is equal to 80 % of another(y).
Ratio of the numbers = x/y =0.8/0.6=4/3

Like? Yes (3) | No (7)  

sruthi   10 years AGO

60x:80y by cancelling we got
3x:4y so 4/3

Like? Yes (1) | No (5)  

19 Mar 2014 Solve

Rate list of some liquids purchased by Shubham is
(Item) (Rate per litre) (Amount required in litres)
Milk ----- 20/- ----------------- 5
Oil ------ 80/- ----------------- 1
Cream ---- 120/- ---------------- 0.5

A shopkeeper offers a discount of 10%, 20% and 30% in the rate of following items. These discounts are given according to the demand of customer. For getting maximum profit, Shubham will use 30% discount in ........ item and he will pay ....... rupee to the shopkeeper.
(Fill in the blank)

OPtion

1) Cream, 196
2) Oil, 190
3) Mile, 178
4) Milk, 190
5) Milk, 188
6) Oil, 194
7) Milk, 180
8) Oil, 188
9) Cream, 178
10)None of these

Solution

In the problem, Shubham has to invest 100 rupee in 5 litre milk, 80 rupee in 1 litre oil and 60 rupee in 0.5 litre cream, therefore for getting maximum profit he will use 30% discount in milk of maximum price then 20% in oil and 10% in cream of minimum price.

Option 5)

Correct Option: 5 Best Solution (36)

Akanksha Mishra   10 years AGO

According to the question
Shubham wants to get maximum profit

Total cost of Milk = 20 * 5 Rs = 100 Rs
if he will use 30% discount then the less amount of the prize of Milk will 30 Rs

Total cost of Oil = 80* 1 Rs = 80 Rs
if he will use 30% discount then the less ammount of the prize of Oil will 24 Rs

Total cost of Cream = 120* 0.5 = 60 Rs
if he will use 30% discount then the less ammount of the prize of Cream will 18 Rs

So Shubham will get maximum profit when he will use 30% discount in Milk
Answer of 1st blank will Milk
------------------------------------------------=
Process for 2nd Blank

now if he will use 30% discount for milk therefore he will pay for Milk = 70 Rs
10% and 20% discount will apply for two other items
Here we will get two conditions
First Condition
where He will get 20% discount for Cream and get 10 % discount for Oil
therefore He will pay to Shopkeeper
= Milk prize + Oil prize + Cream Prize
= (70 + 72 + 48) Rs With discount
= 190 Rs

Second Condition :
where He will get 20% discount for Oil and get 10 % discount for Cream
therefore He will pay to Shopkeeper
= (70 + 64 + 54)Rs with Discount
= 188 Rs

We all know very Well that
190 > 188
and Shubham will get Maximum Profit when he will give 188 Rs To Shopkeeper
So Answer for second Blank will 188

so answer will be Milk, 188(option 5)
I hope my answer will easy to Understand

Like? Yes (20) | No (6)  

ShAg   10 years AGO

total cost of milk = 5*20 = 100
total cost of oil = 1*80 = 80
total cost of cream = 0.5*120 = 60
so to gain maximum discount, he will take;
30% on milk, 20% on oil and 10% on cream.
and pay total of 188

Like? Yes (1) | No   

Krsihna Prasad   10 years AGO

cost of milk=20*5=100
cost of oil=80
cost 0f cream=60
then by applying maximum discount to the item with maximum price gives you more profit ie;to milk(30%)
oil(20%)
cream(10%)

Like? Yes (4) | No (3)  

sharad   10 years AGO

maximunm profit will be on selling milk at 30%, oil at 20% and cream at 10%.
milk = 100-(20*5*30)/100 = rs70.
oil = 80-((80*20)/100) = rs 64.
cream = 120*0.5 - (120/2)*10/100= rs 54.
adding 70+64+54 = 188.
milk,188 will be the ans.

Like? Yes (1) | No   

Vivek Jain   10 years AGO

30% discount on milk will attract highest discount to him. as 0.3x20=6 per litre is highest among the rest

Like? Yes (2) | No (1)  

shalini   10 years AGO

totap price :
milk = 100
oil = 80
cream = 60
so max discnt on milk = 30%
oil : 20%
cream : 10%
total = 188

Like? Yes (1) | No   

Souvik Mitra   10 years AGO

as we can see that milk is the most demanded item by the customer and if it is so 30% of(5*20)is 30,20% of(80*1)is 16 and 10% of (120*0.5) is 6.so total price would be (70+64+54)=188

Like? Yes (1) | No   

sruthi   10 years AGO

cost of :milk=20*5=100
oil=80*1=80
cream=120*0.5=60
for milk 100*30/100=30
for oil 80*20/100=16
for cream 60*10/100=6

so
for milk : 100-30=70
for oil :80-16=64
for cream :60-6=54
hence For getting maximum profit, Shubham will use 30% discount in milk item and he will pay 188 rupee to the shopkeeper.

Like? Yes (1) | No   

Panchanand   10 years AGO

Price of 5 litre Milk is 100
Price of 1 litre Oil is 80
Price of 0.5 litre Cream is 60
So, to get max profit Shubham will use 30% discount on Milk, 20% on Oil and 10% on Cream...
After discount amount will be 70+64+54=188
So Answer is 5) Milk, 188

Like? Yes (1) | No   

subaash   10 years AGO

Milk(30%)+Oil(20%)+Cream(10%)=70+64+54=188.....

Like? Yes (1) | No   

Siddharth Singh   10 years AGO

most expensive (in terms of money spent) item is milk with 20*5=100.
followed by oil which is 80*1=80.
followed by cream 120*0.5= 60.

use 30% discount on milk=> 100-30=70
use 20% on oil=> 80-16=64
use 10% on cream=>60-6=54

amount total payed= 70+64+54= 188

hence, option (5)

Like? Yes (2) | No (2)  

virendra dubey   10 years AGO

the demand of milk is more so 30% discount on milk..so oil==>100-30==>70RS
20% discount on oil==>so oil=80-16==>64RS
10% discount on cream...so cream==>60-6==>54RS...
so total amount=70+64+54==>188RS
so ans=> Milk,188

Like? Yes (3) | No (3)  

pawan kumar chhipa   10 years AGO

milk = 20 *5=100
oil = 80*1=80
cream = 120 * .5=60
for maximum profit 30% discount on milk
he pay for milk is 100*30% discount
for oil 80*20%
for 60 * 10%
total pay
70 + 64 + 54 =188

Like? Yes (1) | No (1)  

Gopal   10 years AGO

maximum pay for milk = 100
so he use maximum discount on this that is 30%
now 20% on oil of 80 rupee
and 10% on cream of 60 rupees
so total payout=70+64+54=188

Like? Yes (1) | No (1)  

Rohit Agarwal   10 years AGO

5 liter milk cost=100 rs
after 30% discount cost=100-30=70

1 liter oil cost=80 rs
after 20% discount cost=80-16=64

1/2 liter cream cost=60
after 10% discount cost=60-6=54

so total cost=70+64+54=188 rs

Like? Yes (1) | No (1)  

ashish kumar   10 years AGO

milk for 5 litres cost =100
30 % discount on it=70

oil cost for 1 litre=80
20% discount on it so cost=64

cream cost for .5 litre=60
10% discount on it so cost=54

so,amount paid by shubham to shopkeeper for getting maximum profit=70+64+54=188

Like? Yes (1) | No (1)  

Anucia Mary A   10 years AGO

if we take 30% discount for milk then the cost for 5 liter is 70
20% discount for oil the cost is 64
10% discount for cream the cost is 54
so the total cost is 70+64+54=188
answer is milk,188

Like? Yes (1) | No (1)  

azharshahid01@gmail.com   10 years AGO

Shubham purchased 5 litre milk i.e. 5*20=Rs 100
1 litre Oil i.e. 1*80= Rs 80
0.5 litre Cream i.e. 0.5*120=60.
Rupees on quantity - Rs(Milk)>Rs(Oil)>Rs(Cream)
So, He will use 30% discount on milk, 20% on Oil and 10% on cream.
So, Total spend money after discount= 70% of 100+ 80% of 80+ 90% of 60.
On calculating, Total spend money= 70+64+54=188.
So answer is 5)Milk, 188.

Like? Yes (2) | No (3)  

Ann Theressa   10 years AGO

Item total price(Rs)
milk ----- 100
oil ------- 80
cream ----- 60

Total cost = Rs240

For getting maximum profit larger discount must be given to the item that costs more.
ie
30% for milk = Rs30
20% for oil = Rs16
10% for cream = Rs6

Total discount =30+16+6= Rs52

Amount he must pay = 240-52= Rs.188

Like? Yes (1) | No (2)  

Rajasekhar Reddy   10 years AGO

Total rate of
Milk is 100/-
oil is 80/-
cream is 60/-
for getting least price we have to use 30% in milk , 20% oil and 10% in cream
we get 70+64+54 = 188/-

Like? Yes (1) | No (2)  

Rahul Kesharwani   10 years AGO

To get a maximum profit with 30%, he must use it with the maximum total amount, so from the below chart u can identify it
ITEM PRICE AMOUNT DIS TL AMOUNT
milk 20/- 100 30% 70
oil 80/- 80 20% 64
cream 120/- 60 10% 54

so total would be 188

Like? Yes (1) | No (2)  

R.RAVIKUMAR   10 years AGO

Total cost will be..
Milk - 100
Oil - 80
Cream- 60

so,if we offer max discount to higher cost, we can get more profit. so,

30% --> Milk = 100-30 = 70
20% --> Oil = 80-16 = 64
10% --> Cream= 60-6 = 54

so, total cost will be 70+64+54 = 188,
when we offer 30% discount to milk.

Like? Yes (2) | No (3)  

Pallekonda Rajesh   10 years AGO

cost of milk=20*5= Rs 100
cost of oil=1*80= Rs 80
cost of cream=0.5*120= Rs 60
for getting maximum profit one has to use more
discount to maximum price liquid
so he will use 30% to milk so
70% of 100=70
80% of 80=64
90% of 60=54
he will pay=70+64+54=188

Like? Yes (2) | No (3)  

mohini gupta   10 years AGO

milk is of 100 rs..hence he should get 30% discount on milk..then 20% on oil and 10% on cream.
total amount =70+64+54

Like? Yes (2) | No (3)  

TRIMURTULU   10 years AGO

for Milk he should pay (5*20)=100/-
for Oil he should pay (80*1)=80/-
for Cream he should pay (120/2)=60/-
-------------
from above data,Shubham use 30% discout in Milk
i.e (100)-((100*30/100))=70
-------------
20% discount in Oil
i.e (80)-((80*20)/100)=64
-------------
10% discount in Cream
i.e (60)-((60*10)/100)=54
if you add 70+64+54 that will yield 188.
so option is(option 5) Milk and 188.

Like? Yes (1) | No (2)  

anubhav verma   10 years AGO

cost of 5 litre milk = 5*20=100
cost of 1 litre oil=80
cost of .5 litre cream= .5*120=60
to avail maximum profit 30% discount on milk , 20% on oil, and 10% on cream hence cost paid = 70+64+54=188
ans = milk,188

Like? Yes (1) | No (2)  

Surya Narayana K   10 years AGO

Ans Milk and 188 (Option 5).

Here demand for items Milk > Oil > Cream.So Milk gets 30% discount, 20% discount in oil and 10% discount in Cream.

Milk with 30% discount=70
Oil with 20% discount=64
Cream with 10% discount=54

so,total 188 and milk gets 30% discount.

Like? Yes (2) | No (3)  

ASHISH MITTAL   10 years AGO

Total pay for milk=100
Total pay for oil=80
Total pay for cream=60
So discount will be 30%, 20%, 10% for milk,OIL,cream respectively , so after solving we get solution milk and 188

Like? Yes (1) | No (2)  

jprakash   10 years AGO

milk 30%=70
oil 20%=64
cream 10%=54
total-188

Like? Yes (1) | No (2)  

madanpal vishwakarma    10 years AGO

if Shubham purchase the
1>milk at 30% profit then=20-(30/100)*20=20-6=14/ltr=required 5 ltr so cost is= 5*14= 70rs

2>getting 20% discount on oil so =80-(20/100)*80=80-16=64 rs
3>10 % discount on cream =120-(10/100)*120=120-12=108 required amonut is 0.5 so =54 rs

so optimal total amonut is =70+64+54=188
(while getting the discount 30% in milk ,20% in oil and 10 % in cream)

Like? Yes (1) | No (2)  

mansi garg   10 years AGO

cost of 5ltr milk =100
cost of 1ltr oil=80
cost of 1/2 ltr cream=60
he will demand 30% ,20% and 10% on milk ,oil and cream resp
so cost=70+64+54=188

Like? Yes (1) | No (2)  

SAM   10 years AGO

20*5=100-30=70(Milk)
80*1=80-16=64
120*.5=60-6=54
----------------
188

Like? Yes (1) | No (2)  

Anshul   10 years AGO

Total Amount OF:
Milk: 100 (20*5)
Oil: 80 (80*1)
Cream: 60 (120*.5)

So, He will use 30% discount on Milk (Rs 30), 20 on Oil (Rs 16) and 10% in cream (Rs 6) respectively.

So, Total Amount to be paid=100+80+60-30-16-6=Rs 188

Like? Yes (1) | No (2)  

Saidinesh   10 years AGO

need discount in item which is highly priced so he prefers milk n the price he pays is not 188 it is 84

Like? Yes (1) | No (2)  

gaurav kumar verma   10 years AGO

(30% of 20)*5=30
(30% of 80)*1=24
(30% of 120)*.5=18

hence he is getting maximum discount in milk.
and then to maximize profit he will ask for 20% discount in oil and 10% in cream
HENCE HE WILL HAVE TO PAY= ((.7)*20*5)+((.8)*80*1)+((.9)*120*.5)=Rs.188 Ans.

Like? Yes (1) | No (2)  

mohd zakir   10 years AGO

after discount rate of milk are as 90,80,70
rate of oil are as 72 64 56
rate of cream are as 54,48,42
hence 70+64+54=188 will be better

Like? Yes (1) | No (2)